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TA的每日心情 | 开心 2021-8-11 17:59 |
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签到天数: 17 天 [LV.4]偶尔看看III 网络挑战赛参赛者 网络挑战赛参赛者 - 自我介绍
- 本人女,毕业于内蒙古科技大学,担任文职专业,毕业专业英语。
 群组: 2018美赛大象算法课程 群组: 2018美赛护航培训课程 群组: 2019年 数学中国站长建 群组: 2019年数据分析师课程 群组: 2018年大象老师国赛优 |
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最大流: ![]() 注意Matlab 中的最大流问题是必须是单源和单汇问题,因此这里需要构建虚拟的源点S和汇点G。
% W! E) Z/ S% X/ i- bclc,clear r" E% f& e& T/ C) X1 _
a = zeros(9,9);. O0 Z, O4 I: C" s
a(1,[2:4]) = [20,20,100];( v9 C1 _. i: W+ m
a(2,[5 6 8]) = [30,10,40];4 M1 D1 |( W* B2 I+ V$ x
a(3,[7 8]) = [10,50];
+ r# `6 E3 C5 T6 a& i% ta(4,[5:8]) = [20,10,40,5];; N$ U" u; Z3 a0 r" _
a([5:8],9) = [20,20,60,20];
& O. h2 A; C! P. j) _a = sparse(a);
+ k! U3 ?* d$ N e* ^[b,c] = graphmaxflow(a,1,9)
4 T3 _1 K0 I! W+ F/ Y8 ?) s1 ?最大流拓展:最小费用最大流 仅仅是在求得最大流之后进行对最小费用的求解: 0 n x' F; P+ M4 _1 F; P
clc,cleara = zeros(5);a(1,[2 3]) = [10 8;a(2,[4,5]) = [2 7;a(3,[2 4]) = [5 10;a(4,5) = 4;a = sparse(a);[b c] = graphmaxflow(a,1,5)
& e, ]5 f2 U# N; ?最大流量为11 自定义Matlab代码:
. T& ~3 C2 h9 J0 `" [8 B
6 ?9 M! b$ b8 n( d' `最小费用求解
( G4 n1 M$ Y5 A0 V9 i- ?: X- L/ q4 m% \# p
Lingo:
+ w i; W7 e. `7 D7 [: `2 {% g
: z, [, U9 z Z# Rmodel:! e3 l1 s6 M4 C5 h4 v' W
sets:
3 n& F6 `: B" V$ h- V; o( X- unodes/s,1,2,3,t/:d;4 N: |% @( e1 ? ]3 H3 P
arcs(nodes,nodes)/s 1,s 2,1 3,1 t,2 1,2 3,3 t/:b,c,f;; X; b! {: Q5 R9 \8 K& S$ t
endsets" ?# K; r( ?" B: u
data:
B5 E; w& ]& @: Ob = 4 1 6 1 2 3 2;
; ~, r- Y& t, l2 }- X* uc = 10 8 2 7 5 10 4;% ^! r$ b4 w2 W; G* g
d = 11 0 0 0 -11;
9 V# e' p8 _9 u* {8 venddata* \+ L" h1 o/ s
n = @size(nodes);* C9 J& v! I, o" h
min = @sum(arcs:b*f);0 B$ ~- x) B, |3 }, R( J- g' h
@for(nodes(i) sum(arcs(i,j):f(i,j))-@sum(arcs(j,i):f(j,i)) = d(i));9 D+ {4 o, h" W
@for(arcs bnd(0,f,c));
) w+ V1 M+ u% u0 U. x9 Z h/ g# qend
0 c% o9 x1 |- B19 \7 @4 M7 i& s/ p% Z
20 c6 C6 _) A5 L8 P4 l0 u0 P
3
/ {/ }" N( n3 I8 X8 f- X/ f4" ?7 g) _6 J0 I1 c
5+ z! w1 _' l* ~4 J) u0 \4 f) C
6" g% m6 Q. J J& [6 y1 L) `& J+ Q3 B
7) c3 c) \, e0 G9 M2 q
8
2 a' J; i. q5 T |9$ l8 e. R1 ^, S3 l
10
( n3 F+ n5 b* S: |& d' D2 J11
- Q1 Z: m6 u6 p. i8 E124 j, C" Q8 h+ k7 v0 U! b
136 \8 y F" ]" |* _4 v; J4 H
14& m5 X7 j% y" @4 w
15
6 p, E, g9 k4 ~% @Matlab实现:
+ h9 ~$ f( R9 b9 D, N) P: z6 r' L; m
3 h9 r7 `. G6 T6 E
( r5 Y. a+ G% q- E% l7 Vn = 5;; N. e: R. W& k/ X1 T7 C+ h# M! t
%弧容量
, K$ u0 E7 d7 w: p2 I( Ka = zeros(5);' l9 }7 l, o, h5 A" l
a(1,[2 3]) = [10 8];
9 G) N) k# s. s' r$ [a(2,[4,5]) = [2 7];3 [+ ^% |* c5 I
a(3,[2 4]) = [5 10];& k* K& u0 W# w* [: b& h
a(4,5) = 4;
& ~. t1 ?' M$ X' ~5 rC = a;( g& S k* y5 _' [( A
%C = [0 15 16 0 0;0 0 0 13 14;0 11 0 17 0;0 0 0 0 8;0 0 0 0 0];
4 X: ~' j/ }5 {/ i; _- k$ [% L) A1 E%弧上单元的费用, C5 \. j; [' D7 C! a
a(1,[2 3]) = [4 1];. _8 O8 F( [- S1 E7 G# ]2 D
a(2,[4,5]) = [6 1];/ V/ `9 j: ]: r3 ] O4 V$ [
a(3,[2 4]) = [2 3];* Y0 r N. |* ^0 ?! d- V& S& t
a(4,5) = 2;5 F3 K* e2 d' ?: B2 [. R3 b
