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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |倒序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>2 @& f2 ]2 _# e+ z0 }
<><FONT color=#ff0000>函数名: abort </FONT>
" z9 H2 X9 q; z; t功 能: 异常终止一个进程 % y; c" z8 X/ T
用 法: void abort(void); 1 t4 l' ~# g8 }/ d! V6 _8 {( j% R
程序例:
2 o& D8 f6 Q9 L3 Y1 m& Y" A<FONT color=#0000ff>#include <STDIO.H>9 \9 t6 V6 V# C: G5 B( k" ?
#include <STDLIB.H></FONT></P>
0 z% ^( u+ r" m/ E, J$ j<><FONT color=#0000ff>int main(void) 4 a4 ~: P* ^& q! z! T7 ^) c' r2 Q
{ * {. R0 U8 ]) ]
printf("Calling abort()\n"); ! k. p7 ]% b9 G$ f! p7 w0 H
abort(); . R( @/ M" U) Z; p/ F! F
return 0; /* This is never reached */   `- Z- R$ {/ o8 C% \* K5 c
} & M) U. o, @! n7 _3 Y; m$ d
</FONT>1 [4 X0 ?& u6 F1 P, r# a6 t
</P>
! N/ o  a2 [2 n: v: Q<><FONT color=#ff0000>函数名: abs </FONT>7 |4 Y: y4 d5 x/ {( V
功 能: 求整数的绝对值
  m, g+ y! E7 w: P用 法: int abs(int i);
# ^  k  R* r4 F# z) n- \  T  M; p程序例:
3 o7 n  b, ~, E: X<FONT color=#0000ff>#include <STDIO.H>
2 c0 A( b- l, E# }+ H#include <MATH.H></FONT></P>1 |* W/ c2 _5 T6 A
<><FONT color=#0000ff>int main(void) . q+ j5 |! }2 V' h
{ , h; _) p$ L# m7 N. u# m4 J
int number = -1234; </FONT></P>- y1 b: l( d$ f# R: D/ o
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
* c' X" T# F  r  _6 p: y" C  rreturn 0; 6 ^5 ~  c& a% S# u0 V* `" N
}
1 ]2 o" m+ t' Q' B# a- l: r</FONT>
0 N0 o* }1 r8 f' Z7 o</P>) W% b0 p# R$ e- j1 w5 F
<><FONT color=#ff0000>函数名: absread, abswirte </FONT>0 b+ Y  n3 O" k3 w. b9 _
功 能: 绝对磁盘扇区读、写数据
& c& d3 T, z5 \, l5 i用 法: int absread(int drive, int nsects, int sectno, void *buffer);   y& U. t0 S8 d& c( u; T" C. X, b
int abswrite(int drive, int nsects, in tsectno, void *buffer);
3 Z& c8 L7 g! Z  {: N程序例: & |9 r" h0 V, z3 ~$ F$ N5 r
<FONT color=#0000ff>/* absread example */ </FONT></P>
% o! e/ w: M8 L+ W<><FONT color=#0000ff>#include <STDIO.H>
1 F& \# r- p( D! o0 g# A" A4 I#include <CONIO.H>
! A; O; m6 f5 p  C#include <ROCESS.H>
7 ~; O  J" p8 Y% r' U; g1 b2 U#include <DOS.H></FONT></P>
6 S. Y5 O7 h1 b* k6 T<><FONT color=#0000ff>int main(void) 6 W! @( ?; b$ K9 T* o, m
{
& {3 h9 F& s" X' D! ^( I  |int i, strt, ch_out, sector; 8 u7 o% l# r. R7 O
char buf[512]; </FONT></P>
, z8 C& d4 Z# H/ @' e: d<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");   ^% f2 ^# K! W9 E) c! `
