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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
2 z! [, I( M. z2 A( ^2 f3 k< ><FONT color=#ff0000>函数名: abort </FONT>
1 X& Q8 I { n( M: n0 e. ?- p功 能: 异常终止一个进程 * o2 e9 Y. \8 r
用 法: void abort(void);
; `- f' E! M" K" W& ]$ }程序例: 7 p4 _3 D* B x3 O6 K
<FONT color=#0000ff>#include <STDIO.H>0 {! z* O7 g- h9 y
#include <STDLIB.H></FONT></P>; E* a2 G/ A0 ?. B" [5 J; b5 ^! [
< ><FONT color=#0000ff>int main(void)
, X- Z6 p, V3 E9 V{
% W6 X3 J0 l7 \$ O+ x7 K, u8 @printf("Calling abort()\n"); ; S+ T$ G W4 ^$ c8 f
abort();
O. g4 Q! x. a: Y9 l! Creturn 0; /* This is never reached */ . P% K3 a; Q) a5 n
} 3 z* ]0 q. g3 T. f' `4 O
</FONT>' y1 D$ c$ Y% `# J q4 _
</P>
. Q, n+ F1 B: D0 q3 p8 z< ><FONT color=#ff0000>函数名: abs </FONT>- ~; L% w2 D2 o" M; q
功 能: 求整数的绝对值
/ G; m- [: |" T用 法: int abs(int i);
7 m5 i# Y5 ~' E* p. K程序例:
6 _7 x( R$ z( w1 t3 @8 C<FONT color=#0000ff>#include <STDIO.H>& w8 K1 t; O+ I$ K4 D$ Q: a
#include <MATH.H></FONT></P>: n6 o, B3 {$ e% I
< ><FONT color=#0000ff>int main(void) % _9 \; D1 B' w3 { G6 w
{ ) {1 [8 [; B( m! [5 ]* n
int number = -1234; </FONT></P>
- x0 h3 V( n% A" G, j< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
* y6 K8 G( h F9 T* L$ kreturn 0; 3 p8 Z- `4 i7 I' m
} " p6 i7 _) q$ g M3 Z6 A* |/ E* ~1 c
</FONT>& O- \, _" T9 H, j2 f! a0 }
</P>' t* O6 A8 q1 U4 u2 {, z! G
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>
. R' n. x- z L" x功 能: 绝对磁盘扇区读、写数据 # ^6 N+ X. P9 _3 H* r+ w
用 法: int absread(int drive, int nsects, int sectno, void *buffer); # ~( R7 [6 x) |$ B6 _0 c
int abswrite(int drive, int nsects, in tsectno, void *buffer); - e% z- H/ E5 Y2 m% a
程序例: ) R: @. B7 Z1 m4 m( b5 E
<FONT color=#0000ff>/* absread example */ </FONT></P>
3 G) E$ \6 J& \# L; A< ><FONT color=#0000ff>#include <STDIO.H>
# j2 T: V n6 o1 H7 B& d/ E& `#include <CONIO.H> R3 V! @- }" x
#include < ROCESS.H>
9 J3 ?3 k% }" K" m, `#include <DOS.H></FONT></P>9 H P* e) W# ?" D) K
< ><FONT color=#0000ff>int main(void) * k. n" b- S" o# `) S
{
; Q/ H2 ], Q, _; ]: v7 m! {int i, strt, ch_out, sector; : p7 b, E+ P" H& [
char buf[512]; </FONT></P>
7 f5 N: v% z5 g< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
4 p2 y4 h5 |& q' rgetch();
g) f# f! o+ Isector = 0; ( `# o6 V0 [3 Y; R- u H
