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TA的每日心情 | 开心 2021-8-11 17:59 |
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签到天数: 17 天 [LV.4]偶尔看看III 网络挑战赛参赛者 网络挑战赛参赛者 - 自我介绍
- 本人女,毕业于内蒙古科技大学,担任文职专业,毕业专业英语。
 群组: 2018美赛大象算法课程 群组: 2018美赛护航培训课程 群组: 2019年 数学中国站长建 群组: 2019年数据分析师课程 群组: 2018年大象老师国赛优 |
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最大流: ![]() 注意Matlab 中的最大流问题是必须是单源和单汇问题,因此这里需要构建虚拟的源点S和汇点G。9 |2 p4 {9 j3 p4 k6 Y3 N% f* O
clc,clear
* V8 K% M1 ]# \; J! Ea = zeros(9,9);9 W$ C' Y6 B' B% }1 h9 f
a(1,[2:4]) = [20,20,100];
, b3 D. Q( A/ K4 Q$ W! W9 za(2,[5 6 8]) = [30,10,40];
3 J4 G# `2 I& P5 O+ Ga(3,[7 8]) = [10,50];
1 U# N8 j3 X0 H8 j( xa(4,[5:8]) = [20,10,40,5];
t7 F# B" S) j/ I- g4 Ba([5:8],9) = [20,20,60,20];
$ n5 E# [1 Y! X4 sa = sparse(a);
5 i' y7 H6 d+ V[b,c] = graphmaxflow(a,1,9)
, }% O. b! A" o- }7 \+ n; V最大流拓展:最小费用最大流 仅仅是在求得最大流之后进行对最小费用的求解: ) w9 J' a" o* c
clc,cleara = zeros(5);a(1,[2 3]) = [10 8;a(2,[4,5]) = [2 7;a(3,[2 4]) = [5 10;a(4,5) = 4;a = sparse(a);[b c] = graphmaxflow(a,1,5)6 z) h0 h. H6 A# |
最大流量为11 自定义Matlab代码: 1 b P+ v. C% X2 E+ p/ [
7 u; M$ w6 A8 c最小费用求解! o* A6 ^% c2 j
' U8 u. q$ U, j- Y) ~Lingo:
. J5 z! r% I+ {3 c u* Y
! L( u& w. R8 f5 n! W9 M& Nmodel:
# v+ \. H7 _. A, `: b( Csets:; O+ S4 u5 r" C% _6 q
nodes/s,1,2,3,t/:d;
) V0 T$ _* e) l% D! zarcs(nodes,nodes)/s 1,s 2,1 3,1 t,2 1,2 3,3 t/:b,c,f;
" J' V& f. x \0 [7 o/ r& Kendsets# ^. f2 [# C" b6 o( l/ A& n
data:5 c9 X O$ X4 S" W" @3 P6 B
b = 4 1 6 1 2 3 2;
9 o, i% s; F ]7 C# W; x: yc = 10 8 2 7 5 10 4;
! R+ l; _' x0 z0 y8 t0 _! Ed = 11 0 0 0 -11;
2 W+ E* L7 V& Genddata0 ^, t2 Y" u: L9 \; g6 T3 \
n = @size(nodes);
. V5 e& W( O! d- u3 l8 E6 wmin = @sum(arcs:b*f);9 l9 R: X8 n) l+ E! k5 r1 q9 C( e
@for(nodes(i) sum(arcs(i,j):f(i,j))-@sum(arcs(j,i):f(j,i)) = d(i));% S3 [1 F" w3 e2 A# \: Q& K4 e5 |
@for(arcs bnd(0,f,c));
6 {2 }- t; q+ s# pend% f& V" [& d- Q5 Y/ W/ q6 K" R
1- ^2 L1 Q. Y0 C a2 `- M/ l
2) \$ z" d- c$ d8 l
3. F! D( J" h( y7 [7 q, Q' }
4, D3 u' ~, I& T
5
% q# R: r" u' k' D# o' l- ~9 T6
5 G* N% ?# P5 ^7/ s+ O# y9 H0 R% D: R
88 }7 w3 ^; K/ g% a
9
2 G7 K- z( U9 ?; Z10- J% v: U+ R A' \
11
+ F1 r0 R. X+ n$ `12/ C/ ^8 I* G) z9 T# Y
13
- m( }5 E$ J: b/ F& F8 E9 T; U14: l5 N- k* g9 O, C. D8 B9 R
15
- ~6 q) n/ M ?* v6 B8 JMatlab实现:) N* Y% p& i! L; w2 ~3 h
: c2 `# y) X: s" E3 {& P' C$ K
: Z7 Z3 v# |9 G( Z. W: @2 R6 N
n = 5;
* m/ F. C" t" m3 ?* `$ n+ g( `%弧容量
Y8 A% k4 O {, n. F& ^/ O- Ca = zeros(5);
0 L! [6 N- j+ c- Pa(1,[2 3]) = [10 8];5 F7 Q# S8 q4 n2 k
a(2,[4,5]) = [2 7];5 [$ }! e# Q' ^. k
a(3,[2 4]) = [5 10];
& i5 Y4 K4 v0 Q! ~* g3 R2 Ba(4,5) = 4;
* W7 K, u/ G4 ^4 D) KC = a;
' @( @9 O7 h% o%C = [0 15 16 0 0;0 0 0 13 14;0 11 0 17 0;0 0 0 0 8;0 0 0 0 0];
, j3 U: C& Q, @* _9 Z) @: V%弧上单元的费用6 B" v5 `% }, g5 E- s' N* ]$ a! O
a(1,[2 3]) = [4 1];/ M7 r& K. \' G9 H
a(2,[4,5]) = [6 1];
. X1 A/ z% Q/ d; l; Z& a- ]# Ea(3,[2 4]) = [2 3];# S2 G: e$ W9 _) \. w; ]' m9 o
a(4,5) = 2;
+ Q k& }' V( ^b = a;5 ]: [& [9 A7 G$ n0 }9 {
%b = [0 4 1 0 0;0 0 0 6 1;0 2 0 3 0;0 0 0 0 2;0 0 0 0 0];" f. e" O# |0 w; w) r
%wf表示最大流量。wf0表示预定的流量值2 r0 Y' n, X) Q: Z+ C8 a, ^; n" D
