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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>$ h- a! q( l% u& o
< ><FONT color=#ff0000>函数名: abort </FONT>
# D9 o$ x: M5 P; H9 N功 能: 异常终止一个进程
3 x1 ]' C% K( r& r$ G9 k用 法: void abort(void); 1 w8 u& L5 ?' w7 s' U" h, z0 U/ e
程序例:
' m# |0 R. U# X. e! t! a<FONT color=#0000ff>#include <STDIO.H>
9 O# K" u' t7 j* W#include <STDLIB.H></FONT></P>6 K9 I+ }4 g) C0 U
< ><FONT color=#0000ff>int main(void) # _6 I; h4 s, h+ y4 M8 Z" ^
{ - X% `- F8 r* P- z7 d
printf("Calling abort()\n");
% L2 h1 I, x0 |& [( `& Jabort(); 4 y b7 Z, f% n' i0 c3 L2 J
return 0; /* This is never reached */
6 a/ r# v0 e c} % |" H5 ~/ `% k7 n* R" }; N1 p
</FONT>( j o$ Y5 p* o" L5 {; Q: R
</P>
5 R5 z0 a4 g2 L< ><FONT color=#ff0000>函数名: abs </FONT>
# m7 S) d/ ~( ]& p功 能: 求整数的绝对值
4 v, ]2 b: {0 V8 C B1 U1 L用 法: int abs(int i); * A' F4 U9 B3 l0 h
程序例:
3 r! U, J. d" F5 h<FONT color=#0000ff>#include <STDIO.H>
* ?) t$ A7 F M" ~7 V4 @0 S- G# N#include <MATH.H></FONT></P>/ R. H- g. z8 X' w+ }1 T% [
< ><FONT color=#0000ff>int main(void)
8 q! F! p1 t- j. E) h# J* \; o3 Y; ^; `{
5 W- K/ D# p3 S- t' u0 hint number = -1234; </FONT></P>
9 L7 v0 R# t- K5 Z) k$ g j< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
S0 a7 f3 Y9 ^" h. W6 A q2 G* Creturn 0;
7 J& D4 @0 x$ R3 m0 Y+ N}
( N# H2 k, O8 A; v1 v</FONT>7 J/ n, N4 W8 Z' V. w- g
</P>- g" g' `$ t A2 G3 d+ c& A
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>7 U) H" k. f5 k' M
功 能: 绝对磁盘扇区读、写数据
3 c7 C+ v6 R6 t& `' M用 法: int absread(int drive, int nsects, int sectno, void *buffer); % c ?" t1 _' }# p- H0 u) E
int abswrite(int drive, int nsects, in tsectno, void *buffer);
2 t* E. [% n" P9 }9 K% e2 `2 q3 g程序例:
+ D7 P$ m5 L% Q<FONT color=#0000ff>/* absread example */ </FONT></P>8 q$ ~) s) ?! @$ A4 P5 y
< ><FONT color=#0000ff>#include <STDIO.H>
* \5 N# r: R- \- i6 i1 g#include <CONIO.H>; E+ Y2 s% I" p
#include < ROCESS.H>
" {( P7 r' y# m#include <DOS.H></FONT></P>- F5 g8 c. T* |6 t: V% Z
< ><FONT color=#0000ff>int main(void) ) }% u* ~; C) n: E/ s% [
{
. a4 Y. W) W- |! P" K# Z/ O7 ~5 uint i, strt, ch_out, sector; ; C* F; ~% n- _8 b0 E
char buf[512]; </FONT></P>6 p1 K2 t, c( H+ N" F
< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
" F8 {* [! f( C2 C- ]1 V% Igetch();
7 Y# p& Q: O' _' F7 D' tsector = 0;
