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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>; V$ M( v/ G. c q/ Z* u. X
< ><FONT color=#ff0000>函数名: abort </FONT>
/ X: Q6 j2 d/ {* x, u$ z6 M. P功 能: 异常终止一个进程
% @: n/ a9 ?1 z- j. _用 法: void abort(void); 1 ~6 ]9 f) m9 x! z/ s L
程序例: , i3 m$ E' b: B) m t. [5 i
<FONT color=#0000ff>#include <STDIO.H>
( m- l% y. r4 }- b9 ]5 r#include <STDLIB.H></FONT></P>
% W$ R/ l1 W* q, Z1 l6 _, W< ><FONT color=#0000ff>int main(void)
8 u( {* z0 A6 W2 i{ ' J% P8 g( r" s+ ]
printf("Calling abort()\n"); 6 n2 m( b: ]; X; Z. q
abort();
& G4 e2 C0 I, Kreturn 0; /* This is never reached */ 5 }3 ^' q* k+ s* M+ a' @/ U
} 0 c* G3 a( x6 x+ H# E
</FONT>
! t$ [( N5 h" w, z3 F</P> T, P) ?- h0 V0 |2 d
< ><FONT color=#ff0000>函数名: abs </FONT>- t8 X1 J: U: [8 t, K' T
功 能: 求整数的绝对值 8 @1 W! ^6 t: N( R# q
用 法: int abs(int i); % o5 t* v& r) p2 y, ^/ u5 z
程序例: ' o0 D3 }# A0 R0 S2 }
<FONT color=#0000ff>#include <STDIO.H>
% ^& s8 E7 l e/ B: F& y( n' G#include <MATH.H></FONT></P>
/ E+ `) n3 L3 I% O2 w4 E6 R< ><FONT color=#0000ff>int main(void)
: q3 G3 V( w8 Y( _$ P" I* W& Q{
3 |6 P l) x& W# |! ?int number = -1234; </FONT></P>
R% ^% V9 ?6 p* O" t' F `" ]< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
- {1 G3 ^' C3 V( Q. greturn 0;
, P# o, {% C5 D: B S' p4 M}
4 V- \: p# _' x& i2 n</FONT>1 F# n+ F& ^% `5 C3 |, h: ?
</P>* b3 a; P2 \- U2 h
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>
, c8 @9 h' ?3 j* r# K功 能: 绝对磁盘扇区读、写数据
; [; h& c1 p7 Q- s$ ^; n用 法: int absread(int drive, int nsects, int sectno, void *buffer); 5 U* U3 {& A' f
int abswrite(int drive, int nsects, in tsectno, void *buffer); / R6 f+ G, f4 k) B I' u, L5 ]
程序例: ( F6 J) p/ K6 |
<FONT color=#0000ff>/* absread example */ </FONT></P>
4 R* @5 \! B& K* c< ><FONT color=#0000ff>#include <STDIO.H>
w+ S! s/ _1 F. p {#include <CONIO.H>7 N h0 f. ^3 Y4 X- N
#include < ROCESS.H>7 u" Z, W: ~2 a3 j' P0 s
#include <DOS.H></FONT></P>3 u) q( s! D! q3 L7 Y: i- w2 g
< ><FONT color=#0000ff>int main(void)
1 I( U& N7 \* U{
) O) }0 w! @) l) o2 w8 C; ]int i, strt, ch_out, sector; $ s+ K, d! ~, m
char buf[512]; </FONT></P>) f# g% U e* Y d8 u
< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
