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发表于 2021-2-23 16:27 |只看该作者 |倒序浏览
|招呼Ta 关注Ta
model:
sets:
weizhishu/1..24/:a,b,c,d,e,f,g,z,k,l,m,n,soe;
endsets
sets:
demand/1..24/:h,cool,xiadian,ddian,price;
endsets
data:
h=@ole(D:\tongzhou4.xlsx,h);
cool=@ole(D:\tongzhou4.xlsx,cool);
price=@ole(D:\tongzhou4.xlsx,price);
xiadian=@ole(D:\tongzhou4.xlsx,xiadian);
ddian=@ole(D:\tongzhou4.xlsx,ddian) ;
enddata
min=@sum(weizhishu(j):520*a(j)+0.0000029*a(j)^2)+@sum(weizhishu(j):520*b(j)+0.0000019*b(j)^2)+
@sum(weizhishu(j):250*c(j))+@sum(weizhishu(j):0.01*d(j))+@sum(weizhishu(j):0.095*e(j))+@sum(weizhishu(j):0.0624*f(j))+@sum(demand(j):price(j)*(g(j)+z(j)))+@sum(demand(j):price(j)*@abs(k(j))) +@sum(demand(j):price(j)*l(j));
@for(weizhishu(j):a(j)+z(j)-e(j)-0.1988*d(j)>=xiadian(j));
@for(weizhishu(j):b(j)+g(j)-f(j)>=ddian(j));
@for(weizhishu(j):d(j)+0.002859*a(j)^2+0.86*a(j)+397.03+6.35*e(j)>=cool(j));
@for(weizhishu(j):c(j)+257+4.16*f(j)+0.56*b(j)+0.00187*b(j)^2+0.88*k(j) = z(j) +0.88*l(j));   
@for(weizhishu(j):a(j)>425;a(j)<1702);
@for(weizhishu(j):b(j)>425;b(j)<1702);
@for(weizhishu(j):c(j)>=0);
@for(weizhishu(j):d(j)>1336; d(j)<13360);
@for(weizhishu(j):e(j)>290; e(j)<8502);
@for(weizhishu(j): f(j)>290; f(j)<8658);
@for(weizhishu(j): m(j)+n(j)<=1);
@bin(m(j));
@bin(n(j));
@for(weizhishu(j): soe(j)=0.999*soe(j-1)- m(j)*0.0345*k(j)-0.04456*l(j)*n(j));
init:
soe(0)=soe(24)=0.5;
endinit
@free(k(j));
@for(weizhishu(j): k(j)<=0; k(j)>=-7.95);
@for(weizhishu(j): l(j)<=5.68);
@for(weizhishu(j):soe(j)>=0.15;soe(j)<=0.85);
end   
数据在附件中   请教递推关系如何赋初值?
@for(weizhishu(j): soe(j)=0.999*soe(j-1)- m(j)*0.0345*k(j)-0.04456*l(j)*n(j));
init:
soe(0)=soe(24)=0.5;
endinit  
这块感觉有问题

tongzhou4.xlsx

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model:
sets:
weizhishu/1..24/:a,b,c,d,e,f,g,z,k,l,m,n,soe;
endsets
sets:
demand/1..24/:h,cool,xiadian,ddian,price;
endsets
!data:
!h=@ole(D:\tongzhou4.xlsx,h);
!cool=@ole(D:\tongzhou4.xlsx,cool);
!price=@ole(D:\tongzhou4.xlsx,price);
!xiadian=@ole(D:\tongzhou4.xlsx,xiadian);
!ddian=@ole(D:\tongzhou4.xlsx,ddian) ;
!enddata;
min=@sum(weizhishu(j):520*a(j)+0.0000029*a(j)^2)+@sum(weizhishu(j):520*b(j)+0.0000019*b(j)^2)+
@sum(weizhishu(j):250*c(j))+@sum(weizhishu(j):0.01*d(j))+@sum(weizhishu(j):0.095*e(j))+@sum(weizhishu(j):0.0624*f(j))+@sum(demand(j):price(j)*(g(j)+z(j)))+@sum(demand(j):price(j)*@abs(k(j))) +@sum(demand(j):price(j)*l(j));
@for(weizhishu(j):a(j)+z(j)-e(j)-0.1988*d(j)>=xiadian(j));
@for(weizhishu(j):b(j)+g(j)-f(j)>=ddian(j));
@for(weizhishu(j):d(j)+0.002859*a(j)^2+0.86*a(j)+397.03+6.35*e(j)>=cool(j));
@for(weizhishu(j):c(j)+257+4.16*f(j)+0.56*b(j)+0.00187*b(j)^2+0.88*k(j) = z(j) +0.88*l(j));   
@for(weizhishu(j):a(j)>425;a(j)<1702);
@for(weizhishu(j):b(j)>425;b(j)<1702);
@for(weizhishu(j):c(j)>=0);
@for(weizhishu(j):d(j)>1336; d(j)<13360);
@for(weizhishu(j):e(j)>290; e(j)<8502);
@for(weizhishu(j):f(j)>290; f(j)<8658);
@for(weizhishu(j):m(j)+n(j)<=1);
@for(weizhishubin(m));
@for(weizhishubin(n));
@for(weizhishu(j)|j#ge#2:soe(j)=0.999*soe(j-1)- m(j)*0.0345*k(j)-0.04456*l(j)*n(j));


