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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>, A, s6 ~3 W5 w9 g, {5 x
< ><FONT color=#ff0000>函数名: abort </FONT>
" X5 ^6 V0 [+ z4 F, o/ c功 能: 异常终止一个进程 G. J5 Y$ X# X: u6 H/ h2 }
用 法: void abort(void); 2 o2 y$ j, R* q- h, u4 V/ S
程序例: 2 [" `$ O% O2 S, f2 I% D, O/ d
<FONT color=#0000ff>#include <STDIO.H>% v G" D) x* `) \6 m
#include <STDLIB.H></FONT></P>
; z* R9 u, m) q+ _$ T/ X' P< ><FONT color=#0000ff>int main(void)
% K/ U+ x. z8 R" d, s% z0 ]{
" N& g8 |8 @0 N& B6 N/ K5 V O5 Pprintf("Calling abort()\n"); : V. G2 t# U& K, N/ q
abort();
9 h4 {% _% x* f; \* lreturn 0; /* This is never reached */ " Z* i2 R; M U0 |7 y; q! f* ^
} 1 u; h$ B0 V" b) Y) K
</FONT>
/ C9 |% a) B5 Q/ L$ R/ A' W</P>
$ j1 W7 \2 m& k' }< ><FONT color=#ff0000>函数名: abs </FONT>/ @5 P7 V ~0 W p3 Z2 I+ |0 N0 Q% n! j# _
功 能: 求整数的绝对值
, Z+ T7 b0 M9 i& @3 E用 法: int abs(int i);
) l3 D% j# S4 B. _程序例: q- v& F$ l2 K
<FONT color=#0000ff>#include <STDIO.H>
1 S, J8 m N- n! v: b#include <MATH.H></FONT></P>
A/ O! y! H) f L< ><FONT color=#0000ff>int main(void)
$ V7 w6 l0 k) b& C{
4 w w2 W& A- t( B9 fint number = -1234; </FONT></P>9 h2 N @! F4 m5 l
< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); ; A) P( b1 s4 r) W1 j
return 0;
+ I5 I; v! i9 r" A) ]3 ]} & N( Q& k- L, D- c( X! W4 q2 e
</FONT>
: I4 F' w# N, r8 A</P>
- F% O& g* \0 r, V+ H, L# w. W: B! m< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>
/ Q8 w7 c6 Z3 h* Z$ K, Y: z功 能: 绝对磁盘扇区读、写数据
1 b4 E/ @8 m3 Y用 法: int absread(int drive, int nsects, int sectno, void *buffer);
. Y+ l+ ]- @0 f2 {int abswrite(int drive, int nsects, in tsectno, void *buffer); ( T! v2 @0 R0 }6 A, |
程序例:
2 W7 l& ^; T/ r9 Q8 H+ C, L7 h3 |<FONT color=#0000ff>/* absread example */ </FONT></P>$ P" z+ d; F3 V
< ><FONT color=#0000ff>#include <STDIO.H>
# _( W) a5 b" h#include <CONIO.H>, W" H H9 z" R, @$ i! g) o
#include < ROCESS.H>. k7 _ @1 F! |. L
#include <DOS.H></FONT></P>1 i4 P8 g4 {3 g' [: c1 K$ Q
< ><FONT color=#0000ff>int main(void) & c# P; ]4 F/ e* V
{ ' p8 S% q3 J0 ^0 ]
int i, strt, ch_out, sector;
# L ~. A0 q( h: Z1 zchar buf[512]; </FONT></P>
8 M( U, y }7 H. e< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); # t2 L& @5 |; T+ o$ a0 Y/ A
getch();
! Y/ [: v C5 ]% m) H# l Usector = 0; 7 g' Q( g0 S7 D$ L3 G7 g0 b! P8 U