if (absread(0, 1, sector, &buf) != 0) 4 _1 C9 E+ p- b6 [
{
& `0 {# ^1 Y0 Vperror("Disk problem");
+ H- F; _5 ~& W5 X" Nexit(1);
/ g8 l4 }$ j$ s4 P}
2 V9 e! s: ?- a R5 `8 A8 uprintf("Read OK\n");
* u+ F1 t6 P+ s8 `strt = 3; 6 A9 n( R. \/ z+ X( G
for (i=0; i<80; i++)
- g& r7 t% Z t, w{
: d; W: M9 k- kch_out = buf[strt+i]; . ^# y8 a0 a4 z- r( I% F+ f
putchar(ch_out); 9 v# V$ E1 C5 u& o- K% m! ~) ~( [
}
: l- k; S, p E. Oprintf("\n");
2 |1 S1 Y# R C( r9 p" ]$ Freturn(0);
9 b0 r4 s; W/ g/ |} $ K; E! {5 ~% O1 o8 o
</FONT>% h- Y9 Z& H- d
& @- R; Z) k$ B M</P>6 _, i5 q7 E2 g( }
< ><FONT color=#ff0000>函数名: access </FONT>
+ C; |3 p5 |: P8 Q功 能: 确定文件的访问权限 + d. |9 G X- {" J2 Z
用 法: int access(const char *filename, int amode);
" |4 z$ J% X7 k0 n$ J4 {程序例: / O. J7 I2 K2 K A
<FONT color=#0000ff>#include <STDIO.H>
; }4 j( t6 y* S#include <IO.H></FONT></P>' x; a- w5 B7 k- C
< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>! i/ s% F: O5 u- L8 `
< ><FONT color=#0000ff>int main(void) 8 L% p& L! h" x/ @# `# O* Y
{ # m, l* F$ l; ^5 \" T+ U" r
printf("Does NOTEXIST.FIL exist: %s\n", 8 _. e o$ `1 v! U* x- D
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
5 u( N$ ]+ ` r4 \( m. T0 nreturn 0;
1 k* |* o5 l6 ?# v* x! e} </FONT></P>
# _1 i, P5 Z* `* n# ~< ><FONT color=#0000ff>int file_exists(char *filename)
) ~1 m: [/ R" S; E" G{ l- t3 G6 h# T/ Q
return (access(filename, 0) == 0);
" a# S' \- R9 z: ^} & o. R. Z) P2 l- y2 X) R# i: S3 K
</FONT></P>
* _0 S4 r: k' H; B- v< ><FONT color=#ff0000>函数名: acos </FONT>; {% w' I2 F1 N N8 Z3 @
功 能: 反余弦函数 1 v. Z7 ~* v6 p$ T
用 法: double acos(double x);
8 E* l, d( Z; q' A7 ]( H/ C程序例: ; A; X) u4 d; D' }
<FONT color=#0000ff>#include <STDIO.H>
, c: a- p. W2 p$ T+ m#include <MATH.H></FONT></P>9 Z' v) B" {+ n* H9 d
< ><FONT color=#0000ff>int main(void)
- D# j6 B* @3 Y: ~{ ' z2 D# D) X! r: }
double result;
/ _4 {! U; L" j8 ydouble x = 0.5; </FONT></P>
2 a9 m2 K1 i* Z" X" ~< ><FONT color=#0000ff>result = acos(x);
) V" b0 _" G5 f$ t3 H3 f0 Uprintf("The arc cosine of %lf is %lf\n", x, result); $ e- W; F1 r0 s, J/ D; ]
return 0;
* |) p* r) y/ C# M, c} </FONT>
. e- t4 Q. A; b$ H
1 t0 P. {+ B2 W2 ~# S! T</P>& `2 r) _, P- g, u- j$ W
< ><FONT color=#ff0000>函数名: allocmem </FONT>/ {) B# r3 [3 S: U1 T3 v
功 能: 分配DOS存储段 5 I0 }6 c, c |- y* ?
