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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>+ L- b4 U4 f2 s/ R4 r( {/ O
< ><FONT color=#ff0000>函数名: abort </FONT>1 V/ N$ q0 D9 R+ g' n
功 能: 异常终止一个进程
; u# _- o! {& U用 法: void abort(void);
5 E) n5 Z' |* A8 V, d/ @: U程序例: ' q+ J& V0 ^- J' p! N% d
<FONT color=#0000ff>#include <STDIO.H>
8 ^' Q' F T8 _) T. Y#include <STDLIB.H></FONT></P>
; [7 X6 p6 s! J% E+ p< ><FONT color=#0000ff>int main(void)
/ V5 T1 X+ z6 o( Q+ w" \; i{
$ o% t7 `: u% @2 mprintf("Calling abort()\n");
# `8 k# j* o- L. r4 \8 v( dabort(); 8 g' @' [% o0 }6 Y
return 0; /* This is never reached */
4 J, _* G3 |0 T) c' O$ q+ _% g+ Q}
* p; @9 c2 I a7 `! p: {</FONT>. }& i* \7 L: g" n0 M! }. ]
</P>: ], x' ]5 D* J# n6 c$ d2 ^; D
< ><FONT color=#ff0000>函数名: abs </FONT>
0 X* X* n$ `/ h3 ^; X1 K" f功 能: 求整数的绝对值
8 D1 A- J/ Z; p9 t+ v9 P+ a用 法: int abs(int i);
0 R3 G4 m' @1 m8 n$ X程序例: 1 I s5 |7 o2 O- N4 w3 _3 t! ~
<FONT color=#0000ff>#include <STDIO.H>! M: U' u" E, S: @) y
#include <MATH.H></FONT></P>8 g) a. o/ u3 c2 H, \- a# z
< ><FONT color=#0000ff>int main(void)
: C! _& o5 K6 @9 L, X{
! l3 g+ d+ F% i! Nint number = -1234; </FONT></P>& u, x: H; n+ ?/ q: i9 G9 k
< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
- h: \6 ^! T4 ~% ~1 m+ ^7 u* Sreturn 0; $ T9 I* v4 R3 `6 }1 F, B! s9 B
} + G ~* y% M# c* H5 u
</FONT> j1 ~) y8 L. ~/ V& e
</P>* s) d. [+ B' k
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>9 Y4 T- T+ B2 Y" l8 a" g
功 能: 绝对磁盘扇区读、写数据 # y, @# x- J- ~
用 法: int absread(int drive, int nsects, int sectno, void *buffer);
$ V* J) q9 G5 w: uint abswrite(int drive, int nsects, in tsectno, void *buffer);
6 @: j |) S( [+ k8 K' u程序例:
+ K" ^ `, ^3 A4 {; g<FONT color=#0000ff>/* absread example */ </FONT></P>
5 P$ ^' y8 a# I- |< ><FONT color=#0000ff>#include <STDIO.H>
, B/ F% B( c) c+ f3 l: q#include <CONIO.H>4 J, Y6 b: _# Z2 l
#include < ROCESS.H>
* {; z; w5 T: y! `, }% A; c+ F#include <DOS.H></FONT></P>
( k! b7 |5 K. m( k! {< ><FONT color=#0000ff>int main(void)
& N$ i3 `" o/ z8 M% y& Z7 X. a{ & s: v; J2 T6 }3 F
int i, strt, ch_out, sector;
) B! A8 y7 z0 ^/ @8 c1 }+ jchar buf[512]; </FONT></P>
. ]) k& g7 p; _< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); " X/ X4 d3 Q* y9 A; E/ T9 P
getch();
; `; V% f/ i, @sector = 0; 6 g3 ]4 v7 M& w' A, J7 s
if (absread(0, 1, sector, &buf) != 0) ! f4 A% Z* k$ c6 ?: M
{
