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TA的每日心情 | 开心 2021-8-11 17:59 |
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签到天数: 17 天 [LV.4]偶尔看看III 网络挑战赛参赛者 网络挑战赛参赛者 - 自我介绍
- 本人女,毕业于内蒙古科技大学,担任文职专业,毕业专业英语。
 群组: 2018美赛大象算法课程 群组: 2018美赛护航培训课程 群组: 2019年 数学中国站长建 群组: 2019年数据分析师课程 群组: 2018年大象老师国赛优 |
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最大流: ![]() 注意Matlab 中的最大流问题是必须是单源和单汇问题,因此这里需要构建虚拟的源点S和汇点G。
* e% d6 r2 J* g5 g* [! B- R) ^1 gclc,clear) j; N9 X8 ` n! G4 k, z
a = zeros(9,9);* O/ z; `- ?* b
a(1,[2:4]) = [20,20,100];; V, E1 E; \9 ^3 g$ t
a(2,[5 6 8]) = [30,10,40];! U# c) I/ v6 F4 K1 s9 a2 l
a(3,[7 8]) = [10,50];2 F4 L( ]1 v( ]/ a% o- u; }* L$ p
a(4,[5:8]) = [20,10,40,5];, k6 N) {2 L( z7 D. K b! K
a([5:8],9) = [20,20,60,20];+ I+ \$ n* A: t8 [$ s2 A
a = sparse(a);
6 z1 }& O5 L, h3 V[b,c] = graphmaxflow(a,1,9)
% n& i. L$ ^; [1 S7 W0 ]* y最大流拓展:最小费用最大流 仅仅是在求得最大流之后进行对最小费用的求解: a7 y- z; d1 D/ L$ P4 c9 j
clc,cleara = zeros(5);a(1,[2 3]) = [10 8;a(2,[4,5]) = [2 7;a(3,[2 4]) = [5 10;a(4,5) = 4;a = sparse(a);[b c] = graphmaxflow(a,1,5)+ Q4 r$ p K, X' p, l
最大流量为11 自定义Matlab代码:
# Q. o- r( K& S3 }) Z4 E$ }( [( X& X! \, F
最小费用求解
; I# q3 [7 y3 L3 S* ] s& ?) m. x& e+ m5 G" f7 n
Lingo:1 {5 j9 H7 a6 S; f
: J7 v1 A" |; b
model:
3 I/ j* M* u+ ysets:
2 A6 L/ M$ N5 U8 Q3 M0 B9 i X8 H9 C9 Knodes/s,1,2,3,t/:d;
3 @2 x6 {, E1 B' ^7 Larcs(nodes,nodes)/s 1,s 2,1 3,1 t,2 1,2 3,3 t/:b,c,f;
! s6 ]4 D+ q$ s5 g6 S+ Yendsets4 f( j* ]$ d& G
data:
& }$ V2 v9 m' P$ `b = 4 1 6 1 2 3 2;2 ^9 T9 H. u, B' E# b
c = 10 8 2 7 5 10 4;
- j9 C$ f+ g n. nd = 11 0 0 0 -11;" V+ X5 U+ Z3 w: g' l
enddata
! |/ t2 H4 I Vn = @size(nodes);
4 T6 i$ F- {4 _0 P3 xmin = @sum(arcs:b*f);
" K5 h: T/ N. v6 l/ K6 T5 S9 l@for(nodes(i) sum(arcs(i,j):f(i,j))-@sum(arcs(j,i):f(j,i)) = d(i));
+ q& K' ~! \, R- p* g* N: Z@for(arcs bnd(0,f,c));
7 H* r6 s& k, `! x4 t, |' z2 ~end/ G9 |* w: q s5 _* }) B7 D
1' F8 W7 Z# z. ]
2
3 _5 Y8 \- I; G( z( ]; n1 L3$ L: O& ~2 J1 y% {& f
4: b) Q6 j& V, O" t/ Y" j) k- h
5
2 z. p% ~' @7 v/ P' h6
6 U* x7 m& t( r7 h7
4 F: @8 c1 n; s: \8+ J, q% G& H' a. [8 q3 ~
9
c# u: D& T# k5 Y, o$ |10' m7 X7 S( h5 [4 q" T; p5 n
11
! j8 y3 y1 w( Y' X12
8 [0 C2 T. |% }; n13: V' U. V9 C5 |" _" a
14
5 W: q# |$ ?8 S6 j# A3 `& v15
: S/ N/ R6 h* Z' c l$ h RMatlab实现:9 B3 h) A6 c% u7 G* c( w$ a
' a" q* s: {8 _/ X' ?) {+ h: A% ^' y& p, B3 f8 k3 R
n = 5;2 @3 f9 P" [+ f/ ?5 U9 Y
%弧容量
8 o8 p2 f- R- n6 z9 f; _a = zeros(5);9 }! { y ?# E0 L9 E
a(1,[2 3]) = [10 8];# w/ g& ^+ t8 B2 k- k
a(2,[4,5]) = [2 7];! L4 z' ]$ t" [6 f; P5 @0 `
a(3,[2 4]) = [5 10];: `! H: _6 ?* o
a(4,5) = 4;& D; t+ d1 O3 Q' q: x7 Y7 I0 a5 w3 t) C
C = a;2 `6 t0 B o6 U! E. I1 Y7 N
%C = [0 15 16 0 0;0 0 0 13 14;0 11 0 17 0;0 0 0 0 8;0 0 0 0 0];( j7 O) s2 I" h5 j
%弧上单元的费用' G3 h+ D. s6 q9 ^- u- V9 I7 B
a(1,[2 3]) = [4 1];
2 r! F1 v4 A! k7 A/ Z3 ia(2,[4,5]) = [6 1];! r. u {9 J P
a(3,[2 4]) = [2 3];
9 c8 z3 S9 K2 `* da(4,5) = 2;
3 A7 P3 h# k0 }/ b" A0 Sb = a;. ]0 M( N# K8 r' F: |
%b = [0 4 1 0 0;0 0 0 6 1;0 2 0 3 0;0 0 0 0 2;0 0 0 0 0];" @8 ?4 n" T+ r& |( M
%wf表示最大流量。wf0表示预定的流量值, S& {0 `3 C! S5 k T$ k9 k
wf = 0;4 s/ \3 T/ N) E8 n2 b/ B
wf0 = Inf;
* [: K0 `% K4 y+ L! K$ M7 ]7 |%取初始可行流f为零流& z: h( i: v- x1 }8 j$ x
for i = 1:n
: A6 ^ C9 ]# _6 F; l for j = 1:n; G$ d3 O* m5 o" r R; i% z" z
f(i,j) = 0;( W+ K% E6 t0 e3 Q$ l
end2 T" [+ e# e/ r6 @; ~- \. N/ V
end
3 ~8 M- `& o* s- N _* K$ fwhile (1)
5 X2 g9 {) Z1 v; {: b9 P+ M %构造有向赋权图' z0 R# O. ^9 n- ^) p% v {" ]4 O
for i = 1:n
. {& l( u* a" O1 x for j = 1:n& i1 n* l# m* |* t) d
if j~=i: H+ V- [% g6 g0 `& c$ ?
