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< ><FONT color=#f70909>关键字 <a href="http://hackbase.com/hacker" target="_blank" >数据库</A> 对象& k; T4 g& o8 @
原作者姓名 Fang</FONT> </P>. M+ j( U6 o' g- v
< >SQL SERVER
; P* Y8 L, H2 L+ i/ B2 B取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法$ J* q' I+ c0 O4 c
系统存储过程sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb</P>
/ m* Q% @/ \% T. Q0 c+ k/ G+ w< >或者</P>! q3 k1 w, o& Q+ Q# i
< >USE master</P>
. L' u3 C: o: Z8 r/ M< >SELECT sysdb.name AS dbname, xlogin.name AS owner FROM sysdatabases AS sysdb LEFT JOIN sysxlogins AS xlogin ON sysdb.sid = xlogin.sid</P>, c f9 r. [* e8 t& B
< >
& `" _, u4 e& q1 D- \6 C! S3 C {sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb获得的内容更准确:第二种方式无法获取Windows NT登陆用户。</P>* r; |# W2 n6 G& z" b- c0 S8 b! O
< >取得表的方法: S7 K2 }0 j6 i5 w' h3 U
系统存储过程</P>
% o! S2 Z% ~ b9 M6 y0 S< >USE xxx</P>" t8 }0 G. Q. E u9 s) F, q8 L
< >EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>- ? Z( W% r* L3 d: j. h
< >或者</P>
2 u L& ^. |" c. z< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的用户表:</P>
, G4 a% t0 x& f8 ?8 n< >USE DBAudit
: M* b1 Z% a$ C, xSELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U'</P>, o, n. H m3 ?. r# y9 w. \4 X
< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的系统表:</P>
3 o' U: l6 E1 y- H, z |. X< >USE DBAudit. T$ A b. S* D
SELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'S'</P>, Z6 u; S# U4 f+ _; w
< >或者统一使用:</P>: i- P6 s. q& [6 I! f
< >USE DBAudit</P>3 t5 s }* ]2 k7 w+ G7 o
< >SELECT sysobjects.name AS name, sysusers.name AS owner, type, sysobjects.id AS id FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U' OR type = 'S'</P>
0 Y& E! X' c- ?3 k4 W0 ^< >注:</P>
: T, ~8 D' H1 Q, X7 r, |< >sysobjects中type字段类型解释:</P>
6 c# @8 H$ D8 a% q, y< >C = CHECK 约束</P>
2 D6 T6 D/ z3 ^# {# C& ]% r4 }< >D = 默认值或 DEFAULT 约束</P>. j" u* b" ?. T+ Q7 [3 |9 L
< >F = FOREIGN KEY 约束</P>
; I* x1 C# u; E8 J: K< >L = 日志</P>
) n" x8 r( O' H) ?) |< >FN = 标量函数</P>
7 M2 Y1 l7 M; Q/ R5 V. I< >IF = 内嵌表函数</P>
! V# {- p% j1 D- G3 _9 Y< > = 存储过程</P>
- |9 ~& J6 z" Y X. Y& X* H< > K = PRIMARY KEY 约束(类型是 K)</P>4 ?( w% _8 |) d$ M
< >RF = 复制筛选存储过程</P>
( @0 t" B# {0 f( y3 D# \4 ^; l<P>S = 系统表</P>! |& O8 @. H& y" h
<P>TF = 表函数</P>
X/ W# J. Y2 ?/ z6 w<P>TR = 触发器</P>/ _: `3 O; ?: Z5 Y
<P>U = 用户表</P>
: A8 }6 v' ]: ^7 z x6 M8 f2 |<P>UQ = UNIQUE 约束(类型是 K)</P>8 E' }9 M0 \ g0 z
<P>V = 视图</P>
& R+ h: y7 n7 M! V, [3 b0 V<P>X = 扩展存储过程</P>
5 \0 C/ ]! }/ z- C<P>取得列的方法/ T$ x% ?% x% Y/ k
系统存储过程</P> t# y( q9 }: K+ Y1 ?5 N$ E+ _8 V
<P>USE xxxDatabase</P>8 d& {2 l9 L. J( `3 {4 |
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help xxxTable</P>
( M- c' f+ O+ v0 K" X<P>或者</P>* C5 q' h/ z4 x$ P
<P>USE xxxDatabase</P>
: F; j# f2 K' u8 S, A( m<P>SELECT syscolumns.name AS name, systypes.name AS type FROM syscolumns LEFT JOIN systypes ON syscolumns.xtype = systypes.xtype WHERE syscolumns.id = xxxTableId</P>: ~* c7 I4 [) K3 H7 {
<P>这两种方法都可以取得包括视图的列。</P>
0 c! n9 ^& m5 [* ]) G8 O<P>取得视图的方法
# A) L* R9 z X( O: u* A4 B& C系统存储过程</P>( N/ Z! z U9 X. {0 _ s7 G( b b* E
<P>USE xxx</P>8 a3 I" f( e$ a! W c+ `( }
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
# k# M) t( @% p3 s: k<P>或者</P>) M. I9 w+ c' g2 }8 F
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图:</P>
& D. F- c- `7 {! e<P>USE DBAudit</P> d0 U& S. ]$ s- T- q
<P>SELECT sysobjects.name AS name, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'V' </P>
( a. J9 o& ]; A3 \) o<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图的内容:</P>) \* K0 f- ^# t$ i