8 i- Z# F7 b( `perror("Disk problem"); 7 E) o/ h6 t% c y: |! P
exit(1);
" W. y7 K/ A* N0 Y" w a6 l}
3 L; G4 c% Q# v9 ]* [2 r( W1 ^printf("Read OK\n");
' x! [' V. ?' a7 Hstrt = 3;
3 S+ ?2 M) E) u& y9 T0 @3 ffor (i=0; i<80; i++)
, }; q) U5 G+ G& ]: D7 c) s0 V3 s{
9 g, l7 P5 I6 w8 Fch_out = buf[strt+i]; - ~8 Y4 E/ A. ]1 x
putchar(ch_out);
! {( r2 L* p4 r}
4 L, k8 z( h$ q0 h1 Z% Aprintf("\n");
$ l6 O6 f/ x0 R: breturn(0);
, z8 z/ V' N+ Q7 i ~% B6 J$ U} / E1 s A) A9 n8 T2 \$ D2 t3 {
</FONT>" }; \! Q4 a% b7 c5 [
4 @9 V& _3 {: v, _0 y# h% D
</P>1 h( K) s) N% m. O
< ><FONT color=#ff0000>函数名: access </FONT>9 l+ Z7 t0 P# C
功 能: 确定文件的访问权限
& w7 }' w4 P9 E用 法: int access(const char *filename, int amode);
6 ^/ I+ i' I# q# a: |程序例:
% m! Q g, ~8 t8 \<FONT color=#0000ff>#include <STDIO.H>
& m/ b' W7 A. B+ S! X, l#include <IO.H></FONT></P>8 `' S- V& R" n8 D# p
< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
' Q( g; t0 F$ i) ]; l< ><FONT color=#0000ff>int main(void) ! ]: \0 }4 z$ ?& r: Y: [8 S
{
: p. {. z3 N8 qprintf("Does NOTEXIST.FIL exist: %s\n",
8 [0 e) N+ ~) G% S! b) z, G0 |file_exists("NOTEXISTS.FIL") ? "YES" : "NO"); $ j) N8 k! b9 `& N1 t* t8 ~) h
return 0; 2 @ i* z+ y* g q
} </FONT></P>
# S2 M' g9 O; o, O< ><FONT color=#0000ff>int file_exists(char *filename) % I- S% |- W# t
{
3 Z. {; H! i, O2 |+ e: ]return (access(filename, 0) == 0);
) }. X$ k6 K: s& o' x- j} ) V8 ?5 `& x" R( c, e: X7 m
</FONT></P>
# f: v& }# c9 N8 r4 w< ><FONT color=#ff0000>函数名: acos </FONT>3 \$ @( w5 R! m: W: E
功 能: 反余弦函数
9 }3 s6 G9 y+ u) z1 ]. d: D: K用 法: double acos(double x); 4 P! G' l7 Q3 r/ b% `
程序例: % Z2 U8 I# B" z
<FONT color=#0000ff>#include <STDIO.H>
7 i3 X& L. ~& M#include <MATH.H></FONT></P>+ T) o4 { p1 h: r" x* R3 q
< ><FONT color=#0000ff>int main(void)
. t% D0 X) X; E8 {' P5 }{ # p* d0 z, P& t
double result;
! ^4 `& X0 B' M) V5 l( |4 Ydouble x = 0.5; </FONT></P>" F2 ?! x5 a% u$ @" k
< ><FONT color=#0000ff>result = acos(x); 0 Q' R* j+ L- o: e0 P- a. t1 F t0 G
printf("The arc cosine of %lf is %lf\n", x, result);
9 J, ~( ?, ~" H& ^! }7 s% Ureturn 0; 8 |* r. ?% `3 M3 g7 a2 R# J/ o
} </FONT>
+ p r9 [( b/ @: N' ~5 E+ @. k$ q5 w
</P>
, r( _" b$ ~- n; D< ><FONT color=#ff0000>函数名: allocmem </FONT>
- f2 p' ?( r7 l8 D: B功 能: 分配DOS存储段
( D! i8 Q8 q s5 c; U4 S+ z, _用 法: int allocmem(unsigned size, unsigned *seg); ; _9 L F0 j" N1 ~# B
程序例: % x* q, O7 ]# M+ k4 {( T7 d
<FONT color=#0000ff>#include <DOS.H>
