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TA的每日心情 | 开心 2014-9-21 08:29 |
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签到天数: 19 天 [LV.4]偶尔看看III
- 自我介绍
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群组: 数学建模 群组: 中国矿业大学数学建模协会 群组: 数学趣味、游戏、IQ等 群组: 南京邮电大学数模协会 群组: LINGO |
function y=mminterp(tab,col,val)- f9 x/ j- q5 P: y2 N' Z
%MMINTERP 1-D Table Search by Linear Interpolation.
7 R J' }) J' t. G. y. W. F- T, L% Y=MMINTERP(TAB,COL,VAL) linearly interpolates the table L; U# L+ g* y9 N! J& t
% TAB searching for the scalar value VAL in the column COL.
: o) e6 t' P: S$ a% All crossings are found and TAB(:,COL) need not be monotonic.
- E. H' ^* b, z3 L0 ~6 B7 i: H% Each crossing is returned as a separate row in Y and Y has as3 @, g. G& ` N/ z6 s9 N! ]
% many columns as TAB. Naturally, the column COL of Y contains1 t/ @$ ?7 Y4 p0 y4 R4 a6 |, a8 M1 K
% the value VAL. If VAL is not found in the table, Y=[].$ x v0 c5 |' b3 @$ n+ [3 [: g: b4 k9 J
& o' h* m, @. x% p/ Y5 G) l
% D.C. Hanselman, University of Maine, Orono ME, 04469
2 X* w4 f, d! L% [: ^* [% 1/26/94! Z9 o% w! o* j5 A* w4 D% f# p+ I5 [: C
% Copyright (c) 1996 by Prentice-Hall, Inc.
& S3 I4 y, D: o# @' ^9 [
- j% p6 |3 c6 V2 F9 I[rt,ct]=size(tab);
8 @4 ^7 Z R% G1 P9 hif length(val)>1, error('VAL must be a scalar.'), end
0 i: q& @3 `! [' b& Z4 V% oif col>ct|col<1, error('Chosen column outside table width.'), end
" ^# l c( t1 t: S6 B8 ?# u9 zif rt<2, error('Table too small or not oriented in columns.'), end
' G& Z) N9 y8 [7 Habove=tab(:,col)>val;
* C S& ~ ?" F6 p4 k' q6 |below=tab(:,col)<val;
" h# `, E' _) F, P( fequal=tab(:,col)==val;
7 \$ J( ~. u* J; H# Eif all(above==0)|all(below==0), % handle simplest case. Y* d% h; T. v0 {1 k- L: b
y=tab(find(equal), ;5 U- ]& m" K$ V! O
return5 z6 {2 v: I. g7 ` _
end3 D* c" j: _$ J. P- b/ O6 H
pslope=find(below(1:rt-1)&above(2:rt)); %indices where slope is pos
+ \ G L3 q6 }nslope=find(below(2:rt)&above(1:rt-1)); %indices where slope is neg
9 \5 _' m" ?' o, O8 i
9 c3 j- r! u! y9 J: `, m N6 iib=sort([pslope;nslope+1]); % put indices below in order
% D7 O/ x( {* Ria=sort([nslope;pslope+1]); % put indices above in order: c) V J7 C+ v3 M$ F( q- T
ie=find(equal); % indices where equal to val
3 g0 H# k2 F9 B6 d" I; s/ {, Q( `0 |4 Z( p$ v0 g1 J, H) z2 _
[tmp,ix]=sort([ib;ie]); % find where equals fit in result
6 h& D4 m& a- bieq=ix>length(ib); % True where equals values fit* A, ]4 T: _: K: z4 u
ry=length(tmp); % # of rows in result y
5 q; ^! b4 q8 H+ e+ c" g3 p+ G# [9 E. Z5 f& ?
y=zeros(ry,ct); % poke data into a zero matrix
. U' I4 F% C, h5 w: [0 a4 c
* k6 m0 z) P' `! K) d$ T0 b5 Valpha=(val-tab(ib,col))./(tab(ia,col)-tab(ib,col));
4 Q! U+ m3 l2 C7 W4 ]+ q! ralpha=alpha(:,ones(1,ct));
, T# F8 l# A# @: E2 }4 z% |y(~ieq, =alpha.*tab(ia, +(1-alpha).*tab(ib, ; % interpolated values- X' z7 e8 @, {4 y' O3 p$ z
/ h; s0 M3 K- A( K5 N4 F6 l
y(ieq, =tab(ie, ; % equal values4 e8 a( z$ J' g7 G v' O
y(:,col)=val*ones(ry,1); % remove roundoff error |
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