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< align=center><FONT color=#0000ff size=3><B><FONT color=#cc0000>函数大全(a开头)</FONT></B></FONT></P>
4 D2 z" x+ X3 M+ H1 E< ><FONT color=#ff0000>函数名: abort </FONT>6 H8 o2 z( t* e; o: F
功 能: 异常终止一个进程
6 k9 m: p: ~4 a8 Y用 法: void abort(void);
! P8 j- w& g8 L4 }程序例: - Z2 C8 P' G# U$ X7 Q
<FONT color=#0000ff>#include <STDIO.H>
6 f; D* C v$ m7 ]#include <STDLIB.H></FONT></P># w- W$ e0 D; \, H. z% v6 Z7 @
< ><FONT color=#0000ff>int main(void)
& ~$ q- t" ]2 h0 o" v1 q* E{
; d [% c2 n6 q% p8 Bprintf("Calling abort()\n");
7 d; q, Q$ }- p7 F: Qabort();
0 K& o% w4 g3 z% hreturn 0; /* This is never reached */
. U8 m4 k! r3 w$ U1 ]* B! z$ j}
/ B1 W, J. U( |) {; Q% e& L</FONT>' [1 s5 p. n! t) H- B6 |
</P>
0 p; @$ Y( R1 [0 p" u, q% e# m< ><FONT color=#ff0000>函数名: abs </FONT>
0 \. ^4 ^0 A. b K. H6 a0 g1 x; {功 能: 求整数的绝对值
4 B1 L; X6 X& T. z# N0 U用 法: int abs(int i); , L# b4 c4 K# q# W
程序例: ; T+ R+ ~8 c E) U \+ i0 n
<FONT color=#0000ff>#include <STDIO.H>
/ B" ~3 `: H1 L1 ]3 t( v#include <MATH.H></FONT></P>: _ @% C6 _ h0 y: w& k6 N
< ><FONT color=#0000ff>int main(void) 0 j" K, s1 t+ `8 l8 S* p- \# @
{
; N+ ]/ C! M6 Rint number = -1234; </FONT></P>2 M& i* Z# |$ m6 |
< ><FONT color=#0000ff>printf("number: %d absolute value: %d\n", number, abs(number)); . k; t2 E$ f/ e
return 0; % u. Y- n' w( R/ w( G
} $ Q. M# k! x5 R8 ?$ c" x
</FONT>: k8 f7 a {% `7 B- Z' M
</P> o" N: Y% [! t9 L* ?
< ><FONT color=#ff0000>函数名: absread, abswirte </FONT>3 K' y& u9 t- P1 E. Q
功 能: 绝对磁盘扇区读、写数据 * M) D1 S* D6 |
用 法: int absread(int drive, int nsects, int sectno, void *buffer);
' j. z+ v. V+ ~ a2 q, kint abswrite(int drive, int nsects, in tsectno, void *buffer); ' e- K$ E K9 I% r( m
程序例: 8 }5 Q r+ M4 w/ V
<FONT color=#0000ff>/* absread example */ </FONT></P>) G2 R% s8 c8 J1 E) [
< ><FONT color=#0000ff>#include <STDIO.H>
' v' E- x6 L: w1 ?3 U; H#include <CONIO.H>- \2 v s. }: C: Z9 X
#include < ROCESS.H> f* r! g: g3 j! \% T% a3 [
#include <DOS.H></FONT></P>* N, F9 E9 V9 `3 ]
< ><FONT color=#0000ff>int main(void) 5 \; L* G2 r0 f% e$ M
{
; I, ^6 \! `8 I( F, fint i, strt, ch_out, sector; 7 @. Y5 p$ _+ k) m) j
char buf[512]; </FONT></P>3 r3 r% A: @+ ^
