QQ登录

只需要一步,快速开始

 注册地址  找回密码
查看: 3047|回复: 0
打印 上一主题 下一主题

高酬matlab编程救助(能做的高手请与我联系QQ 346719984)

[复制链接]
字体大小: 正常 放大

1

主题

0

听众

2

积分

升级  40%

该用户从未签到

跳转到指定楼层
1#
发表于 2008-5-6 07:42 |只看该作者 |倒序浏览
|招呼Ta 关注Ta
在network 中 如何用token bucket to control packet transmission rate.
编程序后做图表分析
能做的高手请与我联系QQ 346719984

内容如下
+ O/ Z6 u. A( g# c- p S8 a% \( u

The risk of congestion collapse on the Internet is becoming a reality ) V+ ^8 O: J7 mgiven the increasing number

* O3 w% A% o5 `4 e7 `7 M' F, Z

of audio/video applications that use UDP as their main transport1 S# h H' A: _( t protocol. Unlike TCP, these

: v% a" l- v7 K. F7 r9 }3 F

traffic do not respond to congestion signal; i.e., a packet loss. As a2 A. I7 b6 f/ Y2 r result, audio/video

3 @! ~& u7 a9 S# l& d

applications may take an unfair share of the network bandwidth and / \) }$ e* k$ f' a3 ~4 f5 _also cause persistent

6 X S$ M$ B6 ?% N# }& j

congestion. To avoid congestion collapse, the IETF has proposed that% X" A4 o+ l( K0 T9 F/ w* i audio/video applications

1 ~- `2 k# z6 F2 m1 s! e

use equation based congestion control (see Lecture‐7 and the reference 1 V0 q" u9 O: J% V/ o/ Egiven on the next

% d9 y; M( p. r$ S

page).

4 M |/ I, i. [3 g# d' e. U& I( i

In this assignment, you will simulate n 1 N, x" s2 o9 {1 Z$ n+ bsources that uses( K) ?$ e. q: N5 \' C equation based congestion control to

1 L8 _* e1 B1 F6 f% ^/ [

set their transmission rate. From your simulation, you will determine ) S* D+ C2 r( A) ?0 [" a, h( awhether equation based

9 }1 r$ d0 p4 }$ _, ^$ d# D

congestion ) L; w# p' `/ v9 O7 S5 ccontrol is effective in reducing packet loss, and hence congestion.

) Q- K, o' T) v4 k. i" v3 y/ F


/ w- `# [0 N- n3 \' ^

The above network can then be simulated as follows:

1 K- g# A9 |& Y" Q, C) D2 Z5 I5 d

Initialization

* e( n, K$ {* _# p

Set the router’s queue size to N, meaning it can hold up to N packets.

* q6 D: c% M1 N/ E+ d. p5 b6 A

For each sender, set an initial transmission rate, and determine the# Z' N0 a* P( E& O7 A: k time when the first packet is

+ z/ [! F Y" _

to be generated.

: H' W* N! }$ c+ m

Body

5 J- {+ A9 G1 k9 K) m" u+ l

FOR t=1 to SIM_TIME DO

$ V9 X- T% o9 ^- T

{

: x# N* C; Q' M' G; @

1. IF the router’s queue is not empty then dequeue a packet, and: E2 j1 T6 Z) L: ]/ v2 @9 U) `" G( M enqueue that packet in

0 b$ q* h0 u/ _! ^

the corresponding receiver’s queue.

- U$ G6 u4 s- p9 k8 t

2. IF a sender has a packet to send THEN

- q6 }: s8 L5 I' z) x7 s- C( [( w

‐ Check if the router’s queue is full. If not, enqueue the sender’s$ P T6 A- V! c: A9 J packet. Otherwise,

% [3 e9 d5 Y; [/ H6 l" Z. @6 D

discard the packet.

9 s* L0 R, Z4 w4 P8 e g

3. Determine whether any packet loss rate messages are generated by5 ?1 l, b: O" _1 b+ H5 ? s receivers. If yes,

: i/ K8 v5 q; p2 b( r

then re‐compute the sender’s transmission rate. Determine the new time 0 y7 ~6 m" K- H9 S3 Ywhen the

& N4 H$ S. O9 Z& {0 R

next packet will be generated. I.e, t+k, where k is the time interval' o& }4 t4 r5 O/ W1 p( i until the next packet

, y7 N; I% h6 D' N: M

arrives.

