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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P># `5 b: ?$ Q8 s, E& R$ }
< ><FONT color=#ff0000>函数名: abort </FONT>
: V3 S P0 t! }) h- x( t功 能: 异常终止一个进程
$ `# F% Y4 j$ j" b* d用 法: void abort(void); : h! W9 D$ ~- W8 u$ |# T9 ?( s8 M
程序例:
, ~9 a4 ?. d% k<FONT color=#0000ff>#include <STDIO.H>
8 m2 c4 t' f$ A; n; a8 _#include <STDLIB.H></FONT></P>) k# H- o0 W* e* A4 b+ x; {: ?
< ><FONT color=#0000ff>int main(void) ! [+ @$ L* _3 l; T$ \
{ ( i: S6 ^, s8 p( C0 H
printf("Calling abort()\n");
3 [; F Q, }' _- |abort();
" z3 w9 A' c5 n0 Wreturn 0; /* This is never reached */ / I- W' O c7 _$ b! D# P! u4 ?
} 7 n$ t0 B( \9 m/ {
</FONT>! b: ^- ]: v6 p) V# ?! ]5 b; M
</P>
# Y- e' |. [/ ^0 s< ><FONT color=#ff0000>函数名: abs </FONT>
0 T! e+ C" w1 a1 S. d) s, t功 能: 求整数的绝对值 * e/ @8 \: y1 r) |
用 法: int abs(int i);
$ g% Y0 q' L7 E8 u2 ~' \( o程序例:
) ?8 U% [: ?3 r3 P: P<FONT color=#0000ff>#include <STDIO.H>: A0 G. L+ z$ r4 O" Q& [
#include <MATH.H></FONT></P>
' z$ F( H7 H6 b% z9 v< ><FONT color=#0000ff>int main(void)
7 L! _) ^, i* i6 ]( P! X5 V{ ( P) g' B9 t6 }* Q K- G' k* F
int number = -1234; </FONT></P>3 w1 R# r: C2 U4 a: s: p8 M
< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
6 d) h% y% g' l: `: D, E& @1 c# @return 0;
- E& ?; P2 u7 V. ~: l1 u: I4 d} & O, H* F5 l) h5 F1 t& o O! r
</FONT>6 n" t, ?* ]7 q% O3 L2 ]
</P>
8 F0 `* t7 F& b ?6 M< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>
% g" }" g# A, {8 `功 能: 绝对磁盘扇区读、写数据
, L# o8 q! {: n用 法: int absread(int drive, int nsects, int sectno, void *buffer);
% ~" \ _& Y6 E% L& zint abswrite(int drive, int nsects, in tsectno, void *buffer); 2 j2 [" F" s) }1 e2 G
程序例:
9 x2 i1 c/ F3 ~8 M* q1 c. d2 x' d0 D" n<FONT color=#0000ff>/* absread example */ </FONT></P>
# z$ _5 \- y) F# S% r1 e< ><FONT color=#0000ff>#include <STDIO.H>
9 ?" j$ r+ {. Q+ i#include <CONIO.H>' }9 T+ F5 n' ^( z. a' c* F6 q" i
#include < ROCESS.H>
( E; x. N! u, T9 }#include <DOS.H></FONT></P>) ^6 R9 v: N9 C' T% v/ D, K% F
< ><FONT color=#0000ff>int main(void)
2 E' S1 g& U6 A* r{ ! N5 n$ [0 W+ A; X q) ~* B1 c% |
int i, strt, ch_out, sector; 3 X7 M' K/ j S% H- e
