QQ登录

只需要一步,快速开始

 注册地址  找回密码
查看: 3071|回复: 9
打印 上一主题 下一主题

虚二次域例两(-5/50)

[复制链接]
字体大小: 正常 放大
lilianjie        

43

主题

4

听众

204

积分

升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    跳转到指定楼层
    1#
    发表于 2012-1-4 17:41 |只看该作者 |倒序浏览
    |招呼Ta 关注Ta
    本帖最后由 lilianjie 于 2012-1-4 17:54 编辑
    , Z2 ~% K# T; @0 N& }0 A1 e  o+ ~2 m5 s9 Z, X  \8 ^; e% |
    Q5:=QuadraticField(-5) ;
    8 V4 o' x3 A1 V4 BQ5;
    & M% C$ G0 _4 ~' f1 h0 N4 u. B0 B& m7 K* Q. |# u
    Q<w> :=PolynomialRing(Q5);Q;
    8 u9 U# Y: E1 R0 W9 G  ?* ~( b; aEquationOrder(Q5);
    8 J' E- M# A  i1 |: d/ U4 qM:=MaximalOrder(Q5) ;) G9 @) z, _8 J( y1 y
    M;
    % j8 N! g' @2 n9 GNumberField(M);) w4 _  ^: m9 x3 [
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    ! |6 ^4 R8 F) |- |# p+ h" V& TIsQuadratic(Q5);
    " [7 ]1 `# v" h) w4 cIsQuadratic(S1);2 z% U2 k  j3 c% N
    IsQuadratic(S4);0 d$ S  p: W( c1 h5 g, x* [+ ~
    IsQuadratic(S25);
    ' R% t% e2 [8 yIsQuadratic(S625888888);7 Q( D; k4 o4 C7 E
    Factorization(w^2+5);  
    , w, C  {$ B0 e5 ]+ E4 vDiscriminant(Q5) ;2 A( `2 ^+ h5 e
    FundamentalUnit(Q5) ;
    " l: x, J* N) }) V0 GFundamentalUnit(M);
    , ~* L. o7 l+ y# oConductor(Q5) ;! K1 v4 ^7 o. `) h' L+ B

    # U! q; n$ F3 UName(M, -5);  I9 \# k# G$ n$ S
    Conductor(M);
    : |& F/ b, w" U7 [5 `0 AClassGroup(Q5) ;
    - p9 s1 \# T: eClassGroup(M);
    5 I: {6 c% @! o* o' kClassNumber(Q5) ;: z$ w" [) w4 @
    ClassNumber(M) ;4 T9 m$ }+ c. R! x0 M! |* q' ?
    PicardGroup(M) ;
    . v- `; q* a+ t$ ~7 iPicardNumber(M) ;
    3 N& F" m+ B. T; r
    # {$ B8 u0 w" zQuadraticClassGroupTwoPart(Q5);
    . m) @; |4 t( r) N* M2 j6 S. QQuadraticClassGroupTwoPart(M);
    % c6 t* t" H, ?+ H1 |% Z3 p6 gNormEquation(Q5, -5) ;! f4 A3 _+ P, b: @
    NormEquation(M, -5) ;+ d4 u; l1 ]9 T+ c- X+ m
    Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field- c! O+ o$ {6 w1 ^
    Univariate Polynomial Ring in w over Q5. X: T0 S5 Y/ Y9 }
    Equation Order of conductor 1 in Q5! Y' \) j% a5 V9 c& I3 g
    Maximal Equation Order of Q5
    * n, @: M$ X, kQuadratic Field with defining polynomial $.1^2 + 5 over the Rational Field& X! k/ z  o" m& c+ }' }
    Order of conductor 625888888 in Q5
    4 }1 G3 z7 N: `5 L) {  b% Ctrue Quadratic Field with defining polynomial $.1^2 + 5 over the Rational Field
    9 v, o/ j3 z* i, jtrue Maximal Equation Order of Q5
    9 A# c- n$ c; J. `! f- Ktrue Order of conductor 1 in Q5
    2 z# _# g  T; R. @+ }true Order of conductor 1 in Q5  B& E8 n4 v& Z
    true Order of conductor 1 in Q5
    9 X; g. f4 l& M* h3 ^$ ?/ q[/ r9 y7 \2 m8 C
        <w - Q5.1, 1>,9 \1 e$ _! H6 B& L$ ]
        <w + Q5.1, 1>
    # l$ v% E+ n  U4 k. g0 V! @]/ b8 c; K  D3 Z* ]& S: z3 ^, S$ q
    -20% B- B9 j% z9 y  @* L9 c- A5 w+ @
    8 {3 V* B) c) T2 K; o9 O( [
    >> FundamentalUnit(Q5) ;
    6 y0 ?5 G2 b8 h/ y                  ^
    / T9 e) P/ O# ?* V" L1 lRuntime error in 'FundamentalUnit': Field must have positive discriminant) a( a) q% w& J. x8 _/ s" d- _8 x

