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智慧的蓝色小毛驴
TA的每日心情 | 开心 2011-12-5 23:03 |
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签到天数: 106 天 [LV.6]常住居民II
- 自我介绍
- 200 字节以内
不支持自定义 Discuz! 代码
 |
程序如下,错误处已用红色标出,请问各位怎样改正,谢谢!!8 L, S& F% c( d
$ {; A" H4 |: U! d/ W
clear all;
, j( Q$ i) i% b. _( z$ r- _8 \2 {close all;& S& l! s. L3 Q" r
a=59.36;b=7.42;m=2374.46;n=296.92;8 t! d; o7 I+ o v d" F
ts=0.001;
% T- ?, c+ z. v2 }9 C! \8 jA1=[0,0,1,0;0,0,0,1;a,-b,0,0;b,-a,0,0]; o" l4 E ]' L. r9 Y% P/ N5 y
B1=[0,0;0,0;m,-n;n,-m];( {+ } ?/ {, v" z
C1=[1,0,0,0];( a3 |' {5 V4 ~8 f& {
D1=[0,0];4 b% x8 }+ _% f ` G+ T
[A,B,C,D]=c2dm(A1,B1,C1,D1,ts,'z');
' t1 i; {6 h3 e* k' m9 Y6 c) ]2 Ax=[0;0;0;0];) z1 x2 I, {( [; X+ B$ ^0 k6 A) ~, n
r_1=0;r_2=0;g_1=0;g_2=0;" G2 X' ?8 `' \" c+ p
c1=5.0;c2=5.0;7 e. r- l- Q+ E4 M& V
eq=5;
# a- r: a( @' O' R) ^" v+ @# Eq=30;
" q7 G% g4 k# v% ?* oCe=[c1,0,1,0;0,c2,0,1];/ z5 t4 ]' ]! R8 R; Z
for k=1:1:2000
8 B! I7 d: S9 N' K1 R- B f rtime(k)=k*ts;' [1 r& p, B% I* q( Q- f( Q
r(k)=1.0;; J' {6 v8 A/ g# L3 L1 ?
g(k)=1.0;, x0 a8 ?, C! X! ]6 q
- q5 C( p# m7 o& s& @1 i
%Using Waitui method 9 m/ o: { t- B
dr(k)=(r(k)-r_1)/ts;
* b. s0 [( Z; d+ J7 v dg(k)=(g(k)-g_1)/ts;
6 g, Z ]: ~) F% K- S$ P# j( G) Y dr_1=(r_1-r_2)/ts;
4 A% ]& j2 E p dg_1=(g_1-g_2)/ts;
, }% V! A3 W" ?2 v! ]" o- C r1(k)=2*r(k)-r_1;
, @# W4 z+ Y7 w; u. ~% B1 J g1(k)=2*g(k)-g_1;- y% N" R0 D; X3 w" F
dr1(k)=2*dr(k)-dr_1;
0 \& }# i' t3 B( A* n. S dg1(k)=2*dg(k)-dg_1;, ^. r4 u, V( I$ f' v/ z
7 y; Z: s0 ?/ g9 |9 `9 a R=[r(k);g(k);dr(k);dg(k)];
4 `/ c7 M: s/ W7 g" X6 r) W) z. P% s6 T R1=[r1(k);g1(k);dr1(k);dg1(k)];* s6 v. p2 k6 X: [
- _" W. _, s5 O% ] E=R-x;4 a7 p! Y' }. H( B
e(k)=E(1);, F# k- j2 @& L& X# _- W
de(k)=E(2);5 ?) a8 ?, }$ Z. E% {+ K
8 M7 Q3 A! K$ c1 \$ C2 _ I0 w
s(k)=Ce*E; - c; Q0 |0 z* f K5 r1 J
X1=abs(e(k))+abs(de(k));3 x' `- G |2 V- Q. I0 D) ]
" j2 q" f6 }" H9 z8 R# I1 xM=3;
1 _+ Z: K+ U: U' C# Iif M==1 %EXP reaching law
2 [, t5 G0 d% d2 P+ x$ w2 N& A' W ds(k)=-eq*ts*sign(s(k))-q*ts*s(k);