: b2 ~9 N- J3 W8 E' ngetch(); , @7 ^6 x+ M# \& `' W7 w1 c/ |
sector = 0;
" o5 c- p' B7 V2 \if (absread(0, 1, sector, &buf) != 0) - e, T' N6 r' C( H) y
{
3 V* V1 m# U2 }' c1 l! k, k; \perror("Disk problem");
6 M0 R# m, L( k) _% L3 qexit(1);
0 h v4 \2 s/ Z% `* M2 K( [1 u8 x}
5 d& ? M$ ]" U7 h( jprintf("Read OK\n"); 1 g6 o D3 T4 s* j& _2 k: O; m5 h
strt = 3; 2 i' k5 E6 X+ r1 R
for (i=0; i<80; i++)
% p4 a5 p3 ~, ?+ m{
% B9 N/ z2 k1 O4 [8 R" b% {ch_out = buf[strt+i];
0 U( P2 n1 W% c1 s% Cputchar(ch_out); & |( q4 z5 U) y* u4 x' k: V& x6 Z
} & e; f6 s# Y# I+ g: ^; o/ z/ k
printf("\n"); 0 Z, h5 \) p+ v. X# U8 h \
return(0);
8 |; E# A* s' L- f2 z5 ^} 6 \; F8 D* X6 u9 ?' p
</FONT>& ?- v+ [1 W6 Y( M& k
* Q3 p( d# z5 o/ |! s" `
</P>
8 i7 E# B4 e, n< ><FONT color=#ff0000>函数名: access </FONT>4 Y% p, s! f, r, T
功 能: 确定文件的访问权限 * C' r! Q$ q) j7 G& x. E0 a
用 法: int access(const char *filename, int amode); i! p, U. A2 D5 `. _
程序例:
) @ {) G6 H5 i3 m5 {( A" x<FONT color=#0000ff>#include <STDIO.H>
, e5 F7 Y& Y3 t# K: ?* @#include <IO.H></FONT></P>
. {& G6 `. ^$ j2 k. @< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>( d$ D5 h1 n! Y1 F+ ]# N7 T0 }# n+ N
< ><FONT color=#0000ff>int main(void) 7 e4 F2 D% _( I' v: W! O3 l; [
{
' W+ P* y Y" ~9 p# E' ~8 `; K8 S8 dprintf("Does NOTEXIST.FIL exist: %s\n",
& |/ `7 s# E4 H- k, Z# kfile_exists("NOTEXISTS.FIL") ? "YES" : "NO"); $ a; D5 S2 v5 ?5 H/ v
return 0;
. @7 c9 j; N, \9 n" m: L- Z2 Y} </FONT></P>6 }( v3 \6 d" H! E. R! e3 H; X
< ><FONT color=#0000ff>int file_exists(char *filename)
& j6 B% [" i0 K$ k! P. m. t{
7 D2 U+ ?2 ~2 d: s; U4 vreturn (access(filename, 0) == 0);
\/ x# I: Y& M+ y' k6 h/ M}
5 R! R4 W9 b8 E( }1 v</FONT></P>) o1 ^) J" a7 C# o2 j
< ><FONT color=#ff0000>函数名: acos </FONT>
$ g/ k% n' c2 i$ m; L* r6 o功 能: 反余弦函数 + z2 a. b- \: r9 H% r% N, O8 _
用 法: double acos(double x); 8 e k- b Y) r
程序例:
: [+ M$ V0 O1 v( i<FONT color=#0000ff>#include <STDIO.H>1 {' `5 ~7 E9 e
#include <MATH.H></FONT></P>' B5 h5 _5 k+ n1 o# D0 T
< ><FONT color=#0000ff>int main(void) - K; w# R' n& x' ~( M1 ~. _
{ 5 L- p# [2 C0 m/ d$ E; ~, O- R% u, e5 T
double result; 1 X+ @5 s2 w" @6 T+ w
double x = 0.5; </FONT></P>& Z7 B0 }8 `( J+ {