a(i,j) = Inf;
) d8 H) k4 R4 ^4 [" j: K end3 E$ d; _! U. ]: x
end5 c6 ^& R6 p/ X) }- b. I8 f
end k- z9 Y# T+ N- L2 x# k7 V
for i = 1:n% k3 W3 r* o# u' C+ @
for j = 1:n! k1 s1 D- ]6 y5 z' U
if C(i,j) > 0 && f(i,j) == 0
* a+ F/ `9 r9 {$ e3 m8 A7 Y a(i,j) = b(i,j);" @+ e5 p. j3 s1 m
elseif C(i,j) > 0 && f(i,j) == C(i,j)% P5 a9 k/ ?) P5 w" h% J
a(j,i) = -b(i,j);
0 m/ O" W$ N v, x' g elseif C(i,j) > 0- d. J& h. b( X8 G, `/ O7 f& Z
a(i,j) = b(i,j);
) B8 d4 J. L3 k" O. Q: U) {# N a(j,i) = -b(i,j);5 T# a* F) m/ E7 W
end W/ |- i" L7 k+ ^8 e. ~) D
end
# L' Q5 W! y+ Z. C: U end
1 E* Q# e' `! e$ s %使用ford算法求最短路,赋初值/ M ]; d8 A" w- ~3 I/ Y. [; w
for i = 2:n* U+ _3 X: s+ G/ d3 o+ D% [+ e2 q$ N
p(i) = Inf;
' m. v3 y! P% _: h. l s(i) = i;1 V4 ?* B& O4 o' d3 R5 z
end ~' U" n8 }8 s: H' i9 T
%求有向赋权图vs到vt的最短路,赋初值
3 o* z) I' |- @& Y for k = 1:n! T+ i0 @, S3 H0 t. G" p$ E
pd = 1;/ D! q) p/ v+ y+ ^, k
for i = 2:n4 x/ Y5 A% w( X2 A" ^
for j = 1:n
& V" H( r) ]6 y0 m if p(i) > p(j) + a(j,i)
% c$ A, p- u0 m6 D p(i) = p(j) + a(j,i);4 T$ X: F6 n; a" _* n4 \, _6 n
s(i) = j;6 ?- l4 a- Y8 m5 T3 i
pd = 0;
% ?/ M) z: \/ G end) K& _( d- k R* z( U+ u Y Y; O
end+ R/ h+ W% @: n
end- X9 B' j! X9 c Q3 l
%求最短路的Ford算法结束! p: ?2 ~* b+ k7 g1 t h k2 @' @( L
if pd" ^6 \* L) u9 |& h9 x: Z. b* q
break;# o3 o6 V3 G/ ~$ K" `$ v/ y
end
" e1 b) e6 Y$ o4 n3 t" } end
$ W8 K5 d; c+ S! P %不存在vs到vt的最短路,算法终止,注意在求最小费用最大流时构造有向赋权图中不会含有负权回路,不会出现k = n
& _: K. S& k& ^7 R3 s- P0 { if p(n) == Inf
4 S1 M2 g; w3 T3 ^) V1 C break;
8 w2 C1 Y; Z- p3 r- _/ D8 N( r& v end7 z' p( s8 l9 _: c" [( D+ {
%进入调整过程,dvt表示调整量5 ]' }) h. h& e' i- i4 f6 V
dvt = Inf;
# y8 o8 Z8 i0 c; [8 H dvtt = Inf;1 F4 I& {- h7 c0 T: T" q
t = n;& ]% T$ r: ?: x3 s
while(1)
: i5 L# ^2 X. g$ I if a(s(t),t) > 07 N' D0 ?$ @5 X: T; Q
%前向弧调整量 m+ o% t, a9 @
dvtt = C(s(t),t)-f(s(t),t);
$ S1 n- Q' ? d( L! p% W6 a0 L %后向弧调整量
4 q) T7 e3 ~2 M/ i7 I7 t/ F elseif a(s(t),t) < 00 {( A+ v2 S6 E$ h" U
dvtt = f(t,s(t));- _; t- y! F- U/ z# \/ ~
end/ s0 B- i8 X1 b$ L/ l
if dvt > dvtt/ W# g% @4 E2 N) Y1 F
dvt = dvtt;9 } a( `; B9 C8 U) L# t
end
; I: T* k5 R% H! p' G* @/ ^; L% d %当t的标号为vs时,终止计算调整量
, D2 h% X& m5 T/ Y, V3 J7 z if s(t) == 1
+ ]' x9 r$ R5 i% P break; ^( f# e* |% ^
end5 E" P! J8 Z! D/ U I
%继续调整前一段弧上的流f3 T" `5 ^. w/ D: P* X8 } ^" T+ m
t = s(t);
: v. S, E. z; M- n end6 M: i( D7 }8 r1 ~# e" |* d
pd = 0;
: x' |0 |1 b* m$ k# a+ { %如果最大流量大于或等于预定的流量值7 ^- M e( }4 c# F' p# T
if wf + dvt >= wf0/ g8 E- [5 E5 R* n
dvt = wf0 - wf;, l$ `: \& t1 P7 `2 L. j
pd = 1;& p: E9 w/ o; p0 B5 b6 ~
end
3 {- w# e( T( {7 E3 ~ t = n;
, t. r8 o {* ~3 R5 D; q %调整过程
/ p) Z7 ^" a( F: B9 ` while(1)2 R' N! C# m9 _* `
if a(s(t),t) > 01 ]" ?' ?9 {+ o& D
%前向弧调整% A+ ^! d$ T0 x: A! v
f(s(t),t) = f(s(t),t) + dvt;
5 A2 c: ~2 H1 w5 P. O, R- U7 H {. ^ elseif a(s(t),t) < 0; W( W7 P- |8 z0 J9 O
%后向弧调整
) a3 I( ~- m! G4 w7 U7 C$ H$ E; y% G1 R f(t,s(t)) = f(t,s(t)) - dvt;+ V/ M0 r) |9 A1 f9 ^
end
$ ]+ \2 c3 J# v) s9 v %当t的标号为vs时,终止调整过程
. ~7 U+ z7 g: |) d, v if s(t) == 1* Y/ c4 ^0 o# v6 x) e8 b
