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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |倒序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>8 ^: P, Y  R. v$ }* c# ]0 R
<><FONT color=#ff0000>函数名: abort </FONT>
. X; D9 ~4 O7 O( x' ^* i1 m* ?! O; Y功 能: 异常终止一个进程
% R$ i3 e7 b/ f) P用 法: void abort(void);
- O  y+ u. a4 i9 j( s% f- M- f+ Q程序例:
  _# Y* Z- D& i$ L<FONT color=#0000ff>#include <STDIO.H>/ }2 C% A; Y* V( l; u9 j* L# h4 {6 M
#include <STDLIB.H></FONT></P>  F0 D2 A) ~& {, A6 G$ Q
<><FONT color=#0000ff>int main(void) 7 b7 h. x% T7 @# e$ K
{ . R5 X- c% V) Y( w  n# E. o
printf("Calling abort()\n"); : @8 M. J; g& w' z; u& u* P
abort();
* J9 s- t2 F& g8 Nreturn 0; /* This is never reached */ + O& ^  g6 }3 S: }
} 8 A' U5 B  q) F; t* d3 c- d8 Z8 t
</FONT>
$ }/ E# s6 l8 O5 L. _</P>7 J: w% v/ ~0 S3 i7 q- c
<><FONT color=#ff0000>函数名: abs </FONT>
# c+ c9 ~% h5 s9 k! Q功 能: 求整数的绝对值
1 _/ T! `5 O/ [1 ~. H用 法: int abs(int i); ) G6 s" p, F7 o( m
程序例:
! [: f/ C! g' q" Z" a) O<FONT color=#0000ff>#include <STDIO.H>2 S6 F% x+ }* N4 o* o5 n3 Z
#include <MATH.H></FONT></P>5 T: O  E1 I! v" e$ x# J4 B
<><FONT color=#0000ff>int main(void) 1 J$ n$ h# K: C6 _
{ # Y8 V* l  s  }7 I0 E
int number = -1234; </FONT></P>% O: ]) B2 e, D2 Y
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); / y9 {6 Q8 i( f5 c5 q
return 0;
4 c4 L- ~% Q$ N( D, }- F/ E, @/ f}
' g4 d- Y' O9 E8 m( L$ ^2 [1 y  i</FONT>
. {; Z! _7 |2 F1 j& P4 a</P>. Y% V# q/ z9 z4 P
<><FONT color=#ff0000>函数名: absread, abswirte </FONT>
; J/ ^- d) {6 R9 O" j功 能: 绝对磁盘扇区读、写数据 * T  q  J- B1 ?( W+ h5 v: B
用 法: int absread(int drive, int nsects, int sectno, void *buffer); 5 G$ k6 F1 F( S7 M+ W
int abswrite(int drive, int nsects, in tsectno, void *buffer);
0 E: b* u! e: y- b程序例: / j; f1 ]( l6 E% @3 ?) h
<FONT color=#0000ff>/* absread example */ </FONT></P>/ D: d/ ^" n' }( ~2 L
<><FONT color=#0000ff>#include <STDIO.H>  E, \. \2 k6 O0 G2 Y0 L
#include <CONIO.H>
8 Q* ?9 W& r5 G0 a#include <ROCESS.H>9 O; I) O8 y$ M  l
#include <DOS.H></FONT></P>
- v1 ^& }% b7 t4 P$ a+ Y- ]<><FONT color=#0000ff>int main(void) % X( H4 h& K9 k* l9 w
{
5 }9 o" v1 V3 [7 m  Q' gint i, strt, ch_out, sector; 2 p* _9 L  E- f" d7 E) c
char buf[512]; </FONT></P>
