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不支持自定义 Discuz! 代码
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本帖最后由 cqwj 于 2010-4-18 13:47 编辑 l9 D1 A* d+ o* i
2 F: L5 X1 k- \' U, m0 D4 r/ q指针处怎么写??- f3 G o P; A ]
我的意思就是说@pointer在模型里面怎么定义?如@pointer(1)=??或 ??=@pointer(1)" N9 W" K9 ?5 O6 i& {
表示什么意思。我个人理解@pointer(1)=??表示把数模变量的值??装进@pointer(1)这个储存单元,外部程序程序可调用此储存单元数据。??=@pointer(1)表示外部数据值??通过DLL传来的数据放进数模变量,这样理解对吗?
7 c+ L/ _8 o7 A! e:) sets:+ X+ Y+ E1 D& U) C C$ a2 C2 ]$ O7 S
xinxi:cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k,zys,x,y,z;7 G8 t4 @) l) i. T3 u1 [+ p
endsets
2 U o$ R. c# C/ V+ ]data:) J, [- d" \) q4 A: ~
xinxi,cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k= @file("li_yong.txt")- q% _ H. x3 ~* t1 Z5 a
@TEXT()=@status();
, }5 v w) p2 y. O9 A, j9 n8 Wenddata
- k1 C$ ]: S' m7 P8 L0 v[bb] min=@sum(xinxi:sj190*x+sj160*y+sj270*z);3 ?3 X, N ^7 s' H/ Y
@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)<=12);
! m) T b; I: Z0 h6 m@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)>=0);
( C3 \$ U' b' F( e; N@sum(xinxi:x)=sr190;* W/ ~/ Q" u* S' Q/ Q" g! I
@sum(xinxi:y)=sr160;
1 [% t/ T5 W3 v5 ?@sum(xinxi:z)=sr270;
( K: W5 C2 `: r5 h@sum(xinxi:x)>=0;% z5 Z [! G. M( M
@sum(xinxi:y)>=0;
# m0 z# V! C! @; i' d5 I, B@sum(xinxi:z)>=0;$ p0 q0 Y L5 N' E' Y; B9 @4 t8 z; {0 D
@for(xinxi(i):x(i)<=cl190(i)*sl190(i));" g1 n" `0 W' {2 J6 W
@for(xinxi(i):x(i)>=0);* Y% l# q+ B* o; L; ], M
@for(xinxi(i):y(i)<=cl160(i)*sl160(i));
, W# ?0 j X5 T I% ^; N9 P! N@for(xinxi(i):y(i)>=0);
: Z, w2 D- y' K# O2 x- K@for(xinxi(i):z(i)<=cl270(i)*sl270(i));
& _' A8 E+ j1 }# q' E$ p$ U@for(xinxi(i):z(i)>=0);" _6 ^* k U& i& m
@for(xinxi(i):@gin(x(i)));
2 U4 \/ R5 r* T4 s@for(xinxi(i):@gin(y(i)));
' L4 V+ i# U: e5 @/ D6 Y@for(xinxi(i):@gin(z(i)));9 s2 Q; A6 H/ G& V
mm=@sum(xinxi:k);
! t! x# b0 t& [/ ], K6 |xx=@sum(xinxi:sj190*x+sj160*y+sj270*z)/mm;
# S& g3 z4 f0 J% ~% {- I# k# o' k* h# F/ X3 s5 A* c2 Y
@for(xinxi(i):zys(i)=sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i));" M0 b1 F& j0 I( h3 o4 |, h' j0 ?
DATA:, x4 G2 @& t/ G) ~& _
@POINTER6 W* M9 w3 i0 |' j7 q
! x' u7 T2 o' A0 h O. O!此处结果想连接VB6.0,却不知道怎么写;4 u0 x. ^, V/ B7 ?# x
ENDDATA8 L& U) D, y& _- _6 z) h% p
7 |' x: r1 P* G0 o0 Y0 o: Kend
8 Y# D8 Z5 i$ q: ^" R- e结果为 主要是想取 X,Y,Z的结果. S# B) j8 W# T4 o$ S& K7 K
Global optimal solution found.
B# G4 @% T C2 D' W; F$ J6 T8 _' r9 m Objective value: 0.000000
. s, r" O0 j7 l2 i1 w5 D j Extended solver steps: 0# v. c( U( o5 w9 `
Total solver iterations: 0
- X8 G e b2 u* ?
