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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>$ ]2 W% v" `7 q2 p
< ><FONT color=#ff0000>函数名: abort </FONT>
# {1 x, x; ~* R: j& V# x功 能: 异常终止一个进程 4 V8 f5 F# y2 \/ l( Y) M
用 法: void abort(void);
. L8 } Y0 R/ c: W7 k程序例: 8 K/ e9 y/ c/ c" ]
<FONT color=#0000ff>#include <STDIO.H>* K- c1 y6 f- y5 Z
#include <STDLIB.H></FONT></P>
2 j) @# k6 t! P* R/ K: T$ `8 }, t< ><FONT color=#0000ff>int main(void) # A6 Y* i9 h6 S+ E3 b3 P, n* P
{
2 H7 C- U7 z6 K; c q5 Q0 B6 M9 aprintf("Calling abort()\n");
4 H$ X* g0 G2 m) p- `4 @abort();
6 o- n" N" _# Q0 i5 G$ nreturn 0; /* This is never reached */
! o: j* ~ A" Q2 w' X' T}
# e/ H& _; t9 L</FONT>
9 B/ M3 F7 n, U" \) O</P>
4 w, Z5 G8 n0 ]# }% ~$ x< ><FONT color=#ff0000>函数名: abs </FONT>
$ _) F4 }2 L. h8 o c功 能: 求整数的绝对值 / ^# j- B0 c% n& ?7 S" p. q
用 法: int abs(int i); $ A P/ @9 w7 x; t) a. h9 l
程序例:
$ V+ a' f8 J8 E$ g1 `- q0 X<FONT color=#0000ff>#include <STDIO.H>" X: @( G, a- }& P
#include <MATH.H></FONT></P>* o! C) X3 T; K/ w/ `! f
< ><FONT color=#0000ff>int main(void) 0 w' x! S5 p7 h1 T# j
{
+ c; [3 X% m% d3 sint number = -1234; </FONT></P>
- P- o! R4 D _( f( C3 h< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); " b' R9 U$ `7 Z* c( }( D* j
return 0; 7 t6 `$ @6 v- p, |; J0 z
} 7 u& A( K( ?( C d: ? ^4 f
</FONT>
( Y7 @$ X2 ?6 a8 ]$ T- O</P>/ a9 P) v' o& {8 e7 R( U
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>" U5 F+ t3 }7 ?, j
功 能: 绝对磁盘扇区读、写数据 ! h7 r; Q# h$ u9 h; c
用 法: int absread(int drive, int nsects, int sectno, void *buffer); : K# E" ^1 z/ K7 ^0 n: D9 W
int abswrite(int drive, int nsects, in tsectno, void *buffer);
6 d3 `% Q X( }5 B- {. M程序例: 9 J. ]# Q8 ^' {# Z' _( \) H
<FONT color=#0000ff>/* absread example */ </FONT></P>/ i! H) Y: s0 Z/ ^. a1 |' r
< ><FONT color=#0000ff>#include <STDIO.H>
7 N: W$ B8 M6 K; `#include <CONIO.H>7 n; V2 U; f5 ^: K! @2 `9 ~
#include < ROCESS.H>
0 \" e+ [1 ^5 {/ R#include <DOS.H></FONT></P>! \; n: {9 L0 _+ M; F* p M4 N; U
< ><FONT color=#0000ff>int main(void) + S7 E* }% f9 z+ t% W& d
{
6 O0 w; u2 h, z w, n7 s0 [/ h. Y8 Aint i, strt, ch_out, sector;
% G0 V& Y& x" w2 B) Achar buf[512]; </FONT></P>
& J$ V: b& f4 ]6 q# ?! R< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); " u& w' }& M2 u9 z7 R5 z
getch();
) ^! x) n/ ]+ D3 Z9 Psector = 0; % h3 n8 W6 P: v
if (absread(0, 1, sector, &buf) != 0) 6 r$ }9 e3 t0 {/ w0 E
{
; D+ y3 J/ `5 C: U/ J' Wperror("Disk problem"); ' N9 T" f- l$ b/ p
exit(1); : S: X. S) l7 d5 w' v9 z4 R+ [
} 2 @$ Q& J v$ q0 N4 g2 X
printf("Read OK\n");
