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发表于 2004-10-4 02:54 |只看该作者 |倒序浏览
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<><FONT color=#ff0000>函数名: ultoa </FONT>
* Q" z! T4 C2 Q* a9 L0 C功 能: 转换一个无符号长整型数为字符串 - ]0 t% r& P& [0 h% M5 u; g
用 法: char *ultoa(unsigned long value, char *string, int radix);
% B; Y8 Z: c) _- a程序例: </P>
1 f5 V: i1 {  b" m3 H<><FONT color=#0000ff>#include <STDLIB.H>
& x. ~* v1 m, X0 G- r. c$ I#include <STDIO.H></FONT></P>
' y6 r7 e% F2 l7 }& }4 Q, o<><FONT color=#0000ff>int main( void ) ( s& S) r9 x/ O, f+ \1 d; a. B
{
, a  C2 w: _" L% ounsigned long lnumber = 3123456789L; 7 j7 X6 ~# Z% T- H
char string[25]; </FONT></P>/ i) X  L; U+ W6 J7 S
<><FONT color=#0000ff>ultoa(lnumber,string,10);
- L( V7 i) {6 uprintf("string = %s unsigned long = %lu\n",string,lnumber); </FONT></P>
& s; @/ h) Y" s' Q8 K+ }; B2 E<><FONT color=#0000ff>return 0;
1 _2 m0 l: {# f+ X% J}
+ Z- c7 l/ Y6 L2 `) q</FONT>8 c! d) y1 Z4 U: s7 R' d' m5 Z8 k

: }/ J7 R, I& D9 |/ F* n8 S( }+ T</P>3 r. x4 J$ r" u8 V1 e
<><FONT color=#ff0000>函数名: ungetc </FONT>9 h  E9 h( U* X+ ?  e1 i+ k6 b& H! o
功 能: 把一个字符退回到输入流中 2 E" B1 f# m% l3 H2 p! {# b& w! C1 k/ Y
用 法: int ungetc(char c, FILE *stream);
) J5 I2 V, E4 o; l程序例: </P>! v3 Z8 c  ]% F* @9 D/ ], V
<><FONT color=#0000ff>#include <STDIO.H>% N# l: C5 J9 h* C2 j' C! X; k
#include <CTYPE.H></FONT></P>" a& H5 W$ f; E. i9 E( ?
<><FONT color=#0000ff>int main( void ) 8 q4 P# `8 H" X$ O2 W! b1 L8 B! T* _
{ 9 k1 S- L$ z+ E  h& m+ f7 f9 {
int i=0;
! K; N. M' U+ W. G) Hchar ch; </FONT></P>3 U; C( O5 x3 q3 @1 e- l5 T
<><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>" M2 b% w4 G0 F. t% B
<><FONT color=#0000ff>/* read chars until non digit or EOF */ * q/ o5 d( g/ O! z5 N; m
while((ch = getchar()) != EOF &amp;&amp; isdigit(ch)) & @" ]* H) k; j8 l: }+ a: s0 q
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
0 B: C7 J) @4 Y( I<><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */
) r. F! M# `: _2 V/ _if (ch != EOF)
7 _4 {7 h) E% F0 {ungetc(ch, stdin); </FONT></P>0 S3 C" \* `! U0 A) ^/ I( [4 ]$ ]
<><FONT color=#0000ff>printf("i = %d, next char in buffer = %c\n", i, getchar()); 9 [; @) a8 b! Z, \: J9 ^, {, k
return 0;
. g4 j7 N* Y; j} </FONT>
7 G" x4 q5 B6 L: D! Q% \
# C1 v6 ^* o5 V/ U$ x% M( E
* {9 U% |, h: q2 g</P>+ V' ]" L- J# p1 O0 g  e; y+ j
<><FONT color=#ff0000>函数名: ungetch </FONT>' _6 z! T) {9 s  H! Q
功 能: 把一个字符退回到键盘缓冲区中
: d+ }7 B+ X- [5 X1 S用 法: int ungetch(int c); , J- ]: Q- S! R- H" S2 O
程序例: </P>
/ ~) B  q; [2 @: w* w7 Q' T<><FONT color=#0000ff>#include <STDIO.H>& S1 U! p$ i" R, T/ Z  ?$ F6 {  \
#include <CTYPE.H>; O+ Y+ F$ c4 W& I+ A0 o+ x# G
#include <CONIO.H></FONT></P>
+ C& l3 |4 L7 V, H% d3 X" u& ~<><FONT color=#0000ff>int main( void )
1 f$ ~" }5 S; X& r% F# h+ S0 E/ y{
2 j. X& r/ W2 R8 R$ ~int i=0;
1 o' Q' T1 F# Q4 i& r0 ychar ch; </FONT></P>
& I- B! P, W& h  U# d5 ?* t. [) \<><FONT color=#0000ff>puts("Input an integer followed by a char:"); </FONT></P>- ^) v6 C+ @% x) ?/ q
<><FONT color=#0000ff>/* read chars until non digit or EOF */ ! K" J. B7 j9 _: U" y
while((ch = getche()) != EOF &amp;&amp; isdigit(ch)) 7 g  z2 U1 q+ A
i = 10 * i + ch - 48; /* convert ASCII into int value */ </FONT></P>
, x: \0 Q3 ~4 ^, r' y<><FONT color=#0000ff>/* if non digit char was read, push it back into input buffer */
# [- K7 p% r6 u$ c: A. M' Fif (ch != EOF)
% U, [# o2 B+ s, X1 _1 P. w9 eungetch(ch); </FONT></P>