用 法: int allocmem(unsigned size, unsigned *seg); ( ]9 J: O, P5 D$ c% S$ M
程序例: 4 J3 j2 |3 O8 v1 k( U
<FONT color=#0000ff>#include <DOS.H>
% C) M; p/ I6 P8 c& D6 r& ^#include <ALLOC.H>
( t+ V, R& Q; O#include <STDIO.H></FONT></P>
+ ^, w8 `/ b y" z/ l2 F0 u4 G< ><FONT color=#0000ff>int main(void)
; o8 X: z# F. u2 r9 L! Z2 y; i# h{ / K8 S, _0 r6 T o8 g8 W
unsigned int size, segp; ! h. z0 U, E+ b. e ~/ E$ E6 Z3 e/ P8 M
int stat; </FONT></P>5 d$ Y4 C8 j8 i4 z$ [( B
< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
0 T) G) o7 E9 Z3 cstat = allocmem(size, &segp);
: E1 ?6 y/ k" d& ?1 c5 W. ?if (stat == -1) 7 y' Q/ {! e9 {/ s8 J5 `/ U+ O% M
printf("Allocated memory at segment: %x\n", segp);
3 |! @/ [. W8 r. U7 Y4 t4 selse 1 z! r h8 I3 A8 r$ _
printf("Failed: maximum number of paragraphs available is %u\n",
- |$ x1 G! `8 ]% \. Z# e; Qstat); </FONT></P>
7 g8 U3 I X5 ]7 G9 e6 c< ><FONT color=#0000ff>return 0;
( V! s1 F5 T L& A. \) V} </FONT>6 S, V6 @; j* p% ?$ s4 k$ r
: `0 \' {& l/ }5 e</P>2 r/ G4 w! o3 g; ~( \0 \+ P% j
< ><FONT color=#ff0000>函数名: arc</FONT>
; {) Z7 C( Z: ^5 A* G' B( T7 Q功 能: 画一弧线
% d3 b8 x. h5 X6 K2 p- L用 法: void far arc(int x, int y, int stangle, int endangle, int radius); 6 Q" p# a' [& Y* K( a+ l3 V1 L
程序例: 8 ]3 @) }+ \6 [& |, t
<FONT color=#0000ff>#include <GRAPHICS.H>( W0 G7 B2 k1 k) U
#include <STDLIB.H>
3 h$ a7 `2 T" K* y#include <STDIO.H>
1 u' O: _1 l3 Q; s) M8 B! v5 s#include <CONIO.H></FONT></P>: w! v, C# U& g& Z. {
< ><FONT color=#0000ff>int main(void) 5 J% \2 B' P( A9 P" z
{ 7 `7 ]- r2 }- f7 a
/* request auto detection */ ' |0 E c1 R1 ?- ~/ E# W
int gdriver = DETECT, gmode, errorcode;
1 O/ }/ R, l2 {1 l' kint midx, midy;
! {# G/ `4 ]* G+ X _! tint stangle = 45, endangle = 135; 7 [7 L4 D) J* K$ w
int radius = 100; </FONT></P> j* R; e* Y7 q, I% j8 I4 H6 \4 k+ V
< ><FONT color=#0000ff>/* initialize graphics and local variables */
% E' F$ o4 m- yinitgraph(&gdriver, &gmode, ""); </FONT></P>
+ T: b$ K& W, M. f5 H9 G3 [: Z< ><FONT color=#0000ff>/* read result of initialization */
" Q4 r9 T- o9 P6 _- A1 | m0 oerrorcode = graphresult(); /* an error occurred */ 2 i3 O% v$ G1 X+ m/ k6 R2 K
if (errorcode != grOk) % L+ m* }& s5 g8 r1 K
{ ) S6 |! P* x9 U! c3 }* X+ S- r) ?# I% N, }
printf("Graphics error: %s\n", grapherrormsg(errorcode));
