Lingo建模语言与实例4

longde

目标与约束段
& }, S8 Y( W7 n( L6 z# x集合段（SETS    ENDSETS）
数据段（DATA   ENDDATA）
初始段（INIT  ENDINIT）
（计算段 (CALC ENDCALC)）
% ~! T% @, ]8 @MODEL:
Title Location Problem;
sets:
. B2 {5 l6 W$ M1 L    demand/1..6/:a,b,d;
    supply/1..2/:x,y,e;
  e, P+ X& D7 d3 p/ U2 p    link(demand,supply):c;
% E; J$ R3 s$ I: cendsets
data:
9 A/ g6 W: b! ~1 z6 g3 F0 Pa=1.25,8.75,0.5,5.75,3,7.25;
b=1.25,0.75,4.75,5,6.5,7.75;
d=3,5,4,7,6,11; e=20,20;
  F) l' {5 c2 ^enddata
5 g5 M5 v1 {8 Y* Vinit:
2 o( o/ b: p" |4 z4 Kx,y=5,1,2,7;
- ~3 u4 O( \, n& `' mendinit
min=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
+ Q) o# n; ^$ o/ T# x@for(demand(i)sum(supply(j):c(i,j))=d(i););
- B) x7 _' v0 F# @* o9 V7 R@for(supply(i)sum(demand(j):c(j,i))<=e(i););
5 q. j) T: E9 i' VEND
8 q& w/ l: r1 \$ v5 P( C

longde

好
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