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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧! f/ ]* T% o9 ~, W* ?0 e
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- model:
4 r, g& x9 A* c9 j\" n - !n个货车8收点运输问题;
\" k8 n9 x2 f* _' |4 @* P\" S# e# D - sets: W4 w2 O0 R: h% f! g
- place/place1..place10/:time1,time2,timexie;
5 h2 o8 S0 p$ E6 T# X8 \3 Y8 N - car/car1..car3/:time;
$ W9 Q3 f- |# f% V2 m6 R8 I - & j. x5 L) @4 W& J
- jiu/1..9/;\" @. j: z6 D* v! o6 q; l
- er/1..2/;
0 {5 F+ Y' h& E3 Z9 @2 O: {/ ^ - ' a4 _$ v& H; s7 G4 |/ f# A( T1 O7 L) v
- lc(car,jiu):lucheng,ct;
\" T; D! c5 a W\" c\" y2 L - plan(place,place,car):a;
, v$ V; \1 W# ~9 ?- T, b L - distance(place,place):dd,dt,which;! Y: b& I5 p u
- endsets; f8 e+ O9 w8 \0 O |& D
- # z! m6 @+ A- p+ m4 U/ v: \
$ M1 |/ q% |( [- !这里是数据;; K$ l0 t) n9 B3 `0 p$ G8 N- o$ q
- data:
3 e4 X\" u7 g7 X2 y. ^0 q6 T% S - s=1;# a3 `8 c4 T2 H
- time1=-10 1 4 1 4 3.5 2 5 1.5 1;
2 `, q7 P\" x\" Y, j - time2=7 4 6 2 7 5 5 8 4 10 ;) ^$ N0 }& ?2 l6 m& a' Q\" P
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;- r# N/ V1 p0 C0 r8 {7 q) w/ X I% A
4 v' Z$ F% X# {/ { L
2 K: l$ g& [) i- I. e- @/ S) g- dd=
}) D4 [' |1 p0 _ - 0 40 60 75 90 90 100 135 80 0
\" ?% Q5 d+ i5 Z9 I1 W- N+ u - 40 0 65 40 100 50 75 110 100 40- K( X* \* F- ] _+ ?
- 60 65 0 75 100 100 75 75 75 60
o+ X: J0 W& s* ]* C' C# n. S - 75 40 75 0 100 50 90 90 125 751 @8 t6 I1 v) Q* y
- 90 100 100 100 0 100 75 75 100 90
5 L/ k; n9 Q. [$ N: a' h9 B - 90 50 100 50 100 0 70 90 75 90
/ R. F( e4 I/ e( x1 R; I - 100 75 75 90 75 70 0 70 100 100
% L& _8 V4 Z% o2 a b - 135 110 75 90 75 90 70 0 100 135
& O3 n% x' w7 \; k - 80 100 75 125 100 75 100 100 0 80
! H) r: _3 q# O$ O0 z - 0 40 60 75 90 90 100 135 80 0 ;) L8 J7 w4 Q) k: v& i7 L' I, d
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0# H( Q9 j$ ^4 B& h1 r% l
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
\" A2 j6 z) v3 `& z - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
- Z; V3 b; S8 s, B% B - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000\" J( R5 l, V4 ~0 m9 e8 \/ \
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000! z0 j1 l$ Y, \. C$ I' u
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
\" p, {/ j9 r4 v3 e) P- l - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.00001 o$ H3 Z) N\" |1 L. M* Z
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000' s+ ?+ }- m6 `5 k9 w5 K\" {
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
9 I* U$ b1 s' u) H9 U& r0 z - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
& x\" O$ b6 G R, q9 w( Q - enddata
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3 }' q, u G9 j' I2 [, h- !目标函数;
! o8 f l3 i+ {: F - min=@sum(lc(I,J): lucheng(I,J));+ I: W5 h% d6 R4 s! }& |! }
9 U& a; K% Z) D6 |7 ?# C- !整数约束;
. d8 G0 _) g+ Z8 k$ l& J) p - @for(plan:@bin(a));
0 O' s' e2 @\" G; | - @for(car(I):@free(time(I)) ;9 n8 ]' r; k/ Q
- : ?' T9 U! {& k0 ]
- !从零点开始最终回来;) o7 D3 @$ w( q0 p/ v
- @for(car(I):
! `) o2 D- m% I. _ - a(1,1,I)=1;a(10,10,I)=1);5 h$ I, }3 }6 \3 g4 D( F; `
- 6 w9 B4 L, g' \- u& t& A
- !每个任务只能有一个;
, s+ }0 Q( D7 t+ S G, G - @sum(car(I):
R( m- y% W% y3 { - @sum(place(K):; I( e& I$ T# b8 c4 \% l8 c
- @sum(place(J): a(J,K,I))))=1;# `\" V8 v! w3 J8 s0 G) m. O# i
- $ h8 K* e! ]* t9 [8 ?8 `8 l
- !每个车的任务最多有四个;8 u( \\" `2 z2 w+ \8 F5 e- p
- @for(car(I):: J; p9 v# e b2 g: ?
- @sum(plan(J,K,I):a(J,k,I))<=6);7 K\" }' w% v4 V
' D* Z, e$ ~$ k, G- !前一辆车任务大于等于后一辆车;
) `, @1 B1 v1 ~ - @for(car(I)|I#lt#1:
, z+ v/ I5 s {\" a - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );. E+ r8 j, u4 F7 v7 E
( g& N9 O2 F+ }9 R- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
6 e\" I% D0 P9 D# Z% H, O - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;3 R5 B8 H: z- ?% o
- @for(car(I):! w/ q- H9 b. [; @+ v! c8 x J0 B* c
- @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:# M. _7 z2 e$ k5 U7 H4 @
- @for(place(jj)|a(kk,jj,I) #eq#1:6 _. c4 N: P' D# k) i k, c5 k
- which(I,kk)=jj ););2 m- c7 t) n% q; s
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:+ x8 D# S+ a+ [- n: Z
- which(I,kk)=which(I,kk-1));
% T( e9 v q6 q _$ L; a$ | - - f8 Z2 M, b3 p! Q
- !时间限制;
9 k5 b* T: g+ j5 t - @for(car(jjj):
E- V7 {9 i4 \ - time(jjj)>=-10;time(jjj)<=7);
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; `6 n\" E6 V- E; \4 T- @for(jiu(jjj):( q! C$ _# { y\" b; G
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));
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G1 {% K q1 \- V- @for(jiu(jjj):
6 H* [& q7 m4 ]* B) m - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));, {: [5 T$ ^& N: V7 k8 b
- ( s& A: E- Q0 j- r% P* @
- !求每辆车行驶的距离;$ x4 `8 a* P0 m( _! _# h9 ]
- @for(jiu(jjj):3 [1 }! e6 r1 D# E
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
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- end4 e! l% s+ H3 ^+ `; H4 Z6 l
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