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发表于 2009-8-16 18:59
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修改一下循环的下标可以使得程序编译通过,但是不知道是不是和你的模型相符合,你仔细分析一下吧!- {: d5 a9 S9 q; v( m' O7 W1 u" Y
; Y6 w8 ^9 U8 D8 E7 U
- model:( x7 G4 ? H1 @\" y, a
- !n个货车8收点运输问题;) u9 x% I0 j) E/ |+ e
- sets:
7 A9 P' _3 [2 U\" j- M+ w# ?$ e! ^ - place/place1..place10/:time1,time2,timexie;& G) O3 d+ M) U$ @0 J9 C+ r
- car/car1..car3/:time;
7 ~8 q- O8 O6 W! j - 5 j' Y, P- u# Y
- jiu/1..9/;
. q) x# B' L( }4 K& x& H' F - er/1..2/;
0 i+ u0 S; Y) U$ W+ R1 C$ Z
. A* i( E K, N* H# p% i- lc(car,jiu):lucheng,ct;% d3 U5 T3 {5 `4 L- n3 } x7 x8 u4 `6 R
- plan(place,place,car):a;- l. F2 _\" m5 v. `6 \\" g W% `: J- Z
- distance(place,place):dd,dt,which;) c$ L% ?5 J. r' w
- endsets
) g: C9 |5 H( D8 S. j8 J6 _1 | - 8 s) T6 p) {$ C5 ~
- ) [1 a; H1 o/ n& B7 o\" M, \9 p
- !这里是数据;2 \8 I. `& e# c\" {$ y$ h
- data:
7 T1 m- k1 `* {7 k; y/ | - s=1;, O4 J1 l' @5 d5 F9 R$ [
- time1=-10 1 4 1 4 3.5 2 5 1.5 1;
; x: X- w4 c2 p7 ]\" ? - time2=7 4 6 2 7 5 5 8 4 10 ;! q' N) K$ A+ W' c, @( H
- timexie=0 1 2 1 3 2 2.5 3 0.8 0;
2 `8 M$ p2 V+ s% z# V% O( b5 H
2 ]\" `7 o; U7 H, w
! [ y8 y. \# y- dd=; ^6 O( [7 r2 A- ~+ S, C: j$ I) P0 T- @
- 0 40 60 75 90 90 100 135 80 0
6 p, t( }+ V: h- G) d- [ - 40 0 65 40 100 50 75 110 100 40
! U) ^$ c' b5 L, }) j - 60 65 0 75 100 100 75 75 75 60$ F1 l5 O: w7 N. J& X2 I9 c3 c, w, b
- 75 40 75 0 100 50 90 90 125 75
8 H1 ~) g* e) j; e' a- O - 90 100 100 100 0 100 75 75 100 90
! h9 s# K! Y5 { x E; [, ] - 90 50 100 50 100 0 70 90 75 906 g+ ~) Q4 }- L# S
- 100 75 75 90 75 70 0 70 100 100! O4 V1 s# M# t1 t$ k
- 135 110 75 90 75 90 70 0 100 135
: ^- C, T5 b3 L; E- f; v9 T - 80 100 75 125 100 75 100 100 0 80
# M; a3 B% w, j9 Y, H& n - 0 40 60 75 90 90 100 135 80 0 ;8 @& J' V4 B# y3 d1 z\" @# V5 f7 x
- dt= 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0( R7 p/ U- c: p+ I& f7 \7 ~+ f& @
- 0.8000 0 1.3000 0.8000 2.0000 1.0000 1.5000 2.2000 2.0000 0.8000
3 l% a0 e, N% n. z - 1.2000 1.3000 0 1.5000 2.0000 2.0000 1.5000 1.5000 1.5000 1.2000
, S# p. l! ~- D: J - 1.5000 0.8000 1.5000 0 2.0000 1.0000 1.8000 1.8000 2.5000 1.50000 E+ D* Y7 @. a6 S1 K
- 1.8000 2.0000 2.0000 2.0000 0 2.0000 1.5000 1.5000 2.0000 1.8000- d/ H\" M& C) ]* t* u
- 1.8000 1.0000 2.0000 1.0000 2.0000 0 1.4000 1.8000 1.5000 1.8000
) c6 `/ K* `# n! @! u: p - 2.0000 1.5000 1.5000 1.8000 1.5000 1.4000 0 1.4000 2.0000 2.0000% f; f: @. W& B# _1 C
- 2.7000 2.2000 1.5000 1.8000 1.5000 1.8000 1.4000 0 2.0000 2.7000# p( l8 |* t F3 ?6 V, j; g# V8 O, K
