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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |倒序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
4 O9 @# m1 [6 g3 M, `<><FONT color=#ff0000>函数名: abort </FONT>' M$ _0 \8 f, Y! W* v
功 能: 异常终止一个进程 : s7 Y! d. H, A  t: t
用 法: void abort(void);
2 {3 j0 O7 u: c4 i" Q; d程序例: * @$ v! z& \7 ]% S* O9 E: v
<FONT color=#0000ff>#include <STDIO.H>/ c! ]" ]( g. w
#include <STDLIB.H></FONT></P>
" r+ w) S2 j6 j- w6 Z" P<><FONT color=#0000ff>int main(void)
, k# d; u& D) m6 u2 V{
' V3 K8 v& H7 p2 G3 L, E" N. N8 Yprintf("Calling abort()\n");
1 ?: \2 O& U, m0 u9 s0 e$ mabort(); : a* N5 ~3 }) u/ t* d1 k: ~( u
return 0; /* This is never reached */
& S: u0 h1 t& P7 a. e} , Y; O6 I( T- p7 b- ?7 Z
</FONT>
! e/ w2 X) m" ]9 j8 _</P>- v, |% z$ M+ Z
<><FONT color=#ff0000>函数名: abs </FONT>
; l( q+ t  X" n. i功 能: 求整数的绝对值 # y' ?) P6 Y1 b0 H+ _* s% Y2 y
用 法: int abs(int i); * B1 R2 f; q+ r, m) k
程序例:
7 q* ~$ s$ c- C3 G<FONT color=#0000ff>#include <STDIO.H>; Q6 j4 v7 E$ k- S3 A
#include <MATH.H></FONT></P>
. l2 H2 C  U9 }/ s2 o9 }# {9 z3 q<><FONT color=#0000ff>int main(void)
; j, ^4 @1 f; d0 \% @3 k{
/ k5 N4 \% U  W# R  Fint number = -1234; </FONT></P>! j: V( Y/ [* e: {& m
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
1 A3 k& n) k# Jreturn 0;
9 C2 }! b9 t+ ~# N8 u} 5 a1 D: o% O) Z; @
</FONT>
+ w+ J9 o0 P, z* @9 o</P>
% s2 ?! D) w: b- q1 Y, a1 m. d<><FONT color=#ff0000>函数名: absread, abswirte </FONT>6 V" e. K: j1 x. C
功 能: 绝对磁盘扇区读、写数据
! K  e" i. y: q$ N2 p( i用 法: int absread(int drive, int nsects, int sectno, void *buffer);
" @8 |- g  E( r. X; Cint abswrite(int drive, int nsects, in tsectno, void *buffer); + `, o/ w6 g: ^" a
程序例: & j  |* s6 B" k! W4 v! V
<FONT color=#0000ff>/* absread example */ </FONT></P>
& {1 ?# f8 S* d6 D<><FONT color=#0000ff>#include <STDIO.H>
( \% K3 b1 K, q8 |/ k# R#include <CONIO.H>
0 [+ n) W0 B, s, ~#include <ROCESS.H>
; X  y' V! C) S! F#include <DOS.H></FONT></P>
% K% N  y* `* [( f3 C<><FONT color=#0000ff>int main(void) . X6 ?. [! G$ H! ?% ^
{
  A8 ]; I6 q' ]int i, strt, ch_out, sector;
# _  J  G; E5 z, lchar buf[512]; </FONT></P>
* @# Q7 [& r1 P  T- v<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); 6 z7 h8 n2 X8 A( K
getch(); # P. V: _) K! [# f
sector = 0;
/ o- z8 w1 [1 q1 n6 {4 Hif (absread(0, 1, sector, &amp;buf) != 0)
6 P5 o. R- k6 D: a: W% D{
9 k  K( O) {: }4 G+ g  g+ Operror("Disk problem"); & g, z# v! ]' L( l7 Z3 c% s  f
exit(1); * ?! G  @9 t2 F; m0 |5 q! t4 _
} 0 `3 Z: `3 |* M0 ~( _
printf("Read OK\n"); / j! M& y' A! {. T
strt = 3;
6 W2 ?, h& }- C' ~% [5 T+ C, z, K2 c  Xfor (i=0; i&lt;80; i++) : V- f& g4 q# u, _6 V
