谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
) r( g3 j+ g. ~& {7 w/ l2 t
: S. V0 D% V! u" U
Time Limit: 1000 ms Memory Limit: 65536 kB
! c8 a& |" t; b6 ?. ?6 v- L. gSolved: 79 Tried: 281
- Y/ x' k$ Q5 h. A7 D6 G
Description
: [/ Z& |) b7 z* z: K* D% \' dA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:

Encoded: HPC PJVYMIY
; ~, U: E: e( |" PDecoded: ACM CONTEST
9 _6 m2 e* A5 ]2 d& \- F. {
In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.


Input
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.



+ A+ A/ H, S" BOutput
& ~, i4 D: h# GFor each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
3 [, \  B0 M' O: p& x- ]3 f
% t! i# c. m9 }$ v0 c
Sample Input
2
HPC PJVYMIY
BLMRGJIASOPZEFDCKWYHUNXQTV
8 ]/ ^) @: G9 X6 A0 M- zFDY GAI BG UKMY
* ~% m8 h2 F* k' KKIMHOTSQYRLCUZPAGWJNBVDXEF


8 x2 D5 I7 w7 _) X6 y
( |" O$ ^4 s/ h( R. g" pSample Output
# Z  x: c$ ~: V) R: O& z1 ACM CONTEST
2 THE SKY IS BLUE
$ {$ b& y' A9 s5 K, _7 `


我的代码是：
* _/ `: S/ Q; X5 R#include<stdio.h>
#include<string.h>
, c" {# R/ N3 B* nint main()
{
1 E" N: I- Z: }6 v$ [/ x     int N,i,j,k;
4 u* n8 {& W6 r) @, M     char c;
$ n. x! ~2 g. s  ]6 y. U* D     char code[1000];
# d& _4 `3 D8 E) g; h5 K     char map[27];
6 M% d/ }1 j, l3 W8 ?     char trans[1000];
6 _# F3 L) R& W& z" \# ]     char wrong[3];
# ^2 Q0 _* L, W9 W4 U( e; }2 F6 A     scanf("%d",&N);
3 v9 D$ d3 ]& Z* {! S% k& k. E* [     gets(wrong);
. s5 E6 L+ i. R( m; [: x2 K' ~8 J     int h=1;
' w/ Y0 f. }, U5 M     while(N--)
     {
0 _4 Z, B. t! o  I' |         gets(code);
/ o* [1 U6 A, W$ g3 k         gets(map);
& V! \9 [4 s& c2 a         for(i=0;((c=code[i])!='\0');i++)
9 }9 v* j* T! O- A         {
$ J& H% |4 y4 a& M4 k% {$ r! o             if(c==' ')trans[i]=' ';
             else {j=code[i]-'A';
& z% `- [; ^* a# s9 ]& a             trans[i]=map[j];}       }
         printf("%d ",h);
+ ?8 J  }+ w$ v+ n" W/ w         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
, e2 o2 p0 n2 N9 Q# [4 I# x" g6 H         h++;
         printf("\n");
" ~" q! z5 T: H2 |# [3 E5 Y     }
- X* l9 W0 g: B9 v( a7 h, S     return 0;
}

" ?: R5 h! |. z. o; m5 I
" [# m; k2 h. W$ ^样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
# b$ S. q2 C, u

zjqylcy

把答案也附上来吗。。。
6 F- {4 V& |3 S0 a是不是k是int型？

葉_浅浅

.....................

linmatsas

C………………………………

_我还活着

没有看懂.....

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。