- 在线时间
- 0 小时
- 最后登录
- 2007-9-23
- 注册时间
- 2004-9-10
- 听众数
- 3
- 收听数
- 0
- 能力
- 0 分
- 体力
- 9975 点
- 威望
- 7 点
- 阅读权限
- 150
- 积分
- 4048
- 相册
- 0
- 日志
- 0
- 记录
- 0
- 帖子
- 1893
- 主题
- 823
- 精华
- 2
- 分享
- 0
- 好友
- 0

我的地盘我做主
该用户从未签到
 |
< ><FONT color=#ff0000>函数名: ultoa </FONT>
: o: [5 o$ }+ @' Y }功 能: 转换一个无符号长整型数为字符串 : a/ S! g: a* R/ a' y/ p1 D9 ]
用 法: char *ultoa(unsigned long value, char *string, int radix);
$ c4 N+ Q; G* F4 ^1 R+ U程序例: </P>
7 L% t! O: W8 M, W: a& L< ><FONT color=#0000ff>#include <STDLIB.H>+ t" t) @* h' v) Z" I# ~
#include <STDIO.H></FONT></P>
# N6 R @" ?3 D2 Y. S< ><FONT color=#0000ff>int main( void )
1 }- F0 A( a; b/ t' S" e T R{ : \3 o* h$ A1 y% u* R+ Z
unsigned long lnumber = 3123456789L;
& E7 a2 b2 G% tchar string[25]; </FONT></P>: _/ G+ r4 ]6 \5 \2 _, m
< ><FONT color=#0000ff>ultoa(lnumber,string,10); * |( j* g7 ~; h5 N. l% f3 I; S3 l l
printf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>
: k0 K1 U! n1 o! Q. H, G< ><FONT color=#0000ff>return 0; % U& ^& f9 ~, T3 {
} ( n/ r/ ?+ }; N {! x8 U. I
</FONT>9 A% z5 Y e3 j- I/ T) D
4 ^' k- u: c$ _; M: k
</P>
1 A( r/ G3 Y7 G; y1 z- I< ><FONT color=#ff0000>函数名: ungetc </FONT>7 a! o$ R5 Y. U3 r$ B
功 能: 把一个字符退回到输入流中
/ M- Z& E' V- n6 `1 F用 法: int ungetc(char c, FILE *stream); 3 ~' X% l$ F% n o- \
程序例: </P>
2 W% C. p0 y( |1 l9 v# B< ><FONT color=#0000ff>#include <STDIO.H># T1 r! U" I2 L. V
#include <CTYPE.H></FONT></P>
- v# K; o Y% N; c9 [# _, c1 s< ><FONT color=#0000ff>int main( void ) " _8 p5 H7 Q5 R8 r
{
7 B% n( p4 n6 h; e0 I( eint i=0; 4 s$ S; E( R/ q* A
char ch; </FONT></P>
8 ]" K3 B+ n" p< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>( o8 B( v# K2 J; I1 l
< ><FONT color=#0000ff>/* read chars until non digit or EOF */
5 C0 C" f& @# r$ g& K$ qwhile((ch = getchar()) != EOF && isdigit(ch)) " Y4 V4 p- H9 S0 @2 G
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>4 x# ?5 u6 l$ ] c# O
< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */
% z! M% L% S6 k- L; _if (ch != EOF) + x# h/ {; R7 P6 h7 k" u
ungetc(ch, stdin); </FONT></P>
( \" e. a0 s% m1 q; r& F. Y+ `< ><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar());
' h5 F3 g: H/ W J d7 ereturn 0; % }1 a. Y z" \/ @0 J' v( _6 G
} </FONT>3 Z% Y" i0 F6 m+ t
3 ]/ J$ s! ~* s! \6 `8 b
' ]! a2 t8 L9 K8 X
</P>1 b4 M W; ?, p+ {- z, Z/ {
< ><FONT color=#ff0000>函数名: ungetch </FONT>/ i1 s5 Q2 X6 z4 q4 J% I
功 能: 把一个字符退回到键盘缓冲区中
- q4 `! Z! | }5 w9 t用 法: int ungetch(int c); ) m' u1 Y2 {! Z' G
程序例: </P>
6 o& R% Z- h6 ]* r( N! a< ><FONT color=#0000ff>#include <STDIO.H>
5 l: J; G9 `+ Z+ c, {/ _ j; c#include <CTYPE.H>: O/ q; v' y4 f8 ^# N2 K) n
#include <CONIO.H></FONT></P>
( r6 j% X7 v/ c: Q. M1 [< ><FONT color=#0000ff>int main( void ) : m! A7 M0 k: I# Y& q, o
{
( X. v3 g+ z% }: |1 j H2 X: F+ yint i=0; # C! N! m2 N& \: K6 Q
char ch; </FONT></P>