break;% h6 L8 E' H) ?4 T; R
end
/ P, C2 c" z" N9 e- T t = s(t);
$ [, l j3 ~8 X8 z end
3 S [& }6 \4 f6 w$ q3 c9 d %如果最大流量达到预定的流量值
6 \2 U. {0 p; p$ ]% q* E if pd' H* [ V8 S- r6 d! M
break;
. j/ P g+ i z. X end
/ h3 K+ J( i0 \% O %计算最大流量
6 T+ C2 S0 M. b: l wf = 0;2 B) t" B K: D& w2 e- n# [6 |; \
for j = 1:n* c5 n3 i& g% B" K
wf = wf + f(1,j);
S8 T& N( s" E) m" r end* y7 X$ M* A- \: f
end
/ G5 h9 ?6 o3 U: u: {%计算最小费用' x: O3 ^. \9 _ T% A" [
zwf = 0;! b O( R7 g" V/ g0 X3 t
for i = 1:n7 v9 v- A' C& g8 e; o: S0 {
for j = 1:n
0 d# \ s# c/ M7 H2 ~, w* V zwf = zwf + b(i,j)*f(i,j);
- N7 @, q, t3 `8 _# O8 s" H end
0 K& ?% Q6 v( @6 G4 o3 jend0 ]4 A/ u5 z& X+ Z3 X$ Y% e9 X
%最小费用最大流
( @6 g) L/ k/ D" D: c$ g D$ e8 tf
4 W' }% m( b+ T8 ^$ q%最小费用最大流量, C( p# n! X6 V8 {
wf4 G) H7 K1 ~9 F6 o9 }8 [% e
%显示最小费用! ?- ?2 G4 y+ [, y, b9 m8 Z" n
zwf
3 ]3 e% I6 w6 B& D1
4 n5 \. |3 s; D2 ]" o* N+ |2
+ T2 ~7 t$ i. e4 V3& \3 J: K( p( y, n- G& I/ O( M) e
4
, d6 `4 _% }- }% [5% @8 z6 J& u3 }% T3 o5 k
6
6 K# Q( L4 L$ X0 V6 l/ W3 a( W7/ h! k; X! }7 j Q( {0 M6 x
8% E0 P C- l6 h$ h* W. j
9
& I7 t" t/ E2 X) ~' \% ^105 `: s% C0 m% |( ]7 |
119 Q; J( e: H1 G4 _0 \0 |
12. R5 D' ^. Q# l: F& B& N! X
13# Z2 @( e5 Q4 ]: [( a+ E+ p1 y4 n
14
8 [! ~; S B ?* c15
! l# R$ ^. e. e+ a7 d3 Q3 L169 N6 d2 b" Z* j9 @( V" A A E$ w
17+ N# N1 }9 H" b7 B
18
. ?" H' X" R+ t* X+ J" q8 E3 c19
5 X4 Z* d. J4 h2 e; S3 u* n20
7 b7 h, N9 M6 f% s21
0 a7 a p' J; B22$ o- \& z( k0 q6 l4 u% G" o6 S
23
/ \9 y) \$ W6 y' C; A- }24
* f+ k1 h# D0 L2 O8 o2 h& A25+ {' [8 Z: {6 p% x. h+ m
261 \+ I% ? M0 P" P) i3 @
27
, N0 H8 N% O/ E# a4 [. E z285 T5 j0 [# i" A
29
& X. n) `! d" H& O# Y% U30
% ^; j2 ]1 K* F% S" @* f31
/ ~. Z+ C" E# ?. l) n$ n325 [: g9 B6 m! r/ T7 x" s2 a: x
33
( k% |( O# x6 u. V9 C8 S0 ]34
; l# f4 k, x$ s, l& l; O b3 _35+ g+ F! o" I a1 j' _% q& m2 m
36( {' v( \4 c+ c0 g
37
: g3 w- e3 S- q; K# |38
. n+ _. y2 F+ w7 e7 b$ J6 a' N39
4 Z9 ~4 `6 b7 [' @2 F: `- e401 E2 [3 x" U! f; a4 }
411 d! b0 ?; O9 h$ s1 u ]
42% [4 v8 B, }! x8 ?8 Z4 _
43
6 U4 q: n8 V r1 p" I44
3 v! T! S( ^6 Y8 e5 ?1 i" D457 E! F1 X; R4 `% E8 t7 d. t
46% L0 Y' ]9 m( J- l" y
47 L7 `1 c$ k' c) C0 k& v- R
48
7 x# N; o5 y3 ]: s% r/ z4 c9 \5 a49
; u% |4 X) |) b" A: y' I% W50' i4 ^& e0 m, p1 z
51
4 F. ?7 x5 K! v( u% G52. T4 D- L5 i0 ]# X
53
5 n6 |/ }0 ^# f54
" @8 @: Y- l/ ~6 {% {55# x' ]/ n: \" ? [$ ]
564 g& n/ P, j% _) W) {
57! v/ M2 |' D$ R& N; T: Z0 A9 a
58" n0 ~# ^" D6 E2 i7 ]+ T
59( ?! \5 N N' v' o
60 l. b& y- ?; f4 x7 H, L4 N3 k; W
613 F. h* V7 H* u% m4 k- v' m5 O
625 _. `, v* _' E0 e) a+ `' ], o' l' H
63
2 B- ~# R, f" |2 h9 @+ E% u' n& ~64
. u3 O8 j" ~0 e- p/ A# b65
# I$ ?! x5 z, m0 E5 Y% {66
( H7 o# c, m8 J& t7 m% n6 _67
) I- C+ M/ ~( a8 O68
- ~( B8 X5 i3 p69" q6 i3 a# B3 i' S
70
/ y% z% F, G: u7 j1 u( S* D- a& d714 s& O7 d" v, Q& s
729 s8 g* y* q; G, E: G
730 T/ g m- S* W2 p
74
* I' D4 d t, [. a: {75/ S* U z2 I) i; A# R: ?0 x! h3 s
76
. h2 Z2 p( E+ B: N- o77
$ @' q) ~* p. }* G' B78
7 T* {7 B% f6 T& `- H79( i: v8 c7 B" P