< ><FONT color=#0000ff>printf("Insert a diskette into drive A and press any key\n"); ( V ~9 Q9 M4 n8 j! E
getch(); . ^# d- Y" E' `- S
sector = 0;
6 [. e* Z f4 nif (absread(0, 1, sector, &buf) != 0)
* p6 @& w& z6 @1 b* O4 {{
1 h, j* { v" g2 O3 bperror("Disk problem");
9 ]1 Y1 O' j9 A/ \0 @/ m# ` Nexit(1);
. E) H0 k! h$ N& d} 2 t2 |/ V1 b) w% U8 p- B+ D
printf("Read OK\n");
6 c1 e: y# x) p- L# fstrt = 3;
) x+ A% H# M) Q2 e% X# j' \for (i=0; i<80; i++) % P& Y; Q/ c- s/ t" h
{
1 F: h, G& y0 e2 v3 s$ Q# lch_out = buf[strt+i];
8 i- b9 \( j3 C. U+ ~& _putchar(ch_out); : Q' b" z& q" G% A8 |: Q7 z3 U% Q
}
" _) X- G: i+ S: Lprintf("\n");
+ q/ g* d3 D; ^5 s+ H* G9 |* [return(0);
7 r% F* m& ^/ N& s}
* x" o1 D( |: {9 `# {) d& v6 c( a</FONT>& p' R6 U0 `$ C/ P' X- z
; I/ O8 p: I; d2 P; }& S& r
</P>- S: f% T! U; U" R$ K5 T% X
< ><FONT color=#ff0000>函数名: access </FONT>
6 R8 ^' Z: ~: _5 \7 {% Q功 能: 确定文件的访问权限 3 T/ M2 e6 K1 E v/ ~1 U( t1 T
用 法: int access(const char *filename, int amode);
9 p, M8 c0 p: [程序例: - {6 v' P- @- A9 z" _& U8 E
<FONT color=#0000ff>#include <STDIO.H>1 S" A, d0 x. N1 E
#include <IO.H></FONT></P>5 X8 \" u3 v1 N8 d' i
< ><FONT color=#0000ff>int file_exists(char *filename); </FONT></P>
0 L; I" q O1 d. u/ z9 h y< ><FONT color=#0000ff>int main(void)
. f: Q; S& ^1 W4 Y, \* |{
/ P9 |' l& n$ w1 J# s! Bprintf("Does NOTEXIST.FIL exist: %s\n",
0 W4 o* @; h0 \, @% F- zfile_exists("NOTEXISTS.FIL") ? "YES" : "NO"); ; P2 S; {. Z2 g
return 0;
/ R& U& r+ g0 w7 g$ N# U} </FONT></P>; e0 W6 f1 A8 C
< ><FONT color=#0000ff>int file_exists(char *filename)
% P G0 S& v! \: Z- h0 h# F{ ' K' [/ ?& l; S- o) v& r
return (access(filename, 0) == 0); 0 _* L' \9 O1 P, v+ W$ ~/ ^
}
$ t3 {- B8 g- v# |2 L1 O/ G8 g</FONT></P>5 n' A" c p$ ^7 ~$ u
< ><FONT color=#ff0000>函数名: acos </FONT>
# ] f6 B( d0 m9 |8 G% i功 能: 反余弦函数 ' O G. M5 p. m% _; I* L- d
用 法: double acos(double x); # Q, A: X/ [ d2 h( n
程序例:
. I" q* c6 J7 }<FONT color=#0000ff>#include <STDIO.H>
4 Z0 r8 r; Q3 u6 x6 ]* t, z+ v#include <MATH.H></FONT></P>: Q2 t' t: `7 D
< ><FONT color=#0000ff>int main(void) 3 Y: T7 O) }; \4 Z+ w S
{ 5 r) K+ {9 n+ U" a3 Q( n3 Z) o
double result; 1 r, X2 @5 `- K2 |' H3 c& f' s# ?