5 s! G) ~6 U/ H" f0 G; J( F#include <ALLOC.H># u9 t4 z# z; k: L9 s4 A& E, a
#include <STDIO.H></FONT></P>1 M2 h F) [0 L6 G
< ><FONT color=#0000ff>int main(void) / |" E. u" f; z# c! k3 k
{
9 Z+ K8 K" |/ K9 Sunsigned int size, segp;
6 T l4 q: t1 ^" {! |" hint stat; </FONT></P>
5 F& C# c" h, l5 R< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ 3 t$ T& N7 |. _ z' r$ f
stat = allocmem(size, &segp);
/ X4 ^) z2 X2 L+ F* Eif (stat == -1) ' n* X2 S: I3 j* {7 {
printf("Allocated memory at segment: %x\n", segp); ! V! z1 J, n! I+ P: v* l: @
else
4 \5 d+ A+ D9 X0 m. g$ d; K, xprintf("Failed: maximum number of paragraphs available is %u\n", 6 o3 ]* A' N$ T& v2 \
stat); </FONT></P>9 [/ @' J; v+ V; z; z+ a
< ><FONT color=#0000ff>return 0;
4 s; }0 `7 P; h# R3 V} </FONT>& J7 b: j0 t8 v! \9 g8 S) k% S, |
/ B- V8 J+ T/ z2 t</P>' P- O( }7 t3 k
< ><FONT color=#ff0000>函数名: arc</FONT>
8 i) p( I7 M" U- p. {4 V' b功 能: 画一弧线 - G( z+ T3 i0 g- @3 g9 M: s# `
用 法: void far arc(int x, int y, int stangle, int endangle, int radius); / N1 m: }3 d& @, v
程序例:
/ O4 P+ v$ ^1 w/ x<FONT color=#0000ff>#include <GRAPHICS.H>, o5 G( c' M. {6 V
#include <STDLIB.H>
) g, f6 }9 Y6 {4 W W, q& `$ V2 y#include <STDIO.H>
. H0 K6 t% @. D7 V8 d+ ?#include <CONIO.H></FONT></P>$ \4 X" i1 a: B# F$ b T* W# _
< ><FONT color=#0000ff>int main(void) 6 R+ H7 n- w J$ \# j
{ 1 s u* t# |# C9 ]3 |4 L
/* request auto detection */
' a/ w" O2 R1 i$ |int gdriver = DETECT, gmode, errorcode; ]! ]4 `+ w1 ^
int midx, midy;
$ n! ?5 R8 R; }1 }int stangle = 45, endangle = 135;
( }. W, P8 l% A4 r+ H& W5 p2 C( ]int radius = 100; </FONT></P>4 \/ C4 X2 `2 K
< ><FONT color=#0000ff>/* initialize graphics and local variables */
[* ]4 s6 q4 `, ]. ~' kinitgraph(&gdriver, &gmode, ""); </FONT></P>9 ^) y- k( h: Q$ S8 S
< ><FONT color=#0000ff>/* read result of initialization */ 2 d: a0 y7 Z3 c8 t+ t5 R0 ?: a
errorcode = graphresult(); /* an error occurred */ # d4 Z" a3 z. e! C. q, A, k
if (errorcode != grOk)
4 J) G/ L/ [- G( W+ N0 {0 E{ 2 {/ s' u, ^8 v
printf("Graphics error: %s\n", grapherrormsg(errorcode)); ' W9 N+ d0 k/ t: v6 e4 M
printf(" ress any key to halt:"); ( _+ k0 o. d" T) Y- s+ o- i
getch(); </FONT></P>
: h/ h. J& M/ e0 P< ><FONT color=#0000ff>exit(1); /* terminate with an error code */ ; l: u: l9 s5 [. s" T- T! Z
} </FONT></P>( h9 F) e. y' o4 G6 k" w
< ><FONT color=#0000ff>midx = getmaxx() / 2;