if (absread(0, 1, sector, &buf) != 0)
) ]& N' u: ~, Q- `{ + B$ J0 Y/ X B& o
perror("Disk problem"); 7 X6 P! P9 d: U
exit(1); 8 } [- {4 A) |2 s+ R1 L
}
( ?4 d' l8 ]# @: f5 r7 Gprintf("Read OK\n");
4 q* F$ b+ L# }, ?4 m: j- Ostrt = 3; 1 z4 i; z- ?8 I A. h
for (i=0; i<80; i++)
4 K4 B0 L- G9 [4 C{
3 k2 N" M5 p8 T9 x2 y4 uch_out = buf[strt+i]; - G9 D4 _# g7 C- T* l
putchar(ch_out);
" m9 }# f; r' {/ k3 i& | n* Q9 z} : l1 i4 Z! |8 C* n( E& C+ e
printf("\n");
R' o* h' v6 e$ Ereturn(0); 7 O: l( J3 k. D" T
} ) N& O; H) e5 ?% F8 v, X- h4 j0 Q* C7 T
</FONT>
6 c6 ?3 O! M/ n: o: I" u a5 a ^5 s F$ h/ P+ `8 Z
</P>
. v! T2 j. t9 T$ v8 D+ A< ><FONT color=#ff0000>函数名: access </FONT>7 k3 T4 t7 D) c1 k. S) f! Z
功 能: 确定文件的访问权限
4 l0 D! Q4 K$ C) T8 v用 法: int access(const char *filename, int amode);
5 ^6 I. Q7 _* B( c程序例: # S4 J# A1 S) Q8 N4 A O* @' {/ \
<FONT color=#0000ff>#include <STDIO.H>
( C' G6 \9 N+ U: D#include <IO.H></FONT></P>
& M& [7 n* g: O6 M7 d< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>: D* f& B5 K. |; n$ Q) _
< ><FONT color=#0000ff>int main(void) + |6 c; ?! T E' X0 u0 L+ D$ u
{ _/ p: `& Y+ C$ ?1 Q
printf("Does NOTEXIST.FIL exist: %s\n", ' [9 g* N9 D/ T3 }! V+ j8 J& P$ K h
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
5 z: @# _: r# F" b4 U% Hreturn 0; 4 e0 W2 q0 }1 Z2 E9 @% i
} </FONT></P>
9 d7 n# [ E* o< ><FONT color=#0000ff>int file_exists(char *filename) + ]7 E2 S7 Z0 Y
{ * J& y* {' o1 \/ N' { R
return (access(filename, 0) == 0); " R/ N. T+ |0 t: c
} % n5 ~5 c# o: H
</FONT></P>) l2 l6 a$ z! C+ M7 ]+ x' _
< ><FONT color=#ff0000>函数名: acos </FONT># t- f) a9 r) g& E v
功 能: 反余弦函数
7 [" g5 L6 S& t4 N用 法: double acos(double x); 1 N4 I7 T/ n5 A1 Z1 K2 [
程序例:
# F' b$ u; v9 N; G+ F; \<FONT color=#0000ff>#include <STDIO.H>
( R! a2 l! E2 {1 p+ A8 W: u3 d! p. j7 N#include <MATH.H></FONT></P>
6 F, g. ^$ `" f. c# ~< ><FONT color=#0000ff>int main(void) 9 Q. ?( ]9 `$ T* S& A' m) t
{
# b& N5 x7 x2 u4 \: p; ]( Gdouble result;
6 Z& ?/ z$ }2 }* B4 ]double x = 0.5; </FONT></P>( O& j! A; V) l# _
< ><FONT color=#0000ff>result = acos(x); 2 U( ]3 T$ T: S- B6 L
printf("The arc cosine of %lf is %lf\n", x, result);
4 z$ K( Q5 {7 A6 P- ]6 {- areturn 0;
0 D7 E8 F# Q7 W& F} </FONT>
( b: g. `2 K2 {# I" M/ g. l1 a7 z' W$ U
</P>