& G5 m( D8 K% T5 u< ><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>2 X% b, A( Y3 C5 [2 f! _
< ><FONT color=#0000ff>/* read chars until non digit or EOF */ $ I3 i2 M) t- W" x- i6 z2 ~/ L/ M
while((ch = getche()) != EOF && isdigit(ch)) 6 K) y- W6 L7 _) O' W
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
1 `3 ^& l7 |7 z5 K3 @< ><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */
* l! N+ ~5 B/ I z. |if (ch != EOF) 5 p0 _' s1 f2 b2 ~3 F/ h
ungetch(ch); </FONT></P>' t9 f" n$ h v* O
< ><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch()); - ]% {$ x$ K: l9 B
return 0;
5 ~. a H: x2 {6 X4 x% }% t}
7 V5 y6 c7 `0 [. a" ^& M% n5 V$ o2 m
6 m# C' F4 ? h% t+ v</FONT></P>
+ ?( Q! Q( g2 \< ><FONT color=#ff0000>函数名: unixtodos </FONT>
4 K& [( f/ Y, @1 h# L8 w/ U功 能: 把日期和时间转换成DOS格式
+ {0 D1 M9 ^: b, J, S% p! _9 Z用 法: void unixtodos(long utime, struct date *dateptr, 3 h3 `6 E: ?1 X; v2 Y4 F0 t
struct time *timeptr); " B8 J% r, F# d; s/ Z. t, p
程序例: </P>
E$ t$ y6 e6 a< ><FONT color=#0000ff>#include <STDIO.H>
6 p2 s+ m& u p# m1 p: Q; g#include <DOS.H></FONT></P>; w2 N6 q5 G, p& C i$ w# L
< ><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun",
& P& D* b5 g: |$ Z- I"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>. \# B" z6 Z7 L8 Q
< ><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>0 _1 {# n$ Y) Z
< ><FONT color=#0000ff>struct date dt; * r4 _" U8 i q: d* q2 _- I I
struct time tm; </FONT></P>% \' M- S0 C; I8 g
< ><FONT color=#0000ff>int main(void) " }4 o* [/ [/ _2 p7 k
{ / p2 z+ A+ S+ d" R3 Z: [
unsigned long val; </FONT></P>7 A4 n, J3 e0 |5 \+ p
< ><FONT color=#0000ff>/* get today's date and time */
9 G& ^4 M$ K" s5 u3 Xgetdate(&dt);
0 \3 R+ x# C j, lgettime(&tm);
; `/ Q/ p3 T: M# X9 `/ W* ^4 d8 Qprintf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>
: Y# w" }$ y" l! d< ><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */ 3 }& }" z; m* `; L/ f
val = dostounix(&dt, &tm);
& c/ C0 ?; K9 y' i- ]/* subtract 42 days worth of seconds */ : U6 }8 ]" W* r9 Q4 @( ~- }9 [
val -= (SECONDS_PER_DAY * 42); </FONT></P>
6 H' p) A: S& p$ n. `< ><FONT color=#0000ff>/* convert back to dos time and date */
. T$ P* A/ h: x$ Z _' Sunixtodos(val, &dt, &tm); - }" r' F) {+ ^0 e; c$ `- y V& t
printf("42 days ago it was %d %s %d\n",
, X+ I; c% X5 O0 R0 Wdt.da_day, month[dt.da_mon], dt.da_year); ' P8 m6 U1 T8 N' @# @& V: I6 j
return 0; ! S( K5 d+ [4 t! P6 U
}
1 j4 ]2 g8 a: j3 \7 o) z! b- x4 y9 u3 O- T3 f
! {0 R2 r: W; ~( ]3 e: f$ r' D' @! P s</FONT></P>
! I% ^$ k. ?. \& I! N- {& A< ><FONT color=#ff0000>函数名: unlink </FONT>
& e/ V: W& e2 N) \功 能: 删掉一个文件
+ h5 X2 A+ ]) ]& L8 S2 D用 法: int unlink(char *filename);
$ J& f" f: m) a程序例: </P>
; O' A9 t* j+ G. c0 o0 e< ><FONT color=#0000ff>#include <STDIO.H>" u( m+ [) i8 _+ m* c/ L
#include <IO.H></FONT></P>
