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< ><FONT color=#f70909>关键字 <a href="http://hackbase.com/hacker" target="_blank" >数据库</A> 对象
$ k0 n: S: s2 E) o* o原作者姓名 Fang</FONT> </P>" O) y, a- s' E- i' M1 v
< >SQL SERVER8 J" I, p9 w( O' K/ D% H
取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法' l8 j* M* y; s" |1 i- U
系统存储过程sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb</P>
. ^6 i5 q. y' w/ g$ h( C* o7 Y< >或者</P>; R. c& ?! K0 ?# [
< >USE master</P>
) x: S. }" l+ O4 o# I7 T- P% t< >SELECT sysdb.name AS dbname, xlogin.name AS owner FROM sysdatabases AS sysdb LEFT JOIN sysxlogins AS xlogin ON sysdb.sid = xlogin.sid</P>( c) F' a0 x" ~/ H3 d) }" s
< >4 t* @$ U& d, n: T$ t( |9 H, A7 K
sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb获得的内容更准确:第二种方式无法获取Windows NT登陆用户。</P>; ?0 O4 J- I5 _
< >取得表的方法7 j0 E3 Y- ^! i: j3 h
系统存储过程</P>
- `" ~( Q/ `; N< >USE xxx</P>
* H! Z9 `- K8 T( ?< >EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
% _$ T2 Y; y# T+ P1 R( L) ^% |< >或者</P>+ ^1 I c& v. N5 M$ s, U
< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的用户表:</P>$ @. O7 V) m* K* l2 `1 B+ y0 p
< >USE DBAudit$ {% S, `& g- d4 {7 i. ]- O$ s
SELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U'</P>
# ?; m$ P; ~, h4 X< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的系统表:</P>: _1 U5 B6 o) ^" L
< >USE DBAudit6 k) t% E2 U) h N( X
SELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'S'</P>
& M- I1 x4 l( A! @" @& y0 h. a< >或者统一使用:</P>2 d# ]; I _+ y) Y) h2 X9 @& Z
< >USE DBAudit</P>
1 |% i) W& u4 n% `$ F< >SELECT sysobjects.name AS name, sysusers.name AS owner, type, sysobjects.id AS id FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U' OR type = 'S'</P>
$ h7 N" g" Z o$ _ |- g2 M< >注:</P>' C- t# f. w' Z4 m5 V- \( Q5 l+ N9 ~
< >sysobjects中type字段类型解释:</P>
% E. k2 M! ~/ Y# b" u$ n( P/ T< >C = CHECK 约束</P>
2 C E- X! U) Y) P8 R. i< >D = 默认值或 DEFAULT 约束</P>
' s5 d! Y9 b6 ~" `* L, \# v< >F = FOREIGN KEY 约束</P>) R$ C) w" n1 j' c; t6 z; z% e
< >L = 日志</P>
8 q$ M) d& Y: n) _% H0 ?# a3 j0 N< >FN = 标量函数</P>& ?% G8 ]; w9 l
< >IF = 内嵌表函数</P>
/ Y0 Y! ^- P0 p< > = 存储过程</P>
% w( _7 O. ? t5 Q< > K = PRIMARY KEY 约束(类型是 K)</P>
; O5 \- F( X8 Q" F# L0 I4 ^< >RF = 复制筛选存储过程</P>
0 p) O% X, y$ R0 K% Q2 H4 u<P>S = 系统表</P>
( u0 s" g$ h- m, Z B<P>TF = 表函数</P>
: G4 Z0 J/ w8 M- }# E3 _' R<P>TR = 触发器</P>
5 r8 `0 G5 z( P3 \<P>U = 用户表</P>$ t( k: s. Q1 \- S' \" D- C
<P>UQ = UNIQUE 约束(类型是 K)</P>9 a8 o+ x' F- \2 o8 n+ h1 X0 o! {
<P>V = 视图</P>
+ V+ m' ?; x% Q3 l- f t+ N% p9 y" f<P>X = 扩展存储过程</P>* U! N! A( {6 P+ c% y7 C
<P>取得列的方法( R, w! P, r) y* L& P j# f
系统存储过程</P>
+ W" g2 D$ l( k- |5 _6 k<P>USE xxxDatabase</P>& n7 |: J* ~9 m- U# H
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help xxxTable</P>
3 v3 L5 C- b1 E<P>或者</P>
) o- m, E, I8 h! L4 I" A<P>USE xxxDatabase</P>1 n! j Y5 j W. Y% a4 t3 v; T! \: I
<P>SELECT syscolumns.name AS name, systypes.name AS type FROM syscolumns LEFT JOIN systypes ON syscolumns.xtype = systypes.xtype WHERE syscolumns.id = xxxTableId</P>
' \, q# x/ J8 J4 \3 i1 \<P>这两种方法都可以取得包括视图的列。</P>
" U1 m: R& B W8 D, s/ E5 P<P>取得视图的方法3 n' ~& G u' J( C* s1 K7 Y
系统存储过程</P>/ L4 Y& s2 `+ S* J W
<P>USE xxx</P>