{ $ A% K7 R& F* J/ t  E  K
ch_out = buf[strt+i];
0 v! ]6 Q! E( K% E8 Tputchar(ch_out);
  m7 g3 ~1 ~7 C7 b# @! x} + r! P9 C; _# j+ J/ Q
printf("\n"); 9 U: ?( [4 h8 A2 Q8 i
return(0); $ q$ X$ z5 z3 i: ~
}
' d' i1 y/ s' B</FONT>! x/ L2 t4 l9 h/ t
8 E; W3 Y; b/ X8 G
</P>4 }. e& n1 q1 ~) ]. Q8 N6 _! n
<><FONT color=#ff0000>函数名: access </FONT>
" x" L5 u/ _5 D  ^$ a; y$ ~功 能: 确定文件的访问权限
0 s. ~/ |* ?6 w! c1 v" y6 [用 法: int access(const char *filename, int amode);
+ d. `9 k( z8 }  w1 f程序例: / {+ w, w2 {" i3 L2 J0 t# b0 ?( O# t) M
<FONT color=#0000ff>#include <STDIO.H>7 Q# p5 g& r; {
#include <IO.H></FONT></P>
- O  F# q$ H4 M$ g& ?1 Y/ e1 l<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
0 s4 C$ @) K. b# @<><FONT color=#0000ff>int main(void)
7 B. ~" D4 q$ ~4 E{ ! z# \' O7 o, ^9 K2 K5 n
printf("Does NOTEXIST.FIL exist: %s\n", . ?/ \  j3 z: h4 y) N
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
4 a$ u8 O3 L2 a: a: c$ D5 sreturn 0; 6 A( R1 k) g+ l! ~+ u5 ~
} </FONT></P>$ P: M- m. I- v  u8 ~* F
<><FONT color=#0000ff>int file_exists(char *filename)
9 N- I7 Y3 H- J! ?{
& |7 C+ n! D% Kreturn (access(filename, 0) == 0);
0 X* }4 B2 y! b+ @}
& k( i/ v# ?- M4 Y# m</FONT></P>
3 A8 h3 x6 r. R% Y<><FONT color=#ff0000>函数名: acos </FONT>
/ V% w1 K. U* R4 ?6 P功 能: 反余弦函数
* r9 w( B/ W9 t# J  R& T# A用 法: double acos(double x);
9 t; G! ~6 u, ~程序例:
: ~- Y  O0 H3 y* i4 b) J<FONT color=#0000ff>#include <STDIO.H>
3 V% A- u) }+ x! f#include <MATH.H></FONT></P>
1 ~1 \0 B. ^; v( H" }1 _2 r8 e<><FONT color=#0000ff>int main(void)
$ `1 |& }2 R$ i{
. ]! {% }) G) udouble result; ' R, S2 _+ I) T* Q3 e( p# b
double x = 0.5; </FONT></P>
3 y! K2 T& r/ D" ~# c<><FONT color=#0000ff>result = acos(x); / N! o0 n0 S/ B- f  N
printf("The arc cosine of %lf is %lf\n", x, result); 7 q* l* u7 C- H* u- p
return 0;
* t% Z  n& l0 S- f} </FONT>: a3 J4 K; }1 p6 j
1 a+ J9 D7 a; R! O
</P>
& N& f5 g& k* w' {$ P7 e( O7 |<><FONT color=#ff0000>函数名: allocmem </FONT>: N9 q/ h8 A% r$ j0 g
功 能: 分配DOS存储段 : U7 R1 B# ?# ?3 f; |
用 法: int allocmem(unsigned size, unsigned *seg);
2 z$ o: z6 J, g, n3 G程序例:
  W" g2 W& D! [<FONT color=#0000ff>#include <DOS.H>" \5 m) N7 j( c* A- p
#include <ALLOC.H>9 L5 W: L6 f2 {; z7 I( H- u
#include <STDIO.H></FONT></P>
0 V$ x$ T1 J5 d& V<><FONT color=#0000ff>int main(void)
2 E8 F  |6 L" i* h  z; q7 m8 n{
1 N5 P% Z- }4 @2 L( B4 sunsigned int size, segp;
8 J3 P! D: }2 c3 Q( o4 }' _; M/ yint stat; </FONT></P>4 `& q4 ^1 `3 S. ~: W  A
<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ / a4 U: X) a% V. w6 R, y
stat = allocmem(size, &amp;segp);
8 A) Z* R3 U. G5 E' c- gif (stat == -1)
: g( C2 c, ^9 }4 o1 |printf("Allocated memory at segment: %x\n", segp);