$ R4 V$ d1 G8 _<P><FONT color=#0000ff>int main(void) 6 M/ l! R7 T/ F1 N. z
{
7 M. U, F% T; Y6 g! S- C9 l0 YFILE *fp = fopen("junk.jnk","w");
6 p+ n9 b" v( qint status; </FONT></P>
/ c" B7 X4 x& ]& ?6 Q3 i# F9 S<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>8 |8 K1 T: B" N5 R: E
<P><FONT color=#0000ff>status = access("junk.jnk",0); / d9 k+ _ |% G8 R, T- U) ^. `
if (status == 0)
; F- H0 t& [" Qprintf("File exists\n");
0 o2 W: N4 j5 X- r% v; r9 ~- N' Melse
* y8 w9 H, W) U' U q6 Jprintf("File doesn't exist\n"); </FONT></P>
6 c4 E, }6 q; ~/ b- H$ n<P><FONT color=#0000ff>fclose(fp);
* M0 j6 [( I, ~unlink("junk.jnk");
- D/ E1 e F8 [( v2 Z& I- y& Zstatus = access("junk.jnk",0); ) w) m# A. j3 ~1 ?# Y% I
if (status == 0) . O, t/ w: d1 E7 F+ \( m: q$ R
printf("File exists\n"); 3 t' z) [+ n/ N
else
2 ]! S7 Z. |) z. G6 S# K5 `: Cprintf("File doesn't exist\n"); 7 F4 S8 x7 S! w6 j8 n
</FONT></P>
' }$ M5 W% o# h1 \3 x* ]9 B1 _<P><FONT color=#0000ff>return 0;
+ C8 a! ^% q% \5 w; {( G} : }7 |3 D. W$ L& f, g4 I4 g
$ b+ c: Z/ u: V) P" M</FONT>
4 L# |# h. Q! t' O* I1 F</P>* }1 M; m7 d& T. w2 s5 x+ P" C
<P><FONT color=#0000ff>函数名: unlock </FONT>
, j; _5 r5 K1 x' i0 L8 K功 能: 解除文件共享锁
, z4 t" t% @" C用 法: int unlock(int handle, long offset, long length);
. o6 l* Q* }7 \& i9 h" Y程序例: </P>
: d2 G: P( b- D5 h0 C" E( D0 Q, T<P><FONT color=#0000ff>#include <IO.H> T" e* M7 R+ t4 J+ E$ A
#include <FCNTL.H>2 K3 u3 i% d5 e! |
#include <SYS\STAT.H>
1 ^: N* }: ^% G! y6 E8 `#include <PROCESS.H>
. a! H! G2 s" U! e% o#include <SHARE.H>/ {; X! V9 B0 ^' t# t6 \0 W
#include <STDIO.H></FONT></P>
& n( E! L4 v& ^+ ~<P><FONT color=#0000ff>int main(void)
, P1 C; z9 H7 k E! Z$ p1 F" v{
2 C& W `3 y2 N3 K5 g: k+ I' xint handle, status;
. B5 @, \. @ Glong length; </FONT></P>
) ~9 z4 L3 T3 S" z# M% H% o* @<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>
$ J& l! \* S. d, n$ j1 L<P><FONT color=#0000ff>if (handle < 0)
- \/ @# X# t0 J3 A" S3 K) b6 K' p{ % I8 J1 ]/ @- h* v
printf("sopen failed\n"); 9 e( H e5 l# Z& a# A: o x
exit(1); - [7 ~$ v" A0 i7 X2 k) l% O
} </FONT></P>/ u. z0 F7 V1 X6 p3 M- ^# P
<P><FONT color=#0000ff>length = filelength(handle); ' l$ G3 W C0 J7 Q7 r
status = lock(handle,0L,length/2); </FONT></P>
3 i! g% X3 S7 }5 ]( R: \( ?. v<P><FONT color=#0000ff>if (status == 0) 4 j. F% b% n: I. P0 T3 a2 {) c
printf("lock succeeded\n");
" I. o" ~" u: k$ I. v9 Uelse
$ s! z* a3 J/ E3 _6 Jprintf("lock failed\n"); </FONT></P>
5 K5 ^* o8 [+ a- d<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>
/ B" Z# R5 ]9 i* v8 S<P><FONT color=#0000ff>if (status == 0)
# L. V0 Q* M6 O" iprintf("unlock succeeded\n");
A$ \+ }2 w% Q6 z. p( @; Oelse - V" f# p0 _+ q8 ]5 T
printf("unlock failed\n"); </FONT></P>1 }! g7 D' y0 C- r0 T
<P><FONT color=#0000ff>close(handle); 2 h/ a+ g2 K. }; [4 t- W
return 0;
$ r: d4 A' x3 Z1 d) ~} </FONT></P> |
zan
|