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不支持自定义 Discuz! 代码
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本帖最后由 cqwj 于 2010-4-18 13:47 编辑
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+ N( P$ }: _7 M3 X( {+ K指针处怎么写??! \% M* c4 e) _: T. N1 L
我的意思就是说@pointer在模型里面怎么定义?如@pointer(1)=??或 ??=@pointer(1)3 E2 i# W4 m! Y
表示什么意思。我个人理解@pointer(1)=??表示把数模变量的值??装进@pointer(1)这个储存单元,外部程序程序可调用此储存单元数据。??=@pointer(1)表示外部数据值??通过DLL传来的数据放进数模变量,这样理解对吗?
6 l& W3 E5 P7 J! e% E5 `:) sets: Q- C( ~/ V4 h
xinxi:cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k,zys,x,y,z;
- [3 `% X9 E5 ?; @endsets
, U, w3 M# L! O; b& z' _+ u" odata:
- Z. \ i5 A, H2 {& x# Ixinxi,cl190,cl160,cl270,gzsj,sl190,sl160,sl270,sj190,sj160,sj270,k= @file("li_yong.txt")6 E' F: d( I, b' A* I) R
@TEXT()=@status();1 w6 O7 X6 P& ?& p
enddata
, r2 d. M3 n% {% T7 {* z/ B/ x" E3 ?[bb] min=@sum(xinxi:sj190*x+sj160*y+sj270*z);
% A5 P# p2 z: i0 `' H) {@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)<=12);, _+ R3 a! X) A* R( F8 i
@for(xinxi(i):sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i)>=0);
4 b# [5 t" r/ f5 w4 u# ~@sum(xinxi:x)=sr190;
8 N1 }" W5 |4 q@sum(xinxi:y)=sr160;
& z" h& e1 v- L8 a& z! h( x@sum(xinxi:z)=sr270;
8 y! p) {0 J0 K1 {6 M@sum(xinxi:x)>=0;3 A6 i4 h. [. _" i& g
@sum(xinxi:y)>=0;
+ @: _8 i4 q' l1 U; X9 R; P@sum(xinxi:z)>=0;! ]' M) p% }! }2 K% G
@for(xinxi(i):x(i)<=cl190(i)*sl190(i)); h6 p: ~/ V- C! U7 g& V
@for(xinxi(i):x(i)>=0);
1 J; M) u/ m5 e4 t+ G@for(xinxi(i):y(i)<=cl160(i)*sl160(i));
+ z* L' v4 g3 c5 F@for(xinxi(i):y(i)>=0);
' r+ W- M( {& Q- O$ I6 L3 A@for(xinxi(i):z(i)<=cl270(i)*sl270(i));
6 k* G1 k1 e$ s@for(xinxi(i):z(i)>=0);
0 S" g1 Q3 Z5 j W@for(xinxi(i):@gin(x(i)));
& F b9 B( Y; e) K! M@for(xinxi(i):@gin(y(i)));$ m6 v h! l6 M+ \- x0 @8 T
@for(xinxi(i):@gin(z(i)));% ~- R- F' J: z) v
mm=@sum(xinxi:k);
2 S3 R5 m: L: U7 k4 N& Qxx=@sum(xinxi:sj190*x+sj160*y+sj270*z)/mm;
* A$ e0 B2 d( R6 ?$ O( I9 v. R, G2 C
Q5 P- J. k n@for(xinxi(i):zys(i)=sj190(i)*x(i)+sj160(i)*y(i)+sj270(i)*z(i));! B" o9 W; a8 J, ~0 P5 p
DATA:1 Z$ U' U7 B1 U+ }0 [( P
@POINTER" Z2 w4 N' }0 P" c9 y
8 j4 \. _ i" y7 y; ^5 `!此处结果想连接VB6.0,却不知道怎么写;
9 z _1 A. J& y4 uENDDATA$ }% a+ T! o* G2 n5 \1 x' B' i$ m
6 I/ z! A7 a: s+ d9 oend, i5 @+ t* F$ _* S" D
结果为 主要是想取 X,Y,Z的结果% ^* U4 R' g' L/ s
Global optimal solution found.