" j, ^" D! y: [& d<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
  n) W. j* F7 r2 Fgetch(); 0 ^8 i% L' c2 {! _
sector = 0;
( [2 Y5 ]6 \2 E! pif (absread(0, 1, sector, &amp;buf) != 0) * M! X# e$ V- E7 {- H" S
{ 7 d7 r3 Z/ ^- A/ E- j- ]$ T+ B, T! O
perror("Disk problem"); 1 w- f' u/ S. t* X
exit(1); & @0 A( A  H8 W% r. D4 s* W/ A( c
}
/ F% }8 ?6 n0 Q# W. tprintf("Read OK\n"); 5 }4 y  P, r+ {/ R) O8 T3 ]
strt = 3; , A0 f! U( g. R  J( y
for (i=0; i&lt;80; i++) - a) x( ]4 }; a# f1 z
{ 4 H1 R( l( l! e
ch_out = buf[strt+i];
( R1 e) n& O4 u8 _: t$ ]3 aputchar(ch_out); 1 A5 D5 X3 y1 }
} 2 C# r6 F" @6 U
printf("\n"); 7 O- p& o) O5 `
return(0); 2 f/ M  m! a0 a/ G- T. z
}
$ q3 v6 D) [/ W, F' `</FONT>
$ V4 P0 W1 L% ~% N
# Y6 _' |. C6 K4 T( N+ z</P>
" `1 K5 |9 j! k+ w( p: F<><FONT color=#ff0000>函数名: access </FONT>
8 U: L6 c- F# q, N, _功 能: 确定文件的访问权限 & y  w+ y+ J+ f' z  P7 D3 J
用 法: int access(const char *filename, int amode); - f- }- w% v& u  {$ B9 D) q
程序例:
1 |+ R; M( n6 k1 n( n3 M  Y$ B<FONT color=#0000ff>#include <STDIO.H>0 G+ l. G- j/ n# [
#include <IO.H></FONT></P>( ]) @# a& X7 L, v7 ^
<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
& @' f9 d) f$ F+ Q. r. B" u<><FONT color=#0000ff>int main(void) - ~" h; L( S- N1 J
{
. K, h5 t6 Z8 x9 Gprintf("Does NOTEXIST.FIL exist: %s\n", - f; [# _: ~; B$ G( D" V
file_exists("NOTEXISTS.FIL") ? "YES" : "NO"); 0 y8 `! d9 C8 o" _: |' S/ Z1 F5 i
return 0; ! y, S+ Z% g8 d. ^1 N
} </FONT></P>
  N. |7 }% l% J! A/ f* J<><FONT color=#0000ff>int file_exists(char *filename) ! {$ q* }4 H, V: J
{
( \* U' h. I+ A* Areturn (access(filename, 0) == 0); 2 J6 E5 J7 [9 K. _$ \
} 3 q+ ~+ z6 q2 c$ _; H, y7 X
</FONT></P>
3 g$ D/ f/ C0 X/ h* P. y3 \<><FONT color=#ff0000>函数名: acos </FONT>+ d6 t+ ~# ?- W; f3 I* h/ A2 v
功 能: 反余弦函数
1 x( U6 z) Q: c8 ^用 法: double acos(double x); 5 t! v* S3 D* z( ?8 m
程序例:
" M6 r. P$ n5 A1 D: x<FONT color=#0000ff>#include <STDIO.H>4 k, M. J5 W1 e* A
#include <MATH.H></FONT></P>
2 e( @' ?4 o2 \( K) x<><FONT color=#0000ff>int main(void)
- R6 ~9 R; n! V6 h0 U) I{ 2 ^! [3 K' i6 |8 Q/ A+ k
double result; % u; J3 W2 h" B% r
double x = 0.5; </FONT></P>
6 @& K+ [4 b3 Y<><FONT color=#0000ff>result = acos(x);
6 _: i3 G! _' l- a5 _8 F8 ^printf("The arc cosine of %lf is %lf\n", x, result); , t- M' ?. b" a6 i; Z
