谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote


Time Limit: 1000 ms Memory Limit: 65536 kB
4 H5 y  |, Q- c- v* ySolved: 79 Tried: 281

Description
; @3 L* R; K$ u  OA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
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Encoded: HPC PJVYMIY
Decoded: ACM CONTEST
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0 G2 L/ y3 @1 r, `In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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  T' R! M9 a2 h& J) mInput
! K/ z/ |. m7 }9 _( ~( AThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
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Output
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
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Sample Input
2
HPC PJVYMIY
BLMRGJIASOPZEFDCKWYHUNXQTV
4 T# g0 _; X8 u6 a' C' o9 [% f( RFDY GAI BG UKMY
KIMHOTSQYRLCUZPAGWJNBVDXEF
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4 H% f, h2 ^3 {0 l, T2 nSample Output
% G3 p- o+ j" O' x3 s7 c) m( w1 ACM CONTEST
2 THE SKY IS BLUE
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3 x7 Y0 J3 ^9 Q6 P( M8 f& X, h我的代码是：
#include<stdio.h>
#include<string.h>
# q/ l+ I2 m. Z' jint main()
0 N) n; Q. J* Z- K- l) O{
! a1 w# j# N; Z& e. ^     int N,i,j,k;
     char c;
     char code[1000];
     char map[27];
     char trans[1000];
% `& \2 ~; e6 ~) X# r     char wrong[3];
     scanf("%d",&N);
1 w+ D9 K8 W) ]. W0 e) [# G     gets(wrong);
     int h=1;
     while(N--)
     {
8 `+ Q( U+ E% h: u) b         gets(code);
         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
8 B& ~6 H4 ~1 L. R3 O         {
# s; }8 R* z, c2 x5 Y6 f' U- U3 C             if(c==' ')trans[i]=' ';
             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
' z) G! i  t# J+ a+ X: H+ p+ u: L         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
  A1 X: K* ]- \2 ^         h++;
         printf("\n");
     }
     return 0;
}

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' M1 I% X/ P* \6 x. p样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
& H  q6 L/ J# h3 j) M$ _是不是k是int型？

葉_浅浅

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linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。