getch(); " ~: @6 \/ a3 L; Y: D
sector = 0; 7 @. ~5 c, I( a' ~
if (absread(0, 1, sector, &amp;buf) != 0)
. L: p) i/ M: ?3 ?# U0 Z{ $ k) w$ W3 C, J" d% I
perror("Disk problem");
1 U+ _$ i# l* }' X/ C% M+ D- qexit(1);
: Z2 H: d/ ]% J0 d6 ?2 b. b} * {0 _: r+ k3 z" C; g/ O
printf("Read OK\n");
5 ]. w8 P, u) `* N8 `7 N4 D1 c4 ]$ xstrt = 3;
2 Q0 z. `) g) ^* \0 C3 c8 T  `for (i=0; i&lt;80; i++)
( r; R/ i3 L: O1 l+ S{ + d( o" f- G! z2 G; u6 q( r' }7 f3 a
ch_out = buf[strt+i];
7 _0 h& V9 q  s1 m% a! z1 E8 {putchar(ch_out); 0 Z3 _' C+ b( J) e
}
9 c. {: C6 J: R- A7 z6 Mprintf("\n"); 2 o2 f- ^8 t7 I) M- q1 F3 x! {
return(0); 5 l' R  @/ c% {, l+ ~# }  `" ]
} ) B) ~/ r$ C3 Y6 L$ T( _
</FONT>
  R3 l1 t9 f* e5 R/ o0 W0 M  U
3 e5 I$ H& z1 w' d</P>
+ G$ }0 `9 @& M<><FONT color=#ff0000>函数名: access </FONT>
. b2 T. n- E! `* u0 \# W% h功 能: 确定文件的访问权限
# d5 I  q  t$ Q用 法: int access(const char *filename, int amode); 0 Y. U( K) a. y) J5 S: K- ~$ S
程序例:
( P) n, }3 g$ m* D+ T<FONT color=#0000ff>#include <STDIO.H>8 \5 m  x; c( @  |3 S) s( C- J; T
#include <IO.H></FONT></P>
: q6 P3 g/ N' t! p. Q<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P># A2 ^6 D3 |3 f9 h: a' M" x
<><FONT color=#0000ff>int main(void) 1 v5 w+ |/ M# `
{ ; g8 m( k) |5 H# D
printf("Does NOTEXIST.FIL exist: %s\n", & u4 N3 b, u: V1 I- N( {
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
# ?4 `1 t1 r$ P! z6 z2 rreturn 0; 2 B& [0 ~6 s& T3 K( d8 E
} </FONT></P>
$ q7 k& m; k1 D. |, j<><FONT color=#0000ff>int file_exists(char *filename)
$ C" W( w. r9 k5 t1 r{
5 m9 `+ ~  V) e4 k  e/ h7 areturn (access(filename, 0) == 0); 5 E5 z. n- v1 b! B
} 8 y# {9 a+ x, P1 I6 Y: O
</FONT></P>
& x% H) m# f$ }/ `8 d<><FONT color=#ff0000>函数名: acos </FONT>
! w8 u( h" r) a* ~# ]: [7 a) W功 能: 反余弦函数
: k, ~( N7 O2 N9 z用 法: double acos(double x);
" [- i$ X; i' ~  B; a程序例:
' t+ w% Z* P5 o. u<FONT color=#0000ff>#include <STDIO.H>2 V/ ~2 o3 }% Q
#include <MATH.H></FONT></P>' w% \& `& Y8 l
<><FONT color=#0000ff>int main(void)
- H* n: ?$ s5 S  ^3 @{ 0 S3 e% O, w  e  ?9 ]
double result;
7 {3 w- j; F5 `( v4 Ndouble x = 0.5; </FONT></P>
8 u1 S. Z# i; v# m. e5 G9 ^; }" }4 i<><FONT color=#0000ff>result = acos(x); " S4 |, ~. T6 T5 F4 ~
printf("The arc cosine of %lf is %lf\n", x, result); , [1 s! p5 v% I: N9 @1 ?: l
return 0; / }1 d- ]% r, o9 p+ g
} </FONT>4 B, p& r) R5 q2 }