) _7 y8 J" y8 @" H3 rif (absread(0, 1, sector, &buf) != 0) & C0 Q& X: y1 A, @6 z# k$ g9 n5 {
{
( G# I* p6 d5 s9 u% Nperror("Disk problem");
7 S5 d4 w8 ]/ q5 {+ s. yexit(1); ' H% Y2 Y4 x1 \; u7 [1 j. M+ _1 d
}
3 d# w; o$ _( ] }; o5 Pprintf("Read OK\n");
* ]* z P+ I$ b: R: \strt = 3; 3 s) ^1 v9 l% r! u8 j3 i
for (i=0; i<80; i++)
1 j# f+ j) V7 |{
1 [6 n. d i/ I! C: D- Ech_out = buf[strt+i];
' ~% n( F; O& v, mputchar(ch_out);
' H2 F( n& ]' M$ t( y3 R3 T} , `* a* g& k6 e2 x$ E% _
printf("\n"); * m$ P' c# H! M- ?% c. S
return(0); 0 E. a; Z9 t3 x$ `/ s; l- \
} & o# _5 M# V9 T+ W0 u( `+ P
</FONT>
p( S; y+ d& q7 @7 J! ?, _8 g" i0 _3 f, }4 W! W B7 V9 i
</P>' n* Z7 \, O: U( K! h3 C% C; B
< ><FONT color=#ff0000>函数名: access </FONT>
! ~$ S% v0 L( ~7 r功 能: 确定文件的访问权限 / c X! M7 q: h3 k: ~7 C
用 法: int access(const char *filename, int amode); ) S7 n! N, p; n! {
程序例:
( v' }# c# M; o9 Z0 h7 Z<FONT color=#0000ff>#include <STDIO.H>
; ]; s- e4 G' g9 Y% D#include <IO.H></FONT></P>9 W: v; i/ i% K* U! F
< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>5 E% {" h0 J# h J" G
< ><FONT color=#0000ff>int main(void)
, w% l1 o$ R" D. |$ w{ ; h' p$ H7 ?1 s0 v/ a( f, O" a
printf("Does NOTEXIST.FIL exist: %s\n",
$ C" ?2 } P* x% ^1 K. Qfile_exists("NOTEXISTS.FIL") ? "YES" : "NO");
6 h5 K1 Q. N7 {6 h. e( {5 Kreturn 0; ' o0 o' w7 s/ @
} </FONT></P>9 I4 z5 L. S5 g, ]; R
< ><FONT color=#0000ff>int file_exists(char *filename) : n! m. A. N. R& `: C. S5 L/ H& J, u
{ , I5 M6 K% {: }4 V% c
return (access(filename, 0) == 0); 6 U% @- l! C, N, u
}
9 j6 o% h q4 D% k</FONT></P>
2 @' V, u' P% O g< ><FONT color=#ff0000>函数名: acos </FONT>+ O8 M% E& A; _, c& x7 K3 `8 ] r
功 能: 反余弦函数 8 ~/ t& p0 G0 n
用 法: double acos(double x);
, a0 i" _9 l8 g( _, U# ^程序例:
T0 x3 I9 ?2 B$ |' r1 B0 Y4 @<FONT color=#0000ff>#include <STDIO.H>
! {2 N D9 K. d( v, k#include <MATH.H></FONT></P>7 o7 n7 x- I8 `, R
< ><FONT color=#0000ff>int main(void)
8 K9 q! B/ S6 I1 L' Y* L0 a{
" Y* z+ L& E+ {$ K4 a) H2 v: C, qdouble result; . r! n9 K: Q; @4 S1 s, H s
double x = 0.5; </FONT></P>/ b8 G2 k2 J. v3 V4 r9 r3 B
< ><FONT color=#0000ff>result = acos(x); 3 Z, J- k" ~0 z
printf("The arc cosine of %lf is %lf\n", x, result); " p2 h+ H, \$ e
return 0;
. {2 F0 n+ M: ]! V$ K! D% T4 }} </FONT>% f* Y; S. G! _/ o) \2 V
) b( t3 q/ b9 o
</P>