3 f3 A* i g. Z' {; u( }2 y0 Mstrt = 3;
; @' I3 M9 @/ C' v2 @for (i=0; i<80; i++)
* t$ L- z' c' y! f{ 2 s! T8 |7 W! G6 I* J# ~
ch_out = buf[strt+i];
& }# g$ f- Q* s% U9 I& o' [putchar(ch_out); % {& w: E! ]4 ?! R0 ]# ~; w
}
$ ^* o+ }, h$ S, t& \printf("\n");
1 X9 } g$ f& C% X& ]: n/ v Jreturn(0);
# o/ x! M8 L9 S9 J% X3 r% R- k} ( _/ a8 ?6 I+ g9 M- {
</FONT>
# [9 I6 D2 X& h/ x0 P6 R+ D/ H. }" v' S" ?/ z* Q
</P>. X, g$ w: d/ k
< ><FONT color=#ff0000>函数名: access </FONT>+ F7 M" Y) e6 K
功 能: 确定文件的访问权限
; K* A5 O, J/ S) @用 法: int access(const char *filename, int amode);
c9 R$ V$ F' {8 N7 F" z程序例:
+ \( t6 `4 L3 `) n- d<FONT color=#0000ff>#include <STDIO.H>, X7 h, F4 x8 s; l% x3 |2 v5 l
#include <IO.H></FONT></P>
( v3 d2 K6 |& F, A< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
* r- z+ y8 H, P* k: E) t< ><FONT color=#0000ff>int main(void) 5 Y, h+ u& i: Z0 K/ {9 \) Y
{ * C3 U$ \8 T) b5 x3 Q; P
printf("Does NOTEXIST.FIL exist: %s\n", & [ W& R; \1 F$ N& O, U# W
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
: V3 q9 [1 k: Z9 t. Greturn 0;
3 J5 r- j0 v- {4 _} </FONT></P>- [9 i8 ?: R) r; a m8 a% Z
< ><FONT color=#0000ff>int file_exists(char *filename) " E( p. [* J& n: f( ~
{
0 J1 B8 R2 W0 [) p, Dreturn (access(filename, 0) == 0); ' t! M/ ^( B! g# a9 J! b; a* y# u
}
2 S8 Y* K/ m2 |4 ^2 v! j</FONT></P>
3 [: e) u1 \6 ?2 s9 \ Z$ M. [, H- s< ><FONT color=#ff0000>函数名: acos </FONT> g- q% d* _- g% `# a% T
功 能: 反余弦函数 & h! A. P+ Y1 }/ N# C
用 法: double acos(double x); " C/ f- O2 v6 E) D! e( D
程序例:
) @& l5 V- k& K& Q6 z% d" O<FONT color=#0000ff>#include <STDIO.H>
5 p" m( E! h( S0 `& q#include <MATH.H></FONT></P>& s9 I F4 L, ~, \- M. J
< ><FONT color=#0000ff>int main(void)
* M! ]' [; T& S, ~+ I( P{
- O3 N7 ]$ c% gdouble result; 4 m2 q3 f7 j" i4 Y/ Z
double x = 0.5; </FONT></P>
, Z8 G- r! e, r7 ]6 o" s$ Y< ><FONT color=#0000ff>result = acos(x);
0 Q [, k# a' y$ t# U% sprintf("The arc cosine of %lf is %lf\n", x, result); [8 M$ p) g/ Q' E. A* O
return 0; / a6 G0 p9 |9 [2 g9 h4 M* V
} </FONT>
* |8 ~1 s9 r. T7 F
! x* p' C, Z1 V/ Y</P>! S- |2 [& U( \3 X
< ><FONT color=#ff0000>函数名: allocmem </FONT>
# B& ]; h( i! e) m" ^功 能: 分配DOS存储段 5 `# {% C6 I0 X5 d+ W0 j
用 法: int allocmem(unsigned size, unsigned *seg); + s& I# X6 V" N( U: Z" Q
程序例: 5 H! u+ N4 ~$ f4 d! ~) O: J& ]& [- D
<FONT color=#0000ff>#include <DOS.H>
- P7 ~) J/ y# O#include <ALLOC.H># O( T' ~% ~( L7 |6 s- t L7 l1 D% l
#include <STDIO.H></FONT></P>
, X% m2 B# V* B" R, T< ><FONT color=#0000ff>int main(void)
, D3 p9 Z- j6 z7 @" D{
0 ~( b) [4 \# U$ \4 g/ L/ Q h$ @unsigned int size, segp;
