求解方程组中的问题

weiyuanzhang

1. e11 == [d1][8 ?4 r' b7 S. f2 |! i! g, E9 [
   
2. d2], e21 == -2[d1][d2], e31 == -3 g[d1], e41 = -3 g[d2], e51 ==
   % d8 q\" i7 r( P8 I. k
3. 3*g^2 + [d1]^2 + [d2]^2 - 3*h^2,# W1 n- g0 C' z( Y# C
   
4. e12 == [d2][2 m& B7 l, M2 }+ p
   
5. d3], e22 == -2[d2][d3], e32 == -3 g[d2], e42 = -3 g[d3], e52 ==
   # w\" x& n  ]' @9 i, U
6. 3*g^2 + [d2]^2 + [d3]^2 - 3*h^2,
   ( |3 M, q( [5 O0 \8 u# d
7. e13 == [d1][
   & H) X( T8 W& a# K) Y8 J
8. d3], e23 == -2[d1][d3], e33 == -3 g[d3], e43 = -3 g[d1], e53 == 6 u2 \: s; ]5 |
   
9. 3*g^2 + [d3]^2 + [d1]^2 - 3*h^2,
   ( Y/ K1 P) L; T) e
10. c11 == e11 - e31 - e41 + e51, c21 == -e11 - e31 + e41 +
    ) t\" |; C2 n5 n, Y) M
11. e51, c31 == -e11 + e31 - e41 + e51, c41 == 4*e21, c51 ==
    & ?/ k, B2 T, _- W: ~
12. e11 + e31 + e41 + e51,8 U7 ~! O3 p* F\" n5 ~
    
13. c12 == e12 - e32 - e42 + e52, c22 == -e12 - e32 + e42 +
    - G, V) A& a7 r; P! O1 W% o7 p
14. e52, c32 == -e12 + e32 - e42 + e52, c42 == 4*e22, c52 == \" l1 j' Y9 s; P7 v/ d/ e1 `1 _
    
15. e12 + e32 + e42 + e52,
    7 K% s\" i4 Q+ g: U6 C
16. c13 == e13 - e33 - e43 + e53, c23 == -e13 - e33 + e43 +
    1 }- g5 l( N: d\" C
17. e53, c33 == -e13 + e33 - e43 + e53, c43 == 4*e23, c53 == % d% E5 m0 \0 E# o1 s. O
    
18. e13 + e33 + e43 + e53,
    $ y* O* P1 d5 C( [) v) F9 ~& \
19. Solve[{c11*[t1]^2*[t2]^2 + c21*[t1]^2 + c31*[t2]^2 + c41*[t1][t2] +
    , S4 O5 P# |/ K/ @7 k$ z
20. c51 == 0, ; x5 x) F& {$ i+ k. T
    
21. c12*[t2]^2*[t3]^2 + c22*[t2]^2 + c32*[t3]^2 + c42*[t2][t3] + c52 == 1 J( |+ x& B0 q+ m) k
    
22. 0, c13*[t1]^2*[t3]^2 + c23*[t3]^2 + c33*[t1]^2 + c43*[t1][t3] + ( i5 L7 B0 c% ^2 \) U, P- @1 Y& p
    
23. c53 == 0}, {[t1], [t2], [t3]}]

复制代码

+ M- [* o: y6 J5 U9 o% w, d请问，我的程序见代码，要求t1，t2和t3，但是运行不出来，请高手指教问题在哪里，谢谢
# ]/ J. F" F( ?  M7 t2 U; |

linmatsas

表示不懂………………

weiyuanzhang

回复 linmatsas 的帖子

( j; T; G. Y7 a! x- x3 h就Solve里面的方程组啊，前面的是给系数赋值
$ z; D4 r' ?% y6 C  v   

linmatsas

回复 weiyuanzhang 的帖子


" L$ w8 e6 ^2 b1 Q5 n3 A3 f  @/ g: P% \    什么错误信息呀…………

hjftc001

方括号好像用的不对。