求解方程组中的问题

weiyuanzhang

1. e11 == [d1][: Z+ d% ~% I\" W! e
   
2. d2], e21 == -2[d1][d2], e31 == -3 g[d1], e41 = -3 g[d2], e51 ==
   ; t  P# v( m) L5 o% _6 H0 S
3. 3*g^2 + [d1]^2 + [d2]^2 - 3*h^2,
   . c2 r0 Y9 a( ^/ P% p( \
4. e12 == [d2][
   0 ]\" k) Z0 ]) T1 y8 A7 I; m4 V
5. d3], e22 == -2[d2][d3], e32 == -3 g[d2], e42 = -3 g[d3], e52 == 9 R% v- b7 z8 Q) n7 l
   
6. 3*g^2 + [d2]^2 + [d3]^2 - 3*h^2,2 [\" y6 N3 x8 O! N  b, K% P
   
7. e13 == [d1][+ K& g; G8 H( Z3 L, `
   
8. d3], e23 == -2[d1][d3], e33 == -3 g[d3], e43 = -3 g[d1], e53 ==
   ) G- Z8 z6 x5 K, E! k$ b
9. 3*g^2 + [d3]^2 + [d1]^2 - 3*h^2,
   . ?# z3 k( N- [
10. c11 == e11 - e31 - e41 + e51, c21 == -e11 - e31 + e41 + + ^, ~  H9 ?- [2 n: S% n
    
11. e51, c31 == -e11 + e31 - e41 + e51, c41 == 4*e21, c51 ==
    , E% V5 P0 y+ w\" h7 Y5 G
12. e11 + e31 + e41 + e51,
    ' `5 s- X' M# l' u
13. c12 == e12 - e32 - e42 + e52, c22 == -e12 - e32 + e42 +
    1 S# h3 b; h/ h' l
14. e52, c32 == -e12 + e32 - e42 + e52, c42 == 4*e22, c52 ==
    - ^' `% }0 ^/ f+ Z$ b6 U' A8 \
15. e12 + e32 + e42 + e52,
    $ x  e: ?% B- X  H6 |1 U, t
16. c13 == e13 - e33 - e43 + e53, c23 == -e13 - e33 + e43 +   u4 p8 x3 U0 w$ e& c, O, q
    
17. e53, c33 == -e13 + e33 - e43 + e53, c43 == 4*e23, c53 == 9 u) `\" d* P( `: e6 j# s, k! E
    
18. e13 + e33 + e43 + e53,
    7 ~, v2 z! Y! Z6 W/ O7 [* g( t9 y
19. Solve[{c11*[t1]^2*[t2]^2 + c21*[t1]^2 + c31*[t2]^2 + c41*[t1][t2] + 2 }' ^7 J/ J8 C5 _, I5 B\" U# b
    
20. c51 == 0, / l# j1 `# t3 p: K2 ]  \
    
21. c12*[t2]^2*[t3]^2 + c22*[t2]^2 + c32*[t3]^2 + c42*[t2][t3] + c52 ==
    8 x, }2 R$ y6 A
22. 0, c13*[t1]^2*[t3]^2 + c23*[t3]^2 + c33*[t1]^2 + c43*[t1][t3] +
    / i4 l6 m  @\" \0 }  ]8 [: A1 Z
23. c53 == 0}, {[t1], [t2], [t3]}]

复制代码

5 p" X, }; t; \* W+ W请问，我的程序见代码，要求t1，t2和t3，但是运行不出来，请高手指教问题在哪里，谢谢

linmatsas

表示不懂………………

weiyuanzhang

回复 linmatsas 的帖子
9 W3 X& o/ C/ o9 M% {+ }
# N( a/ |. n. R$ D5 z就Solve里面的方程组啊，前面的是给系数赋值
- I# t- t  P* G# C   

linmatsas

回复 weiyuanzhang 的帖子


. E8 I/ p# }/ {$ ^5 k    什么错误信息呀…………

hjftc001

方括号好像用的不对。