+ D1 f: |! E J0 |printf(" ress any key to halt:"); 9 ^0 g9 Q6 h A/ U1 K
getch(); </FONT></P>
, J% q& V; Z6 P/ i< ><FONT color=#0000ff>exit(1); /* terminate with an error code */ # j( ?# C+ F3 s/ }& D
} </FONT></P>$ h7 o: n: t( i5 X" s9 K2 H& [
< ><FONT color=#0000ff>midx = getmaxx() / 2; $ B; \! d$ L" ^/ j, c
midy = getmaxy() / 2; 9 r. v& i/ B3 q8 @4 M
setcolor(getmaxcolor()); </FONT></P>* e+ y6 N% Z9 U, B$ |5 i
< ><FONT color=#0000ff>/* draw arc */ ( E) Y7 k) u' e# Q' ^3 {$ z
arc(midx, midy, stangle, endangle, radius); </FONT></P>
+ l6 q8 a! K8 B1 ^8 k$ K<P><FONT color=#0000ff>/* clean up */ 8 M1 p, D% i2 [% P! {* e( L. U
getch();
3 G1 f6 k0 m c. H6 ~closegraph(); 1 i( I) V j% A+ Z. s0 q) m
return 0;
b5 g T/ \/ p9 V j( A2 G} 2 b1 J3 S& q9 R
</FONT>
2 _8 h1 |" k6 Q. p' R& F. `; g' H</P>. Q, b2 u; }9 b6 m
<P><FONT color=#ff0000>函数名: asctime </FONT>
9 K6 Z0 y: S! r# K5 e5 L功 能: 转换日期和时间为ASCII码 - L2 p( d( K1 c, u" j4 L
用 法: char *asctime(const struct tm *tblock); 6 Y, o; O G5 K, ~; D9 [& H/ q
程序例:
; d" N! ]* W; V9 I" P<FONT color=#0000ff>#include <STDIO.H>
' ^& }- Q( N; ?/ D/ f#include <STRING.H>
4 C5 U1 p1 L% z#include <TIME.H></FONT></P>
" Y5 [# |1 g/ s3 m. [& f) O<P><FONT color=#0000ff>int main(void)
# ]% Y a' i; e# x4 M; x{
: g2 ], S: v. z, |7 Hstruct tm t;
1 m6 [5 X4 W* C9 q' X, I# x, i1 nchar str[80]; </FONT></P>0 W( x- F9 U, G0 X- b5 a5 e, B/ _+ a
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
/ C$ z0 C! k$ ~4 L<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
( a2 _% v- L0 Nt.tm_min = 30; /* Minutes */ - v, b1 v" }3 h: F
t.tm_hour = 9; /* Hour */ # M) N7 V+ v/ _( a7 u
t.tm_mday = 22; /* Day of the Month */ 7 d/ O" {7 S. Q- [7 R4 S, B$ Q
t.tm_mon = 11; /* Month */ . Z. u9 ]0 ~7 s' d# a7 G
t.tm_year = 56; /* Year - does not include century */ 3 y% B+ o }7 N3 U, C4 t
t.tm_wday = 4; /* Day of the week */
J7 @# J9 b: w- o- B2 Q# Tt.tm_yday = 0; /* Does not show in asctime */
4 i5 ~8 @# y J! p; x9 rt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>0 d3 c+ N0 p( H. {) A: w
<P><FONT color=#0000ff>/* converts structure to null terminated : y) ~- y2 _# |: B8 m8 V
string */ </FONT></P>
3 O* }6 x: h2 T# I; q<P><FONT color=#0000ff>strcpy(str, asctime(&t)); ! r. C9 q8 D) T, Z& |$ J+ A5 x
