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< ><FONT color=#ff0000>函数名: ultoa </FONT>
7 L2 v7 a9 {: j/ J8 M; a功 能: 转换一个无符号长整型数为字符串
O- I: U% p' {. m) w+ J6 o, F用 法: char *ultoa(unsigned long value, char *string, int radix);
3 \$ W* T+ e j& W, o: A7 |4 d1 l/ h程序例: </P>$ @# J( T% S/ t3 [
< ><FONT color=#0000ff>#include <STDLIB.H>
$ b: N& D: F& Q1 V#include <STDIO.H></FONT></P>
! ?: |" }2 A! H< ><FONT color=#0000ff>int main( void ) ! g# L$ g& C/ @8 m( X+ n7 {4 M
{
+ G, c: j: ~% M6 kunsigned long lnumber = 3123456789L;
) ]( {6 ]4 e4 a" ?( ^char string[25]; </FONT></P>6 A8 U4 n/ \( o
< ><FONT color=#0000ff>ultoa(lnumber,string,10);
! n/ C+ ]! l. Aprintf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>
6 f# H: ]) a+ o$ {9 R: U) A% o4 V< ><FONT color=#0000ff>return 0; 3 C" H% {5 [2 c F8 b" w y
} ! x: C2 X6 |; C0 v9 z
</FONT>" H1 C _2 D9 r8 R2 u
. V1 ^! ~( T8 P3 G E( _4 Z
</P>
% V% v) r* T, ^/ a* d3 b. @! Y# R< ><FONT color=#ff0000>函数名: ungetc </FONT>" p0 r5 N) U4 `! J
功 能: 把一个字符退回到输入流中
: X' D. a- }/ z; \; N# ^用 法: int ungetc(char c, FILE *stream);
2 y) c2 E/ ]7 \ z/ o9 s程序例: </P>+ x5 w9 P% X/ ~
< ><FONT color=#0000ff>#include <STDIO.H>4 H% v! _- ]# n, y
#include <CTYPE.H></FONT></P>
0 C. Q- g+ ?* m9 R+ P$ ^7 t< ><FONT color=#0000ff>int main( void )
' f- A1 J& c) i L8 z{
9 y! ?$ S) s- z V+ {9 n9 H* m6 Mint i=0;
; O8 x7 J7 l) w. t) ^+ l5 Nchar ch; </FONT></P>; j* H3 a4 M' @, R$ r ^* K) W8 e
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>
6 ]( m/ ]. I$ Y* ^: @1 ?< ><FONT color=#0000ff>/* read chars until non digit or EOF */ [) M/ `# y) N8 {6 V( u
while((ch = getchar()) != EOF && isdigit(ch)) : R4 j( J4 Z; C% L3 W C, f
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
9 p c! x; S! x' n# o- S< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ 7 v& Z' V; A8 y/ J/ d# d2 U$ W
if (ch != EOF)
8 }' N; X7 C8 }% _: T0 H: y( Xungetc(ch, stdin); </FONT></P> ~+ R& k; ^8 u4 m. o) p) H
< ><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar()); |+ f2 g1 O' h0 a& R* d1 n
return 0;
) i# ]- ~4 a, E$ p7 Z) f7 x- X$ r0 Y( ?} </FONT>5 W- X C0 v5 x7 G9 B% s1 g# C
5 b! g* v$ z& z7 K% W0 V% [
0 S* X; n8 E1 e" V' Q% z</P>
4 f2 [ c0 O! F( W< ><FONT color=#ff0000>函数名: ungetch </FONT>
" ^2 t& \ W- I# ^: _0 o功 能: 把一个字符退回到键盘缓冲区中
6 E: B( s( J0 E+ W' f用 法: int ungetch(int c); + c1 d- F, E0 P3 D3 o
程序例: </P>; V& t! w8 v* ?# Q$ T2 T9 N8 t6 ]
< ><FONT color=#0000ff>#include <STDIO.H>
( o; |1 `% M) N$ y#include <CTYPE.H>
) M7 d7 `* j6 ^" U. m: I' F#include <CONIO.H></FONT></P>2 p4 Q5 ]$ v" P2 @( t
< ><FONT color=#0000ff>int main( void ) $ r5 D' \( O7 ]5 ~# P4 `8 X' b
{ - x4 j0 F2 e6 b" j! r( R& ?
