谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
" k9 u" P' ]+ p

: i* Z' q2 e  J) j3 `Time Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281
5 S1 \! b4 h5 N  x8 I- j( C
Description
A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
6 R( e2 R( B6 h$ D6 T+ B" |% {
Encoded: HPC PJVYMIY
; c/ R! b  R' o4 g  N8 s# e  lDecoded: ACM CONTEST

In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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/ U0 P' ^- Q9 D
Input
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.

1 ~2 e4 U8 u6 c, J7 O
% s. ^8 b* |" K* @1 B
Output
- |2 _, z/ X! E/ X" L. Z9 cFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.


( k" h: z- Y: O3 c  l& TSample Input
2
HPC PJVYMIY
, F+ G/ I8 @0 B  I1 CBLMRGJIASOPZEFDCKWYHUNXQTV
FDY GAI BG UKMY
. k/ b$ s: S( DKIMHOTSQYRLCUZPAGWJNBVDXEF
1 k7 z2 s6 F  t* J

6 ^$ E8 V0 ]7 a- |" P' N4 H
Sample Output
" j8 W, T$ G1 W0 U1 ACM CONTEST
9 ?0 q* q% e: o. a4 z3 C' N2 THE SKY IS BLUE


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我的代码是：
#include<stdio.h>
" l/ i$ i# q9 b0 c, x#include<string.h>
int main()
{
     int N,i,j,k;
* Q" k0 v" {- `# B$ u3 H     char c;
  V; P3 S' c' L     char code[1000];
4 o2 G) D- P4 \) T     char map[27];
     char trans[1000];
     char wrong[3];
     scanf("%d",&N);
     gets(wrong);
     int h=1;
, e1 T' Y. C1 D2 D( l     while(N--)
/ I' P" V) j$ j4 ?3 G3 d$ d2 x     {
- a, X& y3 y: Y( |         gets(code);
         gets(map);
0 P: J0 [# x4 S# f& j1 X         for(i=0;((c=code[i])!='\0');i++)
         {
             if(c==' ')trans[i]=' ';
5 G) M- D1 M; Y+ t; i             else {j=code[i]-'A';
) s( e- {, Q" w             trans[i]=map[j];}       }
5 g% a! Q( A7 }4 L- \         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
1 C3 _. {: O: D- _! f         h++;
         printf("\n");
     }
     return 0;
}


  k: a# e2 U" y7 q- I% x/ ~样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？

zjqylcy

把答案也附上来吗。。。
  r# W, U. W$ p& i$ C* s+ M# i1 W7 w是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。