803 g, D- c* }3 U9 G( |$ ]& |
81
* }/ j# Z# b- M( f5 U6 I4 H- s2 ?82
- D* ?5 ~& ^' L% o* v. m836 P1 d. ?& b/ K, ?6 E5 K
84
+ `! T, L1 _# b. G85
: X' C: {/ L" d0 [86
( M% ]' t1 K( c87
6 ?' n) Q! u9 O# E. Q: N- S88
6 _( C1 |4 C; z, l0 _89
; e4 f4 Y4 W' W: ^& |90
M! v1 X8 d" {! J912 O* \8 A2 A; n8 h2 x
92
8 z W% h4 [7 y/ m3 u93
; t k3 Z2 b+ ]4 l8 x) P) F" u1 x94
, N9 `: l& L! X; u9 T( d957 W# Q( @& s+ s0 S& V, B
96
2 G. `1 z0 H( c4 J3 u97% i. d4 G1 h6 F% e
98
/ ^ H! p4 F3 r- Y0 V99, b# O2 z2 m. N
1009 s T- V( h) ]/ j# d [7 }' N% g
101
4 U. }) M! n4 X$ ?: @; R: I" ?3 A. b1021 a" j- i- Q, U/ ?
103- m4 E$ a* t. R/ f2 i% s% y
104
L7 n% f3 z% \: J! K- i105
8 f: @2 [- y8 B1066 L8 I3 V) g/ |% I- s9 c6 Q! j8 J; o$ T
107
( ]6 Z, h9 {! e2 ?6 v108
: v3 ?/ M+ U/ S. P109
/ }" }3 S# o) P9 P) c! L1102 a m) t" p3 P! W! ^
111
; H* c! m" t" a" i8 u w112, N: @! O) V% r# j6 L, |& m0 Q4 t
113( g% V" [2 c% n3 W8 `" @0 S
114
: N1 g2 u, }. P' s9 e F8 V0 L115
+ o( O3 h" v) ^" S* z$ z116
+ z) z+ e. p g6 P1 i# F117
: O: x; O0 u5 |1189 F' k& s2 Z" r: y. E
1193 |& ~% Q) D+ A& n9 b, B2 d+ c/ ]
1206 l( N2 C( O: o1 Z2 p
121
& x: |2 K P# d, D7 [- C6 V122
% |4 R4 Y R3 D2 T- \! n+ D- ^1234 I- ^+ ~: V& T
124
# Z- v! }- R' \* l& H: j3 v$ {1259 H9 K+ ], Z$ T1 ~
126" J3 O& X1 B- w0 f
1270 P- D7 i; K" Y7 Q; p r! Y7 C0 _
1288 ^3 h6 x" j& d
129# I5 n R' d; W8 z f# Y9 ^# H
130
- n" \1 e# E, o7 N1 `' R8 A! A. e& z1316 L' L! m$ ^. ]8 V( H; }
132
2 K" q a6 S1 ^( W, q& H1 {! C$ f0 q133& @0 [3 N& ] `' n- [
134* ]7 }# m% K( ], Z
135
1 W$ n' k/ J5 W' n136
! X) g& m \ a, B1372 m: E: ` ?6 h8 q2 Q+ D
1383 p4 o' \6 t) [, ]; _ o" t
139
& C$ ]+ N0 m7 o; m% w4 e+ W( h+ B* I; X140; p$ f" ?: Y ]) t" W
匹配问题:
3 H" {* A% j% G7 H% d" g
3 G6 s& K" h* h" z: z最大匹配:2 q7 |- L! I v8 E: L. o
1 ~. c4 I) e+ \6 T4 X/ H, q N
5 v6 s& _9 d, M6 u2 _2 O' w代码实现:8 E7 L5 g' O o( e: m7 `
& v3 w* d" r2 R0 r7 t& e( U
m = 5;
" x& Y' ] \; F" }n = 5;/ Y# B, b- P! x5 ?9 O
A = [0 1 1 0 0;1 1 0 1 1;0 1 1 0 0;0 1 1 0 0;0 0 0 1 1];% C# t; M( c0 K2 g4 D! N
M(m,n) = 0;8 g2 P2 U- x; _" @% x0 w
for i = 1:m& s" s& f/ P; ^/ {2 L* D
for j = 1:n
. [6 M2 ]. @7 C. @0 T- |. k %求初始匹配M4 ~+ k; {) R s! W' Z
if A(i,j)
) r6 W6 `7 d* @5 e) S- o5 [/ D M(i,j) = 1;
& C( A9 ~0 W9 ~ U( h8 w break;! N2 _' | W; {6 S2 H2 G
end! k+ w% F" R$ q
end
3 ?# H5 v4 c* n( j. i- s& i7 R+ X %仅含一条边的初始匹配M2 u6 W( O# r7 {
if M(i,j)* i3 }7 N' p4 I' k' O ^5 A
break;
7 Q" U# `1 C' }& r; [' u7 @% D end: d! k" u% J1 ~8 M6 n
end
& s. ?* h @& X4 b4 ^6 o
5 m7 G: B$ V1 s$ o0 H0 M/ Zwhile (1)
) y- ? N5 m/ h* F5 g: q+ D %记录X中点的标号和标记
, q+ g, n9 H+ n$ \9 Y( J4 O+ [ for i = 1:m W' Z$ V1 e# J# l
x(i) = 0;
! {# h, ?# M: j) x/ ` end+ q0 C( D/ d/ X6 Q# _/ d
%记录Y中点的标号和标记
2 i$ P$ D% T/ t/ x0 q" z/ x for i = 1:n
+ q2 p+ s- z; B y(i) = 0;; g h4 D! f7 @5 S1 r
end
: Z* q- X C) A" `1 V* N %寻找X中M的所有非饱和点
% S' @& d3 S+ F' \+ i for i = 1:m
5 o7 K" n/ t( D pd = 1;4 |7 z5 J" @: m7 j, e
for j = 1:n7 s* O- |) L2 X
if M(i,j)3 t6 e8 `( G9 d- \' [/ A$ W
pd = 0;
5 H7 H7 \) J7 k& ]. P, w2 V* m/ B6 y end