# t: L; w, c. S- B; M* E< ><FONT color=#ff0000>函数名: allocmem </FONT>* i9 a" s' N9 w b9 B. {/ R8 M2 T/ {
功 能: 分配DOS存储段
: q7 t9 N% E* p8 D2 m用 法: int allocmem(unsigned size, unsigned *seg); # M. `) Y9 m6 z9 B# e9 R% j! \
程序例: + q1 P. o9 `0 y
<FONT color=#0000ff>#include <DOS.H>
2 K5 ~( c# X* I3 [#include <ALLOC.H>
7 K8 E0 J2 D- [: q: p2 E4 r% j6 K# h#include <STDIO.H></FONT></P>
4 G0 |" ^& g# c$ j< ><FONT color=#0000ff>int main(void) 8 r- K: _7 |9 A" g
{ 0 K$ r, [5 |- w
unsigned int size, segp; 7 [5 D( S/ _& I- {. t, u
int stat; </FONT></P>6 `: M7 ]4 h) R3 [5 n9 m
< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ ! J/ q! R$ a+ N* k0 }# n* i9 W
stat = allocmem(size, &segp); 4 l# U/ {. ?8 w8 e# o
if (stat == -1) + e' N/ x. i) A. u
printf("Allocated memory at segment: %x\n", segp);
4 _) K5 h8 \: {9 ]9 Qelse . c! T z- q$ F# U) N5 B% m
printf("Failed: maximum number of paragraphs available is %u\n",
6 [$ }2 q' H8 k; t8 C! xstat); </FONT></P>: _6 s0 X/ W$ q8 s
< ><FONT color=#0000ff>return 0;
! A) A) y" q7 @} </FONT>
! N' F$ `) i1 s- u8 x6 j4 @
r* Y/ g0 l4 _" _% O" q! k</P>
7 f/ _3 f* w% g4 U< ><FONT color=#ff0000>函数名: arc</FONT> 8 e$ D! m0 d# ~4 ?! {
功 能: 画一弧线 ) p- l$ q0 U! N/ C! f R/ q/ K
用 法: void far arc(int x, int y, int stangle, int endangle, int radius); , j$ ]. K; X! T" W: z- B6 L* P
程序例: H# f' X& m+ B( u+ a' C
<FONT color=#0000ff>#include <GRAPHICS.H>+ u- b) `" g7 _. g) [( m7 h; ~
#include <STDLIB.H>
& O5 L- D- v9 |- d, e5 L3 s#include <STDIO.H>
3 q$ [% d- t# `& {( f#include <CONIO.H></FONT></P>- r0 }+ D& f" f$ o1 {" d
< ><FONT color=#0000ff>int main(void) * k! e' f1 M, G" @( P8 M
{ , X: v1 {; M4 ]/ ~) H! y, O" S! k
/* request auto detection */ 5 T; g2 q1 n% e' o' E
int gdriver = DETECT, gmode, errorcode;
9 n2 ~4 B# O9 `int midx, midy;
% J- w! G( f1 Q% j2 I" `7 Fint stangle = 45, endangle = 135;
5 g* O+ W* Z0 L( B5 [/ B- T1 ]int radius = 100; </FONT></P>7 R6 l- \0 `6 A5 w/ x& p
< ><FONT color=#0000ff>/* initialize graphics and local variables */ % i" K R) B8 Y e T& l& \8 `
initgraph(&gdriver, &gmode, ""); </FONT></P>
5 c! ` u1 G& y3 q6 b: h7 l< ><FONT color=#0000ff>/* read result of initialization */
* k1 {+ r- W: _8 {errorcode = graphresult(); /* an error occurred */ ; ]0 e3 q' B. E9 V+ K
if (errorcode != grOk)
/ h0 [$ i. p+ P! U1 q& g* l" X+ y' P{
