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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
% U7 N4 V: s a7 g< ><FONT color=#ff0000>函数名: abort </FONT>8 |0 @4 @5 c/ `4 @" S: P
功 能: 异常终止一个进程 0 J+ W3 a1 H/ `( z, P
用 法: void abort(void); - c+ ~4 O* J) h/ f4 k5 c7 P
程序例:
% P! f7 l' _4 I. X- f w<FONT color=#0000ff>#include <STDIO.H>
/ V$ N/ A ?1 R1 ?0 J, N#include <STDLIB.H></FONT></P>0 R$ w& D# K6 S' o; r
< ><FONT color=#0000ff>int main(void) , M7 p7 N2 R1 R) n, Z
{ + U) Y O" |* P: T3 G
printf("Calling abort()\n");
* P8 a/ v# _% V) R0 W% [5 K- Fabort();
3 |, F6 G4 _. p" v8 ereturn 0; /* This is never reached */ ' X: b2 m' W, u
}
! C. G0 K; H' G; E) E# u; u( }7 W+ u</FONT>/ h) u4 [, s* V
</P>1 A$ k7 B8 X7 o) s$ z1 Q/ z/ z* W
< ><FONT color=#ff0000>函数名: abs </FONT>1 M( ]- |* C7 T
功 能: 求整数的绝对值 6 x0 E0 F) G1 }
用 法: int abs(int i);
& u6 w& J& w/ Y2 O- K程序例:
, n X z8 C$ M$ b3 Q3 b4 y<FONT color=#0000ff>#include <STDIO.H>
" H/ E2 P+ G) s- u$ H#include <MATH.H></FONT></P>
1 s3 l# @& a3 P! J7 t! e& u$ j< ><FONT color=#0000ff>int main(void)
* t' R; {' w% ?+ g/ f{
( R) R/ {1 D7 L \int number = -1234; </FONT></P>
( u% |3 L- _: n: n8 R( [< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
4 D; c M- K: y" }3 m* J6 `return 0; ) t% I1 i1 u! q+ v" H3 }& S
}
0 F% Z: y% y/ D</FONT>* Q1 I4 W4 V1 ^( v% d: Q/ w. U
</P>3 C5 W& I0 w0 k: p) C2 I
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>
* [3 y. y+ L L! ?( e功 能: 绝对磁盘扇区读、写数据
/ F% f0 {: P4 w% Q$ k5 A, @用 法: int absread(int drive, int nsects, int sectno, void *buffer); * q, T' N9 z' |1 c
int abswrite(int drive, int nsects, in tsectno, void *buffer);
) ~- N1 `' W' U) \+ N6 {1 S程序例: ) c+ I2 j, b/ S b4 P' @! \
<FONT color=#0000ff>/* absread example */ </FONT></P>
/ S: Q4 K- W" M8 X* g< ><FONT color=#0000ff>#include <STDIO.H>: v# a# A, L* E9 {, B' l3 P
#include <CONIO.H>8 k' r4 U5 g) @' s" I; G- M
#include < ROCESS.H>
" U0 o) p7 H& W5 R0 n#include <DOS.H></FONT></P>
3 M5 [. E: O) V' ]2 Q< ><FONT color=#0000ff>int main(void) ! Z: B6 q+ Q2 `" Q/ n1 @
{
v4 j# L8 t5 D' t2 f: cint i, strt, ch_out, sector; 8 N7 e1 ?% r; \) _) X
char buf[512]; </FONT></P>1 _! |- X& l2 |2 f( O
< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); 6 z* J% N8 A" s6 o
getch(); ) @4 O6 k) m+ t7 b% e# A2 j
sector = 0; 5 C, E/ d5 Z$ ~
if (absread(0, 1, sector, &buf) != 0)
* l- C1 \1 D9 B3 {" n+ f2 B{ , ]! ?% o X, X. E5 C6 d
perror("Disk problem");
/ z2 o/ Y5 o4 T4 nexit(1);
) w* v+ C3 s) ?& b* E' V* g" q} + m* y, m3 B/ u, O- Q2 ?