' }8 o$ S. W( m! p. h end8 `- k# W& C7 l
if pd
; t" M1 s9 X1 f/ R' {0 Y x(i) = -n-1;
0 _/ n/ |6 |+ o( v/ Q end
( N: q* g) ^4 }( x6 q0 n end
! P: Y( X. b6 }4 ?! g$ `: r pd = 0;
9 }5 v1 |- _7 c9 e" Z% { while(1)7 c( E- z5 P" b2 u! V
xi = 0; I* l. W. y' \2 ^
for i = 1:m1 @! D1 I9 S, n
if x(i) < 0
) y% z G& P( @. l& C xi = i;
: g2 g/ h' E p5 }; y8 }. Q break;2 o( b& e* s. m+ d
end6 d* V, r0 V+ Y' H' W! y! Z
end
6 O4 v* h& m9 |9 n. Y7 o if(xi == 0)
8 ?5 j& k( \+ ?; Y pd = 1;- L" P# }/ t( h; ?3 w" w' s; \
break;- q# e: Z* u' F! t) ~ V, i
end' B0 @( p5 J0 b# R0 y7 E
x(xi) = x(xi)*(-1);
' n" F7 j2 p# g3 Y" ^" P k = 1;7 J8 _+ ^0 \5 u6 ^* ?. @
for j = 1:n
$ A O& n, v* x: q$ L$ f- d& D6 |: Y if A(xi,j)&&y(j)==0
% D5 a, b% e( g y(j) = xi;, W$ z6 a0 P! d
yy(k) = j;
- \5 ^- x" v7 E k = k + 1;& L: M8 C- y3 q: e8 B, h" z
end
9 F# h5 ^$ T: x1 F end& h) N+ O. Q! f/ ?
if k > 1
- Y+ }7 Y+ Q- f k = k - 1;: e X5 w. R; l7 W
for j = 1:k5 c, u* o. b/ |
pdd = 1;
. U7 T3 j/ e9 r1 D) E for i = 1:m
8 l; ?6 k. G S3 e5 x if M(i,yy(j))! X" e* \$ ?2 F+ o2 ^: U. w
x(i) = -yy(j);3 w4 D. W2 O" t
pdd = 0;
' f0 }* v* m. b4 H, | break;1 w4 N8 w" ?$ H# T4 C+ ?( H o
end# D, V; g' \6 m p* u( z9 H9 H
end
5 a) \ k( K3 r# _9 }6 D if pdd
4 p" x! r8 G! Y6 N9 O F# C- | break;
% v L8 `& s S: N' W end
0 O) x. r' F* h& o end6 `% t3 i1 p( I) [0 B/ y: V
if pdd . |# _1 {9 l4 |0 s9 w+ E3 [
k = 1;* @5 d8 J3 J( l& U0 |; Z- [
j = yy(j);
8 \9 {6 K s$ F! M7 u while(1)
8 h! q- x$ `" Q1 r4 R7 I& |. [5 s P(k,2) = j;
b/ I/ D; q4 l M y- s P(k,1) = y(j);
( j3 z5 M6 U8 X% k( b j = abs(x(y(j)));
+ f- l. w8 ~/ Y9 D if j == n+1
' }3 O% I! |3 _' g) [ break;+ Y. a, r8 e/ q3 J3 M" }' V( N
end: D) L* `/ G9 O, D' a6 |+ u2 G
k = k+1;
' z8 ^4 j2 t! p end
& X |: f) l. w) b \ for i = 1:k
/ o* X3 v, h/ g: W& B if M(P(i,1),P(i,2))5 I$ r& K9 z$ V4 U
M(P(i,1),P(i,2)) = 0;
& h* Z% _+ h! ^# h) { else! ^7 U y5 U4 {, C; H& @
M(P(i,1),P(i,2)) = 1;+ c6 x, ?' C0 n) c+ x
end
+ ?. B1 d. u8 L% e+ h0 m! [ end
3 e0 q6 Z8 |7 T9 C; i3 J break;% S% [3 h, c6 V/ Z) f! \- F
end( h( d/ o8 L, t5 A4 v, p9 g7 s. W
end
s3 E$ K# }) b$ _! c2 e0 i end7 a, p+ S" Y0 E8 a W2 Y
if pd
: h1 S( F1 r+ u! K9 W break;
8 _8 o7 J1 m0 r4 A! C' ] end
% f9 u' ` o1 |7 u3 G end
* ~! F4 o$ f3 K* L) j9 m1
- w( l! g6 c* c# @2
+ b: |) V9 m a7 _34 N7 I, V8 `+ \
4
; i9 q/ O0 a( V50 b) ^1 x" x6 b9 O3 x
63 }$ u8 s7 G! p8 e
7, j8 F* u! ~7 w) {
8
! G( G1 {9 G( ~) q+ d* X" y99 `1 B3 S( D" S5 A8 p: C0 P9 l' d! {
10. |# A( g7 [, y9 B4 W+ {$ M0 H
114 g/ ]( c/ B( H, U
121 g2 _) o/ ]1 g( D5 \
13
$ E" a3 k! a8 p4 z: z14
" k4 ~8 s7 L+ C, q) {! D15
" n0 b5 ~) J- \; ^6 C1 C9 a16
9 Z" j: e5 `6 y& Y0 G% z( ]( D" S1 p17
' |$ M; b C3 ` F( Y- F18; s3 R3 o. O& Y5 {3 C/ M7 T
19
7 U' V4 K& F% D7 }20. p- ]$ q: A {5 U% g( }- j
21* I, f5 \; ~4 a2 d
22( Z' f j4 z7 @- U
23
2 ~6 f) T$ f9 [24
( ^) J7 ]4 R/ O25
+ `6 \2 q( R4 v# f26! H( ^9 Y2 u8 X
27
2 u H; s1 W% x; _( [282 W* \/ F, O" {. |: b( T
297 t% x3 X0 V+ K- s6 Y; S2 v
301 A3 {0 l% a: I+ W
31, q" `5 s" t2 o( D
