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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
1 Z) f, M0 r: t) ]1 v$ m< ><FONT color=#ff0000>函数名: abort </FONT>
" H5 f4 Q5 v. B* E5 ?$ }功 能: 异常终止一个进程
) }+ W- ~3 f& L8 e: E3 b+ }5 I! ~用 法: void abort(void); 2 U8 n, J8 b* |
程序例:
+ {7 h, L0 U9 j7 b( U1 Z<FONT color=#0000ff>#include <STDIO.H>
6 b' P, ~( K( ^3 T& m, t#include <STDLIB.H></FONT></P>
) m9 I; M; N+ t0 }6 k. n1 l< ><FONT color=#0000ff>int main(void) . C7 k7 K3 G7 J: |0 b0 t2 }7 n
{
e) r* s# C: M7 I2 E' Eprintf("Calling abort()\n"); 3 ]% D$ ]( O+ W
abort();
- m+ U4 [; P( p: R0 Wreturn 0; /* This is never reached */
9 w4 @- ~: Q: b7 t) }- c6 |} ( k& a# ]7 h+ K. T
</FONT># A0 {3 k; ?" T& p" r8 c' j+ w
</P>9 b; q, {# P5 I! P
< ><FONT color=#ff0000>函数名: abs </FONT>, R: o' Z2 ?9 d
功 能: 求整数的绝对值 - l( D5 [/ |* N* N
用 法: int abs(int i);
! q+ g4 d' @9 R! j/ I1 [3 d程序例: . ^' \0 J% E A ?
<FONT color=#0000ff>#include <STDIO.H>
' z5 C. O2 s& n8 V6 Z#include <MATH.H></FONT></P>& r# X- y/ k$ ~* B) w
< ><FONT color=#0000ff>int main(void)
0 t, M, t# H/ z7 @" Y1 J" t{
. G; V9 C( K. K" n Bint number = -1234; </FONT></P>
& i* r4 f) n( z: a< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
% T& U" I5 a6 n! }return 0; 4 [' c0 h* z' H' ]
}
5 U! G5 X% F) [& d c3 T" i+ m1 \</FONT>% N9 m1 s0 m5 E9 O L* W {
</P>/ K8 E: g$ m; d% R* h
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>
4 I- C: T. |* `/ t功 能: 绝对磁盘扇区读、写数据 * I# c# O+ f; B/ ?; S
用 法: int absread(int drive, int nsects, int sectno, void *buffer); & P: x, Z, P0 l$ @: M
int abswrite(int drive, int nsects, in tsectno, void *buffer);
/ r' S" H( o" h- ~4 P& I$ l% q程序例: ) W, j" @' j' e
<FONT color=#0000ff>/* absread example */ </FONT></P>6 _( D/ a1 q# W( y7 K' R% h# H
< ><FONT color=#0000ff>#include <STDIO.H>- z3 U& Q7 _' s ?
