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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
7 B/ _! X8 J3 r< ><FONT color=#ff0000>函数名: abort </FONT>- ?4 i( j% T$ ]7 ?
功 能: 异常终止一个进程
) A2 W. D4 p& E用 法: void abort(void);
5 ` d5 ^! k$ g6 z/ x- c程序例:
: _! U# y, f: K2 m<FONT color=#0000ff>#include <STDIO.H>
9 W, M0 p. Q y$ I g8 q) [: u#include <STDLIB.H></FONT></P>% |) S% ], U3 i+ W$ G9 x$ u! ?# H
< ><FONT color=#0000ff>int main(void) 2 l- _4 R: X* T2 R# L: X" ]1 P) N
{
: s6 A* E. I4 N8 G* Yprintf("Calling abort()\n");
" q% T+ @$ L5 babort(); / V# Z9 m. ~6 y6 V3 i" f
return 0; /* This is never reached */
; r. m' {9 j& O( r& \} 6 V5 |, U- L6 g, c
</FONT>$ V# A" {" S" |( ^4 A
</P>, }9 f5 y S! x- m& T
< ><FONT color=#ff0000>函数名: abs </FONT>3 X7 t% M4 V5 j# W
功 能: 求整数的绝对值
$ r3 Z1 Q2 ^6 J. k" j: }! k用 法: int abs(int i);
$ k% W% m$ g, v% O) V程序例: & T9 q g- F# k" h" _: r. l k6 @
<FONT color=#0000ff>#include <STDIO.H>+ x9 r( _6 w) h& o; A
#include <MATH.H></FONT></P>
- d$ T! {3 y: r! J9 A/ n< ><FONT color=#0000ff>int main(void)
; b5 N% o! B" N$ d, y6 \{ 5 p8 ?% D) U3 |$ g2 a
int number = -1234; </FONT></P>" A A/ T; {0 R
< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); 9 ?! J$ U3 H2 T) L7 W
return 0;
7 W! o* C$ N n8 ?2 A2 m+ i0 q}
$ ~6 k9 T6 D' w2 O" a$ A2 S</FONT>9 ]7 s. y7 D2 |
</P># k: b" f4 m, S' ?' n0 H, I
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>% B. D6 _% l8 d- a5 u
功 能: 绝对磁盘扇区读、写数据
* k v5 z6 n( {$ g6 V- i用 法: int absread(int drive, int nsects, int sectno, void *buffer);
) L# _- U7 K' M# V6 ]/ fint abswrite(int drive, int nsects, in tsectno, void *buffer); 5 \/ F! V1 t& a; `+ _* |
程序例:
( M) A l% J$ R( i7 S( m<FONT color=#0000ff>/* absread example */ </FONT></P>6 {3 _3 K; {/ [+ {& w. i, A
< ><FONT color=#0000ff>#include <STDIO.H>, L2 j" D |, }, N9 g
#include <CONIO.H>
$ H) z2 i; m* l' R; {/ _: b9 v#include < ROCESS.H>
% \- X& |9 b0 [8 Z1 _#include <DOS.H></FONT></P>
9 q7 ]9 V* p- b1 _0 Q" B< ><FONT color=#0000ff>int main(void)
0 @. D( J! h: ]% B# B' c{
& G' T Q: V, V( e6 A! tint i, strt, ch_out, sector;
3 b, v7 F6 y: Q* m3 Wchar buf[512]; </FONT></P>
& C% B% z" V' }* ?5 S! v< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); 6 g# X( ~9 m$ T6 m/ e: i
getch();
/ \9 N7 N# F7 F( B& C6 U! q. O& jsector = 0;
