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< ><FONT color=#f70909>关键字 <a href="http://hackbase.com/hacker" target="_blank" >数据库</A> 对象2 A7 E( G& x; o. c; h
原作者姓名 Fang</FONT> </P>& U* U9 C d8 J# n1 ~% K; {
< >SQL SERVER6 x- G! ~9 Q9 H! d" f
取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法* ~; K( i% R4 r. Z
系统存储过程sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb</P>
: _9 v* k0 R7 T+ L+ R$ S& ]) f# `< >或者</P>
+ U3 d2 D6 |; p. ^< >USE master</P>
! [- w+ M( F: B6 i: b& y# L< >SELECT sysdb.name AS dbname, xlogin.name AS owner FROM sysdatabases AS sysdb LEFT JOIN sysxlogins AS xlogin ON sysdb.sid = xlogin.sid</P>/ m4 S [- e1 I& O/ R' N6 w
< >
; T% q1 p) j5 e' usp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb获得的内容更准确:第二种方式无法获取Windows NT登陆用户。</P>
( S8 E: E& j$ m+ R< >取得表的方法5 \" w. {8 ~- {) o' c. ?+ ?
系统存储过程</P>
) Z0 n5 O! o& w" b, E< >USE xxx</P>
3 e6 U9 \/ ?8 N/ Q m8 \1 ?! g< >EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
4 ]- \, b6 m- J7 M' x }< >或者</P>" i: G# G y" `2 h) P+ ]- n
< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的用户表:</P>' l3 x4 ^7 g9 u. O3 ~
< >USE DBAudit
' |# ^" Y6 r! Y. s; BSELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U'</P>5 k* S. K" ]4 l( u( B
< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的系统表:</P>
, e# Q k6 P7 I$ z5 c1 ~< >USE DBAudit$ {$ N+ j7 X8 H* ^5 o. v
SELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'S'</P>
/ }1 G: K- f( ^ Z6 N< >或者统一使用:</P>
3 T7 M( T. }, g4 y& p) M# c) M9 N< >USE DBAudit</P>
; i. W* X1 {: I% G# \, U: S< >SELECT sysobjects.name AS name, sysusers.name AS owner, type, sysobjects.id AS id FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U' OR type = 'S'</P>! l8 u6 @, p5 z7 K- ?9 W# P c) V
< >注:</P>1 `: ^9 t& t" M' C2 u$ w2 D% v" i
< >sysobjects中type字段类型解释:</P>
. |. l3 ]/ t& C: Q< >C = CHECK 约束</P>3 O6 W: U+ x4 q" Q( y
< >D = 默认值或 DEFAULT 约束</P>
5 b0 D+ d3 z/ B< >F = FOREIGN KEY 约束</P>
4 g$ p( Q; l4 p# Y8 a5 L< >L = 日志</P>
3 m9 N. R$ s, [) y& R< >FN = 标量函数</P>
' y/ y0 j4 _7 r1 ]; a4 _+ ^< >IF = 内嵌表函数</P>
; r: ]# Y" d( K< > = 存储过程</P>7 i4 p/ |8 C2 I) p
< > K = PRIMARY KEY 约束(类型是 K)</P>
# S" m4 q$ O/ f6 A, i+ o< >RF = 复制筛选存储过程</P>3 t4 ]: G2 y: n5 a
<P>S = 系统表</P>$ W! m9 x1 s- y3 Y, V
<P>TF = 表函数</P>
; N; C. B2 u( @3 Y O9 b<P>TR = 触发器</P>
5 m3 J# q) m/ }! \9 Q/ Z<P>U = 用户表</P>' w! W/ R' w: _( k1 o; q3 ]( n7 R0 W
<P>UQ = UNIQUE 约束(类型是 K)</P>7 I# f, K! K( E
<P>V = 视图</P>* I( C ~8 y7 Z8 B4 Y5 P# \
<P>X = 扩展存储过程</P>
, S: z' n2 k* `<P>取得列的方法
8 w+ c. Z6 d- {" v x3 r系统存储过程</P>
# J4 r3 [! }0 S* w3 K<P>USE xxxDatabase</P>
7 @" T# e' P8 ?<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help xxxTable</P>. a/ \& K W7 U. s* L U( _+ U
<P>或者</P>
w1 O4 ]; `% x: Z+ e; S5 J6 u( [<P>USE xxxDatabase</P>
6 E, w9 }4 z0 w8 E6 T6 w3 y<P>SELECT syscolumns.name AS name, systypes.name AS type FROM syscolumns LEFT JOIN systypes ON syscolumns.xtype = systypes.xtype WHERE syscolumns.id = xxxTableId</P>: }; w, s7 o/ z( G* d, v) r" t
<P>这两种方法都可以取得包括视图的列。</P>* S* Q1 [ j& k# A# j
<P>取得视图的方法: ]) {8 a2 }: ^5 N1 y/ P9 a
系统存储过程</P>6 a1 L Z4 u8 N; n" p
<P>USE xxx</P>- G. P+ V3 d' \" d! I2 i: @* y
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P> W! s6 |! R. i6 u% N# c7 m5 }/ X% d5 }
