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(你应该发一个新帖让网友们帮你解答,不要跟我的帖)
% |& S2 t) t& x/ z }多元回归的代码如下: x=[6744 4536 4893.6 8860.8 7507.2 6782.4 9494.4 6216 6432 8380.8 7375.2]'; z=[6.1 8.5 6.4 5.4 6.3 6.7 5.2 6.6 6.9 5.7 5.9]'; w=[20.95 29.6 21.77 21.38 22.19 24.24 25.93 19.52 19.39 21.54 24.44]'; y=[9460.9 19076.5 13846.7 8342.2 10685.1 11403.1 7384.6 12873.5 10524.5 10446.0 12280.6]'; X=[ones(11,1),x,y,w]; [b,bint,r,rint,s]=regress(y,X,0.5) 得到回归结果: b = g- h- t1 e* ^4 _/ z" B2 x. `( w
1.0e+003 * ( L2 y) {9 D" Z! i: J8 n' _) F. M
7.63365814703216 -0.00125510669136 0.83801013875319 0.32224150099284 5 f& O% X. b3 S
bint = . C7 P. N* J' M) T; r
1.0e+004 *
' B H; G. B8 @! {6 f/ p -1.30439270279949 2.83112433220592 -0.00025564588870 0.00000462455043 -0.15661574000751 0.32421776775815 -0.00588755516686 0.07033585536543 . @ f$ f) g# {- \9 g
r = - U: L6 e: d& P" ~- @; ]
1.0e+003 * 9 P8 }* g# K* S6 X% K
-1.57113991271872 0.47457119617056 -0.02343040684476 0.41501318324491 0.04377602514276 -1.14372443728898 -1.04594801887843 1.22056403128825 -1.06684456987565 1.61340028960900 1.08376262015110 & c9 Z/ v8 m) C' Y( v
rint = & `, F, g' j4 Z( F
1.0e+003 * 3 R8 Z' P+ D/ y& ~" F+ Z$ y3 U
-4.18060826996541 1.03832844452798 -0.58713163609601 1.53627402843712 -1.63265383009492 1.58579301640540 -2.41980607307114 3.24983243956095 -3.01244690932543 3.09999895961095 -4.02599379571372 1.73854492113576 -3.03725872250225 0.94536268474539 -1.33675472238316 3.77788278495966 -3.27677184264986 1.14308270289856 -0.92047402141587 4.14727460063388 -1.61182764620170 3.77935288650389
0 c2 R6 C$ q8 Y' P: ~ s =
) R Y1 H& b4 ?( x7 U 1.0e+006 * : K7 C) `) j) S- g( l
0.00000088230440 0.00001749182053 0.00000000124110 1.66800690870350 也就是说,方程为: y=7633.65814703216x-1.25510669136z+838.01013875319w+322.24150099284 " w* B; a. {- D4 v) Q0 k
都不是很显著,因为置信区间都过了0点! 0 t: z8 o" B5 I* F |# O
[此贴子已经被作者于2008-8-9 13:02:27编辑过] |