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< ><FONT color=#ff0000>函数名: ultoa </FONT>
* W) d8 p- n( v+ e# N% k功 能: 转换一个无符号长整型数为字符串 8 Z& X1 h N3 b) N* Z5 M* s
用 法: char *ultoa(unsigned long value, char *string, int radix);
( h& R x- O: o% t( d程序例: </P>9 K5 y! F: M( Q# H
< ><FONT color=#0000ff>#include <STDLIB.H>
. x4 n+ H* n; y. H; x) m$ |#include <STDIO.H></FONT></P>; V2 D0 d. d9 b
< ><FONT color=#0000ff>int main( void )
6 ]- ^) ?; b+ N8 ~1 [6 o{ # J( r& Q- G/ w5 z' z
unsigned long lnumber = 3123456789L; 5 d8 A8 b) Y5 u' H8 @6 \
char string[25]; </FONT></P>
' @% R( u: S- U \; ~% j< ><FONT color=#0000ff>ultoa(lnumber,string,10);
2 D! p" I' a( {( Zprintf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>
: ]0 q" S2 s( Z< ><FONT color=#0000ff>return 0; ' @- a0 X& ~: m0 a% M
} * z* r/ l' G0 d" b+ _& h
</FONT>
]$ w% n$ ^ S5 T2 E6 n+ r
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' u5 U$ z P: z) J< ><FONT color=#ff0000>函数名: ungetc </FONT>5 v4 a8 z$ I! T* V+ _
功 能: 把一个字符退回到输入流中
$ Y) \. _( [! m8 f用 法: int ungetc(char c, FILE *stream); / m+ _6 u. T3 P# {/ S: n
程序例: </P>
1 M a" e3 a; f( S* @< ><FONT color=#0000ff>#include <STDIO.H>
" t+ \9 s& a& _, `#include <CTYPE.H></FONT></P>$ P) w: _- h* I3 q
< ><FONT color=#0000ff>int main( void ) ; x- t! `# e2 X( ^
{
2 s/ e# ^ T2 Zint i=0;
' x$ I S5 M* f2 M: U; R6 A) wchar ch; </FONT></P>
- @- t- g w7 m, [< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P> R+ d) Y1 u4 j: f# o! e) h
< ><FONT color=#0000ff>/* read chars until non digit or EOF */
) I& X4 x, a4 H, @, ?9 c4 d* pwhile((ch = getchar()) != EOF && isdigit(ch))
3 a1 t* T, w( n6 f, zi = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
" n5 V' c( O: G. L* }5 h! e< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */
6 p2 k8 Z$ h1 yif (ch != EOF)
9 [6 N8 p* b) f- dungetc(ch, stdin); </FONT></P>
( D( r3 [- Z. O' s5 k< ><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar());
$ p4 G; y2 ~) R! F" ]$ ^return 0; . Y! [0 f' w: ~* B- d9 C& X
} </FONT>
" C( G+ w4 G' B) w* Q: K- z/ w% y; k) z4 {/ R" R/ Z* m' L
+ S& k3 e( P- x( C2 C# @
</P>& s) S" A) }- ], a5 k( Y8 q
< ><FONT color=#ff0000>函数名: ungetch </FONT>
4 f9 y7 j! n9 C* \- C! K% C. e* A功 能: 把一个字符退回到键盘缓冲区中 \: C3 S7 m! I7 q& q" g( V
用 法: int ungetch(int c);
5 K( k# K9 H2 ~5 n' h, h程序例: </P># K- _) f$ s; e, U2 q3 t
< ><FONT color=#0000ff>#include <STDIO.H>4 @$ m, F! E' T6 Q' t0 N! o$ z
#include <CTYPE.H>
0 V, }. O3 o, J: O) Z2 y#include <CONIO.H></FONT></P>+ y5 Q0 |6 N, y1 p+ b# r. D
< ><FONT color=#0000ff>int main( void ) 2 n. t9 v& F% I
{ 5 ?% ^' X& Q; K: ^& t/ Y0 F/ O
int i=0; 4 Z1 P8 {& T/ Y; J! ^
char ch; </FONT></P>
/ C) d" x# w& F# U' g9 E+ ]5 r< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>" n0 q% i5 z/ }* c( W% b