b = a;8 N8 V- v( _4 h' w2 a, C% A. D4 y
%b = [0 4 1 0 0;0 0 0 6 1;0 2 0 3 0;0 0 0 0 2;0 0 0 0 0];
+ `* q/ l: B) d7 E# M; r+ r%wf表示最大流量。wf0表示预定的流量值. G/ J7 X2 G( g
wf = 0;' O7 k+ V% F- l" }- s8 r
wf0 = Inf;
- U' i9 A+ \. B6 O%取初始可行流f为零流
" ?7 A; N7 k8 ?& U* h+ e, afor i = 1:n0 R7 y# ~8 r- g, j; _
for j = 1:n
: |& e7 @! }, r! Y f(i,j) = 0;
. A. i' f, Q. j- [4 s8 l end
H7 x( }. \/ f% k; X3 Pend
( A3 z7 @3 b) u9 q5 k Mwhile (1)
7 \- `8 c( l4 X7 ~9 ^ %构造有向赋权图$ `# u, I! ^* q- J5 \% }
for i = 1:n1 [( F! h* F6 F
for j = 1:n8 O2 z+ [8 D- N* _9 M" }% `, `
if j~=i9 X3 B0 Z' e) G/ t& n
a(i,j) = Inf;
9 P9 B( g9 s1 y1 P Y) d" _/ m end1 c3 M. s3 s; \3 l E, f" I
end
+ `2 d+ y& P E( Q6 v, q- T' M% ]5 W end. r3 w: {( b3 b- _* }, `
for i = 1:n3 Y- H6 T7 X7 k' E/ }
for j = 1:n7 p6 k2 v) x+ N" ? N
if C(i,j) > 0 && f(i,j) == 0
* n' d% }2 K/ a, o* i a(i,j) = b(i,j);. d; u+ x! N7 E5 J& U% k% _
elseif C(i,j) > 0 && f(i,j) == C(i,j): ~! Z2 k$ I5 A* P( B9 f
a(j,i) = -b(i,j);
" A4 F# O! x9 ]- `0 N' i, U elseif C(i,j) > 0
! h. V( j0 Y9 T+ e8 u& J a(i,j) = b(i,j);6 ]9 y2 |! V% p# O) T6 Q( _- @
a(j,i) = -b(i,j);
7 J( u2 L0 @0 ]+ U; v3 m( Y end+ E; _4 f/ ^$ d% V2 G0 A
end
: b$ Z$ {3 X: r% {) g end$ ~" `9 D: @+ A
%使用ford算法求最短路,赋初值
& l7 m9 |1 ~# H# o+ h& I! s0 T, k for i = 2:n1 }! z7 p7 H7 t4 S; x
p(i) = Inf;
+ O6 e2 |: Z3 A3 }' Q s(i) = i;( h' A, b$ i9 l( W7 n8 l
end& n: H( ?+ U& p6 ~& B- X
%求有向赋权图vs到vt的最短路,赋初值
. q0 N' s; [* ]& X for k = 1:n
# m) Q2 Q+ U& }6 {& V1 L pd = 1;
% W& z3 P' Q0 H! f2 Z$ q% h for i = 2:n$ ?0 I8 B6 k4 h" }( M
for j = 1:n0 `. G9 q6 O* y1 l1 y
if p(i) > p(j) + a(j,i)
4 W* Z7 }) W/ d; J p(i) = p(j) + a(j,i);& A. d# I; W. ]5 a
s(i) = j; Q5 ^3 u4 E$ N B
pd = 0;
; Q( ?9 b, A C" @; s end2 g. d" M2 g5 [" J; k& h, t: W$ Q
end
6 b0 j$ ~# Z" l0 D9 Q end' I' q# r( o+ Y' V" X2 a
%求最短路的Ford算法结束
) w3 N& B% F3 k# Z* i) w: O { if pd
1 x( [. q; S4 j8 b' c4 I# c break;
+ L- p% K) h0 x end
( T6 c& b- f9 K end
' g3 v" \8 S6 X; c5 ?: s- H %不存在vs到vt的最短路,算法终止,注意在求最小费用最大流时构造有向赋权图中不会含有负权回路,不会出现k = n
/ q. k9 o" S! V- z2 D if p(n) == Inf
7 @" ^! I) j8 D# @. w break;
$ x" Y# U' `+ U# |. |, Y0 Y end
3 p& z* A9 J) M4 ` %进入调整过程,dvt表示调整量
' _& K9 |8 ^% d4 o2 \ dvt = Inf;
" }+ c' a4 J4 U; O7 ^& R dvtt = Inf;8 K3 f& N& I2 g% Q6 R4 ?& U
t = n;* C% }9 f. c8 R& e! `- q5 E
while(1)$ l" }( j& |9 K" f9 m' {3 d
if a(s(t),t) > 0
0 z% H3 J! B# x- q5 \ r b %前向弧调整量
& E# D e" |+ O- ~ dvtt = C(s(t),t)-f(s(t),t);' k6 Q& M1 H f' v
%后向弧调整量5 U4 B$ q0 }/ [$ a# y$ r
elseif a(s(t),t) < 0
) M, A( W" \! Q% Z# E dvtt = f(t,s(t));! n& e% L8 a7 A/ {, H
end
: |2 B* C, t/ Y if dvt > dvtt1 ?2 ^- M) H( F* e9 }6 S/ Z
dvt = dvtt;
) c8 h1 V4 N4 {# \8 }' P' g h end- z8 Q& K) r. u \
%当t的标号为vs时,终止计算调整量7 i7 S# s0 W p; q9 _" N
if s(t) == 1
7 S* x7 X5 `) |) p7 [+ O break;
" t$ m9 r) a! @$ P- r/ E end
: \! ^2 F5 r2 Q/ y {% T$ B# b %继续调整前一段弧上的流f
! q- _7 i7 \( U& A. D. u9 |' `7 W t = s(t);# `, e& ~0 b, N E- Q" A3 h! N% P
end
- R9 Y8 p1 n$ B# n pd = 0;$ _8 X( B5 D3 N# K, O0 C
