新手跪求指导

heugaodie

r = 3.04042*10^(-6);
' M8 t% Z6 s/ F# R$ @0 _p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
. L* U2 K+ k& N+ ?9 y  2 (1 - r) x + r - 1
& q/ Z/ `, T1 ?" jq[x_] := p[x] - 2 r*x^2;
a0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
a = a0; b = b0;
% s; K1 q0 d2 U% u* N+ a& l+ H5 ]) ^Do[x = (a + b)/2;
If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
Clear[x]
) n3 o, n" I# M1 u( z# {Do[x = (a + b)/2;
8 h7 _5 B4 D# M* K6 w1 U If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
9 Q  Z# ~6 P+ ]1 w1 D) M7 z6 \# U If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x2 = x
3 V& V5 g2 z: H& OClear[x]
' A7 F) L: m  H8 h
我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