贴上本人自己写的模拟退火算法的源代码,开发环境 Visual Basic.net 2005; n3 p; E. H6 [4 e; S
觉得有用的给个回复,拉拉人气..
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Public Class CSA. n! q" [+ {5 _% |" X7 S
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Public Function obFun(ByVal x As Double) As Double
) E) E4 d4 c2 l Return 2 * Math.Pow(x, 2) - x - 1+ X) f7 z4 I @6 A1 B: u
End Function
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2 h+ ?& M6 o- ]. J7 D2 e; f ''' <summary>
+ Z" B+ Q- g5 r5 C- ^ ''' 传统的模拟退火算法/ I' o5 W% B, P; S" ~8 ~
''' </summary>( c9 \. I# p0 A5 f
''' <param name="Ux ">参数的取值范围上限</param>
' a- _0 x; e, p5 t* E ''' <param name="Lx ">参数的取值范围下限</param>: J. M* S% G9 H! t! c3 I, t
''' <returns></returns>
3 ~6 M! b; q8 Y- L ''' <remarks></remarks>
: l- V; w* F2 T, y' K& f, t2 a Public Function CSA(ByVal Ux As Double, ByVal Lx As Double) As Double" y$ w5 N% {! Y
Dim init_temperature As Double, total_numk As Double, step_size As Double '定义初始温度,温度k时循环总次数,步长
# B5 @9 [& `2 d; S4 [ Dim x As Double, receivnum As Double '定义变量当前值,前一个值,内循环的接受数据5 D% g& @1 m1 x1 G/ Y
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'初始化SA参数
. R: z8 A' p4 }' G: x5 } init_temperature = 0.014 v, o9 D; R6 @9 T" y
total_numk = 1000
( a# L$ a! ?7 A4 I. D1 \, J O step_size = 0.0015 m: n4 u1 t0 u! V/ J3 A' h
receivnum = 50
: u8 k; T4 N8 q1 D& p x = (Lx - Ux) * Rnd() + Ux '随机产生变量x
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% F: p/ h) X6 v8 z& q5 Z* P Dim k As Integer = 0 '温度下降次数控制变量% Z& g4 Q5 \4 Q* Q" z
Dim temperature_k As Double = init_temperature '定义第k次温度4 ?' [8 a: k, j% {! O* R
Dim best_x As Double
5 u3 y1 p% j! I P' \ Dim de As Double = 0.0
' ?" [# \, f( g' K2 Z1 x H Dim fcur As Double = 0.0$ [$ q7 U# e$ P4 ?( A
Dim xi As Double
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; N1 @+ m( o& S3 i* @ Dim fprevs As Double = obFun(x)) P: s" J$ ?- N: \. R' g
Dim xprevs As Double = x
5 \: t) L( E: C4 y6 B2 g 'SA算法核心. f+ n5 }1 B' p( _/ D
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'xprevs = x '保留前一个变量值' w* r4 c: I a; |
" Q8 K2 q3 O3 I' T& i: R5 k '以下三个参数用于估算接受概率
' Z9 y. s( b& I6 ]# x5 O0 C Dim rec_num As Integer = 0 '接受次数计数器/ n+ _ O- s% g/ T: y( U, I; a
Dim temp_i As Double = 0 '记录下面for循环的循环次数
6 ?3 v3 m3 f: W% L! _0 ~2 |7 R Dim temp_num = 0 '记录fxi<fx的次数
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For i As Integer = 1 To total_numk' u4 H7 {: T! F8 Y: `# U. h
'产生满足要求的下一个数
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+ C$ T* K& y0 Q' l xi = x + (2 * Rnd() - 1) * step_size
- ^1 j* V6 z/ Z! d3 O' n& l Loop While (xi > Ux Or xi < Lx)/ o, v G& I' q
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fcur = obFun(xi)
$ v1 m/ Q/ b. U9 s de = fcur - fprevs- }, ~8 F% L; p! y
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If de < 0 Then '函数值小的直接进入下次迭代4 c0 f |0 O R! f* I# [
best_x = xi$ k K3 x* f- O" }7 Y0 `& p
x = xi
% p) m# S& ?) A# M; g* B rec_num += 1
( f+ o) z- s2 j+ \3 \# v temp_num += 15 D' ]5 h+ s' e* _& S4 t |9 P
fprevs = fcur# |% r" O5 o! B) u- L0 {3 X
Else$ M8 ]* Y" s. Y/ R
Dim p As Double, r As Double
1 V2 ]3 M" X' f( k p = Math.Exp(-de / temperature_k)+ Z+ U- ^9 R) V: ~" ~
r = Rnd()
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5 u. a- G( ^6 ^' ^7 m If p > r Then
3 A) ~- m$ y) \3 L '以概率的形式接受使函数值变大的数
0 K6 S, a& v* a5 I$ A x = xi
5 z* U, Y! K/ M, T; g1 s0 ~# u5 u rec_num += 1
/ T' ]6 W" Z$ ?. w4 |* F* q fprevs = fcur
* Q; m: n. `, S End If. U7 o) M, w, R. J/ X0 r( t+ i6 J
End If
4 ~9 m4 ^5 ?+ z7 Y7 h If rec_num > receivnum Then w( K$ K6 ?) l
temp_i = i - 1
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End If! ?5 r& \! e2 x3 L5 \, R# x
Next
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7 e- F8 D5 p# H1 ^- u: x k += 1+ C/ u2 |9 X% q- K/ G) D
temperature_k = init_temperature / (k + 1) '温度下降原则
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If Math.Abs(best_x - 0.25) < 0.00001 Then Exit Do' f2 X/ \" q! g
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Loop While (k < 5000 )# Y1 W* K. _7 C" M/ R# P/ R
xprevs = x* S7 [. @: D: U, x6 A
" N% ]6 {/ A: W/ x2 K4 u Z Return best_x
0 U. f2 G( |# `8 [9 b/ Q$ r End Function1 o: q9 C# }' i9 D
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End Class # b. Q7 ^4 X# j( L c+ d
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6 Y% J) F- M9 c0 w算法测试: / j$ T9 ?9 b% g: y
在窗口中添加一个按钮 s* O" \& |5 Q, |/ S
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
* J B; ~) T4 s6 p9 x; n Dim csa As CSA_Cnhup = New CSA_Cnhup2 S3 H, s5 J# }6 @3 {
7 A \0 G% D: p ^ Dim x1 As Double, x2 As Double$ }; u- b3 d5 Q
x1 = 2 'CDbl(InputBox("参数上限", "参数范围", 2) & " ")
/ w3 n S: K0 C8 i x2 = -2 'CDbl(InputBox("参数下限", "参数范围", -2) & " ")1 a; J% {- @, R$ W6 p% z. f% u5 v
Dim y As Double
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; }: B/ N9 u, }+ F [ For i As Integer = 0 To 19
: Z9 {( I% D3 } y = csa.CSA(x1, x2)
6 F# }5 m8 @2 x% F, c+ w$ j5 O Debug.Print("(" & y.ToString & "," & csa.obFun(y).ToString & ")")
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Debug.Print((New System.Text.StringBuilder).Append("-", 60).ToString)
1 t2 G+ I6 q$ D. {3 [! E7 W+ IEnd Sub q) s3 N: V. ?% B' g8 d" d
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