新手跪求指导

heugaodie

r = 3.04042*10^(-6);
p[x_] := x^5 - (2 + r) x^4 + (1 + 2 r) x^3 - (1 - r) x^2 +
+ m; }. }: E4 p3 _+ |  2 (1 - r) x + r - 1
q[x_] := p[x] - 2 r*x^2;
7 ~& q' @* F* Ra0 = 0.5; b0 = 1.5; delta = 10^(-6); k0 = 100;
/ [$ y/ t* N9 x: Wa = a0; b = b0;
Do[x = (a + b)/2;
If[p[x] == 0, Break[], If[N[p[x]*p[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
x1 = x
5 ?7 R5 B, W" y1 tClear[x]
Do[x = (a + b)/2;
* v: ?- F5 m2 A' c; A. n! ^ If[q[x] == 0, Break[], If[N[q[x]*q[b]] < 0, a = x, b = x]];
If[N[Abs[b - a]] < delta, Break[], If[k == k0, Print[失败]]], {k, k0}]
8 R6 N8 \" l% E$ m# b$ ?8 Rx2 = x
7 Z' P$ Y! V/ G6 {+ ~5 R* EClear[x]

/ K, O, y/ v' }0 ]/ i( `- Q我想让p q 两函数的解都求出来 每次都是两个一样的解（是第一个的）  明明用了clear的 怎么做
1 V& |0 [2 K- s- p8 ?+ I/ ^7 Z

qudazi

你试一下将Clear[x]换成x=.看看

花如梦

别只用x,换个变量试试

小小灰

看不懂，看不懂