< ><FONT color=#0000ff>/* read chars until non digit or EOF */ & c7 V% ~' J/ b6 R$ F7 ?& l& x# E
while((ch = getche()) != EOF && isdigit(ch))
6 a0 e2 h2 U. Y! U; \% s3 ci = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
+ {: w4 ]/ }& P< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */ * A$ U: N' H# ?" O% I4 t
if (ch != EOF) $ X2 L# P z+ ?" X0 M; Z2 E
ungetch(ch); </FONT></P>3 ~/ N6 l" p3 e; }' Q
< ><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch()); 3 D I; e, Q/ h f
return 0;
1 Z0 ]+ F. B9 B) G}
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</FONT></P>: f. ?* Z% f, H0 f- _7 J
< ><FONT color=#ff0000>函数名: unixtodos </FONT>8 }2 S1 J8 `) t
功 能: 把日期和时间转换成DOS格式 / x; H* z: d2 \) i9 q$ M) d
用 法: void unixtodos(long utime, struct date *dateptr,
# S* B) Y9 _. @struct time *timeptr); 8 U7 o7 Z0 D K) B
程序例: </P>( v9 C' ]# y9 _3 P( s
< ><FONT color=#0000ff>#include <STDIO.H>2 b- V0 R3 {. l- I, j
#include <DOS.H></FONT></P>
" a7 k x. T0 `1 Z6 X< ><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun",
1 K9 `2 t. F. i; q0 M! s- h+ F"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>% p) t0 y6 D( u( y' c
< ><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>! ~! [/ J/ n# } i( e
< ><FONT color=#0000ff>struct date dt; 1 v. {( P* A7 f
struct time tm; </FONT></P>
7 p; L8 b5 K: v1 g, s< ><FONT color=#0000ff>int main(void)
5 K) ^; g# A, A5 d, W7 Y3 N' I{ 2 d, ?$ ^ x$ p7 {" X3 j5 ]
unsigned long val; </FONT></P>
2 i+ H \# ?" o3 R! o< ><FONT color=#0000ff>/* get today's date and time */
+ G; _9 C" F, Z; w. ]getdate(&dt);
9 k$ `7 H! U0 D' ]/ H# B3 Wgettime(&tm); * I) k! V$ ?# ~" N
printf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>9 @/ ]2 o9 q1 ]
< ><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */
% O0 S% q/ f! i6 V8 _val = dostounix(&dt, &tm);
0 ~, y8 v- m2 `! B" ~9 l3 q/* subtract 42 days worth of seconds */ ! H/ H# l+ S3 A0 I5 U9 ^
val -= (SECONDS_PER_DAY * 42); </FONT></P>9 B5 O: B: Q ?0 d% A& b2 Y
< ><FONT color=#0000ff>/* convert back to dos time and date */ . H9 n, t( X; v* F
unixtodos(val, &dt, &tm);
' `$ v' n* o/ o, Gprintf("42 days ago it was %d %s %d\n", 2 R3 J5 U( ]) C) M
dt.da_day, month[dt.da_mon], dt.da_year);
* o2 p9 g8 O' s d( s( nreturn 0;
+ @1 T8 H0 S% H- I} 9 x4 ^& i$ s7 K& F
* e8 R3 f0 j1 |, J! }( [1 _4 n1 p- }. t. ?8 e0 Y0 H8 l
</FONT></P>4 |6 v: h6 f4 Y* |6 v1 [3 y2 Y9 _! U
< ><FONT color=#ff0000>函数名: unlink </FONT>/ p2 p% V% h4 }: s
功 能: 删掉一个文件 2 f1 q9 e* h* _. C# D0 E3 }
用 法: int unlink(char *filename); + }, B# C4 Y- U$ z1 a f- c
程序例: </P>/ z k, y' ]3 a F' {( G& B8 L! }' p
< ><FONT color=#0000ff>#include <STDIO.H>) x$ F X" ?" P# u
#include <IO.H></FONT></P>
: ?2 N: Q8 [6 \<P><FONT color=#0000ff>int main(void)
