- 在线时间
- 36 小时
- 最后登录
- 2017-7-6
- 注册时间
- 2009-4-19
- 听众数
- 5
- 收听数
- 1
- 能力
- 0 分
- 体力
- 2412 点
- 威望
- 98 点
- 阅读权限
- 60
- 积分
- 1865
- 相册
- 0
- 日志
- 1
- 记录
- 1
- 帖子
- 316
- 主题
- 28
- 精华
- 0
- 分享
- 0
- 好友
- 24
TA的每日心情 | 开心 2014-9-21 08:29 |
|---|
签到天数: 19 天 [LV.4]偶尔看看III
- 自我介绍
- 我思我在
群组: 数学建模 群组: 中国矿业大学数学建模协会 群组: 数学趣味、游戏、IQ等 群组: 南京邮电大学数模协会 群组: LINGO |
function y=mminterp(tab,col,val)
/ c1 T$ E( m5 n3 J8 `%MMINTERP 1-D Table Search by Linear Interpolation.# }4 r: K6 y; v) p" t
% Y=MMINTERP(TAB,COL,VAL) linearly interpolates the table* e' U: ]7 }0 a/ }2 r9 ~" P7 \$ K% x
% TAB searching for the scalar value VAL in the column COL.
6 \/ c) r/ y$ t- C" `% All crossings are found and TAB(:,COL) need not be monotonic.5 w0 P4 l, o7 ]( W
% Each crossing is returned as a separate row in Y and Y has as( O. U+ v. _6 t7 s0 X5 }3 A
% many columns as TAB. Naturally, the column COL of Y contains
" O; ^) D6 t* i! }8 S% the value VAL. If VAL is not found in the table, Y=[].3 \: ~$ h4 ^5 f, N0 x. t
7 E6 [2 J% q* M. x$ K! Q% D.C. Hanselman, University of Maine, Orono ME, 04469
9 \5 W* @) o, z6 z+ m0 Y, U" |% 1/26/94
. |5 p& }! @ o/ E) j2 N Y1 C$ [/ |- Y% Copyright (c) 1996 by Prentice-Hall, Inc.
. r8 v2 @& ]6 D- n3 F* N7 [' |' @' n' O' A. `" O- H+ W
[rt,ct]=size(tab);% K2 n" U. W# z3 G: l" S2 o; e
if length(val)>1, error('VAL must be a scalar.'), end' l, n. l/ ~+ G8 j* ~- R: |( O
if col>ct|col<1, error('Chosen column outside table width.'), end R' u7 a; Y3 y
if rt<2, error('Table too small or not oriented in columns.'), end9 P$ ]. H: W# w
above=tab(:,col)>val;1 U1 f# w2 y8 T* N
below=tab(:,col)<val;
6 |, N% c% S: U# F9 v+ x# cequal=tab(:,col)==val;# m( W$ F6 H. |# b
if all(above==0)|all(below==0), % handle simplest case* ^- M) \5 F8 ~4 i
y=tab(find(equal), ;2 K* z7 R6 X' G# |3 ~8 u. B( l
return
" U2 ^8 W4 z; D& ^) F& Gend! Z& U, z9 S4 c! q
pslope=find(below(1:rt-1)&above(2:rt)); %indices where slope is pos) T/ J! K# Q+ M, k3 s
nslope=find(below(2:rt)&above(1:rt-1)); %indices where slope is neg
0 E7 Q! n- b: |! y: w+ m) `
0 i1 ^, }, }9 y3 A) p6 Eib=sort([pslope;nslope+1]); % put indices below in order: X0 X) ` J$ }1 T
ia=sort([nslope;pslope+1]); % put indices above in order
/ a, l, c) p! A9 G$ N5 ?ie=find(equal); % indices where equal to val
% Z9 V+ a" g. [1 }( D+ J, t8 @3 \3 c, r. c# ^
[tmp,ix]=sort([ib;ie]); % find where equals fit in result
1 T2 |; ]* E9 _" \- u8 ?* uieq=ix>length(ib); % True where equals values fit
/ Z3 r7 [; |6 t2 P% t8 J9 ?+ y8 X* |ry=length(tmp); % # of rows in result y# v, ]% X% I* w
$ [# Q) p% z. v4 |y=zeros(ry,ct); % poke data into a zero matrix& j/ _& l* W+ p v. G
]! a5 m9 p G* ialpha=(val-tab(ib,col))./(tab(ia,col)-tab(ib,col));9 ]8 k4 h9 f, f; T6 T4 F" [ Y, {
alpha=alpha(:,ones(1,ct));
: A9 d- ^$ }3 E% \' [2 a& Ly(~ieq, =alpha.*tab(ia, +(1-alpha).*tab(ib, ; % interpolated values" ?5 s/ W4 ~0 [3 [# q5 ?
}! g: J i( h2 I1 t
y(ieq, =tab(ie, ; % equal values
3 F( T( Q W- u1 D" yy(:,col)=val*ones(ry,1); % remove roundoff error |
|