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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |正序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>4 s" {( p2 K! M+ y9 x, ]
<><FONT color=#ff0000>函数名: abort </FONT>
" \: ^* q! [9 E3 r- m功 能: 异常终止一个进程 + q- D* g$ j9 `
用 法: void abort(void);
+ z+ V/ ?2 o/ K3 I4 j" B, s  H$ u程序例: $ I, e" b6 x3 D  O
<FONT color=#0000ff>#include <STDIO.H>
5 c7 S0 U! m* U  a#include <STDLIB.H></FONT></P>
6 O9 y2 [2 ^; a* I- @; X! v) T2 d<><FONT color=#0000ff>int main(void) ; V) n6 q# Y4 [. r  ^/ ?8 b3 Q) Q! z
{ ! G+ A* U: N# E! J, U
printf("Calling abort()\n");
7 }0 [  o0 ]" e, n* B- u+ Rabort();
, I) ~2 s1 O% N: vreturn 0; /* This is never reached */ ) c$ _0 E, {3 p9 E
} 2 S; s6 }, F/ V/ H' Q
</FONT>
% f7 i# I2 q: t5 t$ U</P>
' {+ T3 Y9 r. W# a# E+ I, }# `) c& r<><FONT color=#ff0000>函数名: abs </FONT>+ F  p( n2 V0 W4 ~% w) W/ M7 }
功 能: 求整数的绝对值 ! o8 }3 w' b6 F5 S3 |5 h+ [
用 法: int abs(int i); + G5 i" ^0 ]5 S2 `, H0 E6 x' b
程序例:
/ U% d! k# H# s! o- F/ w' R<FONT color=#0000ff>#include <STDIO.H>
& ]) z/ Z  n* x#include <MATH.H></FONT></P>
( q, x$ l. W* `5 W% b% l! a) G<><FONT color=#0000ff>int main(void)
, V" N, n1 q. K# q8 U{
+ e% ~1 G6 O$ A+ h8 Zint number = -1234; </FONT></P>2 ]# @4 z6 q' b7 k1 u7 U
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); ! K- j* R, _5 X" n1 N2 [
return 0; 3 T' X$ C4 ?5 t* w2 S) o
}
2 @1 D7 x  s+ C8 Q3 q9 x- D</FONT>
. ]% s" S1 M# t</P>* }, ~) u6 p! u. D1 R2 U4 c5 s
<><FONT color=#ff0000>函数名: absread, abswirte </FONT># P9 t8 v5 i& ?- j
功 能: 绝对磁盘扇区读、写数据 9 j8 _) s  A" G, {5 g3 ]
用 法: int absread(int drive, int nsects, int sectno, void *buffer);
; Z' `7 U2 u! Y! c0 C! Eint abswrite(int drive, int nsects, in tsectno, void *buffer);
4 V, b) B- A+ d- d" z9 T程序例: 0 Y. M9 L6 u; K) C: {; A/ o* i% c
<FONT color=#0000ff>/* absread example */ </FONT></P>
& t0 `! `+ R( x8 v% F" L* j<><FONT color=#0000ff>#include <STDIO.H>
5 f2 d; {) r% h4 s, I  P#include <CONIO.H>
2 z& Y& M" G8 `2 |#include <ROCESS.H>
4 R* t2 A6 q/ v- u% C# F$ {#include <DOS.H></FONT></P>9 @2 U; ]: z& [7 C. |1 n) n
<><FONT color=#0000ff>int main(void)
& B3 b6 i( Y) y! D4 H{ , @' y; d. ~% ~  [! ^$ T$ h
int i, strt, ch_out, sector; / t% [" J2 v; }1 Q
char buf[512]; </FONT></P>
) R: ?* Q8 q3 h6 R! B8 x<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