<P>或者</P>
( f4 [2 U6 G t. |<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图:</P>
, r% m0 D: _3 q+ z0 A, T3 o<P>USE DBAudit</P>* {" A) k7 O1 }! s# |( _$ M
<P>SELECT sysobjects.name AS name, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'V' </P>
0 l' D/ n0 q9 @/ ]" |2 e<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图的内容:</P>
$ T8 J( ]6 ?0 A( i* L; k<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>/ u1 U* P. i W
<P>取得存储过程的方法
, T1 `1 h. b) E3 Q8 q5 C系统存储过程</P>/ Z y# l7 ~/ o
<P>USE xxx</P>1 K( S0 ~- ^4 C6 S/ b
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>+ s) I2 n. m* X: g3 P' R9 Z: q
<P>或者</P>' L' k9 i7 k4 f, `3 y- z% M
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程:</P>) e; M5 z- {8 |& |, I
<P>USE DBAudit</P>
7 @ `" K' D$ S<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'P' OR type = 'X'</P>
" [9 y/ O/ y; |* Y& y<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程的内容:</P>7 P8 Q- w9 S L- z& `/ B4 }0 r+ I% k; e
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
- \. l0 ~! T" f. g( M<P>无法获取加密的存储过程。扩展存储过程只能得到dll程序名。</P>0 E* j7 t+ f4 U1 Z
<P>取得函数的方法
) l' W* B# o; s3 ^: Y% e {4 `系统存储过程</P>. a! J0 d! S# \( j/ [9 p0 c: O* u. d
<P>USE xxx</P>9 ~& P7 t& n$ m, X
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>1 _8 p; A( y" M. Y( `4 }
<P>或者</P>
: b G& a4 z z: v) o& F<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的各种函数(内嵌函数等):</P>- {/ Z$ B& ]( k, ~' Y( K( X
<P>USE DBAudit</P>
$ h+ _7 r' J& p. D! h7 L) T<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'FN' OR type = 'IF' OR type = ‘TF'</P>* R0 `1 X; _% e2 I0 V" P
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的函数的内容:</P>
' ~& L0 p$ u, B- L* C7 t2 B, m<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
$ ^! G; h8 b8 |8 E: ~<P>只能获取用户定义的函数内容。</P>
+ O# s [! }* d. L) Y8 B, F<P>取得触发器的方法
/ `1 q8 o. q" J% d. ?4 [3 e$ x系统存储过程</P>
5 f/ O) j% Z) i, S2 J& r. e<P>USE xxx</P> L* g/ _' k6 s7 d5 V6 h3 U8 d
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptrigger xxxTable</P>
6 i# }3 [! \% _7 G T. v4 W% c7 \<P>或者</P>
- T+ g% b0 m7 Y. S<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的表的触发器:</P>
! g7 |) g5 K1 `<P>SELECT sysobj1.name AS name, sysusers.name AS owner FROM sysobjects AS sysobj1 LEFT JOIN sysobjects AS sysobj2 ON sysobj1.parent<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>obj = sysobj2.id LEFT JOIN sysusers ON sysobj1.uid = sysusers.uid WHERE sysobj1.type = 'TR'AND sysobj2.name = 'xxxTable'</P>
$ i7 X4 q, G! j<P>取得索引的方法; w: n0 T4 }1 O
系统存储过程</P>
q- `4 D/ W6 l& v2 E, S u<P>USE xxx</P>- e& g( c* @- c# K! U
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpindex xxxTable </P>" S6 L0 x6 i# ]) R3 z4 e+ o1 R
<P>用户
# X- E' J5 d4 F# R1 ?# z系统存储过程</P>& V5 ]& V9 ^1 w8 n
<P>USE xxx</P>
9 f& m2 p4 Q8 i" n1 n) [ ~1 T<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpuser</P>
" B7 a% c9 m& m( ]<P>角色- [0 D z$ Z2 a( z6 o
系统存储过程</P>
& |" e" O( B+ r9 v# R<P>USE xxx% L3 `% [% o! T. p
EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helprole</P>6 x* A3 c/ A, Y0 I6 k
# z+ @& z: r d! m6 v% G
<P>ORACLE5 V: g; ?1 y+ i/ S' Y8 t6 u( F' J
特殊/ T3 @+ O, p2 U- ^$ Z/ h
