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< ><FONT color=#f70909>关键字 <a href="http://hackbase.com/hacker" target="_blank" >数据库</A> 对象
0 d+ V Z9 G. v7 \原作者姓名 Fang</FONT> </P>
D$ I; @7 R5 F2 q+ h& L< >SQL SERVER5 s5 T- B) t2 m+ @: t: p
取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法7 {; @( J+ [$ l1 W
系统存储过程sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb</P>
! W) r4 P- \4 z< >或者</P># ^$ ~& \0 u- h! h
< >USE master</P>; K. C! k# T F! z1 a! i
< >SELECT sysdb.name AS dbname, xlogin.name AS owner FROM sysdatabases AS sysdb LEFT JOIN sysxlogins AS xlogin ON sysdb.sid = xlogin.sid</P>
" K8 u; S7 { Z2 W r9 M* @< >
; d z% G4 X6 q2 R% `1 M, c6 k! u8 L1 Ysp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpdb获得的内容更准确:第二种方式无法获取Windows NT登陆用户。</P>! b0 U. Y8 W! j0 `. g: `" y, f2 L. h+ g
< >取得表的方法: s6 u5 \& x7 i8 l- ]
系统存储过程</P>
) F9 G) W" Z8 V8 P* _& ~( {% C7 J< >USE xxx</P>
) z- q: w% W; _2 h: T2 g1 `< >EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>- P6 l, j0 N* g) K/ z7 c
< >或者</P>* _8 V8 E% [% }9 S, \
< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的用户表:</P>' ?! l. K% S- |' M
< >USE DBAudit
* f' H/ @( g8 x2 KSELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U'</P>( t+ `9 ~$ |; V2 }
< >获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的系统表:</P>
% m5 T1 j+ H3 c9 x* [3 u0 J2 k< >USE DBAudit6 L$ U6 R" {, m
SELECT sysobjects.name AS tname, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'S'</P>" ] k" [- w3 t, h' u2 ~4 Q
< >或者统一使用:</P>8 {7 n$ F/ `) E0 K: H9 d' t) c
< >USE DBAudit</P>
$ j) s q" U+ P! f' p3 o( P5 P< >SELECT sysobjects.name AS name, sysusers.name AS owner, type, sysobjects.id AS id FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'U' OR type = 'S'</P>
2 h* i3 S8 j! d$ l7 n7 f2 Z s< >注:</P>
* t7 L2 @: P2 B. o4 A( S. f< >sysobjects中type字段类型解释:</P>0 T, m- v A2 X% a6 N4 ^1 Q3 B
< >C = CHECK 约束</P>
! O- u* N; i5 v& g! B< >D = 默认值或 DEFAULT 约束</P>
G2 i' L" O/ u6 l< >F = FOREIGN KEY 约束</P>
: A5 p% P% ^$ k5 k- l< >L = 日志</P>9 ] L( U7 B8 K8 [
< >FN = 标量函数</P>4 S: S% E( d2 x: W5 E+ A R
< >IF = 内嵌表函数</P>" I/ P5 R$ x L& k, F4 c) _ B
< > = 存储过程</P>
5 ?* e' O4 C4 g9 |% N' T" V< > K = PRIMARY KEY 约束(类型是 K)</P>
- x3 r. A0 T2 @; K* d# g1 U- T< >RF = 复制筛选存储过程</P>/ n' \" g: z: q3 `/ y+ F- ?# S
<P>S = 系统表</P>
4 s# `5 _* A6 b6 y0 r<P>TF = 表函数</P>
" i4 Z( l- Q2 c<P>TR = 触发器</P>
2 i0 R+ K' ], T9 L3 \ S$ }% g<P>U = 用户表</P>
. M) @' K, N; J) ^# u<P>UQ = UNIQUE 约束(类型是 K)</P>
$ ?' |# r* M. r<P>V = 视图</P>! }* D/ w7 H ]
<P>X = 扩展存储过程</P>
3 w8 J6 J$ n( z<P>取得列的方法
$ r* F' K$ Z5 j9 r4 o0 u1 k& [! @系统存储过程</P>% ?: a w1 j' m$ i, U
<P>USE xxxDatabase</P>
- Z1 e7 J- U2 A<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help xxxTable</P>8 G8 B( q5 k: ?7 p1 I, G" y
<P>或者</P>: Q9 G6 E3 J1 f( p% w
<P>USE xxxDatabase</P>
) N. b$ h v3 j+ s0 @3 O<P>SELECT syscolumns.name AS name, systypes.name AS type FROM syscolumns LEFT JOIN systypes ON syscolumns.xtype = systypes.xtype WHERE syscolumns.id = xxxTableId</P>
