谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
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3 ^2 a3 U4 K5 Z# OTime Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

Description
" y! ]6 T" D: K' j0 {5 TA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:

Encoded: HPC PJVYMIY
8 D, v% M5 r" LDecoded: ACM CONTEST

: e. f: z- @: v5 K7 l: zIn the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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; [9 ]3 r) B2 r9 d4 Z5 f$ K6 FInput
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
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4 b& Q. p5 V2 Z# c# u2 i* A3 b& A+ ?Output
! ^9 X/ }, u! @5 s7 a2 l! CFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.

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. {+ r. p  _/ u: ]5 Y# a) i. dSample Input
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9 i' b- S% y0 G3 v/ cHPC PJVYMIY
BLMRGJIASOPZEFDCKWYHUNXQTV
FDY GAI BG UKMY
9 G/ g2 X! b3 E# h" U$ [! c+ }8 [KIMHOTSQYRLCUZPAGWJNBVDXEF



Sample Output
1 ACM CONTEST
0 |/ h" _0 B+ P+ z2 THE SKY IS BLUE
; Y' T  ^( V9 _/ B  z0 ~
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我的代码是：
#include<stdio.h>
  U" c# L1 Z% C% t#include<string.h>
6 _6 U" N6 L% x& @! Z2 r1 Cint main()
2 r1 g+ I& P% l  \{
     int N,i,j,k;
     char c;
2 {0 E  M  f9 \. \" b4 d     char code[1000];
     char map[27];
. k, W* V. v0 C% m+ W* m# h     char trans[1000];
5 X$ A  ?2 f5 E& v) i* Z     char wrong[3];
     scanf("%d",&N);
- f; a; Y: y5 @& Q     gets(wrong);
     int h=1;
     while(N--)
3 |% ~. A0 f( G$ h. i& a) C+ \1 y3 O     {
         gets(code);
$ C* E% k- O# ?6 M! B! I         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
         {
! X2 S  e' G# C9 S9 s/ m             if(c==' ')trans[i]=' ';
( r, w" c, R. N) y% N' f4 M* D3 t             else {j=code[i]-'A';
- e/ a  o& s2 e5 i+ n             trans[i]=map[j];}       }
2 C3 f7 I- p* ?+ }$ d& e. ~         printf("%d ",h);
3 d, V* E5 X  i! H2 C- ?/ c         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
. Z1 a' \& `+ X         printf("%c",trans[i]);
; U' t; f" a: ^7 s, M1 I         h++;
; h# X! A3 f" m7 u  b         printf("\n");
     }
/ R% N2 A) V7 _     return 0;
}
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3 f; _7 F) A# |1 c  P& u  k8 Z' x样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
1 M0 @1 g, k; ]' P, k$ j是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。