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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |倒序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
0 x+ A" z/ |8 K7 G: _5 r) P<><FONT color=#ff0000>函数名: abort </FONT>7 ^8 u$ w; s3 x
功 能: 异常终止一个进程 0 v1 D- V# V9 f, v6 V
用 法: void abort(void);
+ z3 U2 Z; I5 ?4 t; ~程序例:
) U% Q' v# o! S+ k<FONT color=#0000ff>#include <STDIO.H>
6 O8 u  M7 L# _- k#include <STDLIB.H></FONT></P>  Q$ j# B5 u* D8 k4 L
<><FONT color=#0000ff>int main(void)
& |/ }9 \* S3 {7 G$ ~{
, Q2 m- v; B- H& E* _/ ?printf("Calling abort()\n"); , e5 d# E0 f# c7 ?
abort(); 1 u/ C; y( o  n& Y! z6 [
return 0; /* This is never reached */
" Y) V& M9 o+ M' o, Z. x4 @}
! s8 K* t: G6 ?4 o; A</FONT>
* }5 d- K0 J  S</P>
5 _/ @: |( d9 v1 a3 V<><FONT color=#ff0000>函数名: abs </FONT>
& L  ^* |. @5 r1 x/ F功 能: 求整数的绝对值
1 G# W+ c2 _  |; \( p用 法: int abs(int i); 1 U6 A) k( _2 p! U3 ?9 Z
程序例:   {' G8 t) D) \
<FONT color=#0000ff>#include <STDIO.H>0 T5 X" p8 O; X5 l6 A4 {1 G/ [; U
#include <MATH.H></FONT></P>0 ?/ H4 E' v+ P! Z8 e5 @7 y
<><FONT color=#0000ff>int main(void) 9 n% E7 Y( o+ d5 e' ^
{
1 H  C! ?9 w2 Z4 G" Rint number = -1234; </FONT></P>; f/ w, H: d4 {" l( Q9 z
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); 1 b) V3 ^! |+ a. f. t2 x+ X
return 0; / d' B  O7 S* S
}
% T5 g# T, m* j6 ~4 y1 S$ ?: d0 V</FONT>
. g8 y5 |0 e1 k+ E+ h</P>
# F5 H0 z! S! o# E' {6 r<><FONT color=#ff0000>函数名: absread, abswirte </FONT>/ o! X; h, d+ o) X. A) E5 u+ y
功 能: 绝对磁盘扇区读、写数据
2 }  q  z& s+ m! _用 法: int absread(int drive, int nsects, int sectno, void *buffer);
3 R( E" B) R4 @& _int abswrite(int drive, int nsects, in tsectno, void *buffer);
& B7 X  Y2 ]  e1 d5 O4 q4 V程序例: ' s0 S% w' ?& d; T0 x
<FONT color=#0000ff>/* absread example */ </FONT></P>7 W1 @8 g" g7 z3 a" H* @% j% y
<><FONT color=#0000ff>#include <STDIO.H>) {" R* {2 H+ N: k' o! N2 m
#include <CONIO.H>
2 J* f3 N% L7 k#include <ROCESS.H>  f  Q- H! Q# R
#include <DOS.H></FONT></P>, |& c: x- _9 l1 U% R: K
<><FONT color=#0000ff>int main(void) $ g+ o. o$ v3 b* X0 Q. k
{ & U4 d  `( z% w* g: [  r8 ~. A
int i, strt, ch_out, sector; 8 c8 m9 n! ]/ W7 Q& r* X
char buf[512]; </FONT></P>
+ [3 W) M% R1 \0 p7 m5 b% k! V<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); 4 q# y) y. T2 R8 _  `) K( F& p
getch();