    7 l7 S4 u* X5 Q8 X& p. c1 C# y( _5 U
    6 z1 g2 T( c; o. d& j) R) g1 F>> FundamentalUnit(M);" P% R- G9 [5 p4 |! V' |
                      ^
    + S. Q3 i1 n2 @5 uRuntime error in 'FundamentalUnit': Field must have positive discriminant0 c# R3 S+ Q2 \4 m( X- r* C
    6 H/ K/ ?; n3 _. b: N" ?
    20
    ! g- |" {1 z+ H0 H9 I% W7 k
    * E+ S+ |, n8 a4 y' K& I$ _, A. j>> Name(M, -5);" c7 z% n  I+ F9 ?& v1 O- J
           ^- C. |0 G/ R+ _2 z' J
    Runtime error in 'Name': Argument 2 (-5) should be in the range [1 .. 1]
    3 ?$ b2 E7 R6 f( Z
    ( [/ t. ?# J( B% z8 N1
    ; q) @2 H1 G- c/ t: K3 ^' v) X9 ~: CAbelian Group isomorphic to Z/2
    4 K. M; N2 e1 M/ B& hDefined on 1 generator
    ! w4 a8 i$ S  WRelations:- S- t( l& t: A0 D- `
        2*$.1 = 0
    * n& a- B0 L8 p3 y+ R9 GMapping from: Abelian Group isomorphic to Z/2
    " e2 h& X  ^$ g" g4 eDefined on 1 generator- \( {1 {; v6 e, i
    Relations:6 Y3 q7 E: N/ h1 ?* j- B( F' @, ?
        2*$.1 = 0 to Set of ideals of M, L8 t; U/ ?# v, U
    Abelian Group isomorphic to Z/2& r5 R) P# j- K: f- e
    Defined on 1 generator+ I" U. [! R5 E7 F8 D* B
    Relations:0 M* `1 C2 x: Y/ p
        2*$.1 = 0
    3 T( R9 H: e* ^! O1 UMapping from: Abelian Group isomorphic to Z/2
    4 D& P# y7 @7 d4 K# G; C% \' qDefined on 1 generator  w+ _7 h. q% s! X" T; D$ {
    Relations:1 B6 s3 o& J+ ^" t; N5 z
        2*$.1 = 0 to Set of ideals of M
    * k# \% w9 k9 g2
    ( L0 e2 |- p' h$ M, f4 L% a29 Z7 s+ f: ]# O# H* q
    Abelian Group isomorphic to Z/2
    2 p7 B7 e8 E5 j7 _$ }Defined on 1 generator; J+ X' T9 v2 A) l
    Relations:8 o% ^/ w4 A3 Z2 F
        2*$.1 = 0
    ; W6 H  L1 L8 ]" ^3 _9 ~Mapping from: Abelian Group isomorphic to Z/2
    - k9 B9 H3 E! Z1 L; O9 S; \! O" K/ v: ?Defined on 1 generator
    5 b0 o' d  Q) X0 L3 |( Z/ yRelations:9 l: i4 [+ V3 X% |, L1 z
        2*$.1 = 0 to Set of ideals of M given by a rule [no inverse]
    3 ^. n  v( u+ r2
    1 p) L/ J' n9 x' BAbelian Group isomorphic to Z/2; c  S+ t! A4 \8 p! v
    Defined on 1 generator$ R) i: P! M8 `5 D4 K! y
    Relations:
    ' v: r! V. U/ k: J    2*$.1 = 08 G  j& m/ r8 E4 V
    Mapping from: Abelian Group isomorphic to Z/2
    - q1 f) R  K  \3 ~Defined on 1 generator
    3 R' B6 G7 `3 f6 ^( K$ iRelations:
    8 v9 ]5 q+ k0 C8 J2 ~  h7 C- \, |) k( J    2*$.1 = 0 to Binary quadratic forms of discriminant -20 given by a rule [no
    " T+ e3 G& x5 [inverse]
    ' K8 }. l- X0 |- P" d. b8 nAbelian Group isomorphic to Z/2
    # ]5 k7 S0 _" N$ f8 d$ r8 ?Defined on 1 generator
    9 t/ D( d$ r6 |! _% }5 GRelations:+ `4 h( }  b& e! `
        2*$.1 = 0
    1 N& F; i* \+ o' \0 MMapping from: Abelian Group isomorphic to Z/2" a& a7 V8 l/ }) B- Q
    Defined on 1 generator! L. x5 _2 x' L: g3 }
    Relations:
    ( v2 b0 ^5 u8 v; z% C    2*$.1 = 0 to Binary quadratic forms of discriminant -20 given by a rule [no . c8 h' V8 o1 H9 k
    inverse]. ]0 K. K# m: g
    false
    8 l; |7 b9 v2 |" S% G" n; A6 Qfalse9 K. U$ U9 \; I/ K  a0 \
    ==============/ e; a5 U; @2 I$ ^0 ^( U9 F

    & h% [" [$ W# }' [4 T# ?
    1 S  @1 ]" @6 Y5 k& \  _Q5:=QuadraticField(-50) ;
    , D# N! ^& u$ `8 HQ5;3 B7 Y9 E- I8 J