double x = 0.5; </FONT></P>2 n8 C7 V/ I6 i) }8 ]! e
< ><FONT color=#0000ff>result = acos(x);
F- f) f% k( t9 cprintf("The arc cosine of %lf is %lf\n", x, result); % c+ d2 E5 y- f9 ^) p
return 0;
# u% j( v: _& l} </FONT>7 A- b6 V5 f3 r" y
# n% O/ ]6 M' V" j
</P>
- l( o, Q% c) W8 D8 T. K. k* o< ><FONT color=#ff0000>函数名: allocmem </FONT>
$ N; Y6 F- X) b) j功 能: 分配DOS存储段 , f: B" z; S; E4 D9 j- t1 J+ O1 K
用 法: int allocmem(unsigned size, unsigned *seg); 8 {2 U# Z& J) p- a! S$ j5 v- H5 p
程序例:
! n M- C# G: | F9 @% J$ o<FONT color=#0000ff>#include <DOS.H>
1 g9 |+ {2 m+ \, O7 S3 C#include <ALLOC.H>
. ?9 ~5 j& f4 E. Y5 B7 S#include <STDIO.H></FONT></P>
! U; O2 ~& O$ i8 b< ><FONT color=#0000ff>int main(void)
! e4 ?: V$ H" r& ^/ y{ 9 h( i) |: e5 Y7 }
unsigned int size, segp; 3 {- O+ ^) h* }# ?' D |$ q
int stat; </FONT></P>9 Z# U8 B8 H# H# ]2 g1 Y* a9 {
< ><FONT color=#0000ff>size = 64; /* (64 x 16) = 1024 bytes */ 5 X% R" C. @! C% [& M' |- h
stat = allocmem(size, &segp); " P& ~7 q( s/ H, h4 L' Q
if (stat == -1) 6 ]5 m N ?' G1 ?3 }! p
printf("Allocated memory at segment: %x\n", segp); ' h1 k$ D6 b9 w; O# P
else 3 {9 n0 `. z+ A3 a
printf("Failed: maximum number of paragraphs available is %u\n", " B1 B1 d3 r4 n3 w% w" c
stat); </FONT></P>6 `' i) S) p; a
< ><FONT color=#0000ff>return 0; 8 K" I0 m: Y7 }! R8 a {1 y, ^3 v. L0 A
} </FONT>
8 u) [+ @$ a# ^2 y5 I7 Z# {, t2 ?
( Z) B$ u7 ]6 A: T7 J. e</P>
, e7 p) D) [4 E8 _: l( W7 h< ><FONT color=#ff0000>函数名: arc</FONT> - L( o& U% O, _
功 能: 画一弧线
; n' ~& R5 O8 R用 法: void far arc(int x, int y, int stangle, int endangle, int radius); 4 r& y8 d2 H* u3 D% X
程序例:
0 e I9 v: W! t/ Z; \<FONT color=#0000ff>#include <GRAPHICS.H>
; }8 @$ U3 V/ @#include <STDLIB.H>% @) m% U3 E$ O
#include <STDIO.H>
& E4 T1 u* i! d- U/ L; o#include <CONIO.H></FONT></P>. K7 B% K3 _$ f4 S/ P
< ><FONT color=#0000ff>int main(void) ( X) y. f3 Y5 b# ]& ]9 C+ ?+ ^
{ 8 |& \) R- n' C
/* request auto detection */ 1 n: o$ d" _ Y; v6 w4 B
int gdriver = DETECT, gmode, errorcode;
) @* t N) m6 z+ w7 Iint midx, midy;
3 J+ e4 o4 Q6 [# \6 U' bint stangle = 45, endangle = 135;
% q' @( m% ^: Z4 k) b# |8 N$ y; Uint radius = 100; </FONT></P>" D/ A4 k( D4 y1 i% u% p4 y. S6 u% ~" @
< ><FONT color=#0000ff>/* initialize graphics and local variables */ 9 ~4 D- f, I: e5 c8 O
initgraph(&gdriver, &gmode, ""); </FONT></P>