char buf[512]; </FONT></P>' ?5 D$ N0 {/ f: \7 m
< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
1 x2 m# i% l4 a1 D, k% ~! S: `, `getch(); * Z: F" ] X0 j% w+ V" d# z6 E
sector = 0; ) {0 E6 u: C6 v3 j
if (absread(0, 1, sector, &buf) != 0)
c' ~ X: m- O B+ ]{ - ^! h1 N2 g9 P- p# `
perror("Disk problem"); / x2 f5 `! K% Q7 R+ h0 {# Q. I" m
exit(1); % E6 V& |# C/ g$ O. K, }
} 8 A0 q' G- k+ K- D6 k. R4 h/ X
printf("Read OK\n"); ' U2 V4 W+ A' {, D! X# I6 J2 x
strt = 3; 6 `. e# D8 o3 B- K. Z2 m, ^! [
for (i=0; i<80; i++) 0 X/ e/ X; n1 D2 B) E' B" q, N
{ # N" R2 [ s x+ U( ~
ch_out = buf[strt+i]; ! [6 ]2 I6 b% L
putchar(ch_out); 5 a( c) n: U7 K) k% D
}
8 ~7 l4 B- d3 Yprintf("\n");
: l1 v9 p2 K- m. m9 g5 freturn(0);
2 {: m1 f) l7 a+ p2 O} ' u Q* Y& D7 R( v
</FONT>. _, k, M* F5 X h
: a$ H2 P1 I# H
</P> b3 K% Z R( w9 l
< ><FONT color=#ff0000>函数名: access </FONT>, X1 O+ Q8 @% O* M4 S6 d* D
功 能: 确定文件的访问权限 4 o9 D V4 P! R0 J" R4 s
用 法: int access(const char *filename, int amode); ; W2 |! B1 f/ B' U7 U6 ]8 A6 D
程序例: 0 v& k0 x# c1 M
<FONT color=#0000ff>#include <STDIO.H>
3 J: n/ }! a4 j; e$ j d* S#include <IO.H></FONT></P>
- ]* H* {5 S2 j+ ?) y: z< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
$ B- t2 h. K9 E% e- a. Q< ><FONT color=#0000ff>int main(void) % R3 W3 s7 [$ c/ I9 k( h
{
9 g4 n' a8 g4 w# jprintf("Does NOTEXIST.FIL exist: %s\n",
* z" `& x- P; n: h( [file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
- B- @* z5 q/ [; \return 0; 5 e0 N9 E& \$ O( N7 I4 t
} </FONT></P>
! H2 _# W" D% y% b. A W< ><FONT color=#0000ff>int file_exists(char *filename) 3 M% A5 ]: B. c; {( C4 _
{ 9 N0 C+ P2 n) j: O
return (access(filename, 0) == 0); ! U9 @* H' w$ o4 ~7 N3 l! G
}
. _( j1 v2 H/ b</FONT></P>4 T- x/ i* v, {* Y
< ><FONT color=#ff0000>函数名: acos </FONT>7 `+ | Z, `- |4 b! d4 V Z* _
功 能: 反余弦函数
/ z A8 i: j' m! k0 @" k用 法: double acos(double x); ! X' |4 u5 f7 W" D) Q6 f% E
程序例: 6 G' o& T8 C; X/ m1 i3 y
<FONT color=#0000ff>#include <STDIO.H>
2 X- @4 X7 |" C6 F8 C#include <MATH.H></FONT></P>
0 l4 |+ @- S5 m b9 w< ><FONT color=#0000ff>int main(void) K$ G: K" C, b
{ a( T; e, S. Z' [* [0 }
double result;
& k" J$ }9 B% ]' wdouble x = 0.5; </FONT></P>