6 q, C- V) g9 v. g" h% R5 |8 }else
9 f! m$ C% @+ O1 V+ Uprintf("Failed: maximum number of paragraphs available is %u\n",
" ^# L: V5 V/ z) h% Z  q% ?* mstat); </FONT></P>
9 P+ W% d/ `/ c0 ~9 r0 Y5 V$ I% A<><FONT color=#0000ff>return 0;
9 Z; R2 d8 ?/ }! w" W$ F  p9 H} </FONT>
) z! F& P2 Z* k. W: |. N1 r5 r2 I1 w1 @
</P>  ^) e; p. g2 {; X% F
<><FONT color=#ff0000>函数名: arc</FONT>
7 i" q5 X3 ?- b3 _8 f6 y0 U功 能: 画一弧线 * f9 _. a" F. J$ N( A7 Z. A
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
6 f4 R5 }" W3 G0 q程序例:
. K2 \$ V: C8 v% u& c4 I/ s<FONT color=#0000ff>#include <GRAPHICS.H>
5 U& R9 h1 O! [2 x0 y#include <STDLIB.H>- [8 @+ ~7 Y  p: I
#include <STDIO.H>
6 M) O( W3 `+ j( X  `#include <CONIO.H></FONT></P>2 E( F; H3 V3 q7 O) N
<><FONT color=#0000ff>int main(void) 3 Y( P$ G4 t" l6 ?4 D9 n
{
/ }' C2 R" J# C5 \  x7 r/* request auto detection */ * L9 J! p( U& f
int gdriver = DETECT, gmode, errorcode;
# g% @; y, ?2 N% ~int midx, midy; ) k- v5 }+ F1 B9 [# _
int stangle = 45, endangle = 135; # g4 O6 _1 f, k2 R' R
int radius = 100; </FONT></P>
" Y# }& ^# T, U1 M- ?<><FONT color=#0000ff>/* initialize graphics and local variables */
9 M. s, @8 ~! p4 X2 |initgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P># c7 k; d# B9 U: N2 D6 [! B) t- ~
<><FONT color=#0000ff>/* read result of initialization */
$ j/ s/ y; u% ^3 Oerrorcode = graphresult(); /* an error occurred */
" O7 v. M' |: Q; s+ Mif (errorcode != grOk)
5 z" ?2 }+ R8 V" h! G{ ( Y+ N+ ?- h" U: I& ?+ ]
printf("Graphics error: %s\n", grapherrormsg(errorcode)); ; ~8 S" _. s* _0 ]& F
printf("ress any key to halt:");
7 B8 G7 o( O1 y$ x6 Jgetch(); </FONT></P>" i: ~+ B5 x/ ]
<><FONT color=#0000ff>exit(1); /* terminate with an error code */ : {) a- ?* e5 Z' U
} </FONT></P>
. V8 W. H; i6 b3 i8 \" r3 f! E& R<><FONT color=#0000ff>midx = getmaxx() / 2;
/ c# j3 ]$ h/ l! L5 amidy = getmaxy() / 2; % w% o- n! J; N$ T& ~* S: r. ?  j
setcolor(getmaxcolor()); </FONT></P>! _9 z. T! G* L
<><FONT color=#0000ff>/* draw arc */
4 l# N3 y. b- u. B. Aarc(midx, midy, stangle, endangle, radius); </FONT></P>7 d* t# R* [3 l: B5 t
<P><FONT color=#0000ff>/* clean up */
. V( D3 c1 R- n0 N' `8 Zgetch(); / N0 I2 `8 d4 r6 N% P7 `( u, |$ `
closegraph();
3 _% r8 q- n1 }/ H: T7 Nreturn 0; 9 v' ]7 q# j# k* k! b* x' b) T
} 2 E3 N. x: L+ p% E7 ]% d: C; v
</FONT>$ q& k  ~& t. r$ s6 b8 S
</P>
. O. R1 V# L8 Q0 I% j7 V<P><FONT color=#ff0000>函数名: asctime </FONT>
# s% d& N8 a3 ]功 能: 转换日期和时间为ASCII码 % d# b0 \% z' D, [4 l: j1 K9 C6 Z7 J
用 法: char *asctime(const struct tm *tblock);
; a9 Q# E* u7 L  k+ a  F! |程序例: 8 A( \8 G  B& M+ s$ y5 }
<FONT color=#0000ff>#include <STDIO.H>