return 0; * j8 J3 r& X9 _. V6 z! H# ~1 y
} </FONT>3 W. t3 X3 i7 l- t
1 m( w3 o; n, N
</P>
! D6 O4 k" U- K0 a, M<><FONT color=#ff0000>函数名: allocmem </FONT>
8 N" v) I7 \  ?( O1 e功 能: 分配DOS存储段 5 {# X7 O0 ?8 z# N6 R" a) F
用 法: int allocmem(unsigned size, unsigned *seg); * Z6 m" N7 _0 Z9 X
程序例:
# E6 ^; Z8 t8 b& N4 a8 _<FONT color=#0000ff>#include <DOS.H>4 Z4 v  ?5 q8 o
#include <ALLOC.H># U- T' }4 D2 k" b; S
#include <STDIO.H></FONT></P>
" N5 x- _' J8 I1 z<><FONT color=#0000ff>int main(void)
/ H' z2 [- y% `) q" @, T{ 9 U# O8 ^4 _8 {# _7 y- J6 D
unsigned int size, segp; * |; S2 Q( g2 l. `4 Q) U4 A5 ^* E
int stat; </FONT></P>
+ M4 }" r( @1 N! R<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
" Y% Y: H7 ^5 n; K/ g5 kstat = allocmem(size, &amp;segp); 3 E7 P6 p4 l  ~" Y5 ?8 h( u
if (stat == -1)
; y7 U- z' j6 k6 x. wprintf("Allocated memory at segment: %x\n", segp); 4 S# f1 j4 M! A- D/ _
else , m* _$ S- @! U" k
printf("Failed: maximum number of paragraphs available is %u\n", ! r' }: K& @  d, Z" p
stat); </FONT></P>1 L0 n- C6 p6 ?9 e1 e
<><FONT color=#0000ff>return 0; 6 y8 B$ v# c& D4 O3 _; w
} </FONT>
! F" K- l, {6 t  l
' W1 C. b; W$ a6 `  p/ j) o; N  C</P>
! p4 }! Q6 m" R! c9 X6 V: @<><FONT color=#ff0000>函数名: arc</FONT> + u, j6 A5 m0 S! x1 S& _
功 能: 画一弧线
; j! L  H2 E$ `1 K$ w2 t5 g; T5 Z用 法: void far arc(int x, int y, int stangle, int endangle, int radius); 7 J$ ~: ^' e  [( W2 r/ s- f
程序例:
! B2 x+ g# \8 z" s' S* q2 D5 I<FONT color=#0000ff>#include <GRAPHICS.H>5 s, b, \- A- u( b" L$ G' v1 U
#include <STDLIB.H>  L1 h7 }& I7 y* b* Y$ `% n6 i
#include <STDIO.H>
/ Y' D, V4 K* q#include <CONIO.H></FONT></P># R+ {$ ?+ i+ D% I9 H
<><FONT color=#0000ff>int main(void) % B; S+ v( v1 D6 `3 N
{ 4 @/ a) ^8 v4 A4 u& Q
/* request auto detection */ ( b1 @4 J/ h, ]* J; l! p3 f
int gdriver = DETECT, gmode, errorcode; $ t% G. T, j. q8 `9 I0 D
int midx, midy;
( P/ [( x0 ~0 P! O3 a$ x5 I% e* _int stangle = 45, endangle = 135;
- ]: O$ f$ N( Kint radius = 100; </FONT></P>
& J6 u' ~! e- j<><FONT color=#0000ff>/* initialize graphics and local variables */
6 v3 p' M0 M% D4 |7 i% M; i6 w: o  Dinitgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>
3 J7 R) ~( H7 l7 G0 R2 O<><FONT color=#0000ff>/* read result of initialization */