5 ~' s' d" _* m/ asector = 0; + [9 R0 `( \4 ~* {$ `8 G/ V
if (absread(0, 1, sector, &amp;buf) != 0)
& d3 o% W+ h$ F/ B) T{
! _% S: I2 @. u; Operror("Disk problem");
4 `7 S0 D) Q' gexit(1); # F% f9 Z1 r: k. V  [
}
. m5 A' S6 z4 f8 G5 J5 N4 r- ~0 Eprintf("Read OK\n"); 8 o  Y8 n* L4 y. V
strt = 3; * q2 r( R5 s8 ]. b, s
for (i=0; i&lt;80; i++) 4 S4 I- e9 _2 h7 j3 s2 j
{ 8 G8 x) \- K/ E, g) s0 O( X
ch_out = buf[strt+i]; ! `: o" v+ V" U$ u2 _/ E, R
putchar(ch_out); 9 H, P2 J! z( Y) y  M/ l
} , w& Y$ U1 L3 k$ t
printf("\n"); + {/ a! p) g- a
return(0); # ^  W0 |: T3 L" N$ k4 C0 X
} ' K1 O1 C7 [" M" M  j1 C
</FONT>6 ^! q, P! G' d# m

: V% {$ k( G3 x' ?</P>
. @) Z5 |* b2 G$ L<><FONT color=#ff0000>函数名: access </FONT>
9 z4 u& P" a: L" y; K: ]& Y功 能: 确定文件的访问权限 + N' Y2 Y1 O) ^( i
用 法: int access(const char *filename, int amode);
5 V1 k7 }( p) E8 K2 l4 X- o程序例:
% ^' D1 d! {  I. g$ s! u) n0 G<FONT color=#0000ff>#include <STDIO.H>: ~( @: g1 w9 u7 _
#include <IO.H></FONT></P>
- ?* E6 Z  E- M* ~4 S9 P<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>0 E1 s+ I  t8 h- M0 b, }$ T& Z
<><FONT color=#0000ff>int main(void) 1 M3 Z; c( d, U! G% Q
{
" E6 c: k, A& f4 ?printf("Does NOTEXIST.FIL exist: %s\n", " s- M1 D- P0 n+ k
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
5 ~% V* n) d% o) c! e; Greturn 0; , Z+ v% U5 I& m/ \
} </FONT></P>( ?9 T( M; b7 ^1 C
<><FONT color=#0000ff>int file_exists(char *filename) & K, T" H, l" X+ N6 G+ t- L
{ 6 r, r* K0 N( R0 I% H' x
return (access(filename, 0) == 0); 3 c* v7 y$ k/ e8 T6 ?  M
}
7 h2 m% w0 E* d2 u1 m</FONT></P>
  d5 v* S/ w& F7 [* Q, y( X<><FONT color=#ff0000>函数名: acos </FONT>9 a) H) G0 C) l7 n* V; E( m+ X
功 能: 反余弦函数 & {  G% @- \- w8 T  r- _# x
用 法: double acos(double x); : J4 j, n9 X, Q) ^8 E+ U
程序例: & S4 h  C# k, F7 J- C7 }, G
<FONT color=#0000ff>#include <STDIO.H>
( X& z! U) P/ r8 l: S# p#include <MATH.H></FONT></P>
. U2 |1 [' t# ~4 q* _( ~: R<><FONT color=#0000ff>int main(void) 9 G% V/ W" ]/ j; m
{ 1 Y, j6 s/ e; ^) f6 L7 m) I
double result;
( z7 Q- h7 C7 J: Z- [8 l6 X2 Tdouble x = 0.5; </FONT></P>6 }( i) h/ m' H) A" {
<><FONT color=#0000ff>result = acos(x);
$ }( V, m- I& T5 b; q" dprintf("The arc cosine of %lf is %lf\n", x, result);
1 d6 I6 u3 F9 p+ z" x- I  G! Hreturn 0;
3 u* W- s- E! s' ~# {& c1 `$ R/ `} </FONT>2 |, n" z6 o% }6 e- K$ W