* C, ?1 \/ r& Q, E6 _#include <STRING.H>
4 x3 @# i8 B  ]1 u8 k* w#include <TIME.H></FONT></P>8 z* U# {. \5 l% i
<P><FONT color=#0000ff>int main(void)
' G/ ~8 U; L+ u  T- z* t{
* J) R* A( P5 C  h, h$ tstruct tm t;
# O' r$ d6 z) B% [char str[80]; </FONT></P>8 Z  h- B5 ]+ f6 Y* N% {1 D0 U' |
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
0 ^8 W# M, ~$ C<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ + W8 Z+ \1 ?" R( @
t.tm_min = 30; /* Minutes */
% M' d$ A6 I" R. @* H4 ht.tm_hour = 9; /* Hour */
9 `) L/ G3 v% E$ y, wt.tm_mday = 22; /* Day of the Month */
  L  S7 a: L# _t.tm_mon = 11; /* Month */
, b- M" x/ B) z* a! b8 F7 e0 w( r% Gt.tm_year = 56; /* Year - does not include century */
2 r: S0 o6 r1 Z. W7 dt.tm_wday = 4; /* Day of the week */ ; \$ A( t) I6 w3 @
t.tm_yday = 0; /* Does not show in asctime */ ! Z0 T4 p. b" Q: P# Z4 ?* v: i% W0 C
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
* t% A6 U& p# o- }7 e* \<P><FONT color=#0000ff>/* converts structure to null terminated
* h' r& k" g- t4 C' Fstring */ </FONT></P>( G" j, N4 C- ^8 X( L. G1 y: T
<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t)); 0 o. }7 Z+ u( {; ]0 a
printf("%s\n", str); </FONT></P>* y2 j- ~' A% t
<P><FONT color=#0000ff>return 0;
4 P6 r. T; w8 J5 ]0 ?}   M4 \4 m6 p; X( n

$ A- B5 k3 _' d; A</FONT>, v8 d! q9 j! x; v! |& |8 f6 a6 b
</P>' e  o; P5 G. ^# G: X
<P><FONT color=#ff0000>函数名: asin </FONT>8 R. x2 I7 ^/ c3 i3 F* N
功 能: 反正弦函数 + }; k5 r+ z( }8 f6 r" L) J, J0 `
用 法: double asin(double x); , o0 ]/ C4 f; Z
程序例: . J$ k( S+ @' [2 @6 v) `
<FONT color=#0000ff>#include <STDIO.H>
4 J& M' D0 x( a#include <MATH.H></FONT></P>6 X/ ~% _! Q9 l
<P><FONT color=#0000ff>int main(void)
' b" c* v, r7 r; ~. t& T" f{ & |3 I/ \9 e7 W* r3 O+ v. y6 e  y' f
double result;
' q! O/ Y3 F! D) O/ }double x = 0.5; </FONT></P>
" k8 E# F* {. r' h/ R! v<P><FONT color=#0000ff>result = asin(x); 1 g, N+ k1 B* Y# ]# ]0 s. g, j* u
printf("The arc sin of %lf is %lf\n", x, result);   v! H/ ?' |" U
return(0);
6 s9 c7 D( c; ~}
. b1 y% i. n$ K4 I2 N& ]</FONT>
5 [' d- y. V2 j/ _2 W8 @( p0 C: |+ r1 w* z
</P>
8 F( A- }1 n8 Y* x<P><FONT color=#ff0000>函数名: assert </FONT>
8 i! v1 D. z0 a% y功 能: 测试一个条件并可能使程序终止 / G. \& v" B: W$ s
用 法: void assert(int test);
. s- F6 N! s# U/ ^程序例: : G; q2 Y6 Q! K" m+ J% D
<FONT color=#0000ff>#include <ASSERT.H>
9 n" S# M& o. L& m1 W2 z/ {2 X+ e#include <STDIO.H>5 M1 E5 @4 e8 q2 e- U. S. D
#include <STDLIB.H></FONT></P>
7 }9 N+ E5 I$ J<P><FONT color=#0000ff>struct ITEM { % y; p" _9 u6 ]: w- x# f1 L; L
int key;
8 H% G( H4 l4 h! xint value;
5 j; ^0 q" ~# v% e# T$ d: N( M# H}; </FONT></P>