! j& s( G* M# \! Z< ><FONT color=#0000ff>/* read result of initialization */ , E2 e* _! J& B) w
errorcode = graphresult(); /* an error occurred */
& b) C. ^, m0 ~) p, H/ d% k* zif (errorcode != grOk)
/ g5 u8 t8 }: T- x; K* z7 f{ : X w+ V0 V* t" C1 I+ n
printf("Graphics error: %s\n", grapherrormsg(errorcode));
& f% s4 C/ N: Y) y1 ^- Vprintf(" ress any key to halt:"); # \1 m4 |2 a% G& ~
getch(); </FONT></P>
Y- D* p3 H* O3 \! N+ ?< ><FONT color=#0000ff>exit(1); /* terminate with an error code */ ' z; L" X6 k& V! _9 B
} </FONT></P>$ p2 j) V! R3 Q6 A& ?* ?# z
< ><FONT color=#0000ff>midx = getmaxx() / 2;
$ ?2 T+ f) ]) ^& D! \! }4 j2 }midy = getmaxy() / 2;
; n9 P6 L. W& L6 H$ X* g. csetcolor(getmaxcolor()); </FONT></P>
( |+ `; B7 a+ @* S< ><FONT color=#0000ff>/* draw arc */ # U: O: B6 [, [! o# y6 k8 j7 [
arc(midx, midy, stangle, endangle, radius); </FONT></P>$ a4 f3 ]% a% A$ n: I% q# M8 v; [
<P><FONT color=#0000ff>/* clean up */ 0 ^8 c4 i- Z9 v* M4 k
getch(); ; @/ n3 K% L% |2 o4 a3 f
closegraph(); : z0 w) t9 T& C9 [
return 0; * r6 ]6 R/ {. p% ?" v
} 7 L$ B3 J+ R! a) {7 V3 J
</FONT>( J0 u& c- s9 H. ?6 C
</P> T+ A H" T4 R( |! w; i
<P><FONT color=#ff0000>函数名: asctime </FONT>/ N9 C5 D6 [- x8 P2 b( ^6 z
功 能: 转换日期和时间为ASCII码 + J( r- v8 I5 U- ?: ]
用 法: char *asctime(const struct tm *tblock); * ]& P Q4 P5 y" J5 l) b
程序例: , \( r% J& U3 _- T; f9 `
<FONT color=#0000ff>#include <STDIO.H>+ y, k' ]' q$ Q% b! s, o/ T A
#include <STRING.H>8 E/ V2 @$ ^2 I# v
#include <TIME.H></FONT></P>
9 s: j+ l0 G: o/ @' ]. q- ?<P><FONT color=#0000ff>int main(void)
" a) Q! D5 @% R5 c; B{
9 [( _. o# b1 i2 ^7 K8 jstruct tm t;
3 [; G" Q4 z- c6 g: echar str[80]; </FONT></P>
8 Z( B0 }& i5 a. w# Y4 l<P><FONT color=#0000ff>/* sample loading of tm structure */ </FONT></P>
8 u7 P4 X$ L6 e D8 E<P><FONT color=#0000ff>t.tm_sec = 1; /* Seconds */ & s. n& W8 _" ]" s
t.tm_min = 30; /* Minutes */ 3 i3 i. D% R5 F: {
t.tm_hour = 9; /* Hour */ $ |; ~4 K5 r) S Y) N& @1 [
t.tm_mday = 22; /* Day of the Month */
, c) A) a* w/ Z' X D$ v8 [+ g% _t.tm_mon = 11; /* Month */
- n( l$ X0 |2 |# v$ ]t.tm_year = 56; /* Year - does not include century */
( [, Z8 B+ o: g/ @t.tm_wday = 4; /* Day of the week */
1 c; @1 @0 E" F! z" } ut.tm_yday = 0; /* Does not show in asctime */ : \8 n) ]# G. \8 z3 m+ N
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */ </FONT></P>
6 R# o6 ?4 v7 F- S0 T<P><FONT color=#0000ff>/* converts structure to null terminated