# I" `2 q; b9 K8 ]2 S2 D: Y" i! B< ><FONT color=#ff0000>函数名: allocmem </FONT>5 M7 i F1 Y5 ?. _7 o; P# E
功 能: 分配DOS存储段
8 |; G' z! I* j4 T# `7 T: [用 法: int allocmem(unsigned size, unsigned *seg); ( r; z- L0 y. G$ u+ W
程序例:
& N) F* ]2 Z0 F- m% c' B$ p<FONT color=#0000ff>#include <DOS.H>5 C* w9 V% Z ^+ x `
#include <ALLOC.H>
! f. b* P3 x t. Y& D. g* K#include <STDIO.H></FONT></P>9 a3 Q- _; a$ J9 ]- _- u
< ><FONT color=#0000ff>int main(void) ( q. m6 j) I+ E; `; A2 y( V% |
{ L" V* B! R) i+ `
unsigned int size, segp; , W' B& c* m0 p: k8 N! y! F* R
int stat; </FONT></P>
. q) {# K& ]4 b< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */
z& I1 ~) t8 h; _2 L2 U. Astat = allocmem(size, &segp);
5 O" J) n$ K" O. xif (stat == -1)
! E& i4 U! j/ H* L4 _printf("Allocated memory at segment: %x\n", segp);
$ r' `4 X+ O3 X2 m1 Velse 1 _. n9 J8 g. i! P, B0 C' E4 c
printf("Failed: maximum number of paragraphs available is %u\n",
) B4 \( x3 f1 l; A$ }' Jstat); </FONT></P>1 ?7 s; ?* Y" V- w% h
< ><FONT color=#0000ff>return 0;
/ p7 ]' l' I7 ]' |2 K! }4 s2 V} </FONT>2 C" ]0 _, Z/ V( o0 R/ g# f$ L
$ X& ]3 z" h ]# Q) N* f</P>
4 p+ m; Y8 `3 ~1 B" e< ><FONT color=#ff0000>函数名: arc</FONT> / \# C8 b2 Q; ^. E8 Q6 @
功 能: 画一弧线 # [" x5 Y7 l! y2 d3 M9 i
用 法: void far arc(int x, int y, int stangle, int endangle, int radius); , @( |8 Q. r9 i. q! p+ i: S
程序例:
0 p( _" V6 {9 B* v+ D6 K8 J<FONT color=#0000ff>#include <GRAPHICS.H>
- K" F# ]) ^$ a+ H#include <STDLIB.H>; [# r( g4 b+ V' ]% q/ N
#include <STDIO.H>1 m3 V: s$ N, e3 t
#include <CONIO.H></FONT></P>" u. @* m( Z0 B7 g3 {2 R1 V0 e
< ><FONT color=#0000ff>int main(void) ' D$ B* W: x, X9 }
{
2 d& }$ v/ I2 q/ S& x/* request auto detection */ . k0 Y, V; o- @" w2 e$ u# L" n ~
int gdriver = DETECT, gmode, errorcode; 3 y7 }9 v$ X; p; E
int midx, midy; ! K" d/ q" J! T; k! q. u8 K7 [
int stangle = 45, endangle = 135;
% w$ ^. \" [" [) M2 _% {; V2 nint radius = 100; </FONT></P>( d3 d0 d8 p0 F0 E. P
< ><FONT color=#0000ff>/* initialize graphics and local variables */
' n3 P' J7 Z- y: n2 @initgraph(&gdriver, &gmode, ""); </FONT></P>
1 H5 g1 Z L8 S' q( {8 \< ><FONT color=#0000ff>/* read result of initialization */
9 X* C3 c5 w4 `7 B' h. j7 Xerrorcode = graphresult(); /* an error occurred */ . _ B8 L- E# g1 l4 S* B$ E
if (errorcode != grOk) ( N; l" Q8 k9 x- p# h& t' k7 H' B0 h
{