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
1 J! K% N8 t) g9 x/ k<P>取得存储过程的方法
% N, z$ r6 @+ b1 N. @系统存储过程</P>
6 s) o1 M/ I6 a5 ^' \1 G<P>USE xxx</P>
: A- y! Q3 B2 `9 E' k& r" y<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
4 \) Z4 J; I2 K" a! k; ]<P>或者</P>7 ~3 O. m% z$ D$ z" p
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程:</P>. }# j# y% x$ ] ]. j
<P>USE DBAudit</P>
% v( V. J# b$ A5 K: R' T( V* w<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'P' OR type = 'X'</P>& X9 ?6 D# w$ p& g6 F
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程的内容:</P>5 g+ V! r2 ]% Y' J
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>* w0 q6 u1 i! e& i8 V& Y
<P>无法获取加密的存储过程。扩展存储过程只能得到dll程序名。</P>1 P K2 N1 x& K" Z$ l
<P>取得函数的方法
) D* }, d# D% P, v1 k! `系统存储过程</P>: `+ Q; ?. @8 F2 _1 R# W3 P, M
<P>USE xxx</P>
4 u, L# t1 H+ i5 A6 G<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
0 H- Y: q# e# p v$ a$ D$ |6 q<P>或者</P>
/ N. f4 L/ V" G8 P<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的各种函数(内嵌函数等):</P>5 B0 X9 _0 B, G4 }8 u, n; D
<P>USE DBAudit</P>4 d9 x2 l J2 X# f* n$ K
<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'FN' OR type = 'IF' OR type = ‘TF'</P>
. ?9 g M" Y- F<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的函数的内容:</P>
9 |/ Q4 B R7 n/ V* u* r<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
4 Z8 _/ v. G/ J8 W% g9 Q9 i<P>只能获取用户定义的函数内容。</P>1 k7 e/ u& h: _* K: W" @) Y
<P>取得触发器的方法* E3 s) S5 a9 a
系统存储过程</P>
' \' z, d( c! N8 ?; v<P>USE xxx</P>
2 t" D$ [" q: a<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptrigger xxxTable</P>
& A" B$ o: Z; A" d5 q4 j6 p7 O<P>或者</P>
; u3 ]; [7 R# e( j f2 q<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的表的触发器:</P>* t$ D, C/ c5 X
<P>SELECT sysobj1.name AS name, sysusers.name AS owner FROM sysobjects AS sysobj1 LEFT JOIN sysobjects AS sysobj2 ON sysobj1.parent<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>obj = sysobj2.id LEFT JOIN sysusers ON sysobj1.uid = sysusers.uid WHERE sysobj1.type = 'TR'AND sysobj2.name = 'xxxTable'</P>& X J' P5 V: G: m$ j2 n" Z
<P>取得索引的方法
$ @6 [& n" j: D4 j% F( \$ R系统存储过程</P>
; e5 M0 I( S- c7 e$ ~# @<P>USE xxx</P>
! J4 X& R @) |, I( \<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpindex xxxTable </P>* w1 U, P7 a: ]: E3 X& E4 Q
<P>用户
6 \3 y. @- B* ^2 c7 z系统存储过程</P>
8 n9 P$ c: C9 e9 Z6 @<P>USE xxx</P>9 e) `+ F5 w! g) @$ Z) C
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpuser</P>
6 }5 B& @, k5 V<P>角色
4 N* c, b8 n: f) _9 U4 T系统存储过程</P>' ?0 P. c8 T& E) r# |% @
<P>USE xxx9 s \) f( n! X5 G: s
EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helprole</P>
! q4 ?+ i! B/ P% j+ K
3 {* u* b4 V! y* r/ t, d2 ~+ P H/ x<P>ORACLE
7 w: n6 {2 Y2 R; I. @7 s% q. B2 c特殊
7 `' |0 f6 d U# q) Z5 wØ ORACLE只能连接特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象。</P>
$ H. D0 z# L. O+ b, A<P>Ø ORACLE表必须用用户来区别,否则表可能重名。</P>
! u# B3 c" |6 n) N* }<P>Ø ORACLE不能区别系统表或者是用户表,因此只能由管理员选择扫描某些特定用户的表。</P>
, R$ r7 Q$ x: |. Q<P>取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法. m" C2 D) N- I0 C$ v
只能由用户指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描到特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A><a href="http://vip.hackbase.com/" target="_blank" >服务</A>器上的所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>。</P>
# \2 M0 w& c2 f& G2 m2 I/ J% b0 @% ?<P>取得表的方法
- b1 ^/ ]2 K6 L8 v: P存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的系统表/视图主要有:</P>& ?9 ^4 n* x5 ]4 L5 Q T# _. Y9 s ?" o