! V6 w: q5 {3 r; i! h< ><FONT color=#0000ff>result = acos(x); " ~- S: a# }) @
printf("The arc cosine of %lf is %lf\n", x, result); ' T. j" X/ ^8 f( I5 _
return 0; a. n4 R. L( V9 H+ L
} </FONT>3 f1 O) C% J. u/ \5 T* f5 r* n4 W3 g
1 b2 O& y3 I8 P2 F
</P>
( `3 f( v$ R; R2 ~3 T0 H< ><FONT color=#ff0000>函数名: allocmem </FONT>/ ] a4 q8 O- Q: p* z
功 能: 分配DOS存储段 / i# G7 b" C, _; e% I; j
用 法: int allocmem(unsigned size, unsigned *seg); ! y+ i4 }7 |1 A9 p( I+ `% Q1 C$ Y8 ?- F1 f
程序例: ; A5 s9 k. [1 M: L9 [8 V
<FONT color=#0000ff>#include <DOS.H>
% z- V( {! g/ j- X* w3 k/ f) L#include <ALLOC.H>% a( }$ S7 n: Z9 l: a8 m2 V! L
#include <STDIO.H></FONT></P>
4 V& j% R) v& x+ P1 ?5 ~< ><FONT color=#0000ff>int main(void)
# b0 [- L, @* _5 o+ a/ `4 [( b{ % O" V4 f$ x5 u* L
unsigned int size, segp;
! D0 U' g2 }( i/ Uint stat; </FONT></P>
- E$ Q( Y$ g v$ T% m, G5 w< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ 9 F9 h! T- d! I
stat = allocmem(size, &segp); 4 l: Y9 K$ z$ b- `. }
if (stat == -1) : N! i0 k" _6 K; g+ v
printf("Allocated memory at segment: %x\n", segp);
% N( J9 p) Y& \. [else
1 {5 K U* R4 q; C2 |# [# uprintf("Failed: maximum number of paragraphs available is %u\n", 5 A/ q, ~! o. P* _* E/ {
stat); </FONT></P>
# W: I: g8 a$ Q8 D$ {+ z6 H) E< ><FONT color=#0000ff>return 0; # \8 r: R; _- c- ^9 ~
} </FONT>
8 `! I" i7 N9 ^( f# \2 M( h8 j6 L! `% i$ S% C# j: @# N
</P>
/ U9 Z# c0 |: i$ S< ><FONT color=#ff0000>函数名: arc</FONT> ( u) u+ f/ ^- J3 [7 P( e
功 能: 画一弧线 4 G3 b% l. g3 z
用 法: void far arc(int x, int y, int stangle, int endangle, int radius); - }; o" x. _1 E+ C
程序例: , M; ~; w3 l- Y6 I, Y, V
<FONT color=#0000ff>#include <GRAPHICS.H>
' o) C# |1 U1 [3 e5 K) I7 g4 M#include <STDLIB.H>
0 @' B( G; w( G; V$ @5 k#include <STDIO.H>0 F1 L$ q6 X) M1 p5 o3 v
#include <CONIO.H></FONT></P>
' P" T4 n, O) B, T; E$ ^& O" `4 c< ><FONT color=#0000ff>int main(void)
" s- S8 h( E% T6 P" f: J9 ^) M1 c% I{
0 K0 q2 W$ O) y7 e9 v/* request auto detection */
, m$ F8 B6 M: I# U4 A( b4 Zint gdriver = DETECT, gmode, errorcode; . s! y- i* O" d4 M- k9 R7 R. u
int midx, midy;
% {- \4 L7 L1 [1 aint stangle = 45, endangle = 135;
3 k4 V8 N. Q" _; x0 o0 D, p1 V& jint radius = 100; </FONT></P>( x+ `3 {7 b! ?