2 z2 j2 m! t+ e2 a% xgetch();
  |( b+ O3 X* m( psector = 0;
/ U" d9 w3 ~; R' mif (absread(0, 1, sector, &amp;buf) != 0) " y" \" f! a  P4 ^' \4 J
{
7 C% ~( Z" X. f" R9 i# I$ Q4 vperror("Disk problem");
* j; F% A7 [0 O# O, Z# Mexit(1);
: R, Z' D6 [- S$ [6 j, ?, j1 U: T}
. R% {" s) N$ U7 T* {0 e- Eprintf("Read OK\n");
/ \- g. R* L4 \7 I! xstrt = 3;
+ U3 q' a$ m$ t, K  ^: P/ Sfor (i=0; i&lt;80; i++)
& b2 v$ w1 U) A/ t6 i  L+ ?{
- V7 T  @0 L) p, z- F8 [3 }8 Nch_out = buf[strt+i];
) h$ {7 `  \+ pputchar(ch_out); $ z; V6 d9 N) N5 K# M3 i
} 1 [3 p, h# E: K: M
printf("\n"); ( [. G5 i+ }! G' ?. o3 A0 z% Q
return(0);
; m: {9 P5 b! `6 N4 x}
9 p" O$ [; [. ?1 e8 y% k* H</FONT>
2 }, u# U' O, ]. j+ T) j! w( x
</P>
4 ?3 Y2 K3 J" L# \7 M6 t<><FONT color=#ff0000>函数名: access </FONT>
) l0 ~* Z4 N* f- g功 能: 确定文件的访问权限 + B: F) k1 L! [. `5 L$ u9 `- ~* L3 w
用 法: int access(const char *filename, int amode);
. h  Y( C9 Z4 Z9 f程序例:
# k7 K$ @5 m7 @' K' D<FONT color=#0000ff>#include <STDIO.H>9 B- x+ B" ?3 ^2 Q% \; \
#include <IO.H></FONT></P>
+ T  @, V6 B1 j: s7 \8 E<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>$ F# r9 b$ v9 F7 j* Q
<><FONT color=#0000ff>int main(void) 5 M/ x# k4 w. {7 ^- ]. g
{
( d1 n/ _/ M  k& O9 R' Q# Iprintf("Does NOTEXIST.FIL exist: %s\n", 9 W: K- p; `" s+ i  r% _
file_exists("NOTEXISTS.FIL") ? "YES" : "NO"); ) T. c1 ~* u- e) n2 |, u5 |3 G
return 0; ( }, |8 h1 {% Z$ T
} </FONT></P>
8 p/ J+ H. \! v4 q8 L7 |<><FONT color=#0000ff>int file_exists(char *filename)
2 V, f0 }! V# {- r( Z! V& P) _{ 5 v* h; T5 V: P/ S; [! E, q
return (access(filename, 0) == 0);
+ q8 M* p/ [; ^, @8 L( r}
! E) [( a% |4 m5 A</FONT></P>
% a$ ^9 E2 y9 c# P1 M. G<><FONT color=#ff0000>函数名: acos </FONT>
9 T/ Z4 D' }& i. G  y$ T: s功 能: 反余弦函数 2 g; i; O: ]; q' h3 J  ?. Z2 I( q
用 法: double acos(double x);
: G/ e0 m! q7 q+ v5 \/ B) ]程序例: ; R& K* }0 d) o
<FONT color=#0000ff>#include <STDIO.H>
$ f' E3 V: i% M1 _#include <MATH.H></FONT></P>4 s  ?* `4 _& D+ R0 N0 r1 h4 U' L3 b
<><FONT color=#0000ff>int main(void)
. P1 O; B* c! B2 W- J{ * ~! g% f2 B1 o9 q- \
double result;
6 B7 V6 J6 {1 Q4 V' W' e; kdouble x = 0.5; </FONT></P>) M0 [6 r8 z! B
<><FONT color=#0000ff>result = acos(x);
5 [1 ]" Y/ Q) I" Rprintf("The arc cosine of %lf is %lf\n", x, result);
$ U+ k! V; X4 kreturn 0;