3 v4 Z9 l$ o ?+ h, X' O G6 A8 `! ^5 a" [midy = getmaxy() / 2; 6 N& Z$ j4 b$ P( z- @
setcolor(getmaxcolor()); </FONT></P>' `7 Q T/ ?& N9 m; l. I
< ><FONT color=#0000ff>/* draw arc */ * }% W3 b7 W* ~) B, o* H T
arc(midx, midy, stangle, endangle, radius); </FONT></P>
- r2 |: w3 q7 d7 z" _( w<P><FONT color=#0000ff>/* clean up */
F; H6 B! y) U6 ~getch(); ' R7 @) }& ?! w+ h
closegraph(); , r) u4 T7 w7 w1 l
return 0;
7 V+ u7 B* t; M}
* |9 Q: y" `) X/ w</FONT>
+ A/ N* `, A; W/ j</P>
8 z* S$ X: K. W<P><FONT color=#ff0000>函数名: asctime </FONT>! r' D% Q+ I0 q8 {- u9 b9 R" w H
功 能: 转换日期和时间为ASCII码 7 }& M1 B. f; D1 g/ W# _
用 法: char *asctime(const struct tm *tblock); 7 C1 \1 B0 l) K- w, R% N) [
程序例: % t/ X" A. U, J9 {& S4 i9 ]
<FONT color=#0000ff>#include <STDIO.H>
1 |3 P. ?- a; Q! k1 n0 v#include <STRING.H>7 c4 U5 a: [+ p3 ^& ?5 Q
#include <TIME.H></FONT></P>: F* d& D9 J1 a& e
<P><FONT color=#0000ff>int main(void) , c; b9 r5 v# C
{ + A3 q3 m7 c7 H% [ }, Q$ ~
struct tm t; ( z, K( ]2 C7 k# {# n4 F& Y* k
char str[80]; </FONT></P>3 Q/ Y) P: g* B
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>8 b9 L; J- c5 d4 s. g1 G
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
' P) H/ \: E0 g* M Ct.tm_min = 30; /* Minutes */ 3 Y& P/ K9 q3 O& z! p
t.tm_hour = 9; /* Hour */
1 K9 `: A8 Z* l: st.tm_mday = 22; /* Day of the Month */
- F7 e8 ~0 Z3 w2 at.tm_mon = 11; /* Month */
- C. i# a1 H$ n9 I: C6 P- n, q+ y- Ut.tm_year = 56; /* Year - does not include century */
( r# N0 P5 k# e) H' H% Dt.tm_wday = 4; /* Day of the week */
0 p5 l# Q9 ~- kt.tm_yday = 0; /* Does not show in asctime */ 1 N4 Y6 p8 u, h {0 `& i) m# H5 i
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>0 M, l# X8 U1 W4 S6 S# Q9 j/ k
<P><FONT color=#0000ff>/* converts structure to null terminated L* X/ d p8 V ]. M P# p
string */ </FONT></P>* e) r4 v3 d& D" A% y4 Q
<P><FONT color=#0000ff>strcpy(str, asctime(&t));
5 M3 w( J0 f* i) l9 J: f. g+ Mprintf("%s\n", str); </FONT></P>
; }$ ]2 ^" n5 G<P><FONT color=#0000ff>return 0;
9 B7 ]0 N3 L5 U2 x! b) W4 ]}
, x. l3 P) A6 u7 `! y
' p* d, H8 i, i; l% E; z7 d</FONT>3 o0 J; F5 p- a$ @% |
</P>, \3 A, W3 A8 |( |
<P><FONT color=#ff0000>函数名: asin </FONT>% d! h4 \7 H9 ~6 D4 F! r+ I
功 能: 反正弦函数
, F+ K' ^& v) n) m" U/ ?: x! @用 法: double asin(double x); 3 B/ ?0 @$ k" x' d
程序例: ( D9 E% j" d3 U& u
<FONT color=#0000ff>#include <STDIO.H>! U6 w, N' a) t0 @' t# Y
#include <MATH.H></FONT></P>5 T3 @5 d0 W% F3 E8 S" ?