/ u+ ^5 t4 l- {% O' W</P>! R0 m$ L* k' g( U) f) _3 s
<><FONT color=#ff0000>函数名: allocmem </FONT>8 x% m0 j! B/ _; K. q' G
功 能: 分配DOS存储段 2 e' }. ?# v, u9 H4 N' m* w* z
用 法: int allocmem(unsigned size, unsigned *seg);
9 p  {6 N0 J9 I/ m, T2 D3 w程序例:
4 ?; q/ n! a" }<FONT color=#0000ff>#include <DOS.H>
5 M- H/ [! l: j#include <ALLOC.H>
/ F) _1 |% R3 M#include <STDIO.H></FONT></P>
+ i9 ?" ]" @1 W0 o, Y8 k% Z3 U<><FONT color=#0000ff>int main(void)
( X* n9 T+ {$ d9 c{
) `: h8 o0 U' W5 T$ S7 Runsigned int size, segp; ! i4 c, v3 K3 y1 c0 A
int stat; </FONT></P>4 T! w; Z5 A# F3 \
<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ . u) p7 H$ x" `
stat = allocmem(size, &amp;segp);
6 u- G  t- U  y% R3 [if (stat == -1)
- B$ O) a* P2 R1 d* X0 R, Bprintf("Allocated memory at segment: %x\n", segp); & h. q! t; G7 t" O
else
9 N$ H3 `) o! w1 ]5 O% G& jprintf("Failed: maximum number of paragraphs available is %u\n", ; P/ {: i8 r( L, i9 R
stat); </FONT></P>/ I) a6 X+ m; X$ c0 n$ k6 C
<><FONT color=#0000ff>return 0;
0 c& Z5 i- ]0 o% p* D0 C} </FONT>6 B8 g! J" P) g) `/ p& v% a
% l# _/ w3 o5 W. W$ u" K1 |
</P>
5 ?- [3 J9 ~; E7 t8 ]9 G+ a<><FONT color=#ff0000>函数名: arc</FONT>
: c' I6 A* @$ v/ ^功 能: 画一弧线 $ w! u" E2 Z/ Q2 p
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
) O0 L) X0 D& A" P" w5 ]* G# d程序例:
5 N, U! y; z* Y2 Q) s+ R# d7 M% p<FONT color=#0000ff>#include <GRAPHICS.H>, J' z. l3 p, o! H! G1 O$ i
#include <STDLIB.H>0 `2 q3 g/ G. J& v
#include <STDIO.H>
! f9 E0 P- S3 V3 x1 k4 [1 ?#include <CONIO.H></FONT></P>9 w/ Q$ ~- n. S/ J6 Z
<><FONT color=#0000ff>int main(void)
: G( i  n, i3 r& S3 |% k{
8 q# f  T2 {6 g: z  j4 ?' v" L/* request auto detection */
" j' m5 s, e/ O! n4 xint gdriver = DETECT, gmode, errorcode; ; E9 s: G6 `" n6 h4 J' s3 [) ^4 c' U
int midx, midy;
4 F; \6 R, U% u' o& e; Eint stangle = 45, endangle = 135;
$ e) }6 S3 t1 Y3 Tint radius = 100; </FONT></P>% c+ K  u/ n# b2 o
<><FONT color=#0000ff>/* initialize graphics and local variables */ , y/ |2 o# F6 E: O9 z
initgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>3 l" _6 F* @* O& d) C' ?# c
<><FONT color=#0000ff>/* read result of initialization */
- g9 V3 U2 {) L9 [errorcode = graphresult(); /* an error occurred */
# G3 u1 [( B, C* rif (errorcode != grOk) ) d+ `; |: I2 `6 ~5 o
{
$ y+ ]. u; m2 j6 Y. ^+ z- gprintf("Graphics error: %s\n", grapherrormsg(errorcode));
