新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
+ E" ]+ z2 E4 ~1 B( y  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
4 p- p; h/ v7 C. |: za = a0; b = b0;
7 T5 v* {! J: H- l6 S$ {" B' ]Do[x = (a + b)/2;
* g4 |7 }' P* F! I: @1 t If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
* C- g+ J; e4 g If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
! h5 J" ]/ a& O% @0 O( i( z% `x1 = x
Clear[x]
Do[x = (a + b)/2;
If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
( ~1 K9 k  x) e- ix2 = x
Clear[x]
& I+ i/ ]& A0 {3 K: r
我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
- q% p6 O) `% V+ j/ X/ o

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