$ \" H! P; {/ t( @# V} </FONT>+ W1 b- J! t8 h; v+ G, Q

% Z  h$ ~  K% ?- G</P>
* B+ C1 K; A  @* R& q<><FONT color=#ff0000>函数名: allocmem </FONT>; u: x- v$ [$ E  _6 K; ~
功 能: 分配DOS存储段 6 Y9 ~: {5 h; p$ i- q: u
用 法: int allocmem(unsigned size, unsigned *seg); 8 @3 X2 D! r  K5 j9 x* f" `
程序例:
' H4 i) v" C! X% B4 N; V# L<FONT color=#0000ff>#include <DOS.H>
; i9 r6 S) e& E! F7 d#include <ALLOC.H>
' H  z# W" }' D% L#include <STDIO.H></FONT></P>
  y# R+ s' P" Z+ F& i! b! D' J<><FONT color=#0000ff>int main(void)
( h- p9 q; Y3 [{
. V' m+ a$ w6 }& Hunsigned int size, segp;
; R* E& u9 W& S9 A! ?int stat; </FONT></P>
  F" }6 U3 t6 V% E<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
+ m! M$ t  l- x/ fstat = allocmem(size, &amp;segp);
, D8 B/ t3 T6 ^. G8 }if (stat == -1) 6 I- ~; {, U+ `3 J
printf("Allocated memory at segment: %x\n", segp);
' `, L, |7 f+ [1 telse ' C6 S# w1 ]) O1 w* t" @* v
printf("Failed: maximum number of paragraphs available is %u\n", $ a- E6 v9 x; Q. h2 y; ^, s
stat); </FONT></P>
4 T( d6 J) a5 t; H0 S) L<><FONT color=#0000ff>return 0; 1 z8 t4 S8 T+ }5 C. k3 W
} </FONT>
& s0 Q2 a( b# }/ n: x, W
2 o$ i8 U( ~6 ]' B. M' d</P>
3 D! A4 z. E8 h7 F4 L4 H7 }0 Z<><FONT color=#ff0000>函数名: arc</FONT> 0 ]# H6 ?( [, ]7 G4 I. A
功 能: 画一弧线 4 o% R# S5 ]2 I6 D; i$ U' F- j
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
& r# w1 _! e% d3 k! `程序例:
# c" a) e; U& m$ ~<FONT color=#0000ff>#include <GRAPHICS.H>
, K9 X* t7 R+ [3 z) K9 m#include <STDLIB.H>
7 E; `0 D* A7 F3 x7 i#include <STDIO.H>3 [4 G) S' B+ g6 [
#include <CONIO.H></FONT></P>( O: o  b7 H1 Y% C) _
<><FONT color=#0000ff>int main(void) . p" f6 a) A$ d. k3 C7 Z# _
{
  P2 d# l" P' z; P8 ?/* request auto detection */
+ C/ B3 @! Q- y" c/ p7 s1 Vint gdriver = DETECT, gmode, errorcode; , t! n9 d4 y2 v' D* W" W# e
int midx, midy; 3 H  V. d, B' g  y% N6 J
int stangle = 45, endangle = 135;
) k! h: ~1 }; R8 D" f5 P% xint radius = 100; </FONT></P>
4 c; H+ `5 O3 @<><FONT color=#0000ff>/* initialize graphics and local variables */   P' w5 D/ ?- }0 ~" u# a
initgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>2 y- K1 W0 {1 x) S4 s6 Y/ B
<><FONT color=#0000ff>/* read result of initialization */
/ v" F: ]& L& w( F1 r  M8 Ierrorcode = graphresult(); /* an error occurred */
, R( e$ s5 E5 Tif (errorcode != grOk) 7 E# S3 Z- l. M8 ]% r+ |3 e, y1 G" V