printf("%s\n", str); </FONT></P>& P+ ^0 L/ a! s, Q$ e
<P><FONT color=#0000ff>return 0; % g- V k: S: g+ M
} E& K ]1 \& F* {% O
3 j. k4 [. k( J l$ u* p- B% J
</FONT>3 j3 x3 {9 u- Z' t4 N5 ~
</P>
% L& F4 h$ l; \ a& W" F+ D0 _" E( a6 a<P><FONT color=#ff0000>函数名: asin </FONT>
$ [* H( H! q4 f8 D$ A: \2 f$ w' Y功 能: 反正弦函数 / }; s; `1 N: I I
用 法: double asin(double x); " g$ K% z( s5 B' J# ?8 I5 F
程序例: 1 j/ i3 m' Q" h" U4 K/ o# u
<FONT color=#0000ff>#include <STDIO.H>+ v2 p" R% O, V* u; p- V8 c) e
#include <MATH.H></FONT></P>/ N# D! z( `5 I
<P><FONT color=#0000ff>int main(void)
( q ~# ` m6 t1 h v" h4 {8 A{
( m6 O2 p$ l$ l ndouble result; 8 z# C5 }; k/ _" u5 Z& D
double x = 0.5; </FONT></P>+ D. d! ^. G6 g8 M% y# S; c
<P><FONT color=#0000ff>result = asin(x);
. |9 c" @3 J/ p$ F# aprintf("The arc sin of %lf is %lf\n", x, result); - h. \" N6 [# U5 L/ }: X$ n) i- @/ Q# l
return(0); $ J ]9 u7 }; B
} ! _- R! {( d. M! V# F& ~
</FONT>
- B8 p, v7 q/ U+ H" i3 Z# \
5 }7 D; |% a) C</P>
, }9 g+ B& L5 w6 q% `7 g7 K- U$ y<P><FONT color=#ff0000>函数名: assert </FONT># q1 G9 w) v/ o, `1 Z
功 能: 测试一个条件并可能使程序终止
4 p5 i1 r3 c6 F, ` p. B. S0 l1 c" ]用 法: void assert(int test);
5 r$ D8 _" G) U0 S程序例:
4 N& Z1 `1 p( \8 ?" N) k s" Q2 l# o<FONT color=#0000ff>#include <ASSERT.H>. i+ Y; Z U$ G0 U, K, E
#include <STDIO.H>0 z; L7 b6 I; c3 s$ K/ v
#include <STDLIB.H></FONT></P>3 Z4 L. \) Y9 {2 X* Y9 a. w
<P><FONT color=#0000ff>struct ITEM {
, ?, O+ Q* F/ H& I- r2 t1 Vint key;
' U& m7 c! R5 m/ i/ \int value;
/ K2 c; K8 ^% o- @, _" r}; </FONT></P>
) K1 b/ J; \1 ?, x<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
1 Y$ H+ H8 C) y4 |- T1 Y* i* zvoid additem(struct ITEM *itemptr) { , _3 b& s/ Q! J$ z2 T
assert(itemptr != NULL); 0 p/ F$ @4 I& ]% O. o2 ]) l0 p
/* add item to list */ 6 t0 T- m2 u, f7 P# N' d
} </FONT></P>/ m2 e8 L/ k+ o
<P><FONT color=#0000ff>int main(void) 6 S$ y) h% F" w1 E0 v7 R6 S
{ . c* _- b( g9 w) @4 |6 q0 \5 @
additem(NULL);
; m$ t- [# N. ~return 0;
, |( P, N# g) n6 E, Q} " o/ i m$ i& b, I. {
</FONT>
1 o0 B" J( X( V, H5 o0 Y6 M" b- A/ Z* E, ^+ {/ Q K Q! D, I0 D
</P>
3 c1 P6 ] I* O0 ^# n2 P2 Z<P><FONT color=#ff0000>函数名: atan </FONT>
" q& x' n: e: P' d( X6 ~功 能: 反正切函数
; G7 K' c3 C+ p5 t- _7 p0 j+ t用 法: double atan(double x); ' F7 L9 P& B* s
程序例:
7 H# m& s3 R+ a& i. w<FONT color=#0000ff>#include <STDIO.H>9 C6 v" k0 N: `; C0 j
