新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
6 v2 ^4 L! ~, H2 i, Q  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
' i2 K! }$ v+ Z: r! ta = a0; b = b0;
. ~2 x, j1 Q) W, vDo[x = (a + b)/2;
9 m! C6 ]5 l/ v" D% [ If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
; O6 q: n$ \& T2 ~+ d4 C' M5 }" ` If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
" `9 R, b# D3 |' h) RClear[x]
Do[x = (a + b)/2;
If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
4 P( F0 O0 k( u+ n4 E. V& VClear[x]

我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
' a% l6 Z9 B; N  j$ I

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