Lingo建模语言与实例4

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目标与约束段
6 r2 q5 U3 {# y; j6 S集合段（SETS    ENDSETS）
. D: g" J5 F7 t; @4 w# q数据段（DATA   ENDDATA）
  t- J- R0 x  \) h* ]- E/ \初始段（INIT  ENDINIT）
（计算段 (CALC ENDCALC)）
MODEL:
/ c- T6 D3 N$ g. W, DTitle Location Problem;
sets:
7 q! Q% u9 J) C" q6 m1 k+ j3 _    demand/1..6/:a,b,d;
. }' p. S/ e6 @) N. D    supply/1..2/:x,y,e;
    link(demand,supply):c;
3 `7 }! X, {; d! `' G% U; uendsets
" A  u2 o5 ~2 [, H7 k3 Pdata:
a=1.25,8.75,0.5,5.75,3,7.25;
b=1.25,0.75,4.75,5,6.5,7.75;
, J; Z6 }* [  X; @6 [7 d+ V0 l3 ad=3,5,4,7,6,11; e=20,20;
- }: l) t$ F) d# Aenddata
init:
. U- K* |; M; J# B) |x,y=5,1,2,7;
# D+ t5 P' j. Q: K+ u3 z7 Pendinit
min=@sum(link(i,j):c(i,j)*((x(j)-a(i))^2+(y(j)-b(i))^2)^(1/2));
; {& p$ x  d4 M: \9 G% g@for(demand(i)sum(supply(j):c(i,j))=d(i););
  H6 {; h( n- J: t, _@for(supply(i)sum(demand(j):c(j,i))<=e(i););
0 h0 [- `: m& S+ gEND

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