int i=0;
/ K( Q- `, b. Qchar ch; </FONT></P>' b; V% S" t W0 }8 g
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>
7 c" M1 k d6 r1 e< ><FONT color=#0000ff>/* read chars until non digit or EOF */ ' G3 T$ G& d0 g, p* K
while((ch = getche()) != EOF && isdigit(ch))
f s6 ~' ~* li = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
7 C) r6 u, J" K/ V: S< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ . T m0 T8 {' G7 X- y3 g
if (ch != EOF)
* A8 i) |, S {; J( Gungetch(ch); </FONT></P>; [& @8 v7 h `# t
< ><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch());
) U4 v9 G$ W3 R& Nreturn 0; , L, F0 S/ q7 E y: c5 A
} 0 |! B# i8 x3 c
2 g# |3 C8 B8 E- w
; T/ w" m a1 R5 ?# J</FONT></P>
6 U, x" g0 F% P! N5 d4 b< ><FONT color=#ff0000>函数名: unixtodos </FONT>
% a4 N. E' Z: {功 能: 把日期和时间转换成DOS格式
4 B% m! X8 ]2 [& T用 法: void unixtodos(long utime, struct date *dateptr,
- X& f8 P5 s) a- s& W. ~struct time *timeptr);
: R" L, ~0 h- }: W i Q, j7 S程序例: </P>$ l! X/ [$ E1 L$ T/ v( W. w3 a! H
< ><FONT color=#0000ff>#include <STDIO.H>
6 K8 t- |: f9 o; t$ V# {#include <DOS.H></FONT></P>
. w! K/ G, d1 d+ _9 W< ><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun",
8 m& s6 }& }& s4 i) c# _* J"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>+ p6 U/ U1 w& o5 f" N: O
< ><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>! A7 r# r& e* d0 y8 v
< ><FONT color=#0000ff>struct date dt; # P: s4 ~) l5 D3 |( B* Y; ^7 @
struct time tm; </FONT></P>/ `4 v3 T. D( W, ?. ]* y$ `
< ><FONT color=#0000ff>int main(void)
+ v/ u/ _) O, {; R& ]{ & ?# \5 P% Y6 o; j1 A
unsigned long val; </FONT></P>6 {. W, Y: U6 e0 O/ U [8 f* U
< ><FONT color=#0000ff>/* get today's date and time */
o) b4 q! u P9 D( |getdate(&dt);
9 I7 f2 U: I& _' \5 ^( ^& n& y0 Egettime(&tm); " `% `" i) X6 E; S: o5 U
printf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>/ M; M2 z/ V4 c( x- A
< ><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */
2 W# ~3 p2 O1 A6 _0 g( K5 l+ Sval = dostounix(&dt, &tm);
( C4 x; J6 Q6 s3 ]/* subtract 42 days worth of seconds */ 5 I' l1 B$ z" j2 z& }
val -= (SECONDS_PER_DAY * 42); </FONT></P>
9 M8 x3 z4 Q. e3 C< ><FONT color=#0000ff>/* convert back to dos time and date */ * Z. I$ c! @3 [) V1 h3 h* O8 U5 h
unixtodos(val, &dt, &tm);
7 c1 K) n# }4 o, q3 j7 _0 b3 uprintf("42 days ago it was %d %s %d\n",
0 \) Q4 d- {1 a" h% g3 s) hdt.da_day, month[dt.da_mon], dt.da_year); 6 A8 Y8 w* F& j9 x
return 0; 9 P5 w* c7 r) V
}
/ }; p- @. [( q1 q2 ?4 \, z9 I1 Y
( Z$ U" u! |) u
. W }& J( Q. f$ I</FONT></P>: P9 J3 y; Q; f
< ><FONT color=#ff0000>函数名: unlink </FONT>
* e* A4 {3 L% p% P3 ?9 C功 能: 删掉一个文件
9 p( p# B7 B7 U用 法: int unlink(char *filename); . m6 y/ a) {# E' [. q( z6 \& z' e; Z* f
程序例: </P>
. n I a7 q L& P: n" D" r* H8 ~! H< ><FONT color=#0000ff>#include <STDIO.H>
7 n+ K% l5 d1 T) K5 N#include <IO.H></FONT></P>! N* e. y8 @) `, }' a
