谁来帮忙看一下这个题错在哪里？

Winter_moon

Cryptoquote
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1 r2 F( A0 t8 |9 g1 }
Time Limit: 1000 ms Memory Limit: 65536 kB
Solved: 79 Tried: 281

Description
  x1 Y- t0 C* n1 Z* l9 X' PA cryptoquote is a ** encoded message where one letter is simply replaced by another throughout the message. For example:

Encoded: HPC PJVYMIY
Decoded: ACM CONTEST
  i( h8 ?, h& R; Q+ u* A
In the example above, H=A, P=C, C=M, J=O, V=N, Y=T, M=E and I=S. For this problem, you will decode messages.

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: g4 i  w  A, s$ H) e/ P4 mInput
The first line of input contains a single integer N,(1<=N<=1000) which is the number of data sets that follow. Each data set consists of two lines of input. The first line is the encoded message. The second line is a 26 character string of upper case letters giving the character mapping for each letter of the alphabet: the first character gives the mapping for A, the second for B and so on. Only upper case letters will be used. Spaces may appear in the encoded message, and should be preserved in the output string.

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Output
For each data set, you should generate one line of output with the following values: The data set number as a decimal integer (start counting at one), a space and the decoded message.
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! S( S% S9 K  g  aSample Input
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HPC PJVYMIY
BLMRGJIASOPZEFDCKWYHUNXQTV
) ^! e' Q5 w0 v9 |, sFDY GAI BG UKMY
KIMHOTSQYRLCUZPAGWJNBVDXEF
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) L- R3 N/ E  w2 U0 `Sample Output
2 b; o# T3 s- T% e7 Z1 ACM CONTEST
2 THE SKY IS BLUE
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我的代码是：
% _; Z/ Z+ @, l, n* M. `: P, Y#include<stdio.h>
#include<string.h>
& [* H- d6 D! \, Yint main()
5 C& n& R5 k* H* o& x{
     int N,i,j,k;
     char c;
     char code[1000];
' _7 B' Q; r7 b1 s. L     char map[27];
8 o' X' `! l7 l* E     char trans[1000];
0 J! ^) v5 _( m" J4 v: K     char wrong[3];
' t/ K$ X3 T. }* E     scanf("%d",&N);
' g+ B# m! u2 T3 M) m     gets(wrong);
6 Y; S; S  ?# X* a' }6 P7 H$ {     int h=1;
     while(N--)
6 y, l8 S1 y! p     {
         gets(code);
4 X0 h8 |! _& ?( J8 Y         gets(map);
         for(i=0;((c=code[i])!='\0');i++)
6 B( c* L3 O% T1 g2 g: w+ ~0 r         {
             if(c==' ')trans[i]=' ';
             else {j=code[i]-'A';
             trans[i]=map[j];}       }
         printf("%d ",h);
         for(i=0;((k=trans[i]<=90)&&(k=trans[i]>=65)||(k=trans[i]==' '));i++)
# W3 _( L! `& T. D         printf("%c",trans[i]);
         h++;
         printf("\n");
2 P2 h# b  B% o9 P9 b     }
& X8 C! M9 T, c7 S( |4 B     return 0;
}


- u8 q# a, F! P6 [  Z4 k; w样例过了，但是提交答案的时候还是wrong answer。是哪里有陷阱？

huangliao6252

int h=1;这个定义应该在 scanf("%d",&N);前面。

_我还活着

没有看懂.....

linmatsas

C………………………………

葉_浅浅

.....................

zjqylcy

把答案也附上来吗。。。
* W2 z9 y% D0 J5 X0 o是不是k是int型？