< ><FONT color=#0000ff>result = acos(x);
+ Y7 k7 i' b& P0 w3 g3 q+ \printf("The arc cosine of %lf is %lf\n", x, result);
' v; w/ U! U p9 |% qreturn 0;
+ t1 x# I0 U4 X5 D+ G! U} </FONT>8 Y3 M5 Q. R- b) o- ]
8 ~/ d' t8 G! _+ }+ U; z</P>
; t& w9 }/ w9 j1 U" [< ><FONT color=#ff0000>函数名: allocmem </FONT>
. v" e: X; H6 d" Z9 g6 O功 能: 分配DOS存储段
4 | M; G1 @: e9 I用 法: int allocmem(unsigned size, unsigned *seg);
$ M. y D. O, D& _1 Z, _程序例:
; x8 \( k% G; A4 x) _6 j5 K7 L<FONT color=#0000ff>#include <DOS.H>
3 `; L9 o( ^) S+ n#include <ALLOC.H># j5 ~( Z/ F W1 k
#include <STDIO.H></FONT></P>3 u3 H$ Y, T9 |. x0 Y
< ><FONT color=#0000ff>int main(void) 4 K: i6 @+ U- ~" R& y* E6 V' @
{ 2 \" L/ Y% R- I R% r" A# G" o! c$ p
unsigned int size, segp; / T7 q/ r& {( p: T
int stat; </FONT></P>
# g& p3 C" s. A) K% @# C/ r+ A2 l< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
& I3 X( t1 D0 }* N- }stat = allocmem(size, &segp);
6 R7 K- h, X& u; kif (stat == -1)
/ H: F9 g( H9 m/ @) I: Iprintf("Allocated memory at segment: %x\n", segp);
' Y9 b: i0 W+ k+ s& Pelse
6 D# U0 \! G' I$ w2 s4 u: r& @printf("Failed: maximum number of paragraphs available is %u\n",
/ g- s) J0 n) x0 k, j4 e: Xstat); </FONT></P>6 }- p$ m( a6 o; J+ N/ N
< ><FONT color=#0000ff>return 0; , Q; [, h0 T, ^" T6 n0 F
} </FONT>
- o% r$ S; a( d; y# A# |
) S- h1 y, p6 j- V0 [* R' Y</P>
, v# F$ c7 L/ f< ><FONT color=#ff0000>函数名: arc</FONT>
2 m; z% H) g9 j" J8 ]功 能: 画一弧线
+ E2 Y* U/ x! J! o- C9 ?4 c. I) o8 S用 法: void far arc(int x, int y, int stangle, int endangle, int radius); / E" T/ \4 ^& }5 C5 c1 U
程序例:
& x Q, I5 n4 B' } ^4 S<FONT color=#0000ff>#include <GRAPHICS.H>8 c3 e. J5 _8 D( Q1 c6 X; {& y
#include <STDLIB.H>
) E0 @0 Z2 `6 o+ e& `#include <STDIO.H>
/ | \# n# ~6 y c+ Q) X7 U$ G#include <CONIO.H></FONT></P>* `/ X6 C4 Z3 O @" H; I( z& F9 y
< ><FONT color=#0000ff>int main(void) K/ \5 i1 A& u; J9 e" _6 b
{ ; s: ?3 b" v3 G* ?7 x: x1 E& @; T
/* request auto detection */
8 E, c7 I' V* j: h: M6 Gint gdriver = DETECT, gmode, errorcode; . V9 u# A: |" K
int midx, midy; ! U" {! o, Z, v/ c% [7 J
int stangle = 45, endangle = 135;
$ i9 t, p* f& uint radius = 100; </FONT></P>8 @4 G) l+ h; q, o2 ~5 ?