N- b+ ]2 t) ^% k8 n- Y0 E1 A& C mprintf("Graphics error: %s\n", grapherrormsg(errorcode));
" f b6 m7 o" kprintf(" ress any key to halt:");
4 j/ w( W& t5 p- Z/ n% g- M6 Zgetch(); </FONT></P>% m3 g, D" A2 W J6 ~& a
< ><FONT color=#0000ff>exit(1); /* terminate with an error code */
0 B, s' T( r6 Y3 F5 ]} </FONT></P>
* X4 \) P. i) j. ]0 n3 m: r< ><FONT color=#0000ff>midx = getmaxx() / 2;
! u2 f- h: @8 ]5 Imidy = getmaxy() / 2; / p# B% F/ @7 {# j; U, u& I
setcolor(getmaxcolor()); </FONT></P>
- X9 A8 F& U& T+ m9 B< ><FONT color=#0000ff>/* draw arc */
9 I/ o f: W9 e% l) T- Y" H, Harc(midx, midy, stangle, endangle, radius); </FONT></P>
9 F2 \* o1 N# z% P<P><FONT color=#0000ff>/* clean up */ 2 p- j, r, I. t. U5 ~9 v' G
getch(); 9 h# A2 y: F6 F: V
closegraph();
1 l( r, I% e1 c" a e9 L2 B: Areturn 0; K! t* C1 F y @+ a, V
}
- u& [% H2 D* x- o* [</FONT>
- s; ^. t( K- h2 ^, e# F</P>9 p5 N6 k$ z' v5 _; ?
<P><FONT color=#ff0000>函数名: asctime </FONT>
6 Z9 W+ U/ m7 u4 c7 O" H功 能: 转换日期和时间为ASCII码 0 W5 J4 I, ^9 a9 [1 F
用 法: char *asctime(const struct tm *tblock); + \' V2 l* k" L# G+ S6 B4 }
程序例: 9 `6 [$ v/ x0 w9 ]1 E% {5 v, f
<FONT color=#0000ff>#include <STDIO.H>5 i$ }2 B* g' F: a7 T) h
#include <STRING.H>0 ?% z! I# h7 M- [; C+ `( V
#include <TIME.H></FONT></P>
; P1 _1 J& E& Y7 b; e3 k5 r f" t<P><FONT color=#0000ff>int main(void) - |, c- [/ P& {. J
{
* H- i( I& m* g5 c( S: G' wstruct tm t; 3 T( X# p9 ~. v l5 v
char str[80]; </FONT></P>
' L% Z& ^- L/ D J9 t& R<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>1 \# t& m* _2 V/ r1 U, r/ u
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ # e5 Q* t; ?, [8 }
t.tm_min = 30; /* Minutes */ 1 r/ d9 s% g8 i& k0 k
t.tm_hour = 9; /* Hour */ 6 u. {+ e7 ~( s; i: e) k2 S
t.tm_mday = 22; /* Day of the Month */ / l: k5 ? C" p& J9 ^7 C2 b6 O
t.tm_mon = 11; /* Month */
; }. f* X9 E! z H4 p: F- ]3 @t.tm_year = 56; /* Year - does not include century */
6 e& d' t+ T) ^$ c4 t# V+ o) Dt.tm_wday = 4; /* Day of the week */ ) d! u8 Z) f5 n0 V4 W9 X
t.tm_yday = 0; /* Does not show in asctime */
. R% ` ~. U- l) `, q! d" Ht.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>( ?$ `$ i5 E3 Y. l
<P><FONT color=#0000ff>/* converts structure to null terminated
+ o+ G7 L# b5 s3 ?string */ </FONT></P>
( L4 r \6 d* v: Y9 z<P><FONT color=#0000ff>strcpy(str, asctime(&t)); * o' X2 u3 I8 p- i