# M0 c2 K! D# q) c' \, y<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
' N9 G0 B0 @/ y4 kvoid additem(struct ITEM *itemptr) {
6 q" c% I; W: B) l. M3 _8 hassert(itemptr != NULL); . a; W1 U' l* w- ?5 C
/* add item to list */ . C: |6 H% F' S, G; I. V
} </FONT></P>7 N2 o0 c; f) P5 p& k
<P><FONT color=#0000ff>int main(void)
  G4 G+ c8 Y) f. \{ - \0 e5 F* [# U" ?4 R: m7 w3 x( j
additem(NULL); ; N# C' o/ K1 v4 p! N2 j
return 0; ( h* f0 ?; g3 ^- {
}
: Q: K, k9 ~1 X2 G. U</FONT>
4 e1 D6 M" x3 C& @2 _0 Q4 S5 d* q1 @# `  j
</P>
! O8 |3 s, T2 _0 k" D<P><FONT color=#ff0000>函数名: atan </FONT>2 j1 P' U2 I7 }$ q( f- F1 b
功 能: 反正切函数 2 M: g; Q" L* m5 _+ e5 Q! y! y
用 法: double atan(double x); ! |+ ?* ^1 e8 q, i$ C: k  L  F
程序例: 4 S; e% K" L- @0 x0 h% X* g
<FONT color=#0000ff>#include <STDIO.H>
8 ~! `7 H9 a% x( J1 \; s#include <MATH.H></FONT></P>
9 Z5 X2 Z1 O0 h/ `+ b$ ~<P><FONT color=#0000ff>int main(void)
" E( o+ \) f" B{
1 q8 o% K4 a' i6 Q% ?' W( @double result; 0 X9 D: Y  S5 a, v( ^9 f
double x = 0.5; </FONT></P>
4 t" U, a2 w' J- n<P><FONT color=#0000ff>result = atan(x);
! f9 F+ ]1 I0 w3 Sprintf("The arc tangent of %lf is %lf\n", x, result);   H3 m- Q& l( f& l9 S2 `& l
return(0); * c/ r  b" b1 |
} # c+ f3 U( M  v. k; L% `
</FONT>1 `9 k. V& k* ]) l  f3 X  Q
</P>, J4 t0 j! e, _! ?. A% H( Y
<P><FONT color=#ff0000>函数名: atan2 </FONT>/ d7 `) x: x, M3 a+ S' `! {6 m
功 能: 计算Y/X的反正切值 % K% J1 K2 F3 l
用 法: double atan2(double y, double x); + g* h# J- Q3 X2 ^- D) D& |
程序例: % y2 b6 D, R. E: A
<FONT color=#0000ff>#include <STDIO.H>6 Y4 Q! g1 `5 Z( d! s2 D
#include <MATH.H></FONT></P>- R" \4 R6 ^( ^8 _
<P><FONT color=#0000ff>int main(void) . R$ n3 [3 v  x. C0 |
{
4 i  F* `( h' zdouble result;
$ p$ N' O/ o$ I% Q% P1 m# R# Bdouble x = 90.0, y = 45.0; </FONT></P>  j5 L  \# `; t
<P><FONT color=#0000ff>result = atan2(y, x);
2 G0 f( p  H6 s/ s- \printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
, o1 V4 v. H: nreturn 0; 7 n; A8 E: X7 e
}   w" @$ w' U% \" H* N
</FONT>
- I4 Q3 d  E0 v! x, `) e* \  v- f6 {</P>
' N& t$ B" k  Z; p% B% u) f- d<P><FONT color=#ff0000>函数名: atexit </FONT>
9 H. m5 u7 w; K0 O# N4 H* j功 能: 注册终止函数 $ v4 E1 D- @- e
用 法: int atexit(atexit_t func); 6 x. v/ C) c" n# b; Z4 b: J
程序例:
, w. D/ ?# f7 S7 T  T<FONT color=#0000ff>#include <STDIO.H>  u2 `& V* }0 a6 k8 m) W
#include <STDLIB.H></FONT></P>& e" l. V/ {1 a
<P><FONT color=#0000ff>void exit_fn1(void)
0 O& y/ c, \: {. a9 \{ + y) t1 c1 V, s, \+ V
printf("Exit function #1 called\n"); # l  p5 A0 L: \$ _: L, b2 ^5 h
} </FONT></P>6 a; I5 Z! u6 F, H
<P><FONT color=#0000ff>void exit_fn2(void)
0 h* e0 |2 P, i" r7 q$ U{ 1 F2 Z  [- t- Y3 |; |  `# C
printf("Exit function #2 called\n");
6 x; m7 v+ o& q$ p( m} </FONT></P>- ]5 t1 u# O9 c% l; q) ~, H5 c  _