wf = 0;
9 G5 P- u, w D9 w* d# dwf0 = Inf;
0 M9 V6 B9 K) Z! Z- ?4 Q4 D%取初始可行流f为零流) W/ v# x3 E5 O, M: ^
for i = 1:n/ x: v) |; ?, p
for j = 1:n
8 i: k1 K' m, {" m% [: \5 D f(i,j) = 0;
6 j9 r- r4 b1 m' r9 n end
7 a, c5 ~9 s1 z# Aend9 v6 X% }. M/ E# b. H
while (1)! @+ p6 p+ ^ U/ d4 ]
%构造有向赋权图
% D. |+ I- E! p- M- }1 Z for i = 1:n: [- }' Z% B5 R, U4 A+ ]
for j = 1:n
! i% L& S( @, p2 m" J" a! G if j~=i
, V: \/ O- J% _+ H6 c( \/ M a(i,j) = Inf;
5 {9 K* o$ {+ D4 W9 |6 d5 ^ end
5 {3 Z, V8 S% i+ h end' i( H" x! f* `- f* w; G# V
end6 t: f8 s' G% b: D& q5 T; d/ |6 b
for i = 1:n3 l0 c: I) q- O. y1 y; ?3 Y4 g) p+ R
for j = 1:n/ c" u; a! f6 g2 M0 h9 L
if C(i,j) > 0 && f(i,j) == 0( C& y6 a- l" g1 u; `
a(i,j) = b(i,j);$ J. Z" N3 V; |, a% o
elseif C(i,j) > 0 && f(i,j) == C(i,j)& J; \, `" O2 g- }, c
a(j,i) = -b(i,j);
% y b) b8 \9 m elseif C(i,j) > 0
4 @; Q6 {& ~* v) v; g% f a(i,j) = b(i,j);' W/ `4 Y/ N2 L/ l% \) _
a(j,i) = -b(i,j);8 `$ v4 z7 L+ Q) W, h3 n* p
end
, N7 o$ B+ D8 [& X# e) u end
8 n& C1 {, m" z5 u4 J end" ?. M5 ?. n8 l& W3 e/ k
%使用ford算法求最短路,赋初值4 g; `* j7 b7 }2 z
for i = 2:n' P8 n! C, ~: q* z& T; N
p(i) = Inf;
9 A/ D; h0 t+ @' V1 P( G s(i) = i;
) R# ?% C" y, X9 K* y end3 N- v' A. u" X: O9 A: Y! D
%求有向赋权图vs到vt的最短路,赋初值5 ?+ w$ i x+ |
for k = 1:n
0 L& q9 n! O* f, ~: Q3 D4 B pd = 1;( \3 g( e& w$ E2 Q9 q4 K# j
for i = 2:n
& x0 f! Y: Y( u, u* ^ for j = 1:n
/ l; B( r5 T2 T: F. P if p(i) > p(j) + a(j,i)
6 t S- |! G9 B ]4 J, x3 X) c2 t p(i) = p(j) + a(j,i);" U: }/ [+ X6 e4 o% G0 X* a% J2 W
s(i) = j;
; b# E. T) x7 Q0 c" m+ O; i$ ?4 [ pd = 0;1 _4 U/ e l: [3 Z# L d8 O7 Q
end
9 n4 Y& k1 d- C3 \ end
! h) b6 M$ @+ w end! n5 g* n4 k: u2 _9 N, _# [% z
%求最短路的Ford算法结束; k1 F% D! ?$ k& D' L) \
if pd+ N4 @. `' l- u( b0 Y n+ {
break;: y# f! b5 l$ t4 j
end
* d0 x# Q9 u) U/ a# Q end3 S, m$ H$ E, F* @5 U! j
%不存在vs到vt的最短路,算法终止,注意在求最小费用最大流时构造有向赋权图中不会含有负权回路,不会出现k = n
3 K/ @2 p( `- e( B if p(n) == Inf# K# Z7 A+ c* U8 c! a
break;
# J6 X$ x% @% C. P3 U! X3 C end5 G* |" d, M: G3 n
%进入调整过程,dvt表示调整量- h. g5 m$ y+ w5 g# w/ ~
dvt = Inf;
3 g. w2 L7 Z1 Q, w dvtt = Inf;( f% E- Y. h3 T4 ^( |8 s
t = n;
" \8 a1 {" @ F while(1)- S- g( i: d1 s. E! @; H' v
if a(s(t),t) > 05 H* G* H- c9 {( q( q/ T- M
%前向弧调整量& h* e$ O9 `! c- K4 H
dvtt = C(s(t),t)-f(s(t),t);+ y0 n1 W3 p1 `6 c# i" J
%后向弧调整量
5 I; r' J4 w4 q* U# v, A/ L elseif a(s(t),t) < 0
2 t& z: y2 l/ K! X# J) n dvtt = f(t,s(t));6 }' r1 j& l1 a+ b
end
: y& p$ W6 z) M* O. m if dvt > dvtt" B. i: y* O5 P( j$ `
dvt = dvtt;
, G0 M6 x1 c7 L end
& {0 h" O. x/ O %当t的标号为vs时,终止计算调整量. J5 J9 Z* [0 O! { n) e7 D1 U: M- G
if s(t) == 1
+ [+ F3 E- O+ w7 O! \ break;
$ c' A8 v' C: ^$ r3 O end$ A7 T3 \! F& B( @# l! U6 A
%继续调整前一段弧上的流f
3 s: Z; V( [9 r% D* t' h t = s(t);# C! D2 X* [( k
end
' L5 e3 G9 @0 ]1 G$ T. ^( ] pd = 0;
9 o1 S1 A$ K7 o4 X6 s' O7 c$ d %如果最大流量大于或等于预定的流量值
4 a, h0 O8 N6 D5 }3 N if wf + dvt >= wf0
/ j5 p/ K- o- X9 d+ t/ f dvt = wf0 - wf;
; a7 z, p! q( W5 q6 R2 N( u pd = 1;9 n; d8 D8 g# u: I( l/ x5 B8 z: y, ]
end
7 k2 s8 e% F& i; t8 H t = n;
. R, P0 H( Q) s( @0 S %调整过程
/ g8 X% H, {8 X) `2 N, u' S/ y while(1)
0 c; M- S4 T# U3 ^ if a(s(t),t) > 0
