Cryptoquote ' C' Y$ P' y( z; m/ Z U3 n; w! [* e4 p: {- p* L# {" H2 f0 n7 Y
( o7 d: {' F' ]/ j! N. C1 VTime Limit: 1000 ms Memory Limit: 65536 kB0 v9 D b3 s# ~+ @) ^
Solved: 79 Tried: 281 # U8 L- W0 M6 ^% r* y- R+ T. `# H* U0 g" A: V
Description " J4 u, e# c3 R0 D; Q/ @6 e8 p/ i
A cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:' \8 K8 E9 {6 I! G/ X
' R3 C& p9 x5 ?/ D8 x" ^In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages. 8 o( b) v* Z2 W( V, I1 Y5 t. z' d
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Input % i% W; T1 b# F+ l2 aThe first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string. ( ?- w( P* t9 y 6 v7 v* j/ }; w5 { 6 F Y6 c# C0 Z4 h5 |# s! e% u4 i 5 l& i0 e! {% D8 O0 N4 wOutput 5 P+ }6 v D9 V; ]( ^+ c* @For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message. , c1 j- t K. }# h& q% [# l5 u5 N9 o9 L: T
! q- @1 O% d; D* T9 GSample Input % i+ C, I; h+ X$ \; C0 O
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HPC PJVYMIY " z9 i3 W- ?0 m, a3 c* K5 G xBLMRGJIASOPZEFDCKWYHUNXQTV ! s/ u, Q, [+ ^! H+ K4 k. }
FDY GAI BG UKMY " u3 B* G* X+ Z' m8 e- sKIMHOTSQYRLCUZPAGWJNBVDXEF 8 v% M+ w; O% Z2 o: ^* @8 _' f3 M0 @. |+ S8 j( S2 G! y% c
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Sample Output * [/ c5 T7 F1 n1 |9 C8 ]1 ACM CONTEST 5 T4 j$ U+ `4 t6 I8 @3 |# W
2 THE SKY IS BLUE ( _( y( E2 S9 v# }* K% m ! w# ?& ]5 ^( {! L. t" j. K& i4 p- O+ E2 U% h" L- m3 y
, |, q* o3 O1 |" ]$ O* ^9 d) |我的代码是: 6 e7 J }* ~; g* l$ Z! C#include<stdio.h> * p3 Q; @5 }2 ~! T& L l#include<string.h>* k9 O5 y; {! y3 J9 J$ L
int main() % K2 ^- Z4 P7 H! b3 g) Z{ ) h* d/ k5 o7 t" k9 r5 ] int N,i,j,k;% ]% A/ v+ p' v; o! q, S
char c; # j1 N4 ^: m2 v! A; y char code[1000]; / L$ \2 Z. v7 e7 V char map[27];7 m1 m& U7 X( Z: J0 e4 A+ B8 d6 ~# ]% ~
char trans[1000];9 V1 s& u: }9 G( o
char wrong[3];# v8 }- ]+ c- s; k; x! G
scanf("%d",&N); 0 U( V: G' E% {& ` gets(wrong); \. t/ o1 T6 C2 t int h=1;. S3 p* b# Q: D2 d7 v
while(N--)$ I" H! T, e: X b! u9 _
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gets(code);* T# n' Z' S( i: Z0 b
gets(map); % C& p7 i& g6 ?: I. s9 M7 g. \; Q for(i=0;((c=code[i])!='\0');i++)4 F* c3 X3 W8 t. @2 P
{% E" T& o9 p8 c# D. ? b: E' c
if(c==' ')trans[i]=' '; & D @% g- X& K# c8 |9 L. t else {j=code[i]-'A';& W& i j- K; A- ?; |3 w; J
trans[i]=map[j];} }7 B, e1 R4 k n) ~# d
printf("%d ",h); " l" a- C' Z0 _' v" }0 n, m5 z7 J for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++) 4 ]: r$ C% X H# x+ G3 V printf("%c",trans[i]); % k V9 w3 _7 k5 H. J4 W# J/ q h++;! `! Y1 P! r" k+ s! F- M" b
printf("\n"); * T& @$ E: c- C7 ^ } z# q- C: @. d return 0; ) ?' E0 _7 E; }" S8 j}' n1 o# I* D; M9 e5 _6 P# ]
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样例过了,但是提交答案的时候还是wrong answer。是哪里有陷阱? 3 }- }0 k- G. x3 A6 c, I