%如果最大流量大于或等于预定的流量值; i9 h$ Y& b+ x. ^- E# U+ `* k- w
if wf + dvt >= wf0
8 | o9 B2 ?/ y8 R! l" N) u& U dvt = wf0 - wf;9 S J H; N( p( g: s3 f4 R Y
pd = 1;0 U+ c" R8 D6 y" L
end( n1 a& [9 }. Z* U, l0 Q
t = n;% ?# e* X( O) K
%调整过程
6 s3 T+ v: R' ~7 Z/ \( P1 K9 | while(1) Q( I/ }' N% D! |
if a(s(t),t) > 0! H- r' Y; \5 s g% @5 s
%前向弧调整3 j7 o. |. K6 n+ k' E( _" `8 k
f(s(t),t) = f(s(t),t) + dvt; - T2 y8 J3 } B2 } l* y) T: n" E
elseif a(s(t),t) < 0
0 J5 Z5 [: [# Q2 J) b %后向弧调整, p" V" [6 @$ m& y% v$ P
f(t,s(t)) = f(t,s(t)) - dvt;
6 c: L3 X' z0 h! W end
9 |: L; r2 b5 ^5 W %当t的标号为vs时,终止调整过程$ a- j: i+ X4 t; `( d: _$ v
if s(t) == 1$ Q+ c; G* A: Z% g. S
break;9 ?/ n( R. D2 [* L
end: ^& W/ f8 C: q
t = s(t);, f6 t e- [: @- i, ~9 d
end
7 @7 M. N) \/ f- D7 l8 J+ _ %如果最大流量达到预定的流量值
0 [3 ^$ G! Q! @ if pd2 m2 l1 `. M4 o2 b2 Q; {) T
break;
/ G* f" r' K% { end
8 p$ q) d5 R/ `. j %计算最大流量5 B1 \- Q( J3 I/ c+ _# ]( E
wf = 0;* @ G* ?% T; w! C, o1 l9 N2 i3 j
for j = 1:n
6 P+ R" i/ v2 b2 b wf = wf + f(1,j);! T( t V1 X4 f& ^5 ~- |$ M
end' n! e* A7 S: q' X# H! Z0 g) `+ n
end8 `/ t/ L, V9 k/ ^
%计算最小费用6 F' t6 Q/ [; S
zwf = 0;
' s7 \; ?/ O9 L4 s7 Yfor i = 1:n
8 A4 G k, w3 o( u" `4 s for j = 1:n
6 A- e* G' u5 T9 H6 ^ zwf = zwf + b(i,j)*f(i,j);2 k+ [/ f% k5 ?9 b# h' `- V
end+ z7 t7 |8 _9 t/ n' P d
end
* B# \$ h* O( h! X- v7 t( B4 n/ e%最小费用最大流0 y) V- z( W: m# M- ~
f
5 X3 f$ J! b% }+ y/ p0 c$ ]%最小费用最大流量
, a7 H6 o ^) u( twf& A* C8 a7 v8 l' O. {
%显示最小费用2 T! X T4 ]& t, K
zwf
4 v0 S! ], q( t" f; P2 O1( p. T- h" f, w$ ]% F
2
) K5 s; {4 ?. e2 [8 a* E3
" V( R+ Z% O3 Z" z W49 ?" v$ \0 w+ z! Z$ P9 ^
5
* t& \" r' G. Z7 U6
7 s2 b8 ]5 r5 U/ t; Y0 q6 S7- Z# f( o3 F2 X" w+ I5 F
8
$ g! B* g( e. G z5 b/ V5 H2 M9; p( s" r" E# W; }& ^
101 b! I2 t; }$ V; [
11
9 ~" j) _/ O4 ^. N12
, ]- e7 S! S: `. F' e( `" O13# _( T5 \" }' I+ P7 E
146 l3 q7 S. b4 }
15
/ _& {6 Q8 r$ \. T" [# j16: @' O) ]5 ?7 C l& v Y. N2 }" Y
17) ^; F& U# G$ X( n1 d
18
( @: }9 R8 J! N0 S( C" Q$ B19
1 o4 B( U6 H/ R20
& o4 x( F1 }4 B5 [3 E& o21" {; T0 E: d- o4 v' O# z# r
22& V! r: q+ S2 b; d# d
23, ^7 P& ?" s0 [, ?. `# u, t9 Q
24
# N; B1 Q0 E$ o5 b# D$ S4 u25; ]1 V( O l5 O4 r% h7 I/ _! t) }
26) w4 b# v) O, m) b# r6 E& m
27
8 r% h! ^* Y/ ]' i& k( P6 s28! c( V, J8 a+ [. U
29) R1 y: o. M0 f
30
6 V1 e2 [- }/ S8 L$ W& Z1 ~9 F+ a31
( X' Z$ {9 G8 E o) c& F6 F& M. h32! A# i1 L0 n8 Q! K3 S
33
. k- b) w1 |4 b, u8 a34 m* b$ i* g0 O/ {
35" K" s) W; R/ f- h# T& n
36
1 K- C; r! c5 g" ^7 W$ x& J, N37
" {. Y- L) A3 h B- }* S. \38
+ U9 e9 N- {+ o! k9 P' i, A39 I' S/ T+ G2 D% ]
40
# t& _ l" x, \: @41# X% `' }6 H, ]
428 w: l, C1 Z/ f4 |. N5 S
43
# {: @1 |) ?2 V3 P44) ~1 F; K# Z1 p2 b3 s! j
45$ S9 q; v( ^$ K! U% a
46' F- _# p( X; \
47& w8 I4 O% [% t
481 q* p; ], C3 \2 i+ Q
49
& T- F9 n F W7 X1 W50
* n% |2 T. [8 g5 s51; Q2 M3 i- Y8 P
52
9 X" w# k! P' Z& T# X0 B53, {& G% y% u- {. I3 o3 r
54
6 t6 U0 j5 A ^' o8 N+ O2 ?0 r ~553 M" {: Y% I( e+ N
56
+ W4 b$ ~3 S$ z }4 J574 x! B# w7 f; y
58
! k8 J0 p9 M! e" _ o0 i59+ s" L7 e9 ?; U