6 k5 N' S/ t S w3 y6 Ostring */ </FONT></P>) U9 s( u& ^' ?9 W
<P><FONT color=#0000ff>strcpy(str, asctime(&t)); " Y* }0 i; V" d
printf("%s\n", str); </FONT></P>
, ~" f' l7 O" ^2 N( v* B+ S<P><FONT color=#0000ff>return 0;
5 s6 D4 p/ F7 f" G; ~: }+ a& X6 _} % s1 k4 N; N+ S9 |- k
: {' D3 [! e: {- B0 j8 o+ L2 v" g' D</FONT>9 \/ _' W. c" o2 }9 t
</P>
, |' D5 s) X$ N3 a3 @<P><FONT color=#ff0000>函数名: asin </FONT>
' p. A* K% ^" Q d功 能: 反正弦函数
6 F" D5 D% Z% q O# e用 法: double asin(double x);
) D d" h$ B0 y7 V6 i8 o8 j: k程序例:
+ a, ]$ G8 m# x9 p' n6 w0 i<FONT color=#0000ff>#include <STDIO.H>
0 L% q6 `) {+ S4 T( Z; {& B0 U! V#include <MATH.H></FONT></P>* s) B% A4 C" K2 _: f; x) o* m; ]
<P><FONT color=#0000ff>int main(void) ( q6 n7 @, m$ h. M' E/ U
{ : h2 a6 R: k, ^ g
double result; # t+ I3 h9 U! }+ ^5 T) f
double x = 0.5; </FONT></P>
" F/ j' v: J4 h<P><FONT color=#0000ff>result = asin(x);
4 m X0 h# E% u3 T9 B4 T/ ^printf("The arc sin of %lf is %lf\n", x, result); . S. M$ p- }5 p$ N9 X2 k, j
return(0); 8 D2 F" B# M3 ^- `% ]5 Z$ h5 T! P5 e
}
0 C5 F* {5 r0 F K/ ]+ f( O</FONT>
. k+ `6 r/ V& b
1 `" B; x# b4 O" w: ^7 c6 R8 L$ ^</P>
7 ^5 }' P. ^, D: [<P><FONT color=#ff0000>函数名: assert </FONT>
9 ^+ R& E r3 N2 V: G' z! }功 能: 测试一个条件并可能使程序终止
6 P: J5 C" e" T5 t# f# _+ a用 法: void assert(int test);
6 t9 k6 P) p) Q7 K9 Z程序例: 4 k; R5 x, P1 p) J- [+ u
<FONT color=#0000ff>#include <ASSERT.H>; a7 ?" k+ `; s. l0 B$ O3 C8 k
#include <STDIO.H>! ^9 ~& `/ k5 ]2 B3 h) ?* V4 a
#include <STDLIB.H></FONT></P>, @: K, {3 t d4 Y
<P><FONT color=#0000ff>struct ITEM {
& } A3 W7 [6 K2 e% C2 xint key; . Q) k! e1 u8 b/ D: ~+ T. v
int value;
* p3 n+ }6 u$ A' ?# V+ C}; </FONT></P>
9 m: } h& R- p<P><FONT color=#0000ff>/* add item to list, make sure list is not null */ ( [! k' e C9 o' G3 y2 [( G
void additem(struct ITEM *itemptr) { 2 h( B/ S' z& \9 o% T: E
assert(itemptr != NULL);
. n" M/ c4 u' F+ q/* add item to list */ 7 a! z- k! z/ t& h3 [) ~, s
} </FONT></P>+ Q M+ w- F% ?/ c# Z- O) x+ \
<P><FONT color=#0000ff>int main(void)
% O3 K" t$ z, E4 a{
' W6 k5 z x( s# N4 E4 k8 x. E7 eadditem(NULL);
% f( A( f( ?; J& v) W% Z) t$ ~return 0;
5 |. x G4 z3 s& k}
. D5 ]$ N" @8 S- d" \, y7 v</FONT>
5 `/ n! h- t! M. Y- p% L1 R. R$ U0 t7 [
</P>
) ]' i$ S. `. J, D V }<P><FONT color=#ff0000>函数名: atan </FONT>4 ]6 R. O1 h- Y4 [+ K! l
功 能: 反正切函数
