求解方程组中的问题

weiyuanzhang

1. e11 == [d1][+ v* m8 C- ^, n/ D# }4 ^
   
2. d2], e21 == -2[d1][d2], e31 == -3 g[d1], e41 = -3 g[d2], e51 == $ ?1 }- T; @$ [. J4 o5 i
   
3. 3*g^2 + [d1]^2 + [d2]^2 - 3*h^2,( s. Z4 L6 z! \# ?5 ]
   
4. e12 == [d2][5 C( X3 @4 z' g, D
   
5. d3], e22 == -2[d2][d3], e32 == -3 g[d2], e42 = -3 g[d3], e52 == : e: _  `. L* l8 {
   
6. 3*g^2 + [d2]^2 + [d3]^2 - 3*h^2,+ C2 |! U/ `0 P  C9 _! b
   
7. e13 == [d1][& Q/ ]1 Y' `# p8 H; d
   
8. d3], e23 == -2[d1][d3], e33 == -3 g[d3], e43 = -3 g[d1], e53 == * Y( i$ z6 i  n, G& E' \; s
   
9. 3*g^2 + [d3]^2 + [d1]^2 - 3*h^2,
   + [% V: N6 i. I0 [0 o\" I
10. c11 == e11 - e31 - e41 + e51, c21 == -e11 - e31 + e41 + 5 b4 E  U3 V  [' u6 Y
    
11. e51, c31 == -e11 + e31 - e41 + e51, c41 == 4*e21, c51 == % i( z+ K. w/ B* W) m- \* |
    
12. e11 + e31 + e41 + e51,# v2 _' l, ^) V- K) C5 M& P8 K
    
13. c12 == e12 - e32 - e42 + e52, c22 == -e12 - e32 + e42 +
    + M1 X! Z8 J5 |5 D2 ~; N2 y
14. e52, c32 == -e12 + e32 - e42 + e52, c42 == 4*e22, c52 ==
    ( ~\" ^( I3 c1 ~$ r/ }* f% a* L
15. e12 + e32 + e42 + e52,
    : c7 h; \\" M7 K! o8 x1 h/ Q* D5 F
16. c13 == e13 - e33 - e43 + e53, c23 == -e13 - e33 + e43 + * H1 U8 R  }) N) N$ w$ Y; r
    
17. e53, c33 == -e13 + e33 - e43 + e53, c43 == 4*e23, c53 == 8 J; e; \( r3 k/ h' }* ^9 a% h
    
18. e13 + e33 + e43 + e53,
    # {# }( V0 M5 F5 O6 z- u! \) x3 g
19. Solve[{c11*[t1]^2*[t2]^2 + c21*[t1]^2 + c31*[t2]^2 + c41*[t1][t2] +
    6 R8 `( a4 `+ Z, M/ m
20. c51 == 0,
    8 y) `: I4 z) }6 H
21. c12*[t2]^2*[t3]^2 + c22*[t2]^2 + c32*[t3]^2 + c42*[t2][t3] + c52 == 4 e4 N- S7 \9 s& o3 z7 ^9 M. r
    
22. 0, c13*[t1]^2*[t3]^2 + c23*[t3]^2 + c33*[t1]^2 + c43*[t1][t3] +
    0 K( O  _: B- i/ i0 p. E\" m
23. c53 == 0}, {[t1], [t2], [t3]}]

复制代码

' n  w7 s$ u7 E/ z5 x# n请问，我的程序见代码，要求t1，t2和t3，但是运行不出来，请高手指教问题在哪里，谢谢
- Q0 ?! _7 d, H; d/ w

linmatsas

表示不懂………………

weiyuanzhang

回复 linmatsas 的帖子
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: [2 v5 C: \  \7 G3 R, i就Solve里面的方程组啊，前面的是给系数赋值
   

linmatsas

回复 weiyuanzhang 的帖子
2 w" a% y& J% w, x; {: J4 G: C

6 W4 s% o, `( n    什么错误信息呀…………

hjftc001

方括号好像用的不对。