<P><FONT color=#0000ff>int main(void)
  l. y1 w+ m& A+ u6 N8 T( ^( l. H# z{
) g) {! ~7 H5 t/* post exit function #1 */
. G4 f+ y0 B7 ^( a$ B- K: Batexit(exit_fn1);
  \$ d# x- O! o: I8 h9 Y: `  e/* post exit function #2 */
) Q$ x0 N, O! F* n0 xatexit(exit_fn2); - i* {7 A, e! `
return 0; 5 z; M" {( ^5 h
} $ B: W& C) C. r, W, w/ c, F$ ~
</FONT>8 ^( k3 d  _. A( i- J

  q# y$ [& ?8 ]# @" s& @</P>! H6 m2 r$ O, M- L6 F
<P><FONT color=#ff0000>函数名: atof </FONT>9 R- U" L% t1 Z/ M/ z) e+ j& r. q
功 能: 把字符串转换成浮点数 , ~+ b9 g4 x4 Z
用 法: double atof(const char *nptr); 9 |2 Z- C# @2 }: E
程序例:
% z7 v, A  U8 m<FONT color=#0000ff>#include <STDLIB.H>/ N8 b/ Q2 w& T, `, j- L
#include <STDIO.H></FONT></P>
$ D! z  F) n+ d1 K$ q<P><FONT color=#0000ff>int main(void)
9 I, h) x/ N, ^, d' p+ S{
! A! B: ?+ b" Z1 Sfloat f;
+ p! F' V7 G$ z* ]6 Qchar *str = "12345.67"; </FONT></P>
8 Q# H& g7 y- G/ O( a5 S9 a<P><FONT color=#0000ff>f = atof(str);
. N2 m+ W4 z  z3 L5 H3 @2 qprintf("string = %s float = %f\n", str, f); 5 e. J8 D8 W! X8 f
return 0; 3 o8 {) i; q! R9 n& J
} 4 t% [. c0 f1 \9 f4 s5 k) _
</FONT>
3 a) J  _+ ]  V: n3 f</P>& G) P9 P8 p. R' @' U
<P><FONT color=#ff0000>函数名: atoi </FONT>  r8 o( [3 Q6 K/ _+ l
功 能: 把字符串转换成长整型数
, r# }5 K8 \' g: a' `1 \" @6 }0 ^用 法: int atoi(const char *nptr); $ e8 A$ B9 \  ^7 L+ _. |
程序例: / O7 l( z- D, r; e" b
<FONT color=#0000ff>#include <STDLIB.H>
+ x' e' J  B( G9 }3 r+ |#include <STDIO.H></FONT></P>7 z' U; o$ g* t0 _) c; O  u1 X
<P><FONT color=#0000ff>int main(void)
6 c! z1 X: y5 X{
6 o$ M8 N: H/ y% [% @int n; " _8 T: t8 f& W  C& p3 E5 }8 A' V% a
char *str = "12345.67"; </FONT></P>
& [' Q% u, h1 ?* t<P><FONT color=#0000ff>n = atoi(str); ) Z' J( \9 G6 Z
printf("string = %s integer = %d\n", str, n); + |8 p- i. Q' ~' C. S) M: |2 ^
return 0; $ F9 _9 y5 G. D! U2 |3 T7 l
}
$ o! T$ L; E3 b% V6 y. z! i</FONT>
+ n" p2 J/ z/ v- N* n; c</P>
3 k6 p7 s$ G( a9 y<P><FONT color=#ff0000>函数名: atol </FONT>
4 U+ b5 k  z, H6 L$ R功 能: 把字符串转换成长整型数
3 Q: `6 ^1 \9 T6 w3 v! S6 M用 法: long atol(const char *nptr);
, y. i* Z6 C; k. F程序例: </P>2 k" d: c: P/ Q
<P><FONT color=#0000ff>#include <STDLIB.H>
; I8 q3 \+ }. W% ?, j! f( Q#include <STDIO.H></FONT></P>  W/ q: B/ m# Q% Z- K( |3 ]( s
<P><FONT color=#0000ff>int main(void) $ g) S% K, m# Y) i# g
{
" z' S% z0 D) @* N  {4 dlong l;
6 B7 p# Q* {6 ]$ f" T- z8 ]7 Ichar *str = "98765432"; </FONT></P>7 O' [& W" @% X7 Y: @6 M
<P><FONT color=#0000ff>l = atol(lstr);
0 n- Y. \0 U1 b# [printf("string = %s integer = %ld\n", str, l); / g( \' R6 }2 b9 _$ H9 f. _! q
return(0); : C( ~4 k6 g5 \1 s5 c% A
}</FONT></P>
zan
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