谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote

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5 o* S! h; \) w4 [1 ATime Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

Description
" b. ?, Y* A" \5 c* `- {. SA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:

1 M* H' S/ b: f# T5 sEncoded: HPC PJVYMIY
Decoded: ACM CONTEST

* C% f8 X8 \. g+ k/ E- y$ x7 ^In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.

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, e9 u. j1 B5 `Input
$ N( r7 ]% N* ]' W! aThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
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Output
4 B/ P5 t% g5 w9 K, A+ ]* RFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.

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Sample Input
2
HPC PJVYMIY
' Q! I- N# g; h$ NBLMRGJIASOPZEFDCKWYHUNXQTV
6 S. Y8 E+ U+ uFDY GAI BG UKMY
/ }; D5 [  y/ `  q8 W: bKIMHOTSQYRLCUZPAGWJNBVDXEF



Sample Output
: h8 p. H/ L) M; T! j# L1 ACM CONTEST
; d( ]. F7 |+ ?. E$ S2 THE SKY IS BLUE
/ M6 \  S% [1 T* x  {1 M5 D
) Z( T+ U( K" W0 U5 k
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6 n) r4 E. t8 y6 l# E我的代码是：
#include<stdio.h>
#include<string.h>
# F6 h( `# o% S6 q9 _+ w7 }% [int main()
{
     int N,i,j,k;
     char c;
: T. n" ^7 g/ p$ V1 ^" K- J$ B# ]) V     char code[1000];
     char map[27];
     char trans[1000];
6 }% m5 W. Z. \     char wrong[3];
3 t$ @! {1 n1 E, o: Z8 d     scanf("%d",&N);
! i7 f5 X7 ~' R% G8 A) x     gets(wrong);
) f4 `$ Z- Q" B( D( S7 X     int h=1;
% u, Y( F9 P8 j9 f     while(N--)
7 R# B  Y! u- H     {
         gets(code);
         gets(map);
  o: q: R/ ]4 K         for(i=0;((c=code[i])!='\0');i++)
         {
             if(c==' ')trans[i]=' ';
             else {j=code[i]-'A';
1 R/ L6 s; n7 o             trans[i]=map[j];}       }
3 O( _. n& I* x8 {8 `5 l         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
6 Z! `# @6 Z1 u         printf("%c",trans[i]);
0 @/ `/ C3 a7 T! W; V         h++;
         printf("\n");
1 C  {0 U1 O2 I: g     }
! z4 `$ P1 m; G# \0 x" c     return 0;
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" e# P) h4 i5 m# `! P, Z& j; i4 U样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。