- 在线时间
- 0 小时
- 最后登录
- 2018-3-16
- 注册时间
- 2018-3-16
- 听众数
- 1
- 收听数
- 0
- 能力
- 0 分
- 体力
- 3 点
- 威望
- 0 点
- 阅读权限
- 10
- 积分
- 1
- 相册
- 0
- 日志
- 0
- 记录
- 0
- 帖子
- 1
- 主题
- 1
- 精华
- 0
- 分享
- 0
- 好友
- 0
升级   20% 该用户从未签到
 |
本帖最后由 419595891 于 2018-3-16 13:51 编辑
$ d, k, Z/ s M+ e& t+ N9 R
+ u$ Q( n2 w# V: [# M' w7 e这是一篇文献里给出的script,但我放到S-plus里跑不出来,有错误,有可能是我不会用S-plus,所以请教大神下面的script是否有错,没有错的话怎么解决错误?能不能改动换到R里运行?
i6 ^$ Y4 e5 e7 B' r# E! z5 s% M9 H8 L5 m. V3 n
library(Design)
, o9 Q' C+ V; \reri <- function(datsam) t& e0 H; K# I1 ^& M' d! H. R
{ - x! W% K# ]7 v9 v8 f! F
fitlr <- glm(outcome ~ determinant A * determinant B, family=binomial, data=datsam)
+ {4 c: E/ W# l0 G' o' K0 Oreri <- exp(fitlr$coef[2]+fitlr$coef[3]+fitlr$coef[4]) - exp(fitlr$coef[2]) - exp(fitlr$coef[3]) + 1
& A3 e% Y9 q6 B6 l4 {}
9 z6 c+ O/ z1 Z: ]# Vsummary.bootstrap(bootstrap(dataset, reri(dataset), B=10000), probs=c(0.025,0.5, 0.975))
0 L1 ^6 e. p0 c2 L6 g* _7 `" Z0 }8 Q: c& p) M9 w# v
————————————我是分割线——————————————————————————————
F S3 [6 \" z# q/ |. m+ j+ X- l- Z* P+ s* ]7 M/ O6 y
* K+ U7 g# Y# x: Y6 b1 l( e! i0 Y
+ ~( }; K$ _( V9 A& i; z9 z library(Design)! t: \8 x% I, z, g; k
> reri <- function(datsam)- O H& E9 M7 L3 T2 h; O9 ]
+ {fitlr <- glm(DM.0813 ~ smoking * rs163184, famliy=binomial, data=datsam)1 t2 h; |- f0 X
+ reri <- exp(fitlr$coef[2]+fitlr$coef[3]+fitlr$coef[4]) - exp(fitlr$coef[2]) -exp(fitlr$coef[3]) + 1}
# S( |% q7 g$ s) I! b M y g8 D/ N2 v Last expression in function is an assignment1 [. j" P5 z9 j7 e7 M
(You probably wanted to return the left-hand side)8 f4 f0 U; e' |4 y1 e
in: reri <- exp(fitlr$coef[2] + fitlr$coef[3] + fitlr$coef[4]) - exp(fitlr$coef[2]) - exp(fitlr$coef[3]) + 1" } |. b2 T0 L1 Y4 M4 m, R: h
> summary.bootstrap(bootstrap(smoking, reri(smoking), B=10000), probs=c(0.025,0.5, 0.975)) 2 N! \ W* F9 w' t1 c$ t
Warning messages:
* y; l" O% n* B$ U Numerical expression has 7028 elements: only the first used in: model.frame(formula, data, na.action, dots)3 ]; C) j) M! M' e
Problem: Object "DM.0813" not found E8 m$ ?" \) Z; K8 K n' Q* B
Use traceback() to see the call stack
4 a0 m4 ?4 L z3 L! R' {! ?
/ g) U6 f7 I0 i8 o2 p6 Q- I/ `9 o* ~
不明白这个错误什么意思,小白求指导……! r! V. S3 f: A3 L6 W9 [( N
# Y# e$ X6 _* N6 Q4 L* m3 P) G3 y0 ]0 E/ G5 g
|
zan
|