4 E& D* ?& ?* R) u& Derrorcode = graphresult(); /* an error occurred */ ) q  j( N5 U' h: z# [
if (errorcode != grOk)
8 L9 H8 E5 J6 b# m  o9 Q: Q{ ( t" P$ W1 H0 V
printf("Graphics error: %s\n", grapherrormsg(errorcode));
0 ?6 U" e) _( N9 Yprintf("ress any key to halt:"); - M) M$ b8 g/ p9 L
getch(); </FONT></P>; k: m  A' ~1 P. ?8 J
<><FONT color=#0000ff>exit(1); /* terminate with an error code */ * V" N0 R0 Y- C! x
} </FONT></P>) r# h6 N7 I1 `: M
<><FONT color=#0000ff>midx = getmaxx() / 2;
/ A; v6 U7 {0 l* U2 b5 ]" O5 k3 }midy = getmaxy() / 2;
& x8 y3 Z# f/ Y8 ~2 `3 Q+ jsetcolor(getmaxcolor()); </FONT></P>
, l# r! f7 u5 h<><FONT color=#0000ff>/* draw arc */
0 g7 B$ l2 T2 ]" rarc(midx, midy, stangle, endangle, radius); </FONT></P>7 n7 D, g: [$ i2 I* q- }9 I
<P><FONT color=#0000ff>/* clean up */ ; Q; Z. W* ~. ~, U" d
getch();
$ v2 p% N5 d, c1 X. K& lclosegraph(); 3 B" ^4 j) j+ f! y
return 0;
1 n/ _7 o$ Y8 m, l8 X6 w}
% }$ b* R8 w( \</FONT>! E7 x+ h) z0 P) T2 g& B3 F
</P>. d- a2 @! F& M) l- {
<P><FONT color=#ff0000>函数名: asctime </FONT>& h; H! S7 b7 u4 ~8 b3 [  ~
功 能: 转换日期和时间为ASCII码
4 }  f% f4 H  U用 法: char *asctime(const struct tm *tblock); ( \3 a0 ?% N7 F+ {! C4 k
程序例:
3 Y( v: v* i9 _- k<FONT color=#0000ff>#include <STDIO.H>
8 c) g, G: Z* `/ r" L#include <STRING.H>
( @2 s& ^9 H9 V8 H) s( x8 n0 `2 O/ C#include <TIME.H></FONT></P>
4 B3 L- ?, T. w<P><FONT color=#0000ff>int main(void)
% p. U0 @* w- I: w) w# [{ 3 B$ _. i6 E2 }3 D& t+ I
struct tm t; 1 Q% @/ P' K3 ]! `- Q$ B
char str[80]; </FONT></P>
: s8 H' B5 Q* o) t1 x<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>" g1 C( D% w# e6 i& H1 z: k. R
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ + F& Q# f2 S, Q7 ]. b- ]) ~
t.tm_min = 30; /* Minutes */
; M1 e# r- M3 ?; t; n2 {t.tm_hour = 9; /* Hour */
+ T5 T- w9 I# S. @: D; U/ Ct.tm_mday = 22; /* Day of the Month */
- }! m( s, V0 s  H. p; st.tm_mon = 11; /* Month */
1 ^! q; h/ V1 F0 e, I3 i* ~+ Pt.tm_year = 56; /* Year - does not include century */
' M5 b, z/ x7 ~- q$ ?6 Q) dt.tm_wday = 4; /* Day of the week */ , g4 T4 G# c1 T
t.tm_yday = 0; /* Does not show in asctime */ + E6 C4 e# e( F8 E- L
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>) l/ A! R9 ^# D0 o' D6 K- E: T0 ?$ ?
