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函数大全(a开头)

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发表于 2004-10-4 03:03 |只看该作者 |倒序浏览
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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P># s6 H1 d0 M" a7 L( d& T$ ?
<><FONT color=#ff0000>函数名: abort </FONT>2 M4 c6 k7 x- r% N, l
功 能: 异常终止一个进程
' }' ^0 G8 b/ b  @# y5 P用 法: void abort(void); 2 n+ A* y' x- R3 J' _  Y
程序例: & T* W" ]" i: j, }# X. I
<FONT color=#0000ff>#include <STDIO.H>
$ {5 g  h5 p) P" c' x- P#include <STDLIB.H></FONT></P>
! m: R; O2 u3 |& R& ]( N2 A3 O$ ^& b<><FONT color=#0000ff>int main(void) 0 v, ~# V) Z+ H; _( }
{ 4 s  ?" z; m- l& t  \% X  d  G* k5 N: ~
printf("Calling abort()\n"); ; K: D( ~" Y! k( O( O
abort();
% {( I$ y/ z7 T2 y7 ^: _' Kreturn 0; /* This is never reached */
# o2 A) i* J3 `; U}
- y7 A% q9 f! Y6 m- h# P) ^</FONT>
1 ?1 z  Z) z+ b7 U9 B* T, L0 P3 a) T</P>2 ^: @. ^) D/ T. T* A' {3 i1 k
<><FONT color=#ff0000>函数名: abs </FONT>
4 h0 [, [! P# W. [功 能: 求整数的绝对值
( M2 q- a8 B9 q用 法: int abs(int i);
' E5 S5 E, x+ b! r2 k' V程序例:
5 C% \) C; R$ B* x1 O. l<FONT color=#0000ff>#include <STDIO.H>
$ y: I2 {# O( e" @4 w) @) ]7 W' ?#include <MATH.H></FONT></P>, Z1 D/ U/ R  C- ~5 j( S" P& O
<><FONT color=#0000ff>int main(void) 6 d- B" c5 ]% G7 p1 a/ d/ l
{ : o5 N' q: Z9 ^6 o4 E2 z  N
int number = -1234; </FONT></P>2 L, M7 k5 O8 u2 G7 r
<><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number));
& [. [0 a5 g: p& @* greturn 0;
, b3 O/ h6 ?# g} 6 ?# Y9 p  ?7 _) j3 T
</FONT>
+ h8 C" e- Z3 s6 x2 w</P>. b1 {, k# q; l" C7 n5 Z
<><FONT color=#ff0000>函数名: absread, abswirte </FONT>
  ^( H  S, D: O' N% ^% s7 }& `功 能: 绝对磁盘扇区读、写数据 9 U* `: I3 g" M7 Q! E
用 法: int absread(int drive, int nsects, int sectno, void *buffer);
+ r3 J+ o9 [8 p$ u! E5 U8 E! Hint abswrite(int drive, int nsects, in tsectno, void *buffer);
3 u! Q8 ^* }0 t1 q程序例: " `+ X# B3 i' E; p5 P
<FONT color=#0000ff>/* absread example */ </FONT></P>7 u% K- h# a% l' ^/ V7 g; x
<><FONT color=#0000ff>#include <STDIO.H>/ F: p/ b  o# B! [0 X: z$ l- U
#include <CONIO.H>- U5 O4 |4 U% U% @2 V9 D
#include <ROCESS.H>
* ~, }& ^# y, |$ w' E4 z7 _#include <DOS.H></FONT></P>
, d$ V; i- L. k' z<><FONT color=#0000ff>int main(void)   \5 L  P1 q% A, p( v
{ & Z9 X" K" {$ k8 a2 y% U1 f! l
int i, strt, ch_out, sector;
* `4 k+ p# Y0 t& A  S4 L  tchar buf[512]; </FONT></P>
" q3 y  e7 n' G+ \  y+ u<><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n");
# f+ x3 q; a$ I8 mgetch(); 4 j2 ]% a& l. m( C% g
sector = 0;
, `2 G# e& s+ Z/ @if (absread(0, 1, sector, &amp;buf) != 0)   h, P) ?6 M0 g  D
{ - W) C# p: o# l4 S# i2 `