4 m7 k& D5 e- B3 o& yprintf("ress any key to halt:");
& j5 B# d7 W" R* Hgetch(); </FONT></P>- f. W/ v  M2 A8 H4 G6 g& d2 a! b
<><FONT color=#0000ff>exit(1); /* terminate with an error code */
" ]% Z, p  @$ K+ `$ ]  g% U' |/ L  o} </FONT></P>. x7 J. z5 T  P* {3 t. J- V
<><FONT color=#0000ff>midx = getmaxx() / 2; 9 g" C2 k) t' i! O
midy = getmaxy() / 2; ! o+ t% ]' M# [/ U" v
setcolor(getmaxcolor()); </FONT></P>* }5 I! q! t9 [  t
<><FONT color=#0000ff>/* draw arc */
& }; X1 e% }) E7 j* W0 yarc(midx, midy, stangle, endangle, radius); </FONT></P>
9 ?. u! ^* ]; b7 F. S( K<P><FONT color=#0000ff>/* clean up */ 2 Y# E( Y; r% \- H
getch(); $ `# p; D% ]" @% W
closegraph(); 5 s% ]9 e  W" z/ \
return 0; $ o5 g1 }% R+ W! r6 ]0 P
}
) s; p( h+ t# Z</FONT>
; e$ _' V2 H' A, _) H7 |</P>
0 {- G& g9 C: K: R1 W) H7 g<P><FONT color=#ff0000>函数名: asctime </FONT>
- Y2 c) F4 z" w% Z功 能: 转换日期和时间为ASCII码 + U# t, @8 w. e' T5 }0 _
用 法: char *asctime(const struct tm *tblock);
. m/ F7 n2 S2 K* H/ v程序例: ; E+ s, q! ?+ V! Z3 q% P, X, c
<FONT color=#0000ff>#include <STDIO.H>
& }/ ^  P$ a/ y* \* D+ m#include <STRING.H>$ O( a9 f+ d4 @2 G
#include <TIME.H></FONT></P>  Z( ?+ p/ q- z
<P><FONT color=#0000ff>int main(void)
( \: M; ~3 `% ^- R1 i# b9 D{
+ B9 {2 Q6 V7 M5 ?6 ]struct tm t; 7 M/ }$ _  `# e! Y# G- Y$ k
char str[80]; </FONT></P>* a% h5 q: L* F
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
5 N: ^3 b' s% D! B2 e1 a<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
: |: ~. T. ~; I( Z, Tt.tm_min = 30; /* Minutes */
- J4 H6 V! h/ z$ i# n) Wt.tm_hour = 9; /* Hour */
: a1 v( n( N( M1 b! bt.tm_mday = 22; /* Day of the Month */
# C1 w7 I4 b+ it.tm_mon = 11; /* Month */
$ p3 {; C. h) `' j9 _+ m; x3 ft.tm_year = 56; /* Year - does not include century */
: c9 C! A5 S. w" q# s4 k+ rt.tm_wday = 4; /* Day of the week */ 2 P7 f& @( z2 r6 d/ a- i: ?( W0 S
t.tm_yday = 0; /* Does not show in asctime */
* J) j/ Q5 W- o7 Z4 k4 a6 m' Dt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>0 u6 u! D! V; U+ ~
<P><FONT color=#0000ff>/* converts structure to null terminated 0 }. z. b/ w5 R  s! C) I
string */ </FONT></P>/ w, W! F) c. g. }
<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t)); ! R( J: [. r3 d$ a* e. [& N
printf("%s\n", str); </FONT></P>
; u# N2 t" M3 u<P><FONT color=#0000ff>return 0;
