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智慧的蓝色小毛驴
TA的每日心情 | 开心 2011-12-5 23:03 |
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签到天数: 106 天 [LV.6]常住居民II
- 自我介绍
- 200 字节以内
不支持自定义 Discuz! 代码
 |
程序如下,错误处已用红色标出,请问各位怎样改正,谢谢!!" a/ }1 p+ } R; Y! L4 O# ?$ X
6 f4 X4 N3 E& C
clear all;, @; T; l4 Q) o0 o
close all;0 P* E2 e4 M1 Q2 a- Q+ X% {2 c
a=59.36;b=7.42;m=2374.46;n=296.92;
# Q+ U$ Z f0 e, g; L' N7 Ots=0.001;* U+ W( ~* R1 z+ x9 l& J! A$ c
A1=[0,0,1,0;0,0,0,1;a,-b,0,0;b,-a,0,0];/ s( V0 q* D8 |1 u2 B) E3 `9 M* z
B1=[0,0;0,0;m,-n;n,-m];- I. c1 ] ]8 ~5 V: J
C1=[1,0,0,0];$ |7 j/ T7 j" s
D1=[0,0];- ]8 d4 u4 Q% O
[A,B,C,D]=c2dm(A1,B1,C1,D1,ts,'z');
) H/ ^- E/ a6 d! Z* ^3 tx=[0;0;0;0];1 ~8 [ i7 f7 b+ _6 {
r_1=0;r_2=0;g_1=0;g_2=0;
+ v; P7 C2 t x% q' Pc1=5.0;c2=5.0;; J1 P! U- v) u, s' |
eq=5;& T1 g# \$ D8 u( [" Q6 T
q=30;6 \! ?: e' |# H3 Y3 {4 P
Ce=[c1,0,1,0;0,c2,0,1];& N. e- I, S0 H# W) F# p$ K, B
for k=1:1:2000* M: e; ?1 d4 U2 X
time(k)=k*ts;
; k& S7 l7 ?: u r(k)=1.0;
4 h& y/ [: \1 R; q" i Q g(k)=1.0;
" ?% L+ Z1 _6 k
0 L9 y# f" T# B) D6 w8 ~ %Using Waitui method
7 s+ Z: z/ L, L1 a- o& i# n dr(k)=(r(k)-r_1)/ts;* v! d/ d8 f8 P6 r' S B
dg(k)=(g(k)-g_1)/ts;5 t/ d3 i3 |9 M8 @+ V6 H
dr_1=(r_1-r_2)/ts;4 h4 m* ?$ r$ ]6 P
dg_1=(g_1-g_2)/ts;, D* W( G: K$ [" y5 A( E! D3 m
r1(k)=2*r(k)-r_1;
# @0 j$ z. d! j5 ~5 h; n g1(k)=2*g(k)-g_1;
4 w3 {' s7 v1 n% r; R/ V dr1(k)=2*dr(k)-dr_1;
& d6 \& S e2 F, A0 _3 l0 y0 S+ P dg1(k)=2*dg(k)-dg_1;' o' t( o9 {+ R7 r' j+ E6 `6 r
0 ^+ \+ ]0 x' I; L' P/ {5 K
R=[r(k);g(k);dr(k);dg(k)];
! d. R! l' ~6 [2 S$ e R1=[r1(k);g1(k);dr1(k);dg1(k)];
: `4 m4 {- p& |/ s S5 b4 p N 7 l: E0 S6 G5 d
E=R-x;4 p$ [; n$ D0 H9 s+ v
e(k)=E(1);
( c* H6 }( N7 w' R de(k)=E(2);
' f4 F8 ?/ }. A4 U$ c# l
& q+ z$ o% p5 m2 V; p' R' z1 z0 r* U$ w s(k)=Ce*E;
; S( p1 P4 _8 ^% w4 { X1=abs(e(k))+abs(de(k));
8 A9 r3 D6 y, }6 P% e' P * |8 e( M% o4 K3 Q; @5 h
M=3;
! Y8 ]. u9 g: |7 J/ j- o- Oif M==1 %EXP reaching law
. L# V# F" R9 |: D: e ds(k)=-eq*ts*sign(s(k))-q*ts*s(k);
( P; `: {4 m6 s2 E; b3 s u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));$ t6 ~: u0 p2 Y6 q& W2 g+ ^) K
elseif M==2 %Variable rate reachine law
) b$ R$ j9 H# L0 K/ G ds(k)=-eq*ts*X1*sign(s(k));; E$ u' j K2 i b# y
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));3 F/ K: x, |" E3 U, U; |
elseif M==3 %Coposite reaching law& c$ y7 c7 y- \2 X& W
k0=0.60;
# g! f/ z2 X% ? if X1>k0 %EXP reachine law1 h$ ^- W3 T# z3 p
ds(k)=-eq*ts*sign(s(k))-q*ts*s(k);- Q [% ]) J. P" `
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));
/ ~* m4 A$ V% q+ L8 J# Y elseif X1<=k0 %Variable rate reachine law
+ c& z" B9 e! D! |; y ds(k)=-eq*ts*X1*sign(s(k));
: s ] E; I) p+ X3 D! U4 z/ S! Y4 q* } u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));
, g# p+ O! P8 f7 k9 v end
0 Y& a# F6 P8 \3 i/ Jend
; U% Z% l6 i: ?' i* cif u(k)>=100 T1 O! X+ c9 q, }
u(k)=10;- e5 J2 b! f% U) g" A9 r
end0 N: q7 i3 I- P, C' ^8 \) H/ @
if u(k)<=-10
* y' L/ S3 {/ Y6 f; u" W) L u(k)=-10;
2 R* i4 y, a* F8 U) M3 H5 Uend1 p# G( K' s' ?' t. Q) S- c" I9 Z
x=A*x+B*u(k);
& R& x- ?) k) G3 w" {1 Z3 by(k)=x(1);8 ~& ~6 m! q5 R( T+ t( `0 ^( t
%Update Parameters
" m& h6 |9 d6 k |7 Xr_2=r_1;
& E" {9 K; i6 q8 e' [r_1=r(k);
5 g" N) d; [( t4 \, d$ Wend
/ _4 S- A3 b4 P, ?figure(1)
2 X; n: x3 v. {: b3 Nplot(time,r,'r',time,y,'b');! j2 `+ J, c% N7 {8 Q* C
xlabel('Time(second)');ylabel('Position tracking');
- s6 [) l$ `( h2 Cfigure(2)
( a9 }5 G! E3 l# g/ w4 K x/ r5 hplot(time,s,'r');
% ]& ~/ ~% i; \6 xxlabel('Time(second)');ylabel('Switch function s');
) p! `0 r% D" Xfigure(3)
* w6 X! b2 }1 L$ ^( C: K! Zplot(e,de,'r',e,-c*e,'b');
& t1 {7 c [1 a& g9 N6 n/ _axis([0,0.001,-0.01,0]);
/ U8 U, f3 E1 ^1 h/ |5 exlabel('e');ylabel('de');
c. X% k& c2 }, mfigure(4)
- M, u$ Y0 M, Hplot(time,u,'r');9 e7 N* X( ^! r( \7 K0 n
xlabel('Time(second)');ylabel('u');
" _. z$ H$ G8 J! V) T9 e5 h3 d$ z" l; C1 X
??? In an assignment A(I) = B, the number of elements in B and0 x5 c( N+ i- u7 x2 L
I must be the same.
) |8 L1 L6 y2 U! |6 l7 nError in ==> matlab02 at 40/ B& t, e4 ~7 l3 E3 k" q
s(k)=Ce*E; |
zan
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