#include <CONIO.H>
- ?# V2 m9 @ }4 R5 i#include < ROCESS.H>
! |( V& h2 }" Q( j, p4 h" o& q#include <DOS.H></FONT></P>. ]7 k- \2 Y1 c( n7 X6 a, H0 a1 x- ]
< ><FONT color=#0000ff>int main(void)
2 y: U5 D3 o" R- K% p9 \) L, f{ 3 {) C+ i8 z; a3 K# _) W: W* g
int i, strt, ch_out, sector;
; R5 u% A0 G |, J. Q* Echar buf[512]; </FONT></P>5 K A" k6 Y/ n C7 c2 D
< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); $ d4 l1 P g. O/ N
getch();
, c3 y* Y: L( a" B7 |2 nsector = 0; 3 M0 y6 r6 i. I: Q: e
if (absread(0, 1, sector, &buf) != 0)
: g' V1 a8 u8 s6 h! E- E{ ! O8 X0 _+ l8 Q0 q) a
perror("Disk problem");
' w( B ^0 p8 g' m/ x2 m2 X, g' pexit(1);
$ P* J8 [5 P! Y, T w. ]% ^} 5 N f+ Z- I! ^' Q/ @, a
printf("Read OK\n"); : P7 ^' F' {: |/ }
strt = 3;
# q7 R; C& d, X2 S6 |" lfor (i=0; i<80; i++)
/ }6 O9 U8 Z6 R0 P{
/ Q% q* A/ C; M' J2 N% fch_out = buf[strt+i]; ; j4 `$ B, m/ F4 F2 S
putchar(ch_out); 4 }. L+ l# L' d. |/ V! J x5 Z3 M
} # g* C! F% o4 X! Y8 N2 Z
printf("\n");
% U G* J, V0 y* D) A0 F4 k( Yreturn(0); & c0 J8 |8 Y% K9 W; Z$ O
} 0 p5 n* M/ X7 F: D+ t& I2 |+ c1 {
</FONT>
; I: n8 {& A3 L' P r
& {) e. P( A' w( \6 V</P>
. g% b( `3 _8 A D< ><FONT color=#ff0000>函数名: access </FONT>/ j8 }& j% f9 @/ h9 `: W
功 能: 确定文件的访问权限
' P+ M. M" ~) q9 E! G( ^ g8 X q2 Q用 法: int access(const char *filename, int amode);
& {/ H( _- y4 |- G8 G程序例: 7 I* o! J C4 I0 j$ ^
<FONT color=#0000ff>#include <STDIO.H>* p( g' A5 r8 `7 ~" m* r) R* _1 }6 L
#include <IO.H></FONT></P>
7 ]& f7 i! ~: T" a+ {" g< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
/ d( j- |! b3 y4 a( X. E< ><FONT color=#0000ff>int main(void)
% a8 ?. I x4 i# H" g{
; z R% B, O& W, e2 Z7 Yprintf("Does NOTEXIST.FIL exist: %s\n",
# k8 z7 N3 j8 Qfile_exists("NOTEXISTS.FIL") ? "YES" : "NO");
( O/ p' j1 y7 d$ creturn 0; 2 A; `: C/ j5 s& f% s! }* w
} </FONT></P>
3 b5 F, }0 s5 w- g7 e3 G< ><FONT color=#0000ff>int file_exists(char *filename) ; V' \- k5 A( q* E
{ ; l8 h' P! n7 _1 ^) ]
return (access(filename, 0) == 0); - r- l& g9 |, m
}
" {5 Z0 V2 e) v' A% c9 j</FONT></P>
! B5 @* e7 M0 H6 z0 R+ L6 e< ><FONT color=#ff0000>函数名: acos </FONT>. m# s3 ?( ~; u7 u) ], @$ E
功 能: 反余弦函数 , v" M s/ O0 [. `7 k3 U- @
用 法: double acos(double x);
p9 {8 p$ s" Y) o& Y1 @程序例: 8 G- P; U& p' @/ m
<FONT color=#0000ff>#include <STDIO.H>) ` L0 w+ y" ^: k
#include <MATH.H></FONT></P>
