贴上本人自己写的模拟退火算法的源代码,开发环境 Visual Basic.net 2005 V8 ~ @8 p% s/ X2 F" F1 |
觉得有用的给个回复,拉拉人气..
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5 j; H) ~1 M+ h( CPublic Class CSA* `" c5 F! ?) O( k) h
( O5 ]; n) _; L$ t( U/ ?# Q" H1 a Public Function obFun(ByVal x As Double) As Double
% F# t' |) p" l4 ] p. n3 |! m Return 2 * Math.Pow(x, 2) - x - 1
/ N, |% o+ F0 L* u6 W; y+ w1 u End Function
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''' <summary>! \/ ~0 Z3 g9 i7 F- v
''' 传统的模拟退火算法
" z& a4 G6 u, v7 i' ^4 Z ''' </summary>
4 u; T: g$ i) q9 h1 {0 i ''' <param name="Ux ">参数的取值范围上限</param>$ o2 p* ~, x' m/ S5 x
''' <param name="Lx ">参数的取值范围下限</param>
- [' a- _1 P2 v/ _, ^ ''' <returns></returns>5 k1 R* H, [8 i! \; e
''' <remarks></remarks>
% S6 H( s( Z. O+ D P Public Function CSA(ByVal Ux As Double, ByVal Lx As Double) As Double
6 E. ]" [9 [. m$ V5 U- q+ s$ h Dim init_temperature As Double, total_numk As Double, step_size As Double '定义初始温度,温度k时循环总次数,步长
) U% `( g, S( b4 E! Y Dim x As Double, receivnum As Double '定义变量当前值,前一个值,内循环的接受数据 c/ w1 ~# f* P
% Y# ?: a" \+ ? '初始化SA参数
" w( w T k( y Y, E; M; r init_temperature = 0.01
5 J" }- I, O) B total_numk = 10005 S% E9 M" g- `
step_size = 0.001" P# A' ?$ X' c4 U; h
receivnum = 50
7 ^5 @" \7 ?# _ x = (Lx - Ux) * Rnd() + Ux '随机产生变量x
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Dim k As Integer = 0 '温度下降次数控制变量
- |4 x, b; U6 k2 w; m4 O; | Dim temperature_k As Double = init_temperature '定义第k次温度 H1 n0 d; ~4 W% A8 c+ ]$ V% M% K
Dim best_x As Double" l2 V( u8 n1 ^& {8 `$ A! i8 }" m
Dim de As Double = 0.0
% p0 O7 P1 I# O% m- T1 I% O* v. r4 _ Dim fcur As Double = 0.0
' I! ?, u+ g7 N: z8 Y Dim xi As Double
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4 ]8 J, T% q. [3 W- G9 O Dim fprevs As Double = obFun(x)
7 e) \ I# J4 r5 a, M8 N ]& z9 X Dim xprevs As Double = x, P+ B- K y" E" Q
'SA算法核心
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'xprevs = x '保留前一个变量值0 B& G q) L; k* g% e
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'以下三个参数用于估算接受概率
7 D6 V0 j4 j: }5 _ Dim rec_num As Integer = 0 '接受次数计数器0 T& c% b! j3 I0 Y3 I9 f! r
Dim temp_i As Double = 0 '记录下面for循环的循环次数* M3 f# t' v b( i; z
Dim temp_num = 0 '记录fxi<fx的次数
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9 D& j( ] L) V3 z: p* E9 n For i As Integer = 1 To total_numk, e$ X- h+ A7 I9 j9 i3 b
'产生满足要求的下一个数
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xi = x + (2 * Rnd() - 1) * step_size% j! y9 U: T" a V) A# w# q/ Z
Loop While (xi > Ux Or xi < Lx)
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fcur = obFun(xi)
7 Q4 r4 ?8 W9 P% x1 ?& S* @4 R de = fcur - fprevs
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+ g& }- A! i3 x- J& B If de < 0 Then '函数值小的直接进入下次迭代& g! C% o" u+ a4 n) j9 n7 ^
best_x = xi; M, g5 H: P. o% I: J8 I6 j
x = xi& U' i; I3 G/ n$ z+ b, G
rec_num += 1
! ^8 E$ {5 ^1 O x/ q temp_num += 1
) `# ~; V7 y ]7 T fprevs = fcur( f% Y% y W: a
Else/ _/ C" \; L5 Z6 m
Dim p As Double, r As Double9 w) S4 S7 j! b: `) s, ~
p = Math.Exp(-de / temperature_k)
+ Y# x+ V1 Q5 j7 N r = Rnd()3 P9 J/ X* O8 U1 h' Q. B+ s5 f9 c. D
3 T( S5 s0 }, ? If p > r Then
) a+ s$ p# }+ _8 R9 u '以概率的形式接受使函数值变大的数2 U# Z4 W4 m- h) N" v, u
x = xi+ }: v) _/ c2 Z6 B, X/ ?
rec_num += 1# j# S. k& A1 Z5 t' @
fprevs = fcur
; h2 Y" k" s3 P' a End If* v7 e1 O' u4 u# C' c \( u( ]9 r
End If
6 H. d: \# r* Y1 T/ b; M If rec_num > receivnum Then$ ?( R7 w: {: b/ u$ Q
temp_i = i - 17 I w7 ^. X/ l
Exit For1 r; z/ B8 G2 o
End If$ g! J* Y9 H2 G2 R8 ]. S) Q
Next
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) E: L3 O& k, G+ K' D8 v% f k += 1
+ O5 L7 u' I, k" {9 z temperature_k = init_temperature / (k + 1) '温度下降原则
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4 }1 S% C5 X8 b$ R' G$ h2 N- q If Math.Abs(best_x - 0.25) < 0.00001 Then Exit Do
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6 C! i5 |# D( @ Loop While (k < 5000 ); W8 A# C( B+ l, L
xprevs = x
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( n. D: K `4 q( q* [, C9 J( O Return best_x
: C! r$ C+ W8 y5 _; |. N2 B End Function
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End Class
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算法测试: " Q6 a" D2 ~4 b: r6 P. A" K) V$ |5 `
在窗口中添加一个按钮
! w, v6 E/ I" z7 g9 UPrivate Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click% n: w) C" [( o5 l( H
Dim csa As CSA_Cnhup = New CSA_Cnhup
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- s5 n k/ N1 o; P4 K Dim x1 As Double, x2 As Double
- U* A3 s& J; c S2 F0 ?3 @- B% t7 m x1 = 2 'CDbl(InputBox("参数上限", "参数范围", 2) & " ")
3 I$ b0 V+ ^, G0 ^7 r) [6 P x2 = -2 'CDbl(InputBox("参数下限", "参数范围", -2) & " ")
& P) i2 q8 D. _9 ]" O Dim y As Double
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For i As Integer = 0 To 199 J6 i8 m3 u$ ~& d) d
y = csa.CSA(x1, x2)' q0 c0 i y( g" r# D8 l$ ]
Debug.Print("(" & y.ToString & "," & csa.obFun(y).ToString & ")")* R. s8 h2 ^2 ^4 k
Next
; C/ @! A) k. H# N: z. {* q/ y Debug.Print((New System.Text.StringBuilder).Append("-", 60).ToString)" V2 w& W) l: ?+ |3 e
End Sub
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