{
6 o/ H1 e: H% C) ^- `7 V$ D+ ^printf("Graphics error: %s\n", grapherrormsg(errorcode));
! ?& [1 I% V0 p) H9 l- _6 ]$ ~9 jprintf("ress any key to halt:"); ) Q' F6 n* t6 n* S# O+ Q
getch(); </FONT></P>
5 }0 ]) R+ B8 {<><FONT color=#0000ff>exit(1); /* terminate with an error code */
$ K9 ~. ?6 K: Y& q# C3 h  w5 O* N} </FONT></P>
7 Q1 Y- T. `, V/ C6 s, L, N<><FONT color=#0000ff>midx = getmaxx() / 2;
; i3 M; {( F6 ]- l. Omidy = getmaxy() / 2; 0 O2 k2 s4 y8 i2 e( p
setcolor(getmaxcolor()); </FONT></P>
; t# Y' Q7 Z/ f+ j<><FONT color=#0000ff>/* draw arc */ * @) v2 B5 q" U( {3 x' U
arc(midx, midy, stangle, endangle, radius); </FONT></P>
5 s2 ?/ y, P" g: N# K3 g& e7 ?<P><FONT color=#0000ff>/* clean up */ 7 Z# g5 C+ t  E
getch(); 5 }. b/ u8 [0 W1 U, A
closegraph();
0 |# _9 G0 s0 @* Vreturn 0;
& c) k$ h- u" v" u3 \& u}
& q! @- f& h, ]5 v& Q% `  J</FONT>
- N( I. f! d" s# k3 g</P>
, D& L5 z4 o* k" s; a4 \' Q<P><FONT color=#ff0000>函数名: asctime </FONT>
. w+ ?7 t7 G3 I* F功 能: 转换日期和时间为ASCII码
) [! b: c5 y2 v/ G* ]用 法: char *asctime(const struct tm *tblock);
. C" m" W- R# Q& G: \" K程序例:
1 w+ W& D5 w6 \2 G<FONT color=#0000ff>#include <STDIO.H>& m" h& H' @  }% ^" P3 h8 N2 E8 j: ]
#include <STRING.H>5 h1 Y* Z$ p. j/ O
#include <TIME.H></FONT></P>: R5 m% M# S% g2 W
<P><FONT color=#0000ff>int main(void)
5 R1 `3 j* j  ~6 u1 N4 y+ @{ . [* ?+ ]' \; ^! ~5 C  u
struct tm t;
- V; h! O/ A& h+ g2 n; @0 b- @char str[80]; </FONT></P>
* e& Y9 d' m4 z; ?<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>  M" w  o7 U* q+ ]2 N4 s8 ?
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ ! v& }4 H* _& o8 ~
t.tm_min = 30; /* Minutes */
$ n6 X5 g; X$ u  @t.tm_hour = 9; /* Hour */
% V! g) o6 a4 U4 U: Ct.tm_mday = 22; /* Day of the Month */ . H/ Z, f- I. R2 E( e/ x, c
t.tm_mon = 11; /* Month */
: \6 I+ U0 u& }( At.tm_year = 56; /* Year - does not include century */
. J8 `4 q6 ^+ b6 y0 k" zt.tm_wday = 4; /* Day of the week */ ' }2 Q- K) \) v3 [" L
t.tm_yday = 0; /* Does not show in asctime */
$ n! x, U* y/ {# ~! y) L7 [. O  W0 dt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
% I" d5 V  w7 G" x. H4 t<P><FONT color=#0000ff>/* converts structure to null terminated 0 @5 q. j) V) h& s: C9 ?$ \+ N8 l
string */ </FONT></P>. {% R9 l# a, X3 K0 }
<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t));