#include <MATH.H></FONT></P>
1 v6 |% \8 X3 [ T! ^: v3 N& S<P><FONT color=#0000ff>int main(void) 3 _$ G$ N8 K# U* M# I0 x
{ 9 o5 i, c Z% F
double result; 7 `4 W( \0 p6 v+ ^" N
double x = 0.5; </FONT></P>, g: X7 Q9 q, Y
<P><FONT color=#0000ff>result = atan(x);
`, H; s2 m% A! g6 dprintf("The arc tangent of %lf is %lf\n", x, result);
3 o- V6 l9 z) `; W# T5 o2 {( N( rreturn(0); 4 ^4 ]# _, E8 u/ N% A8 j
} " l9 V) W7 I V1 ?$ l0 r) l
</FONT>4 n: |5 N; g7 x9 m5 p
</P>* i( i/ ?- ?$ r- {5 Y+ O7 i) j" o
<P><FONT color=#ff0000>函数名: atan2 </FONT>
+ ~0 @9 `4 G5 s: C功 能: 计算Y/X的反正切值 9 }% E6 L5 D2 i% ?1 O8 ^- Y3 Q) U; B
用 法: double atan2(double y, double x); " ^2 _3 R' a V* N# ^
程序例: : q' z: ]- c5 Z
<FONT color=#0000ff>#include <STDIO.H>' E) s. f4 m! O7 \9 o }& D7 k L
#include <MATH.H></FONT></P>. ~4 L$ i8 d3 |* t9 w& r
<P><FONT color=#0000ff>int main(void) . h3 n/ ]* D- E4 U: B; y( e9 v
{ & P, E F# J/ s
double result;
" ~1 O! U* p& l6 z, f9 pdouble x = 90.0, y = 45.0; </FONT></P>/ \9 Z' l9 O3 u' {
<P><FONT color=#0000ff>result = atan2(y, x);
* ~: K$ ]6 ~. ]& @printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
2 D+ M8 z, ^9 j1 dreturn 0;
# w1 g m2 B! v+ d6 k! H}
2 B4 A$ _1 ^( }8 r. A$ P" E</FONT>, K6 T% Q% Z" {* D) v
</P>
, r/ Q4 P+ J/ Z* U9 W5 i: x% q& k<P><FONT color=#ff0000>函数名: atexit </FONT>
* y+ ?& c- W* Q) h: S功 能: 注册终止函数 1 n0 x& I5 `! d
用 法: int atexit(atexit_t func); 0 N" Z5 C- @, o' I
程序例: , {4 Z# Y, n- v6 }7 x% n% X% ~
<FONT color=#0000ff>#include <STDIO.H>+ d$ }" g- l k* {0 f
#include <STDLIB.H></FONT></P>; Z8 S; S7 T) x' Y8 Z# q
<P><FONT color=#0000ff>void exit_fn1(void) / }6 L& }: N" g; b; Y0 C; X
{ . G) u3 q3 E4 U% K" t
printf("Exit function #1 called\n"); 1 p( m) {& o! t1 H6 g8 @
} </FONT></P>
) r+ h3 _+ f. o7 M<P><FONT color=#0000ff>void exit_fn2(void)
4 l8 Y6 g& ]3 h" K; h4 A{
( n& I( Q' ]* c! ^6 e1 j7 \printf("Exit function #2 called\n");
( p) t% l- \6 t/ f} </FONT></P>
8 e$ X( L7 m; Q<P><FONT color=#0000ff>int main(void)
' g4 J& }/ {. ^# A% @7 q; Y{
: U: f) F7 b) @0 \$ `1 M# P$ J7 V/* post exit function #1 */ / |6 w4 D* V- _
atexit(exit_fn1); 6 Z6 k) x& [1 ]# K2 {
/* post exit function #2 */
: ]* R( ? o% {5 Y" |atexit(exit_fn2); 9 X1 x8 F# c, ?0 ]
return 0;
7 p6 t0 t, W+ B: e$ ~; [}