perror("Disk problem");
" [9 h- @3 I6 l: Aexit(1); 2 g1 H! F" _: e5 U9 ]
}
) k; N0 Y, m, i) Bprintf("Read OK\n"); . _% C+ e1 z  ]! _' @1 K( h2 |% v
strt = 3; 1 I1 [+ D: M( M' v9 A
for (i=0; i&lt;80; i++) ! r7 L/ {' V- }
{
2 R* f" F9 T7 e+ F( a, s- Lch_out = buf[strt+i]; 9 @- y, u* J" w' q( s
putchar(ch_out);
8 h: B7 b  E) q6 _" m+ E}
2 E- A. U. I5 b: C, y- @printf("\n");
4 S% x0 S; z5 g9 `5 |return(0);
: K4 L0 P$ Q+ I4 z- o! a}
8 M2 F7 _$ Q7 h" d6 b4 u</FONT>) g+ J5 ^8 r! \* g, k6 H  x  ?, r
( g- T# c! e# A- E6 \8 [
</P>
+ k$ }* Z4 R! e( j# Z% M0 b<><FONT color=#ff0000>函数名: access </FONT>
) A1 s" K( t+ S* V) Z; ]4 u* ?功 能: 确定文件的访问权限
2 Z! D! ?: p- m8 c6 J" y: S用 法: int access(const char *filename, int amode); 1 Z' A$ N4 \4 u! z2 _* i
程序例:
: c' x4 n, @* _9 Z1 a' M9 l<FONT color=#0000ff>#include <STDIO.H>
. e  m. j2 G( c( E* ~) I) w0 l#include <IO.H></FONT></P>
9 i8 M7 P- T: i$ ~1 M<><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>6 Y1 U# |3 F3 E+ a0 k& E9 b- z
<><FONT color=#0000ff>int main(void)
% S5 F1 y  j: T/ b& G{
6 n3 V' C  `7 B: W! J6 b0 f7 Gprintf("Does NOTEXIST.FIL exist: %s\n", 5 ^, s, `& [* ~3 E' M* P, Y2 f: @
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
' P# G; F/ ?1 `: v* xreturn 0; ( I# v4 I+ ~# L% o& B9 k: n4 `
} </FONT></P>
, t) s  k0 S& b( u: l) E7 s<><FONT color=#0000ff>int file_exists(char *filename) % @' J3 w$ V6 @+ _
{
* u" E8 `  {6 Z% creturn (access(filename, 0) == 0); & f3 ~9 Z9 {2 q% v" X
}
+ O: K5 `2 b- p+ c</FONT></P>9 `& X: F. w0 f
<><FONT color=#ff0000>函数名: acos </FONT>
- g7 p. R( t1 n4 z* e" f功 能: 反余弦函数
+ h" J  n( s2 A1 J+ L' D用 法: double acos(double x);
' Z  v1 S7 s; ^/ j9 p程序例:
- a2 {" o7 a$ k  V7 `& Q2 p<FONT color=#0000ff>#include <STDIO.H>
. Y7 C4 }) Q* C" `8 r' L#include <MATH.H></FONT></P>
. A% Q* A# Q* O: m6 q<><FONT color=#0000ff>int main(void) % C+ m! c; S. H6 ~
{
( @$ ?6 R# n3 a! N) @double result; % x/ n1 M" i4 J! R* \" _! H* v
double x = 0.5; </FONT></P>
! }/ b$ Q3 y/ D) X6 W0 G6 d<><FONT color=#0000ff>result = acos(x);
6 l# m  u6 F5 {: Yprintf("The arc cosine of %lf is %lf\n", x, result);
  f7 _) ]- Y4 R* ^6 ?5 Nreturn 0; ) A; Q, M1 g$ ?0 i3 e9 A
} </FONT>
' h6 p9 L0 l8 I8 \' D1 ]& ]* s; b
</P>
4 z3 i. Z% L6 m8 R$ p7 t: _5 h<><FONT color=#ff0000>函数名: allocmem </FONT>
! w+ Z  B7 y4 k8 l" r功 能: 分配DOS存储段
. j4 T5 }. ~. I$ N% E  \- S5 d用 法: int allocmem(unsigned size, unsigned *seg);
8 C4 p/ x) J+ C+ O+ r' O8 R程序例:
2 s2 ~0 _! W6 z" T% ?0 C<FONT color=#0000ff>#include <DOS.H>9 ~+ I; M, d! V# Y$ ]0 c* u* _
#include <ALLOC.H>
. @' p+ l* K6 l; R  c2 _#include <STDIO.H></FONT></P>
8 q: H' P6 w% W5 @, x<><FONT color=#0000ff>int main(void) 8 U4 d. l6 A' O: {