32# \ P3 E+ c3 V$ _, [
338 l- `4 X0 T. x( S( T2 M8 l
34
% n# q w; S8 u35
) k) ]+ @2 d4 |8 ~1 ?5 W36
( w. ]* l3 _+ r/ T( B37
+ S, T: K; f$ O9 ^. h/ s38 ]: V( x0 \( X( h4 L8 q
39
; c: ]( U4 G' {, o" K40
; L" G1 }2 x& S# K+ Q410 l9 h" G* Z$ V2 y# i# D! J+ r+ y
422 H- V/ \0 |# A
436 @& A- R, S7 \( R3 Q3 u. {0 _
44- }- l2 p: W0 x: f, X3 ]6 \, O/ a1 g3 P
45
0 i; r8 ]2 w8 F) Z0 g1 P) h) L, ]46
`" d6 M) u( F1 s" ~47
8 ^( J! O" L9 D- S48! y# V6 j$ Z, A' C
49
0 D; v( c. t( Z) N o50
8 \) I/ B9 w& T51
' l& u4 ^1 t: Z3 } v! j52
4 A) r3 `+ [1 q" a53& h, e9 {8 U" q# y: M+ K
54
9 v! g9 a. C8 ^0 A55
) ?' T0 V5 k- a$ e" n }56
) q- u( \7 K/ q, N* r( j57. h6 H$ z+ }$ \2 c
58; H( ~. |3 ?" ]3 F2 C+ v
59+ t' R1 D0 e1 Y1 n& |5 w
60
7 Y, P3 d' V6 L/ m5 ~( m/ Q61
* X$ P% o5 Z, R& G& K62
. q, f3 }3 I1 G' ?( i1 A! [63
9 u8 _1 d. q9 F% C$ I$ @64
* w ` I! g( `65
7 c) U. e9 U5 a2 S66
+ F7 k* g) P6 n1 Q5 w$ r4 n4 u67
v) Z( K. X& j/ e" C0 r" i68- T9 y! O5 f: D# r
69
% Z0 E$ f" \4 V2 H b70
- O: v @+ Q& k. i715 O4 O& m/ a: f" x6 p# c) v& `
720 T5 a/ b# h! k5 |
73
. t; z) \9 D6 V6 T% g1 s74: e3 z9 f, ]" M6 ~: m
751 A" _% ?. x1 N* A' q3 y( o" D
767 T+ Z0 a2 l& q3 L0 g( c0 G: @
77! f& v7 A% Y& w/ }! Q
78: @) I& b8 b; {$ |
798 ?& B* T4 k: q/ M. b( w
807 u/ X$ e% d. @# ?
814 z1 g5 i' h( }6 r8 d
82, b- g/ I, C- P" O! d2 t7 e# I
83
3 o4 z3 a* l3 F; ^% Z' G842 C: P% n0 F: e \7 c' n5 V
85
7 Q# T! c. d7 z) s; T D W* {86
% w, F: q1 b1 ]3 x: y87
" l4 a/ g8 g2 E, H* u( P. b" w+ a88
7 x. o2 W, @1 }7 D. Z89
3 J5 f' A1 x" `9 j$ c, O908 \; r, H! W5 W
91
; }$ J9 y" K4 F/ v- Y- F- u92# ]" F0 e/ ?9 J6 `
93
) t/ K G( ~( R x94" T" N, r# V/ E/ L7 G; v
95
M+ v0 g$ I# f& F96" s$ f6 K" H5 _2 U `
975 g6 w* f4 ]4 z& P1 w0 r: @
988 T8 u. U n$ X
99
# p) g! K4 B) J100
0 N2 v8 }$ ]" x/ z1016 Q1 X5 b1 c& q# v5 U
102
) d4 Q% }+ z" g, b; u103
, [$ k5 i! H. b* }. U6 e0 A& \最佳匹配3 Y8 p9 a J; y9 U5 o( a
; g. X" ~& F% F0 v: ^4 N代码实现:; F7 R9 {1 u4 v3 R* x: H! o/ i- @
9 R$ N, `7 o' v. Z6 F9 c$ Cn = 4;0 o$ V& a" O, o: Q" w1 L' a- f
A = [4 5 5 1;2 2 4 6;4 2 3 3;5 0 2 1];( u6 S6 C; J9 R, x9 g0 |
M(n,n) = 0;
5 K. T$ l3 J4 Q/ a/ Z0 }for i = 1:n
8 x% s, B6 D" d/ z' p. ]5 ~ ` L(i,1) = 0;( Q5 {" ]5 D% Y+ _) d4 v
L(i,2) = 0;3 ~% o8 O+ g! l/ A5 _9 K% b
end d1 i7 C" j9 o. O
%初始化可行点标记L
0 J6 D P/ }* J7 r. N0 d0 `+ Kfor i = 1:n0 _) J, j7 B. w4 x$ [# b
for j = 1:n* n$ V% r$ A" u5 |. g, d1 a6 [& j/ r
if L(i,1) < A(i,j)" c3 B- U/ [& Y- n5 K
L(i,1) = A(i,j);
[; _% p0 m8 }! Q2 j# H1 ]4 } end
2 @3 c3 z' p! J# _& ], c end2 b$ B$ \: f, z8 ~4 L# j/ k) Q
end
9 N# Z c) \/ c! v%生成子图Gl" l+ y5 v# m2 Z. | h1 Y" ^: x! g7 V2 U
for i = 1:n
; N% I& v! ]2 p j: a! C) s s- u for j = 1:n" |# L& u; {+ m- R1 c# I. N
if L(i,1) + L(j,2) == A(i,j)
q/ g2 z6 M' ~+ [4 S Gl(i,j) = 1;3 A/ ^$ m8 B# `8 i
else o( Q0 l* L$ u2 c( f3 Y; o
Gl(i,j) = 0;2 ^8 r) {$ ?% ?9 I/ a
end
$ x/ s0 U# J0 h; z$ x+ C& R$ x end3 @' s% o+ ^3 c# t
end- e) B0 V A$ {7 J5 o
%获得仅含Gl的一条边的初始匹配M5 E8 k( [7 r' b
ii = 0; Y3 f' }+ F/ i/ q8 j' q
jj = 0;4 U9 u# e, P9 A1 m N* g
