谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote


Time Limit: 1000 ms Memory Limit: 65536 kB
, F* U" B) P2 d" j9 E; p, h. x  w# n6 YSolved: 79 Tried: 281

Description
* C. b, u1 e' ]2 N0 Y1 W: d$ iA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
' j4 ~8 q: d( O, S8 N& R+ D  A' L) g. i
4 h5 K/ U  b6 r$ D' v. a' i  OEncoded: HPC PJVYMIY
$ y! i/ c1 B! _% t5 m# cDecoded: ACM CONTEST
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In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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1 O8 u% x7 b- _5 r( |4 bInput
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.


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Output
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
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Sample Input
2
HPC PJVYMIY
BLMRGJIASOPZEFDCKWYHUNXQTV
FDY GAI BG UKMY
KIMHOTSQYRLCUZPAGWJNBVDXEF
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Sample Output
! i2 ^& u2 _9 A7 c3 \1 ACM CONTEST
2 THE SKY IS BLUE

9 h+ z! Q  c' C. N3 g! B" M' m- y
6 K$ e( O: u# B
我的代码是：
% [0 \2 k" V+ k- |6 y4 M7 G#include<stdio.h>
#include<string.h>
int main()
" D" g' R/ R0 ?( m: z8 ]{
     int N,i,j,k;
     char c;
) J4 T4 u# T8 p/ H2 w     char code[1000];
     char map[27];
* T$ Y) {4 b8 z& G* s     char trans[1000];
     char wrong[3];
) H3 a( c3 t) J8 \     scanf("%d",&N);
1 Y' E; s" D9 ~+ p( f     gets(wrong);
     int h=1;
0 _; z/ A7 S" N" J) T+ g+ l. H     while(N--)
     {
         gets(code);
         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
         {
             if(c==' ')trans[i]=' ';
, A2 P2 C/ ~2 a. e2 k             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
& F) `8 e) G7 n         h++;
6 {1 @4 W, g9 I- p0 }" x0 e         printf("\n");
8 l* D0 S$ g5 ~) W$ ]" z     }
" g" f1 M7 \4 c! ?9 _0 Q     return 0;
}

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样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
) u. K6 B( D& I2 z& K9 @是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。