    ; F  [7 l0 S  W0 TQ<w> :=PolynomialRing(Q5);Q;+ Q$ F; K- x& q* T+ K
    EquationOrder(Q5);5 f  \, w" U& S3 i6 i6 }) S8 [
    M:=MaximalOrder(Q5) ;. P; j$ q# ^$ z- M/ i
    M;
    - K+ v6 g, ]* R$ F; y3 MNumberField(M);9 ?7 ^; v; K+ o" @
    S1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    ! P1 P9 {$ t: X: s! D" Q/ U3 ]IsQuadratic(Q5);. [1 n* r+ [2 \' {$ @, i
    IsQuadratic(S1);$ c1 O/ I* p6 o
    IsQuadratic(S4);- F) _6 e1 r7 q' \$ o. Q& k
    IsQuadratic(S25);
    : [9 q; _/ o) H" R" kIsQuadratic(S625888888);7 l7 ?. f  r% l4 k+ }+ r6 U) m4 u
    Factorization(w^2+50);    r3 B# u0 }3 p, r0 k
    Discriminant(Q5) ;( _+ d! D7 Z* ~* {9 }; c
    FundamentalUnit(Q5) ;
    / E7 w) c$ w/ q' v9 N$ WFundamentalUnit(M);
    ) y. M# s3 Q' {; EConductor(Q5) ;
    - k5 z" }8 v9 i" {1 Y& h# C" E( m4 Y& R/ A- X
    Name(M, -50);
    7 n! w5 ]: ^3 c9 ZConductor(M);" J. n( Z+ U9 D
    ClassGroup(Q5) ; " |" r) J0 ^" J6 P- O& R) `
    ClassGroup(M);$ m) C- W% Q' e6 a1 }3 @+ l
    ClassNumber(Q5) ;% c* g: @7 P% }. j( e4 @
    ClassNumber(M) ;
    # i8 y6 ]/ m1 Y4 q; NPicardGroup(M) ;
    # {( {6 {8 q5 v9 y8 GPicardNumber(M) ;
      P4 O) C* U' m2 I
    3 I+ \: A  c2 _: J5 U' {3 ?QuadraticClassGroupTwoPart(Q5);
    " Z4 W) B/ ]8 a) y' ?  n( RQuadraticClassGroupTwoPart(M);1 ]/ C$ V) K, m: B: I
    NormEquation(Q5, -50) ;8 U$ U& K! F/ m5 _
    NormEquation(M, -50) ;
    3 H" S- a; m5 B
    - n$ ~, S( O7 hQuadratic Field with defining polynomial $.1^2 + 2 over the Rational Field) U  m7 k$ q# A+ w8 C/ X
    Univariate Polynomial Ring in w over Q55 w, t5 Q- w+ n- p9 Q& k# L
    Equation Order of conductor 1 in Q5
    $ o5 l: \) {6 \' J6 K* IMaximal Equation Order of Q5
    ! B3 c  _0 F& ^) vQuadratic Field with defining polynomial $.1^2 + 2 over the Rational Field
    - D0 Q/ E1 ^2 k5 u/ LOrder of conductor 625888888 in Q56 K  O. L% z+ F- J
    true Quadratic Field with defining polynomial $.1^2 + 2 over the Rational Field
    % t" ]% V  ^* d. F7 f9 M# R0 |true Maximal Equation Order of Q5
    " M9 L0 Z3 d! M# b- B% ytrue Order of conductor 1 in Q5
    ! F# j  M5 E, t9 ltrue Order of conductor 1 in Q5
    9 R3 w/ V3 R, P4 M8 l  t( m. Ltrue Order of conductor 1 in Q5" ]* C! P5 }9 j7 K
    [' N# U4 B/ b; S1 x) r8 B$ V7 a
        <w - 5*Q5.1, 1>,. l' k2 l9 G7 k/ m4 C
        <w + 5*Q5.1, 1>
    & I; Z/ X- {0 Q9 H, v+ c]
    8 W# V- m& Q2 W4 b/ q- V-8
    * [# k8 Q* `  T+ D& H9 K! E
      ^, B9 D- _+ S+ h) U& d>> FundamentalUnit(Q5) ;
    1 g' k) u' S) |4 q3 f5 O                  ^- N  k: M7 e7 H+ d
    Runtime error in 'FundamentalUnit': Field must have positive discriminant5 e7 l5 O6 f; O# l; ^

    2 F1 s9 c& z2 A' k# ~  T+ C# U/ A/ J, m
    >> FundamentalUnit(M);3 M' F; J. k% \" v
                      ^
    " d& Y! M0 K1 jRuntime error in 'FundamentalUnit': Field must have positive discriminant& t( W+ A8 c4 H1 J

    2 {$ U* t2 g1 s7 b4 ~+ N8
    9 W8 ^% p1 E& {: w
      m, g6 k1 L, J2 y>> Name(M, -50);
    4 c5 s; t/ m' E3 W0 a       ^
    ; f- U1 S- M. a' u) `6 Z- TRuntime error in 'Name': Argument 2 (-50) should be in the range [1 .. 1]
    * O' A6 u4 i2 r, e. A6 X1 N' n6 ]! B  Z2 J# L9 m! p: f* m8 H
    12 y. t, s4 a) r$ K. h
    Abelian Group of order 1
    / ~1 a( l4 J" d. H' j0 sMapping from: Abelian Group of order 1 to Set of ideals of M# Q4 v/ O; ^! f0 W+ k% t. C
    Abelian Group of order 18 ~3 b7 R! F7 q* y5 V$ o: {
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    $ i  F! _6 E% M1 i- z1* f9 Q. C& R( d' |
    1
    ! t, S* p3 M3 ~$ E& [" CAbelian Group of order 1; F) x' C$ p0 P$ j/ |
    Mapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no: e, p0 g) ~. ?4 ?
    inverse]
    : l+ w. V, t$ _0 a% [2 m1
    1 J0 L) O0 E1 c! XAbelian Group of order 1! G6 v# d, A0 r. y. [" a* }, d  v
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant! |' Q5 u, X, ^6 W) j* N, ]
    -8 given by a rule [no inverse]" E, s. W* M0 u7 Y0 l; o( b
    Abelian Group of order 1
      Q- L5 ?( T% TMapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    " ^9 x+ Q/ G$ G' b2 X  s) V0 Q% Y-8 given by a rule [no inverse]
    6 U* f) Y' q. D7 [* X7 ]1 Bfalse; ?& P7 c" A4 j
    false
    + u: M; E; l1 {) q3 ^1 v: T
    zan
    转播转播0 分享淘帖0 分享分享0 收藏收藏0 支持支持0 反对反对0 微信微信
    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    看看-1.-3的两种:/ l6 w$ z6 B& a! o
    8 q0 B. o$ }9 N/ }
    Q5:=QuadraticField(-1) ;4 c" g2 a  j& f3 q; L: e( j' p$ z
    Q5;
    # W  l, {0 Q6 N3 O, Q8 ~
    9 O. {8 t. s! Q* M" G8 n* BQ<w> :=PolynomialRing(Q5);Q;  N; O: h+ P" \: }, K
    EquationOrder(Q5);5 T+ x/ u/ e* _  o; s
    M:=MaximalOrder(Q5) ;
    % A. g( L6 M  B$ gM;* g& w" b; E/ Y0 z, Q6 f7 ~4 x# U
    NumberField(M);
    1 g& a. Q2 ]' HS1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;
    9 E1 g8 M7 z' ]9 j9 ^6 v6 xIsQuadratic(Q5);; k  Z* L# [9 E' G! B  Q: _+ r7 p1 m
    IsQuadratic(S1);
    ) N0 l# _2 O9 x, a5 AIsQuadratic(S4);
    3 d& C$ b5 C8 K$ rIsQuadratic(S25);
    6 M/ i& o- o2 I) dIsQuadratic(S625888888);6 ]) ~% s9 w0 x0 j8 }
    Factorization(w^2+1);  " z8 g. Z( n2 }
    Discriminant(Q5) ;
    + k" m* t+ M: o! hFundamentalUnit(Q5) ;
    ; `+ o* Q* I* @FundamentalUnit(M);" n) V, f4 i' Q, |
    Conductor(Q5) ;6 Q, o% L2 E8 s  ^+ r

