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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |倒序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
: [& ~1 E0 I4 s) C% t' V) D<><FONT color=#ff0000>函数名: abort </FONT>& H6 A) [; p& j  t/ B) R
功 能: 异常终止一个进程 7 q0 x9 O1 }6 N0 l
用 法: void abort(void);
; Z1 x* \4 Q2 p( S$ v程序例:
3 E0 N9 ~; i8 g9 @" S<FONT color=#0000ff>#include <STDIO.H>
& K9 @5 C; |7 V$ Z1 ]+ e#include <STDLIB.H></FONT></P>
7 R4 R- q' U; v) I1 _<><FONT color=#0000ff>int main(void) ) f/ b* u7 T% l% R/ l9 |+ K
{
' b9 t$ e9 @% Q. a& ~/ L$ mprintf("Calling abort()\n");
+ O& n, u4 a2 E9 d# S4 s0 t7 _abort();   v! s- X7 P! V, q! L
return 0; /* This is never reached */ 1 e( B+ o9 k" U' g( ?$ z7 j$ ], \
} ) O4 M& I" ?% X) `# o
</FONT>5 I  I" ^+ W; H- c; a
</P>
) m! ]3 y6 E6 R: I3 k! H. k<><FONT color=#ff0000>函数名: abs </FONT>
8 ^- p: _% Q. A+ F$ H功 能: 求整数的绝对值
& y3 N* X7 y( l# a5 f用 法: int abs(int i); ' f4 M) y$ X# u1 F
程序例: $ r1 O5 v2 f6 h: R$ t, @- c
<FONT color=#0000ff>#include <STDIO.H>
; A) n7 ?; T9 @: X8 \7 I#include <MATH.H></FONT></P>. M$ v" E$ S; D3 W; X8 Q
<><FONT color=#0000ff>int main(void)
7 n& e# @1 V' J' p. M# W{
, b- g2 }' x7 d* \' Uint number = -1234; </FONT></P>* Z9 R! h+ [7 i
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); + {+ H# }& v4 E8 e& k: O+ h
return 0;
/ Y. z  y- V- H8 r3 g}
) A) p5 N% m6 Y) R2 Q/ A</FONT>
" K' f" q* V1 K1 l  i7 h</P>
/ v8 ?' r1 d$ @* L+ ?<><FONT color=#ff0000>函数名: absread, abswirte </FONT>
4 `" P4 g8 V! j" y8 V功 能: 绝对磁盘扇区读、写数据
# \/ X1 s$ z* L用 法: int absread(int drive, int nsects, int sectno, void *buffer); ; i2 W- P6 L8 z$ [  I
int abswrite(int drive, int nsects, in tsectno, void *buffer); ( p9 j6 H6 k0 T# x+ D  i- d
程序例:
! w. w4 x. s+ s* ~2 U2 q  f# D<FONT color=#0000ff>/* absread example */ </FONT></P>
1 P; W+ f- d2 Q2 h6 k+ X<><FONT color=#0000ff>#include <STDIO.H>1 ~- `# l( |  \! g2 c
#include <CONIO.H>$ f4 C/ V) a  \/ \4 j8 _
#include <ROCESS.H>+ M3 A8 [, z/ s; P4 ~' }5 o$ `