( e! k8 H5 V+ S* s/ e, }( I- c</P>/ L+ q! m6 i. I( k4 C
<><FONT color=#ff0000>函数名: allocmem </FONT>
2 w. f. Y5 a/ a/ P' y功 能: 分配DOS存储段
! G6 _# o! s9 x用 法: int allocmem(unsigned size, unsigned *seg);
" @, ~6 o* B0 J% P0 f" v程序例:
4 t+ H' G8 Z# _, X9 b5 }6 H<FONT color=#0000ff>#include <DOS.H>
7 R+ J; W1 n3 g% a0 ]2 {( m3 @#include <ALLOC.H>* L# i# }6 Z, I
#include <STDIO.H></FONT></P>
7 C7 e7 j) I4 W: L0 @<><FONT color=#0000ff>int main(void)
. y: o  ]0 n6 v; w{ ( F% x& s5 C% W8 `8 z! C8 y
unsigned int size, segp;
7 k1 a/ _/ H, I- a3 V9 Y: m# O5 vint stat; </FONT></P>
0 l$ [& F3 s: u. f) M( }7 S<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ 3 j4 T; \. K2 u/ }1 I& V" C
stat = allocmem(size, &amp;segp); * k+ m& [# m) ~# G7 c9 R
if (stat == -1)
2 Z$ [) R$ Z6 m0 t! D. eprintf("Allocated memory at segment: %x\n", segp);
) x9 G- y) _, d1 J& ^% h( L5 i  ?else   C) E9 s0 D: e. N) [: ^* Y* j
printf("Failed: maximum number of paragraphs available is %u\n",
: X6 J1 x( m% }# W9 G7 U( p# Rstat); </FONT></P>& A" n" i4 G$ ~: t. b) I: L6 I2 B
<><FONT color=#0000ff>return 0;
# _% ^: c! D3 f9 X1 Z} </FONT>) z# i  i) Z: u2 C
  X! ~' T! b0 q7 U; t/ p
</P>5 _4 K, N( P2 S) E& |
<><FONT color=#ff0000>函数名: arc</FONT>
& W# F& v9 c4 F! _功 能: 画一弧线
8 p4 V. O: [0 L& t! O6 s用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
# x: Y$ v8 u0 m% M% q. a5 P程序例:
, O0 D0 F/ c. \& `3 \3 o# v<FONT color=#0000ff>#include <GRAPHICS.H>
' d% F* @7 Y  [* J5 O#include <STDLIB.H>1 g4 M/ P" c' O0 \! x9 f2 F; s
#include <STDIO.H>
! u3 [) h( z! P. {1 i#include <CONIO.H></FONT></P>4 V& v" D$ S. V2 ~& {
<><FONT color=#0000ff>int main(void) 7 A# I; R. }) {5 Y3 a2 i. ^
{
. O3 A5 c2 L( w5 c/* request auto detection */
  t3 O. K' L( {# g( cint gdriver = DETECT, gmode, errorcode; $ L3 T6 X; M2 j9 }# ?% v/ M
int midx, midy;   ?( `5 {& v$ F- J& ~7 Y+ `
int stangle = 45, endangle = 135; . ~: Q5 |. M! D" \. k2 e1 y
int radius = 100; </FONT></P>/ }) I8 ?( @7 ^1 O1 V0 a. _3 N8 v$ `$ U
<><FONT color=#0000ff>/* initialize graphics and local variables */
' k. n* I+ f( ^  T- Xinitgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>9 f# q1 ~9 d. l% T/ N
<><FONT color=#0000ff>/* read result of initialization */
2 z5 H& i: H" ]) }/ }errorcode = graphresult(); /* an error occurred */ ! i; l3 {, B' H  m
if (errorcode != grOk)