5 P, F# Z6 f6 J' K! Pint stat; </FONT></P>7 G; ?! d, T! N1 [' E7 x! W
< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ , e6 b0 ]8 g% W- f, a
stat = allocmem(size, &segp);
' ` e; [. K+ ~( y. \( X0 I" Xif (stat == -1) 5 R* o7 I& l; M3 h
printf("Allocated memory at segment: %x\n", segp);
0 z/ N* z4 \! k3 Welse , U2 [1 p( D! w4 R( [
printf("Failed: maximum number of paragraphs available is %u\n", * A, X; ^3 @* M8 [
stat); </FONT></P>
% z; N8 s/ n" ~' J1 O< ><FONT color=#0000ff>return 0; $ C- I) g6 U0 }" F
} </FONT>
. A4 N2 t( b% W$ L, ]. v# L
3 L+ j7 j. H% @</P>
- t7 {1 V/ o* C6 [5 B" T1 e< ><FONT color=#ff0000>函数名: arc</FONT>
4 n6 Q; o* N9 L v }7 B3 B功 能: 画一弧线 , x; r. u7 o& { M4 N
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
6 L' N6 ?, V& Q. L) Y% h' }程序例:
, F9 z, q( z+ m2 G<FONT color=#0000ff>#include <GRAPHICS.H>
& P, H$ b6 {& C) B. _ ?+ n0 A#include <STDLIB.H>
5 B7 c G9 h8 C) s7 n#include <STDIO.H>
) S6 V* y* N, f3 l d/ ]#include <CONIO.H></FONT></P>: ?- v; s' P1 B4 y* e5 J
< ><FONT color=#0000ff>int main(void) * ~. I2 g& Y$ b' y: k I
{ + g0 q% G& G8 d, T( i
/* request auto detection */
5 G1 o2 O0 c4 _$ Fint gdriver = DETECT, gmode, errorcode;
9 N" e7 |: o3 i: d% qint midx, midy;
9 a% {3 K; }, a- Lint stangle = 45, endangle = 135; & @& T4 N5 r3 }, i' m
int radius = 100; </FONT></P>- K0 M% ?- i$ ^7 H
< ><FONT color=#0000ff>/* initialize graphics and local variables */
M& T. w; Q0 G: ]& ]initgraph(&gdriver, &gmode, ""); </FONT></P>
, M! f; Y* `# C% n! y# u% ?< ><FONT color=#0000ff>/* read result of initialization */
! E% ]' F o7 M+ ~" Oerrorcode = graphresult(); /* an error occurred */
' Z% b/ D' M& m6 z8 d' yif (errorcode != grOk) ' v) K7 M' \! E+ m
{
g4 X) `* Y* c, m) kprintf("Graphics error: %s\n", grapherrormsg(errorcode));
9 v0 Y! k4 {/ ~9 b. `9 M) I, zprintf(" ress any key to halt:"); 2 c+ ?6 L% |: k* R( O5 C! {
getch(); </FONT></P>" Q6 L, z B# _+ y% w
< ><FONT color=#0000ff>exit(1); /* terminate with an error code */ ! E8 r0 m) m! \
} </FONT></P>' [2 }2 V7 w& n7 C* }' U; E, n% [: ?, F
< ><FONT color=#0000ff>midx = getmaxx() / 2; ' Q! V( {0 m, S/ g0 r7 F8 x
midy = getmaxy() / 2; % Q) G) ^: z( F, T, n: l) V4 l4 F
setcolor(getmaxcolor()); </FONT></P>
4 G' Z& [) A) o) t9 h< ><FONT color=#0000ff>/* draw arc */
' V9 E; x, C# T. e+ Carc(midx, midy, stangle, endangle, radius); </FONT></P>
1 f4 |8 `" _1 I6 r0 |<P><FONT color=#0000ff>/* clean up */
1 o! _% h+ B8 X7 `. cgetch(); 6 I' ~/ y/ V W6 U2 l3 l
closegraph(); 7 Y/ d: p7 d, Y7 w# d, m D& a
return 0; ( g f2 g: m# {
} , J$ \) M4 s/ a' r( t$ q" l4 ?