* g" e$ V, v0 c" s; s: s! n3 G6 p1 pif (absread(0, 1, sector, &buf) != 0)
2 I5 E7 C/ }# N$ L2 B0 Z$ h{ 7 _" t, o# U( w% e& K
perror("Disk problem");
3 |5 p9 ]2 C& x) W* |exit(1);
% o" G( ^( u/ p( A} 9 p B: z u/ y5 S. \* B9 X7 }- a8 G5 R
printf("Read OK\n"); 3 h" Q; H' `. a2 x- [% W+ \' R
strt = 3;
7 I$ b4 Q2 w efor (i=0; i<80; i++)
v, h& F4 t1 ?; ?/ h0 g{
! p! v7 ^( s8 B" s/ f7 h7 Cch_out = buf[strt+i]; % F# _ L: P1 U" P* }2 s( C, Q9 N
putchar(ch_out);
% I4 g0 p6 l# D j) L: X7 s) i}
! b/ R' j% @0 l4 P9 H* j# [0 F$ dprintf("\n"); 6 K& }4 |3 D/ C$ }
return(0);
{/ u) L2 w* d" o2 A- A/ P}
4 s0 q1 ^& G* t/ E8 k' a</FONT>% T% }. W O( S1 _* Q& ]3 Y
" `7 Z k5 X0 \2 h</P>* }& h) U3 Z7 R4 u
< ><FONT color=#ff0000>函数名: access </FONT>/ H8 s# ~; T. X) c" y6 j+ r P
功 能: 确定文件的访问权限
@7 [4 t# ^9 S用 法: int access(const char *filename, int amode);
, e% t: a9 m/ F* l5 X4 G4 G6 ]程序例:
T8 c6 [) j1 I% J+ b3 J6 v( |" B<FONT color=#0000ff>#include <STDIO.H>
5 n- [; f9 l% Z# U# s- O#include <IO.H></FONT></P>! V6 N, w! H& k' H; @$ a
< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>- v6 P5 i, a, f( V5 L7 E K2 d; P! s
< ><FONT color=#0000ff>int main(void)
; G( Q0 @6 ~( i, [! W/ U{ 7 o1 h0 ~. I: H7 g' R/ y) X* F
printf("Does NOTEXIST.FIL exist: %s\n", % z/ N: G+ Y) J v( b* U7 K
file_exists("NOTEXISTS.FIL") ? "YES" : "NO"); ; w( Q: @0 u1 ?+ u: S3 L F1 h
return 0;
% c6 ~! q5 H& G} </FONT></P>
0 Z* g' _* @8 X. l< ><FONT color=#0000ff>int file_exists(char *filename) ; X% B Y- e8 y( {# E* e
{
6 [, O$ Z" m3 C4 B+ ^( t& `) J7 i/ \return (access(filename, 0) == 0);
C* E# w4 a/ h( s: W} 7 ?9 B5 A$ D' Z6 X) }7 D8 F
</FONT></P>
9 u/ t1 C3 p8 _< ><FONT color=#ff0000>函数名: acos </FONT>
& M: g8 k% a2 d9 h2 w9 [功 能: 反余弦函数
% ~& I" i/ n0 Q3 ]3 y) q5 h. ?- `$ k9 r用 法: double acos(double x);
- j: W. `; M! B6 V+ i7 E) U程序例:
[9 K q$ q3 v6 I$ f* J6 l<FONT color=#0000ff>#include <STDIO.H>, W9 Z5 W( s6 @8 g3 o4 `
#include <MATH.H></FONT></P>
4 H2 B9 M; O% l< ><FONT color=#0000ff>int main(void)
% G/ G( @4 J, ~{
- P( a5 b& o3 \8 F* H" Z# ]double result; . I; M- }$ z4 b
double x = 0.5; </FONT></P>" l. E& R" L: r4 Q0 M* h8 b
< ><FONT color=#0000ff>result = acos(x);
2 v8 }& m: P+ a# p! H+ m2 [2 cprintf("The arc cosine of %lf is %lf\n", x, result);
& W) Q7 j! H3 c0 F- Y9 i% L' `) Sreturn 0; ; A, X5 O+ P% C/ s
} </FONT>
1 U* U4 }; a- H4 [! G7 G% ^