- 1.6000 2.0000 1.5000 2.5000 2.0000 1.5000 2.0000 2.0000 0 1.6000
+ c' m$ n* C Y- ?, S - 0 0.8000 1.2000 1.5000 1.8000 1.8000 2.0000 2.7000 1.6000 0;0 H, X1 F$ V% g; D! y
- enddata
. l6 o$ d% C. I4 S9 U- w - 5 D2 P1 z# W. N$ O\" s# K
7 v$ ]# g' m8 ], o% x2 x0 N- !目标函数;
5 o/ E! m7 E0 V+ U1 V7 D+ I, y6 s - min=@sum(lc(I,J): lucheng(I,J));9 L4 Z! ]3 h7 v4 k5 w# D' g
- ( {7 J2 T7 b3 W& _/ s
- !整数约束; u& X. V, S/ ]* _* x
- @for(plan:@bin(a));
q, }( L+ {. f7 n\" ] - @for(car(I):@free(time(I)) ;2 ^; \0 ~$ |' E; d* K( G
- E- Q2 J\" g7 T9 E! h2 j- !从零点开始最终回来;5 X* g$ K; r0 A: c; t0 S& k8 u
- @for(car(I):
4 ]2 O% [) v, _ - a(1,1,I)=1;a(10,10,I)=1);
+ a3 a; z5 U/ Q9 f2 C; \ z
( m3 {+ S U0 m+ ~. ?- !每个任务只能有一个;
1 ?6 A! T F+ c# S. j - @sum(car(I):\" ?' K' h( E2 m6 O3 J
- @sum(place(K):/ z! ^! G! a+ h
- @sum(place(J): a(J,K,I))))=1;3 Z( k( s2 Y. a7 q; b# |% r9 L
- ) D- f7 U( k7 z
- !每个车的任务最多有四个;
6 G- {& n+ z2 b% X - @for(car(I):6 n; B, }) `' B( H+ K' ~) q% F
- @sum(plan(J,K,I):a(J,k,I))<=6);
- \; g& B1 b# b7 }$ {% F; p+ E
. ~# H- C7 Z/ _) t- !前一辆车任务大于等于后一辆车;
/ M. {! e( ^) L7 I - @for(car(I)|I#lt#1:
6 _2 K# G; J4 E1 @7 |2 v6 s. R4 Z - @sum(plan:a(J,K,I))>=@sum(plan:a(J,K,I+1) );\" _7 r. `5 H, ~ K$ @. s3 {( ?
# @, z: ~4 \; X& a: @7 P# {- !求which 例子 若a(1,:)=[1 0 0 1 0 1 0 0 0 1];
# E! k\" l C7 O* } - ! 则 which(1,:)=[1 1 1 4 4 6 6 6 6 10] ;/ a* ?7 U: k\" R4 @
- @for(car(I):
\" b. P9 r4 {& t( K+ f3 T) s - @for(place(kk)|@sum(place(jj):a(kk,jj,I)) #eq#1:5 l2 A: }0 w$ w6 t- J
- @for(place(jj)|a(kk,jj,I) #eq#1:
4 `' u/ `, A' n4 n4 r! y - which(I,kk)=jj ););\" T; I- q' h6 v2 j( q! x
- @for(place(kk)|@sum(place(kk):a(kk,jj,I)) #ne#1:
\" R' B0 i! U- S' A* U+ ?' c - which(I,kk)=which(I,kk-1));
+ C0 x/ e9 K# F! k\" X
! @& y2 I! m+ p2 z\" M\" H7 p- !时间限制;
; c$ T9 k( a\" ^8 Y. u }4 X# D - @for(car(jjj):
; ?3 D1 T4 e; S) b. ~) _ - time(jjj)>=-10;time(jjj)<=7);
6 l9 s6 q- N! S- S1 S. |) | - h3 ~/ _% Y0 Y X8 J5 d, j- \
- @for(jiu(jjj):% j4 b6 ~; J# M# `\" H; ]8 y; D
- ct(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dt(which(I,jjj),which(I,jjj+1))+timexie(which(I,jjj)),0));4 k1 X- l2 R2 C2 ]2 h
- ! a6 g3 y1 y\" S$ T, T$ o
- @for(jiu(jjj):
( |& L4 w; M, y. k* C& y - time(I)+ct(I,jjj)>=time1(jjj+1);time(I)+ct(I,jjj)<=time2(jjj+1));1 z6 N. U9 y4 T- z' F9 j2 W2 z- E
: p, Y* V6 |' n4 a. B- !求每辆车行驶的距离;7 g1 k7 d\" Q2 \5 a! ]; k1 [
- @for(jiu(jjj):; i4 \0 X4 s( Y
- lucheng(I,jjj)=@if(which(I,jjj)#ne#which(I,jjj+1),dd(which(I,jjj),which(I,jjj+1)),0) );
- z5 p2 }, @( r. o7 b - );););
\" B$ N& j) y) r - end
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