谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
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' ?  q8 t7 _; ]2 j; MTime Limit: 1000 ms Memory Limit: 65536 kB
* O* g5 a  m0 I1 E* d/ t% m+ oSolved: 79 Tried: 281

Description
" v1 x5 G. [$ D. \! t- cA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
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Encoded: HPC PJVYMIY
( k9 P- c+ F+ o$ \  iDecoded: ACM CONTEST
4 H7 S; G% e1 ^; M: x3 H
3 V7 t" G5 }# M4 E9 _5 a* A: TIn the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.

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Input
  ?6 g7 S# F9 `5 {4 kThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.
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+ P+ u' o, F4 BOutput
4 ?% O1 p' R3 Z0 G! |For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.


! I" {3 ~/ l/ q0 W3 m" V5 o' _/ bSample Input
2
  @% u0 b9 Z1 o% p8 U" sHPC PJVYMIY
7 R+ D! S# n/ G8 J8 CBLMRGJIASOPZEFDCKWYHUNXQTV
9 w$ h& ~. I" C" ?4 u$ UFDY GAI BG UKMY
KIMHOTSQYRLCUZPAGWJNBVDXEF
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; I$ g5 y, e0 F' C3 cSample Output
; Z) @# V2 P) @, X% u: b1 ACM CONTEST
$ n. V; `$ R5 n7 q! N9 m2 THE SKY IS BLUE
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我的代码是：
4 f) ~# X0 l% w1 ^/ C, n7 j7 i#include<stdio.h>
4 z  K8 x2 ]( X; }#include<string.h>
* @& T* ^: \3 C, G( s+ @: Q. Y3 X. Oint main()
{
     int N,i,j,k;
     char c;
     char code[1000];
: l/ U; D5 c# O1 S: a     char map[27];
     char trans[1000];
     char wrong[3];
     scanf("%d",&N);
( v0 g- Y8 \( p9 o8 \     gets(wrong);
$ x( Y: O; h- x8 m/ a4 |     int h=1;
     while(N--)
0 J& n, s+ Q% ~0 O3 i+ H     {
6 a+ M9 Q# [% e, v, {3 q4 g         gets(code);
         gets(map);
! b9 L) P& F6 A' Q/ c+ x         for(i=0;((c=code[i])!='\0');i++)
         {
5 B/ P9 r2 _7 y8 R             if(c==' ')trans[i]=' ';
( j- ?& e  s% _. A9 P" x6 `" n8 g             else {j=code[i]-'A';
/ ]+ ^( d& \) X             trans[i]=map[j];}       }
$ i0 d7 h$ Z$ x' X# g         printf("%d ",h);
; E0 V$ }) R7 j         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
         h++;
) E0 {5 K9 v" M! E         printf("\n");
     }
     return 0;
}

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样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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zjqylcy

把答案也附上来吗。。。
" f) }% t9 u7 G/ f- D是不是k是int型？

葉_浅浅

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linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。