谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
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) D; x0 [! G9 X3 ITime Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

0 d4 A! f3 B8 l8 hDescription
! A% e, c: C  U; b+ y" LA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:
; x# y8 F- Y4 E* l( `, o# w' P: R
) K5 N+ T$ z" C' G' h) T3 ^Encoded: HPC PJVYMIY
: d1 q, n* p/ N) eDecoded: ACM CONTEST

In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.
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  l2 m% B/ r% S; bInput
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.

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3 ^9 L* U3 P, COutput
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
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Sample Input
% o! N( e+ z0 d+ K7 q, i! q2
/ q3 P" H* I& G3 h2 o; i+ tHPC PJVYMIY
1 k. M1 {& O! I; _' `0 k3 `BLMRGJIASOPZEFDCKWYHUNXQTV
6 p) c$ x0 T, [8 u5 p+ N5 x# o% l8 HFDY GAI BG UKMY
' A* ~: H5 R( {7 ~9 O2 I1 ZKIMHOTSQYRLCUZPAGWJNBVDXEF



) `7 _$ p3 p7 P# N& x0 e2 qSample Output
' A* I8 P7 n" N# K, k) L; i8 ]1 ACM CONTEST
: h4 N& N/ G* S6 b+ |2 THE SKY IS BLUE

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2 J* w% ~5 \4 [8 H2 H- q) w我的代码是：
) f" L  A" K+ }2 \# A#include<stdio.h>
. M, O9 f9 S7 h5 c( x#include<string.h>
int main()
{
     int N,i,j,k;
     char c;
     char code[1000];
! D9 B; \, i& Q     char map[27];
     char trans[1000];
2 m0 w# G2 _/ F     char wrong[3];
9 j0 h. D) i, U& Q2 }2 r! N     scanf("%d",&N);
# N& }# s. q! H, A- V& c     gets(wrong);
     int h=1;
3 T8 ~! j+ ^$ u* x5 ^2 l     while(N--)
     {
         gets(code);
         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
/ t* V$ T" F! E         {
             if(c==' ')trans[i]=' ';
6 r& _5 X- [  P& a6 a7 L. ]             else {j=code[i]-'A';
+ B& l4 d7 S- d: G7 D             trans[i]=map[j];}       }
         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
         printf("%c",trans[i]);
0 v4 Z4 q3 v0 v0 b         h++;
$ \! J( [. T* G" g7 ]8 e# S8 f         printf("\n");
9 O2 F3 O$ i) T7 y' R* X! q     }
8 i$ ]8 |7 X7 f, E2 C0 k     return 0;
}

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样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？
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huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。

_我还活着

没有看懂.....

linmatsas

C………………………………

葉_浅浅

.....................

zjqylcy

把答案也附上来吗。。。
是不是k是int型？