{
& F, T- B4 s7 U1 j2 o  cunsigned int size, segp; 5 M) H$ p) `: E) ^
int stat; </FONT></P>* J& \2 `5 f# k. |6 D9 D
<><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ 3 H# Z2 X9 h9 ~9 L) v
stat = allocmem(size, &amp;segp);
6 |0 ?+ b/ ?& Z5 `1 j* u% ~) k, ~) Jif (stat == -1)
+ F6 Z2 j: @" t, u; H4 O7 U  k4 R7 Iprintf("Allocated memory at segment: %x\n", segp);
- `3 h0 m9 J  S% w+ ]3 Aelse
7 A; O3 f! V- r  K4 V* R- Sprintf("Failed: maximum number of paragraphs available is %u\n", ; w5 p, i$ h; m' l
stat); </FONT></P>& R& `0 {0 p3 G: I9 }/ f2 m1 o
<><FONT color=#0000ff>return 0;
! _: m/ _, G$ O5 B' W7 {7 r& f} </FONT>- I& _! L3 k. `# ]

) j9 g, T) f1 ?' t</P>
' s( t4 W. a" U. f) _* u( s<><FONT color=#ff0000>函数名: arc</FONT>
: l: T8 ]8 p& U功 能: 画一弧线 0 [9 P; s8 h7 G; z6 |
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
* A$ j( L' b0 E/ ]1 f# _7 t7 d程序例:
3 [# C# ?8 i$ i! C<FONT color=#0000ff>#include <GRAPHICS.H>
" d* _* d7 I7 d- j#include <STDLIB.H>; u" t) F; O) T! L* r8 p
#include <STDIO.H>5 p& N$ _* t& q5 L, t7 H3 X
#include <CONIO.H></FONT></P>
1 R4 q! u2 C+ D9 c. J  i* k# }<><FONT color=#0000ff>int main(void)
" |9 o2 {1 e1 I{ . w' N, p+ f# P8 W2 X# `& L4 k9 t5 T
/* request auto detection */ # r0 T" U6 O) S5 i6 o! X& i
int gdriver = DETECT, gmode, errorcode;
" \) ^, ^6 ~$ w* X! M0 ?5 tint midx, midy; 9 d% i$ S$ m; }1 k, ?! ^
int stangle = 45, endangle = 135; , w. ~0 e9 i2 d! p5 C2 Z  o( |
int radius = 100; </FONT></P>
/ s% c  `5 m1 g) M3 [  _& F<><FONT color=#0000ff>/* initialize graphics and local variables */ 2 c* p- Q# q/ t* \( D
initgraph(&amp;gdriver, &amp;gmode, ""); </FONT></P>
; f8 L/ q3 g; ?" \0 m' [. ^# v<><FONT color=#0000ff>/* read result of initialization */ 8 L: `' Y3 m( w& J
errorcode = graphresult(); /* an error occurred */
* y1 s$ y8 P  L5 F0 v% n( D* e4 C  gif (errorcode != grOk) * ^* b' \' r) u  `
{ ! O# b8 g& M3 B2 Z: Q" V1 S
printf("Graphics error: %s\n", grapherrormsg(errorcode)); 0 J+ O8 {# n# E) s' a6 @3 U7 q3 d
printf("ress any key to halt:");
5 d& }  ~: `0 c( d3 \4 ygetch(); </FONT></P>& k1 O( k% @' S' I
<><FONT color=#0000ff>exit(1); /* terminate with an error code */ 5 r( ?4 x8 q9 O% B8 {- s3 F- y
} </FONT></P>
% K1 H2 E) p) X) {5 @<><FONT color=#0000ff>midx = getmaxx() / 2;
0 [; P& E8 V$ d% x: dmidy = getmaxy() / 2; 0 t& o1 L1 V0 C& b/ s
setcolor(getmaxcolor()); </FONT></P>9 I& F* z" A/ E, G2 x; `
<><FONT color=#0000ff>/* draw arc */
8 k. S- d: i) j8 C% R. J$ g8 marc(midx, midy, stangle, endangle, radius); </FONT></P>
% M8 B' G/ g5 f<P><FONT color=#0000ff>/* clean up */
; a1 T/ e5 i: |! d1 x8 sgetch(); : s! v% r$ a- |' Y! ?