/ z8 W' x$ `8 w' G7 n/ X  [+ c<><FONT color=#0000ff>printf("\n\ni = %d, next char in buffer = %c\n", i, getch());
$ p0 E: d# O" L5 wreturn 0; 3 Y, W/ Q. ^; p; `& l
} / ~; M& ^* r/ ^

" O( Y! x5 I, h0 v5 m4 j% Y$ ~5 m
" n0 c+ h$ v" G4 x. Q6 _$ M  V0 P* K, D</FONT></P>
3 ?0 ?/ }3 M- A$ b' b  e<><FONT color=#ff0000>函数名: unixtodos </FONT>( ?" M1 I7 S; u/ U: g
功 能: 把日期和时间转换成DOS格式
4 i0 Y8 m0 s# ~& R% p9 [7 x% p用 法: void unixtodos(long utime, struct date *dateptr,
' L* G- `& j" X; i6 astruct time *timeptr);
, N7 N: H* T/ F* \7 E4 P2 {程序例: </P>
) M; l/ S  J3 P5 |% |( e" h. C<><FONT color=#0000ff>#include <STDIO.H>
2 ?& |4 ]. m0 |: ~' h#include <DOS.H></FONT></P>& R) \7 Y! T) B( c) y2 C* E
<><FONT color=#0000ff>char *month[] = {"---", "Jan", "Feb", "Mar", "Apr", "May", "Jun", 7 K( E% W% e  i, B. W( M
"Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; </FONT></P>
. L, u# I+ c  n" T' j/ q- C7 s' H<><FONT color=#0000ff>#define SECONDS_PER_DAY 86400L /* the number of seconds in one day */ </FONT></P>
! [2 u1 R$ A4 t1 w7 l6 O# J! V<><FONT color=#0000ff>struct date dt; ; L3 g' v0 C0 a4 Q
struct time tm; </FONT></P>
/ g' h, D0 u2 l: `5 Y<><FONT color=#0000ff>int main(void) ; L; y6 w* G; r; A) Y, V+ o( j; z/ T
{
' I2 o, n% R1 D3 E8 a6 {unsigned long val; </FONT></P>3 A6 a, j) j6 {' `
<><FONT color=#0000ff>/* get today's date and time */ & p/ T. @7 k# K* v
getdate(&amp;dt); # g3 U# u- k0 v/ Q3 `
gettime(&amp;tm);
& z9 `. K( ~" S9 u5 ~: J; C& E8 C3 Qprintf("today is %d %s %d\n", dt.da_day, month[dt.da_mon], dt.da_year); </FONT></P>
* L* J7 ?1 D# z<><FONT color=#0000ff>/* convert date and time to unix format (number of seconds since Jan 1, 1970 */
: D5 m: o# F! \& g  e! K# Ival = dostounix(&amp;dt, &amp;tm); + K* r5 @2 J2 o) q* L& o6 S$ t
/* subtract 42 days worth of seconds */
$ j. C. S  v4 O9 _6 jval -= (SECONDS_PER_DAY * 42); </FONT></P>( Z7 k4 }+ Q, b
<><FONT color=#0000ff>/* convert back to dos time and date */
! p5 S+ W! b9 r- o4 Qunixtodos(val, &amp;dt, &amp;tm); ! M+ L, Q% m3 f
printf("42 days ago it was %d %s %d\n", 8 H$ N. [; [# Q5 p
dt.da_day, month[dt.da_mon], dt.da_year);
9 K, M" O4 A! a6 z  V9 b4 j0 b0 {return 0; 9 P& P2 F$ S2 a: _( i) Y
}
6 N  J. n& e( w. W/ W$ F$ |' @; C/ `' t# _8 [; y- i
4 H8 L. `1 h3 ^4 P
</FONT></P>
* f2 L7 D+ @" [4 P  W" H, O<><FONT color=#ff0000>函数名: unlink </FONT>
/ ~. c' z$ G  l1 Z功 能: 删掉一个文件 ( s2 |" I/ T+ u5 j% b4 f3 |) ~
用 法: int unlink(char *filename);
+ [$ o; G# `) j; @6 S程序例: </P>, t- g- x; W# J+ h. C* N3 l; P
<><FONT color=#0000ff>#include <STDIO.H>' {1 Y- A5 h: I% m/ R% j" U
#include <IO.H></FONT></P>
. }2 n) O# g% F+ t, z4 s2 b<P><FONT color=#0000ff>int main(void)
% n" \7 Z+ s; z9 U{ / b  t- \8 l& S
FILE *fp = fopen("junk.jnk","w");
, O  d% Z; M- ^: G9 o, Z3 tint status; </FONT></P>1 G7 _6 _- W( {
<P><FONT color=#0000ff>fprintf(fp,"junk"); </FONT></P>- M  Q# G! F9 M$ _' {
<P><FONT color=#0000ff>status = access("junk.jnk",0); 1 x, s" I: N% p4 B0 ~8 a
if (status == 0)
) ^/ E* U* m3 [6 ~printf("File exists\n"); 5 \/ w# D7 }) e- w
else 6 }7 H( I3 E* f6 w4 w& Z* }
printf("File doesn't exist\n"); </FONT></P>
9 a$ F' Z  S1 E<P><FONT color=#0000ff>fclose(fp); - S& _0 b7 [( e3 x0 F) h. e, n
unlink("junk.jnk"); ! O' e2 B9 f  Q/ i4 n9 }
status = access("junk.jnk",0); 3 W, V' m, K9 m! b$ H2 I
if (status == 0)
* t$ ^& U$ f2 M+ T! t  Zprintf("File exists\n"); : T$ `4 p5 P0 k6 Z5 F9 c0 N9 ?
