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< ><FONT color=#ff0000>函数名: ultoa </FONT>" j3 b( Q7 ^$ r
功 能: 转换一个无符号长整型数为字符串 : r) f6 W; t+ ~# u+ W& K
用 法: char *ultoa(unsigned long value, char *string, int radix); , {0 F' G. e8 i# k: k
程序例: </P>6 E+ F1 ^! c) i$ a
< ><FONT color=#0000ff>#include <STDLIB.H>: k, e" Y0 |6 F2 n8 u
#include <STDIO.H></FONT></P>
- b( i' i1 [ U, M< ><FONT color=#0000ff>int main( void )
: g- F" r+ P- ?, G, M S4 Y{ 9 p. k7 z4 t+ j
unsigned long lnumber = 3123456789L; 2 V5 j. J! ?! N8 b7 |) U
char string[25]; </FONT></P>& S6 W; {$ n9 R) F* Y) v3 o# L O
< ><FONT color=#0000ff>ultoa(lnumber,string,10); D8 H, U) r4 h2 A8 r2 ~$ {; l) a/ S
printf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>
9 Q) h+ v7 O3 R9 E8 |" X< ><FONT color=#0000ff>return 0; ' p( F4 \; J7 }5 D [
}
2 f+ F5 _) m2 R' M$ L( n5 K</FONT>
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: u4 `1 i) M9 P) |7 t</P>$ ~3 U/ M$ g) @/ k
< ><FONT color=#ff0000>函数名: ungetc </FONT>
% [5 Q' D- b4 m. Q功 能: 把一个字符退回到输入流中
5 a t3 m- p! b! W1 Z用 法: int ungetc(char c, FILE *stream); 2 ~2 ~4 S/ [ d o
程序例: </P> z5 ^& L4 O$ B& `* h
< ><FONT color=#0000ff>#include <STDIO.H>
# b$ k6 J' M: @. }#include <CTYPE.H></FONT></P>
8 u% s% N4 F, |< ><FONT color=#0000ff>int main( void )
4 C0 w i, H6 @5 c{ : u: Z' }0 l+ U
int i=0; : B8 M) v3 h6 d' C1 ~4 y
char ch; </FONT></P>& _ D: w% y" a8 n1 W" y" Z
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>) s; X, t$ k. y
< ><FONT color=#0000ff>/* read chars until non digit or EOF */ * \' X M1 p M' N1 J5 x# Q
while((ch = getchar()) != EOF && isdigit(ch)) : E- t* h; C& h& ~- w+ p) ?
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>& `. e. F2 y, v
< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ ( U5 q* l% j% p! r- A8 z
if (ch != EOF)
; \/ f. Q: V+ @% g' Q4 g) |ungetc(ch, stdin); </FONT></P>% @5 k* W* f7 d! g+ U, `. o
< ><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar());
6 A+ }. M8 ?! [, E! Yreturn 0;
' p C7 s5 F* b2 A} </FONT>
/ }' v% ~3 W" m5 L }& y7 f/ V9 R) c# i
# \3 d3 v; @2 g _
</P>
D) N& g+ O% O< ><FONT color=#ff0000>函数名: ungetch </FONT>
, k+ c% [" `. ]9 l v, H功 能: 把一个字符退回到键盘缓冲区中
# J5 w. v! Q4 G/ L% J7 k6 T用 法: int ungetch(int c); ! y$ P* @, f+ }6 G J* W3 F
程序例: </P>) t8 ?: ^4 N' T7 l
< ><FONT color=#0000ff>#include <STDIO.H> B! W f! ]" @( ~, o, \
#include <CTYPE.H># g* L/ U/ {# } A: P
#include <CONIO.H></FONT></P>
: u ?+ D0 M" k) }; w- Y0 m3 K* P< ><FONT color=#0000ff>int main( void ) & o1 i, e* a' P, I8 f* P
{
% q+ `3 w) @# {7 g6 gint i=0;
1 u# `5 p/ e7 j; e7 z4 x: S; g$ fchar ch; </FONT></P>2 m I4 j* R u
< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>
# v+ k; u$ D$ Q* ]1 s* t/ U< ><FONT color=#0000ff>/* read chars until non digit or EOF */ 6 w- N( p F( M _! @! q
while((ch = getche()) != EOF && isdigit(ch))