    0 d# ~  \4 Y# T: O/ wName(M, -1);
    4 R  P3 Y$ q0 ~* A: M4 AConductor(M);$ M# l1 i) u. c9 R" y7 @2 h
    ClassGroup(Q5) ;
    % }2 U7 t$ W1 c* dClassGroup(M);/ u6 U& `4 s/ `7 W
    ClassNumber(Q5) ;
    4 ?3 P4 M" Q2 a0 N. t3 z7 B: ?ClassNumber(M) ;
    : A/ k3 `2 V+ B/ W# ]& [' QPicardGroup(M) ;0 b% g9 G2 Z) u; l
    PicardNumber(M) ;0 r7 T* U, F: b7 y) V+ l

    5 B! k" \9 m; A  RQuadraticClassGroupTwoPart(Q5);$ d# s& b8 V7 Y6 \  F. K! i7 f
    QuadraticClassGroupTwoPart(M);: R( i0 x2 G4 d
    NormEquation(Q5, -1) ;
    . n& _1 S8 a0 f/ `8 D4 W# `2 hNormEquation(M, -1) ;
    ; ?  h: z, h! e. a# w9 J- H0 M. t4 W& Y# G- v
    Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field" J2 J  C9 a) P2 P
    Univariate Polynomial Ring in w over Q5
    2 f+ i6 W& {( m3 X, ]( YEquation Order of conductor 1 in Q5
    ; ?; W: a' c- q* E  z  m/ IMaximal Equation Order of Q5, A* u  m) a7 w4 l
    Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field
    ) R" j- w' q' y( S7 qOrder of conductor 625888888 in Q50 k( ^3 X! M+ e/ c& d
    true Quadratic Field with defining polynomial $.1^2 + 1 over the Rational Field# A/ O; P) E4 N; b. R
    true Maximal Equation Order of Q5) T1 h1 A7 z& B! k+ X' B/ p" T6 g
    true Order of conductor 1 in Q5' f; R( Y$ ?. o2 u. X3 z$ P$ w
    true Order of conductor 1 in Q5
    + y7 y, e2 T& E' M7 Ltrue Order of conductor 1 in Q5$ h. C  I9 u, Y& L. p
    [
    4 I) a7 B8 B& ^" x$ f& J    <w - Q5.1, 1>,* Y# b% x+ ~, a$ t
        <w + Q5.1, 1>4 @; f3 z5 A; A" l1 B+ V% R8 H- B( m
    ]! f) c% a4 x" g4 B! y
    -4
      ^+ j; z$ O. s- p
    $ b$ N! I7 O0 x>> FundamentalUnit(Q5) ;
    $ U7 l0 A0 G( N, @+ m                  ^7 J0 s8 B' j8 k$ [1 o) m
    Runtime error in 'FundamentalUnit': Field must have positive discriminant
    - I2 c3 D* I% z: _) D6 E! H% H' d9 ]. y# X" p' U% Q% h) P# {

    % r" b: Y* Q" l( p) y: Y>> FundamentalUnit(M);4 S' l+ k8 B4 s0 u4 E
                      ^
    & t5 @. v3 K! d/ b/ T3 q! iRuntime error in 'FundamentalUnit': Field must have positive discriminant
    7 Z: r. k5 t/ `: p% Q
    ( m( F; p5 w2 w! s/ o) J; I46 U- l# x. N" i7 D% g) F
    4 D  Z- m0 q* g+ p/ q4 v
    >> Name(M, -1);( C) }' i: z+ p
           ^
    * K( ?6 J  ]  Q& dRuntime error in 'Name': Argument 2 (-1) should be in the range [1 .. 1]5 x* s6 J% g; c
    6 w! e6 X/ d: G, z# o
    1! |7 D# N7 _$ f
    Abelian Group of order 1
    & z4 D* P( ^. w; f5 z& W4 f2 XMapping from: Abelian Group of order 1 to Set of ideals of M0 J) @" q# G& O
    Abelian Group of order 1
    ' a1 S) ^1 b: n/ RMapping from: Abelian Group of order 1 to Set of ideals of M
    # }8 G+ R( \* D& m1
    # Y, L" W/ `2 @6 S9 Q5 X) _1
    * V9 D$ K) H! vAbelian Group of order 15 q4 o8 J. O6 \9 o) m* l
    Mapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no; F, P& R8 \( d8 C: F/ J
    inverse]6 }: t2 O' w) C0 x, K2 a
    1. m( j2 c6 h0 Q( |$ s" `
    Abelian Group of order 1. g6 X, `, ?8 y' U( t
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant
    ( V7 i% Y/ `7 p  ^-4 given by a rule [no inverse]) C4 k  c, I/ w' v: d. B8 X4 |
    Abelian Group of order 1
    ' f- c- g" n. J7 I2 }+ m" _Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant7 y3 Q, m  X0 a7 T
    -4 given by a rule [no inverse]/ P% p- ~1 u  z2 U
    false' ]8 m$ d' M7 l- e3 T, t
    false
    ( J1 u+ F6 B; d& z7 ?===============& [$ }% k9 U* V! }

    % `- M' ?' K5 n6 ?Q5:=QuadraticField(-3) ;/ d" Y9 t- s. E( c/ o) R% _7 |
    Q5;0 Z) A, R$ C$ D) N
    0 C% J0 ^& ]3 q+ a  @
    Q<w> :=PolynomialRing(Q5);Q;, E6 g, i8 g& @$ Y8 w2 \# l2 w
    EquationOrder(Q5);6 O, g' t' J% |  R
    M:=MaximalOrder(Q5) ;: }% Q0 Q$ X$ g
    M;
    3 }/ I& {" Q  `6 \NumberField(M);
    , k$ `) U, i" u, rS1:=sub< M | 1 >;S2:=sub< M | 2 >;S3:=sub< M | 3 >;S4:=sub< M | 4 >;S5:=sub< M | 5 >;S25:=sub< M | 25 >;S625888888:=sub< M | 625888888 >;S625888888;/ L+ L, ]; G  e( r
    IsQuadratic(Q5);, m( s. G0 P) Q$ N6 v
    IsQuadratic(S1);
    9 N# G& l, o  o4 f  i1 ^IsQuadratic(S4);4 w9 e; }) F7 I2 k3 w" T9 b
    IsQuadratic(S25);
    ! N* m/ U9 C# ^' G. z5 K( WIsQuadratic(S625888888);
    ' Y5 }7 o6 r% QFactorization(w^2+3);  9 p* Q  ]& H; p1 a3 R
    Discriminant(Q5) ;% ~( M5 O1 n+ A& K
    FundamentalUnit(Q5) ;1 W5 u9 \% ^" ?# C) k+ U
    FundamentalUnit(M);0 p4 {! D# H1 p$ \# U
    Conductor(Q5) ;* F. ]: \# R2 R

