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本帖最后由 419595891 于 2018-3-16 13:51 编辑
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这是一篇文献里给出的script,但我放到S-plus里跑不出来,有错误,有可能是我不会用S-plus,所以请教大神下面的script是否有错,没有错的话怎么解决错误?能不能改动换到R里运行?7 ?& V0 p0 I2 d1 z0 e4 m- ?
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library(Design) 6 \6 F! W, w6 R' {' i
reri <- function(datsam)
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fitlr <- glm(outcome ~ determinant A * determinant B, family=binomial, data=datsam)
/ v& K+ P k( C- B1 Hreri <- exp(fitlr$coef[2]+fitlr$coef[3]+fitlr$coef[4]) - exp(fitlr$coef[2]) - exp(fitlr$coef[3]) + 1 * ? o3 c% t7 s& A" r
} % ^, h* X* X- q, M5 ]& B
summary.bootstrap(bootstrap(dataset, reri(dataset), B=10000), probs=c(0.025,0.5, 0.975)) / G! k6 e0 {7 W. ], s) X, i3 |
1 [$ S) J, R' b1 l# ^7 i————————————我是分割线——————————————————————————————
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library(Design)+ h! f' ^) b4 z* d: x
> reri <- function(datsam)
: ]3 ?, M! h8 c) S* G" g; q8 }+ {fitlr <- glm(DM.0813 ~ smoking * rs163184, famliy=binomial, data=datsam) n- Y8 W4 {- z% P! L ?+ x
+ reri <- exp(fitlr$coef[2]+fitlr$coef[3]+fitlr$coef[4]) - exp(fitlr$coef[2]) -exp(fitlr$coef[3]) + 1}, T: r' h- k+ N/ |. a
Last expression in function is an assignment
2 [# `+ O, u. o; n$ o2 S* } (You probably wanted to return the left-hand side)& }( E- A3 S! ?( Y
in: reri <- exp(fitlr$coef[2] + fitlr$coef[3] + fitlr$coef[4]) - exp(fitlr$coef[2]) - exp(fitlr$coef[3]) + 1- s. W! [5 U6 k3 V" A
> summary.bootstrap(bootstrap(smoking, reri(smoking), B=10000), probs=c(0.025,0.5, 0.975))
/ |4 a) o- M' lWarning messages:
+ P) y' }7 K" U; ] Numerical expression has 7028 elements: only the first used in: model.frame(formula, data, na.action, dots)( D; `* k2 \5 d' I( I5 H
Problem: Object "DM.0813" not found
0 J6 O2 g4 I5 @6 ^, ]Use traceback() to see the call stack2 _3 f# [0 M, l Y! A/ F: a3 }
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* \2 Q2 B$ [8 y3 H. {5 T不明白这个错误什么意思,小白求指导……
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