5 z+ H4 j7 s% U8 \$ }printf("Graphics error: %s\n", grapherrormsg(errorcode)); 2 o$ m( n5 u" y2 [ C* l/ `6 P
printf(" ress any key to halt:");
p+ j0 Y/ Q) v, J+ }* [getch(); </FONT></P>
; p% q' E4 R1 k6 U6 |< ><FONT color=#0000ff>exit(1); /* terminate with an error code */
0 h/ t+ V: C+ a+ h4 l} </FONT></P>
$ M- `- n" S, z9 F! G< ><FONT color=#0000ff>midx = getmaxx() / 2;
) U. H# U' Y( K2 P, ?midy = getmaxy() / 2; / q4 e* i) ^) m8 r% Q+ J1 d5 M. N
setcolor(getmaxcolor()); </FONT></P>
7 R8 a: N4 ^: h9 t< ><FONT color=#0000ff>/* draw arc */
" n; ~1 ?7 E. T1 H8 Oarc(midx, midy, stangle, endangle, radius); </FONT></P># Z, @% v2 {. N9 J* {; b
<P><FONT color=#0000ff>/* clean up */
# Q) r# [- ^3 g3 `6 i7 q* d# b: [+ |getch();
5 e, h. d- |( o/ c- W: b1 Y- B5 Xclosegraph();
7 c9 w3 S$ L% b1 P( O8 ~return 0;
4 a+ N6 [3 L5 d$ g5 D) k/ d$ g}
2 y; v3 d9 z, @7 e8 n9 W* a$ s</FONT>
7 G; | L, L; n3 X" L% B3 A</P>. o v$ D5 u) D/ {, k- l
<P><FONT color=#ff0000>函数名: asctime </FONT>
: z" t- A/ F5 V/ L" y. m4 f3 ~8 ]功 能: 转换日期和时间为ASCII码
" Q F4 D# M" r. i/ q8 f8 P用 法: char *asctime(const struct tm *tblock); * [, @; E& _( @7 Y- B1 c L
程序例:
, j7 ?+ `1 z, P3 o<FONT color=#0000ff>#include <STDIO.H>
" E9 ? f: H j$ n' S# n#include <STRING.H>
0 y: x1 C& p4 e& ]% c#include <TIME.H></FONT></P> [& W" ]6 Z: m) J j: N
<P><FONT color=#0000ff>int main(void) 6 G* W! F, H9 t
{ y- D2 J) L$ [0 q( Z
struct tm t; + }; r8 Q* } I% l% |/ x8 b
char str[80]; </FONT></P>
$ I; o& \7 O3 k9 ?<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
$ h, {1 y' Z1 M, C: t q<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ ; P: y3 u6 G0 C+ ~9 F9 F \; e
t.tm_min = 30; /* Minutes */
1 F9 m h6 _3 ]( {. Z F! d9 ?& `: b5 Xt.tm_hour = 9; /* Hour */
$ o& ?# X9 l. }' u* W# I2 Pt.tm_mday = 22; /* Day of the Month */ 7 b4 T. u: ]9 @% }+ `2 i
t.tm_mon = 11; /* Month */ * ?' S+ U3 _9 e* [
t.tm_year = 56; /* Year - does not include century */
3 l$ P' W- _1 @ @) o9 J7 Kt.tm_wday = 4; /* Day of the week */
5 Z$ t* _. \ U) Q+ D0 h! T1 Dt.tm_yday = 0; /* Does not show in asctime */
# Z, l. W: o) q) T* M7 r6 d8 {t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>* P2 v2 O- O5 L; j; T
<P><FONT color=#0000ff>/* converts structure to null terminated
- m$ E. W, V. G+ s: dstring */ </FONT></P>
9 C3 l/ H" e. Y9 b/ ]* D- G<P><FONT color=#0000ff>strcpy(str, asctime(&t)); & ^8 [5 ?- ]: i