printf("Read OK\n"); 8 J) H v' j8 k8 U# v6 [, n3 g; `4 x
strt = 3; 2 B* M$ S9 f0 B( v6 N# T
for (i=0; i<80; i++)
- U: X1 a4 @, k" D* S0 N9 T0 }{ ! a+ @) S c- _$ r8 B/ M# R. q. X
ch_out = buf[strt+i]; . g& }) k4 H% T3 P0 C+ u1 D7 \
putchar(ch_out);
' o! W/ l8 e2 n0 w$ M}
4 B7 t% J1 O Lprintf("\n");
7 }: b) j/ e3 }5 b& _return(0); / {1 ? i7 b0 G% [( K$ Q
} 9 c1 c. ^3 t# c6 h$ {4 g: v, E
</FONT>% Z/ U8 m$ t6 T$ K( _
+ w+ | U& [8 t# L& Y7 t7 A' U
</P>
x5 B; b7 n1 I) p: l, ~< ><FONT color=#ff0000>函数名: access </FONT>
/ c7 K5 j4 y% P- c功 能: 确定文件的访问权限 ( {4 `1 L2 T, ^# T5 z+ u
用 法: int access(const char *filename, int amode); U, F" z' t& h
程序例: ! i7 x2 W2 U h5 m
<FONT color=#0000ff>#include <STDIO.H>+ r% H6 G0 c% K7 i7 r" k0 }! }
#include <IO.H></FONT></P>
& Z0 g7 W3 |3 z, }( |1 W6 w< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>, p) {4 z1 f: @9 i0 ^% [
< ><FONT color=#0000ff>int main(void)
9 j' H/ h0 T4 ~1 F2 k{
, L: X3 o# n1 h, u A$ fprintf("Does NOTEXIST.FIL exist: %s\n", + s3 v) Z# I I5 s; G7 f; a
file_exists("NOTEXISTS.FIL") ? "YES" : "NO"); ' C/ {* k" {/ C7 y
return 0; 3 n$ x5 }+ X# y% v. H
} </FONT></P>( T; m6 C. i4 {% y8 F, L
< ><FONT color=#0000ff>int file_exists(char *filename)
8 x m! h/ x- z{ " H3 o; w/ R# J2 b
return (access(filename, 0) == 0); 9 h- o5 R5 A+ p; ^6 _, F% l
} ' q1 w5 D/ ^2 c5 [% b* C) K
</FONT></P>' M1 B0 Q2 C P( t4 ?$ S
< ><FONT color=#ff0000>函数名: acos </FONT>' I$ q8 K' j' _6 \8 M: c
功 能: 反余弦函数 / i+ @3 I% n/ P9 E
用 法: double acos(double x);
0 ]+ y+ G: k3 {& S/ @/ Z7 }程序例:
) F8 g, V& e% P7 ~' z<FONT color=#0000ff>#include <STDIO.H>
J- C8 I% u7 U2 H* I( s9 y. J#include <MATH.H></FONT></P>
3 B( }( s a) P8 `. K9 n1 ~7 J< ><FONT color=#0000ff>int main(void)
' m3 o, c. h8 D: o! e. @" R{ ) a+ g/ ]2 h. p3 F. ]
double result; 4 ?- A! u1 _) [% _; l7 X- f
double x = 0.5; </FONT></P>- X1 X8 ^' ]" k' B1 b& a4 q
< ><FONT color=#0000ff>result = acos(x);
( b% S+ {( [' v' a1 o8 mprintf("The arc cosine of %lf is %lf\n", x, result);
! X' ^! C! j- w# P4 zreturn 0; ) J# z R0 K9 s8 o1 W
} </FONT>- Q! c* _$ X u$ Q8 o" B
- L5 v- j+ u! S4 z& @</P>
& u- h. p, n. n4 A, L. D< ><FONT color=#ff0000>函数名: allocmem </FONT>* r" e3 F% k3 F9 e- d8 z# J8 p
功 能: 分配DOS存储段
$ }* E3 h/ ]8 e N1 V用 法: int allocmem(unsigned size, unsigned *seg);
. j" {1 a$ x$ R, i- S% i3 ^程序例: $ ^3 \7 b8 x# q& ?