1 n+ w" a9 ?# y) @- @- T</P>! Y6 C7 D8 ?: e o
< ><FONT color=#ff0000>函数名: allocmem </FONT>' p' A4 b9 h5 H7 S
功 能: 分配DOS存储段
7 P5 J; v1 a' ^, x3 j用 法: int allocmem(unsigned size, unsigned *seg);
( ^! d* Y' O2 x) _3 u3 N程序例:
; _' o3 X1 W1 |4 U6 i$ h- F' o- y<FONT color=#0000ff>#include <DOS.H>
! n ^# c4 z6 z#include <ALLOC.H>
, I+ l( T F0 x" P9 C: u#include <STDIO.H></FONT></P>
2 j0 q: F: {6 a' S< ><FONT color=#0000ff>int main(void)
' V5 ?* n* m) T' c$ Y$ Z* s{ ! @( }; r& S& Y8 M' w
unsigned int size, segp;
/ L& Y5 C h; S1 [- ^int stat; </FONT></P>
0 x% [" S! }. ?6 `< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ H6 _2 W$ P4 {) s
stat = allocmem(size, &segp);
, F2 X- o! \$ _, |* a1 T$ Fif (stat == -1)
7 M9 \/ |: O7 d3 Oprintf("Allocated memory at segment: %x\n", segp);
- T3 ]+ y# F; \ |! A3 L; H& S! Kelse 5 x: M# F/ y4 [6 C
printf("Failed: maximum number of paragraphs available is %u\n",
- {; T# `5 v. Vstat); </FONT></P>% O0 A# o6 N+ r" {8 y7 \8 R
< ><FONT color=#0000ff>return 0; 8 d2 P# c) I2 D9 T6 z! Z
} </FONT>) ?7 `- T p9 A( R' N
# H5 N6 s% Z d! U$ _. i</P>
; _# G: h+ T$ m< ><FONT color=#ff0000>函数名: arc</FONT> 1 R; a+ o* K5 S
功 能: 画一弧线 , J" i, ~/ Q' H* c
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
- K# q. K" C G* H3 U$ v3 @程序例: 3 I1 n! H3 ]" ]
<FONT color=#0000ff>#include <GRAPHICS.H>
$ V6 {9 |- r9 {5 m# L1 f#include <STDLIB.H>
: U& C# t# f' M#include <STDIO.H>
' e5 p( V, |, Q2 U% L: v3 W#include <CONIO.H></FONT></P>
& V4 r L8 D6 [- q< ><FONT color=#0000ff>int main(void) * s+ q% J( ]9 v, P
{
* a: E( D8 y2 k! Z/* request auto detection */ + g L. S8 O6 [) @
int gdriver = DETECT, gmode, errorcode;
0 |% [, B4 h+ H% E r& K4 z0 g' Iint midx, midy;
, U' B. f& z# T# D; e. K0 Uint stangle = 45, endangle = 135;
% Q$ a: j e' N7 G4 ?2 H2 gint radius = 100; </FONT></P>; B) E/ O0 ?) F7 ]; Q& L
< ><FONT color=#0000ff>/* initialize graphics and local variables */
* D! r7 V0 K( Binitgraph(&gdriver, &gmode, ""); </FONT></P># w& S! {7 q( B
< ><FONT color=#0000ff>/* read result of initialization */ 1 h/ S; I) \3 z& \" Q( e
errorcode = graphresult(); /* an error occurred */ + r4 A. U- N0 N2 n9 T
if (errorcode != grOk) 0 `0 K/ D" x+ S
{ 8 t1 U8 o4 w+ o6 x/ t
printf("Graphics error: %s\n", grapherrormsg(errorcode));