60
/ Y8 A1 r9 H2 `1 c61( b8 h! T6 O5 Q( `( x( F
62" F; T3 e) d& {$ I
63) }9 P3 @1 y' C& h, B
64
6 s0 P) u1 I" S7 ]* \5 G65
# i( K. e G( B; e/ e66
+ ^: p& C, V6 ?" C671 L" n5 n& v9 q2 m2 d
68, Q8 f( i8 l/ |& P& K
69# b- J" S" [( Q9 {. N% r
70% x6 P+ ~0 o; H- v
71
5 B/ ~ o% {* y& L7 z72
, |: h, b2 _6 \ w, k9 Q$ |73+ P3 C& |$ L. X/ x( |
74
. g ~/ N+ p. |& J* B% C9 L& g& t G750 b2 w/ z9 b2 R: W/ B& |
76$ R8 B& I( Q7 V" Z& ^+ y/ w9 B
77
. ^" Q R4 \/ C- P78
1 L+ Z. {4 j5 {% `' A/ Q& |79
. X/ t" h( J; K, r; \3 B80. X. m- S* @* u0 e- Y+ {+ g1 \9 E
81/ f, v6 M# A( n' Q7 F( X
822 H* X1 Z. E( [+ ?& a
83
% A/ a' n: W' M& {7 t84- y7 H2 }- K: X2 j5 q
85, }, W1 L# \; g2 J, E4 V6 m
862 N0 @6 k9 y0 P( S1 J1 v
87
c b7 c# u- q/ D& \" i88 h1 \$ [9 C. U( J
89+ T# X# ?& g z8 ?5 u
90
4 E: S. R+ X, W) u. a% z q91! y- ~3 V& G6 |
92
6 {9 j" ?" @0 K93
& n" P k8 k! y! \; i0 G1 A9 G# a94+ C' y" m- V" y4 ^) j- u
95
. A* Q# \( ?$ y. r1 i" b7 j8 c96
! P. z9 f( m: {1 q" h9 E97
- C' c6 ]# i: e98
5 j, D ~. V* I# H0 R+ W; v99- J; M4 @# t; q
100
! [: V! S$ Y1 C) j1 ?3 P101
+ Z/ T6 N; b, M& {% {" i102& F! \ L3 L3 N0 C( ~, R. s, I
103) C0 I! _! V2 p
104
Q9 ^( s. K7 n( w+ \: d5 f7 ~105
& l. ~' h3 n! h8 e0 j$ x d) {106( J) K- e |8 T) Q7 j
107
1 O1 X/ i$ Q9 H+ x108. ^. P+ @# |1 ]8 f, g: @8 A/ \
1096 T5 K; {& o! R; n
110
6 V- _) Z. m( E5 P) A s111' |( x- i9 f, G' X% i! G
112
# B, M2 ~* d; C9 ]" ~( I) F3 V113
7 S* f- A* X* R" Q114: e* F4 m) Y: C) A3 |, q
115* l) y+ Z, q+ O1 B
116
V1 \" y0 [* J" {6 `117
* d+ ? n( B8 n; q% E$ w. H118
$ c- z% J3 v+ U* d: Z, S) F119& U! H& H3 ?5 b5 }
1201 @ m6 ~) H0 r* z/ Y+ e
121
9 O5 O; a9 P: Q" W( K) u' @9 m7 N, t122
1 K3 J. d; K4 p123
1 n( T/ j/ ^2 T6 a. [3 K, V124
; W; h% d/ m1 s0 Q1 i# n125
8 V! b) w# ?) A- R1 L+ m126
6 D" r0 O% d! H5 F4 Y127" f$ o% G1 T( I4 @6 z
128% B+ n$ Q/ k0 P. P3 p! J ^
129+ c5 ]' L) D; t( g
130( f/ p: | a& X3 f y) p; x O
131( N/ Z K9 F P2 l. ^
132) @; p+ ?- T3 _
1336 K) U5 n ^0 L7 A1 ?
134
( R; v9 Q. [! N- \4 [135
9 z( t4 C" C2 x [- D9 F3 ?1365 q' n7 |: e2 r, s3 P7 }6 I
137
) D6 _' T3 r- X& x3 R138
- T5 I# x; U2 L& H% @' z139+ }. J1 H2 d5 [- b5 f/ H
140
3 s4 c6 n* b& t7 y4 P匹配问题:
, V. D0 I" j8 s2 G C, O7 E
* K, }3 R u% O4 j2 l最大匹配:
' [' H3 C! A0 Q4 m# S3 g* [( g& G/ t![]()
& o; E6 K7 e, L$ Q# M9 t3 r5 ]: }& ?1 n& `, ?8 k
代码实现:
3 A8 i/ f' Y) o L# x
; z: H0 Q$ U! \m = 5;! f0 } u8 D* ]4 r$ x* Y. d
n = 5;
: u, g! `9 ^; f1 A! L5 @, j- m- R3 KA = [0 1 1 0 0;1 1 0 1 1;0 1 1 0 0;0 1 1 0 0;0 0 0 1 1];( t$ p9 c0 N4 A$ M
M(m,n) = 0;
?6 N& O% H- W! X+ n8 |$ U" qfor i = 1:m
" X; f1 |/ H. @+ r1 Z- O; p } for j = 1:n1 q: e) @# |+ @
%求初始匹配M
7 r. |- o! D: [% K0 J if A(i,j) * @; H$ ?1 I1 i+ W" l$ `
M(i,j) = 1;
5 W# T( \2 Y8 P3 @4 }( ^ break;
) a+ m$ p0 `+ `: D* N6 F2 B' N4 X9 l end
( u" f% o/ B( | end M) b2 N- K) X/ B8 I7 i Z6 J
%仅含一条边的初始匹配M
# W! N- Z: Y6 t- W. ~1 ~9 F' K$ g% u# j if M(i,j)
( [2 Z( B3 y! ?# d2 M break;
; ^# G/ R0 x7 e _2 n# R, R end! R6 Q* x# P% g! t# ?