+ @4 f5 J0 X4 D7 `$ Y/ ^6 Y{
6 N) a8 C1 }# u$ Xprintf("Graphics error: %s\n", grapherrormsg(errorcode));
: G* w& Y7 {, M4 d% zprintf("ress any key to halt:"); 7 T/ `% f! D9 |9 {1 v
getch(); </FONT></P>
2 [$ P4 k* z! s<><FONT color=#0000ff>exit(1); /* terminate with an error code */
: E& [, B! f7 J/ ~6 b' L7 j, }} </FONT></P>
1 \/ ]4 W( }1 V<><FONT color=#0000ff>midx = getmaxx() / 2;
7 \" `# P' G5 `3 jmidy = getmaxy() / 2;
3 i' D! m  s( Esetcolor(getmaxcolor()); </FONT></P>+ A: k7 a% v1 Q9 U
<><FONT color=#0000ff>/* draw arc */ 3 p4 ^! L. \! a% B0 H
arc(midx, midy, stangle, endangle, radius); </FONT></P>
9 a; i* e1 I( M8 a<P><FONT color=#0000ff>/* clean up */ ' Z+ @1 b# A4 |% x  ^
getch(); * t, l8 P  Q  k$ k8 B- q
closegraph();
! X1 \; p, B  I, q: e8 Qreturn 0; " F( K# E8 {; u3 x: T) v. @
} ! J$ B0 {  [' d) X2 I1 h5 Q
</FONT>
) v; O4 D2 w* G7 C; y. w</P># X- o7 t9 ^4 E. ]+ l) T" I4 C/ y  P
<P><FONT color=#ff0000>函数名: asctime </FONT>! y/ v. W1 g% `
功 能: 转换日期和时间为ASCII码
0 D! G4 i7 ?$ o" D) P用 法: char *asctime(const struct tm *tblock); 6 a- V/ E  [: O( J) T5 A5 g5 F* W
程序例:
. ~! a1 N4 P# L% F2 k2 B( q+ }1 ~<FONT color=#0000ff>#include <STDIO.H>
5 z/ n) v$ |: y+ |$ @7 Q: H- o#include <STRING.H>
0 b: u/ n# q1 ~. V0 b- G#include <TIME.H></FONT></P>
) h, S+ ^4 ~; t; \( a. E- _<P><FONT color=#0000ff>int main(void)
7 E% B3 G+ F- g7 F( f{ ; @2 I( v4 d- Q4 M9 x; z" T& }
struct tm t;
% y1 x# _! y4 }5 E& Q# Wchar str[80]; </FONT></P>
- @3 ^5 t) L$ U8 r- z6 a<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
. v. b# ^% o& [; {, S8 G" I+ ]<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */
- o2 K' P( `7 ^# o! x, m3 z& F% `t.tm_min = 30; /* Minutes */
2 X: q6 u( Z, z3 \& X+ V2 c4 ^" @t.tm_hour = 9; /* Hour */ 1 c3 P0 ?! Z& p
t.tm_mday = 22; /* Day of the Month */
) {: h# _; }) j- D, nt.tm_mon = 11; /* Month */
3 U2 t6 U. X  E0 [7 Bt.tm_year = 56; /* Year - does not include century */
& M' L! |9 S* _$ gt.tm_wday = 4; /* Day of the week */
- Q# A; N& K) d+ [2 |6 D6 st.tm_yday = 0; /* Does not show in asctime */
7 p6 a+ Z9 T$ m* b/ x6 Ct.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>" ]" T+ u* I) G
<P><FONT color=#0000ff>/* converts structure to null terminated ' C. s4 g: R& m$ Y' ~: y5 V
string */ </FONT></P>
7 b; G6 p6 s& j2 v/ }! s5 z<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t));