printf("%s\n", str); </FONT></P>7 {4 y& ]* {8 r
<P><FONT color=#0000ff>return 0;
) W v! n' {6 s# u$ [}
4 E. Y8 F7 {% m7 [
" |. r- [) X4 S6 G1 r6 {! L$ O</FONT>
" f4 c0 h' p V8 q- t" l4 {0 e</P>4 F8 M3 L& f# O1 y
<P><FONT color=#ff0000>函数名: asin </FONT>
$ ^! i h" v4 B: U功 能: 反正弦函数
9 W8 n9 ]5 x; G$ Q& N用 法: double asin(double x); ) p: o& C* n0 f
程序例:
( r& j9 Z) g3 l9 D. R. V% o<FONT color=#0000ff>#include <STDIO.H>
" T) e( M; n, K#include <MATH.H></FONT></P>
/ W% ^3 |' j: \ h8 N" c* x<P><FONT color=#0000ff>int main(void)
0 n5 s# M2 `3 c! r+ c5 h{
* ^$ y6 ?/ ?; V, J6 @( b7 p" Ddouble result;
- Y9 [0 d6 G3 }1 Fdouble x = 0.5; </FONT></P>! b5 H" d5 x* N9 c$ k) t
<P><FONT color=#0000ff>result = asin(x);
9 I1 }' d; y7 y7 fprintf("The arc sin of %lf is %lf\n", x, result); ' U5 j) O J. y' Y
return(0);
& D. J9 L4 Z* f$ [} L: i ?& O' Z* Q
</FONT>
$ B' r0 I1 e6 I Q3 ]0 `. F, O" I/ P: X& ~& s$ Q6 |: B7 A
</P>
' V+ q+ o& l9 C1 h<P><FONT color=#ff0000>函数名: assert </FONT># r; h( r, v3 t, n+ [" ]2 r
功 能: 测试一个条件并可能使程序终止 4 m4 f6 q' }! f; m( V, W& ?
用 法: void assert(int test); 5 P- x) W z5 w- t& F# A- D
程序例:
* Z/ O& x+ e" M( S: O<FONT color=#0000ff>#include <ASSERT.H>' f% \9 ^( ~; ^9 w, {! k$ W* W
#include <STDIO.H>
4 _( w. |% A7 m9 A. |#include <STDLIB.H></FONT></P> m( I, a F- b# A9 g. U
<P><FONT color=#0000ff>struct ITEM { $ ]2 y+ d5 I# q3 {/ C4 F( A6 P& u' N# n
int key; ( P# |& Y8 M6 w
int value; ) b; Z- V' y( \9 ^2 }: }+ u
}; </FONT></P>
5 F( @; o0 y& q1 }<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
6 g' ^, c# u+ P" Y" e. bvoid additem(struct ITEM *itemptr) { 7 ^- Z9 r: } m O9 }! @0 I
assert(itemptr != NULL);
" L0 _0 U4 G! ]/ F/* add item to list */
8 a( s; M, N8 p% x) `7 R4 t7 t5 h} </FONT></P>
7 V$ }; o/ c# ^1 w! T0 l7 z<P><FONT color=#0000ff>int main(void)
: g/ G0 W9 V5 ?# k, t8 [{ " G2 W! [" M% m; m6 i! `7 ?. G! \3 C
additem(NULL); # \0 y2 D" I# |: Y1 B
return 0; 4 v B1 y; _ e
} " M% q& \8 j) `" l; l9 C) F; g
</FONT>2 K$ W2 B, V$ \" n1 m
7 j% G: t- |$ @: P7 \</P>
( r7 r3 J% a7 |' X( g<P><FONT color=#ff0000>函数名: atan </FONT>, u& p) Y4 q9 n) a' a0 d# G5 ^
功 能: 反正切函数 % h1 ]- Q7 u9 o; Q' k/ o! _& K& V' l' m
用 法: double atan(double x); ( v$ Q% k6 r; e2 ?8 W- I
程序例: # O2 N/ @: j/ z9 }% ~
<FONT color=#0000ff>#include <STDIO.H>/ U) D0 Y7 k6 G1 T; p! z