+ P" x. ~: H# `* l/ I: Y+ x: ?<P>这两种方法都可以取得包括视图的列。</P>! A/ `; H- q# n
<P>取得视图的方法% [& d0 X/ d: y
系统存储过程</P>; R' a5 _$ _" [) @1 \
<P>USE xxx</P>2 f0 J3 x6 Y, D, ], Y6 O# E5 t
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
# Z9 s1 y# ], n<P>或者</P> x1 c& S& N# A0 D! k, b. t$ e
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图:</P>! q6 B* L2 Z! Y6 W. z
<P>USE DBAudit</P>
7 }- M" L- n- D) |" `5 E6 [& D<P>SELECT sysobjects.name AS name, sysusers.name AS owner FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'V' </P>0 \1 S2 B& W$ s" K0 e! r! [
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的视图的内容:</P>
$ i7 J/ g' w& s2 c/ w0 K* y9 Y3 N<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
; {+ d$ Z/ k# v+ z5 {; s<P>取得存储过程的方法( T* ? d& J' Y: K) V7 C7 e) }4 y
系统存储过程</P> ]% x- e* v, v1 p
<P>USE xxx</P>
" ~3 u8 d4 e: i" e0 ?1 t<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>/ t7 ]6 w% R' K
<P>或者</P>
, x( s7 r* h% J% {; \% j3 x: r8 K6 S<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程:</P>
+ p) Z" d8 ^# `4 ^5 F9 U<P>USE DBAudit</P>
6 c: H1 n1 X3 F. I<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'P' OR type = 'X'</P>
/ E- A) m& ~; [: h, ^7 M7 G<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的存储过程或者扩展存储过程的内容:</P>
0 E: q* G$ \* w6 ]3 l<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
: t, B( W! W) y, l; T5 |<P>无法获取加密的存储过程。扩展存储过程只能得到dll程序名。</P>9 ^0 h; M9 a% W8 Y- i) ~3 Z
<P>取得函数的方法
5 b9 [8 H0 }) q4 n! [4 I5 |: M系统存储过程</P>5 s3 G. Y! m: `! g1 D" F
<P>USE xxx</P>- k. z e4 P" r$ h- D
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>help</P>
9 g5 A& G8 g5 h: P5 W4 P+ T2 p<P>或者</P>
u2 a0 V1 b5 a. j2 A( C<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的各种函数(内嵌函数等):</P>
% f: s) h7 T& z, ~<P>USE DBAudit</P>
3 ] k1 S7 B) `5 U5 E0 v7 G% t<P>SELECT sysobjects.name AS name, sysusers.name AS owner, type FROM sysobjects LEFT JOIN sysusers ON sysobjects.uid = sysusers.uid WHERE type = 'FN' OR type = 'IF' OR type = ‘TF'</P>
1 ]! e9 Q& |: x<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的函数的内容:</P>
! R( N9 y( |9 S6 V+ m0 I7 X<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptext xxxObject</P>
6 U2 u6 G% w6 @9 n<P>只能获取用户定义的函数内容。</P>4 x2 W9 {6 }# \- ]4 q/ @
<P>取得触发器的方法1 h- t" ]. n8 \0 u; U( E
系统存储过程</P>
8 a T& ?1 D' b7 [, ]+ ?1 a( L/ q<P>USE xxx</P>7 _" U0 T3 r( s/ U3 n
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helptrigger xxxTable</P>
( Y- x* ^5 z S<P>或者</P>6 j# R% T* D2 i) w1 q: O
<P>获取指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>的表的触发器:</P>+ S" w: }+ T# O" _8 |+ ~
<P>SELECT sysobj1.name AS name, sysusers.name AS owner FROM sysobjects AS sysobj1 LEFT JOIN sysobjects AS sysobj2 ON sysobj1.parent<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>obj = sysobj2.id LEFT JOIN sysusers ON sysobj1.uid = sysusers.uid WHERE sysobj1.type = 'TR'AND sysobj2.name = 'xxxTable'</P>
/ R4 s) Y5 g0 z7 @4 D/ |<P>取得索引的方法6 Z: K! _8 P5 u; e
系统存储过程</P>
8 M; M- H5 t( h1 J0 N+ e<P>USE xxx</P>