#include <DOS.H></FONT></P>7 ^9 B, O) ]+ V; e" i$ W( {% N
<><FONT color=#0000ff>int main(void)
$ ?: H, z8 a$ b- W, l{ 6 M4 o0 R  q' s% u
int i, strt, ch_out, sector; 0 R9 u$ \* R9 V7 ~) a# H
char buf[512]; </FONT></P>
' b% I* n2 E9 C9 b<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
" I" ]8 o0 E: p9 S0 T( D% @getch(); 4 u5 z0 l( W/ o9 V0 t1 j! \! [* r6 ~
sector = 0;
; K% |5 V: \+ M; \/ [) @if (absread(0, 1, sector, &amp;buf) != 0) % H: q7 x6 {) e. ?6 b! m
{
) e7 u- [4 U0 Z: ]  f8 D: Sperror("Disk problem");
; `/ z5 g, W* v+ Qexit(1);
5 P: n2 _: ?- T. x1 ?4 q* Z} - H) b3 y0 ]/ j( y5 E
printf("Read OK\n"); 8 v$ j8 J% U' H/ e+ u# Y+ m% u3 ~
strt = 3;   @1 z' G) S2 x* D0 H
for (i=0; i&lt;80; i++)
  j1 J" R7 S$ x" j& w9 |6 T3 \8 ]{ $ }# W+ |) g" D/ g# j( D
ch_out = buf[strt+i]; ! O4 H% y' A2 V
putchar(ch_out); 1 B& s2 q' ^+ R3 S3 C* @, k: @
} ! U# B* u  Z5 t) l9 g9 e/ q3 D1 m" N, m
printf("\n");
6 p& A, A$ O$ D: N% Greturn(0); 3 t. \! s* Z* m
} $ ?: t* g" `2 ^# f9 f2 j
</FONT>  o- M# t$ y2 p# e" _+ F
, \' \* Z3 c* i6 U' h4 \
</P>! t2 G( i3 ~+ G' i' L* O9 y9 v
<><FONT color=#ff0000>函数名: access </FONT>+ r9 k) K4 ^$ x
功 能: 确定文件的访问权限 + O' I0 U8 s" R5 {" |9 E) n
用 法: int access(const char *filename, int amode); : a" c8 m- n9 j6 k/ T$ x
程序例:
0 c! d* F- E/ R/ m  V4 m1 ]<FONT color=#0000ff>#include <STDIO.H>
1 ]* W) C8 f  L  i  Y' }5 T#include <IO.H></FONT></P>5 E5 y( U& v* L: w
<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
& z$ X5 _0 n! [# R- G+ `<><FONT color=#0000ff>int main(void) 1 W& N6 f2 o- e( G1 _' p( S5 b
{
! f! d! ?4 F1 b, Vprintf("Does NOTEXIST.FIL exist: %s\n",
1 u  I( w* B- {6 T. Kfile_exists("NOTEXISTS.FIL") ? "YES" : "NO"); $ R! S* ~9 B3 z2 b$ |# P
return 0;
% i; o8 Y2 K6 q* n2 x# _) U} </FONT></P>8 c- F. i, `  }1 D
<><FONT color=#0000ff>int file_exists(char *filename)
5 Y2 j1 ^+ V. c/ A% r7 _6 c* V{
0 k( k5 `. V1 v1 mreturn (access(filename, 0) == 0);
+ M; }  F5 K6 }$ P6 V' i5 z: I} # Z% y, j4 G, `  A3 t9 V+ v8 {
</FONT></P>% ?% h  ?9 G$ L0 T/ y0 ?