soe(1)=0.5;
soe(24)=0.5;


@for(weizhishufree(k));
@for(weizhishu(j):k(j)<=0; k(j)>=-7.95);
@for(weizhishu(j):l(j)<=5.68);
@for(weizhishu(j):soe(j)>=0.15;soe(j)<=0.85);
end   
数据在附件中   请教递推关系如何赋初值?
@for(weizhishu(j): soe(j)=0.999*soe(j-1)- m(j)*0.0345*k(j)-0.04456*l(j)*n(j));
init:
soe(0)=soe(24)=0.5;
endinit  
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============下面是经过整理后的,至少是可以运行========
model:
sets:
weizhishu/1..24/:a,b,c,d,e,f,g,z,k,l,m,n,soe;
endsets
sets:
demand/1..24/:h,cool,xiadian,ddian,price;
endsets
!data:
!h=@ole(D:\tongzhou4.xlsx,h);
!cool=@ole(D:\tongzhou4.xlsx,cool);
!price=@ole(D:\tongzhou4.xlsx,price);
!xiadian=@ole(D:\tongzhou4.xlsx,xiadian);
!ddian=@ole(D:\tongzhou4.xlsx,ddian) ;
!enddata;
min=@sum(weizhishu(j):520*a(j)+0.0000029*a(j)^2)+@sum(weizhishu(j):520*b(j)+0.0000019*b(j)^2)+
@sum(weizhishu(j):250*c(j))+@sum(weizhishu(j):0.01*d(j))+@sum(weizhishu(j):0.095*e(j))+@sum(weizhishu(j):0.0624*f(j))+@sum(demand(j):price(j)*(g(j)+z(j)))+@sum(demand(j):price(j)*@abs(k(j))) +@sum(demand(j):price(j)*l(j));
@for(weizhishu(j):a(j)+z(j)-e(j)-0.1988*d(j)>=xiadian(j));
@for(weizhishu(j):b(j)+g(j)-f(j)>=ddian(j));
@for(weizhishu(j):d(j)+0.002859*a(j)^2+0.86*a(j)+397.03+6.35*e(j)>=cool(j));
@for(weizhishu(j):c(j)+257+4.16*f(j)+0.56*b(j)+0.00187*b(j)^2+0.88*k(j) = z(j) +0.88*l(j));   
@for(weizhishu(j):a(j)>425;a(j)<1702);
@for(weizhishu(j):b(j)>425;b(j)<1702);
@for(weizhishu(j):c(j)>=0);
@for(weizhishu(j):d(j)>1336; d(j)<13360);
@for(weizhishu(j):e(j)>290; e(j)<8502);
@for(weizhishu(j):f(j)>290; f(j)<8658);
@for(weizhishu(j):m(j)+n(j)<=1);
@for(weizhishubin(m));
@for(weizhishubin(n));
@for(weizhishu(j)|j#ge#2:soe(j)=0.999*soe(j-1)- m(j)*0.0345*k(j)-0.04456*l(j)*n(j));


soe(1)=0.5;
soe(24)=0.5;


@for(weizhishufree(k));
@for(weizhishu(j):k(j)<=0; k(j)>=-7.95);
@for(weizhishu(j):l(j)<=5.68);
@for(weizhishu(j):soe(j)>=0.15;soe(j)<=0.85);
end   
数据在附件中   请教递推关系如何赋初值?
@for(weizhishu(j): soe(j)=0.999*soe(j-1)- m(j)*0.0345*k(j)-0.04456*l(j)*n(j));
init:
soe(0)=soe(24)=0.5;
endinit  
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