Ø ORACLE只能连接特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象。</P>
, e# ~) b+ W) A. ]# ]' y- O! K<P>Ø ORACLE表必须用用户来区别,否则表可能重名。</P>( R6 O% X" a# X& j" v1 m
<P>Ø ORACLE不能区别系统表或者是用户表,因此只能由管理员选择扫描某些特定用户的表。</P>
+ O8 E. W* G* y1 w8 W2 g+ ` m/ Z- k! j<P>取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法
" F8 j' _+ p1 o" [1 ~9 ]& W只能由用户指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描到特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A><a href="http://vip.hackbase.com/" target="_blank" >服务</A>器上的所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>。</P>! I( X0 S4 t/ p" q
<P>取得表的方法& r5 A/ Y7 M& l9 [- y0 C: y
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的系统表/视图主要有:</P>
, q$ x' u. j1 y/ K4 u, E<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
5 v/ n) | c }* {$ F<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象以及相关的表。</P>
+ \) U2 C' s. Y4 C: i<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
2 |3 z0 ]/ Z2 u<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的对象以及相关的表。</P>
# d0 q' v/ y4 e+ a8 D& w<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>. N& o5 ?$ o" L! F6 A4 z
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的对象以及相关的表。</P>
. [' A3 M7 z+ Y5 t i<P>6 C" b. v0 Z# |, `+ N
DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
" X1 l- G! }; k0 F' U7 B<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有相关的表。</P>
, w& L, }; N: i( B<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
8 b p1 ]: {3 g- p1 W0 Y. {! k<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的相关的表。</P>" _. J N! g* C7 F
<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
; Y3 c8 C2 C y, E/ g y<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的相关的表。</P>) A$ F; c; V0 _. J
<P>( d, x! v& L5 ?+ \) R) [2 a8 y* p
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES中取得隶属于指定用户的表:</P>
: H- {1 _$ ~' t7 S9 L/ C; t- \5 r- B<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE OWNER = 'DBAUDIT';</P>
9 V$ S8 {, _- V3 P7 t y5 R/ y<P>取得隶属于指定表空间的表:</P>
' j1 I( s: ]8 z<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE TABLESPACE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'DBAUDIT';</P>
) C' `8 X! f. N5 U) q' a' t<P>
9 D9 F y& C. ~: y( c6 I也可以不指定用户名,从而取得所有的表。</P># c9 `; X/ w; {+ X: ?4 T
<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES;</P>
! O* X" H! V. T6 S( l( _: h- O0 |<P>取得列的方法4 t8 O; m& S( P/ h- z) l6 x! p
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的列属性的系统表/视图主要有:</P>4 ^' {5 K) q( u, Q. K0 r
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS$ X* f3 N3 @* {7 }
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的表的列属性。 E! c5 M$ @- f
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS$ J% S; T7 H8 h# }1 O- x
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。 z. d4 @5 p% Q4 v) [$ u
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS& ^1 G. |0 E: d# w/ J
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的表的列属性。
% p- f/ Z* t) [- QALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLS</P>( ?5 i) Q3 g' ]! n, o( k' T* {: u2 I
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。</P>
$ B0 C- n0 [# p6 b+ y<P>
! w# K8 Y- w* d2 z6 u9 t! i: z. [2 m9 n因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS中取得隶属于指定用户的表:0 U4 D8 H) }& s
SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'TASK' AND OWNER = 'DBAUDIT';</P>
' e/ F/ @9 c; k8 Y7 `- b<P>取得视图的方法7 c4 A# K2 j) m4 W
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>视图的系统表/视图主要有:</P>( M3 k0 y; x+ A7 o0 f# z4 b
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS( }! D; @8 `. K* U* u9 [
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的视图的属性。
a* b) S8 G4 ZALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS
q" u8 g9 W9 M% S7 f描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的视图的属性。( O* c8 ^4 r E& a! b! V/ O- v! ^
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS</P>* p8 I' h9 u, @7 t1 G
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有视图的属性。</P>' Z9 D x: Y! D2 d& o
<P>
% [2 }+ p1 o8 x+ \! G# h$ F/ v因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS中取得隶属于指定用户的视图:4 l) m8 \, x1 x% J( ]2 y
SELECT VIEW<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS WHERE OWNER = 'DBAUDIT';</P>
: x% d% S4 r+ y8 X: H<P>取得存储过程的方法# d$ n! L: \9 A8 n
存储系统对象的系统表/视图有:</P>
2 U7 w$ @8 J! J& [<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>3 |5 l+ Y. ` m9 [2 D- L
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象。</P>2 M. c9 \( I) I8 |7 I. ]- e
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS0 j6 F4 {/ ?* R/ {; F' u) r
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的可以访问的对象。
, e+ x/ A' ^3 D% x+ F3 {9 G8 G+ s. cUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>
6 |9 _5 W& r5 ]- z3 ^2 x<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有的对象。</P>( i: U8 U. I: z6 i$ \& A2 n
<P>SYS<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>
9 U( X! {2 b8 M<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的系统对象。?</P>
# X ?( q9 b# H0 y<P>- }# i+ M0 |. E9 d; G# Y
对象类型有:</P>
0 i3 e, d' N9 G<P>CONSUMER GROUP</P>% Q8 p* t! ^& k1 `( b7 e
<P>CONTEXT</P>
& i1 z( P% K! q+ n<P>DIRECTORY</P>
. c; z2 V# i% L# e<P>FUNCTION</P># U2 T3 q: B- Q3 @! o, K
<P>INDEX</P>. Y. L9 G0 O2 o' c0 V
<P>INDEX PARTITION</P>
- k, D& F/ x; A5 g' f4 L<P>INDEXTYPE</P>
9 J R8 y: `4 @/ U0 C* \4 Y" j# S<P>JAVA CLASS</P>2 }$ A% A8 Q% l" U8 a* U* n
<P>JAVA DATA</P>
: K) q+ A, [/ T2 b<P>JAVA RESOURCE</P>% p( I `# B# V# Y! G5 D
<P>JAVA SOURCE</P>1 h! T. v: {! R4 a
<P>LIBRARY</P>' z, M, y4 ]7 c
<P>LOB</P>; L& t: z( z0 J3 ~0 O/ I& F5 Q& |5 I
<P>MATERIALIZED VIEW</P>* T2 S( N0 m% A& z
<P>OPERATOR</P>$ t1 b9 |' B4 [8 V# r, z# C
<P>PACKAGE</P>! C; P" n6 a. p) \
<P>PACKAGE BODY</P>
9 g% {* }+ I' ~5 ?. D7 m<P>PROCEDURE</P>5 H% n2 b% {2 t& l9 G' n1 f& D
<P>QUEUE</P>
2 l& X z8 t1 V% u1 F* q- h<P>SEQUENCE</P>8 i! b# i9 G8 z4 t
<P>SYNONYM</P>3 @( N0 \' t& g, F; }% Y
<P>TABLE</P>
! u2 l/ r2 V7 K$ ~1 _9 @<P>TABLE PARTITION</P>
" }7 [; }; y4 Z) D1 i7 L$ w, d0 @6 s<P>TRIGGER</P>
4 k5 }( s$ K# b4 x) p q<P>TYPE</P>2 ~5 C% T4 Y0 l Y1 w
<P>TYPE BODY</P>
- `' l# U) c& f<P>VIEW</P>( N& a, {. R4 W$ }
<P>+ y+ I& d q& z& k4 C
因此,取得存储过程可以用:</P>
8 H, [: ~" d) ]- L. e4 g1 \: F- D2 t<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE';</P>" {( T/ j% L$ R/ m
<P>取得隶属于某个用户的存储过程可以用:</P>
$ N: L- R. b: ^' i4 R<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE' AND OWNER = ‘DBAUDIT';</P>
