程序如下,错误处已用红色标出,请问各位怎样改正,谢谢!! ( p# h) `+ W4 S7 z9 p1 p& b, F " x5 j/ K0 E, z7 t1 {. J4 T cclear all; # L. C+ |3 B4 dclose all; 6 T( c7 l( b5 C; {! F% G3 ~# P/ }5 u$ Da=59.36;b=7.42;m=2374.46;n=296.92; 6 _3 O; ?' ~- W7 H4 n' S Ats=0.001; & g% Y3 }3 ]6 `A1=[0,0,1,0;0,0,0,1;a,-b,0,0;b,-a,0,0]; w" u1 A. t3 q" ?% k
B1=[0,0;0,0;m,-n;n,-m];7 p, v. U/ G! A2 l! J
C1=[1,0,0,0]; 7 g5 N, y: [/ F2 R9 F& j/ JD1=[0,0];, z+ x7 a8 s- g
[A,B,C,D]=c2dm(A1,B1,C1,D1,ts,'z'); * s% g% F9 i _7 }2 m7 sx=[0;0;0;0];6 c+ h3 B1 W# D# r+ e; ]
r_1=0;r_2=0;g_1=0;g_2=0; 3 Z4 l8 ^. n' E. {) {( Nc1=5.0;c2=5.0;! `9 ]. L0 K- D E+ o0 ^5 p
eq=5;) f6 M2 k, Z3 N6 N
q=30;- i2 } G6 w) j4 t
Ce=[c1,0,1,0;0,c2,0,1];" Q* x( f" G3 k) d! [
for k=1:1:2000 + t3 [+ r, Q/ g% C# X4 c- Qtime(k)=k*ts;/ o( ?6 g, e9 m! N4 q; W- ?( k
r(k)=1.0;9 t. J0 `3 K' g$ D. S: W8 V$ n' k
g(k)=1.0; R4 [* b$ ]+ D F& j( u' A \; r 2 G9 T+ ?6 ^0 k4 I9 W
%Using Waitui method 6 N2 U8 P( y p' x" `
dr(k)=(r(k)-r_1)/ts;, j! Y% q5 n: f9 ^. K) P
dg(k)=(g(k)-g_1)/ts; 2 A1 {, r4 ]0 @; G' [; \ dr_1=(r_1-r_2)/ts; 7 x. f$ P$ z- b( `% _ dg_1=(g_1-g_2)/ts;$ ?3 q- h0 a+ r ?
r1(k)=2*r(k)-r_1;+ D% r) |/ K# z- l. ?( N6 T- }
g1(k)=2*g(k)-g_1; + P5 ^6 { J# h" f" F( \: y. c$ j8 w dr1(k)=2*dr(k)-dr_1; 5 g- v( z, F( t& i1 u' M0 D- s dg1(k)=2*dg(k)-dg_1; 1 N, o3 C9 y8 H, O: t 7 ]0 U) d' ?/ s' S! G1 b$ D
R=[r(k);g(k);dr(k);dg(k)];& t' o! T4 ^1 D! \+ \ S
R1=[r1(k);g1(k);dr1(k);dg1(k)];: W5 S1 r! _/ b7 ~( p+ B
1 \* |4 v: i5 H! i* {) e
E=R-x; ! v" b; i9 N8 k/ P ? e(k)=E(1);. c# y% w/ ^1 Y5 E c( G$ @
de(k)=E(2); . l% V' Z1 D: g+ @* m( j ) {& M' P+ y8 C. @
s(k)=Ce*E; : Z N$ U- N+ |- i
X1=abs(e(k))+abs(de(k)); 8 X _' s0 l% Q 2 _1 _" b! g5 I5 c0 h) h2 aM=3; 7 O+ u! m4 S1 dif M==1 %EXP reaching law L3 C; h/ S& u ds(k)=-eq*ts*sign(s(k))-q*ts*s(k);! c0 e3 b$ x! }
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));3 I/ v h: ?7 b; I% d% R
elseif M==2 %Variable rate reachine law ) l* J6 B0 ~) g" v& p; F# W0 J1 x4 F ds(k)=-eq*ts*X1*sign(s(k));/ `; x. Q0 T' d; C/ v
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k)); 7 b; f. B) z1 \$ }, _2 Ielseif M==3 %Coposite reaching law 9 K# a2 _5 ]1 a' c0 t3 @. B k0=0.60; 4 T; p* {6 B2 m4 W& i7 C if X1>k0 %EXP reachine law ; Q. i- C9 i; _+ b ds(k)=-eq*ts*sign(s(k))-q*ts*s(k);& w c# f% y8 y: H# o) o8 Q5 o
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k)); 3 `6 [; p) H& F/ i5 j3 d' k2 } elseif X1<=k0 %Variable rate reachine law 6 E% a: I* K5 ^( e1 F0 \ ds(k)=-eq*ts*X1*sign(s(k));0 d# m8 @" k/ W& v$ Z+ _' e
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k)); / F9 B6 x$ t, ]" Z4 ]0 _7 n end - I: t0 P' r' x" l) b- ]end/ U; `" r3 o, g+ ?
if u(k)>=10: d2 m* u& |; }
u(k)=10;& t5 C/ v8 q& D1 C. n7 R
end. R8 X x$ Y. E
if u(k)<=-103 S! E# `( m F4 h- B! ^5 J
u(k)=-10;9 b2 D8 n5 ^* X2 x
end2 T" q0 P, O; S6 N" U
x=A*x+B*u(k); : j, I4 O5 G9 wy(k)=x(1);! C4 C. ?4 d6 N8 P
%Update Parameters# }/ O2 a1 x$ L6 q m7 P' t' n) `
r_2=r_1; . n. o7 M0 d2 j/ T; F9 M0 [8 {r_1=r(k); ; W3 F3 b, ?, Z! }end( i$ O1 E) l" T% p4 M6 y
figure(1) % @9 Y1 C" j4 @2 [$ H9 u) P5 x& ^plot(time,r,'r',time,y,'b'); + {7 {9 h2 K9 w* Txlabel('Time(second)');ylabel('Position tracking');5 N1 a% r6 _6 d4 Z5 }
figure(2)! w0 S% ]7 `, k0 d+ I
plot(time,s,'r');) A3 H- M \! }5 c- d, ~% e. T+ x
xlabel('Time(second)');ylabel('Switch function s');6 I8 d# J9 u V$ N
figure(3)6 V. X# T; E$ { q: Y3 R5 ~
plot(e,de,'r',e,-c*e,'b');7 m% X1 A+ s( W; ]2 r/ p) ]
axis([0,0.001,-0.01,0]);% R" v$ y! l6 B/ K4 I6 D- Z) F
xlabel('e');ylabel('de'); 2 `7 Y" @& g+ E. ]9 U1 \figure(4) a+ p2 }( t& [0 A4 C$ q
plot(time,u,'r');5 Z! a: O+ t' K1 S( p: ]' z
xlabel('Time(second)');ylabel('u');, ?/ z- D) ?* Z" ]0 u5 h0 a
6 L. t1 G( H: B- W; h( H0 ^??? In an assignment A(I) = B, the number of elements in B and # a. C% g0 x$ H. m/ rI must be the same.0 l I* }( }; p% W. z
Error in ==> matlab02 at 40& `. K$ n R9 ?& Y6 [
s(k)=Ce*E;