< ><FONT color=#0000ff>/* initialize graphics and local variables */
0 d& |. k- D9 sinitgraph(&gdriver, &gmode, ""); </FONT></P>
: ]# T+ i' U9 j: O$ B" ^9 S7 ]6 v< ><FONT color=#0000ff>/* read result of initialization */
$ n' b: N8 C0 t2 ]errorcode = graphresult(); /* an error occurred */
0 O* V/ B2 a# H, U7 sif (errorcode != grOk)
c1 E# F$ M2 z9 `) F) @' C, u{ 8 ~7 h% \7 C: z' T0 Q2 Z
printf("Graphics error: %s\n", grapherrormsg(errorcode)); 9 L6 i7 z3 ]. Y
printf(" ress any key to halt:");
# X; a( W- @* n& @getch(); </FONT></P>
! Y" I- C5 e* v( {& n+ P< ><FONT color=#0000ff>exit(1); /* terminate with an error code */
% G9 j) l% n5 \( y. u- f} </FONT></P>, Z' ]8 V& ?' w _3 l" P- x: F' i$ [
< ><FONT color=#0000ff>midx = getmaxx() / 2; " m3 N3 X* g% k: W1 R+ J' n2 E
midy = getmaxy() / 2; 8 V$ z( J; X4 t, y8 N) V
setcolor(getmaxcolor()); </FONT></P>* U9 ^# w/ D$ B
< ><FONT color=#0000ff>/* draw arc */
' S. s4 i% u- U/ T. ^! warc(midx, midy, stangle, endangle, radius); </FONT></P>2 n+ x+ N5 s5 {7 p' b8 v/ \8 P" Y. h
<P><FONT color=#0000ff>/* clean up */ ' v' I( J5 a3 p+ O4 i: v1 k; D W
getch(); ( a1 u- w1 t0 B. a# X. A6 H! C
closegraph(); 1 Y. k0 O; U; b5 S7 V: t
return 0;
- `) |6 v' u' q# `0 Z/ L+ x& P}
" l, D9 g. a: H, x. X/ ]% I</FONT>1 i- e; P: t& U
</P>
, R3 [( t7 A/ k( |8 X<P><FONT color=#ff0000>函数名: asctime </FONT>0 g5 S Y2 J `" U y
功 能: 转换日期和时间为ASCII码 $ j8 e5 r3 z8 c5 J
用 法: char *asctime(const struct tm *tblock);
% c1 E# d# \: K! ]程序例: % H+ M* @. p0 L+ z3 v0 C) e
<FONT color=#0000ff>#include <STDIO.H>
" u8 H6 U1 y! n#include <STRING.H>7 d7 C0 u# [. u; f
#include <TIME.H></FONT></P>2 \8 u/ e) m+ }4 ?: ^0 U5 D/ q- `
<P><FONT color=#0000ff>int main(void)
* A$ _) K2 u- |- Z+ y2 [8 Y{ 7 ?$ E a, h7 W; Q: @& Z/ p
struct tm t;
2 T% O# n" A2 }char str[80]; </FONT></P>
! K4 ]" K$ {, a7 o, o3 T8 r4 ^( R<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>, ~- P' y/ J. ^) i* C5 @
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
! |' ~, p+ ]. s0 \. Wt.tm_min = 30; /* Minutes */ - D( G6 P' a# x8 k; ]5 x
t.tm_hour = 9; /* Hour */
8 L. w! ~0 y7 R$ U g9 X+ `; jt.tm_mday = 22; /* Day of the Month */
8 T' T6 h8 J w* @" X4 H) M- ]; bt.tm_mon = 11; /* Month */ 5 U; U( v7 x/ h7 W
t.tm_year = 56; /* Year - does not include century */ 0 ?6 Y! I r3 m3 {% ~& N( C
t.tm_wday = 4; /* Day of the week */ 8 }0 b' R+ G6 O/ _( R" _