#include <MATH.H></FONT></P>0 X" q2 q. {. a: E8 q
<P><FONT color=#0000ff>int main(void) ; }1 q5 Z: |# S& I
{ 5 c9 V- X+ s* @$ g$ S
double result; & v: y( P5 H' X; h) A' H; { n
double x = 0.5; </FONT></P> U S5 `( b' ~4 Y9 n
<P><FONT color=#0000ff>result = atan(x);
. R: f I6 T# ]/ M) g6 }; X! Kprintf("The arc tangent of %lf is %lf\n", x, result);
. _$ A4 u. w2 a9 breturn(0); # _' p7 ^3 C- L
} " H1 S" w6 n {% R7 x, F1 z
</FONT>7 j2 K4 S( U5 x) N; m: y" }
</P>
8 h; k5 [+ L) l8 Q<P><FONT color=#ff0000>函数名: atan2 </FONT>
: k2 ^6 n" `4 W+ V* ^功 能: 计算Y/X的反正切值
) S4 ], ~1 Q4 `! S用 法: double atan2(double y, double x); + Z* X; z* L3 i( \
程序例:
9 i. B& {" ^2 P5 C& h$ M8 z<FONT color=#0000ff>#include <STDIO.H>" C O! J6 u! c* ?+ _0 F) ?+ R2 Q
#include <MATH.H></FONT></P>
( w6 ^5 Y V0 l( y0 W1 O9 L- y<P><FONT color=#0000ff>int main(void) 8 y6 O( @4 B( _9 b' s: T2 W
{ " b# G5 r0 W L4 G
double result;
D' Q, k, B7 e5 o# k4 tdouble x = 90.0, y = 45.0; </FONT></P>
3 C5 S' ?0 t2 L" `8 ~<P><FONT color=#0000ff>result = atan2(y, x);
4 |& K' n4 T: r2 oprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
+ m6 d7 O. I/ b3 L7 L4 t, W- N- Preturn 0; ( g* e% B/ T& s0 e' F% B) p2 ^
} 5 t% `$ R4 y ~! D4 M4 n
</FONT>
: I5 c+ D& v8 ?9 M# l7 ]</P>" }2 `3 i& C( Q7 q& [2 T' {+ u
<P><FONT color=#ff0000>函数名: atexit </FONT>! A/ Y' u* @$ V% ?
功 能: 注册终止函数
% K! J4 j" t5 W" @7 d9 z用 法: int atexit(atexit_t func); * @9 j$ o; c) J0 v- N7 A6 B
程序例: 6 {6 y% h3 U& i! Z
<FONT color=#0000ff>#include <STDIO.H>( I) X$ z0 C, E# B" Z; ]. _6 R- X
#include <STDLIB.H></FONT></P>: Y, n) x5 t% l4 M2 o X7 S) L/ E
<P><FONT color=#0000ff>void exit_fn1(void)
) t% J( Y' ]4 ?7 T; c, k. L P{
% K$ \3 I3 v6 U6 c1 ^$ Xprintf("Exit function #1 called\n"); $ x- c4 k7 A3 C% P* ?& ^/ o4 n: c
} </FONT></P>
: x. l& ^1 c$ f/ B. ~6 \5 H<P><FONT color=#0000ff>void exit_fn2(void)
6 N" p1 R e5 b{
) ^' s" p0 K& w! U* `' M3 vprintf("Exit function #2 called\n");
9 ~/ o, N/ t+ a$ C. v: d y3 Y% u6 Q" w} </FONT></P>
/ O9 E# d% P' D<P><FONT color=#0000ff>int main(void)
& K# ~6 s. R+ ]{
7 e/ ~) J) Z* |5 P+ d- i6 i7 ?7 n. O/* post exit function #1 */ 0 k! [ c7 e' h* c' { J5 A
atexit(exit_fn1);
* Z, `4 y: y& Y6 m/* post exit function #2 */ 9 D) K: K2 E) M( B- w
atexit(exit_fn2); / A7 F# s, ~9 m2 h! q2 e0 T
return 0; & p+ i1 F% q% c* O
} : h( l" ~4 V4 A O$ R
</FONT>! p9 f% G9 n4 `* A9 I
