新手跪求指导

heugaodie

r = 3.04042*10^(-6);
3 x+ z5 h6 d3 }9 y6 _p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
Do[x = (a + b)/2;
If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
  I4 V& D) w  I: P- gClear[x]
Do[x = (a + b)/2;
7 b) V% `# o- Z0 Z3 B8 c8 x If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
5 m; }" B+ A7 g) h: u6 R5 e. r5 [0 d If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
# Z* D2 {6 @: t) v" `: t; Z' F$ ax2 = x
Clear[x]
+ D& K- c/ g9 v
7 h9 W6 P* J1 Q& O+ j我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
! ~; P3 h! ]- w8 ]: q

小小灰

看不懂，看不懂

花如梦

别只用x,换个变量试试

qudazi

你试一下将Clear[x]换成x=.看看