5 {( l0 G! @4 K1 h; S7 t<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
& N5 c0 F2 D) N9 I<P>或者</P>
' d/ Y2 _7 o' L( B<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图:</P>
8 F5 A. m+ W. Q/ E<P>USE DBAudit</P> Y3 ^' k- z* \# P7 f7 P
<P>SELECT sysobjects.name AS name, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'V' </P>- v$ F3 I. c& E! l
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图的内容:</P>
' B$ i, R. M: G/ H, ~: G0 E<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
. f, N2 s5 ?3 a; [. K& K) y: j<P>取得存储过程的方法( C7 L- X1 G' P( s+ u6 e+ i0 m
系统存储过程</P>
: w! ?: l6 P8 J, a4 d1 i<P>USE xxx</P>
+ g) j: A0 T, {7 A- \<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
) ~/ w, M5 N: a' t<P>或者</P>
A# w( R8 M6 w3 C }( g<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程:</P>
* a2 B2 C! m' X9 {8 e8 w<P>USE DBAudit</P>
! a3 v3 c% Z' E o" `7 S<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'P' OR type = 'X'</P>
; c% j$ i! c2 E- D% p<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程的内容:</P>( \% Y; \. d+ f7 d* ]# W
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>5 g3 r& h6 w2 [" `4 q X7 y" z
<P>无法获取加密的存储过程。扩展存储过程只能得到dll程序名。</P>
6 u K x& [8 E- B: U y<P>取得函数的方法
% |3 U6 o+ `! E' y' }, Q v: [系统存储过程</P>
* T& W' _# h3 }, q6 X9 |<P>USE xxx</P>
$ x: p0 N0 B( ^7 \3 k<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>) x6 n. v2 x, x. q
<P>或者</P>; E. z2 X* s. L. V8 L x( `
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的各种函数(内嵌函数等):</P>
+ i8 E2 R* I7 t$ ~2 l, a<P>USE DBAudit</P>
- w/ S# R$ T+ ?4 F% F; ?<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'FN' OR type = 'IF' OR type = ‘TF'</P># ^' d) i9 A: R7 ]# d
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的函数的内容:</P>5 |+ H# R4 e& Z; _ h& j% m
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
* J5 b F: F5 y& Q7 b<P>只能获取用户定义的函数内容。</P>
( }" Y+ y2 J! L9 x! }<P>取得触发器的方法
& O9 T6 L7 A" K6 {# y) D系统存储过程</P>
" D5 s# A3 a, I$ t<P>USE xxx</P>
3 w& z' W: D3 `" h, B4 V" V0 Y7 F<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptrigger xxxTable</P>3 A3 w ~2 f8 H# t
<P>或者</P>
! }0 `, W" `0 p1 G- s; r<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的表的触发器:</P>
7 c* M( m" Z# Y5 S) B<P>SELECT sysobj1.name AS name, sysusers.name AS owner FROM sysobjects AS sysobj1 LEFT JOIN sysobjects AS sysobj2 ON sysobj1.parent<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>obj = sysobj2.id LEFT JOIN sysusers ON sysobj1.uid = sysusers.uid WHERE sysobj1.type = 'TR'AND sysobj2.name = 'xxxTable'</P>
' N9 m7 p d( s9 M<P>取得索引的方法' c* r: V' E7 b+ q
系统存储过程</P>
* Q# E0 C" _, z( f# t<P>USE xxx</P>
7 R& ~% p* A9 P; E# i% D: H$ j8 K' z<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpindex xxxTable </P>
( @! w3 l7 R4 x. i: `4 ?<P>用户; t1 P7 b5 m2 m# @6 i) }" B
系统存储过程</P>
9 d9 R4 R; H4 E5 L2 @<P>USE xxx</P>) F' J- D0 R& C2 [! C6 i8 _7 W
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpuser</P>
& b' p }+ q. a+ V+ w0 S& a<P>角色
% g) c" s, Z! D% R& J8 K系统存储过程</P>
* b/ X7 C. }/ L7 n' V1 L8 I<P>USE xxx
* A7 f# T% ~+ k, |4 n vEXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helprole</P>+ {4 ~, [$ G6 Y) b$ X3 |
) F+ g% r# q7 Y0 o. V9 Z6 `<P>ORACLE5 ^" |) P7 d) |! S
特殊2 f5 \7 P1 Z6 r( Y6 `+ P
