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不支持自定义 Discuz! 代码
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本帖最后由 cqwj 于 2010-4-18 13:47 编辑 5 ?1 `( H4 D- u% T0 T
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指针处怎么写??
0 U8 d( d% ?1 P% E3 A) g# a我的意思就是说@pointer在模型里面怎么定义?如@pointer(1)=??或 ??=@pointer(1)
# M9 {- y, i# i8 |5 G表示什么意思。我个人理解@pointer(1)=??表示把数模变量的值??装进@pointer(1)这个储存单元,外部程序程序可调用此储存单元数据。??=@pointer(1)表示外部数据值??通过DLL传来的数据放进数模变量,这样理解对吗?
! D, A+ V3 G7 q- H7 ?/ O. w0 Q. a:) sets:' w+ W4 S/ k q$ ^) j1 b
xinxi:cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k,zys,x,y,z;0 H U* ~: e4 n, C! p
endsets6 e0 {$ X- k( W- G0 ]+ y4 ]
data:. r8 L% Q h/ U' Z
xinxi,cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k= @file("li_yong.txt")
4 F3 V. m* x3 a6 t, {5 Q( w* p# u. h@TEXT()=@status();5 D k x( z+ r0 e" ~2 Q. h
enddata
/ @' F/ d- { P3 [" q- K: }5 V[bb] min=@sum(xinxi:sj190*x+sj160*y+sj270*z);
8 W: u2 f6 l+ k5 m, {@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)<=12);2 X' B: N* L! q9 U. }4 {. l
@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)>=0);
/ z- T- }1 m, R4 @$ H@sum(xinxi:x)=sr190;
1 R: x* A1 P; O- P@sum(xinxi:y)=sr160;
. p6 {# l# E' z! Q@sum(xinxi:z)=sr270;
: N F) s! _7 P9 A) U5 {( F@sum(xinxi:x)>=0;' B+ W6 j* l- K! A
@sum(xinxi:y)>=0;
) l- D) ? ^6 S8 ~@sum(xinxi:z)>=0;$ }/ z- z t' t+ I
@for(xinxi(i):x(i)<=cl190(i)*sl190(i));; P g5 b* ^- ^# U; Z' K) ]* w8 i
@for(xinxi(i):x(i)>=0);& r, T7 \& r- s" C- Z
@for(xinxi(i):y(i)<=cl160(i)*sl160(i));
- O0 \' n& l$ \2 f1 e5 I" _ a@for(xinxi(i):y(i)>=0);- r$ r6 w( C; P0 Z7 n- I; h' p+ p
@for(xinxi(i):z(i)<=cl270(i)*sl270(i));7 ^; ?/ a( h. V( y5 o1 K
@for(xinxi(i):z(i)>=0);# K# G; u6 a7 W
@for(xinxi(i):@gin(x(i)));
4 y7 \) a) S# p+ E5 I@for(xinxi(i):@gin(y(i)));
; W0 L H. |) Q" u% e; l4 l@for(xinxi(i):@gin(z(i)));
* k* E+ W8 ]3 q9 j, P4 q/ [' [6 H. umm=@sum(xinxi:k);
4 K }1 D# x# d$ U+ r, nxx=@sum(xinxi:sj190*x+sj160*y+sj270*z)/mm;
( D3 B! _$ N8 t0 C8 o2 X8 R% u6 _, Q5 a# S$ X5 }9 J
@for(xinxi(i):zys(i)=sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i));! b8 t" O9 @' c+ ~
DATA:3 G: V n8 o2 Q, ^ Z: v" E
@POINTER# M1 b c2 z$ N8 M6 x/ [9 b4 D# K/ X
! C' k5 n+ i- A( I; A2 b!此处结果想连接VB6.0,却不知道怎么写;/ n% D7 V- w$ g4 T! o
ENDDATA$ o; \( B0 v3 c! ?( ^
+ \4 q* m5 i p6 b, [* `$ n6 @end, |0 ?9 D- O3 q+ p u) q" D- M
结果为 主要是想取 X,Y,Z的结果- g; h+ Y. L$ u2 N5 I( S( |/ O1 Z
Global optimal solution found.8 c$ h1 J' _ \+ L1 N/ Q
Objective value: 0.000000
0 P' b) F! ^6 L/ G$ [ Extended solver steps: 0
' H. f: U/ [: w# I1 i Total solver iterations: 0& ^$ T A. g9 N
0 o6 H4 G: h7 N- K6 V
, @/ Q" b; S" O+ y4 R- G3 ~ 0
- ?' t& U- M: F0 n! _
2 ~5 s; N' N W M. O1 o! ~8 w Variable Value Reduced Cost
0 V6 x7 C* C9 G# d: O6 `6 } SR190 0.000000 0.000000 f$ A9 i, w r3 D# v2 f
SR160 0.000000 0.000000
% B! l/ N2 j! _8 k) ] SR270 0.000000 0.000000
3 D% Q4 X% {' ]& w8 k) y# e MM 2.000000 0.0000008 c$ F3 ^1 e8 N1 V
XX 0.000000 0.000000
. M/ c( Q9 [. V$ m$ X3 G CL190( ZHANG) 35.00000 0.000000/ `+ e0 B+ ~8 s
CL190( LI) 35.00000 0.000000
5 w& D% y! R9 C3 q CL160( ZHANG) 30.00000 0.000000
b* d) ?* |- Z0 h9 \4 m CL160( LI) 30.00000 0.000000( K' S* ~! {" n5 u7 r- F
CL270( ZHANG) 5.000000 0.0000001 w/ h+ @, m" b& x
CL270( LI) 5.000000 0.000000% m8 S7 \* Z2 r' E0 m' ]
GZSJ( ZHANG) 12.00000 0.000000
: J& I1 t' z9 m8 Q GZSJ( LI) 12.00000 0.000000
% Z/ g/ `" n- S2 J# ? SL190( ZHANG) 0.9000000 0.0000001 [' \$ X& j; X2 y6 \ I3 ?