<P><FONT color=#0000ff>int main(void) 8 F. p1 N8 j2 e5 w q! s$ c4 N/ G
{
. A& n( W9 T/ V+ J5 y/ bdouble result; % u2 J2 f" Q# K
double x = 0.5; </FONT></P>4 K& @: S& ?8 ]7 w4 V4 K
<P><FONT color=#0000ff>result = asin(x); 6 z6 e1 A3 d: V
printf("The arc sin of %lf is %lf\n", x, result); . r8 X, U7 n: ~" |( R
return(0);
6 ?2 p+ t8 l. O0 O}
9 X( }. [4 |3 T/ n6 K9 H5 Y2 ^* F</FONT>
. e1 \5 ?" }, a3 ?4 |8 Z7 M7 {" a) w; i s: W# P
</P>! x5 r) y, ~* n
<P><FONT color=#ff0000>函数名: assert </FONT>% X0 R1 P% K5 A% s$ L a) ?' D
功 能: 测试一个条件并可能使程序终止 + O+ t- {3 i- ~( T3 h" k
用 法: void assert(int test);
+ h0 z+ }! G% j( u. C8 U% w程序例:
2 m2 u" Y% v! Z<FONT color=#0000ff>#include <ASSERT.H>
: ]7 V3 ?7 x2 V( l* ]#include <STDIO.H>: M1 ~* Z! ?6 I9 H: y6 ^4 u
#include <STDLIB.H></FONT></P>! M" v7 S9 ?" P3 J/ D
<P><FONT color=#0000ff>struct ITEM { - A4 K$ W0 M- v7 c% V
int key; . w ?/ r3 b4 Q% i. L' O* }& _
int value;
, N% E. M3 X, e/ N}; </FONT></P>, C2 Y. N. e; z
<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
+ o. l1 v) ^- g. @6 ^3 wvoid additem(struct ITEM *itemptr) { 3 o2 k/ Q: t- N' F" d1 }. B3 I
assert(itemptr != NULL); 3 r3 G' C* q7 V: i8 c& d6 c
/* add item to list */
) y5 A# S( L# ?9 n b} </FONT></P>; o( [9 T; O: a2 y
<P><FONT color=#0000ff>int main(void)
* L, i' F% D8 n" G8 }. ~{ , _/ F8 D* B! z0 b0 n
additem(NULL);
5 ~% J7 ^! O2 I* b1 rreturn 0;
: `) C9 x+ R% x, d}
$ T& i1 Z5 v! @1 Y. {; \</FONT>
- H2 K+ t! o% V& p/ n3 I1 X- e; \1 V9 M) {
</P>7 p4 u0 m6 O7 ~# E" @/ o6 @
<P><FONT color=#ff0000>函数名: atan </FONT>
* O+ L# P% Z, O功 能: 反正切函数
- P& Z( b/ R/ `" X用 法: double atan(double x);
7 _9 y. t1 S \% u D: k( t# k程序例:
! L) M) l4 V) | ?<FONT color=#0000ff>#include <STDIO.H>4 L: e: a5 g: [% Y/ C
#include <MATH.H></FONT></P>
( a$ f4 E! | X) n- S<P><FONT color=#0000ff>int main(void)
* Y% s8 ^' E0 D, ~{
$ m7 F# W! i) Y% E- Y5 Sdouble result;
1 k3 F. A3 N; l) n% E6 j8 Vdouble x = 0.5; </FONT></P>/ U# T; @, a! ]
<P><FONT color=#0000ff>result = atan(x); ! T9 B, T5 i# k7 a8 B3 O: g9 L/ x
printf("The arc tangent of %lf is %lf\n", x, result);
& O* y8 O/ F9 F" K0 f! E q5 C% J; wreturn(0);
' F8 _- {6 ~6 \* w- |}
- ^: }0 c% j9 P4 i, O( |6 @</FONT>" W% \, f! J8 i" V
</P>- }2 x! M. p! H& ]' D# j
<P><FONT color=#ff0000>函数名: atan2 </FONT>) E# t, n G" P7 y0 x: q) ]
功 能: 计算Y/X的反正切值 , ^) S% [0 v+ A, V) b1 h& F
用 法: double atan2(double y, double x); % ~& \" V! b! Z1 Q& Q) y( B3 u
程序例: " V3 M9 Z, t& E8 ]+ {8 ?2 E; Q
<FONT color=#0000ff>#include <STDIO.H>& G9 T; `0 l+ w0 K0 O @5 `+ ?