<P><FONT color=#0000ff>/* converts structure to null terminated 8 [7 L  Z6 ?" K
string */ </FONT></P>
& q' T3 G; r# c<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t)); 4 T5 c& h5 D2 ?' X- L
printf("%s\n", str); </FONT></P>: Z+ F6 y; y$ Q# `: ^: c! Z$ J( g
<P><FONT color=#0000ff>return 0; ; k! ~- p) P/ n2 r# P
} . P, _; t# X2 G" u& D4 f
4 E# X$ l( c, W
</FONT>' A  p4 z8 z! a
</P>% K2 d! x+ |+ Y5 o& ^
<P><FONT color=#ff0000>函数名: asin </FONT>
; ^1 [0 X& _$ n0 u  p6 C6 T功 能: 反正弦函数 2 j, u  x, ], F* d
用 法: double asin(double x); / F3 n! }2 |# i8 Q4 u- h! G
程序例:
$ T  j% V! `; z- l( b<FONT color=#0000ff>#include <STDIO.H>
& z+ S& O6 n% O! k2 R+ W#include <MATH.H></FONT></P>
1 {1 J# T- E1 |, z$ N<P><FONT color=#0000ff>int main(void) 4 @0 S# @; @: v% S+ {' j
{ " E! m% K% u8 L" [( w- R
double result;
7 B. H3 {* b  N! ^double x = 0.5; </FONT></P>
7 u  J5 d, z2 }  w4 D2 h& a<P><FONT color=#0000ff>result = asin(x); ! ~8 m( }' t  K6 B
printf("The arc sin of %lf is %lf\n", x, result);
% K$ D( ^, T* n% K+ M& s, ?return(0);
- ?* e0 Q8 q: }! z% \3 R} : U- u) o- t& Z2 b% Y
</FONT>
, d# X  t# N+ R2 _6 E1 w
1 ^- C- `* b3 D7 `+ W( a' `* }</P>
7 }; X, z' C" D7 ~; n<P><FONT color=#ff0000>函数名: assert </FONT>% ?+ E2 X8 H9 g: N- v7 b
功 能: 测试一个条件并可能使程序终止 5 f( e- k8 Y3 Z, o# P
用 法: void assert(int test);
" [. I* @6 R; \9 |! L程序例:
1 k# ?- Q# c! C: b<FONT color=#0000ff>#include <ASSERT.H>: p- J! t! ^. Y. g5 Y  @2 _
#include <STDIO.H>
& D4 d5 v9 \- N( g#include <STDLIB.H></FONT></P>9 D) }" m. Q4 @
<P><FONT color=#0000ff>struct ITEM {
% i7 h" s3 q* I% i% vint key; 6 r0 ?0 ~; z$ W
int value;
2 p! [. `# h/ O9 S}; </FONT></P>- H% x# a2 o: k- r
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */   D$ F" P8 c5 [! O$ d8 q8 _
void additem(struct ITEM *itemptr) { ) V  p" E2 T. l' y7 A
assert(itemptr != NULL); 0 Z6 k# v9 h* {* a# f$ W, z
/* add item to list */ : H" K/ B' _3 N
} </FONT></P>
0 Y; ~' X7 O7 ?9 ~<P><FONT color=#0000ff>int main(void)
8 V" |  ?3 K, d+ m{
% Y% |' ?3 H5 dadditem(NULL);
/ u8 e0 }( Z2 o# o# D" N, o$ breturn 0;
% Q- ~. @! @: F1 Y6 l: l5 I0 V}
* C$ B2 |* P8 _5 x* R" ^</FONT>
1 t' m) V9 ^6 w; V# }0 m
/ m( @4 M5 x2 ~: z- K$ t% z</P>: N& d; R( Q0 P1 y% n& u- G* I
<P><FONT color=#ff0000>函数名: atan </FONT>% H- t9 j" |. y% ^* f( o
功 能: 反正切函数 + `& |( D) }: [1 ~
用 法: double atan(double x); . j  D6 X+ y1 ^& F' w