( h& o3 W6 e4 V: ?% w- R}
! j2 v$ }/ E) F. \; K  T& I
' i! h: o# b3 x/ r</FONT>
5 n, x) @! X0 ^+ k2 u- p$ S  H0 N</P>
$ G- v6 J& K# `4 G7 M% ?& H1 r<P><FONT color=#ff0000>函数名: asin </FONT>. E+ I# a. u% {) h( k
功 能: 反正弦函数
# l; [( e+ c" @4 U8 K% ^用 法: double asin(double x); . {6 o2 o5 ]& C6 w( h
程序例:
$ E( e, _1 L7 V* `& Z' G: G, M<FONT color=#0000ff>#include <STDIO.H>4 l" K+ h; O; h! o8 g
#include <MATH.H></FONT></P>
( |6 A" K- t1 |1 H) T4 m<P><FONT color=#0000ff>int main(void) - O! J" ^0 ]- ]  V" V
{ ) O* V  e; ]9 P9 w  N
double result;
. k; l, u8 H7 G" z! g4 Idouble x = 0.5; </FONT></P>$ }; X5 l1 x/ e4 m+ ~9 O
<P><FONT color=#0000ff>result = asin(x); 0 Z) q0 `+ W5 l
printf("The arc sin of %lf is %lf\n", x, result); 7 @( M* s" c# {6 o4 N% x
return(0);
/ n5 i; ^# a/ H}
  \6 q; @" \& F. f5 U</FONT>1 N/ s3 G& j- x6 L& |* _3 h

9 X/ {2 e8 K% O# B6 a, R/ s</P>
4 a  p( Q  n" D: A7 p<P><FONT color=#ff0000>函数名: assert </FONT>' t% Z& y  {% |" J/ Y& h
功 能: 测试一个条件并可能使程序终止 * l8 u) k. e! w  `+ [& }5 o
用 法: void assert(int test); * ?8 l9 \  r0 w5 x* s- I: f
程序例: ' A! x0 }' [+ e* d$ k
<FONT color=#0000ff>#include <ASSERT.H>
& h# ~& w( y  C, {3 g$ {#include <STDIO.H>. v2 p& N+ {$ [
#include <STDLIB.H></FONT></P>0 M. n, `1 A0 T% E9 z
<P><FONT color=#0000ff>struct ITEM {
: E( X# f! C1 h6 w, eint key; 7 f! @* l! ?- @: Y# j
int value;
0 g1 x/ e) d) j4 {+ k4 k}; </FONT></P>
: J. \" o7 w( i  Q* x8 H2 |& f<P><FONT color=#0000ff>/* add item to list, make sure list is not null */ 5 f& c2 {& n6 x3 \% |" G
void additem(struct ITEM *itemptr) {
0 _% }- M* n( f$ tassert(itemptr != NULL); 8 ^5 k! L3 v+ q. B" x& L" `
/* add item to list */ ! j$ ~$ c1 t* p4 h( l
} </FONT></P>
! k, S, D7 N4 l3 C* O( J/ D/ r/ C<P><FONT color=#0000ff>int main(void)
5 G8 P5 j0 @: c{ % ^  l8 f2 r; q* K; M) h* Y
additem(NULL);
, N  A9 g" x3 @- N' R( p. l* oreturn 0;
% [! j3 b' a1 `; ?$ s2 J. r+ D} 6 j5 k# M3 D& v- n/ |
</FONT>
  }7 {% H, g7 O5 b( X3 u, p8 L) d; J- N, z+ i$ }5 |/ N  r# f! K5 b
</P>
/ ]0 r2 ~& }9 x: g) h# H<P><FONT color=#ff0000>函数名: atan </FONT>* Q5 |( S, ~5 D+ i# a. }- b
功 能: 反正切函数
. k/ t# b) m& Z6 @: U1 ~- O用 法: double atan(double x);
- a. P4 E$ _5 q9 m+ w8 T  b4 x程序例: 5 y9 q& B2 ~& G5 {
<FONT color=#0000ff>#include <STDIO.H>
) j% o! w, a: O" [) x#include <MATH.H></FONT></P>+ A! G6 X+ I( ]. T; y7 s