' C B: f; n( T& k+ n5 m) E5 ?用 法: double atan(double x); @" }4 u: A. a' B3 k/ j
程序例: ! O8 R, B) F' B6 R. h- e, q
<FONT color=#0000ff>#include <STDIO.H>% I; K+ N: B2 A3 p! [
#include <MATH.H></FONT></P>' G3 k( R& I: `" a. s4 L+ K
<P><FONT color=#0000ff>int main(void)
* O {5 _: n& {% P* E9 V" [{
; a% _/ D) F- R2 v6 d% r, U' ?- h/ Pdouble result;
7 z; G+ `% `9 T9 i+ h# `double x = 0.5; </FONT></P>
$ M, ]& c0 Q ^" e! |9 Y<P><FONT color=#0000ff>result = atan(x); ' }, G) z5 K$ t1 Q; m, V3 p
printf("The arc tangent of %lf is %lf\n", x, result); ( p( q" ]' s2 n, F. S
return(0); $ J' G$ X1 s7 c& i$ A
}
u2 u6 t& O" Y3 |% P4 s</FONT>7 ^ v& y9 C1 F7 b1 F
</P>
' |6 H2 z0 E+ \ F% S" @<P><FONT color=#ff0000>函数名: atan2 </FONT>& {8 q6 u5 X: t9 O
功 能: 计算Y/X的反正切值 " c1 E& I- g% L" H
用 法: double atan2(double y, double x); $ m: ^. X/ f; c& U1 [ D* k
程序例: . E3 @6 X3 L4 G" O; w7 [4 Z# K
<FONT color=#0000ff>#include <STDIO.H>
5 r8 Z6 N% M8 l- r2 M a#include <MATH.H></FONT></P>
4 Y7 K B, B8 e- q$ _9 c$ l<P><FONT color=#0000ff>int main(void)
6 c8 T5 I" b% I& r{ $ h4 B3 t* {" g3 p
double result;
! U' d3 O p$ H# M6 Mdouble x = 90.0, y = 45.0; </FONT></P>7 W j; R4 E/ P. B t3 V
<P><FONT color=#0000ff>result = atan2(y, x);
: L8 @! K, d6 y( s: I% q5 |9 e+ ]3 Bprintf("The arc tangent ratio of %lf is %lf\n", (y / x), result); " s; L* b# W/ K% r4 {* O u
return 0; 9 M2 v7 l1 K3 B" q4 c% S! t
} # F8 w( \; A/ `8 }
</FONT>) u: ?! o5 D; S6 z
</P>
& _# J6 D* J* v, V- [<P><FONT color=#ff0000>函数名: atexit </FONT>
0 f- D& p$ K0 z2 O9 b6 J功 能: 注册终止函数
3 V5 o! ]6 ~) Y* O# f9 y' d: p用 法: int atexit(atexit_t func);
& W7 a N: N" ^8 F1 |0 f! m: d程序例:
, e" Q8 u6 o/ p( V! B" e<FONT color=#0000ff>#include <STDIO.H>2 n @6 ]5 A) t7 |
#include <STDLIB.H></FONT></P>
7 n0 U2 g7 N3 Q7 O. z1 D; _' y z8 }<P><FONT color=#0000ff>void exit_fn1(void) 9 k4 X% M6 @% u. e6 p
{ ' N4 n% F3 w/ p7 b% N4 t& t( b
printf("Exit function #1 called\n");
; g' m# X9 O5 l" [( ?- f} </FONT></P># P. g3 u" L' V) h& x: C3 R+ P
<P><FONT color=#0000ff>void exit_fn2(void) $ t! b. I9 N6 n1 G8 V
{ 7 i! l' M+ g- u% N1 j
printf("Exit function #2 called\n"); " Z: K+ E i! M
} </FONT></P>% R! D2 h& w8 f, z. `7 a
<P><FONT color=#0000ff>int main(void)
U* x/ s; O, `" v; Y% _5 T$ C{ ; L, `8 J; }8 O# _" e+ j6 A+ M& b
/* post exit function #1 */ + m0 F- p& c1 Q* E7 ]& I
atexit(exit_fn1);
" W& s+ n* b0 ]: c5 ]/* post exit function #2 */ 9 o& C9 I& o1 `9 M6 ^3 T! O, {. v$ p