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
% L6 ]4 [8 t: g+ l<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象以及相关的表。</P>: G+ [7 s, a; ]# E" `5 y
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
! n7 ]. ^; Q- d! h; q0 ? F |<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的对象以及相关的表。</P>; F( ]' p" W4 P* q$ P" N
<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>9 m+ I. _- i3 U M5 H% i
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的对象以及相关的表。</P>; h# H0 m" c$ u0 \: L
<P>
0 W# g( i' H. ^; k& M1 l fDBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
9 L0 s0 f0 ~5 h: V<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有相关的表。</P>
' L) c2 @1 F1 s# A1 a: }, w. I<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>" _, W6 K, t" Y
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的相关的表。</P>
' ^* a1 h5 {: p! }<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>& n) G |8 Q1 t; s. A9 }
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的相关的表。</P>
' B4 {4 X X: ^; R2 p) v" W, V6 k<P>- N- |' _3 }+ D8 m. V7 f
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES中取得隶属于指定用户的表:</P>
4 T# n5 z$ O' Y6 N<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE OWNER = 'DBAUDIT';</P>; T4 C2 R X2 ^6 l, C
<P>取得隶属于指定表空间的表:</P>7 O' y3 | W* h2 `8 E7 u2 N4 L$ |
<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE TABLESPACE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'DBAUDIT';</P>9 ]1 j5 h# U$ K! L2 r O
<P>
5 W$ [, M7 T+ i! ` n/ c; x# D也可以不指定用户名,从而取得所有的表。</P>+ Y8 o5 m t4 @4 m6 a6 U; G2 J
<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES;</P> r2 d) }( W( N, S" X
<P>取得列的方法6 q% P0 f+ U* v& K+ B5 o
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的列属性的系统表/视图主要有:</P>" G& G- d: { U: E$ W" _
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
' Z( Q2 R4 W' a# J1 F* y# p7 B描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的表的列属性。. X; w. h& b9 X/ @) J+ e% ]5 g
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
( S; s. r6 L, A/ T, J描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。: c( [; b: T W8 k* d! A# y
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS3 L& P4 @+ ?' V/ I
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的表的列属性。
. ~7 h& ~; o, y V( a; @6 I& _. LALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLS</P>
. J7 V; N: i; |* o) S: B' r<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。</P>
5 @6 w% H4 C- |% h<P>% o! v5 N- H) M0 b( O. G; b9 T
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS中取得隶属于指定用户的表:
. b1 z! o$ |9 ?! D$ c6 pSELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'TASK' AND OWNER = 'DBAUDIT';</P>. |; v; f& F; L0 ?& k, I1 S
<P>取得视图的方法4 a: O+ k' S1 N" ~/ ]2 i6 M
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>视图的系统表/视图主要有:</P>
* D2 q3 B0 c' b5 l<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS
/ B8 y% @# x% U" M" Y, p5 l$ k描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的视图的属性。
: b# c1 z$ \3 K$ t$ PALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS
+ s8 F) S; G# N2 `$ V' B/ w描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的视图的属性。
" j5 r* l2 K( \ @1 LUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS</P>
+ q8 }8 V' r- l<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有视图的属性。</P>2 d2 ~7 `7 w' T- @: X
<P>; Q' e n& u5 `% N1 b9 v+ s- |
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS中取得隶属于指定用户的视图:- f- R0 p# ?, j* b" P
