求帮助，关于S1的积分，为什么我的结果带int啊，这是怎么回事。正确的应该怎么办！！

dyd

syms g v aA bA cA zA u  t1 t2;
% f/ n& _. v- E1 N, V3 c+ nint(g);
) T( f1 ^* s% c  Fint(v);
5 v0 p8 d( f) F7 l+ _' Q1 ~h=0.856;
aA=(1+tan(g)*tan(g));
bA=-(2*1.625+2*tan(g)*(h+30*tan(g))-30*tan(g));
5 T+ h# R( V7 |cA=(h+30*tan(g)-15)*(h+30*tan(g)-15);
zA=(-bA-sqrt(bA*bA-4*aA*cA))/(2*aA);
+ K% P, Y9 o* k, \4 s; V2 F# Y) x- c2 Wya=h+30*tan(g)-tan(g)*zA;
  z/ ?4 ]3 G  O* H3 |s1=(1.625*1.625-(z-1.625)*(z-1.625))*cos(v)*sqrt(tan(v)*tan(v)+1)*(sin(2*((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1))))))/2-sin(2*((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))))/2+((asin(((h+30*tan(g)-z*tan(g))-15)/(sqrt(1.625*1.625-(z-1.625)*(z-1.625))*sqrt(tan(v)*tan(v)+1)))))+((asin(-1/(cos(v)*sqrt(tan(v)*tan(v)+1))))));
p=1.625-sqrt(1.625^2-((15-ya)/sqrt(tan(v)*tan(v)+1)));
H=int(s1,z,p,10);

厚积薄发

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①不小xin--!

啊啊啊啊啊啊是的的的的飞飞飞

dyd

厚积薄发 发表于 2012-5-9 16:25
放个截图看看

8 U! h- _; I8 ~7 K! F, ]2 G好了···我想得到的是带g v h 但是对s1积分却积分不出来，即使积出来也带int 谢谢了
3 g+ b. w# P) s: b) b

ealx0yJu

呵呵,打酱油的.