<><FONT color=#ff0000>函数名: acos </FONT>8 C, x- [' q6 u6 z) D: K( O( d
功 能: 反余弦函数 " x3 K- p0 V, b6 _
用 法: double acos(double x); & r  A. ], m% e
程序例:
  ~0 J* r3 n/ V<FONT color=#0000ff>#include <STDIO.H>
; V/ }" A. c6 P4 _& t( C; t#include <MATH.H></FONT></P>  S0 j# W8 f5 q2 t
<><FONT color=#0000ff>int main(void)
5 Y: d  i" O% C{
# @' [, X: f7 a) {$ }- ^  kdouble result;
/ X$ r6 r: `# S5 z& ldouble x = 0.5; </FONT></P>3 D' C7 D4 \0 `  M$ a6 }
<><FONT color=#0000ff>result = acos(x);
0 z0 H0 e0 \) p9 Gprintf("The arc cosine of %lf is %lf\n", x, result);
) b! c: B9 q" n& J9 z( y: h  X+ e9 wreturn 0;
& l# p5 s! D' F: u} </FONT>
6 }; a/ b' F% s
6 v9 I+ ]2 H1 l6 s0 n, X</P>1 A1 F, O) k, R
<><FONT color=#ff0000>函数名: allocmem </FONT>
. r6 ^" L* @  }: k; ~1 c8 e功 能: 分配DOS存储段
4 z: S2 L! y1 L8 E0 K4 L. n用 法: int allocmem(unsigned size, unsigned *seg);
* W' D. y4 ]7 T" Q# d2 o$ V程序例: 7 S' q5 ?- i7 @5 |* ?" ^
<FONT color=#0000ff>#include <DOS.H>
% W3 b" `7 K  {3 _5 Y#include <ALLOC.H>/ h* Z0 F, ^6 s  L; Y, |1 e
#include <STDIO.H></FONT></P>+ B% j, B. k2 o: B' e( k8 a
<><FONT color=#0000ff>int main(void)
( V  Q- a+ g" v2 F5 ?{
6 c8 Z, S8 U8 O! Punsigned int size, segp;
, [  d8 y; k8 b/ `5 t2 e% }0 D' @int stat; </FONT></P>
; v# K* O) F1 r& B. @+ o" q3 T% T2 |' ?<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
1 g. A4 G- n5 }5 Wstat = allocmem(size, &amp;segp);
6 i5 v" q  I3 gif (stat == -1)
7 Y/ D* Z1 J, G4 oprintf("Allocated memory at segment: %x\n", segp);
* j$ {+ b$ w( n9 ]* G7 aelse - w) u: K  B% A' y, h
printf("Failed: maximum number of paragraphs available is %u\n",
& [/ r/ c2 y* l) \* p0 U$ I: Q0 r: pstat); </FONT></P>
. m9 M% c- i- W0 C8 ?<><FONT color=#0000ff>return 0; ' N5 K' s! ?, S, v, Q
} </FONT>, ?% [7 J9 s; A  \! g
* l, G3 K" I3 T+ Z2 Z4 S8 @
</P>8 |. d( U/ }2 c/ q' f1 A! A- r
<><FONT color=#ff0000>函数名: arc</FONT> $ a2 B, o0 u# Q  A2 w% Y5 n" U$ R3 ]: ^
功 能: 画一弧线 1 ?4 k* i+ l0 C) i$ o) v3 @9 }
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
2 \$ @" b& Y  N6 w" |程序例: 6 u3 z+ p% `# F3 z# \
<FONT color=#0000ff>#include <GRAPHICS.H>9 A; R9 v/ {  f% s( d( `1 p
#include <STDLIB.H>
! J5 l; |* T% O#include <STDIO.H>0 K' x. \; a' ~+ ]; R. ]
#include <CONIO.H></FONT></P>7 p! c8 t6 T# [
<><FONT color=#0000ff>int main(void) 1 c- U6 D/ l& f! B; Z7 i
{ 5 y4 @* z& y6 a7 {) f
/* request auto detection */ 6 ?" d' }& m& a
int gdriver = DETECT, gmode, errorcode; ! g- \, Q9 g* a: ?+ b+ N7 [3 h
int midx, midy;
" I, W; w. E/ {int stangle = 45, endangle = 135;
9 p4 x# r1 F9 ~/ w3 }int radius = 100; </FONT></P>( }1 s: U9 z; Z3 B
<><FONT color=#0000ff>/* initialize graphics and local variables */ / Z! M! c% U8 }3 l. Z1 g; V. C
initgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>
& M/ i2 }' m; Y6 `& ]. s  m8 j0 s) e<><FONT color=#0000ff>/* read result of initialization */ 2 A- w7 v8 K+ A' C6 T
errorcode = graphresult(); /* an error occurred */
! y; c6 ~' C1 I  z  D4 xif (errorcode != grOk) 0 r1 |6 w6 y# v5 [2 m4 P- M7 M3 K
{ 4 d1 J4 c3 G, Q: p
printf("Graphics error: %s\n", grapherrormsg(errorcode)); 1 a8 h0 F  g7 D* C& S. `+ P- C
printf("ress any key to halt:"); 2 t3 ?' W, y7 ]$ V) t+ M
getch(); </FONT></P>
2 H/ D  J, l% y" J<><FONT color=#0000ff>exit(1); /* terminate with an error code */
% i  t* }& C' a( _$ S. J: S} </FONT></P>( n' t" _4 C! {* n* G9 d
<><FONT color=#0000ff>midx = getmaxx() / 2;
! g9 B" \; A7 b1 pmidy = getmaxy() / 2;
: T" P- P3 X. z/ A' r6 dsetcolor(getmaxcolor()); </FONT></P>
4 J& r2 P7 L1 i" d2 a9 ]<><FONT color=#0000ff>/* draw arc */ - K! d$ {) R3 }2 t
arc(midx, midy, stangle, endangle, radius); </FONT></P>1 Z0 J7 D" P* q1 W; J# F
<P><FONT color=#0000ff>/* clean up */ $ m0 ^  J! \* u. J; u8 w
getch();
4 e3 D" A4 }- h4 k3 A5 Mclosegraph(); 6 R1 s# i  X* s& ]
return 0;
' E2 A% R! s/ g}
. a$ Q7 P* H, [3 r+ h5 e</FONT>: L' g* t$ a# z! F& ]! s
</P>& ^3 V; Y& ]  Z' s8 i5 f4 `3 A! [- n. {
<P><FONT color=#ff0000>函数名: asctime </FONT>
8 {$ L: m# Q, n, `  v1 T功 能: 转换日期和时间为ASCII码 ) z+ u; i; p& _4 n4 K
用 法: char *asctime(const struct tm *tblock);
, ?, H$ c' _* E程序例:
1 f$ _- N/ S# [# t$ A% y% b6 C5 l1 {<FONT color=#0000ff>#include <STDIO.H># s( B- I, y7 s
#include <STRING.H>
8 F5 E) W- H+ u2 N' `4 d#include <TIME.H></FONT></P>, f* o2 l* [+ \1 X! K! E; W# ?
<P><FONT color=#0000ff>int main(void)
1 J3 N  m4 G- q& O" C& p{ ! @$ F+ ~( @0 t) e* `
struct tm t; * J: U- i0 _) s9 z
char str[80]; </FONT></P>- \4 A. j. ~5 w  M
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
4 }) y9 ^8 E' f<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
+ p* B0 I0 ?( M6 at.tm_min = 30; /* Minutes */
# }# {6 B" T3 P1 J1 e5 Jt.tm_hour = 9; /* Hour */ $ |( |7 t- l( I- b: d  T7 r0 P
t.tm_mday = 22; /* Day of the Month */
* [, G3 c" {- I6 j+ e8 Ut.tm_mon = 11; /* Month */
8 U" {; `4 e1 X, h& l) M1 }t.tm_year = 56; /* Year - does not include century */
! n4 l( e! M! J; ot.tm_wday = 4; /* Day of the week */
) V8 {+ N! z  O' O4 C+ A) U& rt.tm_yday = 0; /* Does not show in asctime */
' A- e' M  o, ~( r$ L5 l+ Pt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
. F0 Q. |4 t* c0 D# o2 u% _% K5 P<P><FONT color=#0000ff>/* converts structure to null terminated
( r2 Y* f% e) [; Pstring */ </FONT></P>
) x4 d; F# `* _+ |<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t));