printf("%s\n", str); </FONT></P>
2 Q+ f" I% m& o6 S<P><FONT color=#0000ff>return 0;
& m& ?2 p: P! K6 h5 a# @} ) [) n7 g0 [4 D: }: f$ W
3 a; ]$ c" ?, {</FONT>/ | X! @& v$ e9 ~
</P>
2 \, ^, I/ n3 {* W+ Z. f9 C& I, z<P><FONT color=#ff0000>函数名: asin </FONT>" g l# F8 m9 ?5 T/ j
功 能: 反正弦函数 + ]5 [! c1 \& {
用 法: double asin(double x); $ B$ ?3 o3 P: C+ r( q- s) N
程序例: * b* R- m$ d, \( z) o
<FONT color=#0000ff>#include <STDIO.H>9 B _7 b, M' ^- J, @$ N* o
#include <MATH.H></FONT></P>
8 N0 V% E( j- i v<P><FONT color=#0000ff>int main(void)
: E. I& S5 O+ Z- I/ {{ ) c' j+ Z& N, D2 a% g
double result; # {$ m1 R1 |" _ x. x) ^ i0 w
double x = 0.5; </FONT></P>
" Q& o2 L1 G/ |( B$ M. l4 K' Z<P><FONT color=#0000ff>result = asin(x); 2 x7 t0 I( S7 i5 S: y
printf("The arc sin of %lf is %lf\n", x, result);
) U, ?/ v' v/ ]7 ^" j* {& Wreturn(0);
, g, ~5 ` W- w: ~, V: v# [}
# p+ a' d3 `- V) T9 P5 Q! }) [</FONT>) M% a5 Y+ \# \7 c1 h
) ]0 N$ l1 ^9 W! H5 E* ^</P>
% e! A0 W Z! J<P><FONT color=#ff0000>函数名: assert </FONT>
9 O5 @- e6 @. R& A+ B( S5 Z' H0 ]功 能: 测试一个条件并可能使程序终止
! s4 m0 G' c3 M4 K: q& D用 法: void assert(int test); 4 z7 `8 E( Y A% N, Q( Q
程序例: 8 }) g" g+ M4 G2 Y. x O$ i
<FONT color=#0000ff>#include <ASSERT.H>
4 n% V, O! q# s8 s+ g#include <STDIO.H>
" |4 `1 J$ C! B9 B#include <STDLIB.H></FONT></P>
5 T/ l, d* O, f# ]6 T4 c# f<P><FONT color=#0000ff>struct ITEM { " h* f N; i* e& _1 G" f
int key; # H( s4 G7 a: i% K2 h
int value; 8 ]5 y3 g" V' ^3 B7 `3 I% D8 X
}; </FONT></P>
+ i; K4 j. O9 d<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
1 r# X' | G5 _+ ^; s P* r* Q( Pvoid additem(struct ITEM *itemptr) { 0 L( t, C. g$ D& n% E
assert(itemptr != NULL);
& q: p* Q2 d& l2 E' W/* add item to list */
. p+ t2 b; G) L) Z} </FONT></P>2 d% X3 P- z+ j5 u/ M% [
<P><FONT color=#0000ff>int main(void) C; F+ G9 Y# \; @. \2 R& r
{
% h7 r2 G" J0 F) }# O1 y8 [additem(NULL); 8 u5 L, r/ c+ J9 V! @8 C
return 0;
0 j' }# q# R% }: \& b6 A! e}
- B/ C+ b( J" k, ?0 x) F</FONT>9 j3 h% _- g V
( S4 h$ Q- o( f% R</P>2 o V8 M( F. H( n, S9 T
<P><FONT color=#ff0000>函数名: atan </FONT>) J( q y6 |8 L7 z3 O$ k9 P
功 能: 反正切函数 " j/ v* H/ A1 i& i
用 法: double atan(double x); $ U* @! L6 A: V/ M/ m/ ?1 a
程序例:
' V1 B5 n( L' I- Y3 n; `<FONT color=#0000ff>#include <STDIO.H>0 T6 l$ ]' o0 ~( ?