程序例: ' A7 i. M# D, p/ ^
<FONT color=#0000ff>#include <STDIO.H>
- T2 ^2 a7 D0 ~#include <MATH.H></FONT></P>
, G" C6 K8 C6 Y0 ^6 G* z<P><FONT color=#0000ff>int main(void) + T' _1 Z3 P9 L$ F
{ , d5 _& E8 [8 k! ]& `' Z3 P
double result;
: J) _2 z  |0 o, b- Q* Z+ W; _6 wdouble x = 0.5; </FONT></P>
6 C- ^! S+ q, o* |0 m7 p# H<P><FONT color=#0000ff>result = atan(x);
# |( n  r5 z1 o% xprintf("The arc tangent of %lf is %lf\n", x, result); ' l2 |8 k% I0 ]0 D$ m% Z% |
return(0); ' L9 V1 X) j' f: c+ B- X
} $ `/ ?  [# |. T, r* N, u
</FONT>
+ Q! p/ p4 w1 y, E% M</P>
9 ^# K% o" n" ^3 j: h4 p. V<P><FONT color=#ff0000>函数名: atan2 </FONT>
1 |. ^& E6 _( V, Z" @* v: [9 w功 能: 计算Y/X的反正切值
( H" v+ Z( X% P, o" R9 c" Z用 法: double atan2(double y, double x);
! Y: |! U2 `* s" u* P6 E/ N/ z0 K1 x+ X程序例: 8 Y; y4 [# V+ u
<FONT color=#0000ff>#include <STDIO.H>
% B5 w9 B  r4 u+ _9 P#include <MATH.H></FONT></P>/ w- _" `$ s* {( X) a
<P><FONT color=#0000ff>int main(void)
/ J% n4 V. I: I4 m{ / v4 U9 V1 c6 E9 J: a0 ?
double result; - [7 m& _3 z1 l3 @
double x = 90.0, y = 45.0; </FONT></P># e& L. l9 v7 ^0 x+ w* z
<P><FONT color=#0000ff>result = atan2(y, x);
! H7 p/ |- n6 z9 _! k0 Uprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
$ g4 T( {% h! W8 i4 Wreturn 0;
8 r: X0 ~- e$ u6 C  F  z9 D4 w2 {}
  S3 k  |9 r1 t0 j* c& q! }</FONT>
# J% g/ d, z/ v6 u</P>
0 ^3 f' y$ s* n$ b7 x<P><FONT color=#ff0000>函数名: atexit </FONT>! l% o  A4 c1 t4 G7 n$ W7 \$ N
功 能: 注册终止函数 ! \- n0 r& S5 R3 z1 F3 |% S
用 法: int atexit(atexit_t func); / u0 h! `0 F  k$ f! v; X8 S
程序例:
# i" x. H" d8 I: W+ V* }<FONT color=#0000ff>#include <STDIO.H>
! O7 k; F7 h( j! S3 m% N' d#include <STDLIB.H></FONT></P>
3 {$ p5 g' p* n- ^  a% c3 ~: ^<P><FONT color=#0000ff>void exit_fn1(void) & |6 j: V+ D- ]+ x( V
{ % K! {  r9 A: L: t
printf("Exit function #1 called\n");
# q' `/ Q9 I. J} </FONT></P>  L8 z$ I" V7 j1 I( `& Y0 a8 O
<P><FONT color=#0000ff>void exit_fn2(void)   T) K( {/ F+ B0 ], A
{
: `& P$ h& R- a9 m+ p. j0 sprintf("Exit function #2 called\n"); , L5 C! o+ R; B: j2 r6 M- q
} </FONT></P>5 f. G7 h) t& m+ y. h4 H$ T: E
<P><FONT color=#0000ff>int main(void) : T3 q1 ?9 W: H. R: P
{
1 I; f! Z/ C% m+ \/* post exit function #1 */ / ?! U, z' Z8 x* t3 N3 G
atexit(exit_fn1);
0 ]  Z" w4 j" X2 w- ?/* post exit function #2 */ % ]9 d$ F7 s. b
atexit(exit_fn2); : K, i' W. X" G; O4 n/ @% Q
return 0;