closegraph();
2 _6 u# a6 ]; Y. ~. k7 J+ C& Oreturn 0; ( c4 R! x- q8 G2 P+ B! s; Q
}
4 a/ a. _/ l* x+ F& [& N</FONT>+ L2 G0 o$ m/ Q8 s) D
</P>4 g3 L2 `3 V* _( n- I( P% U
<P><FONT color=#ff0000>函数名: asctime </FONT>' m: e; x# d% C) @5 k
功 能: 转换日期和时间为ASCII码
  I* q5 b% i& t: s$ v; N# j用 法: char *asctime(const struct tm *tblock); 9 K& t; |( D, F1 k1 t& p
程序例:
* g# t& a7 z+ ]<FONT color=#0000ff>#include <STDIO.H>
2 |2 M& ^- a& p#include <STRING.H>, b0 e5 N2 ^. L/ s5 t( J3 ^& p
#include <TIME.H></FONT></P>
, b: J. p5 e! C9 ^: h<P><FONT color=#0000ff>int main(void) 1 K( J2 z  i& ~0 o- ?# E& s! j! \8 j
{
; V, N) h5 N' J" k- K: }struct tm t; # u3 S/ C6 I! G; v: Z3 L) s
char str[80]; </FONT></P>, D) k5 x8 j, `) G& J( |1 ^1 P" S9 g, l
<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>2 j. B* F4 g, p% }
<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ ( Q( L: V6 o) |9 |! @
t.tm_min = 30; /* Minutes */
2 \: y+ K7 {1 c! ?t.tm_hour = 9; /* Hour */ ) _) g7 s: U9 @
t.tm_mday = 22; /* Day of the Month */
) `) ]; g* D% m. W% T7 ?5 r* S) \t.tm_mon = 11; /* Month */
: Z3 S6 D3 I; k1 V; _' A" nt.tm_year = 56; /* Year - does not include century */
+ I9 V9 P! M, l1 w$ dt.tm_wday = 4; /* Day of the week */ 8 U+ {# o$ |& _
t.tm_yday = 0; /* Does not show in asctime */
, w, e3 p9 H/ R. S6 P; Tt.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
8 ~/ y9 d9 @6 }; x<P><FONT color=#0000ff>/* converts structure to null terminated
- s/ i$ N+ ?% J7 Qstring */ </FONT></P>
& R2 {4 E! U  t( l<P><FONT color=#0000ff>strcpy(str, asctime(&amp;t)); . c2 U- O" T: ~1 N+ ?' K! l
printf("%s\n", str); </FONT></P>
) X5 J2 L6 F/ F+ b2 ~<P><FONT color=#0000ff>return 0; 2 `  ], T- \. u# X3 G8 [! m* t7 y
}
3 g! Q" `$ f6 G' W4 q
3 [# o' q" I) @" A) L/ e+ G8 D/ t6 G</FONT>& z# _* D3 M& @7 L3 m) Y1 u
</P>  H5 @, c4 g. ~, D6 q
<P><FONT color=#ff0000>函数名: asin </FONT>
+ @3 A) ^) M" B4 x* f1 n0 F" ]功 能: 反正弦函数 & C( ]& V$ U) _' e0 W
用 法: double asin(double x);
; }# o6 s1 d& M7 ~( h" Q程序例: % L+ ~+ R+ C1 z8 Z: B8 ]0 @" c  m! |
<FONT color=#0000ff>#include <STDIO.H>
5 M" f$ q- C5 B- ^#include <MATH.H></FONT></P>
) P+ ~. f' b- a+ J5 y<P><FONT color=#0000ff>int main(void)
9 p# G# D- a' Z8 v{