. i! P( O; B0 s2 w2 f5 }2 ]printf("%s\n", str); </FONT></P>
2 t3 T: h! v7 [# }# P. m1 p<P><FONT color=#0000ff>return 0;
3 \7 Q, m3 `- ^) V. O" Q! j} ; z% b, z3 _9 Z* K. J% K
2 D  u- W* v1 K0 ~' i) p
</FONT>
1 d# I  P% p; V. [( T2 N</P>: O2 U1 }% U7 ]$ c( _, B
<P><FONT color=#ff0000>函数名: asin </FONT>: K1 L! u4 A* o  ?5 O
功 能: 反正弦函数 2 Z1 C4 I* }* ]2 ?" b
用 法: double asin(double x); 2 x4 [$ l5 N8 _/ B
程序例:
# x% z' t$ a& R" L<FONT color=#0000ff>#include <STDIO.H>" `* U0 L- K) b/ @2 n! t. s
#include <MATH.H></FONT></P>& K: p' |( P3 g; x6 I" p5 v
<P><FONT color=#0000ff>int main(void)
# t7 F: j9 i- r0 k1 ~  d  u3 E{
; U2 w+ B/ e8 k8 ldouble result; / K, E9 Z  e6 o0 e% R
double x = 0.5; </FONT></P>  |# ]( N' H6 \" V* I8 k6 p
<P><FONT color=#0000ff>result = asin(x); , `% b. m) q1 P+ c9 y
printf("The arc sin of %lf is %lf\n", x, result); ' E6 I; W4 B( \+ l5 |
return(0);   J# N& V" H0 F4 n
}
: p0 }0 R* T% M* `9 s</FONT>
1 D5 `! X6 \1 M
. L9 u9 s; ^1 b- a# S4 U</P>; P5 z1 L  Z+ J7 q* n, T/ P% B
<P><FONT color=#ff0000>函数名: assert </FONT>
& E" E. W/ m3 H1 k/ l+ N7 V功 能: 测试一个条件并可能使程序终止
: y/ W) i+ G$ R: |/ _用 法: void assert(int test);
5 u9 A+ ]7 H5 _0 o, Y程序例:
" S- k% P1 r: \! W: O<FONT color=#0000ff>#include <ASSERT.H>5 q, k6 B0 k' N6 h9 h
#include <STDIO.H>. P8 R7 K3 V6 A" w
#include <STDLIB.H></FONT></P>2 I( Z' F0 c% z8 `  E5 Q* |4 ?8 ~
<P><FONT color=#0000ff>struct ITEM {
* _& M5 d  ^0 D6 a& Y9 f6 wint key;
& a( x, N; K  h% L8 K% dint value;
& Y$ |1 ^9 E& e. w5 {- s/ q}; </FONT></P>! _. s. V7 K1 z* B* I
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
- z0 C% l1 G1 Z8 h2 Pvoid additem(struct ITEM *itemptr) { 8 r; G( T7 x$ F, O
assert(itemptr != NULL);
' e& L& X' u( ~* s/* add item to list */
2 v; z: V# T* |' v* U5 ?, l. _2 J+ D} </FONT></P>$ I/ Q6 Z! ~8 \6 `) \$ c
<P><FONT color=#0000ff>int main(void) & s" r+ O8 e7 I, y  ^+ e$ t
{
0 U1 K% L9 e6 d! `* ~, ]5 P% {additem(NULL); - H. k/ R4 |& b
return 0;
$ W& m/ F! n+ u. j2 M1 a: _9 X$ p} ) f1 s# d6 y' }
</FONT>. _. K2 p% H+ P' L
0 V: z9 p, z0 f9 Q5 o) e9 o
</P>8 C8 s% z. i6 P/ q
<P><FONT color=#ff0000>函数名: atan </FONT>. B' l0 }1 F/ K% z8 @  T
功 能: 反正切函数 . j- [9 ^  d. p  B
用 法: double atan(double x); ! v) ^3 O- e9 I. @9 A, m# u* M
程序例: , \+ C# f+ ?- ^) j8 w0 j4 {/ K/ }