SELECT VIEW<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS WHERE OWNER = 'DBAUDIT';</P>
& S7 @- K! _# r4 F<P>取得存储过程的方法' [! P+ S7 U# z% C, m( e$ `
存储系统对象的系统表/视图有:</P>
0 F# Z, t1 ]3 ^* W0 M<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>
* Z. x# O& d- U* G G: R* m* U<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象。</P>
8 {$ D- h0 N* ?3 O" H<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS
6 w1 Y$ L! } Y& l/ y/ d描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的可以访问的对象。
% |% `+ D" t- P& \USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>7 |- k3 N( U& R5 E n0 V) k
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有的对象。</P>3 V w% I5 H& _; l
<P>SYS<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>
2 Q; B; U3 ]& [<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的系统对象。?</P>" w, N' }) c, ^
<P>" U; m3 X8 V9 A$ \3 Y* k0 C& Y7 A
对象类型有:</P>
1 X4 M4 V; S$ a( o<P>CONSUMER GROUP</P>
. I* X& g: T7 s' e<P>CONTEXT</P>
9 {& R5 d+ z, ?' E4 N) m<P>DIRECTORY</P>" R: |2 W( X% f+ d
<P>FUNCTION</P>7 l) f8 F4 A9 _" o3 e
<P>INDEX</P>0 R% K- J" {9 n3 G' K7 W3 m
<P>INDEX PARTITION</P>
/ u: K" q' y) Y5 ~* p<P>INDEXTYPE</P>
3 x% y8 q- ]* U<P>JAVA CLASS</P>
/ \! `- {' T- p<P>JAVA DATA</P>* x) z( [. U R2 k: i
<P>JAVA RESOURCE</P>, [; h% X, J3 z. D6 ~5 j4 \
<P>JAVA SOURCE</P>
( L n2 Q9 L, [1 a<P>LIBRARY</P>
/ k3 b8 u: n6 s% P$ f b<P>LOB</P>1 T0 ^* Q7 }' S8 h6 a+ m
<P>MATERIALIZED VIEW</P>
( G. ~& H- o# M! N<P>OPERATOR</P>
I2 x) W4 [* s6 c) X* [" n" [<P>PACKAGE</P>! P. I! G$ `2 g4 N
<P>PACKAGE BODY</P>
7 x2 B0 L% B# m' I<P>PROCEDURE</P>- p* _7 Q: @/ O1 I( N
<P>QUEUE</P>
* _, v/ _. ^3 I& G2 H0 q9 s( C- F<P>SEQUENCE</P>; F, S5 k) ]. a H, X# R
<P>SYNONYM</P>3 Q; ^8 Y% V( w9 i: E6 f
<P>TABLE</P> p' [& n; E' V* \/ T; D
<P>TABLE PARTITION</P>
3 Z3 d; P: i0 F. o1 Q7 w<P>TRIGGER</P>: K- b i# D5 }) x- a
<P>TYPE</P>. X1 v. M* U8 F# @ e" P& X
<P>TYPE BODY</P>
8 T2 y" t3 b# e U0 V<P>VIEW</P>3 n$ B* W- V% p
<P>
" i: |. |! L1 {. L1 W0 l { @因此,取得存储过程可以用:</P>
, G: I* a& `7 I$ m0 E* l6 A<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE';</P>- ?; c- c2 Q0 N+ c% ^7 C
<P>取得隶属于某个用户的存储过程可以用:</P>/ j/ p; D3 @! Z2 |
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE' AND OWNER = ‘DBAUDIT';</P>' k' M0 c1 o' D8 j9 Z \( i
<P>
8 ^& u. S! S# O同样,取得其他的对象也可以用这个方法,包括表,视图等。</P>, e- o) G6 L) G e: `2 T( R
<P>取得存储过程内容的方法0 l: ~6 m) p: w, c. Z7 M
对象类型为类型、类型体、过程、函数、包、包体,JAVA源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的所有对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>都存储在几个系统表/视图中:</P>
; O3 q2 A6 u4 Q: L D$ B% I( C( F<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>9 A- b. t: i. M2 H7 L
<P>存储所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>3 z) A1 ? E' w- b S
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE! ^2 k: Y1 T0 J2 |) I P" \
存储所有可以访问的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。
2 @8 O F+ h" O8 H- q, M2 T3 tUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>
" E# Z2 [( C8 F# q. {3 m<P>存储所有当前用户拥有的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>
) g2 S: @2 J: o8 p<P>
% v4 E z: G. k4 O因此,取得存储过程源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的方法:</P># k6 P k3 f2 g
<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = ‘XXX' AND TYPE = ‘PROCEDURE';</P>
5 Y9 z0 n* C7 \ Z7 u6 r" p1 o<P>取得函数的方法# }; R) H! w/ j
同上,取得函数可以用:</P>6 q1 S4 e' v: J. E% [8 `
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION';</P>
# Q; e8 k0 W0 i# T1 k: B+ Y<P>取得隶属于某个用户的函数可以用:</P>& i5 ?) `& n4 t9 p# }9 R
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION' AND OWNER = 'DBAUDIT';</P>" }7 ?$ F- N( K* q8 m+ Q