' j* l0 N" O% ?$ J6 K% \6 B5 eprintf("%s\n", str); </FONT></P>
! P5 ^% [- s5 t! e& M<P><FONT color=#0000ff>return 0;
; h, ^5 `9 K0 K6 i8 e/ @/ K# O+ j}
/ G0 m- M: `( c4 K% t, Z& ]6 J
9 b% w9 g% h" @</FONT># I9 ]' O$ a7 _8 V' u  A2 X
</P>& e4 K( z9 v9 I
<P><FONT color=#ff0000>函数名: asin </FONT>
$ x7 a6 H. W& n/ u4 U6 e) b功 能: 反正弦函数
; Q8 F3 |" I' r用 法: double asin(double x);
9 Q& o- D) f; t" Z程序例:
8 @) R. U9 t6 j+ U9 V; Q2 j: D<FONT color=#0000ff>#include <STDIO.H>
4 W9 b: M3 X- r, N, E: ~#include <MATH.H></FONT></P>+ d9 m6 Y. N2 M( Q
<P><FONT color=#0000ff>int main(void)
, F3 e5 w1 b* P0 c0 \) @{ 0 R0 h/ d, ~4 W
double result;
; j7 W! m  m% p5 n, Z4 R4 hdouble x = 0.5; </FONT></P>
( w7 F0 Q7 b: x+ d, m) ?) F<P><FONT color=#0000ff>result = asin(x); 7 |- V: s6 ?2 u. S; ~
printf("The arc sin of %lf is %lf\n", x, result); / ]7 D% Z* A6 I9 W7 E" }
return(0); 2 j' N) \6 d8 v, j
} " x! C% `* M. E2 j4 j- A
</FONT>
, ]) t5 o$ j; B2 E5 x+ I, f
- [4 L3 z* O$ u5 g4 {1 y</P>
, w: T5 Y  M/ ?( F  I, ^<P><FONT color=#ff0000>函数名: assert </FONT>
' ?. G( K$ h( c4 E: g功 能: 测试一个条件并可能使程序终止
8 T0 A2 w4 w8 S5 [% i4 j6 O用 法: void assert(int test); 2 q) S& o: f  I) i% w
程序例: 4 Y+ h9 \# ~' u/ y
<FONT color=#0000ff>#include <ASSERT.H>7 V- ^' f4 a4 h+ E5 q
#include <STDIO.H>0 _0 K  n" p4 e, L% r" J
#include <STDLIB.H></FONT></P>
! q2 ?, `" P3 v, L) F4 t<P><FONT color=#0000ff>struct ITEM {
% f, L$ q% ]- m: V4 E7 f! R  a/ i2 Lint key;
4 ?. e+ T6 D; C# @2 lint value; 7 W" r: a, O- a1 _: u1 J
}; </FONT></P>
! u2 \# K' j8 `7 i' d& t' Q<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
" J. d+ F0 W. t8 Dvoid additem(struct ITEM *itemptr) {
/ O8 v; t2 ~! k9 M  M) B- I0 Vassert(itemptr != NULL); " C7 t0 e0 d( b, G1 l; L5 ^" j$ `
/* add item to list */ 8 @: Z* k! i1 u' E% A9 N/ A
} </FONT></P>
: o5 [8 c- G' g2 C8 b9 [<P><FONT color=#0000ff>int main(void) / q7 W9 _8 W. G! H. C8 ]
{
" k" T4 m" Q9 R- W- p8 V: L( cadditem(NULL); . k, a$ h% @/ c0 Z$ L" n3 O( `
return 0; 2 v$ }" K0 z1 ~0 R0 m1 S$ j: z
}
1 B8 N8 \. P' _$ ^% r4 W</FONT>0 ^' C* `* z* W. H

( `5 w; _% x0 k6 y</P>
& ^9 x3 K+ q  Z( x5 Y* @7 }% P<P><FONT color=#ff0000>函数名: atan </FONT>
4 F/ Q/ ]5 g7 \# m+ b+ g& {功 能: 反正切函数
% ]1 q: V! Z  ~  T8 \5 w用 法: double atan(double x); 8 j9 G$ Y( s5 s; O
程序例:
! |( T, S7 \3 d8 h; C/ L<FONT color=#0000ff>#include <STDIO.H>