for i = 1:n# U$ x3 T7 x% k" t5 s
for j = 1:n" X/ i' `- k6 c
if Gl(i,j)& x2 y' l; Q+ l& R9 A. f8 N
ii = i;
; V! X* I/ O: U- x& P0 x jj = j;4 q x* ~7 a' ]
break;
) k" N5 a" B& N4 C end# R! e4 N, O! x$ m8 y6 S+ V4 Z
end
( |6 s M9 \, S" }9 V; l if(ii)
6 I5 J8 f, M+ [+ B. h5 \ break;
$ ~. Y# K. k" @9 P end3 Z N% \: Z1 m3 r
end `1 R8 ~: g- V9 O
M(ii,jj) = 1;1 e" b( J6 v5 b1 I, y1 p$ I9 D
for i = 1:n
) M& L% m, w$ n1 x# v- k+ X( [* [/ ^ S(i) = 0;7 h9 W+ ?0 [& h" c( }3 m
T(i) = 0;* h: j& ~, b6 u$ p W' ]
NIS(i) = 0;
0 ]2 f; q2 u [! b* j) ^( S- i" }end
# ~) u/ `' K6 F4 S* H+ c5 F1 A( K! J4 F& I( g
! c4 Q/ N( f* z" Jwhile (1)3 _0 d' M. h) h2 l5 b/ v3 `3 ]
for i = 1:n
, |/ g- V& A# d1 g4 a/ D' R- c( h" P2 o k = 1;
1 Q# J5 ?1 z( x. C; v6 ` for j = 1:n" g* x+ [" t) H- Y
if M(i,j)
3 _9 E# v. @7 Q# D k = 0;
2 ^$ e; C7 W; p" y$ ~6 h break;
+ ?% e; V6 C" F2 } end. Z, s2 ~/ S6 T) L; W
end
! c+ @5 ~3 N _1 c2 I$ w if k7 b& F; s: f$ P! p, b5 t0 C g# i
break;! N& W! M' s' z$ }; o
end. N$ q4 z% F8 \8 `8 i
end
+ q9 n' I- ?) E%获得最佳匹配M,算法终止3 E. S! [) Z' O! q
if k == 0
1 y. j; j+ L- ?7 ~! T. v4 F' s break;& ^* n1 E: ?# @! I0 t/ \
end# a9 z$ S/ N: ?% D- r
/ j$ R _4 i4 i! t: k
v1 h& r/ w7 I8 n& Y
%S = {xi}
, V) j( Z( y! ^2 {. F; n. cS(1) = i;( K! @" f- K' Y7 P/ z( N7 p+ S
jss = 1;
( b, U3 h `" O( _6 yjst = 0;
- l2 r3 ?% F! F: Bwhile(1)
0 h! S% n2 I! f2 `& I2 x$ {) M jsn = 0;5 N2 x5 F. _# W' A. K! _* B
%选择NL的值" l1 B% M2 i. S+ [& E5 z' g7 C+ ?
for i = 1:jss
% W/ y4 Q* b6 N# G for j = 1:n1 e# X. d4 b' l; ^( s3 o2 w) @6 ?$ ~
if Gl(S(i),j)# }' g& g3 _# A# N
jsn = jsn + 1;
/ x; u! A* T% o$ F: N NIS(jsn) = j;' _, t& L1 |. O1 m
for k = 1:jsn-16 ~4 P/ T ?. n. [/ s
if NIS(k) == j$ ^0 d6 v) r2 Z9 f: |9 u
jsn = jsn - 1;
( a& |6 }! R, P) B1 |; q% { end& D& ^1 S5 _- P9 I$ T" r
end* X! ~0 m, w) c- T% R8 d, x
end
# w; |! L1 k* W8 {- A, | end
9 f2 G7 d; }# v% p: {0 b6 N& z end
; h. J2 \+ L) Z' X( f: B1 R3 j. o %判断NL(S) = T ?1 M h; W1 T3 j5 c6 W
if jsn == jst
0 d0 m: v9 J6 d pd = 1;0 ^* w7 j4 y* ~# d
for j = 1:jsn& c3 @( C! [4 B
if NIS(j) ~= T(j)! D: R" W* N; ], w- ]4 N0 G
pd = 0;
- g! n; J; @" t6 X, G0 z+ c* i+ n break;
' \& v2 c$ w# {& v# M2 f. x+ o end
q+ p" K0 H6 S" f# F end b% M7 Q1 |3 M' U) t
end* J. y* m9 x" U. C
%如果NL(S) = T 计算al的值
9 W$ E0 \/ U' e. d if (jsn == jst) && pd 5 q+ f" L, i# O. b0 }* I% `
al = Inf;
N% ^) u9 `: x, g0 Q for i = 1:jss% |, j- p" Q5 K5 L
for j = 1:n+ P) N( u0 O! U, _- t
pd = 1;
+ x0 v' B0 ~( @$ b+ O for k = 1:jst
4 J7 Q# b" D) x% g if T(k) == j
+ o/ }0 Y5 I, C# @ pd = 0;3 N1 r: s8 L. g' j( j1 l
break;
0 a; C# U# u# x8 n2 j, N end
2 p |' [9 s( ?1 { end; ?6 o% R5 d* O+ O
if pd && (al > L(S(i),1) + L(j,2) - A(S(i),j)); H, O9 p9 Q- o5 Z; H( G8 @
al = L(S(i),1) + L(j,2) - A(S(i),j);
5 ?0 C& V$ g4 |) z1 d) D end6 Y" S5 W/ f( L T
end, ^0 v. O5 b; O2 j7 u) o
end( p2 { d; x, p, @. O5 Z$ S
%调整可行点标记7 y p3 @3 J1 }; l' E
for i = 1:jss
% R* ~& s7 A; P- E L(S(i),1) = L(S(i),1) - al;( C0 K* A! Q* h" {$ c7 G
end
' F1 Y6 b: S+ a %调整可行点标记5 A/ {7 j% ~- k+ j0 V; C