/ Z. `# N' }( {printf("%s\n", str); </FONT></P>5 Q- u  b: c0 |2 x# K- X9 f. Q
<P><FONT color=#0000ff>return 0; / z' L# `7 ]( U/ A9 u' }
} + C9 Q4 z! P$ @. P2 s
6 x/ _. A5 H: J
</FONT>
) ]. C0 Y. E  a9 F$ K" z</P>0 h) m' V( c5 B+ D
<P><FONT color=#ff0000>函数名: asin </FONT>% X& C; q5 p  P6 C8 y0 r
功 能: 反正弦函数
6 a% l$ S: ^/ L4 g用 法: double asin(double x);
% ?8 U4 a9 m9 D" N程序例:
  O. k* @& ^* o; d% W& D) P<FONT color=#0000ff>#include <STDIO.H>5 @( D* V" q/ {& `7 ^
#include <MATH.H></FONT></P>
! \7 x* w% v4 M, [) z% D# P<P><FONT color=#0000ff>int main(void) 3 ]! q  f+ A! R% Y0 G
{
8 j. p6 ~2 Q' L9 ^& Ydouble result; : Q" u- n1 L0 m
double x = 0.5; </FONT></P>
  W' {" Y, n( M& B: Z<P><FONT color=#0000ff>result = asin(x); . a1 w9 l1 `6 l: g( N& }1 V$ z; b
printf("The arc sin of %lf is %lf\n", x, result);
3 x; z$ ?' o* g; C+ a3 V; q0 i* R& Lreturn(0); " k* a1 \5 Z, J% \+ H* e4 W0 A
}   S7 T" _) f7 m; `9 h) q
</FONT>2 Q) w  m9 f; Z

: o; p5 o; L5 p. y; v</P># K6 n4 p7 [6 H" \, T5 |. h
<P><FONT color=#ff0000>函数名: assert </FONT>
8 t) V9 @3 X/ V' C4 a5 u1 L; E功 能: 测试一个条件并可能使程序终止
4 F# `( G  k, r/ v用 法: void assert(int test);
- W1 {% C) ]) v! t/ D, ]程序例: & Q8 L6 W  N9 U& M" L. l/ F' `
<FONT color=#0000ff>#include <ASSERT.H>
2 C4 y& ^4 {) s' ^9 {1 X; t#include <STDIO.H>& x- h9 d* m! h
#include <STDLIB.H></FONT></P>6 {$ P$ e# h0 w8 z1 @
<P><FONT color=#0000ff>struct ITEM {
* A! W! y$ N) a: ?* ~2 W4 ~' Uint key; 4 i3 S' {0 S& H1 d" ?$ `
int value; 0 H, f: b: a$ Z' ^3 S
}; </FONT></P>
8 x% v7 c4 k7 g+ |% ^& J<P><FONT color=#0000ff>/* add item to list, make sure list is not null */ ( V6 c) s5 e: o! L
void additem(struct ITEM *itemptr) {
$ Z+ B8 `; x( U0 Massert(itemptr != NULL);
, V% q& h! z( r/* add item to list */
! b9 g& N  a  O3 ]0 b} </FONT></P>5 c; C. b  r  b$ B$ S" R( U- B
<P><FONT color=#0000ff>int main(void)
* f$ T% J2 k* L& W{ 7 y& j3 a& ]/ g
additem(NULL); $ y, h1 f$ ]% |0 C
return 0; 8 c1 D' n4 d) H, ?9 j
} ( g7 n9 y% o) V2 @# Z- F. m% B  k
</FONT>
+ |2 a; @& ?/ n( U# v+ r$ L
2 h2 i5 Y7 N2 ]4 Y. O& D</P>
! ?4 t' G( I6 B- w" C<P><FONT color=#ff0000>函数名: atan </FONT>
9 r& O$ w. Q! G功 能: 反正切函数
, R. u) H: B1 D( J# n2 Q! Z4 U用 法: double atan(double x);
; n7 D" X0 l8 c& k' g程序例: 3 Q% x; c; U' D4 ~8 V( H% V# a- }
<FONT color=#0000ff>#include <STDIO.H>- n3 p& G- U- |  Y
#include <MATH.H></FONT></P>
; C( c0 N+ O; y: i<P><FONT color=#0000ff>int main(void) 7 d3 ?  x8 H% U1 k$ j+ k, k
{
  j/ X5 B! t8 m- W0 idouble result;
0 Z6 ^$ H4 U, L8 w) xdouble x = 0.5; </FONT></P>
8 d5 H/ o9 z# C  _/ u<P><FONT color=#0000ff>result = atan(x); ( b' y) X" y* f' `