6 t ~" f/ t" _6 G( R- Y7 T<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpindex xxxTable </P>
+ [6 J4 x8 U2 f<P>用户
3 k6 V* |! _" D, J7 h: l3 t9 q系统存储过程</P>7 D9 v! d0 g' F
<P>USE xxx</P>; @+ H4 \7 V" s/ r8 \
<P>EXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helpuser</P>+ a6 \' f* j }& G0 r$ u
<P>角色7 {& {& K9 M4 j/ Y- ]9 [
系统存储过程</P>
2 r( Y# J2 P) ^<P>USE xxx
5 Z+ k& t# e6 W3 x, wEXEC sp<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>helprole</P>
! W- T7 U, ]# z( T( j- b0 T+ D% ^* E% A1 |0 Y
<P>ORACLE$ J- y4 w4 `2 t- j( ~* @# m7 O
特殊: p' n$ t6 l( D' t
Ø ORACLE只能连接特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象。</P>
! B F% u# ?- v$ u: ]' I, I1 q: o' n* r<P>Ø ORACLE表必须用用户来区别,否则表可能重名。</P>
( F1 P! M5 h6 W8 t<P>Ø ORACLE不能区别系统表或者是用户表,因此只能由管理员选择扫描某些特定用户的表。</P>
- G% |2 g/ \6 O<P>取得<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>名的方法5 f7 K& \* N. T. b. ?8 W# k6 w' m( D
只能由用户指定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>,不能自动扫描到特定<a href="http://hackbase.com/hacker" target="_blank" >数据库</A><a href="http://vip.hackbase.com/" target="_blank" >服务</A>器上的所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>。</P>
# H2 j, S5 L% ]<P>取得表的方法& O& y" s; i- G- o7 \
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的系统表/视图主要有:</P>! R: f# G" B2 Y; T3 F6 c
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
& N0 Z8 R2 B* j3 J5 j<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象以及相关的表。</P># }4 x8 J. e+ Y
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>
& c9 v" T, ?" r; z- J<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的对象以及相关的表。</P>- u0 i) f) R E+ n. w
<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES</P>0 J0 A( k6 a6 c) Q
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的对象以及相关的表。</P>
, ?2 x+ `: q8 K+ W$ l4 S. h<P>! U" y! }, o! K, k
DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
% s8 }0 }% B- J; y$ g7 K% W<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有相关的表。</P>
6 y3 j8 M: Z# _6 K<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>* j6 r" c Y8 `
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的相关的表。</P>
2 R/ k: L& U/ {4 l/ D. d3 E% V<P>USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TABLES</P>
0 Q$ D# P/ S* X9 j<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的相关的表。</P>
% R( n, {, @: o0 u7 w<P>
4 d/ s5 ^* {2 u# T$ r+ E- {因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES中取得隶属于指定用户的表:</P>: G6 D5 f: T2 b# i
<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE OWNER = 'DBAUDIT';</P>
" q; e6 }# M7 x' h5 u% M<P>取得隶属于指定表空间的表:</P>
! j4 a& g3 }3 H$ d( {7 p<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES WHERE TABLESPACE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'DBAUDIT';</P>
$ l$ I* ?/ F$ }2 [, d$ e+ ~<P>
; q8 p& C% ~6 V R) k g也可以不指定用户名,从而取得所有的表。</P>
) k' O- T5 F2 J6 Y' q2 p. h<P>SELECT TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TABLES;</P>
$ ~ K& W! G3 e8 h<P>取得列的方法5 f8 L# z7 w' L# n5 g6 a2 D9 ?