/ W+ m2 `8 ?6 z; J3 U- \ u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));" r; \3 M) c; T4 R5 D
elseif M==2 %Variable rate reachine law
9 C( P; B y, s8 L ds(k)=-eq*ts*X1*sign(s(k));7 @9 b- Q3 E( H: O
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));! e8 D, h& q. }2 H" I5 y
elseif M==3 %Coposite reaching law
6 g9 q0 @! W: o2 S0 f/ F k0=0.60;& h1 J8 W5 r7 j% I+ _
if X1>k0 %EXP reachine law7 A5 M0 c" B3 ~6 q# K3 o$ y9 p
ds(k)=-eq*ts*sign(s(k))-q*ts*s(k);% o; R6 Y3 S: u/ [8 I5 r
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));3 e1 s! _. y8 u+ x3 S
elseif X1<=k0 %Variable rate reachine law0 S! P: ?* g( X8 Z) q$ U) ^
ds(k)=-eq*ts*X1*sign(s(k));! |% O" c" q/ m+ n8 P' p$ z
u(k)=inv(Ce*B)*(Ce*R1-Ce*A*x-s(k)-ds(k));
* Z! q# T/ q+ r% P4 r2 E end$ g+ `7 ~3 i( g9 y* C' {5 ^
end
( @) D4 K/ h/ mif u(k)>=10 @/ _& c% K9 v2 w+ s; j: Y
u(k)=10;
* P' D/ {+ `$ T- G( qend
$ N f$ t* ^# B2 kif u(k)<=-10
# U6 L. t2 H* n u(k)=-10;
' Z$ M. l, {, K, _5 Vend: }! I6 f! d' J+ @# \
x=A*x+B*u(k);
6 g& E. U* ]3 [" M: iy(k)=x(1);# I# ~: R3 W! | Y
%Update Parameters
/ N+ Q% _3 s; m& r0 t fr_2=r_1;1 ]+ @0 K! {+ `; s
r_1=r(k);7 \: M2 ^6 |& a' k% [
end
0 o% l1 O( {9 K2 }, hfigure(1)
+ ~, v* H6 f- g9 z) Vplot(time,r,'r',time,y,'b');
8 }8 V: {6 M! `. l6 d8 wxlabel('Time(second)');ylabel('Position tracking');
. i- h/ T7 G) I0 \3 C9 Q ?! s: Afigure(2)
. p* }6 w1 {- V7 tplot(time,s,'r');
' v \2 M9 M! j6 `; H* \8 Fxlabel('Time(second)');ylabel('Switch function s');- R; z. `% k! Q/ V) J" k; K
figure(3)
8 s1 B2 p- W1 D/ [plot(e,de,'r',e,-c*e,'b');! x- F% B9 @ ^- o# q/ s
axis([0,0.001,-0.01,0]);
4 G) ~. \2 v) H) S5 r T0 lxlabel('e');ylabel('de');
9 ~ z* |, t1 v$ M6 w+ w2 @- d+ Cfigure(4)
4 a# ^" Z( r3 C! {1 @* g( B' Aplot(time,u,'r');
9 a5 q9 X& f' O7 N4 I7 Nxlabel('Time(second)');ylabel('u');: O, m$ o5 D! N; A
& N9 ~) s @6 B) D! M
??? In an assignment A(I) = B, the number of elements in B and
1 \& L- s3 ~8 e& q A! O8 L/ f! M1 }I must be the same.
0 ?, b$ R4 A* z& J& ?7 NError in ==> matlab02 at 40
5 L; R0 ?: ]2 j7 h* l4 j s(k)=Ce*E; |
zan
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