- p2 O S" v2 ?) r
</P>
/ c6 C/ \6 W. P2 G<P><FONT color=#ff0000>函数名: atof </FONT>' O7 h+ Z, j9 v3 h( P/ \
功 能: 把字符串转换成浮点数 T) \4 u F8 d& r! w7 P
用 法: double atof(const char *nptr);
; X6 f" Y) g+ b1 E6 m+ c程序例:
$ P4 @+ g: ]7 D<FONT color=#0000ff>#include <STDLIB.H>0 V) j0 P9 e; o7 o% X; T
#include <STDIO.H></FONT></P>4 E8 v! r5 ?* ^& _4 {" Z4 G ^( I
<P><FONT color=#0000ff>int main(void)
% s/ U. v' o8 O+ m/ M9 D{ 6 p1 S+ @2 Q( u3 m. g8 h+ e
float f;
; X$ I/ r/ `6 N9 e) U6 jchar *str = "12345.67"; </FONT></P>2 O4 G4 ]( }0 \. `% I
<P><FONT color=#0000ff>f = atof(str);
0 y4 R8 N- _% E2 i, m- Z8 ]printf("string = %s float = %f\n", str, f);
7 P6 L5 `. y/ i, P/ c* J- ?0 Y2 yreturn 0; 6 T7 g* Y8 K4 u% }1 k% r J" ^
} % }+ `4 e+ o* n
</FONT>
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<P><FONT color=#ff0000>函数名: atoi </FONT>8 ~4 K# d# x1 o9 r% Y |4 m1 b
功 能: 把字符串转换成长整型数
7 M3 ^" `/ K: o1 n' B- ]- r- m/ Z8 [用 法: int atoi(const char *nptr); ( h+ c7 V0 Y0 h& [2 @
程序例:
$ d+ O4 c3 \6 A t0 |& o<FONT color=#0000ff>#include <STDLIB.H>$ q% P; `4 }/ g4 k- P* O
#include <STDIO.H></FONT></P>8 ~. l+ g' C7 F3 S3 E; ^" w- Z
<P><FONT color=#0000ff>int main(void) + V8 U, V7 _+ p- B Y; A+ u: v- f. `; `
{ & q8 y# r9 C" P" |+ L2 T* ]
int n; 0 Y2 o1 A- C3 \9 ^. _8 J4 f0 \
char *str = "12345.67"; </FONT></P>! r7 L; H& i8 U, C2 ]& m: @
<P><FONT color=#0000ff>n = atoi(str);
& L D. B4 s: {$ k0 X, oprintf("string = %s integer = %d\n", str, n);
$ b: y5 j- c" jreturn 0;
$ j z& @- ^' L" I: }' x I! W}
$ d) b2 h% e9 @; L2 Y5 S0 E</FONT>) ^+ f: w3 u9 G
</P>
3 T6 v. `3 q5 d) F# }" G+ Z<P><FONT color=#ff0000>函数名: atol </FONT>
9 V/ E* K5 Z. }1 m9 Y功 能: 把字符串转换成长整型数
/ A/ y4 l4 V5 \7 ^5 |用 法: long atol(const char *nptr);
3 r4 U8 a. H+ u. g4 i/ Q2 P程序例: </P>( k" r0 N5 ^' p+ H+ ]6 G( P9 Z
<P><FONT color=#0000ff>#include <STDLIB.H>
" J C, J. q# @5 M#include <STDIO.H></FONT></P>& z9 S8 P2 g* E8 k
<P><FONT color=#0000ff>int main(void) ' K' B6 V# F) i' V: }
{
! z# b1 i5 r/ @6 U. Z; k; o% ?; Vlong l;
, D% I& b2 R$ hchar *str = "98765432"; </FONT></P>5 M5 Q5 T. L5 I+ c( ~
<P><FONT color=#0000ff>l = atol(lstr);
; p7 h7 A+ M% B, i3 ?5 Cprintf("string = %s integer = %ld\n", str, l); , D' e1 v$ M" A
return(0); ; F! I+ Y1 u s; o3 K. T
}</FONT></P> |
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