& Y' M& ~0 F7 J4 ^6 P Objective value: 0.000000' a# S' K' k9 b# i9 I
Extended solver steps: 0
1 j I: S a3 S; Q Total solver iterations: 0
! E' a. L. x: I; w/ s# @1 a0 A7 P3 E% w+ X* \5 u) f( n
) `7 p5 \# S" x 0# P+ b0 E& [# F! ~# Q
3 i/ I0 f" B6 }( x3 S, F$ c; h
Variable Value Reduced Cost$ z, a* F% K3 p8 _; i* A! x0 s( Z x/ E
SR190 0.000000 0.0000000 B4 y7 k( e, s) {6 w
SR160 0.000000 0.000000
1 d( |0 g! X$ s! f* p; J SR270 0.000000 0.0000008 o& r2 H' ~6 W0 v- t
MM 2.000000 0.000000
" D2 {/ W8 |8 S- b/ D XX 0.000000 0.000000! h) Y, @/ ]& D; k, Y* `
CL190( ZHANG) 35.00000 0.000000
. Z h2 ?2 @/ Y L! |/ Y3 e3 d CL190( LI) 35.00000 0.000000
9 f4 b& Z+ D3 T CL160( ZHANG) 30.00000 0.0000001 g; W) m* b6 O
CL160( LI) 30.00000 0.000000" f$ k0 o0 v1 {& A2 Q
CL270( ZHANG) 5.000000 0.000000
0 W/ {1 F6 c m. R4 t/ `* e6 [ CL270( LI) 5.000000 0.0000006 h; a- F+ m& Q( R1 C
GZSJ( ZHANG) 12.00000 0.000000# C! ^' V" r9 H" ]2 o& G
GZSJ( LI) 12.00000 0.000000: ^) w* y+ m) h& V1 T2 J, L
SL190( ZHANG) 0.9000000 0.000000
) M7 v5 S; W3 p s) s1 `% | SL190( LI) 0.8000000 0.000000
: ?; U; z- @# }7 k" p4 R6 X SL160( ZHANG) 0.9000000 0.000000 j- M7 h7 j# ?2 D2 Q* X8 f
SL160( LI) 0.9000000 0.0000002 _/ x1 W3 `4 F
SL270( ZHANG) 0.8000000 0.000000
" `* i; s( Y" P) z SL270( LI) 0.6000000 0.000000
5 n8 c+ h) ?& h SJ190( ZHANG) 0.3770000 0.000000
. f# u. P9 a) X8 I+ O SJ190( LI) 0.4120000 0.000000
& r& a# V( z |# [ SJ160( ZHANG) 0.4400000 0.000000
6 Z2 W# R, C H1 t( S' f" t* e9 b4 ? SJ160( LI) 0.4400000 0.000000% ^9 n/ d9 X! b2 U% A2 q- R2 v
SJ270( ZHANG) 2.880000 0.000000& C6 r+ B+ K( u. E! q
SJ270( LI) 3.360000 0.000000
* G& U# k; t" I7 m' `, a: k! t" { K( ZHANG) 1.000000 0.0000009 x2 f4 T4 C% T1 I
K( LI) 1.000000 0.000000
" |9 m. C7 m& S$ W ZYS( ZHANG) 0.000000 0.000000
/ ~6 |& b2 |% T: G& c* ^ ZYS( LI) 0.000000 0.000000! s- I& z& N7 T2 F" s0 {
X( ZHANG) 0.000000 0.37700005 S A. t# G+ v' v
X( LI) 0.000000 0.4120000% O \- L8 ~7 ~& C
Y( ZHANG) 0.000000 0.4400000" ]" g6 M& n" S2 j2 O- ~( x) b
Y( LI) 0.000000 0.4400000
T$ _( h* Z* n Z( ZHANG) 0.000000 2.880000
* v6 d7 q6 M6 u0 k! f, [% j Z( LI) 0.000000 3.360000
0 _$ F0 n: w8 F' ~0 B* n3 u
% e' H- ^' E: q- P. n1 s Row Slack or Surplus Dual Price
: _6 j3 ?- |) @( l BB 0.000000 -1.000000
; ?& F% y, }' {9 S A+ F 2 12.00000 0.000000$ Y9 i) S* n' ^, J
3 12.00000 0.000000. g) N! Y* K9 H! L' |# G
4 0.000000 0.000000! ]4 V6 c) v- D( U# F8 R0 Z6 n
5 0.000000 0.000000- |, J3 {- Y6 A+ ]2 b8 ~3 f
6 0.000000 0.000000; X: B9 D8 K6 O1 x: I
7 0.000000 0.000000
) c1 X1 u0 X K 8 0.000000 0.000000% x0 D( r2 C0 D! [7 k4 i/ x8 t- W
9 0.000000 0.000000
7 t% {3 {# [3 G& `" @; B! x 10 0.000000 0.000000
6 ?3 h- t6 X2 |: A 11 0.000000 0.000000+ G: }9 i3 U7 c8 `% `( J" C
12 31.50000 0.0000009 K7 s/ ^2 b' J3 B# \: n
13 28.00000 0.000000% k. N7 C4 J- g6 f
14 0.000000 0.000000
; T- E7 n6 p# f& d/ Z 15 0.000000 0.000000
8 A% n0 ?# U1 Q& ~2 w x9 _ 16 27.00000 0.000000; b7 N% V& w! B% T
17 27.00000 0.000000$ z# {- E+ j# O4 w* x7 L R
18 0.000000 0.000000
7 k2 d$ e- e! K' Y, h% v0 U t0 k 19 0.000000 0.000000
; j1 z p* I2 J: ^ 20 4.000000 0.000000
/ \- {2 W; {. g! G 21 3.000000 0.000000: n* T D0 R6 m( f9 j: P
22 0.000000 0.0000003 B) U( _( Q% b+ ` t# z
23 0.000000 0.0000002 y; \8 K+ X5 H5 J6 @1 e6 D: T0 \/ m
24 0.000000 0.000000: b0 s8 u+ G" ^) D3 m
25 0.000000 0.0000002 ~! N- u. a- a% r
26 0.000000 0.000000
f% P5 `/ H. r& F: K& d6 u$ _ 27 0.000000 0.000000 |
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