. ^& h9 F- h3 ^% t1 F( qi = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
7 i& x4 S; J$ V9 U9 N6 V< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ 6 _; `6 v* ~& g6 u+ c- t
if (ch != EOF) 7 u4 O7 C1 @0 ?" s* ?4 E& i
ungetch(ch); </FONT></P>
6 a. s7 e3 K" H0 x< ><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch()); , Y3 A) P0 V+ R, k
return 0;
; @2 x+ C- e9 p% ^# p+ p( }+ U- s}
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8 ~- [. c6 Z" I) t$ u- B. s% g</FONT></P>3 w, E k. h) V6 F
< ><FONT color=#ff0000>函数名: unixtodos </FONT>" p, z+ C# T8 d7 _+ r
功 能: 把日期和时间转换成DOS格式 2 a* N' J: t8 r$ c+ W8 U: P
用 法: void unixtodos(long utime, struct date *dateptr,
& ` b* {& v7 N- K' {struct time *timeptr); $ ~2 Y) k; O9 W- \0 K/ w, w
程序例: </P>+ v5 j9 y# k, T5 F3 K7 W9 I
< ><FONT color=#0000ff>#include <STDIO.H>4 Y) b8 T! w: Q5 c
#include <DOS.H></FONT></P>5 c- m4 Q" @# `4 `7 ?
< ><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun", $ a6 H& T. ~% ^" T& H2 o
"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>
- |+ h: X0 f) K; o$ g i8 _# T< ><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>
' {. i3 c+ ~2 a# a< ><FONT color=#0000ff>struct date dt;
& c2 ~0 r j: fstruct time tm; </FONT></P>
- T, O" q$ I; ~. l% W2 g$ i+ Q< ><FONT color=#0000ff>int main(void)
: Y8 J( N1 f0 A1 v% b% ^+ Z7 W{
" r, s7 i3 v- i- x7 J! T5 _unsigned long val; </FONT></P>
- e* w& D+ K7 d; P5 }4 R2 ~< ><FONT color=#0000ff>/* get today's date and time */
( F! ]& H2 p! e; {2 J6 mgetdate(&dt); f* B @$ o9 l" a" a( }
gettime(&tm);
, q* u0 s6 P& A6 x! A3 j5 E! A$ n4 kprintf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>
1 D* M1 U5 J1 @$ V" Z, z) K< ><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */
9 r$ K2 D5 P3 e, F; m& fval = dostounix(&dt, &tm); & `5 V( v1 y7 z$ I7 F- F* g3 n
/* subtract 42 days worth of seconds */
! p) L+ e9 U+ r/ Eval -= (SECONDS_PER_DAY * 42); </FONT></P>3 x q, o$ `, u* `9 H2 e' Z
< ><FONT color=#0000ff>/* convert back to dos time and date */ 7 z2 j: r- q8 p: ^4 U
unixtodos(val, &dt, &tm); ( W/ |( @8 Y9 [3 b4 c! @
printf("42 days ago it was %d %s %d\n",
" X! N: t' `+ q4 m9 e# T# V0 u8 v3 Sdt.da_day, month[dt.da_mon], dt.da_year); * Y; a& j. s K1 ~: g
return 0;
4 \; n, V2 M6 d/ n! n# E}
7 S( j6 L3 H$ k- ]' F9 j
/ J, R2 g6 _4 e" I
, G) C" o" m* \</FONT></P>
1 ~6 f, _- y# a/ J< ><FONT color=#ff0000>函数名: unlink </FONT>) m; A8 p2 X2 F% i; A
功 能: 删掉一个文件 8 l& \4 `$ L$ t& P: P
用 法: int unlink(char *filename); ' p/ u, N2 v7 G) f' P
程序例: </P>
0 d/ K8 y2 p6 l$ ^, f3 a+ B* x< ><FONT color=#0000ff>#include <STDIO.H>' i, i& k3 f; `8 w7 k; D% e; {
#include <IO.H></FONT></P>6 ]5 G7 Z0 e6 s! S% i3 }- \
<P><FONT color=#0000ff>int main(void) ( m7 b+ L2 n) u$ L* T9 O
