Lingo建模语言与实例4

longde

目标与约束段
3 O! q2 d: K- Y* c5 P集合段（SETS    ENDSETS）
数据段（DATA   ENDDATA）
) O* H9 P8 m; y3 n* ^7 b7 U. ]初始段（INIT  ENDINIT）
（计算段 (CALC ENDCALC)）
MODEL:
Title Location Problem;
$ `" n" D3 {5 I& psets:
    demand/1..6/:a,b,d;
% a2 s/ D4 z% q* }$ G/ j    supply/1..2/:x,y,e;
2 j' Z* m, K  m, |, b. r    link(demand,supply):c;
endsets
0 P7 Z7 }6 A* D" b* W: h7 _9 Udata:
( {: [* e# _$ g* W/ c# va=1.25,8.75,0.5,5.75,3,7.25;
) V% M* k+ i+ vb=1.25,0.75,4.75,5,6.5,7.75;
9 A! E2 j$ E! E) ^5 Dd=3,5,4,7,6,11; e=20,20;
5 E" M7 F7 y* B$ l. H! Lenddata
init:
x,y=5,1,2,7;
endinit
$ E: Y: H2 N6 a- C8 q  g. bmin=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
& E' a. X0 n) g) d) z) P@for(demand(i)sum(supply(j):c(i,j))=d(i););
@for(supply(i)sum(demand(j):c(j,i))<=e(i););
, K6 H% V& k3 d) D5 Z" m9 \END
. V3 M: X$ a0 _: O" M' C4 H

longde

好
2 `( J+ S& B: m