! W2 q' b; b: h6 }1 U' u; g( S* }#include <MATH.H></FONT></P>' ?- ]) ?3 @  d) I- h' \/ F( o
<P><FONT color=#0000ff>int main(void)
% j) X  i2 Q4 K. P{
! {) N$ j( u5 B- A) ~4 c0 O7 odouble result; * p* @) T. q7 o) ]
double x = 0.5; </FONT></P>
8 N! q5 j0 r$ h: T+ Y  T7 p4 }<P><FONT color=#0000ff>result = atan(x); # ~4 ]$ u( _& |% f8 A# c: h
printf("The arc tangent of %lf is %lf\n", x, result); & ?0 i, A8 U* i$ r8 w" ?4 l
return(0); 3 |9 Q) M: [3 A- L; j5 k3 }
}
, s/ b  M' m6 k0 c: i</FONT>
! L- }! L( e5 d. i1 Y3 l  W</P>
' B! G) M* U1 t! ~) K<P><FONT color=#ff0000>函数名: atan2 </FONT>
0 |$ L7 [  X% G6 z$ ~功 能: 计算Y/X的反正切值
, U& f5 F( @  `用 法: double atan2(double y, double x); ! |9 }1 F( y2 x) e9 z( M$ P8 r3 i8 T" B
程序例:
8 p( q  k7 c% n5 I7 t<FONT color=#0000ff>#include <STDIO.H>
9 n) Y& N3 n6 K4 u- m#include <MATH.H></FONT></P>
3 g& T; \: {- h3 i4 I8 x8 P<P><FONT color=#0000ff>int main(void)
2 b! q, ?7 N4 P4 |4 @* ?* q{
4 M+ i4 ]+ O* |/ Q. A- {0 idouble result;
/ I5 z* |; C. Pdouble x = 90.0, y = 45.0; </FONT></P>; o4 _; R/ K& g% r1 @$ z- z+ W
<P><FONT color=#0000ff>result = atan2(y, x); : c3 e1 \  }. \7 D, f+ R- `- a; z& T
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result); & W  _0 ]) b4 L0 U
return 0;
# H/ R2 f4 l1 d8 A0 Y} 4 r4 i, T) R1 ~! N* q3 }1 e
</FONT>
9 b( T- {. N/ P: U/ t) `  W; I: a</P>! F& `* G& H/ J2 e! @
<P><FONT color=#ff0000>函数名: atexit </FONT>
1 ~, e2 r- w" K- o' j% q) S功 能: 注册终止函数 2 M: j; D" H0 x+ V5 x
用 法: int atexit(atexit_t func);
& W6 F! ^: G0 Z& y* m  I程序例:
' q% g: M7 r, B8 w3 s<FONT color=#0000ff>#include <STDIO.H>
2 c* `5 l4 f/ w$ |9 i7 @9 h#include <STDLIB.H></FONT></P>5 O' S5 d# k9 o. M9 I
<P><FONT color=#0000ff>void exit_fn1(void) . H, e0 c" l7 C7 x( u! f3 o
{
( x* d- j$ i* l, f# mprintf("Exit function #1 called\n");
3 n6 H! S8 O. \5 X} </FONT></P>
, n( \0 I; t# w# j1 o<P><FONT color=#0000ff>void exit_fn2(void) 6 V& @0 K: h2 d* c( f7 h
{
# F4 }0 k1 K& N% D2 j9 @printf("Exit function #2 called\n");
( u" L) @8 j& u1 O) b, E* j} </FONT></P>0 j. T, J# e0 R( \
<P><FONT color=#0000ff>int main(void)
$ T" f3 V* h  s$ j" Y{ ; U$ ~6 }$ [: V" R- }
/* post exit function #1 */
+ s( w  `' u6 j1 E% r- e+ qatexit(exit_fn1);
, A8 p/ i$ ~9 G0 Q/* post exit function #2 */ 4 S# A* ~+ x$ N
atexit(exit_fn2); / l9 G/ u8 k  m
return 0; 8 Y4 [  h7 J' z4 w  a7 {