else 0 ]" F" U( L. T; t# J( J7 k+ X$ F
printf("File doesn't exist\n");
; f/ \% r7 X5 i3 a</FONT></P>& \3 K  q* g& y) a( |. z* y
<P><FONT color=#0000ff>return 0; # @2 E" g' i, N4 c
}
' Y5 h) a& Q# z- x3 \6 W4 |/ J1 n% s5 C8 X
</FONT>' D- a" @0 R9 o1 l
</P>
$ P+ d3 b- R3 ^<P><FONT color=#0000ff>函数名: unlock </FONT>
" T! G8 q' ~, G4 J4 i# @功 能: 解除文件共享锁
9 C. |) m1 o3 L' B' b/ N用 法: int unlock(int handle, long offset, long length);
. z( a6 h/ I8 X; X( Q程序例: </P>- k) \" e& h( ]7 Z5 N8 b
<P><FONT color=#0000ff>#include <IO.H>
" j$ y4 l) m' k) D# `#include <FCNTL.H># z  _$ U' t* k+ e% c: P
#include <SYS\STAT.H>2 w. v; X. M" z4 a6 ~3 }4 J7 {
#include <PROCESS.H>8 Z( n" Z3 e) L2 R
#include <SHARE.H>7 }% q2 Q' I9 G( G  n
#include <STDIO.H></FONT></P>
$ |: u, p( w  C! _. x<P><FONT color=#0000ff>int main(void) ( n! E( J$ M/ {% D: C% @
{
/ h+ B# M5 c: g% A% D$ wint handle, status; , u" H% Y- Q, P2 d
long length; </FONT></P>& C" t) t# h* L8 T2 A8 ]
<P><FONT color=#0000ff>handle = sopen("c:\\autoexec.bat",O_RDONLY,SH_DENYNO,S_IREAD); </FONT></P>
4 l* Q5 C: V+ t" G  y: I7 U<P><FONT color=#0000ff>if (handle &lt; 0) 5 V" i6 i3 n$ g; q
{
7 l: {6 M8 b" H/ P/ K- V9 mprintf("sopen failed\n");
/ c8 ?& R# c# }8 e+ xexit(1); & N+ n1 E, @' M3 @  y+ i
} </FONT></P>
1 G$ g! o" f: T" u# W& G<P><FONT color=#0000ff>length = filelength(handle);
* b* o0 h2 b: T: m" b+ F" s0 Ostatus = lock(handle,0L,length/2); </FONT></P>
0 I9 P8 g" v1 ]/ G<P><FONT color=#0000ff>if (status == 0)
# y4 O9 r' c; J4 q7 m$ W) }printf("lock succeeded\n");
7 t. k. q; S6 Velse & A, F( G! \! {: E% t2 _& m
printf("lock failed\n"); </FONT></P>( [2 k' s5 D6 `6 R7 M' W/ L
<P><FONT color=#0000ff>status = unlock(handle,0L,length/2); </FONT></P>4 c5 A/ ~4 d5 X+ M% N# _
<P><FONT color=#0000ff>if (status == 0) % u. Q6 f" X" r" s
printf("unlock succeeded\n");
, e$ a4 x9 l0 d/ i% x: Zelse
7 S1 I- w" s7 C. w+ [; p8 d0 i' ^' j  Wprintf("unlock failed\n"); </FONT></P>
) X. X! A8 ~- X# z& T<P><FONT color=#0000ff>close(handle); & \# w3 V# q" W4 [5 R
return 0; 7 O) v' [6 B2 ^
} </FONT></P>
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