</FONT>: b. f/ `1 Z3 _- c
</P>
$ a* J( L8 D i- j$ F<P><FONT color=#ff0000>函数名: asctime </FONT> ^ u2 O* {5 v& ]' j: [; K- S
功 能: 转换日期和时间为ASCII码 - G- p8 X) q6 s7 r: G0 q R
用 法: char *asctime(const struct tm *tblock); 7 M$ E& F4 [0 G3 D" m. M% V5 X( X1 Q, C
程序例:
1 f; D$ U5 H C<FONT color=#0000ff>#include <STDIO.H>
" S2 m8 H, _5 b. x3 q#include <STRING.H>
/ D( j4 r$ s1 x7 a& \#include <TIME.H></FONT></P>- c& l' j9 A) c/ T$ V$ m
<P><FONT color=#0000ff>int main(void) ) z9 D' b6 @' B0 F
{ 6 l9 h% ~; [7 f- ]& ]
struct tm t;
1 B d5 y1 i1 A; m5 ichar str[80]; </FONT></P>
# s2 [; B6 z5 c: m: r$ t& F<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
# Z9 T \# E5 n' r8 A3 n<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ & W: R5 }$ U( m. Y
t.tm_min = 30; /* Minutes */ , K; @5 H. y; A t2 m
t.tm_hour = 9; /* Hour */ ) m1 t0 f5 R" |8 a, @5 W# \( h
t.tm_mday = 22; /* Day of the Month */
1 b$ v; o& s! D9 n* ?% m+ Ct.tm_mon = 11; /* Month */
, C7 T2 v( M% y$ h8 Vt.tm_year = 56; /* Year - does not include century */
" i V: P! {, \- C& H0 A: N# j6 T) Dt.tm_wday = 4; /* Day of the week */ - |4 L! j; |* R3 M/ N
t.tm_yday = 0; /* Does not show in asctime */
# N% L, `/ T8 j h& t2 _t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
: x7 p* x6 N+ m<P><FONT color=#0000ff>/* converts structure to null terminated 6 U- r6 S! s) g
string */ </FONT></P>
/ U& R0 W" j2 t( x0 ^/ y% B<P><FONT color=#0000ff>strcpy(str, asctime(&t)); ; X* j! n" E: q( H
printf("%s\n", str); </FONT></P>
4 ~1 y3 ^* H" h' M$ v3 V2 k<P><FONT color=#0000ff>return 0;
3 u; B( b! B0 ]/ @. a: d2 O. M} . P' a# A5 }' m+ t1 R- ^) I- L
( r6 W$ ^, `, z9 `9 s/ `</FONT>5 Y' i. |3 p- ^7 s) Q
</P>
! h* c+ H2 ~0 M; }<P><FONT color=#ff0000>函数名: asin </FONT>
( `' H6 f1 z, k# z功 能: 反正弦函数 $ K ~, n" L1 u ~3 L, e
用 法: double asin(double x);
4 t2 c5 ~' c; {* _( s程序例:
8 J: }+ M7 z h% N0 L1 j2 L9 I<FONT color=#0000ff>#include <STDIO.H>. G, s) k3 q6 C
#include <MATH.H></FONT></P>
2 R( ]! i0 \* d4 Y& Q# A" N6 w( x3 I<P><FONT color=#0000ff>int main(void)
/ @, J8 }6 ~6 H, |0 _) M{
7 c e: `/ i$ |double result;
& V) o$ f) W( u; ~. ?# ]0 }double x = 0.5; </FONT></P>* b2 E- @$ y' o8 r% l* [' w
<P><FONT color=#0000ff>result = asin(x); 1 {9 b$ P7 u0 ?) A$ j: A
printf("The arc sin of %lf is %lf\n", x, result); - D8 N5 @2 E# J3 m; z6 n6 T5 l
return(0);
3 n! { ?, \* t7 o# a) ?" I}
2 f# K ~& O a* d</FONT>* N& m% J% B# y3 C) ?