    + q9 U7 i- T; W$ k" }Name(M, -3);
    % @; G0 g0 Q- Q' }7 FConductor(M);# C1 l+ a- L( q4 i) |
    ClassGroup(Q5) ; 8 G9 o/ v0 @- _$ V7 J
    ClassGroup(M);, z* c* f# w! H; s: T9 e& {
    ClassNumber(Q5) ;
    0 o$ k. y! L+ @! `- UClassNumber(M) ;* e* C1 X* }9 [: j, {! e
    PicardGroup(M) ;
    : r) P' D7 `- pPicardNumber(M) ;  L' ^$ p% ?8 ^  w; b, y5 H

    9 |6 V' {* O0 cQuadraticClassGroupTwoPart(Q5);5 e2 `8 p* g  I% l" Y' v
    QuadraticClassGroupTwoPart(M);7 }, s- y  @0 k! F5 q- I, i
    NormEquation(Q5, -3) ;
    1 Q3 Z* Z/ o. A# ONormEquation(M, -3) ;
    ' I3 d( n+ k, Z4 h+ H$ n# l4 P$ }& ~- |" |$ v! h9 W( x
    Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field9 i% y# s9 ^- j; M3 m
    Univariate Polynomial Ring in w over Q5
    1 T! V' Z6 ]7 L, f* p9 T! lEquation Order of conductor 2 in Q5
    3 j( D5 {: O6 w( Y$ k9 V2 R  j- ?  CMaximal Order of Q5
    & \+ ~) q4 }0 Y3 X! S/ N8 FQuadratic Field with defining polynomial $.1^2 + 3 over the Rational Field. j% K$ @3 v7 W" j% V0 t" B
    Order of conductor 625888888 in Q51 t2 F1 ^: W4 I  Q9 Q0 x
    true Quadratic Field with defining polynomial $.1^2 + 3 over the Rational Field
    - K7 K. }2 p8 K) D8 w  ], {/ ~) M6 utrue Maximal Order of Q5
    % Z3 {2 M6 S- Btrue Order of conductor 16 in Q58 N$ E$ c# H7 x! t; N
    true Order of conductor 625 in Q5" w" ~- ]; \9 c  ?& m% m! U
    true Order of conductor 391736900121876544 in Q58 D5 f2 q$ d+ c2 g. F- E
    [2 h  f- x4 j( T/ u+ y$ l
        <w - Q5.1, 1>,
    4 x0 g; f8 Y- d6 ~4 ^' w    <w + Q5.1, 1>  q( N  I$ u" t( {) M: b! u
    ]$ J4 l* P. Z5 E+ }
    -3
    ; s2 i2 p0 K$ W+ V  D' ?1 r
    & D1 \' b% g' ~" v& v- H# P>> FundamentalUnit(Q5) ;1 l. x- x& q( t% u& O
                      ^
    8 T" F) S8 S3 a% j" g& w. ARuntime error in 'FundamentalUnit': Field must have positive discriminant
    # d. \) W) t" }/ x* }9 x; w" B/ [+ O9 A5 U

    5 T* Q. ]3 T" n- Q9 ]>> FundamentalUnit(M);6 {( `! s: }' r/ x- t% U( x) H
                      ^
    / r' |0 U  S0 V6 M% M5 H. P" g8 `8 k7 F& ?Runtime error in 'FundamentalUnit': Field must have positive discriminant3 G4 E% z" {/ }" K" c: n& P% @
    $ l1 u. V# e  r4 |" k
    3
    % |8 k: ?8 ?3 g( K: I5 ^2 e" v( m
    & G' q8 M* s5 X7 p. g1 _>> Name(M, -3);7 U1 T0 u* D& i5 ?  F0 L% d' }
           ^# |' _) }* O0 n% w0 ]6 k9 I
    Runtime error in 'Name': Argument 2 (-3) should be in the range [1 .. 1]8 D( P8 X+ }1 B8 t# U: b1 v9 S: X
    ; l  P" z' H0 D: ~, U
    18 m- K8 e+ J  M; o, C2 z) |7 ~
    Abelian Group of order 1
    0 ?0 |% C# T" D$ a) V4 D6 D3 [Mapping from: Abelian Group of order 1 to Set of ideals of M
    ; V$ U! F- Z/ s- `( D- wAbelian Group of order 1: J2 L5 g$ R1 ]  ^
    Mapping from: Abelian Group of order 1 to Set of ideals of M
    2 o( S8 d% `% Z1 F& b# H/ W% k: I1* g% H' Q' h1 {% Z) {6 r. f; K
    1
    ; E% X7 s  C* IAbelian Group of order 1
    6 f. J! \' M! f6 p/ v, u3 ]1 u6 w- rMapping from: Abelian Group of order 1 to Set of ideals of M given by a rule [no: C4 S) `" F) ~" `& m/ X5 |
    inverse]
    4 k' L) E8 d; P1
    # j) o9 @1 G4 ~- }2 a/ @Abelian Group of order 1
    . r6 h" i) L+ d: }Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant4 _3 x- h- u* l3 R( |  y6 s2 `- P
    -3 given by a rule [no inverse]
    - R3 p# c& e6 {Abelian Group of order 1/ E9 D( w( m9 s* [
    Mapping from: Abelian Group of order 1 to Binary quadratic forms of discriminant' J3 }6 P' I" P
    -3 given by a rule [no inverse]
    4 U  F- q7 r! W3 U; J+ z+ z( ifalse4 ]: Q1 X- f' D% y0 }+ @
    false
    回复

