新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
  2 (1 - r) x + r - 1
$ g: Y* l, a) I, V0 ~4 [q[x_] := p[x] - 2 r*x^2;
# r2 m5 I. f$ }( v' Ba0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
/ L( e: l+ `3 W8 y1 ~( Ra = a0; b = b0;
9 M+ H& c! N. A: S* IDo[x = (a + b)/2;
If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
8 l& C  k( G8 p: Z( GClear[x]
1 d4 l/ s" N% c( I, [# h) l0 t: oDo[x = (a + b)/2;
If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
Clear[x]
' E% i, H0 G) t; h
我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
0 E* `9 M# k: T. f. j* _

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