<P><FONT color=#0000ff>int main(void)
* O4 C. R% i6 q5 @; y* i% R2 T{
5 t$ v, M* |7 udouble result;   }2 T1 B8 s7 [0 d4 L( p% o
double x = 0.5; </FONT></P>2 C* i, J4 Z- q, D* c6 a- o
<P><FONT color=#0000ff>result = atan(x);
  h' F# r* p) L+ z# r  oprintf("The arc tangent of %lf is %lf\n", x, result); 2 z1 P/ a- n! Y& R( b# F) l( H6 J3 y
return(0);
; l3 L. R  Q5 M0 b, H1 o} " Z* i6 n2 L" A+ O  W
</FONT>" P0 p6 I( z# ^" y3 g- Q# b( X
</P>/ r5 }( L5 ~6 C% a# w% e% U5 Y+ z
<P><FONT color=#ff0000>函数名: atan2 </FONT>
1 w: n& F( f; ~; q$ v功 能: 计算Y/X的反正切值 ( @2 T+ y5 @& P1 z: {
用 法: double atan2(double y, double x); 1 H# A! [# }8 F4 d1 W" d0 [8 U
程序例:
8 r0 N* z( J$ n# M: U9 i/ `<FONT color=#0000ff>#include <STDIO.H>
: T! u/ U' b0 l9 j( M- @/ N#include <MATH.H></FONT></P>
" Y5 |1 V2 X/ U$ H- o& j1 Z<P><FONT color=#0000ff>int main(void)
1 j! j) K) ]- v0 S. w( C8 }{ & ~. Q/ R- s7 r/ e. |- g( o) C" ~0 ~
double result; 1 c8 i$ }+ }, z" L8 |  z3 t
double x = 90.0, y = 45.0; </FONT></P>" l& T6 H4 p1 E' _% L; S6 j
<P><FONT color=#0000ff>result = atan2(y, x);
1 d$ a' |: e5 E' g* q. ?" aprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result); 6 X/ L% _, k/ }* d7 l
return 0;
2 x6 x* ~# p: P) g}
. t. D* U9 Q) i! C- G+ E8 P+ X9 b* s</FONT>4 k; b/ ?, Y( t; `9 S/ ~9 a
</P>
8 Z5 B2 `6 P. X3 F$ K" w<P><FONT color=#ff0000>函数名: atexit </FONT>
% A, A4 b7 t9 c' j功 能: 注册终止函数
0 D& k) }/ b+ J/ n  q8 |: t用 法: int atexit(atexit_t func);
2 v' T/ r  K2 W' [# [. s程序例: 8 Y/ T) V- s9 g) E
<FONT color=#0000ff>#include <STDIO.H>
2 d  _7 T' L! x! [#include <STDLIB.H></FONT></P>
& I1 L2 u# e+ ~, S, s* Z, E<P><FONT color=#0000ff>void exit_fn1(void) $ ~& Z  w/ _/ z' \, u
{
: V; }0 W! H+ c% @* Cprintf("Exit function #1 called\n"); ( Z4 }! ^* ~$ Z6 S+ Y: m  C
} </FONT></P>4 M$ W% G# j, b! z/ j7 p
<P><FONT color=#0000ff>void exit_fn2(void) & V. @" Y+ x$ _( j* T* d
{ : m7 U4 r  _) \, f) }+ Q
printf("Exit function #2 called\n");
* k  u7 ]& @2 Q/ r9 i} </FONT></P>
8 r6 y3 m, e- T<P><FONT color=#0000ff>int main(void) + F$ i3 K# T1 e$ k! _, y3 u
{ . t4 N4 O; W. i1 B
/* post exit function #1 */
: \* |3 u$ j, H* D; n" Vatexit(exit_fn1);
. F! Q: Q" K8 I; ]6 K/* post exit function #2 */ " P3 L- w" v+ \) B$ t* f1 |7 k
atexit(exit_fn2);
* f% @' }: ~- `0 i5 Kreturn 0;
# x* P- i0 @& V: ?, H& l6 F}
1 A+ g$ u: t1 F9 A% @! w</FONT>