<FONT color=#0000ff>#include <DOS.H>
+ ? l' ?5 N; d( R7 V#include <ALLOC.H>7 I, @# {3 w! z) ?! C7 t
#include <STDIO.H></FONT></P>+ `, J4 T: R' s1 g# R
< ><FONT color=#0000ff>int main(void)
. l$ u: o: ]: k{ 4 ~8 [. Y+ F0 J# c3 c9 A9 d
unsigned int size, segp; ! @3 z0 X' a. o1 k, _: ?; C
int stat; </FONT></P>9 U3 u/ \! g- f/ G! v2 i2 H3 v
< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
: ~& L. d" J% gstat = allocmem(size, &segp);
) z, {0 d2 l( f P7 K4 c9 Kif (stat == -1)
7 x$ ^& P Y+ [ P4 D2 n, {printf("Allocated memory at segment: %x\n", segp); 0 @/ O! _" K; j/ \ m$ k# D$ O
else
: @& n% s' l. m1 V( Dprintf("Failed: maximum number of paragraphs available is %u\n",
) b2 s; j; v. D6 r: G, h5 q0 ^* ]stat); </FONT></P>
$ T+ X) A, u8 [& h+ O$ K2 E F< ><FONT color=#0000ff>return 0; 8 i5 c9 ]& J; [' ~9 r V
} </FONT>$ w5 U1 [5 A; Q2 M, q( L
. A0 ]! R0 q1 O2 }! u* ^</P>* _$ k' K$ ]4 D! o5 ]
< ><FONT color=#ff0000>函数名: arc</FONT>
' F+ U2 P% u" ?+ l6 p功 能: 画一弧线 - N. C7 x6 \* |) O2 \' i8 ~# Q* O- _
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
8 B# w- E2 _# h程序例: ! T4 c+ R" L) G: y
<FONT color=#0000ff>#include <GRAPHICS.H>, N. B) a5 R+ E4 K+ G
#include <STDLIB.H>
8 L0 m, w+ w+ m0 O5 J, Q#include <STDIO.H>
4 h; b6 a" E8 j/ K: k#include <CONIO.H></FONT></P>7 g9 G5 |' E4 r0 Z( ? c9 y/ M
< ><FONT color=#0000ff>int main(void) 6 J1 W7 h2 ]' J
{
% z* E: P x% y! Z+ P4 t; M( U& \/* request auto detection */
7 g1 S6 J! ]2 m( U; Oint gdriver = DETECT, gmode, errorcode;
D) \2 Q7 p& u5 I$ V, yint midx, midy; + B6 c7 q* g G5 q
int stangle = 45, endangle = 135;
/ D+ G" e' @' z, S) ^' S& a# \# ~+ Vint radius = 100; </FONT></P>, q6 ~ t. j9 @6 R
< ><FONT color=#0000ff>/* initialize graphics and local variables */
( d% h% w0 a/ X4 ]: Linitgraph(&gdriver, &gmode, ""); </FONT></P> a. l$ N3 X+ h
< ><FONT color=#0000ff>/* read result of initialization */
: S1 M. \, }7 z7 `errorcode = graphresult(); /* an error occurred */ ( U& {2 Q+ p8 t% p7 L6 G
if (errorcode != grOk)
/ @9 U- P2 N; \& Q, R{
" z' Y% I" R9 yprintf("Graphics error: %s\n", grapherrormsg(errorcode)); " G8 Z8 M: e Z
printf(" ress any key to halt:");
, W8 n0 b. p" k3 I) [1 vgetch(); </FONT></P>: Q$ q! z; h, c. U) H& T p# e5 ^
< ><FONT color=#0000ff>exit(1); /* terminate with an error code */
+ L& T1 K T7 X} </FONT></P>
4 {( l8 r* ?. X. j7 Q< ><FONT color=#0000ff>midx = getmaxx() / 2; 0 a0 h/ [: ?# j8 w0 }* i: \
midy = getmaxy() / 2;
: [% d' l% S3 i1 i) |8 osetcolor(getmaxcolor()); </FONT></P>9 `5 H" Z i5 e
< ><FONT color=#0000ff>/* draw arc */ * Z3 j M. {1 B
arc(midx, midy, stangle, endangle, radius); </FONT></P>- w! U# h$ f( [5 e8 q
<P><FONT color=#0000ff>/* clean up */
/ ?* b7 o) j5 `: H4 qgetch(); ! N- @6 w: Y0 u' X7 ?