9 j$ d- g3 }& O1 k< ><FONT color=#0000ff>int main(void) ) ?* t1 i7 e w/ u
{
2 P% w9 p0 A6 g) cdouble result; + w" d* p# m6 X5 m: v
double x = 0.5; </FONT></P>4 ?) ]3 e2 p. c6 K, T5 z
< ><FONT color=#0000ff>result = acos(x); 7 P/ |4 E; Z7 C P) E
printf("The arc cosine of %lf is %lf\n", x, result); 7 v0 q( S; v9 H% U6 x; h6 Z
return 0; ! s- P8 `" t# Z- B1 U- K* @ \/ F
} </FONT>
% W$ W/ Y! p3 O6 J* l& N* k A! c: \5 u" e' n9 w$ n" D4 O
</P>: K3 V6 m" y& e; f" g
< ><FONT color=#ff0000>函数名: allocmem </FONT>9 B) r# i$ [: @8 ?, A2 f) m
功 能: 分配DOS存储段
. U( o) z I. [4 G. j& g5 H. u( K用 法: int allocmem(unsigned size, unsigned *seg); 1 F7 e: W" I2 W8 Q- l& _
程序例: . W0 Z* q) L# c) n
<FONT color=#0000ff>#include <DOS.H>4 p/ X4 I/ a/ k u. Z$ n
#include <ALLOC.H>' V+ j4 |: _% i, ?* ~& @
#include <STDIO.H></FONT></P>
9 b( x: J# F* ]* V3 o4 E6 W< ><FONT color=#0000ff>int main(void) 7 F. N) q* I; y2 q3 H
{
- A: `! X6 ^' O9 K8 m: v8 uunsigned int size, segp;
- z% w3 S, p1 o0 b K1 n6 ^int stat; </FONT></P>
& [+ ]! Q {5 z- A" Y. v< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ 7 C; J3 o- k, j
stat = allocmem(size, &segp);
# O9 Q% n. l, l: K5 Uif (stat == -1) 6 G( ]- C# G8 ? d
printf("Allocated memory at segment: %x\n", segp);
|# \- D8 h: y& t' Telse
) S, a0 M9 a; e8 ?0 Y5 W) x- Kprintf("Failed: maximum number of paragraphs available is %u\n",
6 \/ n4 S+ L J2 `stat); </FONT></P>
3 f; V, _# K5 K" [' I1 y< ><FONT color=#0000ff>return 0; + f( d" Z5 Q" A( g! ^7 v2 o
} </FONT>' ?& I. J |+ {6 m$ J4 t6 w
9 {& j. z2 E8 v4 o; V; x6 [
</P>
! O) w# ]' `& W' @+ p! e4 Q< ><FONT color=#ff0000>函数名: arc</FONT>
, g& o' A4 _+ ^& Q3 X$ b' o功 能: 画一弧线 ! h% w& j5 l# x
用 法: void far arc(int x, int y, int stangle, int endangle, int radius); * v1 v, o. y" i% d/ q$ l
程序例:
" F6 m; i+ g, z) G9 J<FONT color=#0000ff>#include <GRAPHICS.H>
, F4 d) @; f& d+ f1 }6 L#include <STDLIB.H>
# K+ l* g, w( w/ C" p( b' H#include <STDIO.H>
7 J8 _) f \" v3 D5 k% s, B% f: u#include <CONIO.H></FONT></P>1 N: |( l# t! q0 \
< ><FONT color=#0000ff>int main(void)
* p3 R# V6 D4 V+ R0 M* ~{ - v4 Y# V% e" Q O' ~
/* request auto detection */
! U' C% F, }3 N$ ?- D4 jint gdriver = DETECT, gmode, errorcode; 0 X( F/ _/ b3 I8 `4 i, a
int midx, midy; 3 t" D) l) h% G* W$ b, T) a. p5 G
int stangle = 45, endangle = 135; # a1 X6 D! X" p3 A C5 t+ Y
int radius = 100; </FONT></P>( q# ~5 ]: }8 f: v5 t: b