< ><FONT color=#0000ff>/* initialize graphics and local variables */
- a, r: U" L9 k0 _$ K; q5 X# iinitgraph(&gdriver, &gmode, ""); </FONT></P>5 E- S6 @% L6 x p C$ d1 G
< ><FONT color=#0000ff>/* read result of initialization */
, h+ [% } b( B0 I e2 S% [errorcode = graphresult(); /* an error occurred */ ) m' V* h7 i' I
if (errorcode != grOk) + B4 m2 @5 H" H' \) O
{ : U0 ~5 k( i9 I0 S. J3 w1 {
printf("Graphics error: %s\n", grapherrormsg(errorcode));
) y: S6 Z9 [$ k6 T* v6 ^printf(" ress any key to halt:");
' z# n- k- }' P0 U( L; ~+ H4 U' Ygetch(); </FONT></P>& q9 l) X; D2 Y) U4 }4 o
< ><FONT color=#0000ff>exit(1); /* terminate with an error code */ 9 K8 z& E3 F8 \- t/ P/ ?( F: {, l
} </FONT></P>& `) E }2 r6 [/ d
< ><FONT color=#0000ff>midx = getmaxx() / 2; + y2 t8 D2 G& \2 ~9 r% j
midy = getmaxy() / 2;
$ k) r7 y2 H- y9 bsetcolor(getmaxcolor()); </FONT></P>* r2 t' h/ o$ }; I/ D1 L
< ><FONT color=#0000ff>/* draw arc */ * z7 u/ @7 ?! |; q) e7 v% Z
arc(midx, midy, stangle, endangle, radius); </FONT></P>
9 s' }) L" Z1 O<P><FONT color=#0000ff>/* clean up */ ( x# U; o$ X: U0 n% Y# m) r8 y5 H
getch();
) x, V5 S0 W) L1 Q1 s4 Q0 rclosegraph(); ! D8 G6 O" U& t6 p
return 0; " P4 U7 D. M2 @: V5 f9 x
}
g# B O4 j# s! T2 ]" m M</FONT>
3 T5 a% Z" d0 F+ M4 e5 [</P>
, G- J, I5 ~' A! F! H$ x8 X' N<P><FONT color=#ff0000>函数名: asctime </FONT>) N* ?# C1 h* E% t/ C+ n3 b' l9 E# T
功 能: 转换日期和时间为ASCII码 . v* I$ q7 _" ?
用 法: char *asctime(const struct tm *tblock); , a( k7 M5 `! x0 ]
程序例: M0 r# s6 R" c/ ?
<FONT color=#0000ff>#include <STDIO.H>
8 e5 s7 x9 k& V) c: J" A. G#include <STRING.H>
U3 `# N' a$ ]7 _2 g; U#include <TIME.H></FONT></P>
1 Y9 M$ \$ d* t G2 w) S<P><FONT color=#0000ff>int main(void)
" E4 U% h, d0 |& O{
. S3 M) q7 r% }3 j+ ?3 j0 Ustruct tm t; 8 O/ b' m0 B& e
char str[80]; </FONT></P>/ Q: m& V: ?0 D9 |7 N9 a
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>) S( _( y# d m
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
" r, r" r* {3 ]8 {% a K0 R) Y; e/ Et.tm_min = 30; /* Minutes */ 4 Q: s- D% @9 H4 l" s
t.tm_hour = 9; /* Hour */ 9 m! H' [8 m( b# \, Y# s
t.tm_mday = 22; /* Day of the Month */
9 E1 ^/ o- Z/ v1 D) c5 j5 ht.tm_mon = 11; /* Month */
3 _* ~! \3 p$ Et.tm_year = 56; /* Year - does not include century */
) _6 R9 }, Y- At.tm_wday = 4; /* Day of the week */
$ B" ?6 ~0 m- \1 H) Q$ et.tm_yday = 0; /* Does not show in asctime */