7 H+ X" H! Q4 F& M5 F. {0 K! Nprintf(" ress any key to halt:"); " z+ }+ n) p8 O5 W7 J) G. ~
getch(); </FONT></P>
0 a( k: s6 d0 @$ l% }! c< ><FONT color=#0000ff>exit(1); /* terminate with an error code */
, Y7 E2 P M) |) M} </FONT></P>: Z8 W' L2 o$ x0 }/ }2 A
< ><FONT color=#0000ff>midx = getmaxx() / 2; 5 s0 O$ q7 h$ M9 T. H% S o' g9 j# ~
midy = getmaxy() / 2;
; Q8 b Z: Y) ]/ Q* z6 g& B7 i% [6 Psetcolor(getmaxcolor()); </FONT></P>5 ?1 _4 g( @+ A& g
< ><FONT color=#0000ff>/* draw arc */ " r1 J0 Z) f; L
arc(midx, midy, stangle, endangle, radius); </FONT></P>! k N, \2 o* c2 a8 D+ G9 R
<P><FONT color=#0000ff>/* clean up */ / o; q- o, {0 [
getch(); # R! N1 ` l- y* J; l/ V1 m' [5 ]3 ^
closegraph();
6 C5 h4 M* t$ e# s% [. W Freturn 0;
; V! H% M' O+ \: P3 W}
S- V' y2 U i% @& R</FONT>
/ u. o+ _$ {4 q3 x* ?2 ^</P>" p+ a6 a+ e: Z' @9 |4 v( c+ Y
<P><FONT color=#ff0000>函数名: asctime </FONT>
! ?: c3 I- z0 e; i# T6 M功 能: 转换日期和时间为ASCII码
5 K4 b: o3 z+ G# N# x3 a6 Z用 法: char *asctime(const struct tm *tblock); + U$ a- D8 V' V( X" E p' A4 s1 Q
程序例:
' o+ G& h b z7 l! i: o<FONT color=#0000ff>#include <STDIO.H>
4 n% X( H- G: e" J1 D$ t; D#include <STRING.H>! b. g3 u8 i/ T" e0 U
#include <TIME.H></FONT></P>" t) A6 N; H8 p0 v
<P><FONT color=#0000ff>int main(void) 6 u) V* V& I, x' M% Z$ b
{
# k4 Q8 k& ]+ m3 G" Ystruct tm t; 7 e& U- u) v: B8 u8 [( @& W' Y
char str[80]; </FONT></P>. r$ Y) r$ M8 Q k7 F
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>$ {. Z# L4 [, @& Q% m/ Y
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
: Z5 n: D9 _. t- s& U) Bt.tm_min = 30; /* Minutes */ 2 A$ u. Q; T- d. t4 B) A
t.tm_hour = 9; /* Hour */
" D: J5 [ B: f5 ~% h5 d" q2 \) kt.tm_mday = 22; /* Day of the Month */ : ]7 L* p0 V+ k. @6 v, r) Y8 i
t.tm_mon = 11; /* Month */
4 W3 k$ V9 A( ~# `8 b0 r0 r: B7 Nt.tm_year = 56; /* Year - does not include century */ 9 t' x9 w3 i+ b4 P
t.tm_wday = 4; /* Day of the week */ ' G+ @6 ^ E$ P
t.tm_yday = 0; /* Does not show in asctime */ * r& u- H/ o: {. F2 A
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
/ R$ ~9 B; G7 ~3 m. A<P><FONT color=#0000ff>/* converts structure to null terminated
" z! ^/ v1 _# lstring */ </FONT></P>
2 D; w, ~" O0 s/ I3 x4 `<P><FONT color=#0000ff>strcpy(str, asctime(&t));
- X. [# E+ G% z1 pprintf("%s\n", str); </FONT></P>
0 S/ a, r/ a8 j7 b<P><FONT color=#0000ff>return 0;
