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不支持自定义 Discuz! 代码
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本帖最后由 cqwj 于 2010-4-18 13:47 编辑 5 I- E$ Z9 G! _& F
& s/ m4 |) e$ i, [3 d7 v7 b指针处怎么写??
1 u( ]) ^$ ?8 |. ^ |我的意思就是说@pointer在模型里面怎么定义?如@pointer(1)=??或 ??=@pointer(1)& ]. ^8 e* P/ z* b/ T
表示什么意思。我个人理解@pointer(1)=??表示把数模变量的值??装进@pointer(1)这个储存单元,外部程序程序可调用此储存单元数据。??=@pointer(1)表示外部数据值??通过DLL传来的数据放进数模变量,这样理解对吗?/ w1 C2 Z+ |) L: x' q
:) sets:
# T9 m; U ^8 _6 M: n; wxinxi:cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k,zys,x,y,z;
, S" T; p8 M6 N0 J3 ~$ Kendsets
8 L) b; ?: r2 I: M7 zdata:
5 L5 [' \$ i u2 Xxinxi,cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k= @file("li_yong.txt")6 q. x* U4 q* E# v
@TEXT()=@status();
y0 |9 G* t6 I( l! wenddata( a( L* y/ C Q, C$ Z3 Z7 ]
[bb] min=@sum(xinxi:sj190*x+sj160*y+sj270*z);
& Y; Z7 n$ _* s; g; `4 `/ a% I& X$ L@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)<=12);
- S, y; E' ^5 @6 |; [@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)>=0);& S& O! i6 t) h
@sum(xinxi:x)=sr190;* e" ~% C! o7 G& C! Y
@sum(xinxi:y)=sr160;
9 G7 ?$ r; g" y p@sum(xinxi:z)=sr270;
- M) D7 a" j7 J, C a9 n@sum(xinxi:x)>=0;
4 f1 N4 \2 g" V8 t' P0 u@sum(xinxi:y)>=0;- g. H2 V2 |' n9 D; ^3 {
@sum(xinxi:z)>=0;6 e( T' ]0 {& h) ]" P
@for(xinxi(i):x(i)<=cl190(i)*sl190(i));
6 t. W5 g! u1 w( g@for(xinxi(i):x(i)>=0);
& ? V1 a" z. r@for(xinxi(i):y(i)<=cl160(i)*sl160(i));2 I x$ r( r- m
@for(xinxi(i):y(i)>=0);
' _; u# W, i8 {' W@for(xinxi(i):z(i)<=cl270(i)*sl270(i));8 S% I, d; i; O+ E2 f0 _6 \
@for(xinxi(i):z(i)>=0);( x6 Z" g' q5 Q+ S/ o( h
@for(xinxi(i):@gin(x(i)));2 }- e" B$ Z# I* u
@for(xinxi(i):@gin(y(i)));! ~: v6 g; r* ?" h: g0 ~1 ?, ~
@for(xinxi(i):@gin(z(i)));
* k! p0 f+ y9 ]. ^0 F4 zmm=@sum(xinxi:k);
; v/ J- _" W! I" d0 M1 P3 ^# jxx=@sum(xinxi:sj190*x+sj160*y+sj270*z)/mm;- ~$ q9 ^8 I/ C% F- N2 l
9 q3 P; q0 g/ J, z$ w@for(xinxi(i):zys(i)=sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i));7 v, k) }! w1 }% R+ g$ n
DATA:5 \5 ?' r+ }3 H! z2 f2 r% B2 Q
@POINTER
4 I C: R9 s% ], f/ X: E
i. R% n% e2 t9 M( O+ }!此处结果想连接VB6.0,却不知道怎么写;
" z/ B& B ~4 d2 M& s( lENDDATA8 y) B$ i' j2 g3 F: y* e
; [: i' O; x$ [4 c5 ?( f- Rend" o w$ J# Y# F8 ^
结果为 主要是想取 X,Y,Z的结果
% }0 j# w4 k' {0 o+ d% A+ k4 Y( I5 _Global optimal solution found.9 f' h# J6 Q, h/ ~/ m* Z t( e" t
Objective value: 0.0000001 C6 z/ Q1 r8 J- @2 f
Extended solver steps: 0* ~8 x2 ~+ q# m7 B1 \
Total solver iterations: 0
* _ u7 }0 J* ~' i% R/ P" S; L9 v
, q" K) _6 }3 p9 L, Q 0
$ {* I& Z2 L/ }# Q% ?7 e! Y$ b) }& \9 `
Variable Value Reduced Cost' [4 g5 a/ o/ d/ k6 L% q4 S6 K$ p
SR190 0.000000 0.000000$ R" G8 s1 l3 Z( T" @9 f
SR160 0.000000 0.000000% n6 P* G& b6 P( W
SR270 0.000000 0.000000
9 d* G! Q4 ~7 R0 M" ^) x MM 2.000000 0.000000
4 i0 T2 H2 W* j. A XX 0.000000 0.000000
( {* U* w u, @/ ]* s CL190( ZHANG) 35.00000 0.000000