<P>
* p# @% [5 _' m+ k3 \3 s' r取得函数内容可以用:</P>
) N" s2 m' J4 a1 H<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = 'XXX' AND TYPE = 'FUNCTION';</P>4 D9 V0 D" T: U! F* a
<P>取得触发器的方法8 Z$ c, p# |7 l0 k3 L2 z( F) k% Q
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>触发器的系统表/视图主要有:</P>$ C8 R1 G0 }7 u2 ^! A) d
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS1 _3 K- g- K9 P$ z
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的触发器的属性。
$ O6 `( R1 [! e) t9 r5 QALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS
4 M5 O0 F/ N9 Q b3 w+ |描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的触发器的属性。2 m+ y0 A0 b8 j7 J: D Y! H) ^
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS</P>! i5 J n' Z( u$ B+ F+ x7 |& Z
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有触发器的属性。</P>
0 k8 V2 I# K2 o<P>6 `3 a( Y7 U7 ?2 L& x$ G
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS中取得隶属于指定用户的触发器:
+ E% g( m2 f* V: n3 D; tSELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE OWNER = 'DBAUDIT';</P>7 j% y0 W1 f1 I0 O& i0 [' s
<P>9 @. n) c, y+ O2 P; k3 N* h D
取得触发器内容的方法:</P>
, k O0 `: X/ V% n7 j' f& W0 P" n: y<P>SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>BODY FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX';</P>5 n/ S6 l6 K1 |& K/ X$ ?5 A" S
<P>取得索引的方法% x) D. _. I, @( L% F- T
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>索引的系统表/视图主要有:</P> W2 `" b$ G" f8 x, I8 Q6 ?/ h
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES7 [' P2 g. D0 w8 u" K2 c8 f$ M
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的索引的属性。
1 U7 d3 n4 l- I$ Y, mALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES
/ [ |+ n% S: ]2 E描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的索引的属性。: |# S6 F5 L4 F
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES</P>$ V: F, i: }3 e6 n; s
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有索引的属性。</P>
7 ]( O) o( S1 S<P>
+ t: }0 ]; P1 L) Y" U* \因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES中取得隶属于指定用户的索引:
; [- j8 v. j. `" t: H7 cSELECT INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME,TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES WHERE OWNER = 'DBAUDIT';</P>
8 F! V ^) Y6 v, |<P>
% P' G8 O! D9 l) @0 Z' K取得索引相关的列的方法:</P>( R% b/ G% s+ x' y, |5 R1 |/ s w* E
<P>SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>IND<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX' AND TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OWNER = 'DBAUDIT';</P>$ k6 b& K& i* o8 D& E
<P>用户
6 H6 A8 }9 H% ^. u* U; v: I7 h存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>用户的系统表/视图主要有:</P>
) Q) b# x" S2 x<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS; t9 m7 Q- B7 [
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。% p3 @2 { X+ k B7 B
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS& Z( g6 t) s: m( K! o8 C e
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。4 X+ f1 i3 B o) f0 Q) R8 n. W
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS</P>
7 y2 y- b4 x- k' u" E! J" K2 @<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户的属性。</P>' F$ q/ B5 H3 ]8 \* l
<P>' S/ h8 L0 c* ?2 h! j" {8 ^
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS中取得用户:
) u, V- u0 J# r U5 {2 `. `, vSELECT USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ID, USERNAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS;</P> |
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