. \. z5 ]& o% L; A3 K
5 b3 D# H8 l1 m3 c7 y 0! D- E4 W# p& ]6 d
7 C$ h) F1 ~. Q% h k Variable Value Reduced Cost
* v" [" D c+ s7 _, g SR190 0.000000 0.000000' D( R5 q0 ?: h
SR160 0.000000 0.000000& ?/ e3 T, J1 u7 n, t2 M {/ m- E+ U3 q
SR270 0.000000 0.000000
7 p6 p( M4 P& S( W" m; E MM 2.000000 0.000000
, }6 q2 P4 U; c; z XX 0.000000 0.000000 E& a3 u9 ^# M+ I* W
CL190( ZHANG) 35.00000 0.000000
g, l9 ]% v! j0 [/ q% o CL190( LI) 35.00000 0.000000' w+ f7 [# c0 B a9 z
CL160( ZHANG) 30.00000 0.0000009 a: L! U7 Z- l
CL160( LI) 30.00000 0.000000
) f+ E) x6 t" i6 ^$ f b- } CL270( ZHANG) 5.000000 0.000000! _' { e$ l7 u/ B# W
CL270( LI) 5.000000 0.000000
) j+ i" C3 r1 W% _+ m+ B GZSJ( ZHANG) 12.00000 0.0000003 B0 j2 Y% C2 o( }& l% u3 x
GZSJ( LI) 12.00000 0.0000002 h/ l$ `9 k8 _3 v
SL190( ZHANG) 0.9000000 0.000000
- h, p4 c) L; b SL190( LI) 0.8000000 0.000000
" f$ X* G# l# D3 h6 b SL160( ZHANG) 0.9000000 0.000000
' d! u6 ?& @9 j9 ]; E# ]4 a* j SL160( LI) 0.9000000 0.000000
/ Y6 M. J; T6 I# ? c s3 U SL270( ZHANG) 0.8000000 0.000000
7 a4 |- O+ T% ]4 p; Z6 a SL270( LI) 0.6000000 0.000000 {# J' x: |+ a
SJ190( ZHANG) 0.3770000 0.0000009 r6 ?- n. ]+ B9 J
SJ190( LI) 0.4120000 0.000000
, i3 q$ t) p( U SJ160( ZHANG) 0.4400000 0.000000
% k* J. c9 t, X SJ160( LI) 0.4400000 0.000000- S1 u1 E' N0 u9 Q
SJ270( ZHANG) 2.880000 0.000000
$ |! X9 E# J& N8 a( P+ A: Q SJ270( LI) 3.360000 0.000000/ {/ \' J7 o1 o% p
K( ZHANG) 1.000000 0.000000
' P. y# c/ J0 Q* |" ]; L K( LI) 1.000000 0.000000
n9 r/ B+ K L' [0 L* ~+ J# M ZYS( ZHANG) 0.000000 0.000000
8 Z. J. T9 m3 t2 O" f. m6 N ZYS( LI) 0.000000 0.0000004 w8 F6 N! L+ Y& ]$ t" g* P1 A
X( ZHANG) 0.000000 0.3770000
0 X+ g: i% V" B X( LI) 0.000000 0.4120000
! R/ @" V* d7 ^& c/ e# U9 K7 G% H0 p5 l Y( ZHANG) 0.000000 0.4400000! Y1 q- Q f- K- j' \/ t
Y( LI) 0.000000 0.4400000! }) t5 ^, W9 V+ u/ @( |& K: D% y: q
Z( ZHANG) 0.000000 2.880000
4 ]8 i) H! o0 @6 s6 K! |. d/ q) S Z( LI) 0.000000 3.360000% S! f8 m3 S0 q! m5 t
, W! e) j/ T: G; H& ]
Row Slack or Surplus Dual Price
k9 W% X" W5 y BB 0.000000 -1.000000* n3 Y2 O8 D' M) N! d
2 12.00000 0.000000$ n9 S9 ]+ k' u( w1 k
3 12.00000 0.000000
: y# `+ X& S- y- J7 U z 4 0.000000 0.000000
0 Y" @: w: B, b3 P! f% D/ q 5 0.000000 0.000000. W/ o* h/ r2 f, U3 J
6 0.000000 0.000000
r* ^2 m' W0 D 7 0.000000 0.0000006 h9 I' M8 D7 K
8 0.000000 0.0000003 I2 W o! v# }- K$ V) \( `3 y
9 0.000000 0.000000% N4 C4 y8 i P$ c/ }8 ? e
10 0.000000 0.000000) I9 `* V% h! r& _5 ]
11 0.000000 0.000000& c$ x* I# j, ? Y; {" i/ }& P
12 31.50000 0.000000
0 P- C! T" y$ O+ ]) X 13 28.00000 0.000000
) O) [5 p; {0 o% f+ j0 S# B. E 14 0.000000 0.0000008 U) D( k2 ~ |! C
15 0.000000 0.000000* s! S8 T! Q4 a! Z# _" g
16 27.00000 0.000000
) G8 M/ J0 A* C, k 17 27.00000 0.0000007 i. E! s4 \' L7 E% N/ ]+ s
18 0.000000 0.000000
8 N) E7 H% q5 v( f3 S! Z. i5 n 19 0.000000 0.000000
) J7 `& w+ U8 p4 Z( {0 |! a2 e 20 4.000000 0.000000
* r1 ?. t% p9 Y/ } 21 3.000000 0.000000: z+ P0 `( G: v" y0 }4 L- n* t
22 0.000000 0.000000
4 {" ^8 h! u3 u& { K0 l 23 0.000000 0.000000! R1 }. ~0 z$ k5 B
24 0.000000 0.000000" S0 i1 Y- V7 V( y" _
25 0.000000 0.000000
+ e4 V9 I" A0 o* T: Q* U* W0 L5 l, f. W 26 0.000000 0.0000001 q6 g, Q6 A" `& l
27 0.000000 0.000000 |
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