end) J# B9 k2 x6 [) a4 B" V
$ f9 r( R; L5 m O" @9 fwhile (1)2 D: t2 g- K; I4 y; q
%记录X中点的标号和标记
" V; E$ O+ d( Z( H4 A for i = 1:m4 S9 G- G' k+ \2 B2 l; X7 j
x(i) = 0;
: h J2 Q0 a1 B end6 p& E* w B7 g- A: V
%记录Y中点的标号和标记' |+ B+ K) Q6 J) g7 t3 z6 X2 N4 T) s
for i = 1:n
( |7 H" B% }% c. J) Y y(i) = 0;; P; _: ]* K+ _! @9 i4 m* t9 s
end1 F; z2 x3 f: h
%寻找X中M的所有非饱和点# a% ?9 C; u9 p* }
for i = 1:m
B$ ?8 J" c3 }9 d pd = 1;' ~& G% t2 p% V4 P
for j = 1:n S6 R/ i( B$ u, h9 `" A
if M(i,j)9 K% @$ e' N. Y/ {9 _3 C+ v! S' M) F
pd = 0;
" K- z4 k( i) S E- T: N end# ^4 p9 {$ `+ O$ N: \, e
end& A7 }! t% ^2 a3 f4 y0 p
if pd
( X, N n6 U5 m9 ?" m9 H4 A x(i) = -n-1;( R( y5 |5 @; ~9 c
end
5 @' E9 B% Z, ?' _ e( p end2 h9 u; I/ u. k( `: I
pd = 0;7 F. {+ s6 m2 i, ^- j. `1 g$ }- _5 q
while(1)* E% b% F6 X$ r; A* h. h
xi = 0;
- k4 e1 t# k X1 Z# @ for i = 1:m
+ G. k, C* n c5 X, B7 d( S/ k if x(i) < 0- u8 i3 R3 a( S' h t% p
xi = i;5 F7 P: K4 n- N+ i8 D2 Y; [
break;1 x5 `6 H6 x t o: ]1 X, ~% R ^
end
6 ~6 R2 V/ |! _& H- g3 r end+ g/ X/ z' [: [' v/ b0 E
if(xi == 0)
9 i3 f/ y5 a' |1 ^ pd = 1;
* {& ]' r1 m: z9 \: l& A1 C) I" \ break;- I! D1 W3 t( x' L7 ?
end
8 Y* ]$ E) L) X# W! a3 h0 z, R2 Y x(xi) = x(xi)*(-1);( [9 f P" a( G5 ~$ t
k = 1;
) k' p8 O6 T! d% Q9 z for j = 1:n3 M$ k# O7 v, Y+ v: D. Z
if A(xi,j)&&y(j)==0/ q2 N" m1 o- B$ @8 @
y(j) = xi;
+ P6 R! i& N% f yy(k) = j;
$ K3 X6 g3 ^. s9 d+ j1 m6 t) B k = k + 1;" y; Q h0 y) C% e/ {
end; c% {7 F, s% A0 _( L+ i! v
end. v% i6 j c. |6 i9 v0 Z8 i( r
if k > 1 A( d/ r5 C# e1 `5 e: n
k = k - 1;$ e# i0 m; c }
for j = 1:k% X$ p9 q5 E5 E- D: g$ n
pdd = 1;
- X8 \; t! Z( n) t! Z5 s) z; n for i = 1:m
4 j+ C8 u/ [. [ if M(i,yy(j))% [2 Y ^9 w3 f T9 p$ L5 O$ S
x(i) = -yy(j);+ d0 e' j) F& S8 ?0 L
pdd = 0;
2 L- W8 h0 @+ L* z6 I& i! W break;
" L r5 t4 ~! S# _9 S& x end2 U: H! c% C2 h2 i
end
; E/ _: f2 w; f4 n( N1 _ if pdd
H+ L Z: R( y/ W( w- V4 f- q: k break;
( d7 `; R/ {0 f end0 C* a2 b9 v+ {1 Y3 J
end
1 D/ o8 W# L' n! U- \/ P4 j if pdd 3 V* Y/ m& Y$ L+ Q: w2 s& O
k = 1;
; G# C# A7 l+ j, d. Z' m' P6 B j = yy(j);
9 f- ~& |7 U* o9 Z9 u while(1). S/ I4 y- z+ a$ ~# d' `
P(k,2) = j;; _: @/ {8 \5 k" ?9 X5 v! l! S
P(k,1) = y(j);1 v6 a" k& k" i: c
j = abs(x(y(j)));! ~5 D, @" `3 Z1 _& Q. B8 Q
if j == n+1
8 J' u# C- w2 N5 u" U( L5 ` break;
# ?# ~- S: A0 g, O& y4 U end1 z3 Y( L$ [" s+ X( v" l& C U# f: o
k = k+1;2 A# p, o0 R9 E: ]2 n
end' g) h# q) N7 x; k
for i = 1:k
" o5 |* B+ l' \, L( W1 `5 k. _ if M(P(i,1),P(i,2)); Y% y( E2 h1 e: s
M(P(i,1),P(i,2)) = 0;
7 m' Z# \8 o. J else
. Z3 n6 Z# D: z1 x M(P(i,1),P(i,2)) = 1;
' G+ ?( K" u6 K+ H4 }' P end n( ^" u. ]2 t& P E
end
* l7 c# J. l* T: _0 m4 X6 B, n- F8 F$ [, x break;
+ Z5 Q8 z! R$ ^9 {8 C5 N end
0 b2 b C3 d8 r$ z9 b end
* w6 @. F1 S: a3 d5 X6 ? end- g- \1 y+ h$ N/ e+ t! v
if pd* Z- ?% e) l; i" ~: b, S0 A
break;
. R8 n3 j1 i7 H! V4 i end
+ T) z) D# L% I( I$ w end
+ c7 I6 e& @( X3 C- t0 e1
7 k0 I! ]3 l: W2, z1 Y# |; j) D4 f2 f
31 o1 @ f5 [& j7 k5 V9 M2 z