2 _8 M- j0 ?+ h. C4 n8 Q: J7 Q1 ]double result; ) g2 f7 f' S3 E0 w
double x = 0.5; </FONT></P>
' r' `( W+ z6 `7 U' o+ H  ?4 S<P><FONT color=#0000ff>result = asin(x); 3 q" s; z2 I! r4 A: H, ]. P- h
printf("The arc sin of %lf is %lf\n", x, result); / i" e- o5 `; ~1 V% N* @
return(0); ' c; K! a2 @& g& I# E& N
} , i- h, W+ P( E
</FONT>
! e' i  r( O1 X( l+ l( W  {5 x' I1 J& M0 ~9 ]3 K/ s
</P>( \( W+ Q+ q6 h" T+ }
<P><FONT color=#ff0000>函数名: assert </FONT>
% u2 c" _0 f+ j5 Z2 |0 C, ~: q功 能: 测试一个条件并可能使程序终止
% q$ q/ U/ z: J$ ]6 V/ \用 法: void assert(int test);
/ @; h, y! N( y8 i程序例: 1 k' i( ^" @, z. k
<FONT color=#0000ff>#include <ASSERT.H>
2 }4 r. ?. ^' d1 M( H; v#include <STDIO.H>
, Y5 q0 [  H$ d4 @#include <STDLIB.H></FONT></P>
5 D, d$ \* \; e" {$ C<P><FONT color=#0000ff>struct ITEM { 6 h9 |. j% V  y! m9 X4 G8 B2 v
int key; 2 Y+ ?1 C8 u( k: B) A1 D' K5 p
int value; / l1 C: ~! V1 O) O0 g2 e3 {- T. w
}; </FONT></P>
7 M9 r8 \) _# u9 O# S6 _<P><FONT color=#0000ff>/* add item to list, make sure list is not null */
- @0 i# U9 E( D' T4 i8 dvoid additem(struct ITEM *itemptr) {
: s" d- l) |0 P/ B/ g5 Vassert(itemptr != NULL); ' [: u+ a# m- |" R
/* add item to list */ 6 T/ D6 j) W/ J! m+ I
} </FONT></P>+ D1 Q1 x, b$ k2 C* H
<P><FONT color=#0000ff>int main(void) ! G% `2 a" D' e8 U( Q! p" Q
{ & x1 D; D! N- b
additem(NULL);
* }/ \- ]# ?: b1 V, Y! n/ x" w! Kreturn 0; / o/ V1 S- p, o$ B% r2 T# y
}
; l5 e# Q. O8 m. z2 H$ c</FONT>3 k. |0 C; \+ [5 q

$ B: ]$ q$ f& F5 d; g8 b</P>% R% U( g' v5 w: H  }+ n) |
<P><FONT color=#ff0000>函数名: atan </FONT>
+ L! Z9 P* F* l7 ^7 ^功 能: 反正切函数
- c2 B, I: n$ {  {用 法: double atan(double x);
  w6 ]+ h  f/ i5 V' {; W: S! c6 h  l程序例:
. i  \( f; q0 i& C; b  f, X* D/ k6 h, D3 X<FONT color=#0000ff>#include <STDIO.H>) f% ?, ^& M2 U( o! s' k* N* s9 b
#include <MATH.H></FONT></P>6 |: u) Z8 }7 }4 P* L% m
<P><FONT color=#0000ff>int main(void)
6 s' t+ J6 @! ^{ / D4 Z: V4 H2 U) d" n% }# j
double result;
; M5 T5 L. w# |' T* ]. qdouble x = 0.5; </FONT></P>3 _0 @/ H0 |$ T. z9 E/ m
<P><FONT color=#0000ff>result = atan(x);
: {/ c7 J; I! q( g/ P% ~8 c: Iprintf("The arc tangent of %lf is %lf\n", x, result);
. f4 d( @" a( y; k* ?" y" M: W! C6 z' Dreturn(0); + x/ c+ }1 c! H/ A: b8 s
} 4 k0 _1 |4 l) h0 p# }. P5 ~# ?