t.tm_yday = 0; /* Does not show in asctime */ ! e9 o' r' f3 R0 k' \% ~
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
7 C, T0 O/ b! q2 \<P><FONT color=#0000ff>/* converts structure to null terminated ! D2 o3 o$ w" x" j6 F' I5 a
string */ </FONT></P>/ t' r0 w2 o8 j8 ]7 m2 l3 p
<P><FONT color=#0000ff>strcpy(str, asctime(&t));
- M% ?+ ~: \0 V7 Y- Hprintf("%s\n", str); </FONT></P>
4 f ]$ L8 f$ G7 `<P><FONT color=#0000ff>return 0;
! _8 ^0 k! y% R! S# e+ g3 ?- r% I}
/ e2 y0 j9 U! Y4 d3 G8 c
% E6 K. o. H& X. B4 q</FONT>3 j8 e5 H' ?+ z5 A
</P>, ~- R9 b n* v! Y, l
<P><FONT color=#ff0000>函数名: asin </FONT>! y! C/ {$ h* o
功 能: 反正弦函数 4 n6 z6 D; f& c9 _6 o% a& D
用 法: double asin(double x); $ l4 \$ z4 L! e* q7 r; x) f' Q+ Z
程序例: 7 Y) l/ B6 Z* }) B( m* O) |
<FONT color=#0000ff>#include <STDIO.H>3 M: k2 w7 M' H: ?1 Z
#include <MATH.H></FONT></P>
( z" N: A& j# C, D<P><FONT color=#0000ff>int main(void)
0 g+ ?6 ^* @( ]$ X8 _{ , P: i; s0 p# ^" l S+ \9 `6 k- d
double result;
W2 x a9 |9 Qdouble x = 0.5; </FONT></P>
6 N) a4 s$ D; g2 l3 p; Y+ k<P><FONT color=#0000ff>result = asin(x);
+ f3 r4 M& n4 a$ d4 m1 Lprintf("The arc sin of %lf is %lf\n", x, result);
8 }9 q1 G R! F" Hreturn(0); 5 M* l$ P& Z" r
}
4 O" B7 J- a/ s</FONT>
! \- l( P% R8 Q* ^. e5 _ @7 { p3 y( H
</P>+ g% V2 O' g" }; o
<P><FONT color=#ff0000>函数名: assert </FONT>
' G0 E( ?% j% ~" `/ N: L功 能: 测试一个条件并可能使程序终止
: ]" S& \$ S7 s! I$ {7 C用 法: void assert(int test);
( F; [% x y7 k# A5 a程序例: 8 {" w. ~' m8 A$ Y& @& L
<FONT color=#0000ff>#include <ASSERT.H>
/ @2 x6 ^$ e; H/ g$ q- Z+ k6 l#include <STDIO.H>) Y3 G$ N! l7 E; x2 z
#include <STDLIB.H></FONT></P>
; a4 a" Z% `' q) f8 n, [<P><FONT color=#0000ff>struct ITEM { 5 G% Z$ i2 A' }1 t9 F ? H
int key;
9 K' ]. X( |6 fint value; 2 ^3 R3 }9 i7 X& Y% @
}; </FONT></P>+ e: u$ M: ]" m1 D. R, I& C6 [: u& T
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
- l {5 n* w: n5 v2 \$ Yvoid additem(struct ITEM *itemptr) { 4 g& ~& @+ t; z- c% D( F9 E! ^5 s
assert(itemptr != NULL); # G% e* a/ K, n E
/* add item to list */
: @0 }( ~% ?/ z( E* B( X+ w' _0 g} </FONT></P>( x+ W) ~* o7 K& k7 f ]5 v
<P><FONT color=#0000ff>int main(void) 8 r/ ~$ o1 w% C) y# ~6 X
{ " T9 `6 g( i+ t. y- r
additem(NULL); 3 \6 }6 X: u% R; k8 E% }
return 0; 0 n' O! U u" {3 q8 \' Q2 L
}
5 H" s) A2 c5 B3 T</FONT>
$ `7 H. P* f( W. v7 G
) x3 @! \6 r" S6 L" l5 j" p</P>
1 r, D R5 l8 U9 v1 d y! _<P><FONT color=#ff0000>函数名: atan </FONT>