1 F7 d: O, o O! I( P( L: C. g1 t" @}
# Y- e1 n0 y I0 h) u$ ?4 N$ r9 A, p& W- [
</FONT>
+ o7 K: J8 r% N/ S9 f/ i( J</P>& _2 ^1 Z# J3 q7 e& M9 U/ m [5 h+ Y
<P><FONT color=#ff0000>函数名: asin </FONT>
" J: P4 S" ]/ R: N% b" f5 m功 能: 反正弦函数 - H l4 g" T5 b8 \% h
用 法: double asin(double x); , a* n/ b; v N; m
程序例:
4 [$ d" d& ~: j# `<FONT color=#0000ff>#include <STDIO.H>9 k. D# E- K3 u7 t0 h m! H4 V
#include <MATH.H></FONT></P>. ^7 \. K; H& C/ N8 x- j! _
<P><FONT color=#0000ff>int main(void) 4 _* O$ ~# S/ S- e0 z( a0 ] z# }; ~
{
2 j; u3 s* f! V9 z* C7 p( K% Odouble result;
& F* H9 P- e9 ldouble x = 0.5; </FONT></P>3 Z, f+ K) s1 R; q& d- z+ O) P
<P><FONT color=#0000ff>result = asin(x); ; u' p8 }( f. P% G% Q3 N
printf("The arc sin of %lf is %lf\n", x, result); 5 g5 l6 p, B/ Y9 C
return(0); + B7 C. Q9 \8 i# w: x- n8 f+ u! k
}
, |) F# k$ i6 _' H; v; ]+ T</FONT>
% q& e* ?5 w/ \+ W( T% P& w2 C; e' B% K8 N% u
</P>
, z) v0 I& {- C3 o; R1 C! W5 K<P><FONT color=#ff0000>函数名: assert </FONT>
0 K6 p2 ]- Q% V; s9 M功 能: 测试一个条件并可能使程序终止
2 M* }2 m N6 d' j用 法: void assert(int test);
) H* [/ N n3 ]8 l" N4 T* i程序例: ) X2 }8 R5 x; \$ n) F6 C
<FONT color=#0000ff>#include <ASSERT.H>
/ @, z$ Y8 \& ]2 g# ^# S#include <STDIO.H>* N' n/ c, a: \2 w
#include <STDLIB.H></FONT></P>! N6 c1 A4 q- X6 T" ?
<P><FONT color=#0000ff>struct ITEM { 8 g/ B% r3 A' k1 V! Q$ V
int key;
% w+ j6 y" C) U( C4 Rint value;
, I% o3 J$ ~0 S4 K. Y}; </FONT></P>7 T' S. ]1 u3 Z: d" ?- F6 S- n: Q
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */ ! F1 q% s l) G8 o
void additem(struct ITEM *itemptr) { ( ]( [) C) |, O7 @) [2 J7 u
assert(itemptr != NULL);
9 d6 \9 l0 I7 U! ]' E: b4 H/* add item to list */ - T$ T/ D; g2 u/ ^% { h* W
} </FONT></P>
" u! a- L% A. G/ T<P><FONT color=#0000ff>int main(void) : i) c2 z/ o; u/ P) b# A$ R" O* X
{
4 O. F. H* J; Gadditem(NULL); 2 `. g! S0 p, ~3 a) Z9 w% R
return 0;
w/ y' l. l. T: j} 4 j+ _3 x% g7 _0 A# p# T, J
</FONT>& b# {1 \$ ~+ D. ?7 W' a: x
* I$ o/ C4 M! D, D+ Q4 }6 i</P>5 b0 a: ^: i. x" d. e& C0 p6 I' i
<P><FONT color=#ff0000>函数名: atan </FONT>
" [& _( \) U( g( i功 能: 反正切函数
$ l) t' y5 P/ L- G8 }用 法: double atan(double x);
7 p' G! D& @# w* Z& m" h程序例:
6 F7 d- i5 ]2 M- ]0 P<FONT color=#0000ff>#include <STDIO.H>
' j% Y% A' n/ N- N: z* @9 R. ?#include <MATH.H></FONT></P>/ b9 X8 d7 L4 u! P3 m e% F q$ U& g