Z/ u. J1 C7 A; v! S+ J %前向弧调整
/ H# H3 G; P8 f) N4 O5 a+ r5 ~; I f(s(t),t) = f(s(t),t) + dvt; . M% a, N O8 K3 y
elseif a(s(t),t) < 0: e8 p1 f5 L {$ |/ q
%后向弧调整: {/ ^' i2 ~% v6 _2 T* y
f(t,s(t)) = f(t,s(t)) - dvt;
+ v/ o5 ]9 w) q end
2 ^3 [0 J1 q3 s7 o %当t的标号为vs时,终止调整过程. p' [8 E( l" |+ H1 _
if s(t) == 16 S1 t9 _' H" N) X8 ^
break;! Z: w# Z& E8 t( S& s! y
end0 ]8 z2 g( ^) i: v5 O
t = s(t);$ h! q' i. t* ?9 I
end; F; J) u7 W) R3 m8 |
%如果最大流量达到预定的流量值1 ]2 @; f7 j7 p" D' \' v
if pd
. T# l9 Z, f, J( g3 a8 o! I+ ~) G break;% I$ d3 E9 [0 N- f5 Y0 ^. |% h
end
3 i0 e+ V# a1 d6 p %计算最大流量% e/ F5 K% j, p6 N6 d
wf = 0;2 G+ N; U- q( t. ^0 i
for j = 1:n0 V3 ]7 N& T9 ~% f
wf = wf + f(1,j);* n8 J+ @( G+ T' q: @" |7 ~- ?, F
end
0 [3 j: z4 W4 Y" eend
3 {8 p6 h" {3 z$ Y: _. K%计算最小费用8 K2 X9 [7 I/ N( n
zwf = 0;1 X0 J8 @8 T) m
for i = 1:n( C0 M+ q5 B5 {6 L' O i0 R' x
for j = 1:n$ S- q: ?6 G: \2 c$ Z% D, ]$ a
zwf = zwf + b(i,j)*f(i,j);
0 _4 w ]3 f2 F1 y' ^: E end( D4 i' |, M% Q% W& ?2 h4 q5 t8 Q
end: o1 u' h. @' q @5 q& n
%最小费用最大流
# m* b- z1 d7 Ff
0 G0 v! o8 }" g& ?7 c* F- l2 W$ N$ Q% q%最小费用最大流量+ t+ [+ f" k1 K1 p1 H- ~% ^0 s
wf
. O3 J1 ], o9 Y; u%显示最小费用
" Z# W1 F) c# g9 H4 U4 kzwf( t1 [$ n3 z" d4 U& m
1
q6 L4 g( q- @2
; D$ e5 s0 s( W/ N) X' M1 E, m32 u0 s' D! u/ l4 L
4+ t% _ a! f1 s0 l, u
5" z. d5 l3 V ]* r. m
6
1 I' e4 p' ?0 }( T. c5 o72 d0 m. g: s b3 v
8
* M7 J; A/ ]9 H6 q9
9 K* q! R, h5 A' Z5 M9 f10
$ h: |0 Q' r/ f; @6 Z9 T111 G+ j5 ^! m/ D
12
8 f+ I7 ]* q1 h4 A; G132 i+ _- p7 l% a. u ~
14
7 @5 t$ h: Z8 U. U3 w15
* f+ N1 w# w, u: B& s16
" g: l0 v" P' u: @+ v& f& a& [3 `17
9 Q, T: b0 L- @, q% }* Q% l' d187 H, P5 o: S' b( d' L$ I
19$ r. x# U: J. D: |
20, @8 T/ L" f; L6 q8 G" g/ G4 r
21
2 v7 B' C$ h2 U+ X& f3 C8 n224 { y4 k* | r. b: Z6 d# i
235 P8 N+ o4 K6 U% q$ Q' u0 x# O
24
: n1 F6 f7 y; U2 _4 e; d5 g% K25# g2 K) q7 E% \ F4 Y3 a, K9 @
26# L" @* B- D; V @7 [4 S
27
. ~/ o/ q; {* T287 Y7 G4 x% }, W$ b6 i3 q/ R3 R
29: d, x1 u q0 o A" |' ~* U) `# U
304 W1 [% R' V$ Y. i, p
31
M. N2 v8 t ]4 o7 J0 ~( P$ Q3 J32
9 c# w* D$ `* m336 z2 `% ]/ ^% T( T) S# U3 u
342 w4 h3 A: j. _7 D. Z
35. k: ?$ b r& s7 U' E! g6 W
36( L6 g5 y6 B2 G9 U
37; a( k2 C/ D$ { \3 J
38: d! w+ @# K8 S! m
39% z4 {) }8 A6 Z0 v& S( y; A, K
40
' n( l# q9 F$ b4 f- {+ w41
. P7 y/ Q; H0 w42. s1 m9 f$ m7 e# x
43% L. p7 ?6 A- K! x& u
44
7 I" o* F2 f/ c M/ M" `45
* O1 C# B( ~! H7 x46. q9 T0 R! u. J3 j+ u
47
* i" n# w! h! |2 @7 a! m. Y/ e% D$ ]6 e48
8 W# Z4 \! {- X4 q. A49
! b+ T4 ]* b, u! Q, R50$ X% a2 k* O& t3 M6 l4 \
51
$ `' r4 V1 R1 x6 P/ R; e52
2 D K2 D3 K5 b9 h' \7 n5 u1 H! f* Z53; Q# a5 O N! H: D5 S# Q9 x6 Y2 @
54% @& \4 n( c& h# Z) b- f
55
9 v4 w1 b% R0 K# D2 m56
1 \) `% C. G6 r$ E" r# |! U: u( u57
! X0 K. h2 D( h& |, q58! h* w0 G* W, u6 G* g( o# t
596 _7 a5 D/ ~' l) @
60, S4 q m; E# {, I
61
5 F# y: i- `2 `# b, z62; |& Z4 g8 ^) w
63
3 U0 R( ]' J0 @) D9 C/ ?8 s, U% l64
; C1 H: h+ ^5 i& C6 X65. P2 L' \8 H" `* a
66
1 b) p7 F6 {5 x: I( y$ |, D67' E- w @* L, h- S" w% g
68. l+ Z9 Q, x! K8 {/ v" ]/ h$ x
695 D+ C( K. s4 ?- i: |+ i: j
70( G- {# O) T& R3 D* Q1 X
719 X' g: y! R+ \8 H m7 C
72
4 c6 O5 x) ^8 s! h* X73