8 @ A- P" n9 d- Y' ]功 能: 反正切函数
; K) q! j* j' B; B& s5 S; g用 法: double atan(double x); 6 E0 h8 m( d! o% ]- K6 s
程序例: ' ~- T, R. }: |+ `9 G: T6 V, C7 K
<FONT color=#0000ff>#include <STDIO.H>- k/ V/ D" ]# _
#include <MATH.H></FONT></P>
! X6 \- P7 p% g4 ]<P><FONT color=#0000ff>int main(void) 0 \% y; i @- K# E. I- `
{
# O& m4 l9 v3 h; E i# K! vdouble result; & E, Q7 N, p q
double x = 0.5; </FONT></P>
6 z( b& \3 ^2 o; R0 \<P><FONT color=#0000ff>result = atan(x); 0 v/ O2 y% M8 b X) H
printf("The arc tangent of %lf is %lf\n", x, result);
+ M# p( ]# j9 Q' U Rreturn(0); % J3 C$ u9 B0 [
} # Y! |- j$ {. B/ n0 j& G' c2 X# h- _" e
</FONT>
+ r; p9 o9 y5 w5 ^</P>8 M. n' q" T5 @9 Q6 z
<P><FONT color=#ff0000>函数名: atan2 </FONT>
' I6 k8 D3 [' V# b- [9 Z& L* I4 h# H! L功 能: 计算Y/X的反正切值
. b, t0 x1 ]0 a/ X, s$ z# B用 法: double atan2(double y, double x);
/ j5 `; }4 I4 c1 a& c# b% }' \0 m程序例: . Z+ l/ Z7 r. D/ t, I) b( z
<FONT color=#0000ff>#include <STDIO.H>
5 r) C' M1 W1 M* p2 k! F/ N* W#include <MATH.H></FONT></P>% O6 j% Z7 ]$ V `: O
<P><FONT color=#0000ff>int main(void) 2 ?; O1 j$ l$ U% x
{
n- C# ?$ |0 u* r0 d& xdouble result; 1 l6 e; |& {* x# {5 z6 P
double x = 90.0, y = 45.0; </FONT></P>0 i$ f3 [0 G' o2 @+ f* ?- r
<P><FONT color=#0000ff>result = atan2(y, x);
3 B) B# }" Q. Cprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
: m0 \. d" C& K' ]return 0; # v; \6 q* G6 d% F) u
}
2 p5 {" r* Z# ~</FONT>
- H0 E' ?3 C+ N3 `$ s</P>- M3 y5 ^! b+ _/ t# m5 [" S0 G
<P><FONT color=#ff0000>函数名: atexit </FONT>
; M+ l J& F4 N$ L* M4 m0 x功 能: 注册终止函数
# |. c! X5 T5 x用 法: int atexit(atexit_t func);
9 u" a8 \; w: s% u9 m) [1 s2 \程序例: ! `: I7 W9 O u4 z- N1 Q! y
<FONT color=#0000ff>#include <STDIO.H>) G$ J- r7 e' U' G
#include <STDLIB.H></FONT></P>
7 [ p) S/ k7 o- F$ h6 m<P><FONT color=#0000ff>void exit_fn1(void) ) d$ w2 o; c: t9 V
{
`# j( ^2 r/ _4 K% g$ \$ X5 |, M1 Hprintf("Exit function #1 called\n");
! T& V# O9 \8 i2 d5 k J0 W) T} </FONT></P>
5 n2 H* \, D- t' K9 U2 F- d2 J- N<P><FONT color=#0000ff>void exit_fn2(void)
* l- L% W4 w0 z; C4 Z s6 Y{
4 d- x I( D) _& K5 `: b- g3 h, j$ ^printf("Exit function #2 called\n"); 8 o& P; o' L' C+ u8 s2 ` i- T
} </FONT></P>
# d! v1 [! B# P9 I<P><FONT color=#0000ff>int main(void) ; H t/ h) m) I& ^8 Z5 r& G
{
" |) c, ~- u8 E% u# D) w/* post exit function #1 */ ! q: E8 O$ f, u2 n2 M, _3 M. n
atexit(exit_fn1); # x8 f$ B6 r6 k/ n9 ^