5 h3 E4 i3 C2 v7 v4 X1 Q3 ~; z* Bt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
2 k: e+ J S9 B<P><FONT color=#0000ff>/* converts structure to null terminated
& X6 y7 f3 p" J% u4 ?string */ </FONT></P>
. m4 o4 n( L: X+ q: ?. g8 B" y. U<P><FONT color=#0000ff>strcpy(str, asctime(&t)); * y' c' q. _3 Z/ ]- W5 l0 {6 b
printf("%s\n", str); </FONT></P>2 y+ B6 R/ i9 P/ ]
<P><FONT color=#0000ff>return 0;
: A8 Q, h/ d, W7 n; z; a6 C' O}
8 _/ F5 n& m' l3 z5 S+ o" e8 D3 T4 h
</FONT>
9 r& I# M9 j2 j7 Y/ r# L</P>
9 h# p1 d% O, x9 {; x8 `: t4 ~<P><FONT color=#ff0000>函数名: asin </FONT>
' ^6 n% G& E4 g* d( I功 能: 反正弦函数
8 r( m: C7 N/ x1 a* Y' a& g用 法: double asin(double x); c7 _" T* J$ Y+ ~3 j& r3 X
程序例: : H3 V k5 b& |+ M1 ~2 ?- K
<FONT color=#0000ff>#include <STDIO.H>/ P9 L! b2 v/ @) S8 |9 j5 _
#include <MATH.H></FONT></P>
- c9 w) l, ?8 {. A* O<P><FONT color=#0000ff>int main(void)
. r8 s. O* n. n# O" o6 D5 ^{
. B% O: d9 U/ H3 ~double result;
: z1 \4 b6 d9 j8 Zdouble x = 0.5; </FONT></P>
) ^' u% Y' ?; A4 ^2 p<P><FONT color=#0000ff>result = asin(x); 7 K3 r0 H! i! E+ t; b
printf("The arc sin of %lf is %lf\n", x, result); ' V/ ^# e* I! q6 S: P
return(0); : F2 b7 Y$ S, H. l, v: _
} " R1 e1 r C. e8 Y( ^7 {: v8 m2 m
</FONT>
( |, y/ ?5 S; r5 P
0 [5 M2 p/ M+ N</P>2 T; F& Z1 _% X& z {1 h9 i
<P><FONT color=#ff0000>函数名: assert </FONT>5 x& s6 x' T( p! r c
功 能: 测试一个条件并可能使程序终止 + s0 o: o- ^, L9 Z; q2 u
用 法: void assert(int test); 2 F7 b1 ]! B$ g3 \) m! P. ~
程序例:
h3 I1 ]: P" ?7 } a<FONT color=#0000ff>#include <ASSERT.H>
* B) A; \7 w' C7 R) J7 V3 C! K9 O: B#include <STDIO.H>
, l5 u1 Y8 W8 E. u1 H#include <STDLIB.H></FONT></P>+ v- r% z4 ~/ c: M( m' I/ i" a
<P><FONT color=#0000ff>struct ITEM { 6 Y" F6 j7 v. Q. b5 a- N
int key;
5 ~& L: D" U/ F2 A! Fint value;
0 Q3 G, a0 x: g p}; </FONT></P>
' I/ _7 h! p7 o- ]/ b* z- f<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
& e1 B- k6 ?; N; }) Bvoid additem(struct ITEM *itemptr) {
- f0 c9 V& [# f0 i9 u, Lassert(itemptr != NULL);
4 C# t4 @0 W0 L% b6 H2 N; q/* add item to list */ ; z% k9 e$ ^: b. z: q
} </FONT></P>
# u# h( I2 E( Z' s& L<P><FONT color=#0000ff>int main(void)
8 y0 f5 f2 Y! T{
, S& j7 p0 u8 n( z; W6 B# D6 s+ Radditem(NULL); + C1 E$ Q b# r% G a i7 E
return 0; / W2 I2 E* \# U
} 8 G7 O' u* c# j5 C- v2 j/ z; @( [
</FONT># { }& b% y5 k. c5 y, O. n
) Q6 U+ e! U* e</P>$ _3 c8 T, S. V Z7 g5 k! [
