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s=dsolve('m*D2s-m*g+rho*g*V+k*Ds','s(0)=0,Ds(0)=0');# J, x( a# P, r# Z2 y% R
s=subs(s,{m,V,rho,g,k},{239.46,0.2058,1035.71,9.8,0.6});6 y* v, g& n, H
s=vpa(s,10) %求位移函数 - Z5 _7 w: m; P! [& P8 Ev=dsolve('m*Dv-m*g+rho*g*V+k*v','v(0)=0');$ ]$ b( u# h. o8 i# B3 `2 o
v=subs(v,{m,V,rho,g,k},{239.46,0.2058,1035.71,9.8,0.6});6 Z3 d9 A8 A: N* u5 e+ s
v=vpa(v,7) %求速度函数 , i `' V, O8 c9 N9 A+ Cy=s-90; 3 x* m: r$ Q. R1 t$ C9 Dtt=solve(y) %求到达海底 90 米处的时间 - O& y6 I5 J8 W& u+ T$ x7 G8 Lvv=subs(v,tt) %求到底海底 90 米处的速度& o1 g$ c' H3 a& d/ ?2 R; g : P2 ?2 C" x6 L/ j0 {& X
2 d6 @1 n3 h% k. `; K8 W原文链接:https://blog.csdn.net/qq_25862209/article/details/100029925# O" v" ^9 r' E' F- F3 S5 U* t
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