函数大全(k开头)

韩冰

< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(k开头)</FONT></B></FONT>
9 c' E0 {9 w, v</P>
<><FONT color=#ff0000>函数名: kbhit </FONT>
功 能: 检查当前按下的键
用 法: int kbhit(void);
& f: C: O* ^" t. I9 D* Z  ]7 U程序例: </P>
<><FONT color=#0000ff>#include <CONIO.H></FONT></P>
<><FONT color=#0000ff>int main(void)
9 U, ^! K- {1 O' ^; J{
6 W& Z# B% J& T9 F: x2 g) Scprintf("ress any key to continue:");
while (!kbhit()) /* do nothing */ ;
cprintf("\r\nA key was pressed...\r\n");
  S+ i* }; s$ z& Y7 D! Q& breturn 0;
, b% I, Y: t* M} </FONT>
</P>
<><FONT color=#ff0000>函数名: keep </FONT>
1 S: K) _! S: E* E& k功 能: 退出并继续驻留
; F' f  ~- ^6 A  r8 b用 法: void keep(int status, int size);
+ `& a1 P, t; _  t9 s+ e1 P程序例: </P>
<><FONT color=#0000ff>/***NOTE:
This is an interrupt service routine. You
can NOT compile this program with Test
+ ?; S/ J1 f1 V3 qStack Overflow turned on and get an
executable file which will operate
correctly. Due to the nature of this
4 G9 G7 D: D( x, Mfunction the formula used to compute
the number of paragraphs may not
necessarily work in all cases. Use with
; O/ C4 Z0 h+ ]; i( ?6 Z, X; qcare! Terminate Stay Resident (TSR)
programs are complex and no other support
, k# j* \! a" [5 L3 gfor them is provided. Refer to the
  c" O! v6 U7 M* m6 P6 UMS-DOS technical documentation
for more information. */
#include <DOS.H>
5 B' w" ]" O9 V# K: Z- V/* The clock tick interrupt */
  x$ ^+ B5 B2 z; n#define INTR 0x1C
/* Screen attribute (blue on grey) */
% x  y( m2 u. i#define ATTR 0x7900 </FONT></P>
<><FONT color=#0000ff>/* reduce heaplength and stacklength
0 M, |$ G! F; M6 pto make a smaller program in memory */
. B" u4 K5 V  _7 V; e1 H& n& Sextern unsigned _heaplen = 1024;
extern unsigned _stklen = 512; </FONT></P>
<><FONT color=#0000ff>void interrupt ( *oldhandler)(void); </FONT></P>
<><FONT color=#0000ff>void interrupt handler(void)
{
unsigned int (far *screen)[80];
static int count; </FONT></P>
<><FONT color=#0000ff>/* For a color screen the video memory
is at B800:0000. For a monochrome
3 t) y' ?2 q& _$ N, U4 @2 L4 nsystem use B000:000 */
screen = MK_FP(0xB800,0); </FONT></P>
# @& d6 ?! G. P! G5 t0 p4 @8 U# o# S<><FONT color=#0000ff>/* increase the counter and keep it
within 0 to 9 */
' H" w  v8 C9 ^' l: \count++;
count %= 10; </FONT></P>
<><FONT color=#0000ff>/* put the number on the screen */
: h" N: |, o# _# f* Nscreen[0][79] = count + '0' + ATTR; </FONT></P>
<><FONT color=#0000ff>/* call the old interrupt handler */
5 R8 _; }8 i" ?oldhandler();
} </FONT></P>
0 o6 z' d! D- H7 k' \" k<><FONT color=#0000ff>int main(void)
) u- X2 N" E7 [{ </FONT></P>
<><FONT color=#0000ff>/* get the address of the current clock
tick interrupt */
oldhandler = getvect(INTR); </FONT></P>
8 K; }' y1 V4 Z+ v/ E% I. m<><FONT color=#0000ff>/* install the new interrupt handler */
' Q3 y. C) _) jsetvect(INTR, handler); </FONT></P>
<><FONT color=#0000ff>/* _psp is the starting address of the
program in memory. The top of the stack
8 C1 S; x/ c& ]) Y  Y3 Y2 M9 _. Kis the end of the program. Using _SS and
_SP together we can get the end of the
* P1 n" Y' g# |6 ?. ]. c: Ustack. You may want to allow a bit of
4 _. Q6 c; h# Rsaftey space to insure that enough room
is being allocated ie:
* j. ]# ]1 G, Z$ {; ^% e" @4 W(_SS + ((_SP + safety space)/16) - _psp)
*/
* C" u' [& u! x6 Wkeep(0, (_SS + (_SP/16) - _psp));
" f( s- @% Q( s$ hreturn 0;
2 ~: ^# z7 \3 Q* T& B- k* l5 Y) [1 m}
' B& q$ ]/ ~  w) P1 e1 ]# e</FONT></P>
2 G- n$ {* A- l7 w$ ]( f