. M0 x" e( Y* I @0 H$ w& ~4 }" ~<P>
8 J7 V" t6 A8 b) ?同样,取得其他的对象也可以用这个方法,包括表,视图等。</P>2 d% @! X$ K- ~( R/ y6 M- T4 ?
<P>取得存储过程内容的方法7 z6 s. S1 L3 R
对象类型为类型、类型体、过程、函数、包、包体,JAVA源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的所有对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>都存储在几个系统表/视图中:</P>0 u& w4 u' Z/ R
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>
% G7 ^1 a |" Q* Y<P>存储所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>6 p0 Y* }% q6 m, R- W9 u
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE
2 n* z8 W, J; d' N存储所有可以访问的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。- j' _! A1 K$ \8 S0 I0 F/ c- w
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>8 _. {4 e- R' ]+ `" Z2 J: c
<P>存储所有当前用户拥有的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>5 t* _, @3 O7 q3 G y& o/ v9 N/ d
<P>
: T9 Y6 l, B7 A5 M3 c1 C因此,取得存储过程源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的方法:</P>7 ?' H2 q. S% ^9 T3 C3 C% d
<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = ‘XXX' AND TYPE = ‘PROCEDURE';</P>+ a3 P" F1 U, S- J: w" T3 ?, |
<P>取得函数的方法 S7 m* e/ x- x( N+ L
同上,取得函数可以用:</P>
/ r% D+ U& L, A1 s<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION';</P>+ j0 ~+ Q- |: i. G+ o2 ~/ o4 ?
<P>取得隶属于某个用户的函数可以用:</P>
8 p' \- _( Q$ v<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION' AND OWNER = 'DBAUDIT';</P>
! A1 P& N4 _" f+ F5 Z0 S<P>6 @' N! E" }: P7 q! e3 a
取得函数内容可以用:</P>1 l, k6 r1 w% ?! x1 {
<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = 'XXX' AND TYPE = 'FUNCTION';</P>4 p. q7 W5 h1 |
<P>取得触发器的方法
5 T7 m) X/ P) ?8 E+ G存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>触发器的系统表/视图主要有:</P>; b* K" k. |. ?* h) K! W5 I
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS) s7 ?# b2 D4 {* Z# u# {
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的触发器的属性。
5 P) u1 @+ H7 K% j+ G7 }ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS1 K9 H4 M; A& n' `1 N
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的触发器的属性。
+ K: }. @3 O3 ^8 h7 SUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS</P>
" h# k+ N2 i. V+ j! ]! n<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有触发器的属性。</P>; ~8 @$ }4 T+ l7 v R6 j. B
<P>
! e7 A) I0 M' H3 e; E8 P9 [, r因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS中取得隶属于指定用户的触发器:1 Y0 K2 X' q" H) H! p8 s$ R
SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE OWNER = 'DBAUDIT';</P>/ L( j7 E6 k* z, a3 q$ Y
<P>
7 u4 }) d& _, |' z$ B* `取得触发器内容的方法:</P>8 p1 e8 q2 C6 X- P( ], N, x
<P>SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>BODY FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX';</P>
- y, V% q2 T" J<P>取得索引的方法
, w1 z6 ~" t7 @7 W' x y存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>索引的系统表/视图主要有:</P>
6 f9 l4 m2 E" \5 k3 J) e<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES& j+ i- p! E* U! J! e3 g4 r
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的索引的属性。& o* A* j- r7 E$ ]" m) v
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES
- Q: b: O( N* O9 D' m! O描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的索引的属性。7 F) K6 N; f. f* q
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES</P>9 d/ s% J" y" f9 y1 ?9 T
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有索引的属性。</P>
3 e' H( \# E" B+ [' x<P>' s2 q" {! p4 E3 U: D
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES中取得隶属于指定用户的索引:
; t3 k: i" j8 q1 ^- R8 CSELECT INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME,TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES WHERE OWNER = 'DBAUDIT';</P>
2 P$ { F4 {+ |2 P2 X: G2 w<P>5 u6 m0 m$ o+ G: W) r+ u/ H. E! r$ X
取得索引相关的列的方法:</P>- f. s& Z8 n3 V; H
<P>SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>IND<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX' AND TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OWNER = 'DBAUDIT';</P>+ r9 ]" n: i" y0 [
<P>用户
( i) I+ A, l! ]8 D$ |存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>用户的系统表/视图主要有:</P>
3 c& |, [9 e/ T/ O" g<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS6 |1 A6 R- D$ ^2 R I. ?4 I
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。
( b M; J4 I, P; vALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS: i! q' _2 @# D) t+ n* j
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。
& }) B8 s4 K( f/ z5 N* QUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS</P>
: o) p. V: g ]" e<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户的属性。</P>/ b! \5 k% z8 `1 N, Z" e- s- M- Q! E: C
<P>
% y; i# @8 w+ G2 w1 n因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS中取得用户:
8 \; _. P1 a. s' _+ z/ QSELECT USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ID, USERNAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS;</P> |
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