$ Y, S/ J2 X$ F; o' G) ~( C% \2 }

4. Collect all required statistics.

; l; A3 X" T: {; Y: d/ \

}

1 d \2 S4 J6 l4 ^' E

In your simulation, collect the (a) queue length over time, (b) ; p }: @) \0 V/ _5 g6 b# Caverage queue length, (c) average

9 R3 z) y0 h: o! z; T5 E

end‐to‐end packet delay, and (d) Jain’s fairness index. Determine the( }9 q2 f! A2 ?% i* U1 C effect of the following

- W! B; I8 D( d5 O3 R' v8 Y9 l( m+ z

factors: (i) increasing source and receiver pairs, (ii) varying N8 s! O6 ^. ^/ c values, (iii) different packet loss

$ L( u. j2 w: l) `& l. Q

reporting periods, (iv) loss calculation methods, (v) load p, (vi)6 b* j P5 `# d# C) X5 j. ]! {5 A router’s transmission rate;

$ z; K& O, l& X% B

instead of one packet per‐tic, try k packets, and (vii) z) s: r$ t' F3 J' \4 D+ B* I number of new flows ( u( h' O, I4 }/ g+ j- uarriving at time t .

" e8 s! D) t% l+ Q; x6 C: ?/ {

" d: J+ o6 ^6 W0 H

5 K! v9 Y9 {! k

{( K$ l; C+ r* a Do with sources. @2 H3 V# m! ^9 F5 [8 u. z: ` using a token/leaky bucket to control their transmission rate.

8 h( j& }5 [3 i5 Q# v/ z

Another difference is that each source has an application that: |* K2 w2 r/ }+ b' n Y- \' V; j generates bursty traffic, where

, q0 n0 h" _: y" _* v! o8 T8 D: U* Q

multiple packets arrive in consecutive time intervals.

9 B) y3 k; K2 m( H- g

To generate bursty traffic, use the following method:

% @! j i. Z9 K K

T: p# x1 S1 z

8 }/ o! j0 X5 N/ K2 V( N

In the diagram above, an application generates a packet when it is in2 H& U }& c+ B8 j7 P' Y the ON state. With

" K( [5 B1 f& |& T" a. C) Q$ ^

probability k, it will transition to the OFF state where it will remain idle. In 5 L- k' H, }# q y' L0 E$ Kthis state, it has

# e! f. V- n; @: x3 Z4 k

probability z of moving back to the ON state.

( g$ M/ P0 h6 h X! `8 a* X

The pseudo‐code is as follows:

; Z; D$ T8 @9 k

1. Start at a random state: ON/OFF.

0 d! Q: l, U6 L! O, ^

2. At every simulation tic, do

( ~6 l6 p0 H6 `% v* ~ |0 O

a. Select a random number R in 0<= R <=1.

3 ~ z6 @4 B6 v0 y& w0 N

b. If in state=ON* z/ n. U+ A$ V& s; ^% W0 I8 \ AND R>=k, set state=OFF.

4 T+ h3 P2 i0 K

c. If in state=OFF AND R>z, set state=ON.

5 i! r# l" W7 } i& w; U6 l

d. If state equals ON, generate a packet.

7 ?2 V9 i. n5 n' M! Q& X

Design an algorithm to control the token/leaky‐bucket rate of each 1 o p- n5 P) C/ e+ a) Nsource (or all sources

' L; O! ^% ]+ p6 W

simultaneously) such that congestion does not happen. Note, you must/ x: u" x- Y/ ?, m t' ? experiment with

8 Z6 F2 p: z6 t5 }8 F- z

different k : W) X% A9 {+ f% tand z ' T# W* t- K* b+ Yvalues and determine( T) |6 j# c% |( T! h/ f6 i1 s( F1 d; E their impact on congestion.

, u. I5 j8 |/ ]/ Q6 `4 g/ x0 ?

Reference

$ d; m, J2 Y5 [9 S1 m C* J! y2 ~7 G

S. Floyd, M. Handley, J. Padhye,# R& S" F! V2 r3 k# p. ?3 i and J. Widmer (2000) Equation-based Congestion Control for Unicast

2 w9 Q- z# u- ^% p) M: x

Applications, ACM SIGCOMM, May, 8 o. {8 G0 ^8 M8 X* w: {2000.

; C) m( M& K6 j. {6 \

+ M k7 `2 t- c' |) G" X. k5 Z

: N) q% K: L& a9 E





zan
转播转播0 分享淘帖0 分享分享0 收藏收藏0 支持支持0 反对反对0 微信微信
您需要登录后才可以回帖 登录 | 注册地址

qq
收缩
  • 电话咨询

  • 04714969085
fastpost

关于我们| 联系我们| 诚征英才| 对外合作| 产品服务| QQ

手机版|Archiver| |繁體中文 手机客户端  

蒙公网安备 15010502000194号

Powered by Discuz! X2.5   © 2001-2013 数学建模网-数学中国 ( 蒙ICP备14002410号-3 蒙BBS备-0002号 )     论坛法律顾问:王兆丰

GMT+8, 2026-10-13 12:40 , Processed in 1.207859 second(s), 56 queries .

回顶部