8 Q) }0 ?' B0 t' h- j CL190( LI) 35.00000 0.000000
' |8 ], e3 E; ]! W0 S CL160( ZHANG) 30.00000 0.0000009 o1 ]8 ~( ]5 B: `
CL160( LI) 30.00000 0.000000
' C8 }# S( [5 y. k- v CL270( ZHANG) 5.000000 0.000000$ C; a- T3 i4 `8 t1 x" ]
CL270( LI) 5.000000 0.000000' k) B* [# K* m* g$ f3 M6 M& D1 M
GZSJ( ZHANG) 12.00000 0.000000
4 f" s& J: y* B5 Y; H0 U GZSJ( LI) 12.00000 0.000000
$ H6 }/ X. k: U# ` SL190( ZHANG) 0.9000000 0.000000! F; Q" E% p p* `. O9 \, u
SL190( LI) 0.8000000 0.0000001 u! V2 u( H* p) H$ ~+ b# I& h/ v
SL160( ZHANG) 0.9000000 0.000000
/ e7 y& n4 A' a6 ]& K* s6 V SL160( LI) 0.9000000 0.000000
0 h9 }- D; D. ?/ k5 ?6 g. S SL270( ZHANG) 0.8000000 0.0000006 @0 K V3 X8 x4 ]6 v9 K1 k! n3 v7 N
SL270( LI) 0.6000000 0.000000" O$ n0 [ L; p
SJ190( ZHANG) 0.3770000 0.000000# J* |9 A2 M2 x7 t- Z$ P" B
SJ190( LI) 0.4120000 0.000000. L7 ^' L" H2 I: ]
SJ160( ZHANG) 0.4400000 0.000000
% V: Z; x. u+ b9 A& g7 ? SJ160( LI) 0.4400000 0.000000
6 n; L; x3 u1 u- T. G9 j SJ270( ZHANG) 2.880000 0.000000
2 G" v& I) l+ T; z; f$ t# s2 q SJ270( LI) 3.360000 0.000000. Z! s2 G, G0 M$ v9 c
K( ZHANG) 1.000000 0.000000
$ q8 L+ ?0 a& \; g& N/ _& p; Q Q K( LI) 1.000000 0.000000
! T7 K( A) X- B ZYS( ZHANG) 0.000000 0.000000
& D {) m# k/ n/ P) P" W ZYS( LI) 0.000000 0.000000& } u! K: j6 A- d0 J
X( ZHANG) 0.000000 0.37700005 n" G+ F& B8 A% c3 i
X( LI) 0.000000 0.4120000! ^) h7 m( P$ S" V
Y( ZHANG) 0.000000 0.4400000
( O7 m* V- ]1 ]9 h) j6 ]2 I Y( LI) 0.000000 0.4400000, j6 h; T$ _+ i$ ^
Z( ZHANG) 0.000000 2.8800002 B* v+ E. U/ ^" z0 t w$ P& }( x$ L0 O
Z( LI) 0.000000 3.360000 y0 G% |: u9 T& A* b- }8 [8 \
) r" Y8 I# T; Q) o, b3 H. [0 j Row Slack or Surplus Dual Price) y% ^$ N+ Q, G+ F) v
BB 0.000000 -1.000000+ t& f5 Z- d6 ]/ X& ]' ?
2 12.00000 0.000000( E3 e3 E7 P r- C: g! F( V
3 12.00000 0.000000
2 C( j p- c: l2 z, `5 @ 4 0.000000 0.000000
& p4 A/ |2 H* Z 5 0.000000 0.000000; M# ~/ X( { k$ X0 p" r
6 0.000000 0.000000
1 v+ z' o+ y* l4 E/ Q6 S2 x 7 0.000000 0.000000
% ^2 J$ ~/ W8 L 8 0.000000 0.000000: v; t) Q) i3 r& A1 W! ^
9 0.000000 0.000000! `+ `+ [$ @. |' s! S
10 0.000000 0.000000) V% h. w$ T- A
11 0.000000 0.000000
, x$ Q2 T" @4 [! q' e) P( ^ 12 31.50000 0.000000& s; [- `6 o6 Z E; J
13 28.00000 0.0000002 [, X- q0 U2 E) s$ u. I% G- H
14 0.000000 0.000000# ]# V0 q. Q c$ |
15 0.000000 0.000000, e0 L" W6 S$ W' I) w) Q
16 27.00000 0.000000
# r# i4 m/ N+ ?8 l- s% [2 h' l 17 27.00000 0.0000007 t, F6 n& t& M8 \( R. y7 B( c
18 0.000000 0.000000
) [& B/ O' r W8 z# [ 19 0.000000 0.000000
" y4 _) m: f. Q 20 4.000000 0.000000% f+ V! c( `4 e0 D) j& a
21 3.000000 0.000000' H' p1 m2 h9 Z# p$ c8 O4 h
22 0.000000 0.000000
% y, u6 K% @( R( J* a 23 0.000000 0.000000& T6 r( j0 r# I
24 0.000000 0.000000' `& u( C3 P, h+ f1 t5 S/ j
25 0.000000 0.000000
( w4 P+ n, \! O. n 26 0.000000 0.000000& F. P& c4 O% M. |; X; z* D3 F1 m
27 0.000000 0.000000 |
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