' J3 D9 u G, k! K7 B4 ?{ i, w" @8 `" n, i
FILE *fp = fopen("junk.jnk","w");
, |/ D t6 e0 w0 Kint status; </FONT></P>
* q P: c4 m5 r: S* s! x. C<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>+ W6 X* g1 m$ f* E2 d
<P><FONT color=#0000ff>status = access("junk.jnk",0);
' `7 _1 Q- T9 Kif (status == 0)
; a9 ^) @ |5 h: M8 Cprintf("File exists\n"); ) \3 q. d3 y8 U1 K' d( Q
else
7 p& E6 f& B7 i0 k8 v$ Uprintf("File doesn't exist\n"); </FONT></P>
' Z ^% j! [! M' i, X5 L+ u<P><FONT color=#0000ff>fclose(fp); 3 |4 h0 r' e# @" Y& w' I
unlink("junk.jnk"); 1 I) i3 y3 o4 z+ \; Z8 y) B& z
status = access("junk.jnk",0); 9 u* d0 M; ]6 J) D
if (status == 0)
, w" k: O0 M) K' y8 T7 l" Zprintf("File exists\n");
' |3 g1 d: y8 N" Welse
' D& D3 p* T, [/ Rprintf("File doesn't exist\n");
. B q2 C/ {4 [</FONT></P>/ L7 B7 c' k9 M5 T# Y
<P><FONT color=#0000ff>return 0; & ?1 P7 u: V8 @
}
: i C8 I7 ?% v Z, S
. A6 p- f- v. P4 ?</FONT>. |0 r2 ?" N/ F/ C% q
</P>5 A; G/ q4 d. z
<P><FONT color=#0000ff>函数名: unlock </FONT>' k7 J0 t8 b4 E; |8 O
功 能: 解除文件共享锁 V3 T' @5 N5 p5 v) X: f/ j
用 法: int unlock(int handle, long offset, long length);
. @0 v* @6 j* T! C. A( J0 V# A程序例: </P>
$ c) T: l& Q* M* j$ H0 z<P><FONT color=#0000ff>#include <IO.H>% L0 i4 O0 D9 h
#include <FCNTL.H>% V5 W' {& \# z" a
#include <SYS\STAT.H>
4 z( T* t3 D, x- n#include <PROCESS.H>% K2 \' q. z' R- Q4 }1 Y" B! h
#include <SHARE.H>
, ?7 I3 r5 X8 S" c f; Q6 o1 A#include <STDIO.H></FONT></P>' q+ q0 S, e) `) q
<P><FONT color=#0000ff>int main(void) * F4 T! e' `4 o+ c" U3 u
{ ; H y6 n8 ^; C- J
int handle, status;
. h0 }2 E+ [: x5 c& a$ w5 Z! {* I5 slong length; </FONT></P>+ w9 Q0 F* n1 Z# s+ i( s
<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>
5 P" R$ ?# c+ ?& b# u<P><FONT color=#0000ff>if (handle < 0) 0 e: b( b$ _" X) P( p' c" c
{
$ t5 E0 z u) ^: W" Z$ nprintf("sopen failed\n"); ) K9 I2 Z0 ~% D/ V$ f/ }% j, Q) I
exit(1);
- d: A% B! J# F: X N} </FONT></P>
- t3 W- I0 m& F+ g( ^1 n1 R# C4 W<P><FONT color=#0000ff>length = filelength(handle);
S9 C5 i3 `. T8 B; sstatus = lock(handle,0L,length/2); </FONT></P>
: H7 t. J+ j" y" ]<P><FONT color=#0000ff>if (status == 0) u8 }9 J! Q' Z3 G+ n, [
printf("lock succeeded\n"); X9 C1 b" v" S/ r
else - R# @1 n5 v5 r: F! W
printf("lock failed\n"); </FONT></P>
1 L0 r- _$ s2 t# w; ~/ N<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>7 |6 a; {5 g# n
<P><FONT color=#0000ff>if (status == 0) , C6 c' A. q, @% t, k1 @# y
printf("unlock succeeded\n");
@' ~/ H% |2 ielse
. O& ^- \$ E# T# R* Q7 u" u4 Lprintf("unlock failed\n"); </FONT></P>
4 X4 k! m; v; k8 Y2 F. K( i$ [0 X& A2 L<P><FONT color=#0000ff>close(handle);
9 v* C ~9 X6 ], s5 j9 Dreturn 0; , B: @9 J7 H* y" S: Y
} </FONT></P> |
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