closegraph();
; K8 A) D: M& b% [4 rreturn 0; 7 W: b" I0 f9 k
} . e2 M( U. G/ V7 M J' W* O
</FONT>
. y+ |8 ?6 d% ?! Z; `0 x</P>, U% f( h# J( p& t$ @! f* F
<P><FONT color=#ff0000>函数名: asctime </FONT>
& x) `' z& _8 @+ l8 p0 S0 L3 A, q功 能: 转换日期和时间为ASCII码
: u8 e8 V% K: a0 _" r6 w6 E( [用 法: char *asctime(const struct tm *tblock);
! D8 y2 ^' ?9 O! D1 q程序例: - X$ R S) Y6 E; g5 ~) F
<FONT color=#0000ff>#include <STDIO.H>; K) [( N% U; o0 R+ B, \
#include <STRING.H>
- ~* G) G2 f" P$ A' y#include <TIME.H></FONT></P>
e! q J2 l3 G4 s$ y! F2 v<P><FONT color=#0000ff>int main(void)
, x- ^5 Y1 h! @: O7 E% D$ |3 g$ m+ ^5 G{
' Q* |6 K3 D! k8 h+ xstruct tm t;
6 `- ?2 g1 n6 H) K, @char str[80]; </FONT></P>
& E [6 G+ w2 O<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
, r% b* C( g: O m: O! s<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
! `9 I" Y; b. G" m7 e: d+ n. vt.tm_min = 30; /* Minutes */ ' `5 P' `2 {* ^6 Y
t.tm_hour = 9; /* Hour */ 5 h k6 e* q X. A* Y' S
t.tm_mday = 22; /* Day of the Month */ : P3 a" C6 z( h3 a/ v8 t
t.tm_mon = 11; /* Month */
5 J% O+ j r0 J7 b& Rt.tm_year = 56; /* Year - does not include century */
( ?8 a5 Y1 V, i3 ct.tm_wday = 4; /* Day of the week */
' r" p' T, `+ a0 v2 P# ]t.tm_yday = 0; /* Does not show in asctime */ ! j1 @/ A$ F' O1 S2 q
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
. W0 B/ \+ x+ v1 V<P><FONT color=#0000ff>/* converts structure to null terminated 2 f% P6 b1 ^) A% |/ h$ P6 n
string */ </FONT></P>$ `, o2 @' _8 I* A5 o" C
<P><FONT color=#0000ff>strcpy(str, asctime(&t));
; |% s; M- s! W; G, G3 L% `0 }4 ~: Vprintf("%s\n", str); </FONT></P>
; i1 \4 c% Z7 o. ]<P><FONT color=#0000ff>return 0; 4 X7 K& Y) S6 ?6 g7 P' b1 X9 N
}
% M0 p$ m5 f# X% c
: k/ {$ T' Y4 c8 x, x</FONT># N' ^1 e# J. C/ r0 K: r
</P>, p9 b1 L0 l7 _6 ~( ~
<P><FONT color=#ff0000>函数名: asin </FONT>
# `' y, V6 K% J功 能: 反正弦函数
) Y4 \6 i3 v" ]用 法: double asin(double x); _) |* q; F m
程序例: ' W9 q+ h- o# Q8 `8 n) q" E4 }
<FONT color=#0000ff>#include <STDIO.H># ?: {! q2 }- f& x0 {7 [
#include <MATH.H></FONT></P>
- Y7 [% {: o! y/ |5 v9 W: L<P><FONT color=#0000ff>int main(void)
; Y p% `! ?% ]: B{ % b# U7 Y- F( j- B
double result; $ n# \4 S4 W$ Q; u1 A. Y5 K: ?