45 v5 w: i, N: M& N( P2 L% o. B8 C
5
% u& k5 a U% ^# T; {/ m' j" w6
- o' E0 D6 ^* \! E! b2 h0 M+ _73 c; D4 m z0 _' ^, Z1 p1 I
8/ l; V& R- t9 Q/ u6 J, W0 s! D
9/ n; N9 a+ m" _# o, t2 l
10; t3 f0 u) X% g' D8 Q
11
& w& Y6 n% Y. n9 y/ e/ Z12' A m: M9 } ^5 |( ?1 _
13% Y3 N; p9 A* O* ]) `% x
14- ~5 F8 h J' N! n* I. D
15+ Q1 r& P( E8 y3 E# N
16
+ V5 p& C* g; I/ ^- w17% m v0 G' y3 p N* H6 W2 X
18
& ]$ m8 L! n, f19/ ~) l6 `+ ^% x9 ^# i
20
! W0 [3 u6 @/ `21
t6 {, @6 u9 i) r- w. x224 o# c ?1 w7 @
231 a6 @8 V, ~+ j' z" O$ [
24 Z- }6 B. Q' u5 P/ ~
25
) v. v2 i* U* Y: ?" T26
$ ?: I2 p# k+ s5 F2 C7 k2 |270 G @9 S- s+ _; F
28
& u; \. n8 }% R* w' }. l# ~' M8 E290 \* L+ Z, Q7 ~4 |* \: r5 X
30! R+ e; b5 e1 _9 W( }
31
; z( Z& N+ e" |% l$ {, T; l2 F32
9 l6 V" f5 _0 d: L' w8 u" ?33$ C# [/ r# w. e2 ^& e
34
6 H1 o- A* c0 w4 l+ Z35
9 O/ e8 u9 K% U4 i2 T, r9 ?36$ F, R! L" U& I- F5 D+ Y: ^ A
37
+ `. P0 p" s/ T38# h! O7 k8 J: ?0 h+ R
399 b B+ W( C8 Y1 h
40
+ U ~) y5 L, Y/ K0 }410 z1 Z i0 h6 _, N+ z( m$ d& q& x
42
2 ?& {! L, U5 x43
$ B; ~6 Q6 n/ V, O" `4 ?7 k+ q" f K44- [. `/ t! f6 z$ B
45
1 E. U6 Z, }6 P! R. S$ ^46/ a/ G9 D+ }2 f% T! E
47" L0 R3 J4 `+ L, \; w m! m
48; i" U, {% O8 U V7 d- n+ @
49
* r& ? S" O$ N0 u* |506 f- h$ i% x/ ~3 F
51
g8 n* h8 K: T8 r" ^52 ]( Z# W5 u9 c
53
4 C# N! Z* R v6 E D542 l' K9 R, {- r2 x& f
55
( _0 z9 i( Y; n( N, n) d56' L% ?" l5 j: o2 L9 ^/ s' M$ S* d* \4 v: Z
57
4 }( s7 I; t/ Z! Y8 T. B- F d582 D: X3 c, s! @( v" v7 F
59
" a0 J: L0 e- I, W- `% U" ^1 g60
) B0 |& j4 B( y) u, _: }1 S' o% G61" [5 K6 B" v; t3 n
627 D2 p3 L1 l: x2 Y2 A
63
9 T7 a6 }0 D. w- ` Q: P64
4 s6 l0 J8 r5 `% i9 h4 n) Y650 ?! ]: f; D+ w; L( q
66
9 h6 Z4 t7 D# N! W674 f/ k* E$ J- f4 _) X: `8 k
68) d1 c; U9 g8 l8 S
69
2 c* r# K' J5 c5 e H70- N6 b" K k& f$ w0 T
71
* ]! v3 z) z$ p0 v, g72
' q2 _& S9 H* @2 C6 r) o73
4 }$ u9 n! i1 s8 X4 P74/ m2 D M) w/ H) e
750 U- p9 f% P/ b7 B% Z8 T
76
8 O9 h5 d9 s9 o, \, ?4 `4 p8 d77
) g& n9 f+ ]' B( Y6 S7 z78' d' W, {1 L2 t& g9 X0 i
79 r: D, b1 m9 Y4 \' |( f
80, m3 Y L' M$ N
812 P r# `7 k0 o9 V g
82* n( G' W3 t! R: x
83
& @; H% f9 q8 U# Q84 c/ p8 ?1 {! q+ V5 s6 |+ W
85
" J% e$ V. z# ]3 r/ m. ?# n86$ ]6 B+ B/ J' M0 A* c2 O. Q
87
- B- ~1 t [/ |$ u88) j O. S" C+ |6 j& G! ^; U2 T
89
. n$ _8 ^2 b, Y- t& m# V0 i90
# M! F1 g; |) Q: c) w91
2 X: O3 D7 q/ e- E6 m$ q% L/ d4 ]92
7 I0 o$ u. H: ~* I4 a93
4 e3 s- {# ^5 P: c949 i5 N3 g' K5 ^; T
95
+ p6 i6 O$ p$ _8 k96
: _& Q' O: C; B5 L: s, ~1 T" \97
. E8 L; @4 c$ l6 @1 F, P1 D! w( Z5 I98
7 G, {4 ?* q6 X, @8 U1 B, Q99$ x1 {! M0 U9 X( K1 ^/ \
1004 G* O7 w( P$ Y# G; m* a) ]$ x
1012 W: O7 o* E+ t1 U. Y
102) j$ T2 u! h# {. A8 p+ f8 F! p
103) Q$ M- D: p8 O. p2 [
最佳匹配
0 a1 r1 c8 G' X, C: {. ] B3 T, q
代码实现:
+ P% q. K" w' p& S* ]- M7 S _% M3 w
n = 4;
[- \4 S2 R9 D! X8 sA = [4 5 5 1;2 2 4 6;4 2 3 3;5 0 2 1];* B2 k w5 U9 e/ t6 ]# g; }4 X" h
M(n,n) = 0;3 f% R3 `- b4 U, H' k% e
for i = 1:n
, q8 g7 S, i/ `; `4 p9 u4 E. z/ L L(i,1) = 0;& C$ R: J/ j3 Q) Y6 C2 ?