} & a1 J+ b+ E; i( i% C$ `
</FONT>3 b& ?5 ]+ i, T. z( ?4 ]
% z' [0 [/ c+ X6 @. h
</P>
, R5 e4 X8 _  d6 ~8 l<P><FONT color=#ff0000>函数名: atof </FONT>
7 ]* O- x; r$ N. h, q, `: E功 能: 把字符串转换成浮点数
# `6 c5 T% m7 y5 t用 法: double atof(const char *nptr); # q) n1 J. O! N  y# L# J
程序例:
" F+ o& l! b6 {0 W, x; J: l3 b0 I$ [<FONT color=#0000ff>#include <STDLIB.H>4 [3 ]" a. x  A9 C( Z% W
#include <STDIO.H></FONT></P>) ]4 Q/ o! k5 G" S6 H4 d
<P><FONT color=#0000ff>int main(void) ) g# H& N) y% `4 c8 f
{ 7 D9 T5 b$ r! j
float f;
5 _* `' {: q8 ?char *str = "12345.67"; </FONT></P>2 f4 ^/ O( ?4 }1 N0 `/ f" ~
<P><FONT color=#0000ff>f = atof(str);
" i+ g. U6 B' fprintf("string = %s float = %f\n", str, f);
, M  C$ I- l5 ^$ W0 Nreturn 0; + `0 a7 q2 S- `" Z) N2 L( y
}
% v: a2 T  t$ J  m5 Z7 f</FONT>
, o; a% P2 }* B" n( S3 Z1 V& c% i- s</P>' K5 o/ \$ m6 |' D
<P><FONT color=#ff0000>函数名: atoi </FONT>
* x% h" R1 s. j1 \7 C& f功 能: 把字符串转换成长整型数
" V& w( a7 i$ G2 o  e- v用 法: int atoi(const char *nptr); " r  N: ^& `& H" \' W8 v! k
程序例: - w& a) \  S; |% `& @) A9 o
<FONT color=#0000ff>#include <STDLIB.H>
9 s2 k3 S; W- R: u0 X#include <STDIO.H></FONT></P>
5 S! ~' m; Q4 y<P><FONT color=#0000ff>int main(void)
9 F, i' K4 v2 _- h3 \% N: _{ 6 D' R: F! d8 I8 p6 g! ?  J% w9 _
int n;
, a. c; Y2 M6 v6 Rchar *str = "12345.67"; </FONT></P>5 O5 j- }' d5 V4 N! x2 @* P
<P><FONT color=#0000ff>n = atoi(str); ! G8 ]& {2 R( f  Z9 p/ r8 i
printf("string = %s integer = %d\n", str, n);
' U9 a5 K" P/ ?3 Q! Dreturn 0;
4 s  B$ E9 `* m+ z  t$ |' a  X; m}
8 p* ]3 P. @9 a9 b. U$ v</FONT>/ S  R/ P' B1 }% Z: B5 g
</P>
; `8 v2 v, z1 K<P><FONT color=#ff0000>函数名: atol </FONT>
8 e: W, v; {4 |$ N8 P/ V, |1 S功 能: 把字符串转换成长整型数
8 A$ |' B8 D* k用 法: long atol(const char *nptr);
1 D, |* |* U# i5 r程序例: </P>
* H9 A1 b& \2 U% r<P><FONT color=#0000ff>#include <STDLIB.H>. v" ]$ T& c0 o3 m
#include <STDIO.H></FONT></P>
; r# r( {2 M1 G0 k$ c, Y" k) @2 V<P><FONT color=#0000ff>int main(void) + |7 j5 V9 ]" c: U) V* h# B
{
1 h0 S% ?$ [0 R6 R/ a4 w' E9 Plong l; 6 K! s8 L3 z2 g! f+ r* h1 Z) N2 a+ B" k
char *str = "98765432"; </FONT></P>' ?$ P7 Y5 |- `0 G
<P><FONT color=#0000ff>l = atol(lstr);
/ |' r2 `9 b8 {. Yprintf("string = %s integer = %ld\n", str, l); , g8 K( L5 I$ K2 t4 I% [
return(0); % h5 p, O- C" B  z9 E
}</FONT></P>
zan
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