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>表的列属性的系统表/视图主要有:</P>
1 S' U1 H% Y' }) v( l<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
4 ]' ]! B+ M) R9 T, `描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的表的列属性。
! n& H+ v9 g9 [& c! ^' OALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
- P7 ^+ A- `) [8 B描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。; M |2 Y* r1 V5 k- e7 C2 S
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS
* s/ F" c2 R4 Y5 B( z' d描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户拥有的表的列属性。/ I0 k9 o/ ]" T- A0 P
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLS</P>
* I) O c9 `" ]$ A<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的表的列属性。</P>
+ }- ?2 h s2 U& M% T6 \% r* i<P># f- e% J/ L+ e' y) G' b
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS中取得隶属于指定用户的表:
; V4 D+ t. J) ~% a0 @, @SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TAB<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'TASK' AND OWNER = 'DBAUDIT';</P>/ b+ V8 K e* O1 ]5 K
<P>取得视图的方法: S! y+ F h' N6 J+ |
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>视图的系统表/视图主要有:</P># Y- [" o3 e* S7 ^8 Z% u3 I
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS5 q5 O$ G, ^) S. _/ G" A5 G
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的视图的属性。
1 A! k8 S) G- Z9 }7 U8 d; q& |ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS
$ s7 e9 a! [$ O1 K. u描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的视图的属性。# B1 d& @8 E: ~0 G2 K! ?) i5 U3 A
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS</P>
/ h) K% N# w& F+ A9 x4 x* f; L<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有视图的属性。</P>. Y a1 ]: T4 C" G! q4 U
<P>
4 f1 p5 t8 z( b V因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS中取得隶属于指定用户的视图:3 m4 T8 n$ U5 ?$ r2 k0 q3 P: b
SELECT VIEW<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>VIEWS WHERE OWNER = 'DBAUDIT';</P>
. h/ d% r- ~% r S8 b) ~+ H& o<P>取得存储过程的方法
- Q9 l" o3 V/ l3 N) M: Q存储系统对象的系统表/视图有:</P>4 _2 B3 }' `7 O
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>' j1 b% l1 b) J! c
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的对象。</P> N0 K# y3 T* p2 f; ^# a
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS
- N! [( [$ j0 m$ I/ s描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的可以访问的对象。
' J8 ^7 c7 `6 H [/ ] Z2 bUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>8 ]# @* N7 o0 V c# T: B9 j! X2 F7 I
<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有的对象。</P>
$ Q+ B7 a7 p4 _<P>SYS<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS</P>
) v. } m9 u+ u1 ^6 o; q" p' `<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的系统对象。?</P>8 l5 @6 V5 f: S8 }
<P>
) C- K2 s4 ?4 B. Q$ Y6 t. P) U对象类型有:</P>
- [4 S* H' y' Y2 d<P>CONSUMER GROUP</P>" H \) o) X; b$ y& N9 M# R/ n
<P>CONTEXT</P>
" p6 ^, p) [ |& v$ O1 `<P>DIRECTORY</P>
: d: t# O+ z4 e L$ \<P>FUNCTION</P>
4 _3 ^8 s1 A3 G<P>INDEX</P>. {; v$ j# t s8 V+ J
<P>INDEX PARTITION</P>
) d# ^1 k" T0 Z2 a<P>INDEXTYPE</P>( E) X" W2 p/ m N
<P>JAVA CLASS</P>4 D2 b" Q! \9 K: `
<P>JAVA DATA</P>" y S% T# y; w
<P>JAVA RESOURCE</P>