L(i,2) = 0;4 g9 y0 W+ Q) w- B) ?8 x
end' Y* x% ~0 ~. `0 S
%初始化可行点标记L
% l; h" U" g2 f& A4 C+ E; Z/ ?for i = 1:n
. F) u1 U9 E, [. C" x, d for j = 1:n
0 k4 S- [: ^- t/ v# @ if L(i,1) < A(i,j)/ i; L1 q: k7 `% A( L, ^
L(i,1) = A(i,j);
, z& T, k* n0 p, A; | a end7 O" f- R: `$ B* Y/ Y( s' h
end
" u' ]9 V. @3 R$ l5 D, tend
B1 D2 q% J' f%生成子图Gl
4 ~1 b/ }1 x6 E% \4 X, `5 Ffor i = 1:n, ]/ E# y& }4 o" D% |
for j = 1:n
3 @2 t- D/ u- C6 s$ Z if L(i,1) + L(j,2) == A(i,j)7 L$ }$ m6 u, ~
Gl(i,j) = 1;1 g* ^% N; q, y; c3 P
else' I: A2 K! s' n! ~) d2 ~
Gl(i,j) = 0;
, S# V; M" e: G* X$ r2 z* [ end) i5 O! ~9 a9 T/ h3 v
end) K! C" p4 B4 K# s( ?" F
end; @' {% R4 m2 i# s* f/ P5 Q' ~: a
%获得仅含Gl的一条边的初始匹配M5 x. X$ U! N: V- t S
ii = 0;
% B6 s9 w2 K }' Jjj = 0;) E) f( \3 w8 A4 q; y3 g# E2 ?" Q# K
for i = 1:n$ z! ~7 H. U! X+ y! N: L
for j = 1:n! e! p$ R$ Z5 T. G) [, u
if Gl(i,j)
; e1 i! w& G8 s% X4 T$ c ii = i;
; i9 Z% ?( c: ^- m- t. K jj = j;
$ l$ Z! P/ ~+ F+ d break;
2 [3 m7 s, c6 f- d end
. _; y" k. c3 y+ a; y end
, T- @% g, M/ N$ @+ ~8 | if(ii)+ Y$ G; {; v8 b
break;5 `0 r, ^% ^% }- V+ R" G
end
3 ~1 g& m9 m( c9 Zend
E' L" [ q; R1 @! ?+ W9 |M(ii,jj) = 1;. \3 ~8 t# y2 }1 m4 u6 \
for i = 1:n# Z) E O6 x4 z* q, c- l
S(i) = 0;: ]3 l% I6 G) s: b) Y: F( X
T(i) = 0;# e6 R8 Y5 t3 `# b& x) p+ d
NIS(i) = 0;
+ F) A8 P, W" l# y* Vend
# R! K1 R3 c! H) Q4 d3 p$ l
! j* A- H; r2 z9 @. w- w9 d2 P6 r$ s2 Y3 `% K0 R2 ^+ m7 t: e
while (1)- W% k/ @2 w7 I8 j2 a
for i = 1:n# u6 G" I: s& k& N7 |7 Z" ~; ~
k = 1;
' `7 }5 L, M! S5 p for j = 1:n
2 `, j2 D+ E4 K# g if M(i,j)
7 b- O' g$ m; k. J k = 0;
" Q N, X. N2 H' {( y break;& k' r9 {! k/ L$ E% p1 ~
end
" N9 w8 ]. o1 o, V4 v/ K end5 \" H' t3 M# j8 u( ]
if k4 i; }3 _: n- ~; r" }5 i3 s
break;
, h: M) g. u q# m$ ^$ f1 Z% R end
# D% s- x- ~6 d end
4 ]% q7 `* {1 R- i& C( l" S8 h%获得最佳匹配M,算法终止% H) o- y9 L4 [+ d
if k == 0$ e3 U6 U" R; x2 d$ i9 o0 r" b
break;
2 ?& I5 z' A2 t0 r- t% g end M7 A( }$ z9 z( a- y$ ~8 g
! x8 r- T6 t* g0 f
7 H6 |/ T. A+ ^4 j
%S = {xi}
0 Q- g8 l8 t* b7 q Z, f; a3 P4 CS(1) = i;& G% m4 p5 f! m# F2 m. G
jss = 1;
# W$ M: ?7 R' v) c% Vjst = 0;
& T) o8 x( @0 [( _7 B- ^while(1)
% G, w* v, M7 o1 ] jsn = 0;
: f P3 w8 ^! z. Q4 D% P %选择NL的值4 j& M4 n& o# [( F. U, E
for i = 1:jss" D5 r! h* p7 h2 }8 F8 o
for j = 1:n
/ r @) C+ U; H# P# R if Gl(S(i),j)
7 c1 O k, W A jsn = jsn + 1;
* K4 g+ @6 ]# E7 r: B: Q/ q NIS(jsn) = j;
" Y" K3 E% I: M0 m, G for k = 1:jsn-1. Z' A- D8 @* f9 ]* J( N$ \
if NIS(k) == j
/ Z& _$ A, ~% U jsn = jsn - 1;% A v6 r6 E* W2 u5 |' ` M
end& [. a* I- a) G) K* f& S( q6 o
end) \7 |' `7 y/ |) O. ?
end
# X# `4 b% A- ^" a end
: A3 N. d; u' f end2 P6 J! l7 r) M8 h$ J0 v6 X! X
%判断NL(S) = T ?
- i0 |( `7 t' }" h" M: r8 V( c if jsn == jst
* p G q y. L7 q+ q pd = 1;
1 W2 [: J5 e4 O( l/ C- e( j1 ` for j = 1:jsn3 Y2 K) j' C: R6 i# U4 Z t+ q' r' f% L
if NIS(j) ~= T(j)+ s) w0 \& B5 _# o7 f# S% k1 R# C
pd = 0;
7 y5 ^) E7 k3 B3 Q, T break;! D5 T, h. p* x5 w. p) ?
