新手跪求指导

heugaodie

r = 3.04042*10^(-6);
, _7 h9 }! C. a+ c; a- J$ gp[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
; U! ]% t. m$ l  |; |) O( E  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
( T- x+ O+ o9 Ia0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
Do[x = (a + b)/2;
If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
+ V( ~/ E' G! A; d1 x6 I% s3 T If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
Clear[x]
! e; D# @5 |6 zDo[x = (a + b)/2;
If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
0 G7 j" i/ T8 Z; _+ ^% R If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
. K0 Q1 S4 w7 j8 }- ~Clear[x]

2 X; u& K( [2 v/ K2 w我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
0 B2 o' m; w) {- y* _* x

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