<P><FONT color=#0000ff>int main(void) . o; D6 e( n5 K P3 P
{
3 }0 o8 @8 v4 @" s+ Odouble result; 5 ^$ E) Z9 z g/ v$ J6 f
double x = 0.5; </FONT></P>
& Q9 _, q1 }" e- R4 D( |( } y<P><FONT color=#0000ff>result = atan(x); _7 i3 ?9 }, R
printf("The arc tangent of %lf is %lf\n", x, result);
* N" F' y" R' f0 h! ~/ ^9 wreturn(0);
& M# q. b; F9 C, r} 6 ^/ b+ j8 ?1 a% m, t
</FONT>& f' p( r+ H& P5 N9 }: K
</P>/ f; B! x" R% m+ T* |6 V$ k
<P><FONT color=#ff0000>函数名: atan2 </FONT>
8 ?5 k3 L6 g) T1 d' M功 能: 计算Y/X的反正切值
# R+ C" V' q$ d3 M* x用 法: double atan2(double y, double x);
2 {+ s, r/ @+ f3 E* O) `程序例: 6 G" c: ]& V) w/ E
<FONT color=#0000ff>#include <STDIO.H>7 y4 m0 h N6 q1 i4 Z& L% O, ?/ K u+ z
#include <MATH.H></FONT></P>
, O0 f; |3 v3 n& ^7 E<P><FONT color=#0000ff>int main(void) * M) s& q' h. A, Y7 R$ m
{ + k5 j8 `8 h8 }7 M7 X. D
double result; ! j2 r. u1 o0 z& L( Q( m! i
double x = 90.0, y = 45.0; </FONT></P>6 J* F$ `4 Q% x
<P><FONT color=#0000ff>result = atan2(y, x);
+ |6 L$ K4 l# i9 aprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result); 3 i8 o; f! b2 N4 r. S1 ~6 N
return 0; ) d& N( [1 ]3 s
} - R, o( d) V- Y {0 |; {) |
</FONT>7 c; ~: H1 c% q* o( l; F
</P>
" q' X' `% K/ u8 s; \; z<P><FONT color=#ff0000>函数名: atexit </FONT>5 H/ E: b( W: I) A* @8 q; i; o
功 能: 注册终止函数
' e; R7 P1 f8 E7 j7 Y) n用 法: int atexit(atexit_t func); # }) Y, b e0 a4 ]! V: F0 l# F
程序例: : p3 z: N( n' L4 P! N: k2 M( N
<FONT color=#0000ff>#include <STDIO.H>
+ s2 p0 D/ O* j0 O: s3 ^#include <STDLIB.H></FONT></P>& N& H# J4 @ Z% a5 S/ B
<P><FONT color=#0000ff>void exit_fn1(void) 9 F% ~* p+ W/ ] T4 B
{
& t) S( h$ D5 R# U5 pprintf("Exit function #1 called\n"); : T. s0 o: {9 s
} </FONT></P>" @' u! p. [* L5 X2 B( V) Q7 y
<P><FONT color=#0000ff>void exit_fn2(void) 7 q' g5 U) C1 w' R
{
7 N( i" }" R: c/ T4 R: ~$ [printf("Exit function #2 called\n");
) E( W- l, X8 H9 p4 v} </FONT></P># Y$ [0 R9 n0 m7 S0 }8 s' i3 M+ M
<P><FONT color=#0000ff>int main(void)
/ C6 u2 B6 Z* b( ^' b2 d{ # Y3 @% E& ^( T; |0 h/ {
/* post exit function #1 */
7 k1 a& E$ ?) I; k, a( T+ Yatexit(exit_fn1); % Y* c7 d, z' Q7 m' `
/* post exit function #2 */ : u, J+ A, p! Y
atexit(exit_fn2);
, C0 [0 R0 `4 q: @+ A6 v- Jreturn 0; : W0 D. O! t$ L2 P6 g" g
}
* P: k3 l7 |4 O+ Y</FONT>/ n' ^' V+ J* `" F; z H3 ?! [
; c. c4 p. f m7 Y: t</P> [0 L2 X$ _' }% I3 J