Ø ORACLE只能连接特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象。</P>
# x) P/ Q# G0 g- L6 j) _<P>Ø ORACLE表必须用用户来区别,否则表可能重名。</P>9 ?" S# V/ O& z& r! ]$ Z8 q, O% Z
<P>Ø ORACLE不能区别系统表或者是用户表,因此只能由管理员选择扫描某些特定用户的表。</P>' e4 j1 u0 w {: R+ B
<P>取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法
/ r3 b$ N1 K i) A" S) w) z, h只能由用户指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描到特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A><a href="http://vip.hackbase.com/" target="_blank" >服务</A>器上的所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>。</P>
1 ~- Q" x, _/ Y<P>取得表的方法% ~0 y% w% T- \) ?3 z& Q; d
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的系统表/视图主要有:</P>
- n3 V" k1 \% s* T$ R<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
) w- L+ v2 `, i; ^<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象以及相关的表。</P>5 u; ]# R( q. B0 X0 X3 d( b% I; a$ q
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
! \( p; U# C+ P<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的对象以及相关的表。</P>
( _) A" r9 g4 p<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>! A+ }" O' ~8 M) T* q0 ~3 \' M; j
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的对象以及相关的表。</P>8 K2 }5 h3 H1 G/ m9 F. K
<P>, E4 u l; S* m3 ]) ~
DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
! n# `0 f7 {$ ?+ L& ~7 n<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有相关的表。</P>8 z; N' C0 V' ?, H
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
3 @& L7 b% a* g& a% r<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的相关的表。</P>
5 `* y% s. n0 R( K<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>4 ^* \6 X f5 L! `
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的相关的表。</P>% o. f% t) W1 _1 v* K
<P>
) r8 e7 [6 `; h" K s" u7 u% }因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES中取得隶属于指定用户的表:</P>
9 @) I, A* @! S. Q* \% G<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE OWNER = 'DBAUDIT';</P>/ O& u' G) I" W8 Z% m
<P>取得隶属于指定表空间的表:</P>
g3 G } V" v<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE TABLESPACE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'DBAUDIT';</P>9 s/ R; y6 s, A0 J% M8 I! A# B# E
<P>
- I, E6 m# m. v也可以不指定用户名,从而取得所有的表。</P>: `* h. l9 K7 F
<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES;</P>
1 @- U7 J- [/ b, A: y A1 h<P>取得列的方法
' M; G$ ^! w1 P/ n6 [# Y7 J存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的列属性的系统表/视图主要有:</P>
+ T" }% ]5 z% r3 z; q& y<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
4 y! B9 j) A$ R" Q描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的表的列属性。, J% o! O0 {( ~3 t" Z" _
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
2 p; ]1 l/ F5 W1 d- W- s描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。
9 t4 B: z# e0 p& N: D fUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
/ f1 t1 o; N1 i5 E' s5 M; v描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的表的列属性。0 U# w& N/ B4 s- h& m, _
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLS</P>* R6 I+ @. ~9 Q( ~. d0 X1 h0 }
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。</P>( E0 T1 f, I$ ^7 e
<P>9 ]$ L) O8 J, n1 p
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS中取得隶属于指定用户的表:0 C# B( F) T4 X9 \ E( ?
SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'TASK' AND OWNER = 'DBAUDIT';</P>
3 z- U1 T6 f) G; y<P>取得视图的方法
7 u* i" v, p- r! d存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>视图的系统表/视图主要有:</P>7 Z; ?( n) F0 i" t0 o; y
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS
1 X, ^. ]2 n# r: w6 z6 D描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的视图的属性。
* M) R# ?8 }' B6 MALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS) d. q3 I3 U( U/ ~ D- b
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的视图的属性。2 N+ y4 T( \: U7 [8 l* \- f
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS</P>
N2 K6 W' T8 s$ f! R# Z# V<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有视图的属性。</P>
! Q" }$ M$ }- `, S<P>! z0 S& X: X8 ]+ g% }5 Y
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS中取得隶属于指定用户的视图:4 ~+ D. E! `; E9 O* ^
SELECT VIEW<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS WHERE OWNER = 'DBAUDIT';</P>8 m2 q `3 {) j6 g. Z; h. @
<P>取得存储过程的方法
; n: n0 C6 D$ t& H存储系统对象的系统表/视图有:</P>
* k# G5 d5 k( g<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>
7 U V, S% p& ]: k' l* x. ~. i# T% f5 y* l6 r<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象。</P>
! [, f* W1 {3 O, X8 G% \<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS" W; @0 j0 t' E+ f/ O7 o, F. g
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的可以访问的对象。8 N+ J* F: T: [ e9 `( t6 _! B
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>1 M: ]$ e; Z! N, p. Z# J
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有的对象。</P>( B8 y$ \" i$ u
<P>SYS<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>0 s2 O/ \, ^) U3 M8 y" S) @: ~
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的系统对象。?</P>/ m* x# S a0 x3 t/ ^2 u" R
<P>$ y. C! N. l" j4 P( e
对象类型有:</P>5 U( S5 J+ E7 ?1 J% |6 S8 G$ M& K
<P>CONSUMER GROUP</P>
" k# a/ w3 P1 \8 q( g7 }<P>CONTEXT</P>
1 P& V3 O8 E) U* u5 t! a<P>DIRECTORY</P>
+ d2 V, i7 f5 v<P>FUNCTION</P>2 U) l; E7 H: @4 s/ z% X8 J+ e
<P>INDEX</P>/ ~" t4 v" z+ ~- q* b: \
<P>INDEX PARTITION</P>
9 B; _) F+ U- k7 y& r9 y! Q. h<P>INDEXTYPE</P>
4 N9 A% N z; }+ j, l- N* W3 l<P>JAVA CLASS</P>5 e# @- R9 Y# k+ m; |" p# E- `
<P>JAVA DATA</P>6 n: F% Y4 r+ b4 a7 y) H
<P>JAVA RESOURCE</P>
. q5 u0 u. T$ g) L, n( m. f/ d1 f<P>JAVA SOURCE</P>( T A; K' T( F4 v, S
<P>LIBRARY</P>
- \* f8 N: _$ \ k<P>LOB</P>
' @2 V9 C0 k }% @% p<P>MATERIALIZED VIEW</P>
4 K8 D8 a' L! E! m<P>OPERATOR</P>
( N' e5 [: M% v4 A<P>PACKAGE</P>
$ g9 T$ R3 X+ `<P>PACKAGE BODY</P>
! n B$ ~/ M' D0 ~7 _<P>PROCEDURE</P>8 @/ {, k6 @* s9 y- N7 o: q
<P>QUEUE</P>
7 J3 B: ^; W5 F<P>SEQUENCE</P>
7 W" k, X9 z3 B9 y<P>SYNONYM</P>2 y3 t6 O, i) e. `7 K$ ~- C" _9 R
<P>TABLE</P>* K, n, W: F' P: p! g. q4 \
<P>TABLE PARTITION</P>: _8 W$ f: [) C" N, e7 y
<P>TRIGGER</P>7 ~1 p# D5 }# ~* |1 G
<P>TYPE</P>
2 g% r% n& v" j( V% l1 {7 S2 {<P>TYPE BODY</P>
2 Q0 u$ j& d% c4 b J( j- V+ I, h<P>VIEW</P>3 P5 v, Z. b6 J2 O( M2 H! b1 J
<P>1 f- r* V4 p2 ?' m* r
因此,取得存储过程可以用:</P>& K8 B4 Y6 Y6 S) D
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE';</P>
4 P+ F/ m) P& f<P>取得隶属于某个用户的存储过程可以用:</P>
: G3 {3 H' i7 S/ P3 S<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE' AND OWNER = ‘DBAUDIT';</P>4 e- K ~, @: B7 ]9 T9 O
<P>* c( `" u o; e1 U
同样,取得其他的对象也可以用这个方法,包括表,视图等。</P># R0 e2 r0 B; R% |% _% a; u
<P>取得存储过程内容的方法
0 t9 K, o9 T8 [. h对象类型为类型、类型体、过程、函数、包、包体,JAVA源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的所有对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>都存储在几个系统表/视图中:</P>
! N7 K* w/ b6 L+ [1 [<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>5 K/ m0 a5 S/ \# d# P! Q
<P>存储所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>' z. o4 o! A) h( ?! P J
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE# c; h4 k. e4 H3 m& w9 ]8 @
存储所有可以访问的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。9 G+ }! ]( D0 Z* y T
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>
! y5 k5 v( a( w$ C7 ^<P>存储所有当前用户拥有的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>
