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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!" y8 l: e0 ]8 \5 W" T, ~, v7 `
8 G0 q* W! Y& e$ P8 i9 Z; T& z4 o9 n- model:' k6 T1 ~7 s' D5 {) s4 s: ?
- !n个货车8收点运输问题;
\" a6 F. E* h! G' r0 [ - sets:6 L7 V! X2 t, G. H
- place/place1..place10/:time1,time2,timexie;, _8 r' o9 t: Y- T p% _; u) g0 F
- car/car1..car3/:time;, k( c; r\" D2 [0 `% g
- ) p! K) ]! \7 d3 T) L0 V: Y* |, J2 s
- jiu/1..9/;
\" [3 A M G2 k! E2 C% O - er/1..2/;
% k: T' p7 [ W) T: A4 T* k8 G
$ ]' o& y8 E2 E4 u( Z; N- lc(car,jiu):lucheng,ct;
& u; O+ f4 g5 o$ s5 a+ ?( ~ - plan(place,place,car):a;$ N8 w. l\" A\" d! p8 Q
- distance(place,place):dd,dt,which;( S2 z3 U& \1 t7 K' A6 m! j
- endsets
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8 u* P6 U* A# U, i3 I. r+ Z
1 t2 J1 k, d4 _: u- !这里是数据;
+ V+ a* h% o7 N d' L4 }2 o - data:% X- q( t$ i/ l\" B\" r
- s=1;& C7 p/ ]% Q8 ~5 @0 _; A$ }' D' Q
- time1=-10 1 4 1 4 3.5 2 5 1.5 1; : W1 F! I5 b/ i$ ]& |! f7 |9 ]9 ~
- time2=7 4 6 2 7 5 5 8 4 10 ;
: A* `- L2 R1 P( v- n5 s - timexie=0 1 2 1 3 2 2.5 3 0.8 0;
5 h5 c. W. m; E6 P; z% } - 5 n! g4 {1 k/ B9 d7 h
' a1 [/ d5 `1 \/ z1 o' Q( B2 l- dd=, v q$ v, b `- S, {
- 0 40 60 75 90 90 100 135 80 0& k% K; y: l4 }
- 40 0 65 40 100 50 75 110 100 40
8 j0 {. b; H* a: H( b; m, c - 60 65 0 75 100 100 75 75 75 604 N' o4 ^4 w2 [7 x' ~ ], u; G2 I4 _( N/ K
- 75 40 75 0 100 50 90 90 125 75 J/ m+ ~- g% |; x1 {7 N
- 90 100 100 100 0 100 75 75 100 90
$ n( b2 {' I4 P- e - 90 50 100 50 100 0 70 90 75 90
# E4 J; l8 p, B\" E - 100 75 75 90 75 70 0 70 100 1008 G: ^1 e5 z% V% j
- 135 110 75 90 75 90 70 0 100 1351 v6 h1 |6 P* T- V% a& e* Y
- 80 100 75 125 100 75 100 100 0 803 Z* p, N7 y0 l0 n% E
- 0 40 60 75 90 90 100 135 80 0 ;
+ D) r( y\" @. j0 i - dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0& K( }# u/ }. I: {# V( g; n4 S
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.80001 p2 q) k3 q2 U$ f8 M
- 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
& w( u6 X; o1 M, ^ - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.5000
. s# F) a. @- x4 [ - 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000% B8 ?; L: q3 Z @
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000! ~\" [8 H Y3 }9 J
- 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.00008 p+ t: v& D4 [: F: x; p$ o: n
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000
9 R4 f( r) V9 F$ _' Z# F - 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000* c& Z5 K+ n$ b9 n. e$ |9 y
- 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;
' Z w' H\" L0 `' v$ s - enddata0 H4 _; }1 w5 L1 w
- ; `5 V. J' s: {. G& {: t5 C3 Z' I! N
- * G. R1 R; ~% O' d
- !目标函数;$ [3 F }* x' D+ f
- min=@sum(lc(I,J): lucheng(I,J));
6 h5 B$ ]& c& p- y$ P( `. M3 Y
\" X7 J$ j! b6 D/ ^8 S- !整数约束;
6 o( r9 N4 h2 F\" K; w! @! t$ u - @for(plan:@bin(a));& Q% G( L& u0 H
- @for(car(I):@free(time(I)) ;
# S9 K' V9 f- k - % ?4 ^\" k/ s# m3 ^
- !从零点开始最终回来;
, o0 C5 c9 H) |) S9 P - @for(car(I):
' r4 Z/ `; ]) L - a(1,1,I)=1;a(10,10,I)=1);2 s' [( l+ k# @2 P) @# z
- ) a% [2 f5 D2 A1 T3 y
- !每个任务只能有一个;9 \$ b* W' x# @8 ~
- @sum(car(I):
: D2 Z2 f, C# U. F: H - @sum(place(K):* N' N8 P\" x3 M$ }
- @sum(place(J): a(J,K,I))))=1;! m: X6 |7 l/ \3 a' ~
! }. j y/ C! w% J7 @- !每个车的任务最多有四个;
; G' N4 U5 ?; K1 e0 g# ]$ i) E - @for(car(I): j: J6 F7 b\" q- Z, a3 o
- @sum(plan(J,K,I):a(J,k,I))<=6);
9 n9 a6 w& ?% R - 2 T) j' F7 F# @; O8 \\" }# A
- !前一辆车任务大于等于后一辆车;( T7 Z( {2 c& Z2 S
- @for(car(I)|I#lt#1:
) _+ Z8 N5 Q4 m5 \/ ^, x+ B: y - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );5 p' S% s7 B5 r! M1 K+ u
- 7 d7 P9 I. C, c$ U% y
- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
n9 R, I1 K, u/ J3 T) _ - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;% c1 k: J) e2 K
- @for(car(I):4 a8 p- ?+ k2 \4 ?8 K. P
- @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:$ T2 L O1 z2 X% R9 e( {3 q
- @for(place(jj)|a(kk,jj,I) #eq#1:
1 s1 V& N' a& P* M6 ?! P - which(I,kk)=jj ););
' l' f- T\" k. e - @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
% J8 A& g( H( |\" K% v3 R - which(I,kk)=which(I,kk-1));6 B) W9 Q |+ @1 T' B. [
- * R* S7 E0 G$ D! ?& }* g4 s. P9 g
- !时间限制;
1 r a- j G9 c) D* j - @for(car(jjj):
+ t6 C# B/ Q+ e) d - time(jjj)>=-10;time(jjj)<=7);
, m( c9 i+ Y8 e* r% q/ k/ z
- l( \$ @, Y8 n- @for(jiu(jjj):
: U o# l$ B: D5 V! ] - ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));$ G: e5 E# d b: R( i
- . T ]\" j S# N% v
- @for(jiu(jjj):: Y$ V. k6 ^: t3 J0 u* o# _
- time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));/ f7 j( L; r% F: p K7 N
- ( I3 r/ r! J, n2 a4 T
- !求每辆车行驶的距离;/ T; R/ e8 p; J4 O0 ^% Q
- @for(jiu(jjj):
, I* A: N1 ^0 @1 g8 p - lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
/ v\" K1 h+ F/ P$ h- ^; F; O - );););0 x+ N* {2 P7 U* w4 r
- end
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