#include <MATH.H></FONT></P>
0 k) K- c* C( J, n3 u<P><FONT color=#0000ff>int main(void)
1 ~$ M9 D4 T- `* N- q! Q# Z{
+ o m8 g4 W; q$ n+ y# ddouble result; 8 `# [+ z3 d! P9 L: |9 j
double x = 90.0, y = 45.0; </FONT></P>- y0 a0 E, J" ?; ?$ \
<P><FONT color=#0000ff>result = atan2(y, x);
F5 l1 R+ q" ^printf("The arc tangent ratio of %lf is %lf\n", (y / x), result); . e+ `% ]9 P5 |- f# ]9 {0 h
return 0;
, R; r/ R+ b# k% a. ?0 l9 N}
1 }+ `( W4 w6 E' Z</FONT>6 Z! G) _$ J9 k
</P>
3 `8 A3 z' j+ {2 {! b<P><FONT color=#ff0000>函数名: atexit </FONT>
) m4 L E6 R- V5 {2 \8 _/ i功 能: 注册终止函数
4 U! V' X* g2 \2 e2 r1 D用 法: int atexit(atexit_t func); : o: z5 R5 o5 |% i
程序例:
' T# f* f U' a/ I$ t) g, ~% P<FONT color=#0000ff>#include <STDIO.H>% R5 f7 Q* Q5 d/ _: m N; h
#include <STDLIB.H></FONT></P>& g! v9 v2 D; ^' P. d
<P><FONT color=#0000ff>void exit_fn1(void) 2 P" m' r0 R' m/ W2 `. b
{ q/ V' R7 n2 p" o. a! ]0 p
printf("Exit function #1 called\n"); 2 s& Z) ]) c, A& X7 y
} </FONT></P>
$ }: @2 H. x5 S, V2 R<P><FONT color=#0000ff>void exit_fn2(void)
1 B1 z4 L8 x; \4 z* N, h) b{ / E5 `0 k5 B1 `% O6 |/ a
printf("Exit function #2 called\n");
4 ? C4 Q1 b7 W% l) R} </FONT></P>8 ~5 M; N' W, b* e$ Q
<P><FONT color=#0000ff>int main(void)
! s4 y8 E5 L9 ]7 M$ S8 w' ?. H5 ?{
+ H% e, ]0 l) Z# O9 a/* post exit function #1 */
) a4 G( I( U$ }* w# Uatexit(exit_fn1); # B5 r7 v7 M" D7 N8 |! R
/* post exit function #2 */
+ M1 E( k9 I) Catexit(exit_fn2);
$ j' Q r, o% `. o- breturn 0; + Q( @+ f1 x% {3 k1 H
}
7 J% S9 l' n% P7 t& a3 a</FONT>, [7 A) C" i6 W/ O4 A, o) T, W' a
& W0 P. G8 K% \/ f0 x6 Q! K
</P>5 e5 x6 U% c2 t+ t7 Q
<P><FONT color=#ff0000>函数名: atof </FONT>5 u! G! Z. {* L0 l# A
功 能: 把字符串转换成浮点数
8 F; ]& q' v, ] L+ M- S e用 法: double atof(const char *nptr);
9 G' {# {& n* [; w程序例: & s5 _$ p$ u$ y- a
<FONT color=#0000ff>#include <STDLIB.H>
: s/ k2 h7 h3 ^8 m0 q4 O#include <STDIO.H></FONT></P>7 b* m; K7 t/ ?. K( p