0 ?- S: R: K* J) ]. s74
# ~& u( ^- a: d) Q9 }/ {75( @# B5 w2 [" k1 Z
76; V& E# N4 L U% X" Q/ O
77
6 K& e0 \/ w) V* v# s1 a) p* y5 E78
3 y+ G* Z2 n: d4 [5 Q79
# q$ V t* N m0 Y% _7 c80/ m- I9 e: y/ w2 @! U
81
+ X5 H. \9 Y. O82
% J# V# m3 Q3 Q& n83- u6 U& b8 u: ?; J: \
84! R3 f# M9 U/ U
85
! }2 Q: P3 y$ R! X7 x86
, o% u$ e. |4 V4 z. R- V879 r# n' o! W% p. G9 ^& c6 H
88
2 E0 _" r- C. a) r- Z$ X5 r89# V( E2 G9 B. D3 _
90( X( y2 ~8 N' m3 f# ^% i3 z8 \ v
91
9 g* T0 h+ W, l. s" h/ e$ S; J" h92
& n9 X t0 t3 Y9 m! r1 m: U8 d) [93
3 t+ s; i7 y2 j N4 g) ?94
' L O& {4 D: o2 e7 O" @95
4 X X, w% {; S( b' p96: [* r4 a4 S( Q( t5 i
97
% }' E8 a4 b7 I) t98
' M$ e1 }! \; P99
2 a0 Z; i3 ^" F3 S100
3 s' m) _5 h5 a+ t0 a) b1 [5 }101
8 E* X6 q7 [; v- a; u; M102
( U& ]. x% L. q$ q2 B( p1035 R6 d9 a% c9 U
104* i0 r% \ A! G5 w0 Y
105$ W4 G' I" p" B0 B+ R1 ]
106' z7 z: h3 a: o* e- f+ `
107
9 {3 _. e7 g% T$ A; i2 I. G108
* {. M2 h+ n( e# X- v7 r# o1 r& U/ c( T109
5 Q; M* s) F) G/ }4 q( X9 _110
1 k- T, k6 s# k1 X+ ~ h3 U111! ~% z: H% S" k* P' K2 P' D
112. D- W% C( k3 S
113/ R- C( w+ e5 C1 J1 v. t4 U
1149 g. v2 G7 z# r! J6 t8 T9 u
115. a8 A3 L( ]) B1 G3 S, k, k
1160 [) P2 ^3 Q; S& l% G$ U
117
) Q2 A- @( i: M118. m& ^, G- I% ]; i) ^, P) H& V- A. j
119
+ _5 s! o+ w6 t6 U# X L% ~+ _120
8 P) O* T3 K5 N0 [8 U" r. M1211 C) S0 ]3 @' D8 _, _; {( ~* }
122
: T/ K; `8 h0 E: F( I123' Q4 w! a; M% x2 V: z8 s* Y
124
+ T% a8 W: x" H f) X; x8 K$ |" j125% W0 R: n# x9 h; P; R D- d, B
126
1 {6 [! l7 o# T127
9 x2 p8 l, a1 C128
+ t5 w! ~9 O) ^4 q( B s129; R$ T9 E! P$ l6 U2 B D- u" X W
130% [; ^( D" o: c
131
% |& ~( W, {* q, H) M& B1322 |9 |/ a& i6 J) u: o
133* R4 d9 U! {# E) K, E
134
# f# b7 S! w0 s: @. e$ S3 ~6 S135 M1 w* B2 V5 c1 i# e
1363 N& \8 h, r( E# k; g
137
6 Q# p6 r! @" p, v138, N" t- Q, Q: ~3 c9 e
139
: ?& |, P i, g9 g. O8 x. K140
2 d. X) O# c8 m1 A! F1 U匹配问题:1 h! n7 s, ?1 M- ^$ T a; \
" k% A4 c* f( C& E, h+ F
最大匹配:* G- T) n% u& \5 g5 Y# g. N, n. Y6 ~" F
![]()
2 A- ~) _2 {5 Y! b& o" y; r7 n7 _9 d5 {7 w4 l) G- q# a+ m
代码实现:! b; K8 N' M7 \
; i8 I, W6 o( \. u% ? ~m = 5;
4 V$ x4 ]0 b7 G' P1 N2 Bn = 5;
& D6 o. x- K6 d4 iA = [0 1 1 0 0;1 1 0 1 1;0 1 1 0 0;0 1 1 0 0;0 0 0 1 1];1 [: \7 k$ _! e
M(m,n) = 0;
" e l7 V. y' E. f: E5 Z% ]/ r: Afor i = 1:m
. x# z% s1 [4 K, p3 p% ]$ p3 {* { for j = 1:n
, l( N+ ~4 j* @" z %求初始匹配M, e% R- {4 s3 a* n0 ?0 d
if A(i,j) ( Y4 Q. z! c4 N- U" O
M(i,j) = 1;, A% Q/ G l8 Q4 s
break;
& u7 V/ X* ^ w! Q L( Q4 x end
2 x% |8 p) g0 l& | end
7 y& J ^9 p0 j5 T2 h6 k %仅含一条边的初始匹配M
# P/ \9 y( Q' F if M(i,j)
5 r* d, w& o4 ]9 w' _$ T break;4 y( O' O+ ?; Y0 z3 Z! C
end8 O% J& X0 T2 i: d; d! `
end
2 ?) b4 ]" h, I0 B, `! \6 C) b _: ~
3 T2 g+ x S& G* [0 w" W: Swhile (1)% t' s I$ ?0 f$ o
%记录X中点的标号和标记
- \1 u1 @* z' }/ s for i = 1:m
) ?' C0 O9 \5 p- l( Z& z x(i) = 0;0 u4 ?$ M4 ~+ p$ t& ]
end
4 b- d: m7 H' C4 V$ [) K %记录Y中点的标号和标记& X$ e0 N8 m& c7 G' v& u8 M
for i = 1:n
0 ^! R, ^) J ]! j8 V4 L% O y(i) = 0;
}; b0 L3 v6 v' i" t {: s5 b7 m% I* Y end% `. R4 s+ T D) Y9 X4 }8 l
%寻找X中M的所有非饱和点6 C# `) M9 r8 V( Z8 E
for i = 1:m
: t0 g8 [ f; a% `8 P pd = 1;
/ n9 p& j2 t5 ~5 [ }9 M for j = 1:n+ n: W8 ~7 Z' p* @% U- X
