求解方程组中的问题

weiyuanzhang

1. e11 == [d1][
   # D- I1 Q* y7 M9 o
2. d2], e21 == -2[d1][d2], e31 == -3 g[d1], e41 = -3 g[d2], e51 ==
   3 s5 F+ U2 o% ?
3. 3*g^2 + [d1]^2 + [d2]^2 - 3*h^2,
   / e: o7 J' E* D  W4 T
4. e12 == [d2][9 ], m7 b* J5 Y, F* B* h+ m) U, b
   
5. d3], e22 == -2[d2][d3], e32 == -3 g[d2], e42 = -3 g[d3], e52 ==
   0 ^# C7 {8 l4 o( O0 o; ~\" R
6. 3*g^2 + [d2]^2 + [d3]^2 - 3*h^2,
   ! Z! o/ f5 Z3 ]  o) n3 G* D6 `
7. e13 == [d1][8 A' C1 {1 n  C
   
8. d3], e23 == -2[d1][d3], e33 == -3 g[d3], e43 = -3 g[d1], e53 == ; @9 m& x  F% D5 M5 h: O/ c
   
9. 3*g^2 + [d3]^2 + [d1]^2 - 3*h^2,( _# F$ _/ k1 ?& s+ \1 e; ]5 f
   
10. c11 == e11 - e31 - e41 + e51, c21 == -e11 - e31 + e41 +
    ) Y: Q3 f, L; t8 y$ d
11. e51, c31 == -e11 + e31 - e41 + e51, c41 == 4*e21, c51 ==
    # f9 w9 W' w8 e4 C5 Z3 A# a% C0 C
12. e11 + e31 + e41 + e51,: |/ N! H* ^1 u+ i  y. M
    
13. c12 == e12 - e32 - e42 + e52, c22 == -e12 - e32 + e42 +
    - X: H( ]& T2 u# q+ g
14. e52, c32 == -e12 + e32 - e42 + e52, c42 == 4*e22, c52 == ; H+ T5 g7 s\" ?/ e, g9 U1 s7 @1 u
    
15. e12 + e32 + e42 + e52,
    , N* l  q$ [' Y% L
16. c13 == e13 - e33 - e43 + e53, c23 == -e13 - e33 + e43 + 6 D+ `3 p8 e2 }2 p. C4 O; R
    
17. e53, c33 == -e13 + e33 - e43 + e53, c43 == 4*e23, c53 == ( E5 J3 d# ?2 \: h- w! J) L/ S
    
18. e13 + e33 + e43 + e53,
      P2 O3 D. }0 u
19. Solve[{c11*[t1]^2*[t2]^2 + c21*[t1]^2 + c31*[t2]^2 + c41*[t1][t2] +
    % i) P/ v8 s+ n2 D2 E6 ]
20. c51 == 0,
    . A  l. A& m  q9 h6 q) g
21. c12*[t2]^2*[t3]^2 + c22*[t2]^2 + c32*[t3]^2 + c42*[t2][t3] + c52 ==
    $ D6 k4 ?8 s2 X
22. 0, c13*[t1]^2*[t3]^2 + c23*[t3]^2 + c33*[t1]^2 + c43*[t1][t3] +
    1 \- B2 P* X( l- e
23. c53 == 0}, {[t1], [t2], [t3]}]

复制代码

请问，我的程序见代码，要求t1，t2和t3，但是运行不出来，请高手指教问题在哪里，谢谢
7 ?' o3 R3 q/ J0 F; z9 ]7 J

linmatsas

表示不懂………………

weiyuanzhang

回复 linmatsas 的帖子
# K' Q; ~  n* z9 Q' j/ T
( }2 t8 e1 ?  `. ^& o3 l就Solve里面的方程组啊，前面的是给系数赋值
   

linmatsas

回复 weiyuanzhang 的帖子
8 x2 R) x8 R. G9 Y# t0 b
: C# y7 q9 i1 c5 e' X
( Z/ ^& D" J: c3 b% _4 Q# I    什么错误信息呀…………

hjftc001

方括号好像用的不对。