</FONT>
2 _; t; @6 w. Y+ m6 Z/ Z, F- [( M</P>
) w* v1 u2 W: p( S, Y6 r6 [: Z, _$ Z3 d<P><FONT color=#ff0000>函数名: atan2 </FONT>
- C6 v7 r+ s  ?; A6 v, V功 能: 计算Y/X的反正切值 6 f/ s' [" ~# G" u1 a/ K1 S
用 法: double atan2(double y, double x); * k6 h/ f, {# f
程序例: & [/ @: q" V) T# w/ Q
<FONT color=#0000ff>#include <STDIO.H>
. ~  x' V  {+ _  j# U4 A#include <MATH.H></FONT></P>
9 Z  h& g) }! x" m<P><FONT color=#0000ff>int main(void) " e0 f" y$ w6 R8 b8 w0 a$ v
{
" r6 b+ @" Q' }7 l$ xdouble result; / I* l1 Y. y& i2 v  f6 y/ G! f
double x = 90.0, y = 45.0; </FONT></P>! N* @) s. @$ }: b# ?
<P><FONT color=#0000ff>result = atan2(y, x);
7 K/ M/ E- K; P( F8 uprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result); : u9 R/ r, q& a6 U; `8 I
return 0; 1 k  Q3 S$ B# F; _' J" Z* M6 y
}
- C5 {# _1 H0 I8 x1 V; z- c</FONT>* E* x8 g6 l3 t) G' _  N
</P>8 ?5 R: w* @! {, `
<P><FONT color=#ff0000>函数名: atexit </FONT>/ A" D) l" S# Z( f& L$ h; v
功 能: 注册终止函数
$ i+ k8 T" X6 @. J用 法: int atexit(atexit_t func);
5 `( C8 O8 O7 t6 x/ W. |程序例:
6 z9 a1 n9 A2 c4 b, w. E. [<FONT color=#0000ff>#include <STDIO.H>/ L7 {$ d$ ?/ |) G
#include <STDLIB.H></FONT></P>
( J8 K4 \) s: K) P<P><FONT color=#0000ff>void exit_fn1(void)
+ d; O( S- T! A9 v& R( Z; Q( i{
5 W8 |) o3 J1 }, d/ d. Y. jprintf("Exit function #1 called\n");
1 @; x& d7 e  d& a} </FONT></P>
+ M7 J+ ?( d+ f- m; r<P><FONT color=#0000ff>void exit_fn2(void) ( O' x4 H1 M5 W
{
% b1 |; J: X/ S  Q2 a" C+ I% Qprintf("Exit function #2 called\n");
& }4 @2 C' I' w4 D4 _) t} </FONT></P>7 O( S5 g- Y5 f( F8 \
<P><FONT color=#0000ff>int main(void)
+ V& z7 }5 L8 ^* a{ 2 c# U7 x3 u; b+ N3 B
/* post exit function #1 */ $ R' i" ~2 L" O9 d& R* s2 t
atexit(exit_fn1); . A) k, Z5 E' r! ?1 K
/* post exit function #2 */
0 O8 y* d- _6 X1 u/ natexit(exit_fn2);
) X4 X" n/ ^5 S7 G6 y, ureturn 0;
% M7 Q0 A- s; x1 t% W+ Q}
3 E9 w( o- d9 c" f% z</FONT>) J( r7 h' N( j5 T/ K+ z
# T2 ^( Q4 c1 |2 O  y0 z( [
</P>/ [/ I2 U+ |9 G; p, B$ v7 v* h
<P><FONT color=#ff0000>函数名: atof </FONT>
$ T0 ~; b  B% y& |; V7 \, h功 能: 把字符串转换成浮点数 + {- j4 m7 A; {1 Y( ~2 e4 t6 Z
用 法: double atof(const char *nptr);