< ><FONT color=#0000ff>/* initialize graphics and local variables */ ) r- k5 S. m" t0 `) d
initgraph(&gdriver, &gmode, ""); </FONT></P>
" F$ }! k! ^, C" L8 ^0 y$ N< ><FONT color=#0000ff>/* read result of initialization */
0 z3 P) f: |- U1 a, x5 Rerrorcode = graphresult(); /* an error occurred */ " f" `- {/ B5 T& m# w# E0 ?: i1 P
if (errorcode != grOk) ; q2 P: @* z9 |9 L( P5 P
{
$ ~6 D% U& Y m7 Qprintf("Graphics error: %s\n", grapherrormsg(errorcode)); 5 U2 U* B0 z3 K% U. ^
printf(" ress any key to halt:");
/ J+ ~/ w- w0 i% H, I; r! wgetch(); </FONT></P>
2 K4 R: `6 J" e. U' r+ R< ><FONT color=#0000ff>exit(1); /* terminate with an error code */ 9 o+ `4 R6 o: z: n, v: Q7 u
} </FONT></P>
' Q$ z" {9 w0 h< ><FONT color=#0000ff>midx = getmaxx() / 2; 4 V: o& ]7 z! h9 m% b
midy = getmaxy() / 2;
. i( U( W. F1 O0 ^3 v% asetcolor(getmaxcolor()); </FONT></P>7 r; O7 F2 E% `
< ><FONT color=#0000ff>/* draw arc */
+ n$ M( f/ X* l# f/ E' A$ xarc(midx, midy, stangle, endangle, radius); </FONT></P>- w |% J7 X* E, w5 q
<P><FONT color=#0000ff>/* clean up */
, Z" y) b5 [# agetch(); 1 E3 j/ Y$ m2 I$ t5 ?. L
closegraph();
9 U1 ^/ A0 b5 W# h) D8 \+ O1 s$ \return 0; 4 w+ B8 K& U9 i' S7 x' W7 u
} 7 B3 O& E! K4 F6 [. K T" z1 |7 O
</FONT>
2 z, L C& L ]; P7 ]</P>
5 l1 m! W- O% d8 d+ Z9 `<P><FONT color=#ff0000>函数名: asctime </FONT>) s8 N! @/ u, M; B( R
功 能: 转换日期和时间为ASCII码
* W% ]+ b- Y0 E' ?+ W r) q3 R8 _用 法: char *asctime(const struct tm *tblock); 3 k$ z1 t6 }+ Q9 M$ U! O
程序例:
! l+ n, c+ Y: s<FONT color=#0000ff>#include <STDIO.H>
9 ], F8 \/ T1 h" Y#include <STRING.H>
) e/ U, G- W" y$ [( Y' o& E" e$ o#include <TIME.H></FONT></P> f& e' q4 Q3 t- i/ s
<P><FONT color=#0000ff>int main(void)
+ G. D& P% ]+ G: o{
$ |8 t0 K6 f! P% u% O5 A! l. w8 o& Rstruct tm t;
3 d3 n: ^( _0 c$ C4 h1 Mchar str[80]; </FONT></P>6 t2 W$ B1 y7 Y5 p2 K1 f
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
! o) ?: Y, \: }4 n' J<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
- Q4 @. L( N, Z% ?* Ut.tm_min = 30; /* Minutes */ # p V$ ]7 l) o4 A) y
t.tm_hour = 9; /* Hour */
$ E) F- \+ s3 l, @' It.tm_mday = 22; /* Day of the Month */ # R: E7 {9 W) K O X' I
t.tm_mon = 11; /* Month */
Q) ?4 m8 w6 E2 N( e8 jt.tm_year = 56; /* Year - does not include century */
' r. H/ ^% H1 V% _1 [7 M8 It.tm_wday = 4; /* Day of the week */