1 a' t( u; k8 u2 {* r! b</FONT>
$ i9 B& d! ?% u' N
B7 i6 k, I. d1 f</P>9 s2 a; y7 C0 p! t) c" ^/ B
<P><FONT color=#ff0000>函数名: atof </FONT>4 J6 \* `% k/ V Y" \
功 能: 把字符串转换成浮点数
. {2 e5 E3 {9 s用 法: double atof(const char *nptr);
' L# }& D& p. X程序例: 0 U# q9 ]5 n% @ k! ^# t
<FONT color=#0000ff>#include <STDLIB.H>
A4 F1 D8 f) F. M6 U$ }2 m#include <STDIO.H></FONT></P>
( V# F% `( K/ L% L5 c. E" U- R( K/ M<P><FONT color=#0000ff>int main(void) ; ^: t; G$ z/ ]
{
( n; v# k; W" Hfloat f; 4 ?& ^& g3 n% Z- E7 Q7 Y+ d
char *str = "12345.67"; </FONT></P>8 D; S1 S" ?# b" \; q9 M4 B2 @
<P><FONT color=#0000ff>f = atof(str);
8 L% _3 ], f# k) k3 v2 L/ q# kprintf("string = %s float = %f\n", str, f); 3 F% N8 \) F. ~) t) G+ u) S
return 0; " K: ? i: ]; d
}
& }- y: y, k, l* p2 g& Y$ F</FONT>2 k% y( b! F* s
</P>
% b1 Q6 {4 j& ~% U1 q5 x<P><FONT color=#ff0000>函数名: atoi </FONT>
; @" B! I0 V" C功 能: 把字符串转换成长整型数
* ^9 S k% Z2 p6 E6 z用 法: int atoi(const char *nptr); & }) a1 O4 y) z( U+ V4 \
程序例:
% Z/ d6 U* d! q$ @' t<FONT color=#0000ff>#include <STDLIB.H>
/ q# B5 p& @6 y+ W9 ~#include <STDIO.H></FONT></P>
1 F) G3 l% ^4 H, Y, h0 J<P><FONT color=#0000ff>int main(void) 2 i' c3 e. ]) S: h
{ " e% N* N" h, e
int n; 0 P D: p' T R: j) u- W
char *str = "12345.67"; </FONT></P>
, q$ l _/ E6 g<P><FONT color=#0000ff>n = atoi(str); / z* [7 F6 m5 K& c+ V% e: s
printf("string = %s integer = %d\n", str, n); - a y0 g5 E2 j2 L7 \( w" J# {# N
return 0; 9 ~/ V3 L. R. K/ J: _2 k& }3 _4 `* \
} - y% n1 Z) w; p6 l
</FONT>& b8 W/ x2 o9 I6 k+ m
</P>$ k5 Z* u p7 L- a; l
<P><FONT color=#ff0000>函数名: atol </FONT>, S* u& I P2 M
功 能: 把字符串转换成长整型数 ( {3 N) A( w4 F+ E/ M: _ R
用 法: long atol(const char *nptr);
2 t1 r c+ T+ C& N& s程序例: </P>9 W6 d0 G, g) i/ n' y
<P><FONT color=#0000ff>#include <STDLIB.H>
, u/ {0 h6 W7 a+ ^5 o! V#include <STDIO.H></FONT></P>/ A3 A3 x: C& w' G! q \) Z4 F# q1 |
<P><FONT color=#0000ff>int main(void)
* H" P' c: z6 v) z1 N{
. B' Q* g. n( q$ n, t0 flong l; 7 Z; [3 ]' w/ Y3 L: a$ ^
char *str = "98765432"; </FONT></P>
3 J( g0 E9 p |* j0 W<P><FONT color=#0000ff>l = atol(lstr); ( r X& @4 z/ e( ^0 S* f3 _, V
printf("string = %s integer = %ld\n", str, l); 4 V5 p' u+ [; r% v1 s: w5 Z l6 l
return(0); : f1 ~. G. h6 h$ M. S
}</FONT></P> |
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