6 S  ]1 f! q+ ?# b1 K  z} ( h. J. D  C. A% Q* _2 R- L
</FONT>
3 n4 v5 p; ?% a9 R; b
7 X# L8 f" K, ?) f* F3 G</P>$ V- {" k* ]3 h! K. ~& r% l
<P><FONT color=#ff0000>函数名: atof </FONT>( P/ x/ Z! q6 o1 ~, ~/ E
功 能: 把字符串转换成浮点数
/ i7 e% [8 U) ?. k9 d8 U用 法: double atof(const char *nptr);
5 `5 [' r! K0 v* n程序例: ( d, }; L4 p$ C( E1 G' ?( B; R
<FONT color=#0000ff>#include <STDLIB.H>
, p2 g# S- ]0 \, a0 u#include <STDIO.H></FONT></P>( `' a! k2 D: ]& n: Z! Y
<P><FONT color=#0000ff>int main(void)
; @* ^5 r& x4 J) X; L4 N{ / p  I/ D6 ]7 L6 \$ u
float f; * x2 i9 A( l9 }) }6 t1 \6 R
char *str = "12345.67"; </FONT></P>& Q& L$ k+ V% G! z) q  I8 O* [* J
<P><FONT color=#0000ff>f = atof(str); % ~/ |6 P- y9 V0 n
printf("string = %s float = %f\n", str, f);
( w1 P$ X7 h" Q  p9 lreturn 0;
( I4 |0 b! y1 ]; F} - i( S0 Y6 K$ k7 r+ T: Z
</FONT>
# m% X; P: C; Y0 m: z* Z</P>( H! L$ M. z4 ~( |1 Y* X" [
<P><FONT color=#ff0000>函数名: atoi </FONT>, l6 ~, B) C6 N0 X( h
功 能: 把字符串转换成长整型数
7 H7 m! \& P+ L) t9 p" M) y& @用 法: int atoi(const char *nptr); 4 N) i, ], [3 s. j  A/ ]# i  Z
程序例: 4 ?" ?1 R' _  C0 b; W) ^
<FONT color=#0000ff>#include <STDLIB.H>: H( p1 m8 f; H( I- w# B
#include <STDIO.H></FONT></P>2 ^# D, u2 X  [7 ]
<P><FONT color=#0000ff>int main(void)
. F- c  ^, ?$ a, `, X, l{
+ H. s% T  B' a0 B8 g' J) cint n;
% a% Y( c# a4 T& t7 _char *str = "12345.67"; </FONT></P>
2 @+ g3 R7 C) @. J<P><FONT color=#0000ff>n = atoi(str); + s1 c! X) H6 I& @
printf("string = %s integer = %d\n", str, n); - q8 m6 L. O. b  s  _
return 0; - }( m: O6 G$ ~* _4 M
} 6 k- k1 G& O& [' S' o' G) l  s
</FONT>
/ A7 S2 a$ |3 w; M% v3 @</P>! _6 a3 x) l7 Z! H3 A* _
<P><FONT color=#ff0000>函数名: atol </FONT>
# k8 Y/ @' O& [9 h功 能: 把字符串转换成长整型数
8 X) h9 X. p& ~. y1 o6 c+ h用 法: long atol(const char *nptr); ' F$ c' T, G/ R9 m8 [
程序例: </P>3 z0 c2 f" b; K% J5 \
<P><FONT color=#0000ff>#include <STDLIB.H>
) }' }# N. K4 P% X3 \% E& I! G#include <STDIO.H></FONT></P>) N8 W( H% `" l1 T5 q
<P><FONT color=#0000ff>int main(void) ; A& J9 F% c$ _& I
{ " i/ p4 a/ X# t! J( }
long l;
& i1 ?2 Z+ `& {+ r' S, r, ]char *str = "98765432"; </FONT></P>
  @& L5 O/ g) v3 y<P><FONT color=#0000ff>l = atol(lstr);
* b5 z8 X5 e" q( Hprintf("string = %s integer = %ld\n", str, l); 7 X$ p" h2 Y1 n" Z
return(0);
3 b! _0 a& S  ?5 |- A$ h; k}</FONT></P>
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