for j = 1:jst
' \( S2 Z( u- G* j" W2 m L(T(j),2) = L(T(j),2) + al;* V. M6 k$ M9 _% W" p9 c
end4 j8 B5 Y; x% t |* o d9 L; n/ x
%生成子图Gl1 h0 {$ |" G8 i. K5 H) b7 a
for i = 1:n" g J) @* H3 L# h4 n5 o0 n6 J
for j = 1:n( v. A6 u" I/ ]- ^, H
if L(i,1) + L(j,2) == A(i,j)
% r/ a/ w0 d$ _, C( o; k) ] S4 m Gl(i,j) = 1;1 `; b. \- Z, r8 e
else7 R# m' J- k, ?6 q5 P2 F: i, f
Gl(i,j) = 0;
# U) d2 d7 T( s6 @/ j end
+ w$ R8 u9 B0 c: g M(i,j) = 0;
; z* `' o) R6 S. Z. T- W/ V( s k = 0;
. V/ D$ N1 ~( ~' h7 {0 v: { end, w1 Z5 C F E1 c. r
end
) a1 c8 V# P& `2 v- S' Q$ w2 a %获得仅含Gl的一条边的初始匹配M
' `8 ]1 q* v0 @- Z9 x& T. z ii = 0;4 n, @2 q( L; t, l
jj = 0;
& Q* t4 d9 ] D% d% D) D+ ^$ a for i = 1:n
/ \8 L* @3 R2 j j for j = 1:n- A/ }7 `5 X# M9 F8 W
if Gl(i,j)
' M p- ^9 V c0 ]/ N" r ii = i;. A! I' Z+ e, z9 Z
jj = j;' J4 D5 {- d/ A3 ` B0 ]9 z! X6 h
break;
) p0 z* @% Q! P end$ O! k( v9 O! X) j9 j
end
; M( A! L/ f6 {4 [' }- B if(ii): p; x4 p' v0 ~' b& N" O9 H8 ^" N; c
break;2 q3 J3 x" E2 E: Y- @) R; Z+ ~
end
7 ?# k/ T h N end! b5 K5 D' r% M7 S- z% s
M(ii,jj) = 1;
+ t! K/ w% G5 G: V- C break;, b* |* y! s0 G6 M* Q* b
else- R3 W$ Y" K& z4 l) l/ n$ }
for j = 1:jsn$ {% g( `3 G4 b5 Y1 |. _ X
pd = 1;
& x7 }& V/ x3 q8 Y( f" t$ e0 D for k = 1:jst& t0 Z. x5 Q8 u0 p3 u. R& K+ J \
if T(k) == NIS(j)! C2 w& C& @1 T: h0 O; ]- a* c
pd =0
: w# B9 A$ \, n; \4 k" ^9 F7 S break;
% t! W3 i2 q8 m0 Y. h& p" ` end" @- _7 G5 a; a) |! y( r: k
end
8 Q ~' P" y3 B# i9 d; A if pd
6 {- X/ x' ?, Q$ T2 u5 f; H jj = j;; j' `8 j, u' G3 ?* O) [
break;4 c7 G$ H, n6 c
end' g1 \. l. b. P7 h
end
7 z( t, g( w. p; e %判断y是否是M的饱和点3 }; ?7 Y! A! J2 s
pd = 0;
& L6 T" ^ @3 h: I( B6 F E for i = 1:n3 u1 B. r% U% E9 p( R
if M(i,NIS(jj))
$ E; p, t- Y3 o9 c! X T5 W pd = 1;4 V/ a: J5 k& U. `( A5 Z3 M
ii = i;/ h1 @; K' E; b ~; O
break;
& H: ~4 C' b4 P6 M8 Z; @' z end r3 J- z8 O5 I& v8 Y/ q: e/ L ]
end# f) r8 m: R( x0 a3 H
if pd- G* z6 B2 g, ]" T* u0 L& E6 q
jss = jss + 1;
) P; g m. d, x S(jss) = ii;3 ?) |# w% r; G: n
jst = jst + 1;: M2 C/ K8 {4 u4 n& F
T(jst) = NIS(jj);
" Q! ?% A8 c- Y) P else
8 |# q0 O" l5 Y- b for k = 1:jst% M! u# x; w4 e& b% x
M(S(k),T(k)) = 1;2 ?$ O0 ^- Q' {$ _& u( f4 t& C' I
M(S(k+1),T(k)) = 0;* t$ k! a+ ]0 \0 o
end
5 W) D3 O; C( X' c3 l# `, p& s/ f if jst == 0+ N# {# F4 P% b$ g6 Y
k = 0;
7 I0 v) c. Q) _) \6 d end
2 v6 f5 Q* s- b: ?# \6 s* S M(S(k+1),NIS(jj)) = 1;: U' Y2 w5 N& R% u7 \' Z3 P
break;
3 t& A' w7 S2 C% _* K end: m$ A- F/ q: `* E) E
end9 B+ W5 F6 @0 Y4 i& q' y
end6 [1 U# C7 ]2 ?6 j7 d
end
4 h' E0 O: [& ~ `, j, K MaxZjpp = 0;1 x! j" k0 [8 \( J0 F6 w( \+ A/ S8 w
for i = 1:n: r2 g y" }6 s% o
for j = 1:n3 n5 d6 w1 | h" K% g* L
if M(i,j)( D- Y! |; @0 H
MaxZjpp = MaxZjpp + A(i,j);
# s' z: J0 z3 m+ q end% U6 X ?+ d# M! Z7 p, |% K) j6 b
end
8 z' ?$ e( V4 [) v: l5 L end
& C, y" q; o/ b M ^6 V" n: }7 I# p. w5 ~9 z; @
MaxZjpp
& ]" i0 e3 y( ]8 ]( i" Y' U% N
2 J. T9 |0 j) P" C0 ~
7 O, \/ {& f& }. K0 I. N; j) p4 }! H2 j. M
|
zan
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