# m( w( W1 ^7 u- W, }1 j- P7 `; e程序例:
3 \9 O3 q" q6 y4 a+ g, _2 u0 o<FONT color=#0000ff>#include <STDLIB.H>) }. s- r2 _/ ~$ h' J
#include <STDIO.H></FONT></P>% v  ~1 p" ~; ^! F/ Q
<P><FONT color=#0000ff>int main(void) 3 l  L4 S+ ?0 H1 ^" u
{
' c8 t1 {' i6 Q1 K) A! g: wfloat f;
" J/ _$ X- Z6 _char *str = "12345.67"; </FONT></P>
; g# d  M. |9 l& L8 t* `<P><FONT color=#0000ff>f = atof(str); . }# X  a; e& Z! |# _: {
printf("string = %s float = %f\n", str, f); % a5 V0 z3 l+ b! l2 K# G
return 0;
0 I) H* j! B7 L8 n5 @! A}
4 P8 }4 B& R, u8 f, M</FONT>! w+ U9 b5 a9 C6 r8 r
</P>
3 U+ D7 c; ?% C6 |2 ^<P><FONT color=#ff0000>函数名: atoi </FONT>$ ?0 ?2 n6 g$ ~: I# M8 P8 z4 S
功 能: 把字符串转换成长整型数 # c7 S' \5 S6 ~$ Y4 j5 u/ _
用 法: int atoi(const char *nptr); 8 V2 B; }' {; W/ w- `/ m
程序例:
. Q) F0 q+ `* s7 F" w/ W, |3 Q<FONT color=#0000ff>#include <STDLIB.H>
' x2 d% s4 f; [4 g  ]! d" c# n7 e( p#include <STDIO.H></FONT></P>! h: E. }/ C' H9 L9 z+ N. t
<P><FONT color=#0000ff>int main(void) $ C) F0 i- x' p( @7 [; O0 E
{ ! u' R9 t3 s. v3 p
int n; # e7 [0 c. u3 ~( L0 {
char *str = "12345.67"; </FONT></P>
* t3 R, ^% Y1 u% x7 h<P><FONT color=#0000ff>n = atoi(str); . V! [; }1 G% G0 R8 g
printf("string = %s integer = %d\n", str, n);   b! a! m3 q) ]' G: x  h
return 0; 9 p# B; q& J/ L
} ; r! o3 B' C" ?5 [8 o7 W
</FONT>4 u  q3 a9 Q* b: f+ b# |
</P>
& `, Q. j! `8 l$ a5 `2 r" i<P><FONT color=#ff0000>函数名: atol </FONT>
. |/ u) q2 |+ N功 能: 把字符串转换成长整型数 $ ?% h* k3 P3 `/ h
用 法: long atol(const char *nptr);
7 v5 e% G- W, k7 N( L0 O5 {/ C程序例: </P>6 K: S' `9 G- Q: c# S$ Z  g
<P><FONT color=#0000ff>#include <STDLIB.H>' M7 |% d0 u3 m0 R
#include <STDIO.H></FONT></P>7 {* D" A. Y  N( q( _( C
<P><FONT color=#0000ff>int main(void)
% x5 a$ O5 M  I; Y* g{ # h" \3 q) Z8 ~
long l;   n/ A4 |& ~& P. \
char *str = "98765432"; </FONT></P>
/ ?$ n/ V& y  z+ g, e( e. b( k" E<P><FONT color=#0000ff>l = atol(lstr);
6 L8 T2 h2 B. d0 j' u7 Cprintf("string = %s integer = %ld\n", str, l);
2 d; y) c2 H7 ]3 F9 U5 o! _. @return(0);
7 d9 |. a8 o5 G}</FONT></P>
zan
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