3 s" W2 U4 {: B& x, j- Bt.tm_yday = 0; /* Does not show in asctime */
. ^. }7 C. m% y) [: pt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
0 t$ u3 v) W& d9 W<P><FONT color=#0000ff>/* converts structure to null terminated ( ]+ l; I, r1 o2 V9 S
string */ </FONT></P>! @! P! i# N) g. I. T- z9 y
<P><FONT color=#0000ff>strcpy(str, asctime(&t));
0 [9 b' A' m$ Q5 p" K6 ?printf("%s\n", str); </FONT></P>5 X& N9 j+ G$ e, N" r6 i
<P><FONT color=#0000ff>return 0; ) K3 f( A, [ n0 ]' ?- K: |
}
7 R' }3 u- t) ?( U8 m/ O G% X$ R5 ]4 J/ f' u
</FONT>7 O) Q5 A5 o3 v3 m3 [8 n
</P>
% K7 L) f) B! X' k i<P><FONT color=#ff0000>函数名: asin </FONT>
8 G7 }4 M& T3 L4 g功 能: 反正弦函数 ) `. O8 S( F$ N# l y( [
用 法: double asin(double x); 5 @; C o, i; | J, S0 a, Y/ h
程序例: ( Y4 C4 Z1 R! l l4 y5 E. @" g
<FONT color=#0000ff>#include <STDIO.H>
) f. M! p* R. U7 K, E7 g#include <MATH.H></FONT></P>
9 q8 E( b& a) H4 Q<P><FONT color=#0000ff>int main(void)
6 _1 a5 k( c9 o( j: L3 S0 l9 i+ R{ ( z/ V* B: u# P; M# L; x. |) p
double result; 1 ?! F7 u1 e" \% b3 K3 D+ x
double x = 0.5; </FONT></P>. T! p& l) C( Y& b0 D. _1 m
<P><FONT color=#0000ff>result = asin(x);
8 f. q4 a4 m: s6 K2 n# Rprintf("The arc sin of %lf is %lf\n", x, result);
& J; C/ l; x- x2 ]6 ?+ ureturn(0); 4 ? P* L- H9 a% m1 ]
}
- S, c$ m1 h5 ?- s* w d L% Z* |! _</FONT>
4 ]4 Y% U- \3 Y# b! Z, ^
6 u2 w( e( c$ g. q</P>* f5 V; h3 F' `2 [
<P><FONT color=#ff0000>函数名: assert </FONT>
$ ^* G3 W v' O5 [* R0 F功 能: 测试一个条件并可能使程序终止 : m6 i' w! j0 m/ h7 e
用 法: void assert(int test); 9 I" U( W8 z+ d; ]$ N
程序例:
# ]- B q' i8 H7 Y8 s. _<FONT color=#0000ff>#include <ASSERT.H>8 z X! y4 W V3 g. d
#include <STDIO.H>! E) l. G F" x) X4 m* z
#include <STDLIB.H></FONT></P>
9 I/ o! W$ D/ m<P><FONT color=#0000ff>struct ITEM { $ G/ W4 _0 l5 O6 z K
int key;
Q* X5 e' q0 h" j% iint value;
' C8 Y' A. M# V) f}; </FONT></P>
8 R- G! k4 m. {$ V3 [<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
3 l& [$ p% q$ hvoid additem(struct ITEM *itemptr) {
# D. l4 O4 N: r0 E" I- Sassert(itemptr != NULL);
Z: _! G2 Y. P9 k/* add item to list */
) X: V5 i) ]( F; D# y+ I. W} </FONT></P>* Q g, b1 U. U
<P><FONT color=#0000ff>int main(void)
+ D1 d6 O2 R/ ~{ 8 a9 y) Y7 P- D! \
additem(NULL);
7 J: w" @2 Y% p: B" Lreturn 0;
! Q. v- C% b$ g/ S8 n}
# m* n7 F7 J' V5 S* r4 ^' g</FONT>; r. @- F i1 I! x) X v+ u
% y0 f; u, e) l/ x$ ]! R( @</P>