    使用道具 举报

    74

    主题

    6

    听众

    3301

    积分

    升级  43.37%

  • TA的每日心情
    无聊
    2015-9-4 00:52
  • 签到天数: 374 天

    [LV.9]以坛为家II

    社区QQ达人 邮箱绑定达人 发帖功臣 最具活力勋章

    群组数学建摸协会

    群组Matlab讨论组

    群组小草的客厅

    群组数学建模

    群组LINGO

    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-5 15:20 编辑 , l5 _2 O( b& `* q9 E
    0 ^8 I9 H; J+ v5 R
    Dirichlet character
    ; X+ {& m3 K- g1 m. g4 T0 s+ k) JDirichlet class number formula
    / l9 v* W  h0 X& ^6 ~$ u" C  m& ~" s/ T, e( Z: O
    虚二次域复点1,实点为0,实二次域复点0,实点为2,实二次域只有两单位根
    ' Z; V) N6 x' d0 [7 v+ D
      g; T: |4 G, k- q" ~6 \9 O6 X2 X* n-1时,4个单位根1,-1, i, -i,w=4,            N=4,互素(1,3),    (Z/4Z)*------->C*      χ(1mod4)=1,χ(3mod4)=-1,h=4/(2*4)*Σ[1*1+(3*(-1)]=1
    / z) _+ |) O4 G" {  a. a8 R, y. \
    1 w7 s$ J! a3 e( i8 u% c-3时  6个单位根                             N=3  互素(1,2),    (Z/3Z)*------->C*         χ(1mod3)=1,χ(2mod3)=-1,
    1 ^5 n4 G3 M, V& K! F& Q1 l) `h=-6/(2*3)*Σ[1*1+(2*(-1)]=1  A* `* _% e. z- [
    9 d4 w- E( s. z# u1 K
    -5时  2个单位根                              N=20   N=3  互素(1,3,7,9,11,13,17,19),    (Z/5Z)*------->C*         χ(1mod20)=1,χ(3mod20)=-1, χ(7mod20)=1, χ(9mod20)=1,χ(11mod20)=1,χ(13mod20)=1,χ(17mod20)=1,χ(19mod20)=1,
    7 H6 F! F# F3 Y( {* T8 ]0 z, B4 {% c9 q

    4 P9 I% ]: C2 }
    : t6 X9 f: }& J# Q$ X) `& zh=2/(2*20)*Σ[1*1-3*1-7*1+9*1-11*1-13*1+17*1+19*1]=2
    & Y) i3 \+ ~& n% b
    * o, ~! N* i, P+ P8 T- M+ O
    1 q) w! T9 e! `0 e# C& K8 b' i; B4 K& w' G! Q' a. o- g3 L8 k
    -50时  个单位根                          N=2004 h- t2 f  H& Z
    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    Dirichlet character

    21.JPG (79.18 KB, 下载次数: 240)

    21.JPG

    11.JPG (74.76 KB, 下载次数: 244)

    11.JPG

    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-9 20:30 编辑
    3 I. K6 e" _: u/ t5 `& d3 T, {% t  N( L# H
    F := QuadraticField(NextPrime(5));8 f) {2 x5 q) _: C; K

    3 W+ i2 C, d, R5 K, p. QKK := QuadraticField(7);KK;
    ) O+ a$ t0 a% [K:=MaximalOrder(KK);
    5 u: J- W" }2 JConductor(KK);
    ; e# I* W0 n; i8 ?! o8 ]  TClassGroup(KK) ;
    ; h% ]% b8 _# _9 x4 O# c( aQuadraticClassGroupTwoPart(KK) ;
    : P3 K$ a, {$ s! X7 ]NormEquation(F, 7);
    " F- e: r: n' V+ X. LA:=K!7;A;7 O$ a9 P& R2 K
    B:=K!14;B;2 b9 g4 l: M3 k
    Discriminant(KK)
    , q( G( J6 O! O1 T9 p* M
    # v$ g9 N4 ~( q2 V2 Z4 B5 |6 KQuadratic Field with defining polynomial $.1^2 - 7 over the Rational Field4 p9 A% i2 M- O# k, q! x; n
    28
    ( l- n( S( |( C  @Abelian Group of order 1) [. g: w* Z. i* T' v
    Mapping from: Abelian Group of order 1 to Set of ideals of K8 b* p0 X: [+ @6 @, P$ P
    Abelian Group isomorphic to Z/28 r- T4 P( p# \
    Defined on 1 generator( Q: c8 h; a' n' P' {7 |: }* p
    Relations:
    6 l+ U) f7 C; W3 R, `- y# @7 v    2*$.1 = 0
    # B& ]! |) ~3 O, M0 {Mapping from: Abelian Group isomorphic to Z/2
    ; Z! m2 M3 Z7 B. \Defined on 1 generator
    % Z% n& S, T% t( }% Z) J# A: Z9 M  {Relations:7 d4 t  f$ x  ~, w
        2*$.1 = 0 to Binary quadratic forms of discriminant 28 given by a rule [no ) ^  Y2 ]' Q, o3 {9 f! V
    inverse], ~1 Y. ]2 ^  x. J% J
    false
    3 G* U& ]3 h- |5 p6 }( h8 f0 o5 O76 E9 j; w  x! G* _
    14% I- D% ^9 u/ d! R: F0 }  e
    28
    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-10 11:23 编辑
      m: y- j. A+ T* Y. q! ^( R
    , `& A2 Q5 u  `5 c 11.JPG 3 ]) O- Q% w6 G% Y3 E" y