) c# x7 e: w* w: s$ W: R
</P>& ^( e, d& L9 ^* I' V
<P><FONT color=#ff0000>函数名: assert </FONT>: C4 h! p& s2 O' Y* w
功 能: 测试一个条件并可能使程序终止
0 f$ e; z+ S# \+ d5 p! K) b用 法: void assert(int test); ) |% D) K0 {( R% m5 r4 \! g
程序例: % B- }: E2 w5 N3 x" w
<FONT color=#0000ff>#include <ASSERT.H>
; Q$ r4 i* ~+ I7 Y( m: I1 w#include <STDIO.H>
. w4 r1 U9 A5 p) u% n#include <STDLIB.H></FONT></P>
. y; w/ L" T- F' t) `# n- B<P><FONT color=#0000ff>struct ITEM {
) t! x. l: e5 I; p' A- aint key; y/ C- L+ {3 i0 c. E( e" k4 f7 }
int value;
- ]4 ^8 r3 x2 X; ^% R& u& M K}; </FONT></P>: c" o: @, F' [6 s
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */ ' X1 j+ f% w+ u. w
void additem(struct ITEM *itemptr) { * Z; H; o) I) Q/ k) r
assert(itemptr != NULL);
. H: S0 ?3 I* @( p/* add item to list */ ! z) }0 h: z& I$ ^) \9 A
} </FONT></P>
& k7 S) L3 \! l+ y2 X<P><FONT color=#0000ff>int main(void) / y# ^6 w$ l5 k
{
8 Z$ C$ b6 H! B: Eadditem(NULL);
" h4 P" _8 d6 }6 c5 E+ Nreturn 0;
+ H3 n$ G' C6 Y) K7 d}
# J9 j8 F& W+ }8 q</FONT>1 F( J% n8 ]2 ]4 h8 @
$ k4 ]8 J9 J+ E8 L6 O</P>
3 I* ]4 Q, c2 E$ @. }4 ?* }<P><FONT color=#ff0000>函数名: atan </FONT>* `0 v n2 J( X- Z- K4 Q8 z& X: o
功 能: 反正切函数
0 F. A, E& f0 \. f$ X( U+ A. r用 法: double atan(double x);
, \7 |* t& b( W' H: J& Z程序例: 7 [0 w. b7 m, ]" _% M5 ~0 O
<FONT color=#0000ff>#include <STDIO.H>
+ t, p& Y# C2 F6 G. b#include <MATH.H></FONT></P>: i6 F& v5 C1 s% y2 f# O( P- P
<P><FONT color=#0000ff>int main(void)
1 g! C, L, D- R3 s) S{
/ w8 j4 P; ~$ P. q0 Ldouble result; 4 d& m7 x5 x' V( W
double x = 0.5; </FONT></P>
( h& \) U6 }* ^ a6 }5 |<P><FONT color=#0000ff>result = atan(x);
' q3 q( b P) M7 [4 @7 t( N2 fprintf("The arc tangent of %lf is %lf\n", x, result);
1 X5 s$ h: |: W1 u8 a0 Vreturn(0); 8 t- i; ~/ B4 {2 ^" t% n% N) T
} ( G- z$ y1 X+ m! M2 T. w N; E
</FONT>
3 G' F1 h1 P# H3 g# b6 ^</P>4 p" t' T3 i4 s& o1 C: i
<P><FONT color=#ff0000>函数名: atan2 </FONT>$ P% Y: D) y, D z
功 能: 计算Y/X的反正切值 ; w/ p( G* q4 P
用 法: double atan2(double y, double x); ( s6 M. D8 K. M" N) h
程序例:
5 d7 {, x" M8 m" j<FONT color=#0000ff>#include <STDIO.H>
! h5 h5 v) N9 F4 r& Z: X#include <MATH.H></FONT></P>
( a6 p4 Z- ?" P/ A0 j/ e<P><FONT color=#0000ff>int main(void)
7 y+ O% ]9 v: [+ p{
: J. g& u3 o- P+ A5 G0 adouble result;
6 J1 }1 E: P& p q0 V" z' ~double x = 90.0, y = 45.0; </FONT></P>
! |2 j" B( n- f& l<P><FONT color=#0000ff>result = atan2(y, x);
2 C: A/ l1 A6 v% V& ]! Uprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
) H& f+ d3 q8 q* w3 Zreturn 0; 3 c# \" }! v) x/ a/ O
}
& H0 _" d8 Y% C) c6 G( c</FONT>! { v) B- U: a9 u
</P>* T8 V3 i" z7 W. @
<P><FONT color=#ff0000>函数名: atexit </FONT>
; A: n2 n+ `3 ^6 f功 能: 注册终止函数
) U& j! }. t8 l5 m% t用 法: int atexit(atexit_t func);
* E$ f1 v, J& E- C6 V; l程序例: . n* g. h2 G+ Z4 j' B7 X
<FONT color=#0000ff>#include <STDIO.H>6 ] c) t0 T* u& u* _! L7 Z
#include <STDLIB.H></FONT></P>
$ r5 D* w$ l. S7 G$ o: ~<P><FONT color=#0000ff>void exit_fn1(void)
+ ~4 s2 x6 ]! b0 {4 C& }{