<FONT color=#0000ff>#include <STDIO.H>. B# x8 U8 P; r) S( ^# G8 a; e
#include <MATH.H></FONT></P>
. B0 N& Y7 @3 f5 d: U5 b( r) e<P><FONT color=#0000ff>int main(void)
6 A1 I! O9 h) Z8 Y% I' `{ . W1 a$ U$ I' o% o; Y% z) H* b
double result; 3 c% F) U: d6 v6 O$ Y* R
double x = 0.5; </FONT></P>* @% P! a" p1 {
<P><FONT color=#0000ff>result = atan(x); % Y# Q7 k3 F3 h% i/ G1 D1 U  w
printf("The arc tangent of %lf is %lf\n", x, result); 1 r, M) v: _# P2 B0 v' y+ n
return(0); 7 d5 Q$ n0 B1 }  ]. q' g# j
} * U' v, k2 P; g, o" [3 m
</FONT>
+ o" ]3 p( V5 E8 l  Z</P>
& N* B5 c6 T7 g* \9 D* F<P><FONT color=#ff0000>函数名: atan2 </FONT>5 ~, n% C1 s5 C4 V3 [1 U3 h$ k
功 能: 计算Y/X的反正切值
/ ]+ [! e/ e9 L1 Q, t0 d用 法: double atan2(double y, double x);
( M2 z; n2 s, i0 W: a5 u2 v4 K程序例: % c" y6 y) I( j  N) l& x6 k
<FONT color=#0000ff>#include <STDIO.H>7 D" p' V# |4 f1 k- H, ~
#include <MATH.H></FONT></P>, s/ {( P# s) i" h. i
<P><FONT color=#0000ff>int main(void)
1 K/ o* K7 |$ ~2 S, b{
2 }2 d! ~8 S# T6 N# A- ^% D9 Bdouble result;
2 Y2 K6 R+ p7 D# Y" a5 s9 p4 B  z8 adouble x = 90.0, y = 45.0; </FONT></P>. y& _2 `& d: \
<P><FONT color=#0000ff>result = atan2(y, x);   f+ U/ C1 }/ G
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
; O7 c) }  x$ ^return 0;
7 E' z( m  U: u}
* |4 q$ j6 H7 ~) e6 s</FONT>
* g: r( ?( W5 W8 ~1 n</P>7 ?) n1 P" }  f3 d
<P><FONT color=#ff0000>函数名: atexit </FONT>
$ }; O' C* Y0 X3 ]功 能: 注册终止函数
- W; v1 o  D0 G7 q用 法: int atexit(atexit_t func);
! R/ V5 n& s  u& }: T; g程序例:
* E& q( g4 ]4 A) @) ]; ]8 u<FONT color=#0000ff>#include <STDIO.H>; o8 M3 o. K4 ?! I& D
#include <STDLIB.H></FONT></P>
$ X- i* U( g3 ~+ O% m& f<P><FONT color=#0000ff>void exit_fn1(void)
4 b; o  w. g7 ~' `{ ; o7 b( j9 K) L# G* V
printf("Exit function #1 called\n");
5 x- ^9 l' y6 f" V& r! I} </FONT></P>
. w3 ?* d; \/ s4 W) C9 W- K7 v8 c<P><FONT color=#0000ff>void exit_fn2(void)   m4 y/ r+ _0 o( |; k2 X3 G
{ " t4 h( \/ l: ?) v' P; X2 K* o
printf("Exit function #2 called\n"); ! V1 v7 Z6 X6 i* ^% u( y8 u
} </FONT></P>
+ R* |- l, S3 h<P><FONT color=#0000ff>int main(void) 6 }/ H# C% m" B; {) ^
{
. C7 G. [& k7 _0 H% @# f5 e/* post exit function #1 */
. L3 \, Y6 @, P" y  Catexit(exit_fn1);
. d& p4 @4 l2 T: Y/* post exit function #2 */
6 g8 [0 M& t  n; H1 g4 uatexit(exit_fn2); * v7 O. [7 w! f" a5 v3 t
return 0;
' V8 v; r3 p) [' z}