if M(i,j)
/ I% B- ?# F4 ~$ T# H4 z pd = 0;
( {+ b& \% J* {3 J$ a end
1 u4 V3 F1 _% _1 Q end
# v7 Z. n7 P0 ~. t) | if pd4 u# Y$ C% @; H$ C& N7 B
x(i) = -n-1;5 H7 e/ Q8 w7 h9 p
end
- A8 i) S, a: J3 H4 @9 ?& {9 b end, H( u0 P4 M& |% |2 K$ Y: `6 g
pd = 0;
* t/ m$ G/ Y$ j& D5 H. T. Y( S while(1)
. B5 i, w4 r& E2 X* A, a; M0 ` xi = 0;4 k( I% J" Y: r7 `; N! I
for i = 1:m: t0 F1 ~1 ?/ b/ }' S& A3 a6 P; t
if x(i) < 0 a: f: L6 i. Q' h3 R
xi = i; l8 ]" x3 u+ K$ Z5 q5 j9 N3 X
break;
; B% v$ R+ h0 x" C1 [' c end
$ A4 H$ p& z% Y5 I M end
* T9 A1 V: l! u" x* X' @ if(xi == 0)$ U0 i8 a; C+ e8 p1 t$ ^( M
pd = 1;1 m0 t/ X/ `: s
break;: R0 A# X1 ?9 ~% k$ w
end, k. i6 W! _& [
x(xi) = x(xi)*(-1);7 q, U- f8 C2 M( J3 t
k = 1;
) B5 V$ u% n' G4 p+ `. O) K0 X for j = 1:n9 r- S. x9 Z9 s! ]: m. {
if A(xi,j)&&y(j)==0$ M* Z, |! b, j' p. W7 D
y(j) = xi;8 j2 k' m4 P* W/ H
yy(k) = j;
3 ?; W: G4 r! `2 I n1 i k = k + 1;
( e0 ]* s: P+ t8 A" \9 Y2 A end
9 q& C0 v! x [# i# A. h0 R: k end% T! b o# k- u- Y @: K6 G* z+ K
if k > 1
4 N$ ]4 K' T1 K3 g, h' Y k = k - 1;* m5 y0 K1 H% ~, L( y
for j = 1:k
6 H4 s i5 I3 s5 h pdd = 1;
/ \+ W8 _5 x3 i8 V for i = 1:m2 H; E( y( V" S+ V) h
if M(i,yy(j))
5 [: H+ T/ i+ k( e x(i) = -yy(j);
2 P2 }& [ @$ r3 p pdd = 0;
6 B! i7 ?' L. E/ Q: H2 P- X break;
7 I, b' |$ H4 | end
* i" X" D6 h2 C/ z3 R% x end8 X1 Q8 i- d/ ^3 j' x V' N5 i5 c
if pdd
4 H! u5 v" v6 O break;
7 n O" M5 j" C+ a/ M F end
5 u" H j! i+ j% X. }* F/ t end& c2 a7 p! N% w
if pdd * I# M7 E! {, P1 y+ k
k = 1;+ m( ^0 @% `; c
j = yy(j);
0 B* f1 w1 T2 N' ^" ?5 a while(1)
3 l( k3 j" C3 X* e( v+ o P(k,2) = j;1 q: k) b% M! c( r5 A* h6 d
P(k,1) = y(j);! @- `7 i! F0 U+ \) r3 Y- S
j = abs(x(y(j)));
- R1 `2 g& c+ v. |# M if j == n+1" P+ ]+ w1 L# v G: [0 Z/ k
break;
: E4 I( n9 ^- j' z# _ end. b) R3 X: N( c& D( `( W1 M
k = k+1;
$ B# [! f7 X7 q$ K end
1 r3 C9 {+ _6 W/ } for i = 1:k# r! l0 n* C2 m. u* F
if M(P(i,1),P(i,2))3 p1 k2 L4 I& H. T' E
M(P(i,1),P(i,2)) = 0;
# i" b/ ]( o" s: n0 p- y else
2 P! u" `- ^$ \- f \2 X/ \ M(P(i,1),P(i,2)) = 1;# C( d* ^$ Y$ h
end
3 a3 O1 L& M) I) H end
0 C) ^* \7 W7 V6 f9 X1 q. y break;
, i8 `7 Y9 t7 a) x8 i end
" F3 q: h; Y n+ `1 U1 x end* G1 L" n6 ~- q3 M: u- P
end
, |$ B7 [* c0 g0 h7 s if pd
2 @1 c9 O/ [: A8 ?* H; ] break; M1 _2 h1 ~2 p6 k2 Y
end- q$ `2 O! @' _# j5 c
end4 [1 E: p* `- X2 y( K: ^6 L
1* z, \* u* Q1 n! P
21 T' u4 J' Q7 T v' M U- }
3
/ G$ r5 B( C- M7 @$ K4# L# n! T' j3 `
5. s8 B E/ E3 j" {: z
6
2 ]. I. g5 E2 v% m( Q: A' ]7' b1 u+ v" h. e$ X" _
8" Z1 x8 w" Q( k, Q( X7 S5 p
9 b! F8 j4 F/ _+ n7 b' i: r: O
10
0 P4 S4 x, E1 ~) }4 |11
' |- E: z: L' \0 Y12
5 |9 ?" ?/ s3 x# l13$ h8 J. r, o% p8 H2 B2 J! y
14% s( O/ q) Q2 f6 o
15
& a1 T( u' G& T0 M8 D16
" z/ x I4 C! p* K3 N7 C17
# d' [4 r; h7 L. P18
" M) y1 o# k3 i191 d1 ~5 n# {& z! _9 z$ P- z N
20% w! Y9 |* O/ l! F, Q4 Q" ]
21& f" h! I+ _5 W. I# ^
22
) c2 s* C6 l/ |23
$ M2 i% G3 L; e2 W: S, T24
0 j3 f" F& Y% _1 Y% j d; x% n25: J4 w% }& U+ ~0 \: t% g+ |: {; ]
26# [2 S, m0 \7 j1 b V, D4 A/ D
27
3 H6 C9 o0 B W' _+ _28% `3 F* t; E. A( v
29
5 i6 c: n' k5 J& }30
# M3 [' E1 @$ R( r. C( ]9 ]8 o31
& d ?( Y1 q( g& p _32