double x = 0.5; </FONT></P>
N! H; B& o# d* i6 U$ H: m<P><FONT color=#0000ff>result = asin(x);
4 T* h' `( z/ mprintf("The arc sin of %lf is %lf\n", x, result);
2 I% P! g: i5 [- breturn(0); - b- N: N0 ]- Z+ }) S- C5 o
}
) S+ n1 v: x# ?( Z) E& c& K</FONT>
# N( C8 N( C9 R; S, X* s) H7 y1 C" O7 u [- H' E' T; K- M* B
</P>! o& T2 |1 D! C3 ?
<P><FONT color=#ff0000>函数名: assert </FONT>
8 @; V- F; c7 Q Y9 J功 能: 测试一个条件并可能使程序终止 / e6 |& o# c! K B" z$ u
用 法: void assert(int test); 8 `% H. `, h& p2 k+ L/ U6 B, [6 ~
程序例:
; R. M! C! m4 y; \5 `: Y<FONT color=#0000ff>#include <ASSERT.H>
7 r! o$ s2 e$ t9 J. l#include <STDIO.H>" [* S* L" K/ F; |' D5 J3 B
#include <STDLIB.H></FONT></P>7 z% h( N6 k; I4 }0 f
<P><FONT color=#0000ff>struct ITEM {
) T- b; z1 Y4 {, tint key;
. ^( W( T8 N9 {5 ^int value; ! M$ I2 R$ E0 l- S0 n% i/ M: z6 [
}; </FONT></P>+ i! U0 G! G- e7 v4 F
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */ - g& q, F6 S' x; ]
void additem(struct ITEM *itemptr) { + H* W. N" N" J4 D) s, \! A1 V
assert(itemptr != NULL);
+ M t g: `& ~) c/* add item to list */ 1 g9 i2 ? t8 n- k1 D8 i) A4 Z* @
} </FONT></P>
# Z' m& E7 k7 g! d$ X<P><FONT color=#0000ff>int main(void) 7 [% y( S( v* r; \( M1 x
{ ( \$ D s2 F& i V( p
additem(NULL); 3 ?2 x% _& v! D8 q9 x8 Q
return 0;
- z" U% w5 V) h} , L1 u3 D/ j6 s# w
</FONT>% h; f$ G8 Q, H2 V; S
, T' W; {& z( P7 P
</P>& a$ |& ~7 H8 M3 `# I
<P><FONT color=#ff0000>函数名: atan </FONT>
/ T, K+ T# t7 ?% K* _功 能: 反正切函数 - y1 v, w7 F+ y
用 法: double atan(double x);
! y, @* a) F @. _! P1 z& Q6 @$ P: c程序例:
6 q2 j9 C2 {. |4 U' g+ V<FONT color=#0000ff>#include <STDIO.H>
6 p I* {3 L$ D; `3 k6 Z#include <MATH.H></FONT></P>
3 J5 U/ o+ x8 J+ B! @, i<P><FONT color=#0000ff>int main(void) 5 U; k5 U" Z. r d2 I7 X9 D7 @
{ & P, s p; u* f8 ^4 R, ~6 a& D
double result;
3 c/ q$ r& a4 ~* A# Q* t& G1 jdouble x = 0.5; </FONT></P>2 Q; Q4 H! P0 n# [ \
<P><FONT color=#0000ff>result = atan(x);
3 d0 n& P: r. {, r. x1 E& sprintf("The arc tangent of %lf is %lf\n", x, result); 4 c, Y' S7 ]. `& [