7 G: T4 H9 c9 H</FONT>
" J# @, L. Z8 \) l: R4 f8 I6 `! n5 U$ ^
</P>
& O8 `& v( _1 I" b+ Y3 N<P><FONT color=#ff0000>函数名: atof </FONT>7 V# R0 t  A# z5 {
功 能: 把字符串转换成浮点数 9 D3 F' o) J( u+ V) m/ m
用 法: double atof(const char *nptr);
; K9 e9 {- g5 p# V- _3 R. @; G程序例: & j5 F. z: _* b2 I
<FONT color=#0000ff>#include <STDLIB.H>6 e) {) d- W% x% B# d" H3 Q
#include <STDIO.H></FONT></P>
. R7 [: _, x4 i0 e<P><FONT color=#0000ff>int main(void)
4 {8 r  b# J- S# k  {. E# @1 n{ - B/ L  o8 v3 F3 _& v
float f;
+ @1 @+ U3 L' e6 x4 cchar *str = "12345.67"; </FONT></P>
5 A* R# @% O" g9 d<P><FONT color=#0000ff>f = atof(str); ! ?" k4 y" r* C7 l* n: u3 C7 q
printf("string = %s float = %f\n", str, f); 2 R, K: @9 x0 G0 x. }2 e2 X' @
return 0;
+ S% D5 n# z  |1 _- N}
8 [8 @6 f& a: h7 \# ^</FONT># S0 A( ^) M  B8 o6 D
</P>
$ }% Q/ ~3 x8 b( Q<P><FONT color=#ff0000>函数名: atoi </FONT>2 U9 t) H6 t6 n' B% q
功 能: 把字符串转换成长整型数 2 V5 U8 ^4 Y* v, \  I1 q* q8 c1 p
用 法: int atoi(const char *nptr);
0 }. I+ J9 M  [程序例:
" G& T1 b/ s/ k  ?<FONT color=#0000ff>#include <STDLIB.H>
2 Z% F. g9 P5 }#include <STDIO.H></FONT></P>
& i/ I! J- g' }2 `! q' o: Y/ l# s<P><FONT color=#0000ff>int main(void) 9 Y; A& C4 v- o4 E" k/ N7 O0 }, @
{
/ i/ O' i. |8 gint n;
/ F1 q; I2 l8 S* A. m* wchar *str = "12345.67"; </FONT></P>/ w3 f) i: w- v- i( g
<P><FONT color=#0000ff>n = atoi(str); 2 f8 U) v) b/ m2 g
printf("string = %s integer = %d\n", str, n); 6 w- [8 I  B& r
return 0; 7 A. l  u2 f; R- `& i  H
}
! `) s" d( l2 E3 R9 k</FONT>' ?8 E  Z$ N" `! O3 q" v& X
</P>) H# S( o# U" b/ ~8 S1 S' E
<P><FONT color=#ff0000>函数名: atol </FONT>
# `# v9 x6 ^# `& @) d/ q6 |0 v. v  [功 能: 把字符串转换成长整型数
+ ^9 j+ J9 p. v, ^, ?) S用 法: long atol(const char *nptr);
1 C9 @& t! j1 F) q8 B/ s4 H4 d' l' A9 i程序例: </P>
8 Z  `9 X  `- b/ Y<P><FONT color=#0000ff>#include <STDLIB.H>
. b& x( E9 h$ F5 p! k3 C2 O#include <STDIO.H></FONT></P>
: e0 h; J9 g' i+ O! j<P><FONT color=#0000ff>int main(void) 1 i% I+ P' w( F' X4 i' v$ X# g
{ 4 @" x- V% Q; k  n6 d
long l; . ]9 Q! w" |: D
char *str = "98765432"; </FONT></P># P1 g, [3 Z4 z  ~, }
<P><FONT color=#0000ff>l = atol(lstr); 7 S0 `4 u; y; ~- ?7 o& }
printf("string = %s integer = %ld\n", str, l);   L" Q5 X8 J- G. E; X6 H; x
return(0);
0 x7 T' B" T2 \) g9 h7 d. \  J0 {}</FONT></P>
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