6 D8 W; \7 ^1 Q: B! A<P>JAVA SOURCE</P>% \/ v- o4 H5 w' I# T
<P>LIBRARY</P> m# b; d' v3 h+ U
<P>LOB</P>* G6 \* r4 c) H C8 Y( M# |. X
<P>MATERIALIZED VIEW</P>, E" Z: T6 T8 P; q* y
<P>OPERATOR</P>1 b" z/ M% K5 R/ ?5 ?7 n# i
<P>PACKAGE</P>; F6 x1 t4 k5 X6 o! n; ]
<P>PACKAGE BODY</P>2 d7 z3 u% M3 S' x8 h$ q
<P>PROCEDURE</P>
& Z- t. m2 G5 J4 ?7 t1 v<P>QUEUE</P>& O9 P2 e, z Y
<P>SEQUENCE</P>
h# x$ t8 \4 A# E4 p' D<P>SYNONYM</P>
( d9 l6 x( j$ [: t<P>TABLE</P>: x, z' j0 O! {' W0 i: \8 G
<P>TABLE PARTITION</P>
& e( H- [" `, t: R9 ^5 i f- E<P>TRIGGER</P>. H4 I3 F: p' F# r+ x
<P>TYPE</P>1 ?# O, X# Z6 z E, C
<P>TYPE BODY</P>5 p) y2 K, g" n9 s) t
<P>VIEW</P>: V! J( j7 j2 z2 r
<P>
, F0 o; k' @3 h" k/ K因此,取得存储过程可以用:</P>0 s1 ^' c; ^5 T+ u9 d/ h5 N" Q& x$ o
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE';</P>
1 R/ r4 a! D) d- B<P>取得隶属于某个用户的存储过程可以用:</P>
* r# C+ O! G9 ?! d) C% L) n<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'PROCEDURE' AND OWNER = ‘DBAUDIT';</P>- S. W* F! ?+ ^! i
<P>
. `0 y7 W& k( I2 o. A$ |; s' H' w/ k同样,取得其他的对象也可以用这个方法,包括表,视图等。</P>7 F. A w) W3 `- J- e8 f" _
<P>取得存储过程内容的方法( X+ j6 l, }' |; ]3 h
对象类型为类型、类型体、过程、函数、包、包体,JAVA源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的所有对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>都存储在几个系统表/视图中:</P>
: z$ ^! F7 ]6 z X/ M# L$ X2 w<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>7 B) {( C$ B* w3 |8 J; S+ u
<P>存储所有<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>, J3 |4 m* P3 h- f+ B; O5 v
<P>ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE* c7 d, n5 q8 _3 z- {1 V
存储所有可以访问的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。
4 U- E+ L$ v o) S o1 `5 OUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE</P>/ D2 A6 Z9 v& h" {: G
<P>存储所有当前用户拥有的<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>对象的源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>。</P>
! }, J2 E5 e8 n3 N; Y<P>( O v5 R+ d3 Z2 J7 u1 a! I
因此,取得存储过程源<a href="http://hackbase.com/hacker" target="_blank" >代码</A>的方法:</P>" A/ h1 a7 T2 C. J3 J( J }
<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = ‘XXX' AND TYPE = ‘PROCEDURE';</P>
; f# b, c$ y6 F& ^- ?$ d<P>取得函数的方法
1 k% A/ J) g- X( V/ s9 z同上,取得函数可以用:</P>+ I- U0 c0 a% _# I1 I
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION';</P>
) Z! Z! i! }; ^<P>取得隶属于某个用户的函数可以用:</P>3 E5 m5 X# I) k) D# X# Y" q
<P>SELECT OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OBJECTS WHERE OBJECT<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TYPE = 'FUNCTION' AND OWNER = 'DBAUDIT';</P>
& P/ j7 i7 M% b<P>
. R) k! t/ t/ T2 c8 ?取得函数内容可以用:</P>9 }/ T7 s% l3 `# |- C4 B
<P>SELECT TEXT FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>SOURCE WHERE NAME = 'XXX' AND TYPE = 'FUNCTION';</P>
+ B/ N3 F" H, d+ @<P>取得触发器的方法
/ H5 L* Q/ m: j2 a; U* J存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>触发器的系统表/视图主要有:</P>5 d9 \& C: a; m( a! c
<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS$ O$ _0 d9 q0 h' q$ s! f) ]" T
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的触发器的属性。" E% X4 E* J1 r1 j. u) b" C
ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS9 F( e: J! ?) h3 I
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的触发器的属性。