2 w! O( h$ z$ u<P><FONT color=#ff0000>函数名: atan </FONT>
! e: v5 `# H: \功 能: 反正切函数 ) ]' d6 z* ~3 T3 |2 M8 V
用 法: double atan(double x); 8 A. E7 A3 f( T, v
程序例:
) O2 }+ f1 y- j! s<FONT color=#0000ff>#include <STDIO.H>8 F0 t* T, n2 d; l
#include <MATH.H></FONT></P>
5 }7 `/ O; e6 A5 x1 c5 v/ Q<P><FONT color=#0000ff>int main(void) 9 ]7 Z3 i1 t- Z
{ 6 m( w0 Z; h6 m7 |; o
double result; 8 F- u I' P! x* H$ e# f
double x = 0.5; </FONT></P>
+ _7 t$ @7 P* P+ O% ~! }<P><FONT color=#0000ff>result = atan(x); $ t7 s8 C1 R! ?( Q) S
printf("The arc tangent of %lf is %lf\n", x, result);
: [- H! E8 n, vreturn(0); * D4 ~& v- c* u+ {. H: G
} $ e' [( `6 s& i# M% T+ w7 Q
</FONT>
+ J/ h4 v C5 y" u2 j</P>. c1 s( y$ |4 `' T) M
<P><FONT color=#ff0000>函数名: atan2 </FONT>8 I2 h4 H/ p% Z" p, w5 J
功 能: 计算Y/X的反正切值 9 C& g, ], ~1 {, z: a
用 法: double atan2(double y, double x);
5 o" s# ?) Z% \+ K, p程序例: ' L3 S4 T( m, H5 I
<FONT color=#0000ff>#include <STDIO.H>
* F% n- e: n/ Q3 ?2 Z6 ^ Y#include <MATH.H></FONT></P>
4 l# ~2 ^, Q( Z u$ \3 W* M4 r E<P><FONT color=#0000ff>int main(void) . ?1 _, G# u( N1 W* Q
{ 0 a7 m; O" w s: f
double result; 6 X/ N; I' R/ G/ @1 `
double x = 90.0, y = 45.0; </FONT></P>
: Z+ q! a8 K' v/ v<P><FONT color=#0000ff>result = atan2(y, x); / \& B/ k8 C2 q( o$ P0 S. E
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result); ; q9 g9 u1 E( P& D/ e1 b# H
return 0; ; T! N3 B/ E& u. C
} % M" s' D% s% x3 u0 b* }& V) O
</FONT>
4 x l6 D" |0 Q( f9 d</P>
7 d# x) U; y/ ?- \2 N* D1 S6 p<P><FONT color=#ff0000>函数名: atexit </FONT>/ j v* o! \# \; f; n
功 能: 注册终止函数
1 ]7 [$ E" ?4 X: s ~5 I' a用 法: int atexit(atexit_t func);
4 R; {8 Y( O9 u0 e程序例: ! I. B- d1 P) P" u, O! P
<FONT color=#0000ff>#include <STDIO.H>
4 u" H/ U! g. i1 a& o/ @! y#include <STDLIB.H></FONT></P>0 n" f2 b7 k! H( ?
<P><FONT color=#0000ff>void exit_fn1(void) 0 g5 u7 h3 C2 v. x
{
6 f, c; g1 j! ?5 F: Bprintf("Exit function #1 called\n");
$ x h a6 u/ f/ G} </FONT></P>
' m8 M& |( W& a6 v' Q# N/ F! ]<P><FONT color=#0000ff>void exit_fn2(void)
/ A h! y& W0 U4 I# s{ 7 l+ c2 G8 w' A4 Z L8 s
printf("Exit function #2 called\n"); 7 H+ K& f7 x d! F2 z m! ^
} </FONT></P>% U9 s% ~7 Y) V, B! i6 E; u" A6 l
<P><FONT color=#0000ff>int main(void)
: Q X9 O% |9 u' C0 q{
9 `2 d O# V& d4 B; ~/* post exit function #1 */ - y! t/ B" n$ H3 W( B
atexit(exit_fn1); , G8 P+ Z: F9 @4 w/ ?
