求大神帮忙看看我这用LINGO求解弧-路模型的代码到底是哪里有错啊,,一直运行不出来结果。。很急啊,在线等
model: !机车运用周转时空网络模型; sets: L/1..7/; !L:承担该交路牵引任务的机车集合; Nodes/nit ns1d10005 d10009 d10013 d10004 d10008 d10012 d10002 d10007 d10006 d10010 d10011d10015 a10002 a10006 a10010 a10003 a10007 a10011 a10001 a10004 a10005 a10008a10009 a10012 r10001 m10004 m10002 m10006 m10010 m10005 m10008 m10009 m10003m10007 m10011 ft/:time; !一共38个节点; Arch(nodes,nodes)/nit,a10001 d10002,a10002 d10005,a10005 d10009,a10009 d10006,a10006 d10010,a10010 d10013,nft nit,a10003 d10004,a10004 d10007,a10007 d10008,a10008 d10012,a10012 d10011,a10011 d10015,nft a10001,r10001 a10002,m10002 a10005,m10005 a10006,m10006 a10009,m10009 a10010,m10010 a10003,m10003 a10004,m10004 a10008,m10008 a10007,m10007 a10011,m10011 a10012,nft m10002,d10009 m10002,d10013 m10006,d10013 m10005,d10010 m10005,d10011 m10005,d10015 m10005,nft m10009,d10015 m10003,d10008 m10003,d10012 m10007,d10012 m10004,d10006 m10004,d10010 m10004,d10011 m10004,d10015 m10008,d10011 m10008,d10015 nit,ns1 ns1,d10006 ns1,d10010 ns1,d10011 ns1,d10015 m10010,nft m10011,nft ns1,nft/; !所有的弧段(一共51条弧); numberpath/1..20/; Paths(nodes,nodes,numberpath)/nit,r10001,1 d10005,nft,2 d10005,nft,3 d10005,nft,4 d10005,nft,5 d10002,nft,6 d10002,nft,7 d10007,nft,8 nit,nft,9 nit,nft,10 nit,nft,11 d10004,nft,12 d10004,nft,13 d10004,nft,14 d10004,nft,15 nit,nft,16 nit,nft,17 nit,nft,18 nit,nft,19 nit,nft,20/:p; !可能的机车走行径路集合(始发点-终到点-序号);
Paths2(nodes,nodes,numberpath)/nit,a10001,1 a10001,r10001,1 d10005,a10005,2 a10005,m10005,2 m10005,d10010,2 d10010,a10010,2 a10010,m10010,2 m10010,nft,2 d10005,a10005,3 a10005,m10005,3 m10005,d10011,3 d10011,a10011,3 a10011,m10011,3 m10011,nft,3 d10005,a10005,4 a10005,m10005,4 m10005,d10015,4 d10015,nft,4 d10005,a10005,5 a10005,m10005,5 m10005,nft,5 d10002,a10002,6 a10002,m10002,6 m10002,d10009,6 d10009,a10009,6 a10009,m10009,6 m10009,d10015,6 d10015,nft,6 d10002,a10002,7 a10002,m10002,7 m10002,d10013,7 d10013,nft,7 d10007,a10007,8 a10007,m10007,8 m10007,d10012,8 d10012,a10012,8 a10012,nft,8 nit,a10003,9 a10003,m10003,9 m10003,d10008,9 d10008,a10008,9 a10008,m10008,9 m10008,d10011,9 d10011,a10011,9 a10011,m10011,9 m10011,nft,9 nit,a10003,10 a10003,m10003,10 m10003,d10008,10 d10008,a10008,10 a10008,m10008,10 m10008,d10015,10 d10015,nft,10 nit,a10003,11 a10003,m10003,11 m10003,d10012,11 d10012,a10012,11 a10012,nft,11 d10004,a10004,12 a10004,m10004,12 m10004,d10006,12 d10006,a10006,12 a10006,m10006,12 m10006,d10013,12 d10013,nft,12d10004,a10004,13 a10004,m10004,13 m10004,d10010,13 d10010,a10010,13 a10010,m10010,13 m10010,nft,13 d10004,a10004,14 a10004,m10004,14 m10004,d10011,14 d10011,a10011,14 a10011,m10011,14 m10011,nft,14 d10004,a10004,15 a10004,m10004,15 m10004,d10015,15 d10015,nft,15 nit,ns1,16 ns1,d10006,16 d10006,a10006,16 a10006,m10006,16 m10006,d10013,16 d10013,nft,16 nit,ns1,17 ns1,d10010,17 d10010,a10010,17 a10010,m10010,17 m10010,nft,17 nit,ns1,18 ns1,d10011,18 d10011,a10011,18 a10011,m10011,18 m10011,nft,18 nit,ns1,19 ns1,d10015,19 d10015,nft,19 nit,ns1,20 ns1,nft,20/:X,tw; !Xijk-第k条径路是否包含弧(i,j),每条径路可能经过的弧集合,tw-机车经过该弧的费用; links(Paths,L)/nit,r10001,1,1 d10005,nft,2,2 d10005,nft,3,2 d10005,nft,4,2 d10005,nft,5,2 d10002,nft,6,3 d10002,nft,7,3 d10007,nft,8,4 nit,nft,9,5 nit,nft,10,5 nit,nft,11,5 d10004,nft,12,6 d10004,nft,13,6 d10004,nft,14,6 d10004,nft,15,6 nit,nft,16,7 nit,nft,17,7 nit,nft,18,7 nit,nft,19,7 nit,nft,20,7/:Y,C; !Yijkm-第m台机车是否选择路径k,C-机车经过该径路的费用; endsets data: time=0 240 210 5901140 60 350 900 30 300 600 840 920 1180 480 1000 1320 200 750 1330 140 450 690 780 1040 1340 1440 580 1100 1420 570 810900 1160 300 850 1420 1440; !各节点对应时刻; tw=0 0 0 0 30 0 0 200 0 110 0 0 10 0 0 370 0 0 0 630 0 0 10 0 0 20 0 0 0 560 0 0 0 50 0 0 0 0 50 0 0 20 0 0 10 0 0 50 0 0 280 0 0 0 600 0 0 0 0 20 0 0 40 0 0 0 340 0 0 20 0 0 600 0 0 10 0 0 600 0 0 0 0 0 40 0 0 480 0 0 20 0 560 0 0 10 0 820 0 0 0; !机车经过各弧的费用; enddata min=@sum(links:C(i,j,k,m)*Y(i,j,k,m)); @for(L(o):@for(links:C(i,j,k,o)=@sum(Paths2(u,v,k):tw(u,v,k)))); !每条径路的费用; @for(Arch(u,v):@sum(Paths2(u,v,n):X(u,v,n))<=1); !每条弧至多被一条径路所包括; @for(L(o):@sum(links(u,v,s,o)|s #eq#k:Y(u,v,s,o))=1); !每台机车有且只有一条走行径路; @for(Paths2:@bin(X)); !定义X为0-1变量; @for(links:@bin(Y)); !定义Y为0-1变量; end
|