<P><FONT color=#ff0000>函数名: atof </FONT>8 B4 T$ `! g" ~7 q; O; j" Q- R
功 能: 把字符串转换成浮点数 : e8 y/ v& z7 J7 {. _0 G/ }# v
用 法: double atof(const char *nptr); / _0 l& c$ C0 s& `$ Y" F
程序例:
/ g8 j4 U' u; }. f" g y/ }5 G+ T; p# |<FONT color=#0000ff>#include <STDLIB.H>
5 D% f' ]& D2 ?( b. X#include <STDIO.H></FONT></P> e: N$ }! [# C4 Q( d
<P><FONT color=#0000ff>int main(void)
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float f;
% k! X8 s @/ [' y( U# nchar *str = "12345.67"; </FONT></P>
; G( b8 J2 a) w, f8 K. M1 A<P><FONT color=#0000ff>f = atof(str); : r3 X M2 R9 J7 r$ w/ D$ m. D! @
printf("string = %s float = %f\n", str, f);
+ M# x1 S" S/ c" l! A5 x6 }return 0;
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</FONT>1 @/ H7 \ k+ y" |% j, w7 S5 t
</P>
9 I* \0 W! P" h+ ]6 T. p! O( H" S; Y<P><FONT color=#ff0000>函数名: atoi </FONT>
( e( `: O6 x' X5 k8 Y6 h X6 F功 能: 把字符串转换成长整型数 ! w) g& q: _( o" Q- R+ l$ r' e
用 法: int atoi(const char *nptr);
+ K" z" d9 E2 ~3 ?. C& Y T程序例:
* i+ `$ _5 j% T! J<FONT color=#0000ff>#include <STDLIB.H>
/ R4 @7 X; }, ?9 H- U$ n#include <STDIO.H></FONT></P>
1 Y& q3 \2 l! c1 o% c/ w0 g' T: ^<P><FONT color=#0000ff>int main(void)
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int n;
, Z' M# `+ U6 k6 N; i; n8 Gchar *str = "12345.67"; </FONT></P>3 a8 N- {+ R; @1 y( |
<P><FONT color=#0000ff>n = atoi(str); 9 [3 i3 D7 p$ e- U
printf("string = %s integer = %d\n", str, n);
7 |& z P" L) h! @/ N/ S sreturn 0;
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<P><FONT color=#ff0000>函数名: atol </FONT>( y7 R# m) v9 }7 e% a4 Y5 J# B; J* W
功 能: 把字符串转换成长整型数
: N u$ Q5 l8 K用 法: long atol(const char *nptr);
; s% F! d4 ?# e程序例: </P>' O- p& s1 a X9 g$ g4 |. c5 n$ W
<P><FONT color=#0000ff>#include <STDLIB.H>
% p/ [/ \5 X: M0 X3 s$ t6 [#include <STDIO.H></FONT></P>
% j" N3 v, `3 I: X' S$ s. B' K4 i. ]<P><FONT color=#0000ff>int main(void) 2 i- n% p- h9 r# c- o! T9 c
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long l; " @1 r+ }9 y% W# l( m! M$ i
char *str = "98765432"; </FONT></P>
7 c1 }# w8 g% ^* a( T<P><FONT color=#0000ff>l = atol(lstr);
: N6 z4 x. R, Z$ T' ?& uprintf("string = %s integer = %ld\n", str, l); 5 X* {8 v; t) I% S) B
return(0); # y- ^4 f0 M6 c6 D
}</FONT></P> |
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