return(0);
6 L6 h* L4 H% y* W+ o}
/ q0 g! T; T) U* _8 [# S0 W* ]</FONT>
0 p# k* ]5 s- \/ B& ^* f/ X2 K0 x</P>
, q7 q$ `- P. D. c4 a) H4 {- K' r<P><FONT color=#ff0000>函数名: atan2 </FONT>! T8 z3 w" y, R
功 能: 计算Y/X的反正切值
# h/ u/ [) I' c# f1 Q: Q用 法: double atan2(double y, double x);
, V Q. S4 r G5 n/ I程序例:
2 I) r$ q5 d+ ]; L6 W<FONT color=#0000ff>#include <STDIO.H>
) V! e8 v1 @0 U0 N& u. Z#include <MATH.H></FONT></P>/ s, j" b* z8 {4 y- F7 R+ c) T$ M
<P><FONT color=#0000ff>int main(void)
6 r& P5 Z7 }' s* ^ J{
% [7 I$ H" S r V$ e6 qdouble result;
9 @7 R- R/ b0 U: I* m4 N; idouble x = 90.0, y = 45.0; </FONT></P>3 S l; ~, t1 L& \
<P><FONT color=#0000ff>result = atan2(y, x); . `5 ]- l5 a* V
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result); + s/ L/ e+ F$ i W! o9 p. }
return 0;
. Z5 V3 i; T+ ?}
7 w' F1 o4 }3 z+ Z</FONT>
) W* h" k* g3 v</P>
! K Z6 t9 [$ X o7 c2 H" e* Z<P><FONT color=#ff0000>函数名: atexit </FONT>& l- a5 M$ A8 N1 O
功 能: 注册终止函数 9 V4 k. X! i, R9 r
用 法: int atexit(atexit_t func); : F% D' ^* e* J6 c# G
程序例:
6 R7 b9 I4 x' d+ e* u3 T0 J<FONT color=#0000ff>#include <STDIO.H>
- W+ j2 j7 s; g6 V#include <STDLIB.H></FONT></P>* J- a$ z- `( Y U4 n* t0 \ h
<P><FONT color=#0000ff>void exit_fn1(void) 2 {: H# I0 H( j7 E9 r' P
{
7 f" L6 V x n6 ^9 ?% rprintf("Exit function #1 called\n");
* j0 M- X; y/ Q} </FONT></P>
. P/ Z4 b1 v# g% Z<P><FONT color=#0000ff>void exit_fn2(void) 3 A/ a' Z; G* o+ z5 _. l6 L
{ , C3 e! P+ Z% ]+ g- G! \6 a
printf("Exit function #2 called\n"); ) l" z& E+ z! A
} </FONT></P>9 B# I. _+ W% O( U) X% W. H, T5 \! d
<P><FONT color=#0000ff>int main(void)
* a* g+ i+ ^' E{ : }# v4 e4 F& ]7 H% c, I' X
/* post exit function #1 */
" a* x k: U+ Z# O( c6 d- uatexit(exit_fn1); 7 w/ O8 \7 f j
/* post exit function #2 */ $ w% n; h4 K D! F( U) O0 W8 F
atexit(exit_fn2); , d: X& U, |/ T3 b& c* q' Q B! y
return 0;
' {+ P8 J5 f. s0 s+ ]} 6 C1 p* \2 n* b5 H5 I3 C
</FONT>9 @/ u; J$ N9 l% ^- Z7 o4 D+ ?