{
' d2 h% l# o! v+ I: eFILE *fp = fopen("junk.jnk","w"); " A9 N4 ]' C7 S- l
int status; </FONT></P>7 \7 G. ]6 }: g% [6 C4 f2 {1 d) B
<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>
& \$ y2 ^4 @; i) ~3 r4 p% d<P><FONT color=#0000ff>status = access("junk.jnk",0); 4 p, m* s' K+ @- V, W+ a4 ^
if (status == 0)
6 b4 ^0 S* o: g* H l0 _printf("File exists\n"); $ a' z$ v3 Y- U! K
else - x; _0 ~. q; J5 K% R
printf("File doesn't exist\n"); </FONT></P>
1 C( ~' Z, e: C<P><FONT color=#0000ff>fclose(fp); 9 Z/ z' r3 i1 y; ?, a; K( r! B
unlink("junk.jnk"); 0 v! W. b0 N' b. J
status = access("junk.jnk",0);
# F! G5 x* N- g# A2 lif (status == 0) 5 S! ~4 n2 i) d
printf("File exists\n"); % }, z! }. C `: w) n. X1 {: F
else 1 v* O1 F; R, `6 K3 W
printf("File doesn't exist\n");
% U. _' y% P+ A</FONT></P>! p, f6 ?- K8 O# A3 G
<P><FONT color=#0000ff>return 0;
0 h2 l/ i, }+ W# Y} 3 O5 G9 d" N: i! Y2 T$ r X
- R. O+ _4 }9 M% l2 T
</FONT>
2 G5 G) L& |( o) O- h0 i</P>6 s9 @) s0 _4 r, e* o; y
<P><FONT color=#0000ff>函数名: unlock </FONT>1 `2 p/ L4 M5 _% m+ C Y! P- T5 g
功 能: 解除文件共享锁
; w p2 \% T Y用 法: int unlock(int handle, long offset, long length);
, m3 H+ ?8 t$ n$ o }程序例: </P>( A9 y, m$ e4 _$ \! \6 y+ H/ p4 T
<P><FONT color=#0000ff>#include <IO.H>
( d& [+ w9 x" r3 K' n. o, ?#include <FCNTL.H>1 N8 s; R% [' e# k
#include <SYS\STAT.H>
" ]9 b8 O7 g+ e8 ~7 Q#include <PROCESS.H>
1 x' V/ r" T2 w* x0 q7 @#include <SHARE.H>7 {' t. E3 S6 u$ E; E c
#include <STDIO.H></FONT></P>
/ Z) F& k+ T* u1 }6 F. v<P><FONT color=#0000ff>int main(void) 6 L) B* V' H7 P5 h# K0 u! f+ Q$ X
{
" b( w) U: b! ^2 n! S- K! Rint handle, status; : e0 x& e; }% {. ^& U/ m, k. r
long length; </FONT></P>
% a, Q' U4 e! t<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>
: I9 ?0 j& @6 o<P><FONT color=#0000ff>if (handle < 0) % G; Y1 O8 i* O2 @' q4 z% B
{ # P2 R, i5 P c9 }$ ^6 e
printf("sopen failed\n");
\) I* r" B- t ]exit(1);
# _4 m! q3 C2 S/ @} </FONT></P>
" _2 W. h! O! n* K. i0 B1 t<P><FONT color=#0000ff>length = filelength(handle);
1 \3 }: o- c$ Sstatus = lock(handle,0L,length/2); </FONT></P>, q7 {/ n9 a9 H4 Q. f
<P><FONT color=#0000ff>if (status == 0)
/ W" B4 B% @9 \# b+ `printf("lock succeeded\n");
4 o( x7 E( S* V! |# k6 n& G) G+ Nelse 2 S# x$ m, Q& e+ a
printf("lock failed\n"); </FONT></P>4 }+ U# I) l, E
<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>! m& z% ~0 t4 K7 y2 A
<P><FONT color=#0000ff>if (status == 0) v( u3 Q# H" V4 n+ i& p
printf("unlock succeeded\n");
$ N* ?; W4 d! u8 L( Q! _% |else
0 k) B: T4 ]* [printf("unlock failed\n"); </FONT></P>; D" ?+ k- a' w ?% N. m3 o6 T- E
<P><FONT color=#0000ff>close(handle); - X3 ^# t: i& n& p6 p) I
return 0; : G: o* S+ U4 g& \+ |- c
} </FONT></P> |
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