#include <MATH.H></FONT></P>
% P/ p/ {3 ^6 m5 E7 ~+ F<P><FONT color=#0000ff>int main(void)
, N' O! x! R& a/ p{
8 `! [- Q. N4 m; [double result;
: @2 ]' B- j" a, l+ pdouble x = 0.5; </FONT></P>0 ^- A2 t) _0 g7 @9 F& e& c, a
<P><FONT color=#0000ff>result = atan(x);
5 a+ e6 l3 X5 p4 s5 y/ t" c9 J; aprintf("The arc tangent of %lf is %lf\n", x, result); $ s8 _ y r; W: {9 t
return(0);
0 Z1 Q) z" c$ V8 _, t4 Z}
# P1 J# u& n9 p) w$ D) _/ x</FONT>
: o. I; B" z K/ w$ j( k! J% }7 Q</P>
9 l% [1 b5 S0 T2 |0 x2 x2 S<P><FONT color=#ff0000>函数名: atan2 </FONT>: u$ N# M7 J( u. c: H
功 能: 计算Y/X的反正切值
8 U; v1 i7 O) R用 法: double atan2(double y, double x);
% K) s' k9 D& _+ @6 U7 [程序例:
( s* L7 k& _1 N* V3 H+ F {6 F<FONT color=#0000ff>#include <STDIO.H>0 f/ P# M1 j: M" B
#include <MATH.H></FONT></P>; M, P* D. }- ~% u+ b: g# D* B5 Y
<P><FONT color=#0000ff>int main(void)
& c) [9 |8 j0 T# C) u8 K1 V8 Z1 R& a' t. b4 \{ 5 \; m$ s9 v* v+ _$ P, X
double result;
6 ]+ n3 m5 I+ w3 g1 h% B5 J# ndouble x = 90.0, y = 45.0; </FONT></P>5 a( |. e2 x' F7 I8 N% F
<P><FONT color=#0000ff>result = atan2(y, x); . g! i: r- j- m
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
7 _* f1 r& J, o6 T5 kreturn 0; 6 V4 ?2 T0 i' T, e
} A) |9 _7 L2 ?9 Z# i
</FONT>
( U+ v7 {; d8 d2 L4 B: p</P>
. N+ w( R0 H2 w* I; a: a* U4 P<P><FONT color=#ff0000>函数名: atexit </FONT>+ f; W R" i' T) o
功 能: 注册终止函数
5 L' v( b7 e8 J `4 y% C3 ^用 法: int atexit(atexit_t func);
) i) v% A0 d# \& N; y" B程序例: 3 R# c2 t. J$ M4 d8 j4 y* F
<FONT color=#0000ff>#include <STDIO.H>" ]: F1 f6 W. y- ^, _
#include <STDLIB.H></FONT></P>
: w5 K; p3 _' U% p+ q. x8 a" H0 n. u; v<P><FONT color=#0000ff>void exit_fn1(void)
* b: _2 B/ _$ n1 W/ T, \1 o; [1 n{
; X( y( W1 s2 X( Kprintf("Exit function #1 called\n");
: ^! d, T3 a9 Y/ D: x+ B7 e5 R} </FONT></P>
3 v- @7 ~1 K* v. {+ ~/ f& v<P><FONT color=#0000ff>void exit_fn2(void)
' I$ a" |* h5 e( m. M3 w{ " Z- C1 l6 p2 P/ r8 a' c7 u# F
printf("Exit function #2 called\n");
; f, t4 H1 c. y0 }) _0 ~} </FONT></P>
7 n3 s7 v/ F+ b$ m* n2 n6 D<P><FONT color=#0000ff>int main(void) , Q. V2 S6 I( j) M1 t& f
{
" J8 }+ e- n5 i9 p% G7 t5 e6 Z/* post exit function #1 */ : G* A8 r b0 H" S2 t; n
atexit(exit_fn1);
9 K! [0 F' R$ D) a/* post exit function #2 */
" x% r0 k, j; batexit(exit_fn2);
. ~6 q% E1 l6 z7 b/ Qreturn 0;
) s2 v1 l( Y. i) x$ f2 G}
; i0 \: |& i5 t7 z! u</FONT>
