Lingo建模语言与实例4

longde

目标与约束段
集合段（SETS    ENDSETS）
数据段（DATA   ENDDATA）
) q4 h* H; t, q- G, o, A  C' t初始段（INIT  ENDINIT）
（计算段 (CALC ENDCALC)）
8 k4 F+ A1 L2 G& L- N; I- yMODEL:
, d: W( ~. P/ D$ V; `Title Location Problem;
6 X. q' t6 P; Y( a0 esets:
    demand/1..6/:a,b,d;
    supply/1..2/:x,y,e;
4 n& Z: `# \9 o: d2 R% i- a    link(demand,supply):c;
+ v9 O- J& B2 C. u& w; n' aendsets
data:
# Q7 D( a1 |9 ta=1.25,8.75,0.5,5.75,3,7.25;
8 }8 U. m# p4 Hb=1.25,0.75,4.75,5,6.5,7.75;
2 d4 N0 J7 e! G! hd=3,5,4,7,6,11; e=20,20;
enddata
init:
x,y=5,1,2,7;
endinit
5 M7 _# Z  V4 S- e1 G9 v) smin=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
8 [3 s! x1 H/ D5 T@for(demand(i)sum(supply(j):c(i,j))=d(i););
7 b4 ]! o" a0 N7 }) _2 P@for(supply(i)sum(demand(j):c(j,i))<=e(i););
. |; _6 [: C+ r5 X6 Y) \4 m1 A0 ?END
! r' K/ G; v3 \, \

longde

好
5 P& {' x  _9 y: z" q6 ?. ]: ~