/ q* I9 d9 N F: ~4 v33; a/ ~4 a0 g& E y+ R- w3 Y
34; d" J% p$ W8 k: b- b" ]) |
35
/ E9 ^) X, u' p8 }+ T+ l$ ?8 \2 |2 O36 q; y% W5 w, L9 x' z6 w- l! V
37- b6 g% Z& B' Y/ P4 `) S
382 g2 ?/ v J0 w- S: A, `
39
9 E% Z- x1 A8 E. D3 K405 V* a7 v) H) O& A
41
/ f' I, B7 p; f( G8 B4 h" j42, {. i* A4 }% p
438 P" x$ T) e/ X) |
442 o* w: ]. w6 d* D/ W; L
45
2 o/ v# n! u l- x1 I* P46
9 q6 I$ E6 p' B/ j! N47) A1 B( \" B/ r( ^/ B
48
- a& s1 l% p( \0 V495 s! V/ K* i& `0 m6 s
50
% W9 s _) X+ X5 }51/ o4 g, K* u4 s* {* W8 m+ M2 ~
52# ?- e& a: i% \
53
% N4 ?0 b. S! D! n5 D. e+ o54 I& F" W' O8 U3 _# X. b# w
550 e a0 y- q3 J+ V
56
; x# W9 [. l7 b6 n% D5 n. X57
3 I6 \2 n* p# S# d% I% j/ M$ ^( n589 l% X% B' W1 e" U* p1 i4 x
59
+ L2 z* m2 Z1 K60( N0 ]: s+ ]3 \; I T
618 Z4 r6 d% ~6 ]: z2 J I( Y: v, B
62
5 b- [5 p) \- Y5 I( A+ }! d# r63! F( `7 r0 n; ^4 F2 }3 |- @
64
+ [( v q o8 m, C( h65) d& a3 a+ O5 a2 I, j- Q2 s
66" ~/ w% h$ z# A5 |3 W. C, ^
67
( g( `0 ?0 \' y4 g( {# I3 r: n+ Q6 x68
( a$ i! Q1 {4 Q8 T# k692 ] v- A4 a. D; |% E+ E
70' A" x1 q6 ?" U# l: u! m5 V
71
! k! J7 h, C- F1 K72
2 Q1 c# [* v& g. h+ i739 V+ s9 @4 E2 R [( \1 i
744 X* r0 M) `& t2 u
758 f% ]1 F/ g3 W% S b- d) K
76; o s; W, M9 E# }- v
77: v% P9 R( Y3 f5 F
787 d# a, e( S5 d! \
79
, }7 l. `) V' {( O j% [+ Y80
1 o' p) Y/ k Z7 `, J1 [, V" y81
. Q( m% k9 I1 v5 Z- @" i82
_4 }2 t1 t; ^' p) Q! |. D( ~/ B; Y83* b7 j& s; f3 |. x; S' N
84; f/ A' [0 q7 D/ } n) J7 s% O
85
& o! @' w- Z8 P: h; i. |: @, p869 q0 z: m2 G) s4 d7 o0 P7 K6 \ k* i
87- L2 \0 y- k7 T0 p
88
) u( W5 Q$ O) |3 d" s89
) `/ u E& E- U: z& p5 Y9 {90, ]& T R& F. L7 V% a
91
7 c% j7 x# k4 i# H92
, h; [( |6 a1 B2 _$ Z, v d' ~0 Y* h( J93
x" i2 M+ }2 H* T3 S94
1 I) c6 P, T& W; [, _% I95
L' W ?. @; X) o96
! z1 l _) G& K( r1 h; I97
, Z$ t9 P5 F5 F5 i5 _, `98, A7 @0 q% c$ b! L% B/ {/ C
99
! D7 a7 X. O) k6 e6 Z2 v0 ^100
8 u7 o$ C9 Y0 E& D3 J101! |4 i( V: Q2 j/ Q$ L
102
5 E7 q9 e7 {% U/ I6 M+ x' u% @103. d9 X, j4 i/ g- o
最佳匹配# n- s# G$ P; [7 U; R, x4 N
7 ~+ t( h# v7 o5 T8 N0 b; i
代码实现:
! p+ Q# O8 j1 [7 v% n- u5 F
+ W( N, C( P1 [0 ]& Bn = 4;
/ H8 o3 {4 l; q, n! R0 W8 iA = [4 5 5 1;2 2 4 6;4 2 3 3;5 0 2 1];
, F* W5 t D( T7 @4 @# D- x% LM(n,n) = 0;2 l1 H6 y2 e# `; x5 l, U& s ]
for i = 1:n* D5 T- g/ z0 v, v
L(i,1) = 0;: ?8 b! x5 \( \' ~3 J/ [
L(i,2) = 0;' L* U( d9 ^/ P% k: B
end$ L/ F& M- W' N# H. Z) @
%初始化可行点标记L
j) b' c p7 E- j4 c' w0 ]for i = 1:n2 \# M" h, d9 y) h2 m" E+ ^. m9 B' k
for j = 1:n
# ^. n5 a% N; g1 w& d if L(i,1) < A(i,j); o# d) }; J$ ~4 ~+ M
L(i,1) = A(i,j);
5 ]2 F4 y. Y9 S# y; h: t6 ] end" ]/ E/ d! y8 N) e$ T
end
4 l9 q8 O- K2 c. H5 |end& h# G' k% K1 Z: Y# I
%生成子图Gl) x5 T8 z! y+ ]
for i = 1:n6 C" H$ m9 d: a- O& S
for j = 1:n+ x7 Z8 U1 v0 g4 r
if L(i,1) + L(j,2) == A(i,j)
$ r! x4 [; ^% o0 r Gl(i,j) = 1; g; G' ]* R& ]! e- z( q% U7 F: ?9 t
else% F2 t& H4 D3 @
Gl(i,j) = 0;
6 B& `+ `/ u1 r' d/ Z4 v Z4 C/ D+ [9 l end- n! u. B# q. X$ R% _( ^
end7 ~! D# T5 D1 E y' q
end2 t; `5 g6 E& R, i
%获得仅含Gl的一条边的初始匹配M
/ h. I% a* s: ]% P, R% o7 U/ t9 jii = 0;! N( b, F O4 n8 j) V
jj = 0;& Q! t- P3 f4 l- K1 |
for i = 1:n% K6 F, X2 ]9 E* b5 B0 t2 `, ?