    6 _4 h9 z" y- C2 ?5 E/ k, ]6 n 3212.JPG
    9 p- H0 r8 Q. @. x. {' [4 c
    & j( j. U+ t  O5 Z6 g7 ` 123.JPG
    - ~. Q3 k, `. ^, `; T3 H3 S8 D- d) _, U. q! ^' h- N& g
    分圆域:
    ) B. g3 ]" a7 [  j: e$ M  kC:=CyclotomicField(5);C;
    1 c$ ^* d! _: q( m0 ^5 R! m# N, mCyclotomicPolynomial(5);
    & u% L) X8 U- I" n/ sC:=CyclotomicField(6);C;
    0 h4 l8 I9 w, j0 I; JCyclotomicPolynomial(6);
    , x5 Q" h  t; }$ HCC:=CyclotomicField(7);CC;
    ' j! f# m( j3 Z1 Y' z# {2 D1 V$ f9 MCyclotomicPolynomial(7);+ [" t: S  V% ~/ Q& c9 w' a- H
    MinimalField(CC!7) ;
    " p! H4 e8 k% i7 V  hMinimalField(CC!8) ;5 N8 g- g( n; o. Y. h" b7 }. D: X- b0 t
    MinimalField(CC!9) ;
    5 m( N- _+ j! h% b* h# B( L+ QMinimalCyclotomicField(CC!7) ;, P/ S( C- L$ D+ r
    RootOfUnity(11);RootOfUnity(111);0 @) i3 t0 C/ }0 c  I
    Minimise(CC!123);
    # o2 i( l/ t. PConductor(CC) ;5 H$ _; J( S" S5 v( V7 U
    CyclotomicOrder(CC) ;9 \1 J' m9 j7 ?, a' Z

    + X1 m' M" ?6 R% T! B* dCyclotomicAutomorphismGroup(CC) ;
    % [6 r' i* o1 C) Z- r  z0 g$ r* O
    Cyclotomic Field of order 5 and degree 4" b" b8 }( C7 X7 V1 G. Q3 y& y( ^
    $.1^4 + $.1^3 + $.1^2 + $.1 + 11 X2 N# Z$ `- V7 Q4 d7 ^' Z
    Cyclotomic Field of order 6 and degree 27 ~- _, t( C, U" }8 Q+ C
    $.1^2 - $.1 + 1
    6 P/ k. _3 t. ~  l$ U+ `7 hCyclotomic Field of order 7 and degree 67 N; H( @( ^( @7 `' G
    $.1^6 + $.1^5 + $.1^4 + $.1^3 + $.1^2 + $.1 + 1
    3 n% |) ^. h3 h6 V# i7 |6 ZRational Field9 w* ]; V% h1 T) d5 {1 Q
    Rational Field
    6 P% z$ F  i+ o! u1 Z! O; w4 rRational Field2 ~6 l& {6 |9 p: }5 F0 ~. M+ N
    Rational Field" o- J7 o) Q0 Y5 X5 ^
    zeta_11; g( b  `' O" k+ ]" j( v3 C
    zeta_111& A' y6 \, R* C
    1234 R" B9 i2 C2 M+ n
    70 ^* |' s! `( X2 ^7 r3 O% u' O
    7
    ' X9 z- Y" T9 v! p; @- @% y; CPermutation group acting on a set of cardinality 6% ^+ l0 |2 V2 y
    Order = 6 = 2 * 3
    5 a1 B; q# M* o6 r) {1 u1 M    (1, 2)(3, 5)(4, 6)4 A8 d% N9 A5 e8 T! \
        (1, 3, 6, 2, 5, 4)
    ( V+ L2 O+ x$ x8 A# eMapping from: GrpPerm: $, Degree 6, Order 2 * 3 to Set of all automorphisms of 5 c+ b4 n2 K  O( c- R1 u7 k3 T
    CC% [" I0 j/ `4 S- b7 j% J; F
    Composition of Mapping from: GrpPerm: $, Degree 6, Order 2 * 3 to GrpPerm: $,
    1 k3 r4 i+ g# E1 V; m- p4 WDegree 6, Order 2 * 3 and
    * ?, e8 F, }, x' g$ k  N* sMapping from: GrpPerm: $, Degree 6, Order 2 * 3 to Set of all automorphisms of
    , ~& O( ~2 c# q7 xCC
    回复

    使用道具 举报

    lilianjie        

    43

    主题

    4

    听众

    204

    积分

    升级  52%

  • TA的每日心情
    开心
    2012-1-13 11:05
  • 签到天数: 15 天

    [LV.4]偶尔看看III

    本帖最后由 lilianjie 于 2012-1-10 17:41 编辑
    4 j; \: I: e6 W9 B; r
    lilianjie 发表于 2012-1-9 20:44
    : z' Q9 }: I0 w( {1 P分圆域:( M, h, g, f/ R% L5 E5 Q
    C:=CyclotomicField(5);C;
    ; |1 j; [, n; T" u$ ICyclotomicPolynomial(5);
    , d2 m. q9 C7 i- |! e5 {* [

    $ U7 v: L5 P. t$ E分圆域:4 ^4 |$ T- p8 w# }" d( W* `1 D
    分圆域:1231 b4 i' m1 m& T2 [! Q( i
    + u" O. M6 u% s  |
    R.<x> = Q[]
    $ R0 _! ^( t" o# ^2 A+ IF8 = factor(x^8 - 1)6 ~! O- b" N; J& Z6 o$ o0 d$ U2 i
    F8
    0 j' e( I5 F- q; F" O8 K- r- F/ E! s
    ' h9 U& T% K9 D0 [1 |" R(x - 1) * (x + 1) * (x^2 + 1) * (x^4 + 1)(x - 1) * (x + 1) * (x^2 + 1) * (x^4 + 1)
    ' ~3 q/ v* e- u$ F& k* e8 ]2 }& P3 ]8 o8 K: _' k
    Q<x> := QuadraticField(8);Q;. w  O( [( g( I5 U: N% D' b
    C:=CyclotomicField(8);C;
    : H8 U: N( \/ |$ YFF:=CyclotomicPolynomial(8);FF;3 G5 N) C. z* A, q