`" }( p# S" C( W/ b$ @, w" I<P>
' j( ^: B& a7 P. n g! E6 B7 Z因此,取得存储过程源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的方法:</P>
7 D- n$ m+ o% x7 E1 Z9 E<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = ‘XXX' AND TYPE = ‘PROCEDURE';</P>
! \5 @; l( H7 C8 {3 k+ g<P>取得函数的方法
4 \3 t7 W! m4 l' R- f* j4 f同上,取得函数可以用:</P> @ M- v5 y/ u T# U& o6 y
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION';</P>
# z8 r/ K7 S V8 N3 H7 ]/ d<P>取得隶属于某个用户的函数可以用:</P>5 s/ T1 F" ^5 m$ I4 x; T
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION' AND OWNER = 'DBAUDIT';</P>( V/ w$ x* G/ x8 r( ?2 z
<P>
7 w: j$ r& b5 k取得函数内容可以用:</P>
- ^2 k6 G5 q( G7 T, T1 Y<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = 'XXX' AND TYPE = 'FUNCTION';</P>
1 ^) U9 e+ `% t0 {<P>取得触发器的方法; A- d- Z$ d0 [& B* P {
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>触发器的系统表/视图主要有:</P>
. `4 h, l u+ T. t! p2 z3 ^) g<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS
* ^5 ~8 n) }% c; j6 E( _# O描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的触发器的属性。5 J$ q! T6 Q) [3 U
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS
( m" |! Z7 m, ?0 z- G9 F6 k- O& P描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的触发器的属性。
; | ]2 O+ A, \) m0 e9 _4 d% c. LUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS</P>/ k1 R( q" J2 s( {3 o3 N, W, {
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有触发器的属性。</P>
# T7 Q/ T. w* A1 |8 e# B<P>9 D# Z5 ]+ Z! w$ i' ^- n. ^
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS中取得隶属于指定用户的触发器:8 H: X, }5 X: T' W' D
SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE OWNER = 'DBAUDIT';</P>. U) I5 y- L4 Y7 [5 ~" a
<P>& T$ @4 q9 A+ O0 D
取得触发器内容的方法:</P>
- N- A2 r+ k2 E<P>SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>BODY FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX';</P>
+ w' L' S4 I g1 j3 S* G<P>取得索引的方法
& D8 i# u3 U" _! i1 m存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>索引的系统表/视图主要有:</P>+ i4 N) |& ]2 o/ q5 e8 x/ C
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES
6 w3 W) X8 a+ |* X描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的索引的属性。
, l( U4 g+ ]" g, d' gALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES
% M& ]( o$ {( p描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的索引的属性。! p+ n' N) O. g, x) ?
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES</P>$ e7 k: [7 { a+ E& s: ^7 u- j
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有索引的属性。</P>
- d; m4 |" ^- L- `<P>
# h. I8 V& }) l: R5 b! |因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES中取得隶属于指定用户的索引:
" k1 |* r4 \, d+ NSELECT INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME,TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES WHERE OWNER = 'DBAUDIT';</P>
* a" \* b/ m: H& r0 e- x; n<P>- |+ {* s( m- [0 c0 g, P# s
取得索引相关的列的方法:</P>) A' O4 a+ L3 c+ Q
<P>SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>IND<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX' AND TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OWNER = 'DBAUDIT';</P>) C2 \$ [& ~3 k! T. `3 |
<P>用户
" k0 ]( X+ x- \, q/ Z8 r存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>用户的系统表/视图主要有:</P>$ V1 w; s- M% e% H2 r6 O! a8 X
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS, j0 e* j7 Y8 H3 K6 c
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。, r3 Y( v; P+ Q
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS
' A2 a' M: C/ v1 }. d3 `描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。
7 X* _7 h- B8 Q2 D6 N* V; tUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS</P>
8 o! ^) R% L+ H2 F" b3 j. Z9 l8 V3 F: v<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户的属性。</P>
/ I- U1 ?1 L- h B! ?% ?3 j( c: W5 S<P>% I# I: t6 q1 k( g8 M/ [
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS中取得用户:
# C& S4 S4 }1 U+ ]) r% x- bSELECT USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ID, USERNAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS;</P> |
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