for j = 1:n% @; B9 I( ?3 C
if Gl(i,j)
8 ~& M/ l# O( o! t+ h ii = i;( U) G% c$ O1 p, _
jj = j;( W2 Q: E% ^( X7 ^+ R# k {
break;
9 j) O5 |! E w& ~4 i( J+ H/ c end" S5 |1 v2 Q8 h
end0 J# T, H1 w0 A Z8 x" b1 [* H8 e
if(ii)$ |( s, {8 b7 S' v+ `! f
break;* R. W4 n" F% F9 i0 P; P, y: M- r
end
- U5 x- E, u6 p6 S5 yend
, V- P B" O7 [0 q% m! V, mM(ii,jj) = 1;
2 h& y" K7 U- K3 qfor i = 1:n
. d/ m$ S* ~. M$ W* ? S(i) = 0;) A5 p5 b- h9 Q
T(i) = 0;1 Z% x7 C" a- n. \& m) g
NIS(i) = 0;! j6 K' a$ J6 Z, i" s! u% o
end
* O& f2 G% ?5 j& w. x4 i. b
" F/ I, `/ Y3 k9 T9 b4 Y, @3 a! e! ~' z& Q
while (1)1 n" a7 I9 a% T2 e) |+ q
for i = 1:n+ `* z& f0 @2 N9 }- l; J
k = 1;+ {; A# _) i6 w
for j = 1:n
8 F0 s2 U: l+ S8 ]$ G( q7 i if M(i,j)& |2 f& |2 @$ a9 ~: P5 ]6 o
k = 0;
5 G: d7 e. T( }' c! Q8 S8 E break;
. P' ^1 \" f& Z D% ]/ E* [ end
4 b* c7 q# \6 D( a" I end- D4 T- E+ ^9 I- C* T2 S$ W
if k
9 X( b: `$ |2 `; ~- w break;$ c6 ~) B8 H& F K7 z
end; |, a# G" x1 ~5 z
end
?% q0 a4 \4 m4 P( U& x$ i% h1 x%获得最佳匹配M,算法终止
/ p# ?( N4 z4 s1 m) X2 H: L1 r if k == 07 p2 y) g: L- [& x: t) E8 n% e6 z
break;
2 [) v1 B* A" L/ { end
+ O+ ~6 i% O1 _3 h5 n
' C$ L/ G+ s3 N* ~& n
8 q: E% k- d5 s Q# G/ ~%S = {xi}) U4 W0 M2 j0 K! C. z( D
S(1) = i;
& _, w) v+ U& ~5 W4 [2 e7 vjss = 1;$ P8 }+ j6 ~- d; J" p/ U
jst = 0;+ @8 v+ `( `) n; @
while(1); P* M9 f% M Z( Q, y* c
jsn = 0;
* |4 Y1 F9 j/ \3 y0 `9 ^ %选择NL的值 z) l1 G0 W5 `& j/ p
for i = 1:jss
4 x0 e2 a. F' N for j = 1:n' R5 U& H) s( C& p( H
if Gl(S(i),j)' ?8 z( P \+ a; [
jsn = jsn + 1;
% z' U8 j/ T: K% S+ e8 x$ J- b0 o NIS(jsn) = j;4 f3 i0 p' o- x
for k = 1:jsn-10 z! P1 a8 j$ ~4 T5 M$ u" v8 |
if NIS(k) == j
6 U# [! A2 l& Y jsn = jsn - 1;6 }# ^* P) {( u4 N
end
, M H$ @ T& C end* @$ o* I/ H4 n+ G( i5 Q2 ?
end; I" H" T0 [ V1 ~- [$ G( f+ S% D
end7 b4 W4 f" b2 [5 o0 s# J( x
end! S5 W! i% L5 l# a
%判断NL(S) = T ?% Z6 m% T; z$ M. _4 m9 S7 M0 E
if jsn == jst
2 c+ ^5 q, t) N' V9 Q+ L3 @& f pd = 1;
* @1 e: r( c7 f1 c for j = 1:jsn+ ~, y9 E) D6 k/ k. x9 y! v
if NIS(j) ~= T(j)
% R0 A" M) d4 o pd = 0;
- M6 y1 a. m. n* L2 G3 } break;
5 N7 A- E6 S4 Y) T end
2 }% B; g4 S' j end( M& ?8 T+ }3 u8 N* A; K0 i
end/ t0 R1 A' u& v; o) N9 h
%如果NL(S) = T 计算al的值& z4 M8 h" h( {' J' Y0 R W
if (jsn == jst) && pd ; i2 x; b; s8 v/ I- m& k; P
al = Inf;
, ~6 z% ^+ g, J4 ^, z' c for i = 1:jss
- O ?0 F$ s7 ~/ L0 G for j = 1:n* i4 l1 h( w, q8 J* J6 H4 E" F
pd = 1;* a* e0 _6 e" W- u& o
for k = 1:jst) }( z. u% t# {# w/ D5 n* G8 L
if T(k) == j
9 }) @. }8 I B- q, h S5 j I% y3 Q pd = 0;7 i3 M, X* B. b! w: Q
break;+ e3 {+ b" b P0 G: Y2 {
end* {+ S2 ~ { _) u
end
9 F5 ^* s1 k/ C+ {7 H* Q2 I if pd && (al > L(S(i),1) + L(j,2) - A(S(i),j))9 E7 f. o* [2 o: }! }
al = L(S(i),1) + L(j,2) - A(S(i),j);& @9 w6 S2 E+ M/ W# F
end5 }! i9 \2 c% T
end$ O5 |& m( \1 o* f/ ]9 C$ T
end
5 F! z( D: N; f+ Q! c7 Z$ [& h* e. R %调整可行点标记4 X) s7 A. W% u, @! _: X
for i = 1:jss4 b; I* f7 ?" T- J! n1 l