<><FONT color=#ff0000>函数名: kbhit </FONT>
8 k3 v* f( `! |( b* h2 V% H功 能: 检查当前按下的键
/ O" M. [4 H: Z% v5 |& F5 u用 法: int kbhit(void);
程序例: </P>
<><FONT color=#0000ff>#include <CONIO.H></FONT></P>
<><FONT color=#0000ff>int main(void)
{
" \2 D5 `: M4 q) I$ ucprintf("ress any key to continue:");
while (!kbhit()) /* do nothing */ ;
cprintf("\r\nA key was pressed...\r\n");
return 0;
6 R5 u' e/ q3 }6 y}
; o0 b. g# ?$ Y; Q

  P) H# k0 ?# |  j/ V# z</FONT></P>
<><FONT color=#ff0000>函数名: keep </FONT><FONT color=#0000ff>
, W! I3 ?2 r$ o8 T0 E3 D7 L<FONT color=#000000>功 能: 退出并继续驻留
用 法: void keep(int status, int size);
& |$ R4 C9 S3 w程序例: </FONT></FONT></P>
<><FONT color=#0000ff>/***NOTE:
* P# U, s" D" X! ]This is an interrupt service routine. You
can NOT compile this program with Test
( P( X2 R8 _0 X- {" G6 ^4 @Stack Overflow turned on and get an
. y9 N9 n% f% Uexecutable file which will operate
correctly. Due to the nature of this
function the formula used to compute
6 ~1 `' q3 U' \7 k/ ^8 ithe number of paragraphs may not
necessarily work in all cases. Use with
care! Terminate Stay Resident (TSR)
% |2 r# s  P2 ]( U; wprograms are complex and no other support
for them is provided. Refer to the
MS-DOS technical documentation
5 [6 O. v( \. @& U1 \. i' Xfor more information. */
#include <DOS.H>
/* The clock tick interrupt */
#define INTR 0x1C
. R) ]* X5 v3 Z+ k( O$ p+ B7 s/* Screen attribute (blue on grey) */
#define ATTR 0x7900 </FONT></P>
<><FONT color=#0000ff>/* reduce heaplength and stacklength
to make a smaller program in memory */
extern unsigned _heaplen = 1024;
: F2 r% Q4 _- c! c7 Jextern unsigned _stklen = 512; </FONT></P>
<><FONT color=#0000ff>void interrupt ( *oldhandler)(void); </FONT></P>
<><FONT color=#0000ff>void interrupt handler(void)
9 V% _7 l" d4 s" E9 u; [7 }; S/ T{
  u7 w& @/ J& j& T3 q+ aunsigned int (far *screen)[80];
static int count; </FONT></P>
3 O% ^/ ~9 {5 ]1 {$ k$ M<><FONT color=#0000ff>/* For a color screen the video memory
  W" F$ G1 M( \* H) j$ V  ?; d4 Cis at B800:0000. For a monochrome
system use B000:000 */
8 [4 h, K( y# ]' ^/ V* g; |screen = MK_FP(0xB800,0); </FONT></P>
" f, \6 E' G- r4 n3 O9 O" t) n<><FONT color=#0000ff>/* increase the counter and keep it
within 0 to 9 */
count++;
2 y0 x2 @* O: S4 ~! y+ V$ mcount %= 10; </FONT></P>
& V( B" Z+ O3 n9 s3 e<><FONT color=#0000ff>/* put the number on the screen */
) F/ Q* E: H/ F0 tscreen[0][79] = count + '0' + ATTR; </FONT></P>
<P><FONT color=#0000ff>/* call the old interrupt handler */
oldhandler();
1 ?! K+ @, P4 T} </FONT></P>
<P><FONT color=#0000ff>int main(void)
{ </FONT></P>
<P><FONT color=#0000ff>/* get the address of the current clock
tick interrupt */
oldhandler = getvect(INTR); </FONT></P>
; h0 o! J, f5 L<P><FONT color=#0000ff>/* install the new interrupt handler */
setvect(INTR, handler); </FONT></P>
7 \1 P* F0 I9 e/ n( ^& E: s2 E<P><FONT color=#0000ff>/* _psp is the starting address of the
. c8 x: L8 Z. p! J0 M/ X; tprogram in memory. The top of the stack
, V, i3 x1 ]4 z1 e6 vis the end of the program. Using _SS and
_SP together we can get the end of the
stack. You may want to allow a bit of
: }+ x; }3 j" Z" isaftey space to insure that enough room
is being allocated ie:
(_SS + ((_SP + safety space)/16) - _psp)
3 ^7 M" C, l4 ~, @*/
keep(0, (_SS + (_SP/16) - _psp));
return 0;
}</FONT></P>