2 r( f6 B. M& a- f2 w! W! u
2 s8 ?# M, b) q( c9 D8 z</P>1 Y" g6 E+ t( o2 H! O2 c
<P><FONT color=#ff0000>函数名: atof </FONT>" B: B8 ~; h! s( }* Q) \. Y
功 能: 把字符串转换成浮点数 # u- G5 \ m+ Y# p% N
用 法: double atof(const char *nptr); 5 R) J3 q# [4 A& ]7 w1 w
程序例:
& B& c5 _2 S' |# }# o<FONT color=#0000ff>#include <STDLIB.H>4 r. z# L% Q( J7 k; F& z) l
#include <STDIO.H></FONT></P>
$ q1 x K C+ k: c* F1 p<P><FONT color=#0000ff>int main(void) : P& G0 @: C& P; ]! O
{
7 U3 K! M0 T% R q/ i! z0 y9 f6 Vfloat f;
3 n3 W3 }6 C9 X6 K( k$ nchar *str = "12345.67"; </FONT></P>
9 I/ K) d4 P; N$ L<P><FONT color=#0000ff>f = atof(str); / o: U# p, [& Y2 k# T# T
printf("string = %s float = %f\n", str, f); # }8 r0 q; C% @ E! a% r s* P
return 0;
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+ A4 K- N. [6 q+ Z+ L& k$ R</FONT>
; k2 k3 @9 b. S; }- ?% B7 V! G' C1 Z</P>
# y, W' t- Q& M1 x# z) M! \<P><FONT color=#ff0000>函数名: atoi </FONT>- e: D: d" Y8 U2 _! g+ p
功 能: 把字符串转换成长整型数
+ {2 u7 G7 H: t" i/ J用 法: int atoi(const char *nptr);
$ l3 E( ~. |% i" @9 e) [程序例:
, j# u5 W6 S+ N& M9 J) n<FONT color=#0000ff>#include <STDLIB.H>" H. G3 E6 q/ E: q/ a# o
#include <STDIO.H></FONT></P> v. y( G, `& M& A9 p
<P><FONT color=#0000ff>int main(void)
. _4 k8 h- Z7 `! W6 w( }3 ]{
( R1 }* W" e; c0 Gint n; 0 c7 r4 @ p5 a7 J% g' K. d
char *str = "12345.67"; </FONT></P>3 K% b/ X2 {3 q: M f2 X l. \: M
<P><FONT color=#0000ff>n = atoi(str);
7 Q5 s, H' @9 M: x+ Oprintf("string = %s integer = %d\n", str, n); 4 P1 Y L6 x4 ?7 t: @% Z
return 0;
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2 x8 g% J5 d4 H. `% `) W: @& _2 J</FONT>
5 b+ E7 C5 T" F" J. @: T</P>
" c; X7 J; X9 A G<P><FONT color=#ff0000>函数名: atol </FONT>
! o# P& S" w4 H3 U/ ]功 能: 把字符串转换成长整型数 ) ~ c4 u; A+ `3 l4 P, x* r1 P
用 法: long atol(const char *nptr); 9 X! I: S& U2 C- z ?& D
程序例: </P>$ _0 V$ V) i* R2 m0 W
<P><FONT color=#0000ff>#include <STDLIB.H>8 _8 e9 K. T5 @5 P3 b& A$ @ r+ }3 ~# d
#include <STDIO.H></FONT></P>
& r) E+ i+ [% d' g8 [<P><FONT color=#0000ff>int main(void)
2 d$ i* |% N2 s7 i. G* e( i% c{ 7 z7 i& M, e1 w
long l;
1 z! r) L) V5 \char *str = "98765432"; </FONT></P>' F! S7 L; r# p$ K
<P><FONT color=#0000ff>l = atol(lstr);
% y$ m3 A. h$ ]) Cprintf("string = %s integer = %ld\n", str, l); 7 J4 ^, A6 I+ y5 l- ^
return(0); ! d a9 t! t' ]6 C: r
}</FONT></P> |
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