L(S(i),1) = L(S(i),1) - al;
: \* A" ~* l7 m& A, x/ c7 ~ end; ^( s9 N9 v) b7 V( X! T* k: g
%调整可行点标记
/ q: G" B1 w1 D) ]0 | for j = 1:jst
, u* \; O$ l( t4 y& p L(T(j),2) = L(T(j),2) + al;, _: H& G. @! D; U, {2 A& y
end
& x; p4 I& l9 y2 T1 S %生成子图Gl
+ }, k1 k% ]' Q; o/ e for i = 1:n
1 @' Y7 m$ ^" g) j0 B! E6 W k for j = 1:n
; B( ]; } U* v( ~/ h, u9 g if L(i,1) + L(j,2) == A(i,j)9 H* r; {9 L- J- v, O3 b- ]3 Z+ m
Gl(i,j) = 1;
& t+ \+ Y1 v O, P% ~" t else
) `* C1 S$ C9 C+ L Gl(i,j) = 0;
! i3 B( d6 s- L, n, h: F end# t* _, \ V% h/ z) s* \1 p' j
M(i,j) = 0;
. o5 k" N, |+ v% m k = 0;
9 Q- U$ t9 }2 j end6 K' [# ~ s9 K0 v4 _
end
/ }9 ]# E) n/ I %获得仅含Gl的一条边的初始匹配M1 Z8 D8 u1 d( b9 e/ M) g8 \
ii = 0;
6 y& P) n F) ] jj = 0;
5 i9 k9 }" F3 q, C" I for i = 1:n
0 S0 P9 e) W( u' A9 y for j = 1:n
3 I$ P+ f% L6 A/ x0 Q" Z9 C if Gl(i,j)5 V" m4 A4 `; `3 ]$ H; A& w F
ii = i;) M, d3 e- t# b, s2 f
jj = j;3 c8 k) l ~! Q. g
break;
4 m+ @% p+ Y# e% p1 C end+ m) u0 q5 G5 a
end4 R# ]+ c' O! b4 Q1 g
if(ii)4 [% ]' s5 t, N+ f7 P
break;
8 D# p: |4 ]( J. j7 J end
1 k) L! Q% g" ~ end
: V( w4 ?+ t% K3 E' j: k M(ii,jj) = 1;: g' ^3 K4 L$ h$ s: q. e
break;' A6 }6 _' Z8 n$ S
else
3 H# T: ~+ F' }# e, j for j = 1:jsn+ _4 Z: h: e* Z2 T# O
pd = 1;- X5 e* Z* E, Y
for k = 1:jst
?' f. N3 ]; M if T(k) == NIS(j)
$ E/ T* v6 A/ Z! I2 H& E) G) R pd =0
" @# l5 o- I1 e0 @. j* B8 d break;. ~' ^4 z/ w6 C7 J& K
end3 _3 o, d1 X% [. ^, e+ o
end' M, ?: E( _- m
if pd- g4 N5 o, w/ I; r8 C6 a
jj = j;! R) ?, u& h. Z# o/ n
break;
& b! {3 W3 E: Y% o end
5 ~ ?1 h3 \' e! t* m end- K/ Z0 d. {& H J/ ^( d9 n
%判断y是否是M的饱和点0 @) P0 V( ^5 Z' X" L
pd = 0;" u" l* j1 m6 ^ }2 k7 f: b8 |
for i = 1:n
# N2 Q9 U6 N& [, v3 h if M(i,NIS(jj))
6 _+ f9 u' u5 x/ g/ T2 e$ C pd = 1;6 D* W2 S! `; Y+ ^
ii = i;) C; e# v) n: C# n" P8 T3 n' o3 O
break;
1 A4 Y. ^+ _; e end6 R, m j# w% \* h
end
! U# H: p2 t3 H9 K8 b$ h; `2 q' u0 | if pd) I+ @6 x" x7 Y+ d
jss = jss + 1;1 e9 p' ]' W. E! o3 \
S(jss) = ii;
+ k1 Q+ D1 Z7 y( Q jst = jst + 1;/ S* ~$ y+ V9 D. b. |! @
T(jst) = NIS(jj);) u' E6 L8 w; K0 X/ K* L
else
' U. c- b l3 E R. B9 H! c8 J8 c for k = 1:jst
/ ]7 l. S+ {3 Y/ ?: o% C9 W) u( A M(S(k),T(k)) = 1;
! c& k9 v. ~% z# J0 r. g u9 l M(S(k+1),T(k)) = 0;
" N- M. d. e; O9 ] end
t) A" Q9 Z2 q5 f0 ~ if jst == 0- }. A% P0 h* P
k = 0;3 a$ Z' F0 H. Z; [- f) J; Z
end
9 z! y+ ~6 B# B5 u% Y# u M(S(k+1),NIS(jj)) = 1;
+ e' R: I/ E$ X& N4 _ break;
1 z) }9 c" W* V end
) z+ J1 R6 i+ Q3 u! [! i end' `" w2 V8 [9 b
end8 A! E3 i) z" U4 S: Z3 m& [4 I# q8 M
end
s1 v& g$ B) {! z MaxZjpp = 0;
" Q9 o2 W# a0 N; S3 V& O! D for i = 1:n" t/ m' G% v: k
for j = 1:n
6 L; ]7 E8 y( w- J3 {9 g if M(i,j)
; Z, @; J$ |, i* k MaxZjpp = MaxZjpp + A(i,j);
$ Q: P5 ^/ N1 p" B end
: `5 P# k8 h' ? end
, A1 E3 Y8 R _; k. P6 S end0 R$ a- S Y/ T( B$ B% _
M% @8 [( t( K/ j) s
MaxZjpp
1 L! k3 @/ E. ^9 W% r: V @3 B* g( J3 u- t( ] Y( j
6 L8 N5 V. T. X* S3 L! Q0 |
; b, G% Z. v; B* ~3 _) g1 s2 Y
|
zan
|