SL190( LI) 0.8000000 0.000000
- {4 J- K2 f' Z SL160( ZHANG) 0.9000000 0.000000
# f1 b) X" W* R8 S9 b SL160( LI) 0.9000000 0.000000
2 e( ]+ O* y, n6 D/ G8 h1 a SL270( ZHANG) 0.8000000 0.000000! \ ?8 U5 l. N7 u
SL270( LI) 0.6000000 0.000000
. D1 T% t% c7 G: u% n, s/ S SJ190( ZHANG) 0.3770000 0.000000
2 p0 T- V" ?$ Y SJ190( LI) 0.4120000 0.000000
6 s( C) n1 c O& h' ? SJ160( ZHANG) 0.4400000 0.000000% p0 D. w* w, F/ P1 d) p
SJ160( LI) 0.4400000 0.000000
. e* b: N6 q: F" @* q SJ270( ZHANG) 2.880000 0.000000
* E3 V+ y' K# j& I SJ270( LI) 3.360000 0.000000; f0 P) @) L% b+ w6 [
K( ZHANG) 1.000000 0.000000
/ K, i; q4 D' u' t+ d K( LI) 1.000000 0.000000
; z- [8 K3 W. ?" \$ R ZYS( ZHANG) 0.000000 0.0000006 M) y7 C! y, G% B+ s1 x1 @' {1 {
ZYS( LI) 0.000000 0.000000. k- Y q( U5 y3 f, j
X( ZHANG) 0.000000 0.3770000
8 d S# i5 Z% w) `) s$ R X( LI) 0.000000 0.4120000
. ^8 T f7 v1 k4 n/ C* \ Y( ZHANG) 0.000000 0.4400000
9 H$ Y c/ r# |0 F& R, D( k Y( LI) 0.000000 0.4400000
9 d: s3 n7 G- u1 s8 ?/ l1 i Z( ZHANG) 0.000000 2.880000
/ o* ?/ Z7 {3 K/ n$ L Z( LI) 0.000000 3.360000
' h, @1 v, U3 Z; }3 i( L+ |4 @& B4 h$ o. G
Row Slack or Surplus Dual Price
2 k9 R0 e" [9 b# {; E BB 0.000000 -1.0000000 t: L# Y2 K* d4 h
2 12.00000 0.000000- _9 J K" F# B& Z
3 12.00000 0.000000
# Z# F4 M. o; G. P% I z% F 4 0.000000 0.000000
7 n2 r, k( k( ?( T 5 0.000000 0.0000006 \" |% H% P! _& O% P8 Y8 f9 ?) r
6 0.000000 0.000000
. P+ U( }) a b 7 0.000000 0.000000! N, k$ z3 g7 m" S6 T
8 0.000000 0.000000% c4 A; F) [7 \
9 0.000000 0.000000
# s7 b$ {, j" u( j 10 0.000000 0.000000
$ M# {' R, @( N9 J1 _. {- G) E& S 11 0.000000 0.000000
$ L4 b l. b" L7 |' t% W 12 31.50000 0.000000
; q, ]- F% N9 X, ?! A, S; q 13 28.00000 0.000000
6 z1 v7 m4 p7 S; f7 r7 t 14 0.000000 0.000000
0 ~( p1 @) V3 W0 P 15 0.000000 0.000000
( u- I# [$ M4 U5 |: ]7 i: }* ? 16 27.00000 0.000000
6 d7 w& ~+ b; w/ p! G4 ^ 17 27.00000 0.000000
* r. `& n `3 p+ O* V 18 0.000000 0.000000* ~! ^( {( m5 V
19 0.000000 0.000000- d' y7 e t4 L- T& x9 r7 S
20 4.000000 0.000000
( i( g% }: y% Z 21 3.000000 0.000000& X8 x7 D: H2 B
22 0.000000 0.000000
5 A% n N8 U* N0 s5 V 23 0.000000 0.0000003 a% R0 F2 M% \: c$ q4 m
24 0.000000 0.0000006 r% {, H2 E. o1 Z, _0 y/ L
25 0.000000 0.0000006 n* h0 n, U& @7 V" D# U
26 0.000000 0.000000
0 I. E. x3 G; i9 M5 A 27 0.000000 0.000000 |
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