0 S3 ] Z) o4 t* `# I- Hprintf("Exit function #1 called\n");
9 ^3 Y+ ]9 R, }2 |& ~( g7 M} </FONT></P>
; h' R1 m( m; b. e" s8 b: N& r5 Z<P><FONT color=#0000ff>void exit_fn2(void)
! @0 @; [* t# f2 U+ K' c c+ u2 U{
% _5 P e' \; [' ~printf("Exit function #2 called\n"); ! p! X, ^, W, A! S7 T
} </FONT></P>
$ ]4 x- R [/ c3 L- B& z' L8 t<P><FONT color=#0000ff>int main(void) + D8 T- G5 e4 C0 _$ x( B( m. b
{
8 ^( U, A6 V8 A4 N/* post exit function #1 */
; Y9 D9 X( V6 e0 v9 Aatexit(exit_fn1);
- c% j* k7 l: S+ u/* post exit function #2 */
^1 n& v" W! W, M9 eatexit(exit_fn2); 2 L9 z* f3 g! l$ y, D' p4 N# r, Z
return 0;
4 R$ E1 i. a" ~7 [( N* O; Y} $ p5 I$ \5 |& l+ y" ], p
</FONT>, c& w) c' r$ z- O, S1 a
) D; F* T$ S4 i8 T
</P>' y7 D& ?; H% j3 x2 t1 C- E0 y
<P><FONT color=#ff0000>函数名: atof </FONT>3 Y. K6 y" W; t6 v( r% y
功 能: 把字符串转换成浮点数 ( D- j' L9 V' e+ ^
用 法: double atof(const char *nptr);
* u8 l, A$ |( u' U2 F) }8 y程序例: ; w8 r% O) K5 d, X, a3 w1 Q2 I
<FONT color=#0000ff>#include <STDLIB.H>7 D# P+ P5 H- b- W: o/ q2 E R& \
#include <STDIO.H></FONT></P>) N3 `: j0 |3 b1 p+ T' a$ j; z
<P><FONT color=#0000ff>int main(void)
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float f; 6 k1 J' o; U3 W( w5 P1 H
char *str = "12345.67"; </FONT></P>
( C+ J6 U* }0 k2 @2 \<P><FONT color=#0000ff>f = atof(str); 8 X) q0 c+ m) J1 f& U1 O5 K0 r
printf("string = %s float = %f\n", str, f);
! {* P. c5 f$ \( p6 p6 Lreturn 0; 0 |" R1 x* `8 K
}
6 G+ B1 d l# d; p* G</FONT>
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<P><FONT color=#ff0000>函数名: atoi </FONT>
C6 o0 A5 T9 Q( A* Z4 G功 能: 把字符串转换成长整型数
+ Q. p' s( C, G0 x6 L# X2 P用 法: int atoi(const char *nptr);
# e; |/ @$ l* K8 J4 D' a p7 d$ i程序例: " p7 P! y; a) t% d0 k5 B3 x% ?' o
<FONT color=#0000ff>#include <STDLIB.H>! v4 ^2 p3 l0 F- e/ W) V
#include <STDIO.H></FONT></P>
: U' j6 v; k% R5 _) Y# {) c<P><FONT color=#0000ff>int main(void)
1 [& i K0 o/ @! A{
- Y X7 Q, g/ \' M& Qint n; / R% R8 b& a: I U
char *str = "12345.67"; </FONT></P>
" j/ K I4 V( g1 y6 S+ j, |* _<P><FONT color=#0000ff>n = atoi(str);
7 S: p* ^3 D9 k5 n3 ~; ~4 M5 qprintf("string = %s integer = %d\n", str, n); 2 a4 V+ \( J# U. E
return 0; 0 \, y% o" ^( M) F, ^: S* b. K
}
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</P>
5 Y6 B) v" m% L4 \( i5 @! ^<P><FONT color=#ff0000>函数名: atol </FONT>
+ y1 c+ w$ M5 {* U+ b功 能: 把字符串转换成长整型数
# Z6 [; u2 D. M" S用 法: long atol(const char *nptr);
6 E0 c; |/ L9 u* G% G& p8 L程序例: </P>
2 ~' [. g8 e1 ? n @<P><FONT color=#0000ff>#include <STDLIB.H>
; Z7 {5 U: B& P1 `7 d#include <STDIO.H></FONT></P>1 \5 M* _8 t& u7 _
<P><FONT color=#0000ff>int main(void) % v" d. Z+ h/ J) M9 @# X0 _) W
{
9 f# n5 @& s9 M/ C: zlong l; $ R& x6 g: G- P8 S
char *str = "98765432"; </FONT></P>
6 [( R# W( o0 \: Z5 X I<P><FONT color=#0000ff>l = atol(lstr);
' Y! z# r4 O# ~: O9 Jprintf("string = %s integer = %ld\n", str, l);
) W0 ?) _. V. E! w! Yreturn(0); 7 g+ ~! P" x; Q7 P% r
}</FONT></P> |
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