* |2 o: @5 I4 U
</P>
4 b0 p, k% H1 X& T9 J- F<P><FONT color=#ff0000>函数名: atof </FONT>
7 t6 r6 ?7 X, [5 {4 o @功 能: 把字符串转换成浮点数 $ o* m$ W1 M5 A1 G; Z* ^4 V, i
用 法: double atof(const char *nptr);
0 M P2 h' K! S) Q8 G. N程序例: & @! c' ? q# x' d5 h: j* L0 }2 y ^
<FONT color=#0000ff>#include <STDLIB.H>, h0 C% I% `: U1 T
#include <STDIO.H></FONT></P>
+ o( W( O) {: M5 u: S! D<P><FONT color=#0000ff>int main(void) 6 t& `: {6 J8 |) k8 L: I
{ 3 T& h, j- ?/ w+ y! Y @
float f; ! m( C j' n0 L
char *str = "12345.67"; </FONT></P>! {4 S! i _! x) \& j
<P><FONT color=#0000ff>f = atof(str);
6 B/ T- ]2 z' B* d8 H8 z4 ]) wprintf("string = %s float = %f\n", str, f);
0 f" t1 o: I5 X7 _. b: j" Z9 }- lreturn 0; 4 W4 h& b- T( q9 G) e. v
}
4 \1 ^3 O$ P- K) ?2 m, N8 e! h0 \</FONT>* ^8 | y' r% ?6 Q
</P>
' K( M/ ^( ^. T# F# s<P><FONT color=#ff0000>函数名: atoi </FONT>
# r/ G; i6 I* ~9 d: t0 Z功 能: 把字符串转换成长整型数 + v8 k) }% k8 Y: Z! k2 G
用 法: int atoi(const char *nptr); ' Z A9 U& J( n/ M; p) C% d
程序例: ; B0 h, m* [/ F e' |- {6 C3 T
<FONT color=#0000ff>#include <STDLIB.H>
/ o: m/ R0 Q% C8 `6 o4 t#include <STDIO.H></FONT></P>
1 G9 @5 R% `5 H<P><FONT color=#0000ff>int main(void) 4 e- _; H/ m2 l
{ % l# ?# o; k9 D4 W
int n;
$ p6 a& g3 o! Q7 @: Echar *str = "12345.67"; </FONT></P>, U6 K4 X: K0 \ G$ n- ^: b
<P><FONT color=#0000ff>n = atoi(str);
5 P7 z$ ] z, hprintf("string = %s integer = %d\n", str, n); # B9 t# r* G9 }8 ^" n3 x! `' m
return 0; ( Z, A, q) M1 Q( y$ a
}
. T; J5 u p( x+ N0 R</FONT>
) A' B' Q8 M% ]% z/ A2 ^</P>
4 b( y6 ~. y5 F4 U3 ?<P><FONT color=#ff0000>函数名: atol </FONT>+ P% t8 n- U+ r# W1 E: |6 S$ E
功 能: 把字符串转换成长整型数 ' ~, B6 X7 x0 g- d2 J
用 法: long atol(const char *nptr);
. ^+ s- t3 _7 y9 |; S; K程序例: </P>
2 j: Y: r {9 O3 l<P><FONT color=#0000ff>#include <STDLIB.H>
. m* A8 ^2 n/ }- A5 `% ~: i#include <STDIO.H></FONT></P>
) N+ x# {- i: O* H5 A<P><FONT color=#0000ff>int main(void) ' p& y* S/ |% }, Z3 p: Z
{ 3 g* C- A; s2 e7 {* I$ p
long l;
- O; n. |$ {, P' R! b' t# fchar *str = "98765432"; </FONT></P>/ a' J) l& J2 ` G& W* \5 q, B$ E0 n. N
<P><FONT color=#0000ff>l = atol(lstr); " V0 m, ^1 M7 y5 _) i) \5 `1 d
printf("string = %s integer = %ld\n", str, l);
6 K9 f% b1 P( ~5 g! ?return(0);
2 e2 O, H \8 [- s1 n}</FONT></P> |
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