atexit(exit_fn2);
' l* Q' h0 T9 ^+ G" b+ L. zreturn 0; - K: b% E' I8 i: w$ Q' V$ Y
}
% {, G1 M p; p0 p1 T- h</FONT>! W W6 F9 m/ q$ @/ Q3 {( R4 J
9 C) n' ] P- t+ |</P>
- Y( h8 F$ X& O8 }<P><FONT color=#ff0000>函数名: atof </FONT>
, J; c4 p/ o( |3 U功 能: 把字符串转换成浮点数
; }+ N( b% g6 K+ V7 e! ^用 法: double atof(const char *nptr); & i. K, ?; @) _% K' S+ f
程序例:
4 M* [& R+ [( ~3 q5 s9 V U, |<FONT color=#0000ff>#include <STDLIB.H>
. h, i9 F* f% U# ~* M: \#include <STDIO.H></FONT></P>. t8 K' y- b1 @
<P><FONT color=#0000ff>int main(void) 5 h3 I9 V8 l3 Y- E( h
{ . P1 }9 U# P' G( X( t5 Y
float f; h7 U: Y z/ ]2 l- [- }0 ^% \9 H, w
char *str = "12345.67"; </FONT></P>1 }( o5 z( W. [9 o4 O# v i
<P><FONT color=#0000ff>f = atof(str); * q0 I" {, X8 L1 n3 |
printf("string = %s float = %f\n", str, f); , |0 U% z3 A: N; f! E
return 0; : ?% w# F+ c! z, H4 D( N
}
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: D( N/ w% `0 d X<P><FONT color=#ff0000>函数名: atoi </FONT>/ k* z _" i3 }6 X' `: N5 j
功 能: 把字符串转换成长整型数
6 G6 r0 |% ]+ O* }; d用 法: int atoi(const char *nptr); ) W7 f3 a& B: q- J8 O% N! J( P
程序例: : P' r$ \7 _$ @: j+ ?/ s8 v
<FONT color=#0000ff>#include <STDLIB.H>
a+ V; b' Y: V! t2 g# L#include <STDIO.H></FONT></P>
, R8 p& e: }) q% }+ u# V<P><FONT color=#0000ff>int main(void) 1 j( q1 ^" J3 w$ o \( k5 R$ W+ Q0 O
{
8 N# d+ K3 N+ a2 h5 j3 Gint n;
! n; A0 m+ T1 F6 k0 j& Tchar *str = "12345.67"; </FONT></P>
" m% D6 m) t/ j9 u- q: V/ S<P><FONT color=#0000ff>n = atoi(str); " o, e4 H/ k; f+ P. {% U1 H1 D
printf("string = %s integer = %d\n", str, n); " l. w$ H7 W9 \* s
return 0; - v$ u3 k r+ x( J, Q+ y( {) P
}
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0 Q% N' {* o) [6 T3 h4 N. a8 v<P><FONT color=#ff0000>函数名: atol </FONT>
! F3 g; |. u# a; l8 o% F功 能: 把字符串转换成长整型数
8 ?" A" Z/ V- ?+ F用 法: long atol(const char *nptr); + ^/ t! ^8 O1 T
程序例: </P> J) k9 S# M5 k$ x
<P><FONT color=#0000ff>#include <STDLIB.H>
2 n W$ l ~6 d* G#include <STDIO.H></FONT></P>
! H7 h1 h1 m' v$ p* x1 E/ X<P><FONT color=#0000ff>int main(void) ; ^* T% Q' c$ ^8 I2 s( i. X
{
2 H0 U. k+ p, @long l; 0 @! V9 Y7 Z, a
char *str = "98765432"; </FONT></P>0 M8 z1 }. G7 `
<P><FONT color=#0000ff>l = atol(lstr); ! x7 N% U6 `' K. w+ a' Y9 |# j) z
printf("string = %s integer = %ld\n", str, l); ( J6 U Y6 L3 _7 z
return(0);
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