+ q$ v4 G( Z# \4 T9 K# ~) lUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS</P>
. A; Z! j# ?( P1 k<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有触发器的属性。</P>$ s w ?' L. a3 {2 L: Y1 I
<P>
% j, C: l% @6 [6 I* c5 y6 e2 ^因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> TRIGGERS中取得隶属于指定用户的触发器:, O$ X0 Q% `: ^5 f
SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE OWNER = 'DBAUDIT';</P>
, } `+ X0 v* s0 |, [: m<P>" b2 m+ g) l+ P/ Q9 a3 J+ M, ]: A# m
取得触发器内容的方法:</P>
. S4 g/ h3 w+ H" ?2 \2 b<P>SELECT TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>BODY FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>TRIGGERS WHERE TRIGGER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX';</P># G' s+ o$ N4 T" [' H
<P>取得索引的方法5 f( \) H/ l* T9 x3 }6 k
存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>索引的系统表/视图主要有:</P>
! U) i+ e" d E5 z6 U& k0 C' Z<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES( ]# y6 h- v8 V5 r) C5 f
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的索引的属性。
( o& }3 M1 |* x! j3 R/ K. dALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES6 \9 _0 N9 s0 U6 j
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户可以访问的索引的属性。
4 a- T) e1 z0 ]1 OUSER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES</P>
$ W9 X1 }) b$ ]. p; ^& W5 Q% {0 Y<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的当前用户拥有索引的属性。</P>
% g0 d6 L) F, Z, \8 P<P>% e3 j) a1 y' p- V. }* M8 ^. ^& K
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A> INDEXES中取得隶属于指定用户的索引:6 X/ _: L5 g! k1 ~, c# z |1 G
SELECT INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME,TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>INDEXES WHERE OWNER = 'DBAUDIT';</P>
7 u; J* m. c H<P>( {0 Q# E+ o( u
取得索引相关的列的方法:</P>0 w8 c9 ?0 @+ {5 d) d
<P>SELECT COLUMN<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>IND<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>COLUMNS WHERE INDEX<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>NAME = 'XXX' AND TABLE<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>OWNER = 'DBAUDIT';</P>
4 x- g$ t' }3 a0 k( C<P>用户
# V) {3 L: {) ]- G! `6 K存储<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>用户的系统表/视图主要有:</P>
8 I- r: |& f( ^% t$ D<P>DBA<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS3 G4 c- X6 y8 N( v6 q
描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。
0 N% f- k& `# T: e& F1 X' r' n+ IALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS
7 i$ E: ~1 Q/ Y c6 `9 \描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中所有的用户的属性。' B. c% E3 P* V4 \$ v7 K
USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS</P>
% ]8 _5 h1 P' I2 X( N1 P3 ]9 K9 S<P>描述<a href="http://hackbase.com/hacker" target="_blank" >数据库</A>中当前用户的属性。</P>
! G# p& |' ?7 ]<P>- V5 g& s7 j) x7 f
因此,可以从ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS中取得用户:
; f4 F5 G% ?) M2 R% BSELECT USER<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>ID, USERNAME FROM SYS.ALL<a href="http://hackbase.com/hacker/tutorial/200502019779.htm#" target="_blank" >_</A>USERS;</P> |
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