<P><FONT color=#0000ff>int main(void)
3 N v5 u3 r, c8 D+ X1 @{
+ \1 s% Z6 q% {5 j: R0 c( |3 |float f; * d/ b( u6 x% e& P0 ~7 N
char *str = "12345.67"; </FONT></P>
# h. i6 R. G: R7 R8 y! X0 b<P><FONT color=#0000ff>f = atof(str);
% C3 n t( ^; I* tprintf("string = %s float = %f\n", str, f); * Q Y+ H5 z+ @1 t, I
return 0;
* Q* y7 y* K9 c J3 B} , v+ T$ B1 y1 N2 |+ `
</FONT>
- f: M3 K9 p7 Q- A& F</P>1 e: U9 g. k) I0 S, z
<P><FONT color=#ff0000>函数名: atoi </FONT>
9 \1 c- M. D9 O" q. ]功 能: 把字符串转换成长整型数 & g3 a! U1 M' D$ {! Q
用 法: int atoi(const char *nptr);
& o- t9 v* s# V, \5 N程序例: + }* J3 ^: H+ N% w1 K& B( O
<FONT color=#0000ff>#include <STDLIB.H>
: K- q9 L G3 A#include <STDIO.H></FONT></P>
! N2 \: x( V% e2 i; \<P><FONT color=#0000ff>int main(void) 9 N4 P, K( S/ X/ s* D- ^
{
, R7 t$ Y$ d, X" V; o" lint n;
8 ?9 C. F" {+ Q* {$ fchar *str = "12345.67"; </FONT></P>
$ l% p. u* o& M$ l! Z: D# i- u' I<P><FONT color=#0000ff>n = atoi(str); 4 G( V$ @& I. J9 z
printf("string = %s integer = %d\n", str, n);
5 ~% b& r% p. x( u) f5 s' B% Freturn 0; : l9 O7 W# T" u1 {% S( q; |- V7 C
}
?, ~- ]7 `* U/ Q' b9 j p</FONT>
' l/ \0 p5 ?7 d1 e+ J</P>
* ]% `6 X2 T) A8 F3 a<P><FONT color=#ff0000>函数名: atol </FONT>
A9 [2 j* F+ r& I' w6 O功 能: 把字符串转换成长整型数 * Y: M9 C; o' X+ `! A0 j
用 法: long atol(const char *nptr);
, m M9 E& f4 Q程序例: </P>
. C! M7 L# ^ j$ ?6 l<P><FONT color=#0000ff>#include <STDLIB.H>% D6 C: G( J* G/ Q' V' f
#include <STDIO.H></FONT></P>
8 p0 v$ Q7 e) o% j<P><FONT color=#0000ff>int main(void)
9 X5 p; Z' y- S7 w, P$ [% g3 [{
% i, J3 |0 ]& b; ]3 }long l; : t# H0 U" }; w2 j; i" U6 x% a
char *str = "98765432"; </FONT></P>. p/ t- `# \3 q; A9 [8 f
<P><FONT color=#0000ff>l = atol(lstr);
5 U: G W. d; c3 }; pprintf("string = %s integer = %ld\n", str, l);
1 e0 V; i- F4 N! @return(0);
2 l4 s5 v5 e0 F}</FONT></P> |
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