<P><FONT color=#ff0000>函数名: atan </FONT>% A* [% v1 J0 Q: u+ w. Q$ X
功 能: 反正切函数 ) b8 V0 h3 N; N
用 法: double atan(double x); 5 v2 O* z3 y6 X) U
程序例:
+ W2 z. r. M$ L0 E<FONT color=#0000ff>#include <STDIO.H>" D$ Z1 b. |- b* e) ~& Y
#include <MATH.H></FONT></P>* O( f5 f* @, j" y6 |( N6 ?" n4 S
<P><FONT color=#0000ff>int main(void) - J& t# K+ l9 ]9 N
{
* b" ^$ T9 F% [" Tdouble result; . `5 }; u8 d! O+ r2 Z5 N
double x = 0.5; </FONT></P>& c! _ h2 p- d# Z2 [/ x% D4 h
<P><FONT color=#0000ff>result = atan(x); 6 o# w. z$ e. o; h/ }
printf("The arc tangent of %lf is %lf\n", x, result);
6 e. M. C5 O) @6 M& a# l. h mreturn(0); 2 U* t' _1 r- k3 k! C/ K6 Z
} ' r- {) f4 A+ y0 F# V# A/ t4 w
</FONT>
' c" W- L9 K! u* X" t</P>) ?8 I# U4 q" E8 S1 B$ i5 O
<P><FONT color=#ff0000>函数名: atan2 </FONT>
- P0 Z" W/ x0 y6 v" X功 能: 计算Y/X的反正切值 {3 J# {- |8 P7 }& R. h% m
用 法: double atan2(double y, double x); 6 X+ ?7 X$ L. o+ X
程序例: 1 x: J+ O$ [& ?- |( K- l
<FONT color=#0000ff>#include <STDIO.H>) n! a9 ^2 y( [6 ^6 l: u
#include <MATH.H></FONT></P>/ E9 ?& ~( f j( X% `* z1 |) x
<P><FONT color=#0000ff>int main(void)
4 [& I, b L- F. W0 Z{ ) m# j' n& C0 N- l0 j9 }+ ~" @
double result;
4 a5 D" t% W& {7 Q8 zdouble x = 90.0, y = 45.0; </FONT></P>
6 B8 Z% z. w9 w( O( F<P><FONT color=#0000ff>result = atan2(y, x);
' K, b# U0 N9 q/ lprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
, W; k2 z( h" s7 jreturn 0; + W0 x3 T& ? T7 V- F3 Y$ K: L
} ; A) E7 O! S) n
</FONT>( {. P- ]( y: t& ? z7 \
</P>
: t0 K7 n7 ]( i- p3 t7 m<P><FONT color=#ff0000>函数名: atexit </FONT>9 a# y9 d2 I% R
功 能: 注册终止函数
6 Y- x5 m) ~+ |0 H5 \7 G/ T$ B1 L* n/ z用 法: int atexit(atexit_t func);
. u7 m4 O0 l$ E7 z% `3 ]程序例: , C" m5 h9 M/ l3 {1 [6 `( h' e
<FONT color=#0000ff>#include <STDIO.H>
5 \: O/ p B/ u% `2 q" M#include <STDLIB.H></FONT></P> E- @' X8 H2 p8 H- I3 M4 S
<P><FONT color=#0000ff>void exit_fn1(void)
1 {# E& |: p2 w7 m: P3 w, V{ / e( r: n. v s, p/ U. z$ q4 y
printf("Exit function #1 called\n");
% x& r% @- N5 f} </FONT></P>
: ~. ?( g: y* m! @! m<P><FONT color=#0000ff>void exit_fn2(void)
: A0 z1 N3 k8 ~# F" l{ , D- f, p% m+ n- b3 y7 a) Q
printf("Exit function #2 called\n");
' W4 L# W1 A& H# K/ f+ ]) [6 ~} </FONT></P>
' a& Q2 P: o4 k \) v<P><FONT color=#0000ff>int main(void)
+ x+ W. O! J. d: R+ Q{
# S1 d* z4 ?2 x/ p, M/* post exit function #1 */ 3 C( T/ n) J. d1 x, U# F
atexit(exit_fn1);