* \" \+ @3 B' D# G) o- e, a
% W8 _' O0 Q' C4 t0 Y</P>, j9 W" Z. S& G0 Q$ S5 f" W4 ?' d
<P><FONT color=#ff0000>函数名: atof </FONT>+ w* K$ H" M) d' L. ?, F/ q8 z. m
功 能: 把字符串转换成浮点数
) ?, c* P' f) D: h; x5 Q% e用 法: double atof(const char *nptr); 5 h! E' F# \5 _, o* a% ^1 h
程序例: $ E8 v, A( P8 C& L- O
<FONT color=#0000ff>#include <STDLIB.H>
3 r6 P8 F" f1 {#include <STDIO.H></FONT></P>
1 i8 e/ C0 h" _7 a" M<P><FONT color=#0000ff>int main(void)
# h& f' a+ e, Q( d+ B/ |/ w{ ; R) Y; p4 q  {, O8 ~- F) |
float f;
9 T& o- O; O" B7 Y  mchar *str = "12345.67"; </FONT></P>
9 m9 [2 _- {( L1 g<P><FONT color=#0000ff>f = atof(str); 3 H% ?* M/ V3 q
printf("string = %s float = %f\n", str, f); 1 z$ [8 ^' i# r8 x8 @
return 0; - y5 B0 P9 O, R7 i+ L
} ) z; E$ y( ?/ P9 E
</FONT>7 s# i  j3 {4 Q9 c% Z
</P>
! @9 Q+ u& T) q% c' p, J<P><FONT color=#ff0000>函数名: atoi </FONT>
& l' t& R5 \- F, j9 B4 t功 能: 把字符串转换成长整型数
  ~, o% e! D3 V% K, Q7 v' f6 ^用 法: int atoi(const char *nptr);
  C" f+ P( u- h: s程序例:
, F4 P' r3 Y0 u' \1 P2 n8 ]6 U<FONT color=#0000ff>#include <STDLIB.H>, X- a; A. G* w# \/ A
#include <STDIO.H></FONT></P>+ G4 Y3 k3 ^$ t! {8 O4 `
<P><FONT color=#0000ff>int main(void) 6 [, E, _; R+ {( C/ O
{
5 u# ?2 t: K# C/ I1 Yint n; : }4 j1 Z# q7 A0 ^* I
char *str = "12345.67"; </FONT></P>8 J8 a: P/ ?5 c0 v! K# h
<P><FONT color=#0000ff>n = atoi(str);
+ }9 F* g  q: c7 z2 p" T, w% {printf("string = %s integer = %d\n", str, n);
  o) d0 p9 X+ g0 ^# Sreturn 0; 3 B) H$ V7 K* _' ?2 U
}
8 D6 o3 S9 i3 @4 y</FONT>! B/ H0 ?' g9 @: S- G5 D' ^1 d
</P>6 P8 R- z8 M% l: y
<P><FONT color=#ff0000>函数名: atol </FONT>
3 Q3 x' J4 l: f8 ^功 能: 把字符串转换成长整型数
+ Q) S3 Q4 ?$ x2 a, s1 i用 法: long atol(const char *nptr);
% K' i$ C! Q! o8 W7 {$ [' o6 k程序例: </P>* J/ L4 P; s# u# H2 j' T
<P><FONT color=#0000ff>#include <STDLIB.H>
& ~7 T9 P/ l2 z& p! u. J  C#include <STDIO.H></FONT></P>  x3 [5 w# F+ z+ J/ e+ ^- B' a2 ?
<P><FONT color=#0000ff>int main(void) 2 G- T  {. E) R, R* n; j
{
( v1 \$ v; i" o. Tlong l; 7 U  V$ q3 M4 M4 a: h
char *str = "98765432"; </FONT></P>
' |5 F; [. m" M, f' P# z3 _<P><FONT color=#0000ff>l = atol(lstr);
4 e# v1 B: h6 @4 U+ b% G- A, Nprintf("string = %s integer = %ld\n", str, l); 5 A* v2 ^. n6 Y: E8 o
return(0); / T0 ]- v0 T# ?5 [3 I1 P% ^
}</FONT></P>
zan
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