/* post exit function #2 */ ! _2 y8 j* V* q" W$ a, Y
atexit(exit_fn2); , b, b% w3 b6 m5 {1 w* Q8 p r1 H A
return 0;
. h" W+ `- b& k$ {7 U' J4 d} ' t# V: l8 v4 O$ J/ q2 I$ d
</FONT>. \; q( ~# d+ h. ~/ ~
5 T4 J( T& D- V0 b, M
</P>
% m& `6 C3 x- b<P><FONT color=#ff0000>函数名: atof </FONT>% z# w0 h$ J3 m: }
功 能: 把字符串转换成浮点数 0 M/ Z8 b9 M# h7 X! M+ f& }
用 法: double atof(const char *nptr); 6 n: }6 F2 C( A5 q4 v4 }* |
程序例: 8 B2 ^" X/ ]: s$ q& [+ P* Q
<FONT color=#0000ff>#include <STDLIB.H># r9 c, O/ e6 h4 `
#include <STDIO.H></FONT></P>
! A6 Z) @/ P" v0 }( R7 y<P><FONT color=#0000ff>int main(void)
, G' n$ P& f5 G8 ]+ V{ + y" |) [) q. S8 |0 E6 ^
float f;
8 Z% J* O8 T0 L& Echar *str = "12345.67"; </FONT></P>7 A- j T0 Y/ r) I" M
<P><FONT color=#0000ff>f = atof(str); # k) A, R5 a9 f7 Y3 ?6 i. @, S
printf("string = %s float = %f\n", str, f);
1 \6 F9 T. c' d0 j8 M1 ^0 m9 jreturn 0; 2 y& {2 a# ]" G$ b( C# c
} " f: V8 G9 N2 t
</FONT>
) K7 J6 G$ ]; P, d. j</P>* ~, C' K+ `$ C: s H& {. A9 e
<P><FONT color=#ff0000>函数名: atoi </FONT>
3 S9 L; Z: h) _6 d! r4 h: s+ ~功 能: 把字符串转换成长整型数
7 N; L# C# u% |; S2 r0 F1 l% B用 法: int atoi(const char *nptr);
" ]2 l9 f" J0 `6 `8 g( V5 v程序例:
% Q0 K! ~5 j) f/ e! \( E5 t4 n<FONT color=#0000ff>#include <STDLIB.H>
/ \' T/ n+ D8 l# m, O#include <STDIO.H></FONT></P>6 B) X2 y/ Y8 a7 v) @0 m5 Z/ W
<P><FONT color=#0000ff>int main(void)
6 e& `8 I8 U! o* E) h$ y1 c, o{
# ]& N" Y, Y% d! V ?4 fint n; ! a- m9 @$ E& ~ O9 L- a( t3 R
char *str = "12345.67"; </FONT></P>5 o3 k N: l4 A m. l' p9 p
<P><FONT color=#0000ff>n = atoi(str); # q: a$ d' s+ Q0 G4 t, ~% K
printf("string = %s integer = %d\n", str, n);
: u* n- ]+ Y8 E. d. ^* Preturn 0; ! V% K1 i! b- |4 `
}
1 w0 ?7 l# F7 Q/ R6 e</FONT>
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<P><FONT color=#ff0000>函数名: atol </FONT>8 N% x. a8 J. N/ x2 f
功 能: 把字符串转换成长整型数 - R+ w! {) a+ u( y4 ~8 o% Y1 ?
用 法: long atol(const char *nptr);
2 s' _. K1 j' u$ ^# K1 f程序例: </P>- f+ _) G$ V8 l2 G# x
<P><FONT color=#0000ff>#include <STDLIB.H>: ]3 z7 z5 o$ P; i
#include <STDIO.H></FONT></P>
8 @* m, I8 v% F<P><FONT color=#0000ff>int main(void)
) G3 ]; l' w2 O9 U0 u8 ~{
% ?5 [) y8 X/ X" Y) x. _2 ?* klong l; ; |/ u- \- ` |8 \* ^, {
char *str = "98765432"; </FONT></P>
& E4 O) p( p2 q$ e1 E3 Q<P><FONT color=#0000ff>l = atol(lstr); * ~; ^6 X7 P6 E+ @$ ?8 ^2 Q% A) E
printf("string = %s integer = %ld\n", str, l); - @. p" G/ {9 A- L' O
return(0); % P* k5 `! D. a5 y9 [, }
}</FONT></P> |
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