end
" V* G: w9 `$ C1 {5 ?/ X; y5 Q end
4 f% A( C- {, |) m( X1 q$ G4 o end
* f$ W4 }; @% E- U %如果NL(S) = T 计算al的值
7 w. S$ d$ }' A3 h8 F; r if (jsn == jst) && pd ) `" A- {% _1 c/ O) y* Q6 T! F+ q
al = Inf;
. I+ t S! [7 y4 k( }7 H5 E; H for i = 1:jss
. l9 a- c5 W' L* `7 C: B# M; a0 m for j = 1:n) `# ~. W4 c7 _' T& ~: C' o
pd = 1;% p3 C7 S, x4 g
for k = 1:jst
8 } |7 M$ u1 y7 J if T(k) == j0 n2 s( }5 z% Y
pd = 0;* \9 ?: j8 d3 }
break;& ~- h2 C% f- @1 v* l
end
8 A8 v) G) s- Z# F! }% J end
6 r' F' z7 z- ~8 u. m& k if pd && (al > L(S(i),1) + L(j,2) - A(S(i),j))
- z# ?; ?) j; Y1 ?- X# O1 J Z6 _ al = L(S(i),1) + L(j,2) - A(S(i),j);$ c" H9 @0 p) R1 n" ?- y$ n
end% ?" t" T% ^/ G, G; k. S9 t
end" J b8 m; F8 I
end
& @6 d7 E4 }, [" T8 J %调整可行点标记: f6 X1 N0 D$ f1 O0 |2 P
for i = 1:jss4 M# g7 h1 e% \- V7 @/ v+ Z
L(S(i),1) = L(S(i),1) - al;
8 W" K6 R* U; L# _ end4 Y# {2 F# Y8 u
%调整可行点标记 m; l7 u8 h% u! |$ Z
for j = 1:jst- T/ h: D! r3 f
L(T(j),2) = L(T(j),2) + al;% [ \" A7 Z ~' c, V/ G! y2 r
end
0 }' d6 k/ [4 n. F' [* }. Y* h. r %生成子图Gl
* Y& g9 e1 M& B' q4 r( E for i = 1:n4 v4 A1 \' P7 e' P1 Y+ |2 M
for j = 1:n3 `0 O* g6 c; o
if L(i,1) + L(j,2) == A(i,j)" g; L3 r# |- T9 g3 g6 d
Gl(i,j) = 1;4 g6 G+ p' I X
else! J: [( z+ ]* t! P6 X' j i. i9 I) A
Gl(i,j) = 0;4 J! o1 W" h. C' c% J' U6 Y
end2 f) E5 j& Y9 ~' L8 s
M(i,j) = 0;' Y$ }& n) z! }, d) n `
k = 0;
7 p+ L# t0 n& [8 m' H# Z: M end
1 K6 ]9 A' t& v' G- ]+ ~ end
) z6 J$ S2 e+ a8 a4 t7 T: i %获得仅含Gl的一条边的初始匹配M, z. i3 n; S' w3 X9 L* y' V0 l
ii = 0;
1 K- H O y# p% i9 ^) c jj = 0;
$ Y) U$ \8 O. @* s for i = 1:n
$ a7 }1 m2 @3 Z' c+ ^ for j = 1:n4 U, q. D- n+ Q' r
if Gl(i,j)
9 e; x" L5 M; U) {) O ii = i;
, ?' U$ U- I5 ]2 c jj = j;
: j2 b7 v1 b2 w: D6 F: x/ D8 A break;
' y' }- A& E f Q8 R i9 `: x end
! ^6 Z# z, q; u8 W" U& p4 N6 u end
( V( ]7 C' b J if(ii)* x6 S! R5 b2 s4 {
break;" W1 m- c) u7 f
end
! \) f+ O% ?- s end$ {2 A& j7 M! g, ?3 y
M(ii,jj) = 1;5 D+ r: d3 b6 V6 n* |0 P
break;$ \2 J3 a! h2 R- H( f
else Y. r" b7 N J! T: [
for j = 1:jsn
i D1 f, B" ] K. w; D pd = 1;
. c; [# l }, c3 u/ @% i for k = 1:jst% K7 [# Y2 Y( h7 X( }$ ^, f
if T(k) == NIS(j)
3 b5 Q E5 L4 H) ~! w0 C" P pd =0. K$ ?! Y' N9 m- [/ `2 l
break;# s$ ?3 _6 \# m/ s" P
end! X8 k& S7 `: z S
end
9 V* c5 E7 n$ K( ]* A0 N if pd
! n" ~% V' s9 ~+ M: A+ V jj = j;
; v. G) I& G% Q) E& i' u$ Y- {7 K break;
' O8 n5 L9 Y4 p end- ^/ V6 v) y4 O- L" q% I' N; F
end8 M) t/ W+ x) `+ e# k
%判断y是否是M的饱和点1 O( v+ n# m5 ~: P
pd = 0;
; h' \1 `5 Y0 j k2 V+ | for i = 1:n# o$ T: w7 q g% j- r
if M(i,NIS(jj))' |# r* o n5 r; r0 |$ I
pd = 1;
% p" [, \- ?3 o+ L5 w) w ii = i;
( Z4 ] s0 {, W break;
9 L7 P' `9 [: N6 v* P! N6 P end0 l7 r2 w+ A" h) v4 y4 d7 r) {
end
9 @4 J6 y; x1 `( U if pd
. S+ }0 x+ y2 [6 j( { jss = jss + 1;6 m6 i: O3 \, a% b e( J! U' J
S(jss) = ii;
- @- A" U6 s- o5 V jst = jst + 1;. q6 d2 x, W' y% `% h* U6 }" t
T(jst) = NIS(jj);
$ o5 Q! v! Q. J9 K8 v4 _ else
8 g: m6 P& L8 S/ K5 r P* m for k = 1:jst$ i0 g w. x4 d) D- y
M(S(k),T(k)) = 1;7 [( e! u9 W; ]! G% Q; r1 b% j3 \1 Q8 t
M(S(k+1),T(k)) = 0;
- l3 f% k5 C! D# {0 o end+ a! n9 R6 Z/ o$ ~7 N4 u5 `5 a& j
if jst == 0$ N9 `! l* Y; [0 j% [& Q" T: `
k = 0;
9 M: u3 ^! r" r! E$ F6 o5 Z: X4 b end
/ v# j" o; M" D( ~5 p M(S(k+1),NIS(jj)) = 1;( p" q! x7 N9 M0 d4 ~" D8 G
break;0 H! |# n9 p* ]9 P
end
. M h! t M* H7 M% U end
2 O7 j! ?5 T! X% h' x! g5 t end. p% v' j' e5 L! t
end
4 L$ S; d+ W8 [; i) f MaxZjpp = 0; k' K, N$ k0 ^; [6 X$ P$ W
for i = 1:n
' ~( O: d: I7 }$ g" O; @# c for j = 1:n
`, \7 O" p7 h5 u2 ^' C if M(i,j)
7 Q' Y( \2 L9 N/ G: S MaxZjpp = MaxZjpp + A(i,j);5 Q2 B* H' L9 J% m/ B. c0 `! [+ o
end
2 |. B% h" u9 x+ n8 p/ f end
$ |5 d$ z+ L+ J: o4 [( T end% Z" k& m1 J4 P6 Y' a$ n
M5 F! E" T- L# X( `7 t: Q- o
MaxZjpp( S3 A: f3 D9 B; M
d. E0 x N5 T4 U: N, u" _* F
- `2 @6 Q4 b: V, _5 H& J$ w, Y" p2 D4 ^. ?6 n/ A
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zan
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