% @& P4 p( l0 ^" G( k" \/* post exit function #2 */ : H1 y1 s' Z$ S1 }
atexit(exit_fn2);
. F2 M& A7 u+ Y3 t8 Oreturn 0;
' @8 `5 S+ s; h% c% F} ( X; O! H- E( ?2 p/ |
</FONT>3 t8 v4 t, U% ^) y% a! U* Q% b
1 w& @8 R5 n& \# X6 k</P>. u9 c8 Z/ Q9 j0 G: m
<P><FONT color=#ff0000>函数名: atof </FONT> f$ Y% w/ t7 ^" K! |! f
功 能: 把字符串转换成浮点数 " \, x# \5 S3 U7 ^$ y' o+ E- R
用 法: double atof(const char *nptr); : ?+ u/ c" m: |1 D$ a( Z
程序例: 5 l0 X; x% `% Q7 f2 l6 R8 i7 `/ C K
<FONT color=#0000ff>#include <STDLIB.H>0 ^( `# r" s6 p4 F
#include <STDIO.H></FONT></P>! p; N! A% Q* |- d' s
<P><FONT color=#0000ff>int main(void) . a3 h+ F4 T" J. q
{
! V' K, B9 _; ^5 I4 N. V: e! D5 s3 vfloat f;
# Z9 Y3 X. j$ |' h9 ^1 d8 cchar *str = "12345.67"; </FONT></P>2 q( o/ n8 m9 p, o4 u n s- L
<P><FONT color=#0000ff>f = atof(str); . }# B* @! n1 a; `3 ^ d/ K
printf("string = %s float = %f\n", str, f); ; m# E# a7 A6 F' }/ N
return 0;
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<P><FONT color=#ff0000>函数名: atoi </FONT>
6 x8 a1 A5 o, l功 能: 把字符串转换成长整型数
- f T0 {$ b$ B- [$ h用 法: int atoi(const char *nptr);
/ l* Y9 `7 t3 `% t8 [4 |: k程序例:
4 h+ Q+ `% ]9 d: S, q7 n<FONT color=#0000ff>#include <STDLIB.H>
9 ^ z! |8 _* T) R, r+ G! O2 w- W#include <STDIO.H></FONT></P>) `# C' L% s' K) t1 i5 j
<P><FONT color=#0000ff>int main(void) 2 `0 q! p. g Z$ t% \" H
{ 2 a. w+ c6 N* B3 {/ p6 d
int n; ; M2 J! B2 E& J# [4 t
char *str = "12345.67"; </FONT></P>5 h! ^( K/ H) K* a7 F
<P><FONT color=#0000ff>n = atoi(str);
5 X9 V: k, ?) M( a' w [* |printf("string = %s integer = %d\n", str, n);
n9 E) f8 H$ H8 s# j7 A. dreturn 0;
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<P><FONT color=#ff0000>函数名: atol </FONT># J2 j8 M4 l8 |0 @) K- P
功 能: 把字符串转换成长整型数
5 |! g$ L5 e$ d4 b用 法: long atol(const char *nptr);
' h) G& S( ~( t! V/ |程序例: </P>& ]+ y9 ]# N2 Z3 m# ?! W* N
<P><FONT color=#0000ff>#include <STDLIB.H>
5 C2 g/ `: ]) _' q* N) j#include <STDIO.H></FONT></P>
8 Y) \/ R+ p; }% t5 d ^<P><FONT color=#0000ff>int main(void)
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long l; . Y* s) l9 L1 m* q& s9 z( x
char *str = "98765432"; </FONT></P>4 o5 H$ L/ y& N
<P><FONT color=#0000ff>l = atol(lstr);
) c9 j8 @ I( X: j: Tprintf("string = %s integer = %ld\n", str, l); 2 x9 f! c# l) `
return(0); ( a, W0 M0 o! A0 b1 I' l
}</FONT></P> |
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