<P><FONT color=#0000ff>int main(void)
8 w) l: j. i0 u# c% L{ + M- H; t: \- J% ` H
FILE *fp = fopen("junk.jnk","w"); 5 v# F6 e: {4 b9 p; G
int status; </FONT></P>
3 X, C$ E" M. P& N<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>8 B/ W u$ F0 f0 c6 \* v' `
<P><FONT color=#0000ff>status = access("junk.jnk",0);
. |/ o) D$ S- Z4 i& K. P2 z7 Q q7 ]if (status == 0)
1 a8 _6 [1 G- ~' |printf("File exists\n"); 5 [7 {" }- R( J; y7 J7 K% _& W
else # y8 V0 {+ i8 r& v h8 {
printf("File doesn't exist\n"); </FONT></P>
6 A' I4 x! |9 ^<P><FONT color=#0000ff>fclose(fp); , ^( C( K" k' w1 l5 F4 r% @
unlink("junk.jnk");
6 s4 Q. D9 o. p% q0 I$ w Lstatus = access("junk.jnk",0); : k4 I! u9 Q' g7 C
if (status == 0)
. a3 Y/ f, y0 X! @ `; ~& _" Hprintf("File exists\n"); , c" P; x& F* \( b/ R+ D
else . V+ w/ D- h" \: q
printf("File doesn't exist\n");
7 @: ?% p- @- x1 U% a</FONT></P>: O* W2 u% H* x T+ Y2 O: s. v
<P><FONT color=#0000ff>return 0;
) T& q4 G3 G5 |7 _}
( k7 N! ~- [ w% C: P6 b3 Y
& x8 s; G+ R2 p4 r$ m</FONT>/ e# \( _7 T; }
</P>
5 \: m: H5 ]' B& A<P><FONT color=#0000ff>函数名: unlock </FONT>+ X' _2 _4 A D9 w' {2 t& Z" z
功 能: 解除文件共享锁
8 j2 _% @$ A) g8 y用 法: int unlock(int handle, long offset, long length); $ t* N( T. t4 w- A7 r
程序例: </P>) z/ v0 S# o% I, Q$ a9 ~( e, x
<P><FONT color=#0000ff>#include <IO.H>9 }! W# D: L# K% L3 S5 @
#include <FCNTL.H>, K6 C p6 J$ e1 H& }
#include <SYS\STAT.H>7 u' t. f3 _/ \: @- j
#include <PROCESS.H>9 r. i( T% U7 U3 P. b+ m9 ^
#include <SHARE.H>
+ P# A t7 ]2 B2 |3 o#include <STDIO.H></FONT></P>( W& w2 N' v' M
<P><FONT color=#0000ff>int main(void)
6 P1 q! A7 {: w9 `% {1 ]{ 1 ^, `9 J) X& q6 m6 x# r0 V
int handle, status; c' D0 R) h. D+ u- h1 n: I
long length; </FONT></P>
) G% _' i2 {: W' |2 `<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>) w. n8 }7 O s5 T1 Q" U3 K
<P><FONT color=#0000ff>if (handle < 0) , g/ m% ~& _/ r7 c, b8 D
{
: w7 b& c4 S$ a7 k; m& |printf("sopen failed\n"); $ u' \8 G* _' H" g
exit(1); ! F8 a; i# o/ U) u9 V
} </FONT></P>+ r% ~9 O, @) u* O8 g/ c6 [* k
<P><FONT color=#0000ff>length = filelength(handle);
) N) O, T8 E5 A$ T) Mstatus = lock(handle,0L,length/2); </FONT></P>& R! C. ?4 z+ ]0 \) V# J# Z1 W/ v) U! p
<P><FONT color=#0000ff>if (status == 0) & @9 V& m1 g; \2 U- y% Z
printf("lock succeeded\n");
" [2 e' b) x$ j. h. welse
9 Z& z, N9 V2 {+ a$ d# q3 Fprintf("lock failed\n"); </FONT></P>
: r! r0 G' ?# d; D# j V- K<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>
' c; o6 C' b4 j( [" M<P><FONT color=#0000ff>if (status == 0) ' E9 T0 U: _& O% J \
printf("unlock succeeded\n"); 2 @" H; p# Z& A5 ?
else 6 y+ L8 c/ c. a- @8 x( L2 `
printf("unlock failed\n"); </FONT></P>
" o3 d" w8 M4 R( M: a<P><FONT color=#0000ff>close(handle);
Y# C4 m# R3 H) o6 Vreturn 0; + q Y2 {( ^6 f
} </FONT></P> |
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