printf("The arc tangent of %lf is %lf\n", x, result);
9 {$ K: @7 C3 t; [/ mreturn(0);
/ b9 [2 d# x. b+ E! H  F}
# `9 h9 p( Z4 ^5 G9 r! T</FONT>4 ]3 I6 J; V0 }  S  L. p/ s
</P>' Y2 N' L/ a9 z- C& k
<P><FONT color=#ff0000>函数名: atan2 </FONT>
$ c  q) E' {! S- K2 X8 |/ b功 能: 计算Y/X的反正切值 - g: [/ G) j1 [6 R; @) `
用 法: double atan2(double y, double x);
+ ]+ f* u6 o) L5 G程序例:
( S0 [% h* X- {6 T7 M2 @<FONT color=#0000ff>#include <STDIO.H>- k! f! d3 ]. [& l
#include <MATH.H></FONT></P>
) Q1 V0 f& b* Q( @: ^* y1 v<P><FONT color=#0000ff>int main(void)
6 w3 H4 M) U; Y9 X; |{
: |5 d; a) ?' s$ D& s( x/ Ydouble result; ; i2 g; j7 T1 V$ d' F
double x = 90.0, y = 45.0; </FONT></P>
1 w0 V* f5 B) ^! y# |* e<P><FONT color=#0000ff>result = atan2(y, x); % I; Y/ W8 R! E5 H. L
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
% v0 c! f1 [% X' Z5 P2 p% Oreturn 0; . |: \8 s6 p& F  X) a
}
7 R0 W! ^: _9 ^6 R' i. \$ ?; l</FONT>
) [6 J6 p# S0 j! C1 I5 v</P>
& c- q4 n/ r" z" F<P><FONT color=#ff0000>函数名: atexit </FONT>+ {% e0 }' p) J' ]4 g. E
功 能: 注册终止函数
7 J; ?7 u/ X1 V0 |, h: a用 法: int atexit(atexit_t func); 5 v- h. m2 ~7 z  E/ |
程序例:
3 O" w' j& Q4 `$ S<FONT color=#0000ff>#include <STDIO.H>
8 @1 l# E- U, V7 j#include <STDLIB.H></FONT></P>6 e9 z* z6 v& Z" |9 z% _4 f  m6 E* X
<P><FONT color=#0000ff>void exit_fn1(void) ) o1 t- E% d+ ^4 |& {
{
+ z+ M4 R: B2 D) u* qprintf("Exit function #1 called\n"); ; e  m& u1 X5 ?' D6 P
} </FONT></P>0 p3 I) o& R0 o7 h/ T
<P><FONT color=#0000ff>void exit_fn2(void) / D8 D. z) K6 v6 C, Y1 |  b3 E
{
0 T. C: W4 P) V) K+ @% v0 lprintf("Exit function #2 called\n");
8 [9 I3 P0 }' H, B} </FONT></P>
- d: l% K7 h+ K<P><FONT color=#0000ff>int main(void) : M( s' T9 N+ K; F
{
% C; Q0 j* m, L2 f8 O/* post exit function #1 */
. l. J# `: L: G, U1 ~0 F! y3 yatexit(exit_fn1); 4 |3 {2 j' T) C7 Y( @1 r% ^+ g
/* post exit function #2 */ . `5 z/ W" r! d2 s6 n9 D
atexit(exit_fn2);
8 C1 P  j& r! i# E0 E, Z% Oreturn 0;
' N6 i+ V) t) E9 J}
' e( v$ t% Q) _0 g: [9 i</FONT>, Q2 S' V7 P1 \. F

( t. M( F0 d0 b1 m, t! _</P>
7 Y0 h2 `3 H4 b% S$ o<P><FONT color=#ff0000>函数名: atof </FONT>; Q" X: t3 g. r2 _' C
功 能: 把字符串转换成浮点数
7 O" K2 p: p6 E) f) R( c2 n) A用 法: double atof(const char *nptr); ' z( w& X8 U4 {
程序例: 6 p6 t  p3 g' B2 d+ R0 }
<FONT color=#0000ff>#include <STDLIB.H>
' g9 M$ c5 J; \+ a$ h9 X#include <STDIO.H></FONT></P>
/ f7 z4 N' g- D7 @- m3 M7 F<P><FONT color=#0000ff>int main(void)
' M4 B8 `+ |9 d% r3 ?3 B{
6 Y8 Y$ P2 \9 Ifloat f; & \! t* Y/ R3 e7 U
char *str = "12345.67"; </FONT></P>
& ?+ H% u. h+ V$ Q$ `# F<P><FONT color=#0000ff>f = atof(str); ! h2 F1 a/ g' k
printf("string = %s float = %f\n", str, f); # m% b+ c+ ]8 ?