/* post exit function #2 */ . @5 M% V. o6 T' i7 V0 _& @ x
atexit(exit_fn2);
$ g8 ^2 E- R' X5 ]: d3 dreturn 0;
w, q# e) v O" F} : G. b1 i/ s) E' U& p" _8 \* n' r
</FONT>$ Z5 G3 e6 |+ ^9 Q9 M# [. c
$ E6 W5 w0 f3 q6 [, f' j- m# O
</P>. \! |% G+ [# J+ Y
<P><FONT color=#ff0000>函数名: atof </FONT>8 }# f" H1 \% j; ]7 |) D
功 能: 把字符串转换成浮点数
" `# r; @- N9 T+ B% r* H用 法: double atof(const char *nptr);
4 N, Q8 M: _7 R% q0 |3 H程序例: " h% n# y4 J( e. ?! p
<FONT color=#0000ff>#include <STDLIB.H>) ]/ N. t8 t( i2 T
#include <STDIO.H></FONT></P>
4 k: {: l- I/ W<P><FONT color=#0000ff>int main(void) " ]* }1 ?# |2 w! L, m
{
6 `' u5 d; Y7 V4 J1 Efloat f; 6 }8 W, K- K( K! _9 m6 A
char *str = "12345.67"; </FONT></P>/ Y9 l' M) M* b. o* x2 x
<P><FONT color=#0000ff>f = atof(str); - ~3 | b( E1 L& t+ b1 o
printf("string = %s float = %f\n", str, f); ! a6 t& K% J5 L4 s# e2 M+ e) l
return 0;
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</P>- w( V9 M4 y9 n
<P><FONT color=#ff0000>函数名: atoi </FONT>
& [6 I4 _5 k) j6 _$ P. \ M功 能: 把字符串转换成长整型数 1 \5 V- _6 [% v% ~( a# c% z
用 法: int atoi(const char *nptr);
2 t. H6 X: G) s) b程序例: / _6 i1 Y7 c/ z/ d+ f
<FONT color=#0000ff>#include <STDLIB.H>0 X5 z# }) d3 \
#include <STDIO.H></FONT></P>% _* o: K2 T" h" }' p4 U
<P><FONT color=#0000ff>int main(void)
+ p) R( L4 w& K3 ?1 a: T& q{
7 A, C8 S* P8 i$ p( yint n;
# T8 [3 y& A& A" i+ [, P- T: Achar *str = "12345.67"; </FONT></P>
6 G* w7 a5 B! \$ X- {- o<P><FONT color=#0000ff>n = atoi(str); , g& Z8 {0 k. m; h% v, Y
printf("string = %s integer = %d\n", str, n); ' B& m9 a7 k( y! O
return 0;
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</FONT>
3 @! h0 M/ R; m! B; L4 s</P>
8 q. I- }4 B) p, C9 S I5 r<P><FONT color=#ff0000>函数名: atol </FONT>
8 l9 ~; _8 u. i功 能: 把字符串转换成长整型数 # I; x& t9 j% s' c
用 法: long atol(const char *nptr);
* F! E# B: W! Z! G: R# k程序例: </P>, G. J; }) R2 k: `: C& z8 c
<P><FONT color=#0000ff>#include <STDLIB.H>$ e, {7 l: M0 \. H G
#include <STDIO.H></FONT></P>
6 p; A; N/ k. Q, i<P><FONT color=#0000ff>int main(void) * k+ c( R0 c0 \! K
{ 0 Y1 v* c2 J7 b$ W2 i5 U
long l;
3 b$ y8 q. d% j/ b7 G$ i/ achar *str = "98765432"; </FONT></P>
, g: E4 B2 s" R. f0 x' c) ]+ K<P><FONT color=#0000ff>l = atol(lstr);
/ V9 I- N" v5 h9 p. Lprintf("string = %s integer = %ld\n", str, l);
4 P0 z1 P4 W' d( `# o$ ^0 f( |return(0);
; T) R6 y; {" s9 n) u2 W$ z}</FONT></P> |
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