    2 ]9 F: U2 h( y0 M& s" c1 Z- k  TF := QuadraticField(8);
    % I, i! J" G, E, _) |( o. g3 zF;8 y' l1 s6 W# f- F) _
    D:=Factorization(FF) ;D;
    / F( U( a- I! L; H% bQuadratic Field with defining polynomial $.1^2 - 2 over the Rational Field
    ) Y- D! _& e; X8 h# Q, dCyclotomic Field of order 8 and degree 4
    5 H4 |4 [; [5 o8 e# v4 ^$.1^4 + 1* }: M0 {+ d3 l1 Y/ k
    Quadratic Field with defining polynomial $.1^2 - 2 over the Rational Field! g* a" e3 z' `4 {8 d$ w6 g: a" h( A
    [
    % p( o- y/ ^+ y9 s% r" V    <$.1^4 + 1, 1>+ D9 B: C4 x& p5 _; d
    ]* {( R% \. d1 Z8 h( o  `( R+ A- u3 X

    4 b# {: I! Y5 s  E6 Q* x8 ZR.<x> = QQ[]
    + o, n- O  ?7 m3 s- O: b* }% `3 [F6 = factor(x^6 - 1)
    1 _/ O% X5 z9 q3 YF6. g& I+ A* f0 {

    - j. L5 x" M! _$ F) a8 N1 `(x - 1) * (x + 1) * (x^2 - x + 1) * (x^2 + x + 1)(x - 1) * (x + 1) * (x^2 - x + 1) * (x^2 + x + 1)
    $ a+ }( t) |$ I. e9 [+ r, A* V
    3 M( J7 F2 Q$ n3 A/ e9 uQ<x> := QuadraticField(6);Q;
    0 M, Y" f9 o; }3 _. b$ h# R1 ^C:=CyclotomicField(6);C;/ m# n( d4 d$ h8 w5 u# m
    FF:=CyclotomicPolynomial(6);FF;
    ; s4 c7 Z3 U4 K# z) G8 P0 w; l: \: \' h+ z' w
    F := QuadraticField(6);0 }1 }. z4 p/ [9 @# {! [2 j
    F;
    + D! z, n# c/ D1 @5 z( _! s6 e, I. R( UD:=Factorization(FF) ;D;. L# P# \$ K  u) n+ B2 y, H
    Quadratic Field with defining polynomial $.1^2 - 6 over the Rational Field
    5 {; L1 w" }/ t' r# x& f' o+ pCyclotomic Field of order 6 and degree 2/ I+ B9 ^. ]# ?$ h
    $.1^2 - $.1 + 1
    ; w; o2 [* _! W. IQuadratic Field with defining polynomial $.1^2 - 6 over the Rational Field
    " S( g3 I5 t+ U* }# ][5 }& l% ?# J/ V0 S+ w
        <$.1^2 - $.1 + 1, 1>0 z6 `7 j) I- c+ y
    ]" m: i) {, _1 o- c2 t  Q
    & H5 Q. `9 I3 V" g& r, W: v3 t
    R.<x> = QQ[]
    1 Y: @  w8 [. R2 t  Y% x8 rF5 = factor(x^10 - 1)8 J" Q/ M2 C% b: f3 A+ ^) `
    F5) F6 K  n7 ^/ u- l8 i. d7 D
    (x - 1) * (x + 1) * (x^4 - x^3 + x^2 - x + 1) * (x^4 + x^3 + x^2 + x +
    9 [. A% Y( ^, A  u5 r1)(x - 1) * (x + 1) * (x^4 - x^3 + x^2 - x + 1) * (x^4 + x^3 + x^2 + x + 1)
    * t- w# }0 U  p( C/ U( [
    , ^: T9 A6 G! ~Q<x> := QuadraticField(10);Q;
    ; ?8 ^" f; {$ i' e, _- f2 e% Y7 SC:=CyclotomicField(10);C;6 O5 m* g: {1 W" S0 z
    FF:=CyclotomicPolynomial(10);FF;
    " `4 ?4 p- ~  b7 B/ [  y& K- C7 j- W- g$ @% {  ^& H
    F := QuadraticField(10);
    ! V0 W, ]$ w' I' _F;
    ( P. u* q5 m' k" R8 t1 b8 E# fD:=Factorization(FF) ;D;
    0 S8 }/ z5 ?6 F$ ^4 sQuadratic Field with defining polynomial $.1^2 - 10 over the Rational Field! X" {, w; E: O3 O6 ^4 P+ ^- A
    Cyclotomic Field of order 10 and degree 4
    - s  ~: j8 l+ b  q9 \: v" Q$.1^4 - $.1^3 + $.1^2 - $.1 + 1+ v( c( N, V% d
    Quadratic Field with defining polynomial $.1^2 - 10 over the Rational Field6 Y+ J  K4 c! a/ r
    [1 K: X, Q( S! d% D+ q
        <$.1^4 - $.1^3 + $.1^2 - $.1 + 1, 1>
    7 S1 H6 n$ U! I]

    c.JPG (217.37 KB, 下载次数: 241)

    c.JPG

    aaaa.JPG (98.21 KB, 下载次数: 238)

    aaaa.JPG

    aaa.JPG (157.27 KB, 下载次数: 237)

    aaa.JPG

    aa.JPG (126.91 KB, 下载次数: 236)

    aa.JPG

    a.JPG (242.91 KB, 下载次数: 254)

    a.JPG

    回复

    使用道具 举报

    15

    主题

    4

    听众

    113

    积分

    升级  6.5%

  • TA的每日心情
    开心
    2012-1-13 11:49
  • 签到天数: 9 天

    [LV.3]偶尔看看II

    回复

    使用道具 举报

    您需要登录后才可以回帖 登录 | 注册地址

    qq
    收缩
    • 电话咨询

    • 04714969085
    fastpost

    关于我们| 联系我们| 诚征英才| 对外合作| 产品服务| QQ

    手机版|Archiver| |繁體中文 手机客户端  

    蒙公网安备 15010502000194号

    Powered by Discuz! X2.5   © 2001-2013 数学建模网-数学中国 ( 蒙ICP备14002410号-3 蒙BBS备-0002号 )     论坛法律顾问:王兆丰

    GMT+8, 2026-5-6 00:17 , Processed in 0.545572 second(s), 101 queries .

    回顶部