return 0; * x; G. b2 U) B- ~
} + u. T8 G9 z0 U) o% ]* A* X% k
</FONT>
8 ]3 O) d4 s6 a1 F1 A/ y1 }</P># P1 x, C4 G) P4 G
<P><FONT color=#ff0000>函数名: atoi </FONT>
" v7 ~. W) v2 E4 P" t* o6 {功 能: 把字符串转换成长整型数 % I9 o: Q# r/ z
用 法: int atoi(const char *nptr); 6 A8 V* k/ v; t; Y! x. s0 u
程序例:
3 b; z8 Y; c( {9 }7 K<FONT color=#0000ff>#include <STDLIB.H>
" J) P  k, B  b" C4 o$ C#include <STDIO.H></FONT></P>
9 Q/ e- H" V5 y2 F<P><FONT color=#0000ff>int main(void)
& Z) A# y/ W9 ?* E) q' z: l{ 4 g: s2 \( t6 u3 B: C
int n; ) g1 S3 T0 c3 N& l( E- ~( ?
char *str = "12345.67"; </FONT></P>
# \8 Y. O6 N# D2 I1 |2 Z+ D<P><FONT color=#0000ff>n = atoi(str); - c- y& {" _  k8 X5 Y$ K
printf("string = %s integer = %d\n", str, n);
- {2 t/ Y1 `, I3 Y8 o5 m! ~0 Ireturn 0; 9 S3 E4 u* L+ S% q+ `, I
}
; d; P6 q% h" B! _& p( C9 z</FONT>
* u; S2 d, {9 [. j. h</P>% t7 K- ?9 `  v! v- G4 d
<P><FONT color=#ff0000>函数名: atol </FONT>
$ u8 }! o6 s) k' V* \- U, _# H! _功 能: 把字符串转换成长整型数 / S0 s3 s, }" @4 E4 O. C
用 法: long atol(const char *nptr);
" y$ q0 D3 L1 s/ \; [( p% Z/ P程序例: </P>. r$ ~0 w; ^) O8 S( j* [: v
<P><FONT color=#0000ff>#include <STDLIB.H>
, B( N5 J5 j% |#include <STDIO.H></FONT></P>' Z8 A# l+ [3 k2 G1 _
<P><FONT color=#0000ff>int main(void)
: q# W6 K' u0 ]0 c0 `( U{
" O9 U9 S7 a+ H1 v( Clong l;
4 H. k# D! T  W6 f7 L+ x$ kchar *str = "98765432"; </FONT></P>
8 \; {3 J' }& R9 y3 \<P><FONT color=#0000ff>l = atol(lstr); 2 y/ [' k3 E" c$ N8 v0 i
printf("string = %s integer = %ld\n", str, l);
- v/ R) n1 `' d; Y9 Freturn(0);
) u, L% I4 {, b1 W7 l" c}</FONT></P>
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